A 1 meter wide door is initially open at an angle of 30o as shown (top view). You push with 20 N force in the middle of the door as shown and the door rotates around the hinge on the left. The door has a rotational inertia =3.0 kg m2. The angular acceleration of the door will be:

The energy of the skater at each position is:

At position A, the skater is at the lowest point, so the PE is zero. The KE can be calculated using the formula KE = (1/2)mv², where m is the mass of the skater and v is the velocity:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

Therefore, at position A, the skater has 1920 J of kinetic energy and 0 J of potential energy.

At position B, the skater has gained some height, so there is some potential energy. The KE can be calculated as before, and the PE can be calculated using the formula PE = mgh, where m is the mass of the skater, g is the acceleration due to gravity (9.81 m/s²), and h is the height:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

PE = (60 kg)(9.81 m/s²)(3 m)

PE = 1764 J

Therefore, at position B, the skater has 1920 J of kinetic energy and 1764 J of potential energy.

At position C, the skater has reached the highest point, so the KE is zero. The PE can be calculated as before:

PE = (60 kg)(9.81 m/s²)(6 m)

PE = 3528 J

Therefore, at position C, the skater has 0 J of kinetic energy and 3528 J of potential energy.

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Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

\(f_s = \mu_s N\) --- (1)

where;

\(f_s =\) static friction force

\(\mu_s =\) coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

\(N = ma_{min}\)

From equation (1)

\(f_s = \mu_s ma_{min}\)

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

\(F = f_s\)

\(mg = \mu_s ma_{min}\)

\(a_{min} = \dfrac{mg }{ \mu_s m}\)

\(a_{min} = \dfrac{g }{ \mu_s }\)

where;

\(\mu_s = 0.383\) and g = 9.8 m/s²

\(a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }\)

\(\mathbf{a_{min}= 25.59 \ m/s^2}\)

Hi there! :)

Reference the diagram below for clarification.

1.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
\(R_T = R_1 + R_2 + ... + R_n\)

In parallel:
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}\)

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

\(\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega\)

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
\(R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}\)

2.

We can use Ohm's law to solve for the current in the circuit.

\(i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}\)

3.

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is 3A for each 10Ω resistor.

4.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

\(V = iR\\\\V = (6)(15) = \boxed{90 V}\)

The object changes direction when its velocity changes sign. You can get the velocity function by differentiating the position function with respect to time t :

x(t) = 4t ² - 41t + 78

→   v(t) = dx(t)/dt = 8t - 41

Solve v(t) = 0:

8t - 41 = 0

8t = 41

t = 41/8 = 5.125

Just to confirm that the velocity indeed changes sign:

• Pick any time before this one to check the sign of v :

v (0) = 8•0 - 41 = -41 < 0

• Pick any time after and check the sign again:

v (6) = 8•6 - 41 = 7 > 0

Now just find the position at this time:

x (5.125) = -433/16 = -27.0625

which means the object is 27.0625 units on the negative x-axis.

You can also do this without calculus by completing the square in the position function:

4t ² - 41t + 78 = 4 (t ² - 41/4 t ) + 78

… = 4 (t ² - 2• 41/8 t + (41/8)² - (41/8)²) + 78

… = 4 (t ² - 2• 41/8 t + (41/8)²) - 4•1681/64 + 78

… = 4 (t - 41/8)² - 433/16

which describes a parabola that opens upward. When t = 41/8 = 5.125, the quadratic term vanishes and the turning point of the parabola occurs at a position of -433/16 units.

A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.

1) Ultraviolet radiation is commonly used in sanitizing hospitals because, viruses, methicillin-resistant Staphylococcus aureus, and vancomycin-resistant enterococci are all susceptible to the germicidal effects of UV-C.

2) According to the photon theory, electrons that have been stimulated return to the ground state to create atomic emission spectra. Light or the photon is the energy that is released when electrons drop to a lower energy level.

3) To characterise the atomic characteristics of light, Albert Einstein used Planck's quantum theory.

Planck's hypothesis is supported by Einstein's demonstration that electromagnetic radiation, such as light, has both wave-like and particle-like properties.

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Answer:

I think C

Explanation:

if im wrong then what is it im taking the exam too

Answer: C. She can increase the number of wire loops.

Explanation:

Answer:What happens to the dew point temperature of a descending mass of air? As air sinks, it becomes warmer. (Warmer air expands and can hold more water, therefore the dew point may increase.) ... The hot water causes condensation of water vapor as it touches the cooler mirror.

Explanation:

Repeated rhythmic pattern best describes the introduction to Imperial March, heard in this excerpt.

It first appeared in the second movie, The Empire Strikes Back, also is known as the leitmotiv, a recurring motif connected to certain people or incidents in a play. The Imperial Motif, a motif for the Empire that appeared in the previous movie, is replaced by the Imperial March in the sequel.

The influx of minor chords, especially those that nearly sound normal, conveys the idea of a deeply deviant, malevolent worldview. For fun, I transposed these warped chords in the song down a semitone so you could hear how the march will sound with the more traditional chords.

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Answer:

432 J

Explanation:

When moving linearly:

Kinetic Energy = (1/2)mV^2

So here you have:

KE=(1/2)(6)(12^2)=(1/2)(6)(144)=432

The unit for energy is Joules (J), so your answer would be 432 J.

The value of the inductance, in , microhenrys of Tarik's solenoid is approximately 1.6239 microhenrys.

To calculate the inductance of a solenoid, we can use the formula:

L = (μ₀ * N² * A) / l

where L is the inductance, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.

In this case, we have:

N = 175 turns

Diameter = 8.05 mm = 0.00805 m (converted to meters)

Radius = Diameter / 2 = 0.00805 m / 2 = 0.004025 m

Length (l) = 2.37 cm = 0.0237 m (converted to meters)

First, let's find the cross-sectional area (A) using the formula for the area of a circle:

A = π * r² = π * (0.004025 m)² ≈ 5.08398 × 10⁻⁵ m²

Now we can plug in the values into the formula for inductance:

L = (4π × 10⁻⁷ T·m/A * (175)² * 5.08398 × 10⁻⁵ m²) / 0.0237 m

L ≈ (1.2566 × 10⁻⁶ * 30625 * 5.08398 × 10⁻⁵) / 0.0237

L ≈ (38.5086 × 10⁻⁶) / 0.0237

L ≈ 1.6239 × 10⁻⁶ H

Now, let's convert the inductance from henrys to microhenrys:

L ≈ 1.6239 × 10⁻⁶ H * 10⁶ μH/H ≈ 1.6239 μH

So the inductance of Tarik's solenoid is approximately 1.6239 microhenrys.

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Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.

(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)

Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)

(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.

Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.

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The net electric force on particle 2 is -21.7 N.

The net force on particle q₂ is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

The force  between particle 2 and particle 1 is calculated as;

F = -( 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.1)²

F = - 25.2 N

The force  between particle 2 and particle 3 is calculated as;

F = ( 9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.15)²

F = 3.5 N

The net force on particle 2 = 3.5 N - 25.2 N = -21.7 N

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Answer:

wind blows a pool chair across the yard

Explanation:

The question is asking about forces at work like air resistance wich is pushing the chair across the yard. Work is when a force pushes pulls so when air resistance is pushing the chair because of the big surface area that is doing work.

Answer: (1) C, (2) B

Explanation: I took the test, but to solve question 1 use the inelastic collision formula m1v1+m2v2 = (m1+m2)v2 to get the answer. Question 2 is b because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.

The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.

The kinetic energy of the bouncy ball after it collides with floor is 30 J.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

According to the given in question,

a.) Using inelastic collision formula

\(m_1v_1+m_2v_2 = (m_1+m_2)v_2\)

\(v_2\) = 60/16 m/sec = 3.75 m/sec

b.) Because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.

The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.

The kinetic energy of the bouncy ball after it collides with floor is 30 J.

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Answer:

Tension of the wire(T) = 169 N

Explanation:

Given:

f = 65Hz

Length of the piano wire (L) = 2 m

Mass density = 5.0 g/m² = 0.005 kg/m²

Find:

Tension of the wire(T)

Computation:

f = v / λ

65 = v / 2L

65 = v /(2)(2)

v = 260 m/s

T = v² (m/l)

T = (260)²(0.005/2)

T = 169 N

Tension of the wire(T) = 169 N

The tangential acceleration of the short player's ball is twice the tangential acceleration of the tall player's ball.

The ball of the shorter player experiences twofold of the ball of the taller player's tangential acceleration. The reason behind this is that the magnitude of the tangential acceleration correlates directly with the radius of the circle.

The ball belonging to the smaller player is positioned nearer to the elbow, resulting in a decreased radius. It can be deduced from this statement that the ball of the short player experiences twice the magnitude of tangential acceleration compared to the ball of the tall player.

The answer is: ashort = 2atall

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The Complete Question

A short tennis player hits a ball that is r meters from their elbow with an angular acceleration a. A tall tennis player hits a ball with the same angular acceleration where the ball is 2r from their elbow. How does the tangential acceleration of the short player's ball Ashort compare with the tall player's ball a tall? Choose 1 answer: ashort 2atall ashort Otall ashort 1 atall 2

Answer:

12,000 grams = 12 kg

Explanation:

Volume V = 20 x 20 x 30 cm³ = 12,000 cm³

density of water d = 1 g/cm³

so the mass is 12,000 grams = 12 kg

I mean if it will be anything the asnwer would be 23^90'200

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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Dream theories have in common that they are related to conceptions about reality.

Dream theories are a series of theories that focus on explaining the dreams that an individual experiences when sleeping.

There are three main theories about dreams that are:

Activation-synthesis theory: This theory states that the brain is randomly activated during sleep and that brain activity is generally associated with memories and sensory information.

Theory of psychoanalysis: This theory states that dreams contain unconscious information for the individual about his interpretation of reality. This information is later synthesized and processed by reason so that the individual takes it as a meaningful message.

Threat Rehearsal Theory: This theory states that dreams are "rehearsals" of risk situations in which situations that are considered dangerous to the individual are simulated and in which the brain is trained to act in them.

The main similarity that these three theories have is that they are related to the interpretation that the individual has of his reality and the sensory information of his interaction with the environment.

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The electric potential at x=3.0m is  - 180 Volt according to the figure 1.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.

Electric charges and time-varying electric currents are the building blocks of electric fields.

The electric potential at x=3.0m is given by = initial potential energy + electric field× distance

= - 180 Volt + 0 Volt/meter×3 meter

= - 180 Volt.

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The car is moving at 21 m/s after the 6 seconds.

This is because:

Initial velocity + (Acceleration x Time) = Final velocity

15 m/s + (2 m/s/s x 6 seconds) = 21 m/s.

The car is moving at 21 m/s after the 6 seconds.

This is because acceleration is the rate of change of velocity, so the velocity of the car increases by 2 m/s for every second it accelerates, which results in a total increase of 12 m/s in 6 seconds. Adding the initial velocity of 15 m/s, the car's final velocity is 21 m/s.

Acceleration is a fundamental concept in physics and it refers to the rate at which velocity changes over time. It can be expressed mathematically as the derivative of velocity with respect to time.

In the given scenario, the car's acceleration is 2 m/s/s which means that the velocity of the car increases by 2 m/s for every second that it accelerates. Therefore, in 6 seconds, the velocity of the car increases by:

The initial velocity of the car was 15 m/s and after 6 seconds of acceleration, the final velocity is:

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

Explanation:

wavespeed = wavelength * frequency

wavespeed / wavelength = frequency

343 / 17 = 20.17 Hz

343 / 0.017 = 201764 Hz

So range of frequencies we can hear is between 20Hz and 20,000 Hz ( or 20.17 to 201764 if you dont round up/down)

The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

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The models that predict galaxies should be getting farther apart now are; accelerating model, critical model,- and coasting model.

Observations show that the expansion of the universe is accelerating, such that the velocity at which a distant galaxy recedes from the observer is continuously increasing with time.

The accelerating model of the galaxies predicts that galaxies should be getting farther apart now.

From the model presented in the graph critical model of the galaxies also predict that galaxies should be getting farther apart now.

Another model that predicts that galaxies should be getting farther apart now is coasting model.

These models can be seen in the graph as they increase proportional with time. That is the distance between galaxies increase with increase in time measured in years.

Thus, we can conclude that there  models ( accelerating, critical and coasting model) predicts the relative position of the galaxies from us.

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