Answer:
Mechanical Energy, Thermal Energy, By Feeding Them Food, Light Energy, Electromagnetic Energy, it's right on Edge
Explanation:
Answer:
1. mechanical energy, 2. thermal energy, 3. by feeding them food, 4. light energy 5. electromagnetic energy
Explanation:
got it right on edg ;))
Which statement best describes 0 degrees latitude?
A. The northernmost point of earth at its axis.
B. An imaginary line that runs through Greenwich, in London.
C. An imaginary line that spilts earth in half between the North Pole and the South Pole.
D. The southernmost point of earth at its axis.
Answer:
C. An imaginary line that spilts earth in half between the North Pole and the South Pole.
phosphorus appears directly below nitrogen in the periodic table. the boiling point of ammonia, nh3, is higher than the boiling point of phosphine, ph3, under standard conditions. which of the following statements best explains the difference in the boiling points of these two compounds?
The difference in the boiling points of ammonia (\(NH_3\)) and phosphine (\(PH_3\)) can be best explained by the presence of hydrogen bonding in ammonia, which results in a higher boiling point compared to phosphine.
Ammonia has a nitrogen atom, which is more electronegative than the phosphorus atom in phosphine. This causes a larger dipole moment in the ammonia molecule, leading to stronger intermolecular forces due to the formation of hydrogen bonds between the nitrogen and hydrogen atoms in adjacent molecules. These stronger forces require more energy to break, resulting in a higher boiling point for ammonia.
In contrast, phosphine lacks hydrogen bonding due to the lower electronegativity of phosphorus compared to nitrogen. Therefore, the intermolecular forces in phosphine are weaker, requiring less energy to break, and leading to a lower boiling point under standard conditions.
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When using a Van de Graaff generator charges repel because all the charges are all
When using a Van de Graaff generator charges repel because all the charges are negatively charged.
Why does the Van de Graaff become negatively charged?The Van de Graaff become negatively charged, because the rubber belt is an insulator and a poor conductor of electricity, the positive charge does not spread evenly across the belt.
Instead, as a result of electric induction, the inside of the belt remains positively charged, while the outside of the belt becomes negatively charged.
Thus, When using a Van de Graaff generator charges repel because all the charges are negatively charged.
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Consider the chemical equations shown here.
Upper N Upper O (g) + Upper O Subscript 3 Baseline (g) right arrow Upper N Upper O Subscript 2 Baseline (g) + Upper O Subscript 2 Baseline (g) delta Upper H Subscript 1 Baseline = negative 198.9 kilojoules. StartFraction 3 Over 2 EndFraction Upper O Subscript 2 Baseline (g) right arrow Upper O Subscript 3 Baseline (g) delta Upper H Subscript 2 Baseline = 142.3 kilojoules. Upper O (g) right arrow one half Upper O Subscript 2 Baseline (g) delta Upper H Subscript 3 Baseline = negative 247.5 kilojoules.
What is Delta.Hrxn for the reaction shown below?
Upper n upper O (g) plus upper O (g) right arrow upper N upper O subscript 2 (g).
Answer:
-304.1
Explanation:
Just took it on Edge 2020
The enthalpy change for the target reaction is obtained as -304.1 kJ.
What is Hess law?The Hess law of constant heat summation states that; the heat of reaction can be obtained as the sum of the heat of several reactions.
In this case, the enthalpy change for the target reaction can be identified as; -198.9 + 142.3 + (-247.5) = -304.1 kJ.
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Please help me
How many hydrogen(H) atoms are in 3(NH₄)₂Cr₂O₇
And How many Nitrogen(N) atoms are in 3(NH₄)₂Cr₂O₇
Answer:
24 H
6 N
Explanation:
3 × (4 × 2) = 24 H
3 × 2 = 6 N
Mechanical advantage of a machine is always less than velocity ratio. Why? d again in a sewing machine?
please fast
Answer:
The mechanical advantage (M.A) of a real machine is always less than its velocity ratio(V.R) because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant
why does a new flu shot need to be made each year ?
because we could be sick if don't get the shot there is a higher chance to have the flu
What happens inside an air-filled balloon is squeezed on all sides?
O The air molecules move more slowly.
O The air molecules move farther apart.
O The air molecules move closer together.
O The air molecules remain in the same place.
Answer: The air molecules move closer together.
Explanation:
Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.
Answer:
a) 72 °F= 22.22 °C
b) 213.8 °C= 416.84°F
c) 180 °C= 453.15 °K
d) 315 °K= 107.33 °F
e) 1750 °F= 1227.594 °K
f) 0 °K= -459.67 °F
Explanation:
Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:
Fahrenheit a Celsius: \(C=\frac{F-32}{1.8}\)Celsius a Fahrenheit: °F= °C*1.8 + 32Celsius a Kelvin: °K= °C + 273.15Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32Fahrenheit a Kelvin:\(K=\frac{F-32}{1.8} + 273.15\)Entonces se obtiene:
a) 72 °F= \(\frac{72-32}{1.8}\)=22.22 °C
b) 213.8 °C= 213.8*1.8 + 32= 416.84°F
c) 180 °C= 180°C + 273.15= 453.15 °K
d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F
e) 1750 °F= \(\frac{1750-32}{1.8} + 273.15\)= 1227.594 °K
f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F
12) A solution of acetic acid, HC2H3O2, on a laboratory shelf was of undetermined concentration. If the pH of the solution was found to be 2.68, what was the concentration of the acetic acid? (Ka = 1.7 x 10-5)
HC2H3O2 (aq) + H2O(l) C2H3O2-(aq) + H3O+(aq)
The concentration of acetic acid in the solution is 0.257 M.
What is the concentration of acetic acid in the solution?The concentration of acetic acid in the solution is determined from the Henderson- Hasselbalch equation as follows:
pH = pKₐ + log ([A⁻]/[HA])where;
pKa = - log(Ka) of acetic acid[A⁻] = concentration of acetate[HA] = concentration of acetic acidpKa = - log(1.7 * 10⁻⁵)
pKa = 4.77
Equation of reaction: HC₂H₃O₂ (aq) + H₂O(l) --> C₂H₃O₂⁻ (aq) + H₃O⁺ (aq)
From the equation of reaction; [A⁻] = [H₃O⁺]
[H₃O⁺] = antilog -(pH)
[H₃O⁺] = antilog (-2.68)
[H₃O⁺] = 0.002
[A⁻] = 0.002
[HA] = [A⁻] / antilog of (pH - pKa)
[HA] = [A⁻] / antilog (2.68 - 4.77)
[HA] = 0.002 / 0.00812
[HA] = 0.257 M
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A solution of NaCl was prepared in the following manner: 0.0842 g of NaCl is massed out on an analytical balance. The solid is transferred to a 25.00 mL volumetric flask. Deionized water is added to the flask such that the bottom of the meniscus is at the line. A 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask using a volumetric pipet and diluted to volume. 6. Calculate the concentration of NaCl in the resulting solution in mg/L NaCl. (answer = 67.4 mg/L) 7. Calculate the concentration of NaCl in the resulting solution using propagation of error through the calculation. Use the manufacturer's tolerance values as the absolute error. The tolerances can be found in Chapter 2 of the Harris text. Assume a Class 1 balance and Class A glassware. Treat the tolerances as random error. (answer = 67.4+0.4 mg/L) 8. Identify 2 possible sources of random (indeterminate) error. Identify 2 possible sourses of systematic (determinate) error.
Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl
To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7. Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.
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Using the following balanced equation, 2 moles of C2H6 will produce how many total moles of products?
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
a. 2
b. 10
c. 4
d. 6
Answer:
Explanation:
b
How do you shift realities?
I’ve been trying for weeks now
Answer:
1. learn how to script
2. be in a good state of mind
3. drink water water warer
4.search for yt tutorials
Explanation:
One lawn chair is made of aluminum (c=0.89 j/g°c) and another is made of iron (c=0.45 j/g°c). both chairs are painted the same color. on a sunny day, which chair you want to sit on? why?
The preferred chair to sit on a sunny day is the one made of aluminum. It offers a more comfortable seating experience compared to the iron chair. The aluminum chair's higher specific heat capacity helps it absorb less heat and stay cooler.
Why is the aluminum chair preferred on a sunny day?Aluminum is the preferred choice for sitting on a sunny day due to its higher specific heat capacity (c=0.89 J/g°C) compared to iron (c=0.45 J/g°C). Specific heat capacity refers to the amount of heat energy required to raise the temperature of a substance by one degree Celsius per gram.
When exposed to the sun, both chairs will absorb heat energy from the sunlight. However, aluminum has a higher specific heat capacity, meaning it can absorb more heat energy per gram compared to iron. This results in the aluminum chair heating up at a slower rate than the iron chair.
The slower rate of heat absorption by the aluminum chair makes it more comfortable to sit on during a sunny day. It will take longer for the aluminum chair to reach an uncomfortable temperature compared to the iron chair, providing a more pleasant seating experience.
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A buffer solution is made by adding 25.7 ml of 4.1 M NaOH to 215.0 mL of a weak acid HA. The pka of HA is 4.09. The activity coefficient of the weak acid is 0.88, and the activity coefficient of the weak base is 0.77. The pH of the resulting solution is 4.35. Remember that NaOH is a strong base and will therefore be considered to dissociate completely. What is the concentration of the HA solution before AND after the NaOH was added? Please show work for both concentrations.
The balanced chemical equation for the dissociation of a weak acid is: HA(aq) + H2O(l) ⇌ H3O+(aq) + A-(aq). The initial concentration of weak acid is 0.49M. The concentration of the HA solution after the NaOH was added is 0.277 M.
What is a buffer solution?A buffer solution is a solution that resists a change in pH. It contains a weak acid and its corresponding conjugate base, or a weak base and its corresponding conjugate acid. There are two types of buffer solutions: acidic buffer solutions and basic buffer solutions. According to the question, the volume of the NaOH solution is 25.7 mL, the molarity of NaOH solution is 4.1 M, and the volume of the weak acid HA is 215 mL.
To determine the initial concentration of the weak acid HA, the number of moles of NaOH added must first be calculated. Using the molarity of NaOH and its volume:
Moles of NaOH = Molarity × Volume= 4.1 M × 0.0257 L= 0.1056 mol
Next, it is necessary to determine how many moles of HA were present before the NaOH was added. Because the NaOH is a strong base, it will react completely with the weak acid HA to produce its conjugate base A-. The amount of weak acid HA consumed will be equal to the amount of NaOH added.
Moles of HA consumed = Moles of NaOH= 0.1056 mol
The volume of the weak acid HA solution is 215 mL.
Convert this volume to liters:215 mL = 0.215 L
The initial concentration of the weak acid HA can be calculated as follows:
Initial concentration = Moles / Volume= 0.1056 mol / 0.215 L= 0.49 M
A balanced chemical equation is necessary to calculate the new concentration of the weak acid HA. The balanced chemical equation for the reaction between NaOH and HA is:
HA(aq) + NaOH(aq) → H2O(l) + NaA(aq)
Moles of NaA produced = Moles of NaOH= 0.1056 mol
The volume of the solution is the sum of the volumes of the weak acid HA and the NaOH. Convert the volume of the NaOH solution to liters:
25.7 mL = 0.0257 L
Total volume = 0.215 L + 0.0257 L= 0.2417 L
The number of moles of HA remaining can be calculated using the moles of HA consumed and the moles of NaA produced:
Moles of HA remaining = Moles of HA – Moles of NaA= 0.1056 mol – 0.1056 mol= 0 M
The number of moles of A- produced is equal to the number of moles of NaOH added because the acid and the base react in a 1:1 ratio.
Moles of A- produced = Moles of NaOH= 0.1056 mol
The new concentration of A- is then calculated:
New concentration = Moles / Volume= 0.1056 mol / 0.2417 L= 0.436 M
Next, we need to calculate the new concentration of HA. We can use the Henderson-Hasselbalch equation:
pH = pKa + log ([A-]/[HA])
Rearrange this equation and solve for [HA]:
[HA] = [A-] × 10^(pH - pKa)
Substituting the known values:
pH = 4.35pKa = 4.09[A-] = 0.436[HA] = 0.436 × 10^(4.35 - 4.09)= 0.277 M
Therefore, the concentration of the HA solution after the NaOH was added is 0.277 M.
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Would sweet tea be an example of a mixture or a compound?
Sweet tea is an example of a mixture. A mixture is defined as a combination of two or more substances in which the individual components are generally still distinguishable and can be separated by physical means.
On the other hand, a compound is a substance made up of two or more different elements chemically combined in fixed proportions.Sweet tea is usually composed of tea leaves, sugar, and water. The individual components are still distinguishable and can be separated by physical means such as filtration and evaporation. For example, if sweet tea is left to stand, the tea leaves will settle to the bottom and the sugar will dissolve in the water. Therefore, sweet tea is an example of a mixture and not a compound.
In conclusion, sweet tea is an example of a mixture and not a compound because the individual components are still distinguishable and can be separated by physical means. It is composed of tea leaves, sugar, and water, which are combined to create a unique flavor and taste.
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3. How do we get mass from moles?
A. multiply by Avogadro's number
B. multiply by molar mass
C. divide by Avogadro's number
D. divide by molar mass
the oxidation number of a nitrogen atom in n₂o₃ is
A nitrogen atom in N2O3 has an oxidation number of +3.
The unknown nitrogen oxidation number can be given a variable (x) to ascertain its oxidation number. Since oxygen has an oxidation number of - 2 and there are three oxygen particles in N₂O₃, the complete negative charge from oxygen is (- 2) × 3 = - 6.
The total charge of a compound is equal to the sum of its oxidation numbers. Since the compound in question is neutral, the sum of the oxidation numbers must be zero in this instance.
2(N) + 3(O) = 0
2x + (-6) = 0
2x = 6
x = 3
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Obtain an expression for the isothermal compressibility κ = −1/V(∂V/∂P)T for a van der Waals gas.
Obtain an expression for the isothermal compressibility for a van der Waals gas.
a κ=1Vm[RT(Vm−b)3+2aV3m]
b κ=−1Vm[2aV3m−RT(Vm−b)2]
c κ=−1Vm[RT(Vm−b)2−2aV3m]
d κ=1Vm[2aV3m−RT(Vm+b)2]
The expression for the isothermal compressibility for a van der Waals gas is given by:
κ = −1/Vm (∂Vm/∂P)T
where Vm is the molar volume of the gas.
The isothermal compressibility is a measure of how much the volume of a substance changes when the pressure is changed while the temperature is kept constant. For a van der Waals gas, the volume depends on both the pressure and the temperature, and the expression for the isothermal compressibility is derived from the equation of state for the van der Waals gas.
The equation of state for a van der Waals gas is:
(P + a/Vm2)(Vm − b) = RT
where P is the pressure, T is the temperature, R is the gas constant, a and b are constants that depend on the properties of the gas, and Vm is the molar volume.
To obtain the expression for the isothermal compressibility, we start by differentiating the equation of state with respect to pressure at constant temperature:
(∂/∂P)(P + a/Vm2)(Vm − b) = (∂/∂P)(RT)
(1 + 2a/Vm3)(Vm − b) − (P + a/Vm2)(∂Vm/∂P) = 0
Solving for (∂Vm/∂P) gives:
(∂Vm/∂P) = (Vm2 − bVm − a)/(Vm2P + aP − 2aVm2)
Substituting this expression into the definition of the isothermal compressibility gives:
κ = −1/Vm [(Vm2P + aP − 2aVm2)/(Vm2 − bVm − a)]
Simplifying this expression using the equation of state gives:
κ = −1/Vm [(RTVm2)/(Vm3 − (b + RT/P)Vm2 + aV2m − abP/V)]
Finally, rearranging this expression gives the correct answer:
κ = 1/Vm [(RT(Vm − b)3 + 2aV3m)/(Vm3 − (b + RT/P)Vm2 + aV2m − abP/V)]
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Consider X driving a car in the morning and works at medical diagnosis in the afternoon. Following his work schedules, which model you used for the two activity of X? Explain with the logic in terms of machine learning.
The model used for the two activities of X, driving a car in the morning and working at medical diagnosis in the afternoon, is likely a hybrid model combining supervised and unsupervised learning techniques.
Supervised learning is a machine learning technique where a model is trained using labeled data to make predictions or classify new instances. In the context of driving a car, supervised learning can be used to train a model on labeled data such as images or sensor inputs to recognize objects, detect traffic signs, or make decisions based on road conditions.
On the other hand, medical diagnosis involves analyzing patient data to identify diseases or conditions. This task often involves a combination of supervised and unsupervised learning. Supervised learning algorithms can be trained on labeled medical data to classify diseases or predict patient outcomes. Unsupervised learning techniques such as clustering or anomaly detection can be used to discover patterns, identify outliers, or group patients based on similar characteristics.
A hybrid model that combines supervised learning for specific tasks like object recognition in driving and a combination of supervised and unsupervised learning for medical diagnosis can provide a comprehensive approach to address the different requirements of each activity.
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File that is temporarily stored on your computer. Save #1 SYNTHESIS OF FLUORESCEIN a. Propose a mechanism (curvy arrows) to show the conversion of the quinoid form to the lactone form НО, OH HOOH А НО. Zwitterionic Tautomer Yellow Lactone Tautomer Colorless Quinoid Tautomer Brick red
The file that is temporarily stored on your computer is called a cache. As for the question about the synthesis of fluorescein, the conversion from the quinoid form to the lactone form can occur through a tautomerization process.
The mutation that results from a tautomeric shift ALWAYS converts a purine to a purine or a pyrimidine to a pyrimidine. A point mutation could result from a tautomeric shift in Computer.
Any change to the nucleotide sequence of an individual's genome is referred to as a mutation.
It is possible to characterize a tautomeric shift as a transient modification of the nucleotide base structure
The mechanism involves the transfer of a proton and rearrangement of electrons to form a zwitterionic tautomer, which can then undergo a cyclization reaction to form the yellow lactone tautomer. The quinoid tautomer, which is colorless, can also be converted to the brick red form through further oxidation.
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how to find the electron in an atom/element
Answer:
to find the number of electrons an element has locate it on the periodic table of elements find the atomic number and note the number of protons because they are naturally electrically neutral
Answer:
M-A=N
Explanation:
M-A=N
Here is an example.
The equation above means that the atomic number (A) subtracted from the average atomic mass (M) equals the combined amount of neutrons and protons. Since we know that 35 17Cl is Chlorine (this is because Chlorine (Cl) is the 17th number on the periodic table and has the average atomic mass of 35), we can insert our data into the equation and end up with the following:
35-17=18.
From here, we can tell that we have a mix of neutrons and protons, with the total being 18. Since the atomic number is 17, we can reasonably assume that there are 17 protons and 1 neutron.
But we still need to find the number of electrons. Fortunately, the number of electrons is always equivilant to the number of protons and the atomic mass, so we know that the number of electrons is 17.
So, we have;
17 Protons
1 Neutron
17 Electrons
How many grams of NaOH are needed to neutralize 50 grams of H2SO4
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 49g of NaOH are needed to neutralize 50 grams of H\(_2\)SO\(_4\).
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. Stoichiometry is a part of chemistry that help us in making relationship between reactant and product from quantitative aspects.
Mathematically,
H\(_2\)SO\(_4\)+ 2NaOH \(\rightarrow\)Na\(_2\)SO\(_4\) + 2H\(_2\)O
number of mols of H\(_2\)SO\(_4\)= grams/molar mass
The mole ratio between H\(_2\)SO\(_4\) and NaOH is 1:2
Substituting all the given values, we get
50g/100g=X/98g
X=98g×{50g/100g}
X=49g
Therefore, 49g of NaOH are needed to neutralize 50 grams of H\(_2\)SO\(_4\).
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1) Under what metabolic condition is pyruvate converted to Acetyl - COA [1] 2) Write a chemical equation for the production of Acetyl-COA from Pyruvate. Under what conditions does this reaction occur? [6] 3) To what metabolic intermediate is the acetyl group of Acetyl-COA transferred in the Citric Acid Cycle? [2] 4) To what final products is the acetyl group of the Acetyl-CoA converted [5]
1) Pyruvate is converted to Acetyl - COA under aerobic conditions in the presence of oxygen, as part of the process of cellular respiration.
2) The chemical equation for the production of Acetyl-COA from Pyruvate is:
Pyruvate + CoA + NAD⁺ → Acetyl-CoA + CO₂ + NADH + H⁺. This reaction occurs in the mitochondria of eukaryotic cells, and in the cytoplasm of prokaryotic cells.
3) The acetyl group of Acetyl-COA is transferred to oxaloacetate to form citrate, which is the first intermediate of the Citric Acid Cycle.
4) The acetyl group of the Acetyl-CoA is converted to CO₂ and H₂O as part of the Citric Acid Cycle, which generates ATP and other energy-rich molecules. The final products of the Citric Acid Cycle include ATP, NADH, FADH₂, and CO₂.
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A 0.380 kg sample of aluminum (with a specific heat of 910.0 J/(kg x K)) is heated to 378 K and then placed in 2.40 kg of water that is at 293 K. If the system is left to reach its equilibrium state, what will the equilibrium temperature be? Assume that no thermal energy is lost to the external environment. Use 4.186 J/(g x K) as the specific heat of water.
Answer:
The equilibrium temperature of the system is 276.494 Kelvin.
Explanation:
Let consider the system formed by the sample of aluminium and water as a control mass, in which the sample is cooled and water is heated until thermal equilibrium is reached. The energy process is represented by First Law of Thermodynamics:
\(Q_{water} -Q_{sample} = 0\)
\(Q_{water} = Q_{sample}\)
Where:
\(Q_{water}\) - Heat received by water, measured in joules.
\(Q_{sample}\) - Heat released by the sample of aluminium, measured in joules.
Given that no mass is evaporated, the previous expression is expanded to:
\(m_{w}\cdot c_{p,w}\cdot (T-T_{w}) = m_{s}\cdot c_{p,s}\cdot (T_{s}-T)\)
Where:
\(m_{s}\), \(m_{w}\) - Mass of water and the sample of aluminium, measured in kilograms.
\(c_{p,s}\), \(c_{p,w}\) - Specific heats of the sample of aluminium and water, measured in joules per kilogram-Kelvin.
\(T_{s}\), \(T_{w}\) - Initial temperatures of the sample of aluminium and water, measured in Kelvin.
\(T\) - Temperature which system reaches thermal equilibrium, measured in Kelvin.
The final temperature is now cleared:
\((m_{w}\cdot c_{p,w}+m_{s}\cdot c_{p,s})\cdot T = m_{s}\cdot c_{p,s}\cdot T_{s}+m_{w}\cdot c_{p,w}\cdot T_{w}\)
\(T = \frac{m_{s}\cdot c_{p,s}\cdot T_{s}+m_{w}\cdot c_{p,w}\cdot T_{w}}{m_{w}\cdot c_{p,w}+m_{s}\cdot c_{p,s}}\)
Given that \(m_{s} = 0.380\,kg\), \(m_{w} = 2.40\,kg\), \(c_{p,s} = 910\,\frac{J}{kg\cdot K}\), \(c_{p,w} = 4186\,\frac{J}{kg\cdot K}\), \(T_{s} = 378\,K\) and \(T_{w} = 273\,K\), the final temperature of the system is:
\(T = \frac{(0.380\,kg)\cdot \left(910\,\frac{J}{kg\cdot K} \right)\cdot (378\,K)+(2.40\,kg)\cdot \left(4186\,\frac{J}{kg\cdot K} \right)\cdot (273\,K)}{(2.40\,kg)\cdot \left(4186\,\frac{J}{kg\cdot K} \right)+(0.380\,kg)\cdot \left(910\,\frac{J}{kg\cdot K} \right)}\)
\(T = 276.494\,K\)
The equilibrium temperature of the system is 276.494 Kelvin.
Answer:296
Explanation:
I got it right :) and mark me brainlest please
In a separate location, take notes from the sources you’ve identified. These notes will provide details for your research paper. While reading and taking notes, use these reading strategies to analyze texts and websites.
Explanation:
External force of 220 applied on a pistan of a cylinder containg 1.25 ammonia gas move 10cm as shown in diagram below
The web's ______ advantage allows for data and resource sharing that enables communication with a website.
The web's connectivity advantage allows for data and resource sharing that enables communication with a website.
In our daily lives, communication helps us build relationships by allowing us to share experiences and needs and connect with others. It is the essence of life that allows us to share We all need to communicate.
In our daily lives, communication helps us build relationships by allowing us to share experiences and needs and connect with others. It is the essence of life that can be shared. We all need to communicate. Effective communication results in a sense of satisfaction and accomplishment for all involved. Clearly communicating your message leaves no room for misunderstandings or message changes, and reduces the chance of conflicts.
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How do you calculate the percent composition of an element in a compound
Answer:
Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.
Explanation:
Where is OH on the IR spectrum?
The hydroxyl (OH) functional group typically appears as a broad peak on the infrared (IR) spectrum.
The exact location of the peak depends on the specific compound and the environment of the OH group. In general, the OH stretch vibration occurs in the range of 3200-3600 cm^-1. This broad peak is due to the hydrogen bonding interactions that can occur between OH groups and neighboring molecules. The intensity and shape of the peak can provide additional information about the nature of the OH group, such as whether it is involved in intermolecular or intramolecular hydrogen bonding. Overall, the presence of an OH peak in the IR spectrum is indicative of the presence of an alcohol or hydroxyl-containing functional group in the molecule.
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the element antimony has two stable isotopes, antimony-121 with a mass of 120.90 u and antimony-123 with a mass of 122.90 u. from the atomic mass of sb, 121.76 u, one can conclude that:
From the atomic mass of Sb, 121.76 u, one can conclude that the element antimony has more of isotope Antimony-123.
Explanation:
Antimony is an element that has two stable isotopes:
antimony-121 and antimony-123 with masses of 120.90 u and 122.90 u, respectively. The atomic mass of Sb, 121.76 u, can be used to conclude that antimony has a greater percentage of antimony-123 than antimony-121.
Let's calculate the percentage of antimony-121 and antimony-123 in antimony as follows:
Suppose x is the percentage of antimony-121, and (100 - x) is the percentage of antimony-123 in antimony.
At this point, we can use the average atomic mass of antimony and mass of antimony-121 and antimony-123 to calculate x as follows:
x = ((121.76 u) - (122.90 u) (100 - x)) / (120.90 u - 122.90 u) = (121.76 u - 122.90 u + 122.90 x) / (-2.00 u) = (122.90 x - 1.14 u)
/-2.00 u Solving for x gives x = 42.7%
Therefore, we can conclude that antimony has more of isotope Antimony-123.
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