three grams of the same substance in different phases are stored in three different containers each containers.each container is barely large enough to hold a substance. which statement can be known about the behavior of the atoms in each container?​

Answer:

See below

Explanation:

F = ma       net force is 300 N upward

300 = 306  * a         a = .980 m/s^2

Answer:

Waxing Gibbous

Explanation:

New Moon Rises at sunrise, transits meridian at noon, sets at sunset

Explanation:

a) The gravitational potential energy of the system of three masses at the given positions is 188.36md.

(b) The redefined reference height is h₀ = 0.55d.

(c) The new reference height measured from the base is h₀' = 0.96d.

(a) The gravitational potential energy of the system of three masses at the given positions is calculated as;

total gravitational potential energy = P.E(mass 1) + P.E(mass 2) + P.E(mass 3)

T.G.P.E = m₁gh₁ + m₂gh₂ + m₃gh₃

where;

T.G.P.E = (4.6m x 9.8 x 3d) + (2.21m x 9.8 x 2d) + (m x 9.8 x d)

T.G.P.E = 135.24md  +   43.32md  + 9.8md

T.G.P.E = 188.36md

(b) The redefined reference height is calculated as follows;

0 =  (4.6m x 9.8 x h₀) + (2.21m x 9.8 x (h₀ - d) + (m x 9.8 x (h₀ - 2d)

0 = 45.08mh₀ + 21.66mh₀ - 21.66md  +  9.8mh₀ - 19.6md

0 = 45.08h₀ + 21.66h₀ - 21.66d  +  9.8h₀ - 19.6d

0 = 76.54h₀ - 41.26d

76.54h₀ = 41.26d

h₀ = 41.26d/75.54

h₀ = 0.55d

(c) The new reference height measured from the base such that the highest two objects have the exact same gravitational potential energy is calculated as follows;

m₂gh₂ = m₁gh₁

2.21m x 9.8 x h₂ = 4.6m x 9.8 x h₁

21.66mh₂  =  45.08mh₃

21.66h₂  =  45.08h₁

h₁ = 21.66h₂/45.08

h₁ = 0.48h₂

h₀' = 0.48 x (2d)

h₀' = 0.96d

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The question is incomplete,I will complete the question and provide the answer.

Due to the nature of the question,I will sketch an answer/solution to the question and submit it as an attachment.

So you will be having two attachments,

1) The question

2) The solution

From the options given in the first attachment with is the question,the correct answer is option C.

1 AND 2 ARE GOING UP.

Proper explanation using sketch and arrows is given in the second attachment which shows the solution to the question.

Answer:

Isobaric process is one carried out at constant Pressure.

Explanation:

An isobaric process is a process that takes place under constant pressure. The first law of thermodynamics can be written as follows for the Isobaric Process:

ΔQ = ΔU + PΔV

where,

ΔQ =  Heat Transfer

ΔU = Change in Internal Energy of the System

P = Constant Pressure

ΔV = Chang in Volume of the System

In an isobaric process, heat supplied to the system is utilized to increase its internal energy and to do work.

Hence, all the options given are incorrect. The correct option is:

Isobaric process is one carried out at constant Pressure.

12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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Answer:

19.6 m/s

Explanation:

The parameters given are:

Mass M = 20 Kg

Force F = 285 N

Angle Ø = 30 degree

Time t = 4 seconds

Coefficient of friction = 0.72

At the plane, the weight of the box will be mgsinØ

Resolving forces at the plane, we will have:

MgsinØ + Fr = F

Where Fr = frictional force.

Fr = F - mgsinØ

Substitute all the parameters into the formula

Fr = 285 - 20 × 9.8 sin30

Fr = 285 - 98

Fr = 187 N

But for the box moving toward the top of the plane,

F - Fr = ma

Where a = V/t

Substitute all the parameters involved into the formula

285 - 187 = 20 ( V/4)

98 = 5V

V = 98/5

V = 19.6 m/s

Therefore, the speed with which the box is moving is 19.6 m/s

Some psychologists believe that eating disorders represent a defense against unconscious conflicts related to sexual development. These psychologists have adopted a Psychoanalytic approach to eating disorders.

A psychoanalytic approach is based on the idea that our unconscious thoughts, feelings, and motivations can have a powerful influence on our behavior by focusing on helping individuals to gain insight into their unconscious processes, recognize and resolve conflicts, and modify their behavior.

Therefore, with this data, we can see that a Psychoanalytic approach is based on unconscious mental processes to develop a cure.

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Answer:

c

Explanation:

im sorry if im wrong

mark me as brainlist please thank you

Answer:

E = m c^2 = 2.5 * (3 * 10E8)^2 = 2.25 * 10E17 Joules

Answer:

The answer is D. 2.25 × 1017 J

Explanation:

got it right on edge 2021

Answer:

564

Explanation:

Answer:

D

Explanation:

the answer is d because process of genetic recombination in bacteria in which genes from a host cell (a bacterium) are incorporated into the genome of a bacterial virus (bacteriophage) and then carried to another host cell when the bacteriophage initiates another cycle of infection

Answer:

the same question I want to know

a. Spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\), b. The net force on sphere A now is the force due to sphere B, which is: \(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\), c. The magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

a) The magnitude of the force (F) sphere B exerts on sphere A can be calculated using Coulomb's law:

\(\rm \[ F = \frac{k Q_1 Q_2}{R^2} \]\)

where:

k is Coulomb's constant \(\rm \( k = \frac{1}{4\pi\epsilon_0} \)\) where \(\rm \( \epsilon_0 \)\) is the vacuum permittivity constant),

\(\rm \( Q_1 \)\) and \(\rm \( Q_2 \)\) are the charges on spheres A and B respectively, and

\(\rm \( R \)\) is the distance between the two spheres.

Since both spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\)

b) When an identical sphere C makes contact with sphere B, they share the charge equally. Sphere B now carries \(\rm \( \frac{Q}{2} \)\) charge, and sphere C carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, it exerts no force on sphere A. So, the net force on sphere A now is the force due to sphere B, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\)

c) When sphere C makes contact with sphere A, they both share the charge equally. Each sphere now carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, the net force on sphere A now is the force due to the charge on sphere A itself, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot \frac{Q}{2}}{R^2} \\\\\rm = \frac{3}{8} \frac{k Q^2}{R^2} \]\)

So, the magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

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Answer:

it's an insulator

Explanation:

Insulators provides resistance

Answer:

C. insulator

Explanation:

Given,

The frequency of the sound, f=40 Hz

The speed of the sound in the air, c=340 m/s

The speed of a wave in a medium is given by the product of the frequency and the wavelength of the wave.

Thus the speed of the sound with the given frequency is calculated using the formula,

Where λ is the wavelength of the wave.

On rearranging the above equation,

On substituting the known values,

Thus the length of the wave or the wavelength of the given wave is 8.5 m

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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To obtain the type, orientation, location and magnification of the image, we shall first obtain the location (i.e distance) of the image from the mirror. Details below:

The location i.e distance of the image can be obtained as follow:

1/f = 1/v + 1/u

Rearrange

1/v = 1/f - 1/u

v = (f × u) / (u - f)

v = (12 × 24) / (24 - 12)

v = 288 / 12

v = 24 cm

Thus, the the location of the image is 24 cm

Since the location of the image is positive (i.e 24 cm). Thus,

Now, we shall obtain the magnification of the image. Details below:

Magnification = image distance (v) / object distance (u)

Magnification = 24 / 24

Magnification = 1

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Answer: D

X and Y

Explanation:

X The least amount of magnesium Took in magnesium

Y Slightly less magnesium than the cell Took in magnesium

Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.

Answer:

Cells X and Y

Explanation:

Active transport occurs when a substance moves across a membrane against its concentration gradient.

Cells W and Z were placed in a liquid containing more magnesium than the cells. Magnesium therefore, diffuses passively down it's concentration gradient into the cells.

However, cells X and Y were placed in a solution containing less magnesium than the cells, yet these cells took in magnesium against this concentration gradient. This, shows that active transport had taken place.

Answer:

9.18/13=0.7062 second

Explanation:

9.18meters devide it by the speed 13m/s

≈0.7062

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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Answer:

The same as its translational KE.

The easy way to do this is to make up numbers and use them.

So, I'll say m=2 and r=3. I will also say v=3 .

Rot. Inertia of a hoop is mr^2. So the rot KE is: 1/2 (mr^2)(w^2)

note: (1/2*I*w^2)

Translational kinetic energy is basically normal KE, so 1/2(m)(v^2)

Now, lets plug our made up values in:

Rot Ke : 1/2 (9*2)(3/3) *note w = v/r

Tran Ke: 1/2(2)(9)

Rot Ke: 9

Tran Ke: 9

9=9, same.

To calculate the refractive index of the liquid, we can use the formula for the radius of the nth bright ring in Newton's rings: \(r_n\) = √(n × λ × R). Therefore, the refractive index of the liquid is approximately 1.378.

\(r_n\) =  √(n × λ × R) (formula )

Where: \(r_n\) is the radius of the nth bright ring,

n is the order of the ring,

λ is the wavelength of light,

and R is the radius of curvature of the lens.

the third bright ring (r_3 = 3.65 mm = 0.365 cm), the radius of curvature of the lens (R = 10 m = 1000 cm), and the wavelength of light (λ = 0.0000589 cm).

n = \(r_n\) / √(n × λ × R)

Substituting the given values:

n = 0.365 / √(3 × 0.0000589 × 1000)

Calculating the value:

n ≈ 1.378 ( refractive index)

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The star of a cross-country team is Ken Runfast. Ken recently ran for 12.4 minutes at an average speed of 5 m/s. After then, Ken's average speed was 6.1.

Distance is the overall movement of an item with consideration of direction. Regardless of an object's starting or ending position, distance can be defined as the amount of ground it has covered.

We can determine an object's actual size by learning how far away it is. The area an object occupies in the sky can be measured. The distance from it must then be determined in order to determine its true size. An thing appears smaller the further it is away.

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m

When a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:

Given that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.

Let us use equation 1

V = U + at

9 = 0 + 6.78a

a = 9 / 6.78

a = 1.33 m/\(s^{2}\)

Now let us use equation 3

\(v^{2}\) = \(u^{2}\) + 2as

\(9^{2}\) = 2 x 1.33 x S

81 = 2.655S

S = 81/2.655

S = 30.51 m

Therefore, the distance covered by a T-Rex is 30.51 m.

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v0 = initial speed

g= gravity = 9.8 m/s^2

h= height = 121 cm = 1.21 m

KE = PE

1/2*v^2 *m = mgh

1/2 v^2 = gh

vo^2 = 2* g* h

vo^2 = 2* 9.8 * 1.21

vo = √(2* 9.8 * 1.21)

vo= 4.87 m/s

Their vertical launch speed is 4.87 m/s

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Gravity is not described as the bending of space.

So answer 3 is the correct option among them.

Gravity is described as a fundamental interaction which causes mutual attraction between all things with mass or energy.

The characteristics of gravity include the following:

Gravity is also known as the universal force of attraction acting between all matter. Gravity has been found by experts to be by far the weakest known force in nature.

In conclusion,  Gravity creates stars and planets by pulling together the material from which they are made.

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