7. How many kilograms are equal to 3.3 scruples?

Answers and explanations:

1) Lead, it is heavier than iron.

2) Lead, since it's heavier, it would have more mass and therefore more atoms.

3) (for sodium) 82.03379 gram x 6.23= 511.070512 grams= 417.05 pounds

(for sucrose) 342.29648(one molar)  x .65= 0.4 pound

The sodium would be heavier (not sure if accurate)

4) Because atoms are way too small to count, therefore we use molar masses.

The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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The freezing point of a solution of 60.0 g of glucose, dissolved in 80.0 g of water is  -7.67 ⁰C

Freezing point is the temperature at which a liquid turns into a solid. In theory, the melting point of a solid should be the same as the freezing point of the liquid.

At freezing point, these two phases viz. liquid and solid exist in equilibrium i.e. at this point both solid state and liquid state exist simultaneously. The freezing point of a substance depends upon atmospheric pressure.

Given,

Mass of Glucose = 60g

Mass of water = 80g

Moles of glucose = 60/ 180 = 0.33 moles

Molality = number of moles of glucose / mass of water in kg

= 0.33 / 0.08

= 4.12 molal

Depression in freezing point = Kf × molality

= 1.86 × 4.12

= 7.67 K

Freezing point of pure water = O⁰C

Freezing point of glucose = 0 - 7.67

= -7.67 ⁰C

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c is the correct answer

The correct answer is option A: Subtract the atomic number from the mass number.

An atom is composed of a proton, a neutron and an electron. These are collectively called subatomic particles.

The proton and neutron are found in the nucleus of the atom, surrounded by electrons.

The atomic number is the same as the number of protons in the atom or the number of electrons in the neutral atom.

The mass number is the sum of the number of protons and the number of neutrons in the atom.

Hence, to obtain the number of neutron, we subtract the atomic number from the mass number.

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Answer:

white

Explanation:

Answer:

Magnetic Forceeeeeeeeeee

Answer: 25 moles

Explanation:

I remember learned this in last year AP Chemistry class

A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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Answer:

I think nuetron stars

Explanation:

log1.429V=3.20  volume (to the nearest 0. 1 ml) of 4. 70-m NaOH must be added to 0. 700 l of 0. 250-m HNO2 to prepare a ph = 3. 20 buffer

pH= pKa +log {[ NaOH ] / [ HNO2 ]​}

3.20=3.80+log{(V×4.70)/ ( 0.700×0.250)}

3.20=log1.429V

Volume will be 3.20=log1.429V

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The number 8.00 represents oxygen with three significant figures  because oxygen is being used and CO2 is produced as a byproduct. The balanced equation for C2H6 + O2 --> CO2 + H2O is as follows:2 C2H6 + 7O2 --> 4CO2 + 6H2O

Oxygen to two significant figures: The number 8.0 represents oxygen with two significant figures.Sodium to three significant figures: The number 22.99 represents sodium with three significant figures.Oxygen to two decimal places:

The number 8.00 represents oxygen with two decimal places. The balanced equation shows that in order to produce 4 molecules of CO2, 2 molecules of ethane react with 7 molecules of O2 to produce 6 molecules of H2O as well.  , where the last zero is considered to be significant. combustion occurs

This reaction shows that combustion occurs because oxygen is being used and CO2 is produced as a byproduct.

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The mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

The mass of an object can be calculated using the following formula:

F = ma

Where;

m = F/a

m = 356/4

m = 89kg

Therefore, the mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

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This principle is important in laboratory reports because it can be used to determine an object's or material's density, which is an important physical property used in many applications.

The Archimedes' principle is a fundamental physics principle that states that the buoyant force acting on an object submerged in a fluid equals the weight of the fluid displaced by the object. It is critical to use the Archimedes' principle in a lab report to accurately and precisely determine the density of the object or material being studied. This principle provides a dependable and accurate method for calculating density, which is useful in many scientific and engineering fields. By including the Archimedes' principle in a lab report, you show that you considered all relevant factors and used appropriate methods to determine the physical properties of the materials being studied.

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Answer: .04544 or 4.544 x 10^-2

Explanation: Simply divide 923.0 by 20312. Use 4 significant figures because it is the least amount of significant figures present in your calculation.

The answer for the given equation in significant figures is 0.045.

The number of digits in a value, often a standard measure, that make a contribution to the precision of the value is referred to as significant figures. The first non-zero digit is used to begin counting significant figures.

All zeros to the right and left of a decimal point are never significant. For example, the number 0.00798 had three significant digits.

In the given equation, let us assume the number is X.

X = 923.0/20312

X = 0.0454.

Thus, the answer is 0.045.

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The specific heat capacity of the given material is approximately 0.00353 J/g.K.

The given information of the specific heat capacity of a material, mass, and the temperature change can be used to find the specific heat capacity of the material.

The specific heat capacity of a material is the amount of heat energy required to raise the temperature of one unit mass of the material by one degree Celsius or Kelvin.

The formula to calculate specific heat capacity is given byq = m × c × ΔT

where, q = heat energy, m = mass of the substance, c = specific heat capacity of the substance, and ΔT = change in temperature of the substance.

Rearrange the formula to find the specific heat capacity of the substance:

c = q / (m × ΔT)

The given values are:

Heat energy, q = 400 J

Mass, m = 190 g

Temperature change, ΔT = 71 K

Substituting the given values in the formula:

c = 400 / (190 × 71)≈ 0.00353 J/g.K

Therefore, the specific heat capacity of the given material is approximately 0.00353 J/g.K.

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Reaction takes place is

2KClO3 --> 2KCl + 3O2

from above equation 2 moles of potassium chlorate is forming 3 moles of Oxygen gas.

now given 6.83 moles of oxygen and moles of potassium chlorate is missing,

consider x moles of potassium chlorate are needed to form 6.83 moles of oxygen

from above condition, .

3 》》》》2

x 》》》》6.83

3/x = 2/6.83

x = 3×6.83/2

x= 10.245

Answer- 10.245 moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas.

decay rate of approximately 1.69x10^17 Bq (becquerels),

The decay rate of a radioactive sample is determined by the number  of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.

To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.

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Answer:

The correct answer is - 75 grams.

Explanation:

Half-life is the amount of time that is used by the given amount of substance or element to make it half of the initial amount of a particular radioactive substance.

Equation for alpha decay for radon

\(^222_{86}Rn\Rightarrow^{218}_{84}Po  \)

we need to calculate the left amount of radon after given time

using formula half life

\(N(t)=N_{0}e^{-\lambda t}\)

\(\lambda =\dfrac{0.693}{3.82}\)

\(\lambda=0.1814\)

\(N(3.82)=150\times e^{-0.1814\times3.82}\)

\(N(3.82)=75.0\ g\)

Thus, the left amount of radon is - 75 grams.

1. Reduction half reaction (or cathode reaction):-

Ag+(aq)  +  e-  ---------> Ag(s)..........(1)

2. Oxidation half reaction (or anode reaction) :-

Sn(s) --------> Sn2+(aq) + 2e-  ............(2)

3. Overall reaction :-

2*(1) + (2)

or, 2Ag+(aq) + Sn(s)  --------> 2Ag(s) + Sn2+(aq)

A galvanic cell, often known as a voltaic cell after the scientists Luigi Galvani and Alessandro Volta, is an electrochemical cell in which an electric current is created by spontaneous Oxidation-Reduction events. A voltaic cell is an electrochemical cell that uses a chemical process to generate electrical energy. The oxidation and reduction processes are split into half-cell sections.

To create an electric current, galvanic (or voltaic) cells employ a thermodynamically advantageous redox process. Each half-reaction occurs in its own compartment, or half-cell, which contains an electrode. The anode is the electrode where oxidation happens, while the cathode is the electrode where reduction occurs.

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Answer: 31.5L

Explanation:

Ideal gas law is valid only for ideal gas not for vanderwaal gas. The equation used is PV=nRT. Therefore the volume of oxygen gas is 31.5L.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of oxygen gas =78.5 kPa=78,500=0.7747atm

V= volume of oxygen gas=?

n =number of moles of oxygen gas = given mass÷ Molar mass

                                                          = 32.0g÷ 32

                                                          =1 mole

T =temperature of oxygen gas=298K

R = Gas constant = 0.0821 L.atm/K.mol

0.7747atm×V=1 mole×0.0821×298K

V=31.5L

Therefore the volume of oxygen gas is 31.5L.

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The reaction is thermodynamically favored because it releases energy, which is indicated by the negative value of the change in enthalpy (∆H) of the reaction. This means that the products have a lower enthalpy than the reactants, making the reaction spontaneous and energetically favorable.

Additionally, the decrease in the disorder or randomness of the system (negative ∆S) is outweighed by the decrease in enthalpy, resulting in a negative change in Gibbs free energy (∆G) and indicating that the reaction will proceed in the forward direction.

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> 2.40 g of NaOH can be used to produce 6.36 g of Na2CO3 through a reaction. To determine the number of grams of Na2CO3 that can be prepared from 2.40 g of NaOH, we need to consider the stoichiometry of the reaction between NaOH and Na2CO3.

By calculating the molar mass of NaOH and Na2CO3 and applying the appropriate conversion factors, we can determine the amount of Na2CO3 that can be obtained.

The balanced chemical equation for the reaction between NaOH and Na2CO3 is:

2 NaOH + Na2CO3 → 2 Na2CO3 + H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of Na2CO3 to produce 2 moles of Na2CO3.

First, we need to calculate the molar mass of NaOH and Na2CO3:

NaOH: Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 39.99 g/mol

Na2CO3: Na (22.99 g/mol) + C (12.01 g/mol) + 3 O (16.00 g/mol) = 105.99 g/mol

Next, we can set up the following proportion:

2.40 g NaOH / 39.99 g/mol NaOH = x g Na2CO3 / 105.99 g/mol Na2CO3

Solving for x, we get:

x = (2.40 g NaOH / 39.99 g/mol NaOH) * (105.99 g/mol Na2CO3)

Calculating the value of x, we can determine the number of grams of Na2CO3 that can be prepared from 2.40 g of NaOH.

Note: Remember to perform the actual calculations using the given values in order to obtain the specific result.

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The average rate of disappearance of CH3NC over the time period from t = 342 s to t = 513 s is -2.92×10-5 M s-1.

To calculate the average rate of disappearance of CH3NC over the time period from t = 342 s to t = 513 s, we can use the formula:

Average rate = (change in concentration) / (change in time)

First, we need to calculate the change in concentration of CH3NC over the time period from t = 342 s to t = 513 s:

[CH3NC]342s = 9.96×10-3 M

[CH3NC]513s = 5.97×10-3 M

Change in concentration = [CH3NC]513s - [CH3NC]342s

= 5.97×10-3 M - 9.96×10-3 M

= -4.99×10-3 M

(Note that the concentration has decreased, so the change in concentration is negative)

Next, we need to calculate the change in time:

Change in time = 513 s - 342 s

= 171 s

Now we can calculate the average rate of disappearance of CH3NC:

Average rate = (change in concentration) / (change in time)

= (-4.99×10-3 M) / (171 s)

= -2.92×10-5 M s-1

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6 g/cm³

Hi there !

density formula

d = m/V

V = 33.0ml - 25.0ml = 8.0 ml = 8 cm³

m = 48.0 g

replace

d = 48g/8cm³ = 6 g/cm³

Good luck !

Answer:

Mg (s) + 2HCI2 (aq) → MgCI2 (aq) + H2 (g)

I think this is the correct answer I not a 100% sure if it is correct.

Explanation:

Guessing

We have that for the Question, it can be said that the percentage of arsine molecules have de- composed is

Percentage of arsine molecules=79.62%

From the question we are told

A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which temperature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?

Answer in units of %

.

Generally the equation for the ideal gas   is mathematically given as

\(PV=nRT\\\\Therefore\\\\(\frac{296}{760})*(0.465)=n*0.0821*213\\\\n=0.010356\\\\\)

Hence

\(\frac{511}{760}*0.6165=nf*0.0821*263\\\\nf=0.014479\\\\0.010356-2x+3x=0.014479\\\\X=0.004123moles\\\\\)

Therefore

\(Percentage\ of\ arsine\ molecules=\frac{0.004123*2}{0.010356}*100\)

Percentage of arsine molecules=79.62%

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Answer:

Empirical formula: CH₂

Explanation:

We need to find the empirical formula of a compound that has carbon and hydrogen.

To find the empirical formula of any compound, if we have the mass or mass percent, we should follow 3 steps:

1. Calculate the moles, dividing by the atomic weight.

The atomic weight for carbon and hydrogen are 12 g/mol and 1 g/mol, so, doing the division we have:

C = 85.5 / 12 = 7.125

H = 14.3 / 1 = 14.3

2. Determine the number of atoms of each element in the formula

To do this, we just divide the previous moles by the lowest quantity we obtain. In this case, the carbon:

C = 7,125 / 7,125 = 1

H = 14,3 / 7,125 = 2

This means we have 1 atom of carbon and 2 atoms of hydrogen.

3. Write the empirical formula with the previously obtained atoms

Now that we obtained the atoms of each element, we just write the empirical formula with these numbers:

C₁H₂  but we can neglect the number one so:

Hope this helps

Answer:

glcolysis

Explanation:

Glcolysis uses glucose to create ATP within the cytoplasm of the cell.

Answer:

the answer is glycolysis

Explanation:

Scientists refer to the long-term alteration in ocean chemistry caused by CO2 absorption from the environment as ocean acidification.

The reaction can be expressed as:

\(CO_{2}\) + \(H_{2} O\) → (\(H^{+}\)) +. (\(HCO3^{-}\)).

Ocean acidification is a process that happens when the water absorbs too much carbon dioxide. In the equation,  \(CO_{2}\) represents carbon dioxide. The  \(CO_{2}\) in the equation represents the water molecules in which the carbon dioxide reacts.

Ocean acidification is the term for a long-term decrease in the ocean's pH that is mostly brought on by the ocean's absorption of carbon dioxide (  \(CO_{2}\)) from the atmosphere.

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