A 0. 495M solution of nitrous acid, HNO2, has a pH of 1. 83



a) Find the percent ionization of nitrous acid in this solution. You may assume the temperature is 25 oC.



b) Calculate the value of Ka for nitrous acid. You may assume the temperature is 25 oC.



c) Using the value of Ka you determined in b), calculate the pH of a solution formed by adding 1. 0 g of NaNO2 to 750 mL of 0. 0125M HNO2. You may assume the temperature is 25 oC

I would dissolve non-polar solid iodine in liquid bromine, which is non-polar, as the solvent.

Polar substances are substances whose molecules have oppositely-charged ends. Examples of polar substances are ionic compounds as well as polar covalent compounds like water and hydrogen chloride.

Non-polar substances are substances whose molecules do not have charged ends. Examples of non-polar substances are covalent molecules such as carbon dioxide, bromine, etc.

According to the principle of solutions, like dissolves like. Hence,  non-polar solids will dissolve in non-polar solvents.

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Answer:

75 grams

Explanation:

At 95 °C, you can dissolve up to 75 grams of K2Cr2O7 in 100 mL of water.

The solubility of a substance in a particular solvent is the maximum amount of that substance that can dissolve in the solvent at a given temperature. The solubility of a substance can be affected by factors such as temperature, pressure, and the presence of other substances.

For K2Cr2O7, the solubility in water is highly dependent on temperature. At 95 °C, the solubility of K2Cr2O7 in water is approximately 75 g/100 mL. This means that at 95 °C, you can dissolve up to 75 grams of K2Cr2O7 in 100 mL of water. Since 100 g of water is equivalent to 100 mL, you can dissolve up to 75 grams of K2Cr2O7 in 100 g of water at 95 °C.

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Answer:

1 × 10²⁴ atoms O

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

30 g O

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Step 3: Convert

\(30 \ g \ O(\frac{1 \ mol \ O}{16.00 \ g \ O} )(\frac{6.022 \cdot 10^{23} \ atoms \ O}{1 \ mol \ O} )\) = 1.12913 × 10²⁴ atoms O

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

1.12913 × 10²⁴ atoms O ≈ 1 × 10²⁴ atoms O

Answer:

21.16 g

Explanation:

Balance the equation

3 Zn + 2 MoO3 = Mo2O3 + 3 ZnO

And prepare their molar masses

Zn - 65.38

MoO3 - 143.96

Mo2O3 - 239.92

ZnO - 81.38

Since Zn is the limiting reagent; (you can determine this by trial and error but I'm too lazy), basically 29.2 g of MoO3 needs 19.892 g of Zn to react; while 17 g of Zn would need 24.955 g of MoO3 so we have shiet leftover. So we should always use the limiting reagent, in this case,

Zn

as it gets used up completely.

Anyway:
We can now solve using the ratio between Zn and ZnO.
(17 g of Zn /

65.38 g per Zn) x (3 mol of ZnO / 3 mol of Zn) x (81.38 g per ZnO / 1 mol of ZnO) = 21.16 g of ZnO

sooooo you get

21.16 g

(typing this on mobile and kinda hungover so yea)

The two parameters that are commonly plotted in an absorbance spectrum are the wavelength of light (measured in nanometers, or nm) on the x-axis, and the absorbance (or optical density) on the y-axis.

The amount of light absorbed by a sample is calculated as a function of wavelength in absorbance spectroscopy, also referred to as absorption spectroscopy. This can provide crucial details about an atom's or molecule's electronic structure.

Various radiation is absorbed by chemicals and elements when it passes through them, depending on the chemical or element in question. In the emission spectrum, coloured lines can be observed exactly where the dark line pattern appears.

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If the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

The Gibb Free Energy is used to obtain the feasibility of a reaction. If the Gibbs free energy is positive the reaction is not spontaneous. If the value is negative, the reaction is spontaneous while a zero values indicates equilibrium.

From the equation;

ΔG = ΔH - TΔS, it follows that if the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

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Answer: D - hydrogen bond in petrol

Answer:

7.53*10²³ molecules of oxygen will you need.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can then apply the following rule of three: if by definition of Avogadro's Number 1 mole of oxygen gas contains 6.023*10²³ molecules, 1.25 moles contains how many molecules?

\(amount of molecules=\frac{1.25 moles*6.023*10^{23}molecules }{1 mole}\)

amount of molecules= 7.53*10²³

7.53*10²³ molecules of oxygen will you need.

Answer:

THE NUMBER OF ATOMS OF CHLORINE IN THE SAMPLE IS 25.95 * 10^45 ATOMS.

Explanation:

Number of molecules = 4.31 * 10^22 molecules of SCl2

From Avogadro's rule which states that equal volume of gases at the same temperature and pressure have the same number of molecules.

1 mole = 6.022 * 10 ^ 23 particles or atoms

So therefore, we equate the given value of SCl2 molecules and solve for the number of atoms of chlorine in the molecule

1 mole = 6.022 * 10^23 atoms

From the break down of SCl2

SCl2 -------> S+ + 2Cl -

So therefore, 2 moles of chlorine is present

2 moles = 2 * 6.022 *10^23

4.31 * 10^22 moles = x atoms

= 4.31 * 10 ^22 * 2 * 6.022 * 10^23 / 2

= 25.95482 * 10^45 atoms

In conclusion, the number of atoms of chlorine present in the sample is 25.95 * 10^45 atoms.

the mr-vp tests are part of a battery of tests called imvic tests. these tests are useful in identifying and differentiating  Gram-positive cocci.

mr-vp tests can be regarded as a test that is used in the determination of fermentation pathway that is required in glucose.

It is used in mixed acid fermentation pathway and can be used in  identifying and differentiating  Gram-positive cocci.

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Answer:

Valency of nitrogen in the given compounds:

N₂O₃ = +3

N₂O₅ = +5

NO = +2

-TheUnknownScientist 72

Explanation:

Basically, the hydroxonium ions, H3O+ are responsible for the acidity of a solution and the hydroxide ions, OH- are responsible for  the basicity of a solution.

In an acid solution;

The concentration of the hydroxonium ions is greater than that of the hydroxide ions.

In a basic solution;

The concentration of the hydroxide ions is greater than that of the hydroxonium ions.

it said answer for 5 + points

The photon has the following parameters;

We know from the Bohr model that energy is given off when an electron falls from a higher to a lower energy level and we can work this out by the use of the Rydberg equation.

We know that;

1/λ = RH(1/\(n_{2} ^{2}\) - 1/\(n_{1} ^{2}\))

Given that;

RH = Rydberg constant

Then;

1/λ = 1.097 * 10^7(1/1^2 - 1/(5)^2)

λ = 9.5 * 10^-8 m

The frequency is obtained from;

c = λ f

f = c/λ

f = 3 * 10^8 m/s/9.5 * 10^-8 m

f = 3.2 * 10^15 Hz

Energy is obtained from;

E = hf

E = 6.6 * 10^-34 Js * 3.2 * 10^15 Hz

E = 2.1 * 10^-17 J

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The volume of 15.0 m stock NaOH solution would be required to prepare a solution with a volume of 500.0 ml and a concentration of 0.200 m NaOH 10 mL.

To prepare a solution with a desired concentration, we can use the formula C₁V₁ = C₂V₂, where C₁ and V₁ represent the concentration and volume of the stock solution, and C₂ and V₂ represent the concentration and volume of the desired solution.

In this case, we have the following information:

C₁ = 15.0 M (concentration of the stock NaOH solution)

V₁ = unknown (volume of the stock solution needed)

C₂ = 0.200 M (desired concentration of the NaOH solution)

V₂ = 500.0 mL (desired volume of the NaOH solution)

We can rearrange the formula to solve for V₁:

V₁ = (C₂ * V₂) / C₁

Substituting the values into the equation:

V₁ = (0.200 M * 0.500 L) / 15.0 M

Calculating the expression:

V₁ = 0.010 L

Since the given volume is in milliliters, we can convert it to mL:

V₁ = 0.010 L * 1000 mL/L

V₁ = 10 mL

Therefore, to prepare a solution with a volume of 500.0 mL and a concentration of 0.200 M NaOH, you would need 10 mL of the 15.0 M NaOH stock solution.

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The beta-pleated sheet is a secondary structure found in proteins that is characterized by the orientation of hydrogen bonds between adjacent strands. The correct answer to the question is (2) H bonds perpendicular to the molecular axis.

The correct answer is option 2.

In a beta-pleated sheet, the strands of the protein backbone are extended and oriented in a zigzag pattern, forming a flat sheet-like structure. The hydrogen bonds between adjacent strands occur between the carbonyl oxygen of one amino acid and the amide hydrogen of an adjacent amino acid, with the bonds running perpendicular to the axis of the strands. This arrangement allows for maximum stability and strength of the structure, as the hydrogen bonds provide strong interactions between adjacent strands. The orientation of the hydrogen bonds also creates a characteristic "pleated" appearance in the sheet, as the strands are forced to bend slightly to accommodate the perpendicular arrangement of the bonds. Overall, the beta-pleated sheet is an important structural motif in proteins, contributing to the overall stability and function of the molecule.

The correct answer is option 2.

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Answer:

the oil spreads to cover the water

Answer:

I think it is ; The oil floats to the surface of the water

Explanation:

I don't know about the other one.

Answer:

140 g (to 2 sf)

Explanation:

The atomic mass of magnesium is 24.305 u.

The atomic mass of oxygen is 15.9994 u.

So, the gram-formula mass of magnesium dioxide, in g/mol, is

\(2(15.9994) + 24.305 = 56.3038\)

So, the mass of 2.5 moles is (56.3038)(2.5), which is equal to 140 g (to 2 sf)

The reaction is an example of an electrophilic addition reaction and the product obtained is an organic product. It is noteworthy that organic products are derived from living organisms and generally contain carbon and hydrogen.

Markovnikov's rule predicts the regioselective outcome of an electrophilic addition reaction of a protic acid to an alkene. It states that the electrophile (positive charged species) will be added to the alkene carbon with the highest number of hydrogen atoms, and the nucleophile (negative charged species) will be added to the carbon with the lowest number of hydrogen atoms.

In the reaction of hydrogen chloride with 2-methyl-2-butene, the electrophilic hydrogen (H+) from HCl is added to the double bond of 2-methyl-2-butene. According to Markovnikov's rule, hydrogen will be added to the carbon that has more hydrogen atoms and the chloride ion (Cl-) will be added to the carbon that has fewer hydrogen atoms.The major organic product of the reaction between hydrogen chloride and 2-methyl-2-butene is 2-chloro-2-methylbutane. The hydrogen from HCl adds to the tertiary carbon of 2-methyl-2-butene, forming a tertiary carbocation, which is more stable than secondary or primary carbocations. The chloride ion (Cl-) then attacks the carbocation to form 2-chloro-2-methylbutane, which is the major organic product.2-methyl-2-butene + HCl → 2-chloro-2-methylbutane.

The reaction is an example of an electrophilic addition reaction and the product obtained is an organic product. It is noteworthy that organic products are derived from living organisms and generally contain carbon and hydrogen. Hydrogen chloride is a strong acid, and it reacts with the 2-methyl-2-butene to form 2-chloro-2-methylbutane as the major organic product.

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The concentration of the diluted solution will be 2.44%.

From the equation of dilution:

(M1)(V1) = (M2)(V2).

where M1 = concentration before dilution, M2 = concentration after dilution, V1 = volume before dilution, and V2 = volume after dilution.

In this case:

V1 = 17.06 mL

V2 = 50.00 mL

M1 = 7.16%

M2 = ?

M2 = (M1)(V1)/(V2)

        = 7.16 x 17.06/50

               = 2.44%

Thus, the concentration of the diluted solution is 2.44%.

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Answer:

Well what are the numbers but ik that it ius 5

Explanation:

Answer:

PV=nRT

0.20×v = 0.070×8.00

0.20V= 0.56

0.20v÷0.20v = 0.56÷0.20v

= 2.8

When, using Hess's law, the  ΔH° for this process is -394 kJ. Option B is correct.

Hess's law is a principle in chemistry that states that the enthalpy change of a chemical reaction is independent of the pathway between the initial and final states. In other words, if a reaction can occur via multiple routes, the total enthalpy change for the reaction will be the same regardless of the pathway taken.

The overall reaction is;

Sb(s) + 2Cl₂(g) → SbCl₅(s)

We can break down into two steps;

Sb(s) + Cl₂(g) → SbCl₃(s) ΔH° = -314 kJ/mol

SbCl₃(s) + Cl₂(g) → SbCl₅(s) ΔH° = -80 kJ/mol

To get the overall reaction, we can add the two equations together:

Sb(s) + 2Cl₂(g) → SbCl₅(s) ΔH° = -394 kJ/mol

Therefore, the ΔH° is -394 kJ/mol.

Hence, B. is the correct option.

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--The given question is incomplete, the complete question is

"Using Hess's law, calculate δh° for the process: sb (s) Cl₂ (g) SbCl₅ (s) from the following information: sb (s) Cl₂ (g) sbcl3 (s) δh° = − 314 kj sbcl₃ (s) Cl2 (g) SbCl₅ (s) δh°= − 80 kja. A) -290 KJb. B) -394 KJc. C) +394 KJd. D) -234 KJe. E) +234 KJ."--

Answer:

1. (See explanation)

2. 46. 23 from the mother’s egg and 23 from the father’s sperm.

Explanation:

ok for number one I am not entirely sure, but I am pretty sure that light, chemicals and temperature can all affect which genes get turned on and off. I am not entirely sure if the question is asking about the environment influencing inherited traits in the form of natural selection tho? If that is something you’re seeing right now, it might be a possible answer. But honestly I am not completely sure.

The combination of fire and water would lead to the formation of steam.

At face value, it would appear as if it is not possible for use to be able to put together water and fire. Is this really true? While it is true that in many instances, water can be used to extinguish fire, but water can in some cases also be combined with fire.

How does this work, we know that when heated, water can be converted into steam and the steam would have a lot more energy than the water in the liquid state.

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The half-life of the substance is 3.106 years.

Here,

a = the initial amount of substance

1-r is the decay rate

x = time span

The equation is given in its correct form as follows:

a = \(a_{0}\)×\((0.8)^{t}\)

As this is an exponential decay of a first order reaction, t is an exponent of 0.8.

Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:

a = 0.5 a0

0.5\(a_{0}\) = \(a_{0}\)×\((0.8)^{t}\)

0.5 = \((0.8)^{t}\)

taking log on both sides

t log 0.8 = log 0.5

t = log 0.5/log 0.8

t = 3.106 years

The half-life of the substance is 3.106 years.

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a) The absolute pressure at point B cannot be determined based on the given information.

b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable with the provided information.

a) The absolute pressure at point B cannot be determined because the information about the liquid levels or the densities of the liquids in the tank is not provided.

The absolute pressure depends on the height of the liquid column and the density of the liquid, which are missing from the given data. Without this information, it is not possible to calculate the absolute pressure at point B.

b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable. To calculate the relative pressure, we need to know the absolute pressure at point F and subtract the atmospheric pressure.

However, the absolute pressure at point F is not given, so we cannot determine the relative pressure. Additionally, the value of atmospheric pressure (Patm) provided is not relevant to calculating the relative pressure at point F.

In order to determine the absolute pressure at point B or the relative pressure at point F, we would need additional information such as the liquid levels in the tank, the densities of the liquids, and possibly the atmospheric pressure at point F.

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Answer: C

Explanation: everything else seems like it is obeying the laws of gravity except wind blowing sand into the air. hope this helps.

Answer:

1.02 N/mm2

Explanation:

We can see that the pressure is applied on the small weight that covers the opening.

The area of the circular opening is π(0.512 mm)

= 0.824 mm2

Pressure = Pressure = Force / Area

=  (0.847 N) / (0.824 mm2)

= 1.02 N/mm2

Answer:

Nicotine

Explanation: