A ball at rest rolls across a frictionless floor at 12.0 m/s/s. How far will it travel in
8.00 s?

Answer:

54 miles.

Explanation:

12 times 4.5.

Answer:

\(\boxed {\tt 54 \ miles}\)

Explanation:

Distance can be found by multiplying the speed by the time.

\(d=s*t\)

The speed is 12 miles per hour and the time is 4.5 hours. Therefore,

\(s= 12 \ mi/hr\\t=4.5 \ hr\)

Substitute the values into the formula.

\(d= 12 \ mi/hr * 4.5 \ hr\)

Multiply. Note that that hours, or "hr" will cancel each other out.

\(d= 12 \ mi * 4.5\)

\(d= 54 \ mi\)

d= 54 miles

The distance covered is 54 miles.

Answer:

a. y = (tanθ)x - 1/2gx²/(v₀cosθ)²

b. Range R = v₀²sin2θ/g

c. Time of flight T = 2v₀sinθ/g

Explanation:

a. Show that the path followed by the object is parabolic

Let the vertical component of its velocity be v₁ = v₀sinθ and the horizontal component of its velocity be v₂ = v₀cosθ where v₀ = initial velocity of the projectile.

Now, for its vertical displacement Δy = v₁t - 1/2gt²   (1)

Its horizontal displacement Δx = v₂t  (2)

From (2) t = Δx/v₂

Substituting t into (1), we have

Δy = v₁(Δx/v₂) - 1/2g(Δx/v₂)²

= (v₁/v₂)Δx - 1/2g(Δx)²/(v₂)² =

= (v₀sinθ/v₀cosθ)Δx - 1/2g(Δx)²/(v₀cosθ)²  

If we assume the initial position is at the origin, then Δx = x - 0 = x and Δy = y - 0 = y. So,

y = (tanθ)x - 1/2gx²/(v₀cosθ)² .

This is the required equation and it is a quadratic equation in x. Thus, the path followed by the projectile is parabolic.

b. The Range, R

The range, R is obtained when y = 0

So, 0 = (tanθ)x - 1/2gx²/(v₀cosθ)²

[(tanθ) - 1/2gx/(v₀cosθ)²]x = 0

x = 0 or (tanθ) - 1/2gx/(v₀cosθ)² = 0

x = 0 or (tanθ) = 1/2gx/(v₀cosθ)²

x = 0 or (tanθ)(v₀cosθ)² = 1/2gx

x = 0 or x = 2(sinθ/cosθ)(v₀cosθ)²/g

x = 0 or x = v₀²(2sinθ/cosθ)/g

x = 0 or x = v₀²sin2θ/g      [sin2θ = 2sinθ/cosθ]

So its range R = x = v₀²sin2θ/g    

c. Time of flight, T

The time of flight, T is obtained from (1) when Δy = 0 and t = T

So, 0 = v₁T - 1/2gT²

(v₁ - 1/2gT)T = 0

T = 0 or (v₁ - 1/2gT) = 0

T = 0 or v₁ = 1/2gT

T = 0 or T = 2v₁/g = 2v₀sinθ/g

So, the time of flight T = 2v₀sinθ/g

The collision, Miguel is moving in the opposite direction at 1.2 m/s.

Define collision.

A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

Miguel's post-collision velocity can be determined using the law of conservation of momentum.
Momentum is a vector quantity and is equal to mass times velocity (p=mv). Before the collision, the momentum of the system (Miguel + Fernando's car) is equal to (m1=72kg)(v1=4m/s) + (m2=125kg)(v2=0m/s) = 782 kg*m/s.
After the collision, the momentum of the system is equal to (m1=72kg)(v1=?m/s) + (m2=125kg)(v2=2m/s) = 782 kg*m/s.
By solving for v1 we can find that Miguel's post-collision velocity is -1.2 m/s.
This means that after the collision, Miguel is moving in the opposite direction at 1.2 m/s.

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Answer:

Batteries are intended to store chemical energy and then it converts into electricidal energy. So overall, batteries produce energy.

Explanation:

The bin will not move because the frictional force is greater than the net force acting on the bin.

The net force acting on the bin is obtained by subtracting the force acting on the Easterly direction from that acting in the Westerly direction.

Net force = 110 N - 52 N

Net force = 58 N

The frictional force acting on the bin is determined as well using the given formula:

Frictional force = coefficient of static friction * normal reaction

Norma reaction = 26 * 9.81

Normal reaction = 255.06 N

coefficient of static friction = 0.25

Frictional force = 0.25 * 255.06

Frictional force = 63.8 N

Since the frictional force is greater than the net force acting on the bin, the bin will not move.

In conclusion, the frictional force is the force that opposes relative between two objects at their surface of contact.

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There are two methods of measurement of current with an oscilloscope. They are

A) Measure the voltage drop across a shunt resistor and

B) Measure the current with a current probe

A) If a current sense resistor is designed into the DC power supply, this is the most convenient approach.

Measuring the voltage drop across the sense resistor with an active differential probe will provide good results as long as the common mode signal is within the probe's specified operating range and the voltage drop is large enough. However, using a differential probe on low level signals requires some attention to the noise reduction in the measurement system.

B) Current flow through a conductor causes an electromagnetic flux field to form around the conductor. Current probes are designed to sense the strength of this field and convert it to a corresponding voltage for measurement by an oscilloscope.

This allows you to view and analyse current waveforms with an oscilloscope. When used in combination with an oscilloscope's voltage measurement capabilities, current probes also allow you to make a wide variety of current measurements.

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Answer:

It's b

It said I needed at least 20 characters so I'm writing this sorry guys

Answer:

b increasing the area of their contact

Explanation:

The average force exerted on the ball by the golf club is 490 N.

Thus,  F = p/t = 0.49 * 10³ N = 490 N.

Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.

A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.

This is because bowling balls are larger in mass than ping-pong balls.

Thus, The average force exerted on the ball by the golf club is 490 N.

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Answer:

The sporadic decrease and increase in its brightness, which does not respond to a regular or predictable pattern. This change is due to dust that can be the product of the collision of two comets or the rupture of one. Another possible but less likely explanation is that the star is experiencing a kind of internal upheaval never seen before. The second one makes me more interesting because it is a lake that has never been seen before but I feel that it may be much less likely.

Explanation:

The amplitude of an oscillating electric field refers to the maximum magnitude or strength of the electric field during its oscillation.

In the context of electromagnetic waves, such as light, the amplitude represents the maximum displacement of the electric field from its equilibrium position. It is denoted by the symbol \("E_0"\) and is typically measured in units of volts per meter (V/m).

The amplitude of an oscillating electric field determines the intensity or brightness of the electromagnetic wave. It affects various properties of the wave, including the energy carried by the wave and the maximum electric potential difference experienced by charged particles in its presence. The larger the amplitude, the more energy the wave carries and the stronger its influence on charged particles.

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Answer:

A property of matter by which it remains at rest or in motion in the same straight line unless acted upon by some external force

Answer:

The source of energy that is used to power the movement of contraction in working muscles is adenosine triphosphate (ATP) – the body's biochemical way to store and transport energy. However, ATP is not stored to a great extent in cells. So once muscle contraction starts, the making of more ATP must start quickly.

Explanation: Brainliest?

If a person's far-point distance with their contacts is 8.5 m, what is their uncorrected far-point distance?The far point of the human eye is the farthest point to which it can focus without straining. For a normal eye, this distance is usually infinity.

When the image formed on the retina is not clear, the distance from the eye to the farthest point to which the eye can focus is called the far-point distance. The ability of an eye to focus on distant objects is its capacity.

If the person's far-point distance with her contacts is 8.5 meters, her uncorrected for point distance can be calculated by using the following formula: Diopter = 100 cm / focal length in meters Using the above formula we have:Focal length = 100 cm / Diopter Focal length = 100 cm / 8.5 meters = 11.76 cm

Uncorrected for point distance = 1 / (focal length) Uncorrected for point distance = 1 / 0.1176 metersUncorrected for point distance = 8.49 meters

Therefore, the uncorrected for point distance of the person's eye is 8.49 meters.

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The value of the Fermi-Dirac distribution for energies less than the Fermi energy at absolute zero temperature (T=0K) is 1.00.

The Fermi-Dirac distribution function describes the probability of finding an electron in a specific energy state in a Fermi gas. It is given by the equation:

f(E) = 1 / (1 + exp((E - EF) / (kT)))

Where f(E) is the Fermi-Dirac distribution function, E is the energy, EF is the Fermi energy, k is Boltzmann's constant, and T is the temperature.

At absolute zero temperature (T=0K), the exponential term in the equation becomes infinite for energies less than EF, and the distribution function simplifies to:

f(E) = 1 / (1 + ∞) = 1 / ∞ = 0

Therefore, for energies less than the Fermi energy at absolute zero temperature, the value of the Fermi-Dirac distribution function is 0. However, it's important to note that this result assumes ideal conditions and a non-degenerate Fermi gas.

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The magnitude of the electric force on object A and on object B is -7.23 × 10⁻⁴ N, and the direction of the electric force on object A is towards the charge B, and the direction of the electric force on the object B is towards the charge A.

Charge A, q₁ = 4.0 × 10⁻⁹ C

Charge B, q₂ = -8.0 × 10⁻⁹ C

Distance between the charge, r² = (0 - 0)² - (2 - 0)²

r = √(4)

r = 2 cm = 0.02 m

Permittivity of free space ε₀ = 8.8 × 10⁻¹² Far/m

The force between two charge object, F = q₁q₂/(4πε₀r²)

F = (4.0 × 10⁻⁹ × -8.0 × 10⁻⁹)/(4 × 3.14 × 8.8 × 10⁻¹² × 0.02²)

F = -7.2 × 10⁻⁴ N

Since opposite charges attracts each other, so the direction of force will be towards each other.

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The formula for the mass remaining after t years for a sample of radium-226 with an initial mass of 100mg is given by \($M(t) = 100 \times 0.5^{t/1590}$\). After 1000 years, the mass is approximately 87mg. The mass will be reduced to 30mg after approximately 2167 years.

(a) The decay of radium-226 follows an exponential decay model, where the amount of radium remaining decreases by half every 1590 years. The formula for the mass remaining after t years can be derived using the half-life concept. Let M(t) represent the mass remaining after t years, then the equation can be written as \($M(t) = 100 \times 0.5^{t/1590}$\). Here, 100 represents the initial mass of the sample, and 0.5 is the decay constant derived from the half-life.

(b) To find the mass after 1000 years, we substitute t = 1000 into the formula: \($M(1000) = 100 \times 0.5^{1000/1590}$\). Evaluating this expression gives us approximately 87mg.

(c) To determine when the mass will be reduced to 30mg, we need to solve the equation \($M(t) = 30$\) for t. Substituting M(t) and rearranging the equation gives us \($100 \times 0.5^{t/1590} = 30$\). Solving this equation, we find t ≈ 2167 years. Therefore, it will take approximately 2167 years for the mass of the radium-226 sample to be reduced to 30mg.

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Answer:

the answer is b

Explanation:

The event horizon is directly related to the mass of the black hole, with larger black holes having larger event horizons.

What is Black Hole?

A black hole is an astronomical object that has collapsed to such a small size that its gravitational pull is so strong that nothing, not even light, can escape it. Black holes are formed from the remnants of massive stars that have run out of fuel and undergone a catastrophic collapse, or from the merging of two or more smaller black holes.

M87 and Ton 618 are both supermassive black holes, with masses estimated to be around 6.5 billion and 66 billion times the mass of the Sun, respectively. However, the size of their event horizons would depend not only on their mass but also on their spin and the density of the surrounding matter. It is therefore not possible to predict which black hole would be bigger without additional data and calculations.

It is worth noting that the first image of a black hole that was released in 2019 was actually an image of the event horizon of the black hole in M87, not the black hole itself. The event horizon of M87's black hole was estimated to be around 40 billion km in diameter, which is larger than the entire solar system.

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In all of the following, with the exception of, degeneracy pressure is the source of the pressure that prevents the crush of gravity. The correct option is D) a very massive main-sequence star.

It's possible that small main-sequence stars will continue to fuse hydrogen for hundreds of billions of years. Red dwarfs are what we call these stars.

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(P4.33) A dielectric cube of side a, centered at the origin, carries a "frozen- in" polarization" P = kr, where k is a constant.(a)The total bound charge is given by Q_b, and since it is proportional to a^3, the bound charges will add up to zero only if k = 0. Otherwise, there will be a non-zero net bound charge.(P4.35)The total bound charge on the surface is given by Q_b, which is equal to -2χ_e q.

Problem 4.33, we have a dielectric cube of side length a centered at the origin. The polarization is given as P = kr, where k is a constant.

To find the bound charges, we need to consider the divergence of the polarization. The bound charge density, ρ_b, is given by:

ρ_b = -∇ · P

In this case, since P = kr, we can calculate the divergence:

∇ · P = ∂(krx)/∂x + ∂(kry)/∂y + ∂(krz)/∂z

= k + k + k

= 3k

Therefore, the bound charge density is:

ρ_b = -3k

To check if the bound charges add up to zero, we need to integrate the bound charge density over the volume of the cube:

Q_b = ∫∫∫ ρ_b dV

Since the polarization is "frozen-in" and the cube is centered at the origin, we can integrate over the volume of the cube:

Q_b = ∫∫∫ (-3k) dV

= -3k ∫∫∫ dV

= -3k (Volume of the cube)

= -3k (a^3)

The total bound charge is given by Q_b, and since it is proportional to a^3, the bound charges will add up to zero only if k = 0. Otherwise, there will be a non-zero net bound charge.

Problem 4.35, we have a point charge q embedded at the center of a sphere with linear dielectric material of susceptibility χ_e and radius R.

To find the electric field, polarization, and bound charge densities, we can use Gauss's Law for dielectric materials. The electric field inside the dielectric sphere is given by:

E = q / (4πε_0 χ_e R^2) * r

where r is the radial distance from the center.

The polarization, P, is related to the electric field by:

P = χ_e ε_0 E

Substituting the expression for E, we get:

P = χ_e q / (4πR^2) * r

The bound charge density, ρ_b, is given by:

ρ_b = -∇ · P

Since P only has a radial component, the divergence simplifies to:

∇ · P = ∂(χ_e q / (4πR^2) * r)/∂r

= χ_e q / (2πR^2)

Therefore, the bound charge density is:

ρ_b = -χ_e q / (2πR^2)

To find the total bound charge on the surface of the sphere, we integrate the bound charge density over the surface area:

Q_b = ∫∫ ρ_b dA

Since the bound charge is on the surface, we can integrate over the surface area of the sphere:

Q_b = ∫∫ (-χ_e q / (2πR^2)) dA

= -χ_e q / (2πR^2) ∫∫ dA

= -χ_e q / (2πR^2) (Surface area of the sphere)

= -χ_e q / (2πR^2) (4πR^2)

= -2χ_e q

The total bound charge on the surface is given by Q_b, which is equal to -2χ_e q. The negative bound charge is located on the surface of the sphere, compensating for the positive charge at the center.

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Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

Answer:

Minimum uniform acceleration in Km/hr² is 20,505.05 km/hr²

Explanation:

In other to determine the acceleration, we can use the formula below

acceleration = velocity/time

Time wasn't given in the question, hence we calculate for time using the parameters given and the formula below

Velocity= distance/time

time = distance/velocity

distance = 2000m ⇔ 2km

time = 2/203

time = 0.0099

Hence, we look for acceleration

which is

acceleration = 203/0.0099

= 20,505.05 km/hr² ⇔ 2.0 × 10⁴

Answer:

the answer is a because I saw it in a syllabus

Answer:

just doing this so you can give brainliest to the other person

have a great day!

Explanation:

Answer:

a

The height is   \(H  = 6.74 \  m \)

b

The horizontal distance is  \(D  = 23.74 \  m \)

Explanation:

From the question we are told that

  The speed is  \(v  =  15 \  m/s\)

  The angle is  \(\theta  =  40^o\)

   The height of the cannon from the ground is  h  =  2 m

  The distance of the net from the ground is k  =  1 m

Generally the maximum height she reaches is mathematically represented as  

     \(H  =  \frac{v^2 sin^2 \theta }{2 *  g }  +  h\)

=>    \(H  =  \frac{(15)^2 [sin (40)]^2 }{2 * 9.8}  +  2\)

=>    \(H  = 6.74 \  m \)

Generally from kinematic equation  

    \(s = ut + \frac{1}{2} at^2\)

Here s is the displacement which is mathematically represented as

         s  =  [-(h-k)]  

    =>  s =  -(2-1)

    =>  s  = -1 m

There reason why s =  -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half

     a =  -g = -9.8

    \(u  =  v sin (\theta)\)

So

    \(-1 = (vsin 40 )t + \frac{1}{2} * (-9.8) t^2\)

=>  \(-4.9t^2 + 9.6418t + 1 = 0\)

using  quadratic formula to solve the equation we have

    \(t  =  2.07 \  s\)

Generally distance covered along the horizontal is  

   \(D  =  v cos (40) *  2.07\)

=>   \(D  =  15 cos (40) *  2.07\)

=>   \(D  = 23.74 \  m \)

Answer :B: Bulbs B and C will remain lit.

If the switch is closed and Bulb A is removed, Bulbs B and C will remain lit. Option B is correct.

An electric bulb is a gadget that uses electricity to create visible light. It is the most popular type of artificial lighting and is necessary for modern society.

The light bulb is connected to a switch in a parallel configuration. The switch is open, which means there will be a lot of resistance and no current will flow via this route.

Across the parallel connection, the battery would create the same potential difference. Because the current would not go via the open switch, it would instead flow through the light bulb, causing it to illuminate.

If the switch is closed, the circuit get completed, hence the current starts flowing in the circuit and the bulb start glowing.

When one bulb in a series circuit is removed out, the rest of the bulbs stop shining and shut off.

But if bulb A is removed,in that condition the only connected bulb can glow. If the switch is closed and Bulb A is removed, Bulbs B and C will remain lit.

Hence, option B is correct.

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Answer:

The first graph has force on the y-axis and extension on the x-axis,

The 2nd graph has extension on the y-axis and force on the x-axis.

The arrows are pointing in opposite directions in both graphs(The bottom arrow points downwards/inwards in the first graph and outwards/upwards in the 2nd graph and so on)

Explanation:

Answer: 0.24 kg/m

At the 39.7 cm mark on the meter stick, the electric potential (relative to infinity) is -140.74 x 106 V.

Electric potential is the effort required to transport an units charge from one place to another in the presence of an electric field. Earth is typically chosen as the reference point, but any location outside the range of the applied electric charge can be used. potential electricity.

Let the negative charge be located at the left end of the meter stick and the positive charge at the right end. E = kq / x2, where k is the Coulomb constant (8.99 x 109 Nm2/C2) and q seems to be the charge at the left end of the meter stick, can be used to calculate the electric field at a location x cm from the left end of the meter stick (4.02 C).

The following equation can be applied to compute the electrical potential difference seen between left end of the meter stick & infinity:

ΔV left = -kq / d = -kq / 100 cm = -kq / 0.01 m = -8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = -359.57 x 10^6 V

Similarly, the electric potential difference between the right end of the meter stick and infinity can be calculated as:

ΔV right = kq / d = kq / 100 cm = kq / 0.01 m = 8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = 359.57 x 10^6 V

The total electric potential difference between the 39.7 cm mark and infinity can then be calculated as:

ΔV_total = ΔV_left + ΔV_right * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 359.57 x 10^6 V * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 218.83 x 10^6 V = -140.74 x 10^6 V

Therefore, the electric potential (V) at the 39.7 cm mark relative to infinity can be calculated as:

V = ΔV_total = -140.74 x 10^6 V

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