2. Some ionic compounds are hydrates—solid compounds to which is bound a specific


percentage of water. Some hydrates melt when heated and release energy when they


solidify. For example, at 32 °C, liquid Glauber's salt-sodium sulfate decahydrate,


Na S04:10 H,00)—solidifies and releases 78. 0 kJ/mol of energy. Calculate the


enthalpy change when 2. 50 kg of Glauber's salt enters the solid state?

The Value of x in the hydrate is D. 10.

To find the value of x in the hydrate \(Na_{2}SO_{4}\) * x \(H_{2}O\) , we need to determine the amount of water lost during heating and relate it to the moles of anhydrous \(Na_{2}SO_{4}\) .

First, let's calculate the mass of water lost:

Mass of water = Mass of hydrate - Mass of anhydrous \(Na_{2}SO_{4}\)

Mass of water = 3.22 g - 1.42 g = 1.80 g

Next, we'll convert the mass of anhydrous and water to moles using their respective molar masses ( \(Na_{2}SO_{4}\)= 142 g/mol, \(H_{2}O\) = 18 g/mol):

Moles of \(Na_{2}SO_{4}\)= 1.42 g / 142 g/mol ≈ 0.0100 mol

Moles of  \(H_{2}O\)= 1.80 g / 18 g/mol = 0.1 mol

Now, we'll find the ratio of moles of water to moles of \(Na_{2}SO_{4}\):

x = Moles of \(H_{2}O\) / Moles of \(Na_{2}SO_{4}\)

x ≈ 0.1 mol / 0.0100 mol = 10

The value of x in the hydrate \(Na_{2}SO_{4}\) * x \(H_{2}O\) is approximately 10. Therefore, the correct answer is D. 10.

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Explanation:

According to orbital hybridization theory, in ethene the C atoms are using sp2 hybrid orbitals. This leaves one unhybridized p orbital available to form the second bond (Pi bond) in the C-C double bonds.

One sp2 hybrid orbital from each C atom overlap to form one sigma bond between the two carbon atoms. One p orbital from each C atom then overlap to form a pi bond that completes the C-C double bond. The H atoms are bonded via sigma bonds to the C atoms when the H s orbitals overlap with the remaining sp2 hybrid orbitals from each C.

The molarity of NaOH is calculated to be 0.079 mol/L. It is important to include the correct unit of molarity,

The given information states that the mass of KHP is 0.325 g and the volume of NaOH used is 20.15 mL. To find the molarity of NaOH, we can use the formula: Molarity = number of moles of NaOH / Volume of NaOH in liters. The number of moles of NaOH can be determined by the number of moles of KHP used in the neutralization reaction, as per the balanced chemical equation: KHP + NaOH → NaKP + H2O. In this equation, 1 mole of KHP requires 1 mole of NaOH for neutralization.

To calculate the number of moles of KHP, we divide the mass of KHP by its molar mass. The molar mass of KHP (C8H5KO4) is 204.22 g/mol. Therefore, the number of moles of KHP is 0.325 g / 204.22 g/mol = 0.001591 mol.

Since the stoichiometry of the reaction indicates that the number of moles of NaOH is the same as the number of moles of KHP, the number of moles of NaOH is also 0.001591 mol.

The volume of NaOH used is given as 20.15 mL, which needs to be converted to liters by dividing by 1000. So, the volume of NaOH is 20.15 mL / 1000 = 0.02015 L.

Substituting these values into the formula for molarity, we get Molarity = 0.001591 mol / 0.02015 L = 0.079 mol/L.

Therefore, the molarity of NaOH is calculated to be 0.079 mol/L. It is important to include the correct unit of molarity, which is mol/L or M, in the answer.

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A sample of gas to behave most ideally (act as an ideal gas) at low pressure and high temperature.

A gas will behave most ideally (act as an ideal gas) under the following conditions:

Overall, these conditions allow for the assumption that gas molecules are point masses with no volume and that they do not interact with each other.

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Answer 2, 3, 2

Explanation:

Answer:

Explanation:

Understand that the graph of an equation in two variables is the set of all its solutions plotted in the coordinate plane, often forming a curve (which could be a line).

A proportional equation y=kx where k is the so-called "constant of proportionality".

The balanced oxidation half equation is given below:

Oxidation reactions are reactions in which the oxidation of the species increases.

Oxidation reactions can involve addition of oxygen or electronegative elements to a substance or the removal of hydrogen or electropositive elements from a substance.

The balanced half-reaction for the oxidation of solid manganese dioxide to permanganate ion in acidic aqueous solution is given below:

MnO₂ + H₂O → MnO₄⁻ + H⁺ + 3 e⁻

In conclusion, the balanced oxidation half equation shows that three electrons were lost by the manganese (iv) ion to form manganese (vii) ion.

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Al(NO3)3 solution concentration and the concentration of H3O+ ions in the solution following the addition of HNO3 are given in the problem. We can determine the presence of [Al(H2O)5(OH)2+] in the solution using this knowledge along with the known equilibria for the hydrolysis of Al3+.

For Al3+, the hydrolysis process may be expressed as follows:

Al(H2O)63+ + water becomes Al(H2O)5(OH)2+ + H3O+.

The reaction's equilibrium constant expression is as follows:

Al(H2O)5(OH)2+) = K

Al(H2O)63+ / [H3O+]

We must take into account the dissociation of Al(NO3)3 in water in order to determine [Al(H2O)5(OH)2+] in a 0.15 M solution of Al(NO3)3:

Al3+ (aq) + 3NO3- Al(NO3)3 (s) (aq)

Al3+ has a concentration of 0.45 M (3 times that of the Al(NO3)3 solution) in an Al(NO3)3 solution with a concentration of 0.15 M. H3O+ is present in the solution at a concentration of 0.10 M.

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Answer:

oxygen atoms

hope this helps:)

Answer:

A) Chemical Change

Explanation:

Chemical changes occur when bonds are broken and formed between molecules or atoms. This means that one substance with a particular set of properties (such as melting point, color, taste, etc.) is turned into a different substance with different properties.

Explanation:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral. ... Chemically, we say that the atoms have formed bonds.

Therefore, if the volume of sulphur hexafluoride is increased to 8.150 litres, the final temperature is 0.106 o C.

The inorganic compound Sulphur hexafluoride, sometimes known as sulphur hexafluoride, has the formula SF6. It is a gas that has no colour, no smell, is not combustible, and is not harmful. Six fluorine atoms are joined to a sulphur atom in the middle of the compound SF 6, which has an octahedral structure. It is a molecule with a high valent. An artificial, odourless gas called SF6 is utilised in the energy sector to maintain the security and dependability of networks. Because it is highly stable, non-toxic, inflammable, and electronegative, it won't combine with other substances that would change how it behaves or how effective it is.

It is a strong greenhouse gas with a great potential to contribute to global warming, and its concentration in the earth's atmosphere is rising quickly. Under electrical stress, SF6 breaks down during its working cycle, creating hazardous metabolites that represent a health risk to working employees in the event of exposure.

PV = nRT

R is a constant, pressure is assumed to be constant, and moles and n are, of course, constants.

Direct variation is now the only option.

final temperature and volume

V = kT

final temp and volume

v = kt

I believe this concept is known as Charles' law.

V/v = T/t

7.600 x 10-1 × 8.150= 5.817 x 101 / t

0.76×8.150=58.17×t

t = 0.106 o C

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Answer: True

Explanation: The value of the equilibrium constant indicates whether or not a reaction is favorable. Reactions for which Keq is greater than one are favorable, meaning that the reactants are higher in energy than the products and signifying that energy is released as the reaction proceeds.

Answer:0.100

Explanation:

Answer:

AlI3

Ag2O

k3N

Ca3(PO4)2

MgF2

Answer: Employments of friction based electricity incorporate contamination control, Xerox machines, and painting. They utilize the property that inverse electrical charges pull in. There are different utilizations including the properties of aversion and the making of electricity produced via friction flashes

friction based electricity is an awkwardness of electric charges inside or on the outside of a material. The charge stays until it can move away through an electric flow or electrical release.

In view of similar kinds of examinations like the one you performed, researchers had the option to set up three laws of electrical charges: Inverse charges pull in one another. Like charges repulse one another. Charged items pull in nonpartisan articles.

The pressure exerted by only the hydrogen gas is 735.5 mmHg, the pressure can be determined by the Dalton's Law of Partial Pressure.

In this case, the total pressure is given as 753 mmHg, which is the sum of the partial pressures of the hydrogen gas and the water vapor. Since the hydrogen gas is collected over water, we know that some of the water vapor is also contributing to the total pressure.

To account for this, we need to subtract the vapor pressure of water at 20.0°C from the total pressure. According to a vapor pressure chart, the vapor pressure of water at 20.0°C is 17.5 mmHg.

So, the partial pressure of the hydrogen gas can be calculated as:

Partial pressure of hydrogen gas = Total pressure - Vapor pressure of water

Partial pressure of hydrogen gas = 753 mmHg - 17.5 mmHg

Partial pressure of hydrogen gas = 735.5 mmHg

To determine the pressure exerted by only the hydrogen gas, we need to use Dalton's Law of Partial Pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas.

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The mass of magnesium chloride produced is 392 g if we start with 100.g of magnesium.

The quantity of matter present in an object is determined by its mass, which is a fundamental attribute of matter. It is a scalar quantity and is denoted by the letters g or kg (kg). Weight, which is the force of gravity acting on an object and which varies depending on the gravitational field, is distinct from mass.

The reaction's chemically balanced equation is as follows:

Mg + 2HCl → MgCl₂ + H₂

This demonstrates that when one mole of magnesium (Mg) is combined with two moles of hydrochloric acid (HCl), one mole of magnesium chloride (MgCl2) and one mole of hydrogen gas (H2) are produced.

We need to know how many moles of magnesium there are in 100.0 g of magnesium in order to determine the mass of magnesium chloride produced. Magnesium has a molar mass of 24.31 g/mol, therefore

moles of Mg =  mass of Mg / molar mass of Mg

Moles of magnesium = 100.0 g / 24.31 g/mol.

Moles of Mg = 4.11 mol.

One mole of magnesium interacts to create one mole of magnesium chloride, according to the balanced equation. As a result, 4.11 moles of magnesium chloride were also created.

Magnesium chloride has a molar mass of 95.21 g/mol. Hence, the amount of magnesium chloride that is created is:

Mass of MgCl2 =  moles of MgCl2 x  molar mass of MgCl2

Mass of MgCl2= 4.11 mol x 95.21 g/mol

Mass of MgCl2 = 392 g.

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Answer:

1.058337 grams of hydrogen and 2H2 + O2 ==> 2H2O hydrogen peroxide

mols H2 = grams/molar mass

Using the coefficients in the balanced equation, convert mols H2 to mols O2.

Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.

and it could also produce H2O water but no air but it could make other things

When reactants are mixed and heated in an esterification reaction, a liquid product is formed along with other byproducts.

When reactants are mixed and heated in an esterification reaction, a liquid product is formed along with other byproducts. Esterification is a chemical reaction between an alcohol and a carboxylic acid, often catalyzed by an acid catalyst such as sulfuric acid. The reaction produces an ester and water as byproducts.

During the reaction, the alcohol and carboxylic acid are mixed together and heated. The acid catalyst is added to speed up the reaction. As the reaction proceeds, the ester and water are formed. The ester is a liquid, while water is a gas at the reaction temperature.

The liquid product that collects in the side of the apparatus is the ester that is being produced. This liquid can be separated from the reaction mixture and purified using various techniques, such as distillation or extraction. The byproduct water can also be removed by distillation or other means. The ester that is produced can have a wide range of applications, such as in the production of perfumes, flavorings, and plastics.

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Answer:

hibernation

hard outer skin to reduce loss of water

Explanation:

I got a few potins for this, but...yeah.

Adaptations that help animals live in the deciduous forest biome hibernation and hard outer skin to reduce loss of water.

A deciduous forest is a type of forest which is dominatred by the trees that lose their leaves seasonally or in the growing season and Earth has dry forests.

Hibernation is a process in which plants or animals adapt themselves in order to survive in the adverse condition to conserve energy. At the same time animals will try to hard their outer skin to reduce the loss of water in the summer season.

Hence correct options are (2) & (3).

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Answer:

1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃

Explanation:

The given reaction is a double decomposition (metathesis) reaction. A reaction in which the products are formed by the exchange of the ions present in the two reactants. NaCL and AgNO₃ exchange ions to form AgCl, which precipitates and NaNO₃.

The balanced equation for reaction is given below;

NaCl(aq) + AgNO₃(aq) ----> AgCl(s) + NaNO₃(aq)

In the reaction above, the mole ratio of the reactants to products is 1 : 1 ---> 1 : 1

This means that 1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃.

Given the molar mass of the compounds above;

NaCl = 58.5 g/mol; AgNO₃ = 170 g/mol; AgCl = 143.5 g/mol; NaNO₃ = 85 g/mol

Therefore, 58.5 g of NaCl reacts with 170 g of AgNO₃ to produce 143.5 g of AgCl and 85 g of NaNO₃

The ideal gas law formula is used to determine the missing values in questions. When dealing with problems that require solving for missing values using the ideal gas law formula, always ensure that all values are expressed in the correct units and temperature is converted to kelvin.

The ideal gas law formula is represented as PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, T represents the temperature in kelvin, and R represents the universal gas constant. Solve for missing values using the ideal gas law formula:1. 10°C, 5. 5 L, 2 mol, __ atm.The temperature must be converted to kelvin first: T(K) = T(°C) + 273.15K = 10°C + 273.15 = 283.15KPV = nRT

Rearrange the equation to isolate P: P = nRT / V

Substitute the given values:

P = (2 mol)(0.0821 L•atm/mol•K)(283.15K) / 5.5 L

: P = 8.28 atm

2. __ °C, 8. 3 L, 5 mol, 1. 8 atm.The equation PV = nRT can be rearranged to T = PV / nRThe temperature must be converted to kelvin first: T(K) = T(°C) + 273.15T = PV / nR

Substitute the given values: T = (1.8 atm)(8.3 L) / (5 mol)(0.0821 L•atm/mol•K)T(K) = T +

: T = 332 K or 59°C

The temperature must be converted to kelvin first:

T(K) = T(°C) + 273.15K

= 12°C + 273.15

= 285.15

KPV = nRT

Solve for n by rearranging the equation: n = PV / RT

Substitute the given values: n = (1.2 atm)(3.4 L) / (0.0821 L•atm/mol•K)(285.15K): n = 0.141 mol

The ideal gas law formula is used to determine the missing values in questions. When dealing with problems that require solving for missing values using the ideal gas law formula, always ensure that all values are expressed in the correct units and temperature is converted to kelvin.

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The % ionization of a 2.00 m aqueous solution of the base is 0.0022%

What is pOH ?

It is a measure of the hydroxide ion (OH-) concentration of a solution. Therefore, it can be used as an indicator of the alkalinity of a substance and, in some cases, also as an indicator of electrical conductivity. pOH is the negative logarithm of hydroxide ion content and is given by the formula:

pOH = 14 - pH

OH = Kw /OH+

where Kw = self-ionization content of water.

Applying the logarithm on both sides, the more general form of the equation is: In relation to corrosion, pOH can be used as an indicator of electrolyte conductivity in galvanic cells. The conductivity of a solution depends on the concentration of ions that act as charge carriers. The higher the concentration of OH ions, the stronger the alkalinity, the higher the conductivity of the electrolyte, and the higher the rate of galvanic corrosion.

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Approximately 8,199.30 grams or 8.1993 kg of Cl would be emitted into the atmosphere each year if the Freon leak were allowed to continue.

To determine the amount of Cl (chlorine) emitted into the atmosphere each year due to the Freon leak, we need to consider the molar mass and molecular structure of CHF2Cl (Freon-22).

The molar mass of CHF2Cl is approximately 86.47 g/mol. Given that 20 kg of CHF2Cl is released per month, we can convert it to grams: 20 kg * 1000 g/kg = 20,000 g.

Next, we calculate the number of moles of CHF2Cl: 20,000 g / 86.47 g/mol = 231.31 mol.

Each molecule of CHF2Cl contains one chlorine atom, so the number of moles of Cl is the same as the number of moles of CHF2Cl, which is 231.31 mol.

To convert moles to grams, we multiply by the molar mass of chlorine (35.45 g/mol): 231.31 mol * 35.45 g/mol = 8,199.30 g.

Therefore, approximately 8,199.30 grams or 8.1993 kg of Cl would be emitted into the atmosphere each year if the Freon leak were allowed to continue.

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Answer:

b

Explanation: