3A car travelling at initial velocity 30m/s overtake a bus which was 120m
ahead. The bus then moves with initial velocity 10m/s and accelerate at
5ms-2.
when will the bus also now overtake the car,
what is the time interval
between the arrival of the two cars if the car is to travel a total distance of
450m .
Answers
The bus is 120 m ahead of the car, so the car covers this distance in
120 m = (30 m/s) t
t = (120 m) / (30 m/s)
t = 4 s
Now take the car's position at the moment the car overtakes the bus to be the origin.
Car's position at time t :
x = (30 m/s) t
Bus's position at time t :
x = (10 m/s) t + 1/2 (5 m/s²) t²
The bus overtakes the car when their positions are equal:
(30 m/s) t = (10 m/s) t + 1/2 (5 m/s²) t²
t / (2 s) ((5 m/s) t - 40 m) = 0
t = 0 or t = (40 m) / (5 m/s) = 8 s
If the car travels a total distance of 450 m, then it does so after
450 m = (30 m/s) t
t = (450 m) / (30 m/s)
t = 15 s
The bus overtakes the car in the first 12 s of this journey, so both vehicles reach the same destination with 3 s between them.
Related Questions
If someone gets pushed through a small opening and hits someone else, whose fault is it, the person who got pushed or the person who pushed?
Answers
A physics book slides off a horizontal tabletop with a speed
of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance.
What is the height of the tabletop above the floor in meters.
Answers
A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. The height of the tabletop above the floor is 0.264 m.
Given data:
Speed = 1.10 m/s
Time taken to strike the floor = 0.480 s
We are supposed to find the height of the tabletop above the floor in meters.
We can use the formula of distance to calculate the height of the tabletop above the floor.
We also need to make use of kinematic equations to find out the distance fallen by the book.
Let us first calculate the distance fallen by the book.
Let the height of the table be ‘h’.
From the kinematic equations of motion, we know thats = ut + 1/2 at²Here, u = 1.10 m/s, a = acceleration due to gravity = 9.8 m/s², t = 0.480 s
Putting these values in the above equation, we get:s = 1.10 × 0.480 + 1/2 × 9.8 × (0.480)² = 0.264 m
Now, we can find the height of the tabletop using the formula of distance.d = h + sHere, d = distance fallen by the book = h, s = 0.264 m
Putting these values in the above equation, we get: h = d = s = 0.264 m
Therefore, the height of the tabletop above the floor is 0.264 m.
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A student made the electromagnet shown and use it to pick up one sewing pin. Which change to the electromagnet would most likely allow it to pick up two sewing pins?(I attached a picture of the electromagnet and the answer choices)
Answers
ANSWER:
C. Double the numer of coils of wire around the nail
STEP-BY-STEP EXPLANATION:
In order to let him pick up two sewing pins, the student must double the number of coils around the nail.
Need help solving this problem
Answers
a) The tension in the rope is 123.9 N.
b) The moment of inertia of the wheel is 0.09 kg m².
c) The angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.
(a) To determine the tension in the rope, we need to analyze the forces acting on the object. There are two forces: the force of gravity pulling the object down the incline and the tension force pulling the object up the incline.
The force of gravity can be broken down into two components: one parallel to the incline and one perpendicular to the incline.
The parallel component causes the object to accelerate down the incline, while the perpendicular component is balanced by the normal force of the incline.
The tension force is responsible for the object's acceleration down the incline, so we can set up the following equation:
T - mg sin(theta) = ma
where T is the tension force, m is the mass of the object, g is the acceleration due to gravity, theta is the angle of the incline, and a is the acceleration of the object down the incline.
Putting in the given values, we get:
T - (12.5 kg)(9.81 m/s²)(sin(37°)) = (12.5 kg)(2.00 m/s²)
Solving for T, we get:
T = 123.9 N
Therefore, the tension in the rope is 123.9 N.
(b) To determine the moment of inertia of the wheel, we can use the following equation:
I = (1/2)MR²
where I is the moment of inertia, M is the mass of the wheel, and R is the radius of the wheel.
Putting in the given values, we get:
I = (1/2)(12.5 kg)(0.12 m)²
= 0.09 kg m²
Therefore, the moment of inertia of the wheel is 0.09 kg m².
(c) To determine the angular speed of the wheel after 3.50 s, we can use the following equation:
ω = ω₀ + αt
where ω is the final angular speed, ω₀ is the initial angular speed (which is zero in this case), α is the angular acceleration, and t is the time.
We can find the angular acceleration using the following equation:
α = a/R
where a is the acceleration of the object down the incline (which we already know) and R is the radius of the wheel.
Putting in the given values, we get:
α = 2.00 m/s² / 0.12 m
= 16.7 rad/s²
Putting in the values for α and t, we get:
ω = 0 + (16.7 rad/s²)(3.50 s)
= 58.5 rad/s
Therefore, the angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.
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Select the correct answer.
Which sentence describes an example of sublimation?
A.
Dew forms on leaves on a cold morning.
B.
Liquid deodorant sprayed on a person’s body evaporates.
C.
Dry ice changes to carbon dioxide gas when kept in an open container.
D.
Ice cream in a bowl melts.
E.
Water vapor condenses on a cold surface and forms droplets.
Answers
Answer:
C
Explanation:
Sublimation is when a solid turns into a gas.
A is not sublimation, it is condensation (gas to liquid = water vapor to dew)
B is evaporation (liquid to gas = liquid deodorant to gas)
D is melting (solid to liquid = ice cream to liquid ice cream)
E is condensation (gas to liquid = water vapor to water droplets)
C is the correct answer, because dry ice is a solid and carbon dioxide is a gas, so it is changing from solid to gas.
What is net force 200N air and 600N gravity
Answers
600N - 200N = 400N
Let me know if it works.
A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answers
Answer:
Explanation:
My name is Jeff
Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Answers
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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The train slows down at the railroad crossing. Is that acceleration, velocity, speed, of none of the above?
Answers
Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please
10. In a laboratory experiment, students recorded the
following length data: 12.2 cm, 12.1 cm, 12 cm,
11.9 cm, and 12.20 cm. (a) Determine the average
length and express the answer using the correct
number of significant figures. (b) Based on your
average length calculation in part (a), discuss the
importance of recording measurements to the
appropriate number of significant figures.
Answers
a) 12.1 Average.
B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
What does the average?A data set's mean (average) is calculated by summing all of the numbers in the set, then dividing by the total number of values in the set. When a data collection is ranked from least to greatest, the median is the midpoint.The mean, median, and mode are the three primary varieties of average. Each of these methods operates slightly differently and frequently yields values typically a little off. The average that is most frequently used is the mean. You add all the values and divide this sum by the total number of values to obtain the mean value.Averages are mostly used to track changes over time within a sample group or cohort.Since averages can be used to compare different quantities of the same category, we employ them. The calculation of averages has limits since it cannot reveal how something is distributed among individuals. For instance, the distribution of income is not shown by per capita income.A) Determine the average length and express the answer using the correct number of significant figures:
12.2+12.1+12=36.3/3 = 12.1 Average.
B) Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:
It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger
Answers
During an earthquake, it is important to take appropriate steps to ensure safety
Steps you can follow in two different scenarios(i) When you are in the classroom
Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.
Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.
Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.
(ii) When you are out of danger:
Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.
Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.
Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.
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What is the potential energy of a 12 kg box on a 5 m high shelf?
Answers
Answer:6
Explanation:$’n
Maribel has an iron rod around which she wraps copper wire. She places the device on a table near a compass. What will happen to the compass if she sends current through the copper wire?
A.The needle of the compass will point at a right angle to the device
B. The needle of the compass will point toward the device
C. The needle of the compass will show no effect
D.The needle of the compass will spin in circles
Answers
If Maribel sends current through the copper wire in the iron rod, the needle of the compass will point toward the device.
What is electric current?Electric current is the rate of flow of electric charge.
According to this question, Maribel has an iron rod around which she wraps copper wire. She places the device on a table near a compass.
If Maribel sends current through the copper wire in the iron rod, the needle of the compass will point toward the device because the metallic needle is attracted in the direction of the current.
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After the elevator accelerates, then it moves at a constant speed of 6.0m/s, calculate the tension inthe cable.
Answers
We know that
• The mass of the elevator is 5000 kg.
Let's draw a free-body diagram.
As you can observe, there are just two forces involved, the weight of the elevator and the tension force. Let's use Newton's Second Law.
\(\begin{gathered} \Sigma F_y=ma_y \\ T-W=ma_y \end{gathered}\)But, W = mg = 5000kg*9.8m/s^2 = 49,000 N, and m = 5000 kg, a = 0 (because the speed is constant).
\(\begin{gathered} T-49,000N=5000\operatorname{kg}\cdot0 \\ T=49,000N \end{gathered}\)Therefore, the tension in the cable is 49,000 N.
A 12 volt power supply is connected
to two 30 Ohm resistors in parallel.
What is the voltage drop across the
resistors?
12 V
30 Ω
30 Ω
[?] volts
Answers
24 volts is the voltage drop across each of the resistors in the parallel configuration.
When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.
Given:
Power supply voltage (V) = 12 V
Resistance of each resistor (R) = 30 Ω
Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:
1/R_total = 1/R1 + 1/R2
Substituting the values:
1/R_total = 1/30 Ω + 1/30 Ω
1/R_total = 2/30 Ω
R_total = 15 Ω
Now, we can find the current flowing through the resistors (I) using Ohm's Law:
I = V / R_total
I = 12 V / 15 Ω
I = 0.8 A
Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:
V_drop = I * R
V_drop = 0.8 A * 30 Ω
V_drop = 24 V
Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.
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Which equation relates charge, time, and current?
O 1=
Δg.
1
49
O 1 = Agt
O 1= 49+1
answer fast pls
Answers
Answer:
I = Δq / t
Explanation:
The quantity of electricity i.e charge is related to current and time according to the equation equation:
Q = It
Δq = It
Where:
Q => is the quantity of electricity i.e charge
I => is the current.
t => is the time.
Thus, we can rearrange the above expression to make 'I' the subject. This is illustrated below:
Δq = It
Divide both side by t
I = Δq / t
A tennis ball and a bag filled with sand have the same mass. They are dropped from the same height and they hit the ground. The bag of sand stays on the ground, while the tennis ball rebounds. Which experiences the larger impulse from the ground?
Answers
Answer:
The bag of sand
Explanation:
I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.
In 2015, the minimum wage in Mexico is $7.00 per day. Minimum wage in the US is $60.00 per day at the same time. US workers must be paid overtime for more than 40 hours in a week, whereas Mexican workers may work 48 hours in a week before overtime must be paid. The United States, Canada and Mexico have a trade agreement (the North American Fair Trade Agreement, or NAFTA), that allows companies from the three countries to import and export agricultural (grown) products without tariffs. Tariffs are taxes paid on imports and exports. NAFTA also guarantees that companies from the member countries must honor each other's patents. You are a finance consultant for Bennie's company. Write a memo recommending that Bennie move the company to Mexico. Include the following information: ✓ How re-location of the business will reduce all three of the company's biggest expenses. (Write one paragraph for each of the biggest expenses explaining the benefits of re- location for each). supply ✓ How the re-location will make Bennie more competitive. ✓ Anticipate some of the concerns that Bennie might have about operating a business abroad. Address these concerns in the memo and convince him that the benefits outweigh the potential problems. Use these words in the memo: competition mit 2 NAFTA demand price quantity Section 4 supply chain off-shoring incentive quality manufacturing consumer
Answers
Answer:
Explanation:
MEMORANDUM
To: Bennie
From: Finance Consultant
Subject: Recommendation to Move the Company to Mexico
I am writing to recommend that we move our company to Mexico. The move will reduce our expenses, make us more competitive, and provide several other benefits. In this memo, I will discuss the three biggest expenses and how the move will help reduce them.
Firstly, labor is one of the biggest expenses for our company. The minimum wage in Mexico is only $7.00 per day, which is significantly lower than the $60.00 per day in the US. Furthermore, Mexican workers may work 48 hours in a week before overtime must be paid, whereas US workers must be paid overtime for more than 40 hours in a week. This means that we can save a lot of money on labor costs by relocating to Mexico.
Secondly, transportation is another major expense for our company. Mexico is closer to many of our suppliers, which means that we can reduce transportation costs by sourcing our materials locally. This will also help us to reduce our carbon footprint by decreasing the amount of fuel we use for transportation.
Thirdly, the cost of doing business in Mexico is generally lower than in the US. Mexico has lower taxes and fewer regulations, which means that we can save money on compliance and other administrative costs. Additionally, the North American Fair Trade Agreement (NAFTA) allows companies from the member countries to import and export agricultural products without tariffs, which will help us to reduce our costs further.
The re-location will make us more competitive by allowing us to offer lower prices to our customers. Lower labor and transportation costs will enable us to produce our products at a lower cost, which means that we can sell them at a lower price. This will help us to increase our market share and attract more customers.
I anticipate that Bennie may have concerns about operating a business abroad. However, the benefits of the move far outweigh the potential problems. By off-shoring to Mexico, we can take advantage of the incentives provided by the Mexican government and create a better supply chain for our manufacturing processes. We can also maintain the quality of our products and ensure that they meet the demand and quantity required by our consumers.
In conclusion, I strongly recommend that we move our company to Mexico. The move will reduce our expenses, make us more competitive, and provide several other benefits. Thank you for your consideration, and please do not hesitate to contact me if you have any questions.
Sincerely,
[Your Name]
how much ume does it take to use 300 W of power to do 1800 J of Work?
Answers
Answer:
P=300 W
W=1800 J
P=W/t
t=W/P
t=6 s
water flows into the house by means of pipe.inner diameter 2,4cm
absolute pressure 400kpa
flow rate 6
height 4
upper level inner diameter 1,2cm
calculate pressure at the upper level
Answers
The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.
How to determine pressure?Calculate the cross-sectional area of the lower pipe:
A₁ = πr₁²
where:
A₁ = cross-sectional area of the lower pipe (m²)
π = mathematical constant (3.14)
r₁ = radius of the lower pipe (m)
A₁ = π(0.12 m)² = 0.0452 m²
Calculate the cross-sectional area of the upper pipe:
A₂ = πr₂²
where:
A₂ = cross-sectional area of the upper pipe (m²)
π = mathematical constant (3.14)
r₂ = radius of the upper pipe (m)
A₂ = π(0.06 m)² = 0.0113 m²
Calculate the flow rate per unit area:
q = Q/A
where:
q = flow rate per unit area (m³/s)
Q = flow rate (m³/s)
A = cross-sectional area (m²)
q = 6 m³/s / 0.0452 m² = 13.28 m²/s
Calculate the velocity of the water in the lower pipe:
v₁ = q/A₁
where:
v₁ = velocity of the water in the lower pipe (m/s)
q = flow rate per unit area (m³/s)
A₁ = cross-sectional area of the lower pipe (m²)
v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s
Calculate the velocity of the water in the upper pipe:
v₂ = q/A₂
where:
v₂ = velocity of the water in the upper pipe (m/s)
q = flow rate per unit area (m³/s)
A₂ = cross-sectional area of the upper pipe (m²)
v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s
Calculate the head loss:
hL = (v₁² - v2₂²) / 2g
where:
hL = head loss (m)
v₁ = velocity of the water in the lower pipe (m/s)
v₂ = velocity of the water in the upper pipe (m/s)
g = acceleration due to gravity (9.8 m/s²)
hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m
Calculate the pressure at the upper level:
p₂ = p₁ + ρghL
where:
p₂ = pressure at the upper level (Pa)
p₁ = pressure at the lower level (Pa)
ρ = density of water (1000 kg/m³)
g = acceleration due to gravity (9.8 m/s²)
hL = head loss (m)
p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa
Therefore, the pressure at the upper level is 1081 kPa.
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in 10 minutes a heart can beat 700 times at this rate in how many minutes will a heart beat 140 times at what rate can a heart beat
Answers
28. An electron with a speed of 4.0 x 10° m/s enters a uniform magnetic field of magnitude 0.040 T at an angle of 35 degrees to the magnetic field lines. The electron will follow a helical path. a) Determine the radius of the helical path. b) How far forward will the electron have moved after completing one circle?
Answers
Answer:
r= 1.09×10^-4
Explanation:
Given
V=speed=4.0×10^5 m/s
B= magnetic field= 0.040 T
©=angle= 35°
m= mass of electron= 9.11×10^-31
q= charge of electron= 1.60×10^-19
solution
qv×B= mv²/r
qvBsin©=mv²/r
qBsin©=mv/r
r=mv/qBsin©
r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)
r= 1.09×10^-4 m
a) r = 1.09 * \(10^{-4}\) m
b) Distance travelled : 6.845 * \(10^{-4}\) m
What is an electron ?
An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
given
charge of electron : 1.6 * \(10^{-19}\) C
mass of electron = 9.11 * \(10^{-31}\) kg
v = 4.0 x 10 m/s
B = 0.040 T
theta = 35 degrees
since ,
force in magnetic field on electron = centripetal force
a) q(v*B) = m \(v^{2}\) / r
q v B sin(theta) = m \(v^{2}\) / r
r =m v /q B sin(theta)
r = 9.11 * \(10^{-31}\) * 4.0 x \(10^{5}\)/ 1.6 * \(10^{-19}\) sin (35)
r = 1.09 * \(10^{-4}\) m
b) far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr
= 2 * 3.14 * 1.09 * \(10^{-4}\) m = 6.845 * \(10^{-4}\) m
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1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answers
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
Personally, do you think you will benefit from the discoveries of Archimedes’ and Pascal’s Principles? How?
Answers
Answer:
whats the question
Explanation:
A string of length 75.0cm has fixed ends. Two consecutive harmonics are 420 Hz and 315 Hz. Find the wave speed and the fundamental frequency.
please use equations: f=vλ and λ=\(\frac{2L}{n}\)
Answers
The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).
We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).
Using n=1 and λ=2L/n, we get:
λ = 2L/1
λ = 2L
Using n=3 and λ=2L/n, we get:
λ = 2L/3
Using n=5 and λ=2L/n, we get:
λ = 2L/5
We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:
v/λ1 = f1
v/λ2 = f2
Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:
λ1 = 2L/1 = 2L
λ2 = 2L/3
Substituting these values into the above equations and solving for v, we get:
v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s
To find the fundamental frequency, we use the formula f=v/λ1:
f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz
Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 60.0-kg man just before contact with the ground has a speed of 4.18 m/s. (a) In a stiff-legged landing he comes to a halt in 1.00 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.245 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answers
Answer:
a) The average force that acts on the man is \(2.508\times 10^{8}\) newtons.
b) The average force that acts on the man is 1023.673 newtons.
c) The force of the ground on the man is 1612.093 newtons upwards.
Explanation:
a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:
\(m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}\) (Eq. 1)
Where:
\(m\) - Mass of the man, measured in kilograms.
\(\vec v_{A}\) - Initial velocity of the man, measured in meters per second.
\(\vec v_{B}\) - Final velocity of the man, measured in meters per second.
\(\Delta t\) - Impact time, measured in seconds.
\(\vec F\) - Average net force, measured in newtons.
Now we proceed to clear average net force within expression:
\(\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})\)
\(\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})\) (Eq. 2)
If we know that \(m = 60\,kg\), \(\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\), \(\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\) and \(\Delta t = 1\times 10^{-6}\,s\), we obtain the following vector:
\(\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right]\)
\(\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N]\)
The average force that acts on the man is \(2.508\times 10^{8}\) newtons.
(b) If we know that \(m = 60\,kg\), \(\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\), \(\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\) and \(\Delta t = 0.245\,s\), we obtain the following vector:
\(\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right]\)
\(\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right]\)
The average force that acts on the man is 1023.673 newtons.
(c) From Second Newton's Law we find the following equation of equilibrium:
\(\vec F = \vec N -\vec W\) (Eq. 3)
Where:
\(\vec F\) - Average force that acts on the man, measured in newtons.
\(\vec N\) - Force of the ground on the man, measured in newtons.
\(\vec W\) - Weight of the man, measured in newtons.
By applying the concept of weight, we expand the previous equation:
\(\vec F = \vec N -m\cdot \vec g\) (Eq. 3b)
Where \(\vec g\) is the gravitational acceleration, measured in meters per square second.
And then we clear the force of the ground on the man:
\(\vec N = \vec F +m\cdot \vec g\) (Eq. 4)
If we get that \(\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right]\), \(m = 60\,kg\) and \(\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right]\), the average force is:
\(\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right]\)
\(\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right]\)
The force of the ground on the man is 1612.093 newtons upwards.
Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?
Answers
What do you picture in your mind when you read this simile?
Bolt runs as fast as lighting.
Bolt runs very fast.
Bolt runs in a straight line.
Bolt runs in a wavy manner.
Bolt's each step produces thunder.
Answers
When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."
This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.
While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.
Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.
Know more about the simile here:
https://brainly.com/question/1443894
#SPJ8
the following question is about relation between the period and mass attached in spring.
Answers
ω = sqrt( k/m )
ω: angular frequency; m: mass; k: spring constant
ω = 2π/T
T: period (how long it takes for one revolution)
T = 4.59s/10rev = 0.459s/rev
ω = 2π/T = ω = 2π/0.459
ω = 13.6889 radians/s
One revolution, or 2π radians, is 8 cm. (4 cm to stretch out, the same 4 cm to retract)
13.6889 radians/s * (4cm/2πradians) = 86.01 cm/s
ω = 86.01 cm/s = 0.086 m/s
Let's take the first example, where mass is 50g and angular freq. is 4.59s.
50g = 0.05 kg (kilograms are standard in SI, not grams, and are used more directly in calculations relating to force)
ω = sqrt( k/m )
0.086 = sqrt( k/0.05 )
Square both sides
0.007396 = k/0.05
multiply both by 0.05
k = 0.0003698 N/m = 3.698 * 10^-4 N/m
Let's graph frequency in relation to mass (mass is the independent variable)
Let's calculate the slope of the period-to-mass graph
m (slope) = (T2 - T1)/(m2 - m1) (change in frequency over change in mass)
Let's use the second example for T2 and T2, and the first for ω1 and m1.
m = (6.32-4.59)/(100-50) = 1.73/50
m = 0.0346 seconds/gram, which means for every gram of mass added, the period for 10 revolutions increases by 0.0346 seconds.
if vector A and B has equal magnitude and A+B is 3 times larger than A-B what is the angle of A and B Search instead for if vector A and B has equal magnitude and A+B is three times larger than A-B what must be the angle of A and B
Answers
Answer:
Let's represent the magnitude of both vectors A and B using the variable "m".
According to the problem statement, we have:
|A| = |B| = m
|A+B| = 3|A-B|
Squaring both sides, we get:
|A+B|^2 = 9|A-B|^2
Expanding the left-hand side using the dot product formula, we have:
(A+B)·(A+B) = A·A + 2A·B + B·B
Similarly, expanding the right-hand side, we have:
9(A-B)·(A-B) = 9A·A - 18A·B + 9B·B
Substituting the given magnitudes, we have:
(A+B)·(A+B) = 2m^2 + 2(A·B)
9(A-B)·(A-B) = 18m^2 - 18(A·B)
Substituting these expressions back into the original equation, we get:
2m^2 + 2(A·B) = 9(18m^2 - 18(A·B))
Simplifying and rearranging, we get:
20(A·B) = 323m^2
Dividing by |A|·|B| = m^2, we have:
20(cosθ) = 323
where θ is the angle between vectors A and B. Solving for θ, we get:
θ = cos⁻¹(323/20)/π * 180
θ ≈ 83.4 degrees