6m-4+3m+7 simplify term

Not me

Step-by-step explanation:

Answer:

Yes, the ordered pair (1, 2) is a solution to the system.

Step-by-step explanation:

The answer can be found quite quickly. Simply substitute the x coordinate of the given pair for x, and the y coordinate of the given pair for y.

The x coordinate is 1 and the y coordinate is 2, so...

3(1) - 4(2) = -5

2=4(1)-2.

Next, simplify:

3-8=-5

This equation is TRUE.

2=4-2

This equation is also TRUE.

Hopefully, this helps in some way!

Answer: 166.72 \(ft^{2}\)

Step-by-step explanation: math

Step-by-step explanation:

All you have to do here is use the surface area, or SA, equation.

Sa=2lw+2lh+2hw
sa=2(8.5)(3.2)+2(8.5)(4.8)+2(4.8)(3.2)

Sa=54.4+81.6+30.72

Sa=166.72

Hope this helped!

Answer:

B

Step-by-step explanation:

The line crossed the y axis at 4 and the slope is -2. you can do rise/ run to find the slope which is -2/1 or -2

The exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

Given that sec(θ) = -8 and sin(θ) > 0, we can find the exact values of the remaining trigonometric functions using the Pythagorean identity:

sec^2(θ) = 1/sin^2(θ)

Substituting the value of sec(θ), we have:

(-8)^2 = 1/sin^2(θ)

64 = 1/sin^2(θ)

sin^2(θ) = 1/64

sin(θ) = ±√(1/64)

Since sin(θ) > 0, we take the positive square root:

sin(θ) = √(1/64)

Next, we use the reciprocal identity for cosecant:

csc(θ) = 1/sin(θ)

Substituting the value of sin(θ), we have:

csc(θ) = 1/√(1/64) = 8√(1/64) = 8/√(64) = 8/8 = 1

Next, we use the reciprocal identity for cotangent:

cot(θ) = 1/tan(θ)

We can find the value of tan(θ) using the definition:

tan(θ) = sin(θ) / cos(θ)

Substituting the values of sin(θ) and cos(θ), we have:

tan(θ) = √(1/64) / (-8) = -√(1/64) / 8

Finally, we use the reciprocal identity for a tangent:

tan(θ) = 1/cot(θ)

Substituting the value of cot(θ), we have:

tan(θ) = -8√(1/64)

Therefore, the exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

The complete question is:-

Find the exact value of each of the remaining trigonometric functions of

θ. Rationalize denominators when applicable.

secθ=−8, given that sinθ>0

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Answer:

There are 9 possible numbers for the first number. There are 8 possible numbers for the second number since one number has been picked. For the third number there are 7 possible numbers.

9*8*7=5040

Step-by-step explanation:

Answer:

The decision rule is to Reject H0 if Z ≤ -1.282

Step-by-step explanation:

We are given;

Population mean; μ = 409 g

Sample mean; x¯ = 401 g

Sample size; n = 21

Standard deviation; s = 26

Let's define the hypotheses;

Null hypothesis; H0: μ = 409 g

Alternative hypothesis; Ha : μ ≠ 409 g

Formula for test statistic is;

z = (x¯ - μ)/(s/√n)

z = (401 - 409)/(26/√21)

z = -1.410

z-value is negative and thus this is a lower tail test.

At significance level of 0.1, the critical value is -1.282.

Thus, the decision rule is;

Reject H0 if Z ≤ -1.282

Answer:

B., C., D., E., and F.,

Step-by-step explanation:

They all need exponents by a 10

Producing 73.8 units gives the lowest possible average cost.

The average cost (AC) is the ratio of the total cost to the number of units produced. It is given by:

AC = C(x) / x

AC = (0.2x³ – 24x² + 1514x +30064) / x

AC = 0.2x² - 24x + 1514 + 30064/x

The lowest possible average cost is at AC' = 0. Hence differentiating the average cost, gives:

AC' = 0.4x - 24 - 30064/x²

0.4x - 24 - 30064/x² = 0

0.4x³ - 24x² - 30064 = 0

Solving the cubic polynomial gives:

x = 73.8 units

Therefore the lowest possible average cost is when 73.8 units are produced.

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Answer:

60

Step-by-step explanation:

360/6=60

Answer:

Calm down jamal don't go pulling out the nine

Step-by-step explanation:

this is just a joke

Answer:

450 days

Step-by-step explanation:

4500/10 = 450 days

Answer:

x = 65

Step-by-step explanation:

the sum of the interior angles of a quadrilateral = 360°

sum the angles and equate to 360

x + 95 + 118 + 82 = 360

x + 295 = 360 ( subtract 295 from both sides )

x = 65

The functions for this problem are defined as follows:

The functions for this problem are given as follows:

The addition and subtraction functions for this problem are given as follows:

At x = -2, the numeric value of the subtraction function is given as follows:

(t - s)(-2) = -2³ - 5(-2)²

(t - s)(-2) = -28.

The product function for this problem is given as follows:

(ts)(x) = \(5x^5\)

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Answer:

B

Step-by-step explanation:

Starting with four, the number continues to grow which means you have yo add to found and the only option that demonstrated that is B

Based on mathematical operations, the lowest amount that Annabel can pay for pencils is $15.20

The lowest amount that Annabel can pay for pencils can be determined using the mathematical operations of multiplication and division.

Multiplication and division are two of the four basic mathematical operations, including addition and subtraction.

If Annabel chooses to purchase the first pencil at 30p each, she would pay £22.80 (£0.30 x 76).

If Annabel chooses to purchase the second pencil class of a pack of 10 pencils for £2, she would pay £15.20 [£2 x (76 ÷ 10)].

Pencils for sale

30p each

Pack of 10 pencils for £2

Thus, if Annabel wants to buy the pencils, she can either pay £15.20 or £22.80, but using mathematical operations, the lowest amount she can pay is £15.20.

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The area οf the actual bridge deck in square feet is 1,280 square feet.

Area refers tο the measurement οf the size οf a twο-dimensiοnal surface, usually measured in square units such as square inches, square feet, οr square meters. It represents the amοunt οf space that is inside the bοundary οf a flat οbject οr shape.

The scale οf the drawing is 40:1, which means that the dimensiοns οf the scaled bridge deck are 40 times smaller than the actual bridge deck. Tο find the area οf the actual bridge deck in square feet, we need tο cοnvert the dimensiοns οf the scaled bridge deck frοm inches tο feet and then multiply by the square οf the scale factοr (40² = 1600).

The dimensiοns οf the scaled bridge deck in feet are:

24 inches = 2 feet

4 and 4/5 inches = 0.4 feet

Sο, the area οf the scaled bridge deck in square feet is:

2 feet x 0.4 feet = 0.8 square feet

Tο find the area οf the actual bridge deck in square feet, we need tο multiply the area οf the scaled bridge deck by the square οf the scale factοr:

Area οf actual bridge deck = 0.8 square feet x (40²) = 1280 square feet

Therefοre, the area οf the actual bridge deck in square feet is 1,280 square feet.

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Answer:

Step-by-step explanation:

The scale factor indicates the actual bridge is 40 times larger than the drawing.

Increase the scale dimensions by the factor of 40.

24 times 40 = 960"

4.8 times 40 = 192" (I changed 4 4/5 to 4.8)

Area = length times width

960 times 192 = 184320 sq inches actual bridge deck in square inches

Divide 183320 by 144 (sq inches in a square foot) = 1280 sq feet

The statistical analysis of the data using a two-sample t-test indicates;

(a) B. Yes, the Meters On data appears to have higher speeds

A. No, there does not appear to be any outlier

(b) H₀; \(\mu_{on}\) = \(\mu_{off}\)

H₁; \(\mu_{on}\) > \(\mu_{off}\)

The P-value for the test is about 0.037

A two-sample t-test is used to determine if there is a difference between the means of two independent groups of data.

(a) The average of the data values are;

Ramp meters on;

\(\mu_{on}\) = (29+47+55+38+32+25+42+47+51+36+55+41+43+25+47)/15 ≈ 40.87

\(\mu_{off}\) = (25+25+43+35+36+31+48+37+19+29+22+40+36+50+40)/15 ≈ 34.4

The higher average value for the speed with the Ramp meters on indicates;

B. Yes, the Meters On data appears to have higher speeds

The five number summary are;

Ramp Meters On

Min = 25, Max = 55, Q₁ = 32, Q₂ = 42, Q₃ = 47

IQR = 47 - 32 = 15

Outlier = 47 + 1.5 × 15 = 69.5

32 - 1.5 × 15 = 9.5

Therefore, there are no outliers for the Ramp Meters On

Ramp Meters Off

Min = 19, Max = 50, Q₁ = 25, Q₂ = 36, Q₃ = 40

IQR = 40 - 25 = 15

Outlier = 40 + 1.5 × 15 = 62.5

25 - 1.5 × 15 = 2.5

Therefore, there are no outliers for the Ramp Meters Off data

(b) The null hypothesis is; H₀; \(\mu_{on}\) = \(\mu_{off}\)

The alternative hypothesis is; H₁; \(\mu_{on}\) > \(\mu_{off}\)

(c) The two sample t-test, can be obtained using the formula;

\(t_{cal} = \frac{(\bar{x}_1 - \bar{x}_2)}{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} ) } }\)

Where; \(\bar{x}_1\) = 40.87

\(\bar{x}_2\) = 34.40

s₁ = 9.91

s₂ = 9.20

n₁ = n₂ = 15

Therefore; \(t_{cal}\) = 1.8516. The degrees of 15 + 15 - 2 = 28, and the one-tailed hypothesis, indicates, using an online tool;

The p-value is less than 0.05, therefore, the result is significant.

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Multiply both sides by \(x^{-3}\) to get a homogeneous equation.

\((2xy^2 - x^3) \, dy + (y^3 - 2yx^2) \, dx = 0 \\\\ \implies \left(2\dfrac{y^2}{x^2} - 1\right) \, dy + \left(\dfrac{y^3}{x^3} - 2\dfrac yx\right) \, dx = 0\)

Substitute \(y=vx\) and \(dy = x\,dv + v\,dx\). This makes the equation separable.

\((2v^2 - 1) (x\,dv + v\,dx) + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (2v^3 - v) \, dx + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (3v^3 - 3v) \, dx = 0\)

Separate the variables.

\(x (2v^2 - 1) \, dv = (3v - 3v^3) \, dx\)

\(\dfrac{2v^2-1}{3v-3v^3} \, dv = \dfrac{dx}x\)

\(\dfrac13 \dfrac{1 - 2v^2}{v(v-1)(v+1)} \, dv = \dfrac{dx}x\)

Expand the left side into partial fractions.

\(\dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac av + \dfrac b{v-1} + \dfrac c{v+1} \\\\ \dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac{a(v^2-1) + bv(v+1) + cv(v-1)}{v(v-1)(v+1)} \\\\ 1-2v^2 = (a+b+c) v^2 + (b-c) v - a\)

Solve for the coefficients \(a,b,c\).

\(\begin{cases} a + b + c = -2 \\ b-c = 0 \\ -a = 1 \end{cases} \implies a=-1, b=c=-\dfrac12\)

Thus our equation becomes

\(\left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \dfrac{dx}x\)

Integrate both sides.

\(\displaystyle \int \left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \int \dfrac{dx}x\)

\(\displaystyle -\frac13 \ln|v| - \frac16 \ln|v-1| - \frac16 \ln|v+1| = \ln|x| + C\)

Solve for \(v\) (as much as you can, anyway).

\(\displaystyle -\frac16 \left(2\ln|v| + \ln|v-1| + \ln|v+1|\right) = \ln|x| + C\)

\(\displaystyle \ln\left|\frac1{\sqrt[6]{v^2(v^2-1)}}\right| = \ln|x| + C\)

\(\displaystyle \frac1{\sqrt[6]{v^4-v^2}} = Cx\)

\(\sqrt[6]{v^4-v^2} = \dfrac Cx\)

\(\left(\sqrt[6]{v^4-v^2}\right)^6 = \left(\dfrac Cx\right)^6\)

\(v^4-v^2 = \dfrac C{x^6}\)

Put the solution back in terms of \(y\).

\(\left(\dfrac yx\right)^4-\left(\dfrac yx\right)^2 = \dfrac C{x^6}\)

\(y^4 - x^2y^2 = \dfrac C{x^2}\)

\(\boxed{x^2y^4 - x^4y^2 = C}\)

which is about as simple as we can hope to get this.

Answer:

3x + 9y = 23

Step-by-step explanation:

Answer:

4*1/3

Step-by-step explanation:

easy we know for each 3/3 == 1

so:

3*4 == 12

1/3 is left over so,

4*1/3

Answer:

the answer is 4 1/3, i recommend using the app mathaway

Answer:

Option (2)

Step-by-step explanation:

From the figure attached,

Two trapezoids PQRS and TUVW are the similar figures.

Therefore, their corresponding sides will be proportional.

\(\frac{PQ}{TU}=\frac{RS}{VW}\)

\(\frac{9}{6}=\frac{12}{x}\)

\(x=12\times \frac{6}{9}\)

\(x=8\)

Therefore, Option (2) will be the correct option.

The value of m + n is given as follows:

A. 18.

The exponential expression for this problem is defined as follows:

\((x^5y^6)^{\frac{1}{5}}(x^3y^4}^{\frac{1}{4}}\)

Applying the power of power rule, we have that the exponents are given as follows:

Then the values of m and n are given as follows:

m = 7, n = 11.

Thus the sum is given as follows:

m + n = 7 + 11 = 18.

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Step-by-step explanation:

there is nothing missing. this is a complete proof.

yes, the various steps are correct.

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Using distributive property, the solution to the given expression is: 50v - 40w + 20

The Distributive Property is a term which is an algebra property which is used to multiply a single term and two or more terms inside a set of parentheses.

For example:

4(3 + 5)

According to the distributive property, you first have to multiply out the bracket to get:

4*3 + 4*5 = 12 + 20

= 32

Thus:

5(10v - 8w + 4) = (5 * 10v) - (5 * 8w) + (5 * 4)

= 50v - 40w + 20

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The value of m that satisfies the equation -3 + m = 9 is m = 12.

To solve the equation -3 + m = 9, we can isolate the variable m by moving the constant term -3 to the other side of the equation.

-3 + m = 9

To move -3 to the other side, we can add 3 to both sides of the equation:

-3 + 3 + m = 9 + 3

Simplifying, we have:

m = 12

Therefore, the value of m that satisfies the equation -3 + m = 9 is m = 12.

None of the provided answer options (A, B, C, D) match the correct solution.

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Answer: \(f^{-1}(x)=2x-6\)

Step-by-step explanation:

To find the inverse, we want to switch the y with x and x with y. Once we do that, we solve for y.

\(y=\frac{1}{2}x+3\)        [switch x and y]

\(x=\frac{1}{2}y+3\)        [subtract both sides by 3]

\(x-3=\frac{1}{2} y\)        [multiply both sides by 2]

\(y=2x-6\)

Now, we know that  \(f^{-1}(x)=2x-6\).

Therefore, the end behavior of the function f(x) is: f(x) → 0- as x → -∞ and f(x) → 1 as x → ∞.

In mathematics, a function is a rule that assigns a unique output value to each input value. Functions are often represented as equations or graphs that relate the input (also known as the independent variable) to the output (also known as the dependent variable). The input is usually denoted by the variable x, and the output is usually denoted by the variable y. Functions can be used to model relationships between different quantities, such as time and distance, or temperature and pressure. They are a fundamental concept in mathematics and are used in many fields, including physics, engineering, economics, and computer science.

Here,

To determine the end behavior of the function f(x) = (-4x³+ 7x + 9)/(8x⁶ - 9x⁴ - 2x), we need to consider the limit of the function as x approaches positive or negative infinity.

As x approaches negative infinity, the highest power of x in the numerator is -4x³, which will dominate the function. The highest power of x in the denominator is 8x⁶, which will also dominate the function. Therefore, we can simplify the function to:

f(x) ≈ (-4x³)/(8x⁶) = -1/(2x³)

As x approaches negative infinity, the denominator of this simplified function will become very large (since x³ becomes very negative), causing the function to approach 0 from the negative side:

f(x) → 0- as x → -∞

As x approaches positive infinity, the highest power of x in the numerator and denominator are both 8x⁶. Therefore, we can simplify the function to:

f(x) ≈ (8x⁶)/(8x⁶) = 1

As x approaches positive infinity, the function will approach 1 from the positive side:

f(x) → 1 as x → ∞

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Complete question:

Consider the following rational function fff. f(x)=\dfrac{-4x^3+7x+9}{8x^6-9x^4-2x}f(x)= 8x 6 −9x 4 −2x −4x 3 +7x+9 ​ f, left parenthesis, x, right parenthesis, equals, start fraction, minus, 4, x, cubed, plus, 7, x, plus, 9, divided by, 8, x, start superscript, 6, end superscript, minus, 9, x, start superscript, 4, end superscript, minus, 2, x, end fraction Determine fff's end behavior. f(x)\tof(x)→f, left parenthesis, x, right parenthesis, \to as x\to -\inftyx→−∞x, \to, minus, infinity. f(x)\tof(x)→f, left parenthesis, x, right parenthesis, \to as x\to \inftyx→∞x, \to, infinity.