9. Samuel and David are in the weight room bench pressing the same 900 N weight. If David
has longer arms than Samuel, who does more work on the weight while bench pressing? Why?

can someone please help

Answers

Answer 1

Samuel and David are in the weight room bench pressing the same 900 N weight. If David has longer arms than Samuel, then David does more work on the weight while bench pressing.

What is Work?

This is referred to as the energy transferred to or from an object via the application of force along a displacement. It is calculated by the following below and the unit is in Joules.

Work = F × s  where f is force and s is displacement.

People who have longer arm spans will have a greater total distance to push the bar in order to reach the 120 degrees angle of elbow flexion. This means that there will be more work done in this scenario and is therefore the reason why David does more work on the weight while bench pressing and is therefore the reason why it was chosen as the correct choice.

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Related Questions

Which is one piece of evidence of seafloor spreading? help :(​

Answers

Answer:

Mid ocean ridges are evidence of sea floor spreading as tectonic movement opens a gash or "fault" in the ocean floor.

Answer:

Eruptions of molten material, magnetic stripes in the rock of the ocean floor, and the ages of the rocks themselves; this evidence led scientists to look again at Wegener's hypothesis of continental drift.

¿Qué trabajo realiza una carreta que contiene una de masa 800 lb de cemento si se desplaza 100 m por un suelo nivelado?

Answers

Answer:

Ver respuesta en el procedimiento

Explanation:

En este caso, necesitamos la expresión que nos permite hallar el Trabajo realizado por un objeto a través de una distancia dada. Esa expresión es:

W = F * x   (1)

Donde:

W: Trabajo en Joules (J)

F: Fuerza en Newton (N)

x: Distancia o radio en metros (m)

En este caso, solo tenemos una masa de 800 lb, y la distancia que se esta recorriendo. No tenemos ningún dato adicional que nos diga si por ejemplo, es empujado por una persona o parecido, solo los datos de la masa que lleva la carreta. Por lo tanto, la única fuerza que podemos asumir se está ejerciendo, sería la fuerza del peso del objeto que se calcula así:

P = mg   (2)

Donde:

g: aceleración de gravedad (9,8 m/s²)

Ahora bien si reemplazamos (2) en (1) nos queda:

W = mgx  (3)

Y antes de realizar el cálculo debemos convertir la unidad de masa en libra a kilogramo, usando la siguiente conversión:  1 lb -----> 0,454 kg por tanto:

m = 800 * 0,454 = 363.2 kg

Ahora podemos usar (3) y calcular el trabajo:

W = 363,2 * 9,8 * 100

W = 355936 J o simplemente 355,936 kJ

Espero te sirva.

PD: También puedes usar el valor de gravedad como 10 m/s² y tendrás un resultado de 363200 J o 363,2 kJ.


If
you weigh 140 pounds, what is your weight in kilograms

Answers

If you’re 140lb pounds in weight then the kilograms will be (63.503) in kilograms

A sound wave with a power of 8. 8 × 10–4 W leaves a speaker and passes through section A, which has an area of 5. 0 m2. What is the intensity of sound in this area? (Intensity = I = ) 1. 8 × 10–4 W/m2 1. 8 × 10–6 W/m2 1. 6 × 10–4 W/m2 1. 6 × 10–6 W/m2.

Answers

The intensity of sound can be calculated using the formula: Intensity (I) = Power (P) / Area (A).Plugging in the given values, we have: Intensity (I) = 8.8 × 10^-4 W / 5.0 m^2.

Calculating this expression gives us an intensity of 1.76 × 10^-4 W/m^2.

Therefore, the correct answer is: 1.6 × 10^-4 W/m^2.

The intensity of sound represents the amount of power per unit area. It is calculated by dividing the power of the sound wave by the area through which it is passing. In this case, the given power is 8.8 × 10^-4 W, and the area is 5.0 m^2. Dividing the power by the area gives us an intensity of 1.76 × 10^-4 W/m^2.

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Question 1 of 24 Click to read the passage from "Everyday Use," by Alice Walker. Then answer the question. Which of the following best describes the internal conflict in the passage? OA. Maggie doesn't know whether to feel happy or sad to see Dee. B. Maggie's scars make her feel insecure. C. Maggie and Dee are very different. D. Maggie dislikes waiting for her sister. SUBMIT​

Answers

The internal conflict in the passage is about how Maggie feels about Dee's arrival. Maggie is feeling insecure about her scars and how Dee will react to her seeing her.

The correct answer to this question is option B.

Maggie is self-conscious of her appearance due to the burns on her skin. Her scars resulted from a house fire in which she was injured while trying to save some family heirloom quilts. On the other hand, Dee is confident and proud of her African heritage.

She changed her name to Wangero, saying that Dee no longer represents her real personality. Dee has also gained a formal education, moved to a big city, and embraced new ideas while rejecting her past, which has left Maggie feeling left behind in rural life.

In conclusion, the passage's internal conflict is Maggie's insecurity about her scars and how her sister Dee will react to seeing her.

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What are the properties of mars

Answers

Answer:

Explanation:

Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth

Calculate: An object’s weight is determined by its mass (m) and the acceleration due to gravity (g) affecting that object: w = mg. On Earth, g = 9.8 m/s 2 .
What are the masses (in kilograms) of the three objects on the Gizmo? (Note: 1 N = 1 kg  m/s 2 )

Answers

We have that using the Equation \(w = mg\) we derive the various mass of the objects on the Gizmo

Example

\(14N\ object=1.42kg\\\\80N\ object=8.16\\\\98N\ object=10kg\)

From the Question we are told that

Object’s weight is determined by its mass (m) and the acceleration due to gravity (g) affecting that object: w = mg.Gravity g = 9.8 m/s 2. (Note: 1 N = 1 kg  m/s 2 )

Generally

For a Gizmo Bearing Weight of represented as integers

Say

14N,80N,98N

Therefore

For 14N

\(w = mg.\\\\14 = m*9.8.\\\\m_1=1.42kg\)

For 80N

\(w = mg.\\\\80 = m*9.8.\\\\m_2=8.16kg\)

For 98N

\(w = mg.\\\\98 = m*9.8.\\\\m_3=10kg\)

the relationship between force and acceleration verification of Newton second law of motion​

Answers

Answer:

below

Explanation:

According to Newtons Second Law of Motion, also known as the Law of Force and Acceleration, a force upon an object causes it to accelerate according to the formula net force = mass x acceleration. So the acceleration of the object is directly proportional to the force and inversely proportional to the mass.

What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2

Answers

Answer:

7.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

7.5 N

Hope this helps you

By studying ____________________ scientists have learned about the layers of the Earth.

Answers

Answer: By studying seismic waves scientists have learned about the layers of the Earth.

16/07/2021 23
question 9 of 10
homework
which movement will require the greatest amount of work to be
done?

this activity is
a force of 10n moving an object a distance of 3.0 m
b*
assessment
percentage
a force of 10n moving an object a distance of 5.0m
a force of 15n moving an object a distance of 3.0m
c attempts
a force of 15n moving an object a distance of 5.0m

Answers

D.  The movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

What is work done?

Work is said to be done when an applied force moves an object over a given distance.

W = Fd

where;

F is the applied forced is the displacement of the object

A force of 10n moving an object a distance of 3.0 m

W = 10 x 3 = 30 J

A force of 10n moving an object a distance of 5.0m

W = 10 x 5 = 50 J

A force of 15n moving an object a distance of 3.0m

W = 15 x 3 = 45 J

A  force of 15n moving an object a distance of 5.0m

W = 15 x 5 = 75 J

Thus, the movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

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Physical Appearance Bias Definition

Answers

Discrimination on the basis of the physical appearance of a person is called physical appearance bias.

Our society has constructed a notion of physical attractiveness. It is related to the quality of the social appearance. Physically attractive people are at advantage as compared to the people who are not physically attractive. Physical appearance bias is the discriminatory behavior provided by our society to the people who are not unattractive and not so good looking. This physical attribute may be the height, weight, color of the skin, etc. This perception of discrimination of our society more often results in adverse consequences.

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The earth has a mass of 5.98 × 10^24 kg and the moon has a mass of 7.35 × 10^22 kg. The distance from the centre of the moon to the centre of the earth is 3.84 × 10^8 m. A rocket with a total mass of 1200 kg is 3.0 × 10^8 m from the centre of the earth and directly in between the earth and the moon. Find the net gravitational force on the rocket from the earth and moon.

Answers

Answer:

F = 4.48N

Explanation:

In order to calculate the net gravitational force on the rocket, you take into account the formula for the gravitational force between two objects, which is given by:

\(F=G\frac{m_1m_2}{r^2}\)         (1)

G: Cavendish's constant = 6.674*10^-11 m^3kg^-1s^-2

r: distance between the objects

You have a rocket at the middle of the distance between Earth and Moon, then, you have opposite forces on the rocket.

If you assume the origin of a system of coordinates at the rocket position, with the Moon to the left and the Earth to the right, you have:

\(F=G\frac{M_em}{r_1^2}-G\frac{M_mm}{r_2^2}\)       (2)

Me: mass of the Earth = 5.98*10^24 kg

Mm: mass of the Moon = 7.35*10^22 kg

m: mass of the rocket = 1200kg

r1: distance from the rocket to the Earth = 3.0*10^8m

r: distance between rocket and Moon = 3.84*10^8m - 3.0*10^8m = 8.4*10^7m

You replace the values of the parameters in the equation (2):

\(F=Gm[\frac{M_e}{r_1^2}-\frac{M_m}{r_2^2}]\\\\F=(6.674*10^{-11}m^3kg^{-1}s^{-2})(1200kg)[\frac{5.98*10^{24}kg}{(3.0*10^8m)^2}-\frac{7.35*10^{22}kg}{(8.4*10^7m)^2}]\\\\F=4.48N\)

The net force exerted over the rocket is 4.48N

The net gravitational force on the rocket from the earth and moon is 4.48N.

The gravitational force between two objects is:

F = Gm₁m₂/r²

Where m₁, m₂, are masses, r is the distance between them and G is gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²

Let us assume that the rocket is at the origin with the Moon to the left and the Earth to the right. Hence:

\(F=G[\frac{m_em}{r_1^2} -\frac{m_mm}{r_2^2} ]\)

Where me is the mass of earth =  5.98 × 10^24 kg,

r₁ is the distance from earth to rocket = 3.0 × 10^8 m,

m is the mass of rocket = 1200 kg,

mm is the mass of moon = 7.35 × 10^22 kg,

r₂ is the distance from moon to rocket = 3.84 × 10^8 m - 3.0 × 10^8 m = 0.84 × 10^8 m

Hence:

\(F=6.67*10^{-11}[\frac{1200*5.98*10^{24}}{3*10^8}-\frac{1200*3*10^{22}}{0.84*10^8} ]\\\\F=4.48\ N\)

The net gravitational force on the rocket from the earth and moon is 4.48N.

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A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².

Answers

The distance from the axis of the force applied is 2.05 m.

What is the distance from the axis of the force applied?

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

F is the applied forcer is the distance from the axis of the force applied

Another formula for torque is given as;

τ = Iα

where;

I is the moment of inertia of the doorα is the angular acceleration;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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I need help with this practice problem solving My questions are at the top of the picDoes more tin foil mean more reflection of sunlight in the solar oven? Explain why/why not thoroughly

I need help with this practice problem solving My questions are at the top of the picDoes more tin foil

Answers

Note that:

Aluminium is good conductor of heat because of its high thermal conductivity

The solar cooker cooks food with the heat is energy absorbed from sunlight. The aluminium foil is used as a reflector in the solar oven so as to gather/trap sufficient sunlight into the box inorder to be used by the cooker.

Therefore, the presence of aluminium/tin foil in the solar oven will help speed up the rate at which heat is trapped, hence the rate at which the food gets cooked.

More tin/ Aluminium foil means more reflection of sunlight in the solar oven.

A spring has a force of 2.0N and an extension of 0.30m. What will the extension be if the force applied is 6 N.

Answers

Answer:

extension = 0.9 m

Explanation:

The formula relating force to extension for a spring is given as follows:

\(\boxed{F = kx}\),

where:

• F = force applied on spring

• k = spring constant

• x = extension of spring

From the above formula:

\(\frac{F}{x} = k = \mathrm{constant}\)

This means that, for a spring, the ratio \(\frac{F}{k}\) is a constant value. Therefore, we can say:

\(\frac{F_1}{x_1} = \frac{F_2}{x_2}\)

Substituting 2.0N and 0.30m for F₁ and x₁ respectively, and 6N for F₂, in the above equation, we can solve for x₂:

\(\frac{2.0}{0.3} = \frac{6.0}{x_2}\)

⇒ \(x_2 \times \frac{2.0}{0.3} = 6.0\)          [Multiplying both sides of the equation by x₂]

⇒ \(x_2 = 6.0 \div \frac{2.0}{0.3}\)

⇒ \(x_2= \bf 0.9 m\)

Therefore, the extension of the spring when 6N force is applied is 0.9 m.

The extension of the spring when the force applied becomes 6 N is 0.9 m.

What is the force constant of the spring?

The force constant or spring constant of the spring is calculated as follows;

F = kx

k = F/x

where;

F is the applied force on the springx is the extension of the spring

k = (2 N) / (0.3 m) = 6.67 N/m

The extension of the spring when the force applied on the spring becomes 6 N is calculated as follows;

x = F/k

x = (6 N) / (6.67 N/m)

x = 0.9 m

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Two students push on a box in the same direction and a third student pushes in the opposite direction.
What is the net force on the box if each push with a force of 50 N? (Hint: It may help to draw a picture.

Answers

Two students push on a box in the same direction and a third student pushes in the opposite direction. The net force on the box if each push with a force of 50 N is (F)= 50N.

What is force?

According to the first law of newton's law of motion when a particle is at rest it always be at rest if any external thing affect on it. That external or internal thing that helps the object move that called Force. It can be measured in Newton, Dyne.

How can we calculate the net force?

To calculate the force we have to study the question carefully. Two  students push on a box in the same direction and a third student pushes in the opposite direction. So according to the question the net force will be,

F = 2f₁-f₂

Here we know,

f₁= The amount of force that two students apply on the same direction. = 50 N.

f₂= The amount of force that students apply on the opposite direction. = 50 N.

We have to calculate the net force= F N.

Now we put the values in above equation, we get,

F = 2f₁-f₂

Or, F= 100-50

Or, F=50N

From the above calculation we can say that,  The net force on the box if each push with a force of 50 N is (F)= 50N.

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momentum? b. A student claim that he can produce linear momentum in carrom men with the help of a striker. Is his claim true? Explain. [2] inciple of conservation of linear momentum. momentum ? b . A student claim that he can produce linear momentum in carrom men with the help of a striker . Is his claim true ? Explain . [ 2 ] inciple of conservation of linear momentum .​

Answers

The claim of the student is True, he can produce linear momentum in carrom with the help of b.

To explain the principle of linear momentum we can say that:-

According to the principle of conservation of momentum, if two things collide, the total momentum before and after the impact will be the same if no external force occurs on the colliding items.

Linear momentum conservation When the net external force is zero, the momentum of the system remains constant, as expressed mathematically by the expression.

Initial momentum = final momentum

Formula of Linear momentum is:-

Linear momentum = mass × linear velocity

P = M × V

The law of momentum conservation is based on Newton's third rule of motion, which states every force has a corresponding and opposing reciprocating force.

So we understand that Principle of Linear momentum. The initial momentum is equal to final momentum after collision hence, the carrom striker follows the concept of linear momentum.

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Two bumper cars are driven toward each other. The initial momentum of bumper car 1 is 250. 0 kg and the initial momentum of bumper car 2 is –320. 0 kg. M/s. After the cars collide, the final momentum. Of bumper car 1 is –311 kg. M/s

What is the magnitude of the final momentum of bumper car 2?
Your answer should have three significant figures. ​

Answers

The final momentum of bumper car 2 is -241.0 kgm/s.

The magnitude of the final momentum of bumper car 2 can be found using the conservation of momentum principle, which states that the total momentum of a closed system remains constant before and after a collision.

To calculate the final momentum of bumper car 2, we can use the following equation:

initial momentum of system = final momentum of system

250.0 + (-320.0) = (-311.0) + final momentum of bumper car 2

-70.0 = (-311.0) + final momentum of bumper car 2

final momentum of bumper car 2 = -241.0 kgm/s

The final momentum of bumper car 2 is -241.0 kgm/s.

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An engine produces 240 KJ of energy in 2.0 minutes. What is the power output of the engine?​

Answers

The power output of an engine is given by the equation:

Power = Energy / Time

Where Power is measured in Watts, Energy is measured in Joules, and Time is measured in seconds.

First, we need to convert the energy from KJ to J, since the SI unit of energy is Joules. Therefore,

240 KJ = 240,000 J

Next, we need to convert the time from minutes to seconds. Therefore,

2.0 minutes = 2.0 x 60 seconds = 120 seconds

Now we can calculate the power output of the engine by plugging in the values:

Power = Energy / Time

Power = 240000 J / 120 s

Power = 2000 W

Therefore, the power output of the engine is 2000 W (or 2.0 kW).

How does adding thermal energy to solid ice affect the molecules in the ice? Describe what happens to both their motion and spacing.

Answers

Once ice has been taken out of the freezer, its molecules start to travel more quickly when heat energy is supplied.

Motion and spacing Given that the ice is substantially colder than the air outside the freezer, heat energy will transfer from the air to the ice. The molecules' kinetic energy is increased by the heat input, which weakens the ice's structure. Hydrogen bonds that were keeping the ice together start to disintegrate when the ice warms up further, causing molecules to migrate more quickly. In time, the molecules will travel so swiftly that the ice will experience a phase shift and convert into water.

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an object has a -6 c charge. the object breaks into two pieces. one piece has a charge of -3 c. what is the exact charge (in c) of the other piece? do not include units with your answer.

Answers

The exact charge of the other piece is -3C.

Since the object had a charge of -6 C, the total charge of the two pieces must still be -6 C after breaking. If one piece has a charge of -3 C, then the other piece must have a charge of -6 C - (-3 C) = -6 + 3 = -3 C.

In other words, the total charge of the two pieces is equal to the original charge of the object, and the charges of the pieces add up to the original charge.It's important to note that the charge of an object is a scalar quantity and is conserved during any physical or chemical process. This means that the total charge of a system remains constant, regardless of the processes that take place within it. The principle of charge conservation is a fundamental law of physics, and it is closely related to the principles of energy and momentum conservation.

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A skateboarder is riding in an empty swimming pool.
How is the potential energy of the skater changed to kinetic energy?
As the skater accelerates down the side of the pool, potential energy is conserved.
As the skater prepares to go down the side of the pool, kinetic energy is changed into potential energy.
As the skater goes down one side of the pool and up the other, potential energy changes to kinetic energy.
As the skater rests at the bottom of the pool, potential energy is gained.

Answers

Answer:As the skater goes down one side of the pool and up the other, potential energy changes to kinetic energy. At the top of the pool, the skateboarder has the most potential energy and the least kinetic energy, and at the bottom of the pool, the skateboarder has the most kinetic energy and the least potential energy. As the skateboarder rides down the side of the pool, the potential energy is converted into kinetic energy, causing the skateboarder to accelerate. At the bottom of the pool, all the potential energy has been converted to kinetic energy. As the skateboarder goes up the other side of the pool, the kinetic energy is gradually converted back into potential energy, causing the skateboarder to slow down and eventually come to a stop at the top of the other side.

Explanation:

which one of the following questions cannot be answered by the egg drop interactive? (7 points) what affect does rebounding have upon the safety of an egg as it lands? what affect does the size of an egg have upon its impact force upon landing? what affect does the nature of a surface have upon the impact force of an egg that lands upon it? what affect does the height from which an egg falls have upon the velocity change it will encounter upon impact?

Answers

The question that cannot be answered by the egg drop interactive is "What effect does the nature of a surface have upon the impact force of an egg that lands upon it?"


The egg drop interactive allows for the manipulation of variables such as height, velocity, and egg size, but it does not provide a way to change the surface upon which the egg lands. Therefore, it cannot provide information on how the nature of a surface affects the impact force of an egg.

The egg drop interactive allows users to explore how changing certain variables affects the outcome of an egg drop experiment. For example, users can change the height from which the egg is dropped and observe how it affects the velocity and impact force upon landing. They can also change the size of the egg and see how it affects the force of impact. However, because the surface upon which the egg lands cannot be changed, the interactive cannot provide information on how the nature of a surface affects the impact force of an egg.

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After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work. What type of circuit does this traffic situation model?

Answers

Answer:

C

Explanation:

a parallel circuit because there is more than one path

Answer:

C) a parallel circuit because there is more than one path

Explanation:

EDGE 2022

a body falls freely from rest.calculate it's acceleration


Answers

Answer:

10 m/s²

Explanation:

Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.

∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².

Answer:

10 m/s^2 I hope it helps u a lot

The Keck Telescope has a diameterof 10.0 m. When it is looking atMars, 7.38 1010 m from us, how farapart are the closest objects it couldpossibly resolve? Assume the lighthas wavelength 633 nm.[?] m

Answers

Given:

Diameter, D = 10.0 m

Distance, x = 7.38 x 10¹⁰ m

Wavelength, λ = 633 nm

Let's find how far apart the closest objects it could possibly resolve.

First, apply the formula for the angle for angle separation (limit of resolution):

\(\theta=\frac{1.22\lambda}{D}\)

Thus, we have:

\(\begin{gathered} \theta=\frac{1.22*633\times10^{-9}}{10.0} \\ \\ \theta=\frac{7.7226\operatorname{\times}10^{-7}}{10.0} \\ \\ \theta=7.7226\operatorname{\times}10^{-8}\text{ rad} \end{gathered}\)

Now, to find the distance of the closest objects, we have:

\(d=\theta *x\)

Thus, we have:

\(\begin{gathered} d=7.7226\times10^{-8}*7.38\times10^{10} \\ \\ d=5699.28\text{ m} \end{gathered}\)

Therefore, the distance of the closest objects is 5699.28 meters.

• ANSWER:

5699.28 m



A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting

from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,

and air resistance can be ignored. Find

a) the maximum height above the ground the rocket reaches

Answers

Answer:

The maximum height above the ground the rocket reaches is 123.1 m.

Explanation:

Let's find the final velocity at a distance of 200 m:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

Where:

\(v_{f}\) is the final speed =?

v₀ is the initial speed =0

a is the acceleration = 1.25 m/s²

d is the distance = 200 m

\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)    

Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:

\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)

Where:

\(v_{f}\) = 0

\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)

Finally, the maximum height above the ground is:

\( h_{max} = h + H \)

Where H is the vertical component of the 200.0 meters.

\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)

Therefore, the maximum height above the ground the rocket reaches is 123.1 m.

I hope it helps you!                                                          

If it takes a P wave five minutes to travel from the epicenter to a seismic station, approximately how long will it take an S wave to travel that same distance

Answers

Answer:

9 minutes to take an S wave to travel that same distance.

It take approximately 9 minutes for an S wave to travel that same distance that P wave travel in 5 minutes.

What is P wave?

P waves, are the first waves to arrive at a seismograph.

What is S wave?

An S wave, or shear wave, is a seismic body wave that shakes the ground back and forth perpendicular to the direction the wave is moving.

S-wave is about 1.73 times slower than the P-wave.

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When a chemical reaction occurs in a sealed container, what is the total mass after the reaction compared to the total mass before the reaction? A.
the same

B.
less

C.
more

D.
variable

Answers

A, When a chemical reaction occurs in a sealed container, the mass of the materials in the container stays the same. A chemical reaction is taking place in a sealed container.

The statement of the total mass after the reaction is "the same."

What is a chemical reaction?

When one or more chemicals are transformed into one or more other compounds, a chemical reaction occurs.

What is mass?

A substance is something to do with mass that takes up space. The mass of a compound is the total amount of atoms present in grams that make up a molecule. The grams is the unit of mass.

The principle which implies that the mass of matter in a closed system will remain constant regardless of the type of change that occurs. The amount of mass will not change whether it is due to a change in condition, dissolving, a chemical reaction, or any combination of these. Because the number of each type of atom remains constant, the mass will remain constant.

Hence the correct answer is A.

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