indicate the number of protons and neutrons in the following nuclei. part a 5624mn2456mn express your answers as integers separated by a comma.

Answer:

1. The two gases making the highest relative contribution to the greenhouse gases are: "CO2 and CH4."

2. The effect of increasing amount of greenhouse gasses is: "All of the above"

3. Which one of the following is a wrong statement?: "Eutrophication is a natural phenomenon in freshwater bodies"

4. The major contributors to the greenhouse gases are: "All of the above"

Explanation:

CO2 is carbon dioxide, and CH4 is methane. Also, the greenhouse gas effect is natural, except, the amount of greenhouse gases is not.

1176 g of H2SO4 is needed to prepare 6.0L of a 2 M H2SO4 solution.

What do you mean by solution?

Solution in chemistry is a homogeneous mixture composed of two or more substances in which the molecules of the solute are completely dispersed in the solvent. Solutions are typically liquid, but can also be solid or gaseous.

We know,

Molarity (M) = moles/volume

Therefore, moles = Molarity x Volume

moles = 2 M x 6 L

moles = 12 moles

1 mole of H2SO4 = 98 g

Therefore, 12 moles of H2SO4 = 12 x 98 g

= 1176 g of H2SO4

Hence, 1176 g of H2SO4 is needed to prepare 6.0L of a 2 M H2SO4 solution.

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Answer:

45 m/s north

Explanation:

Edge 2020

Answer: (B) 45 m/s north

Explanation: right on edge 2020 (so basically the same reason as person above)

The solutions ae all acidic with pH less than 7.

a) To calculate the pH of a solution with [H+] = 1.2 x 10^(-1) M:

pH = -log[H+]

pH = -log(1.2 x 10^(-1))

pH = -log(1.2) + log(10^(-1))

pH = -log(1.2) - 1

pH ≈ 0.92

The solution is acidic.

b) To calculate the pH of a solution with [H+] = 5.8 x 10^0 M:

pH = -log[H+]

pH = -log(5.8 x 10^0)

pH = -log(5.8)

pH ≈ 0.24

The solution is acidic.

c) To calculate the pH of a solution with [H+] = 3.92 x 10^(-3) M:

pH = -log[H+]

pH = -log(3.92 x 10^(-3))

pH ≈ 2.41

The solution is acidic.

a) To calculate [H+] in a solution with pH = 2.5:

[H+] = 10^(-pH)

[H+] = 10^(-2.5)

[H+] ≈ 3.16 x 10^(-3) M

The solution is acidic.

b) To calculate [H+] in a solution with pH = 3.31:

[H+] = 10^(-pH)

[H+] = 10^(-3.31)

[H+] ≈ 4.54 x 10^(-4) M

The solution is acidic.

a) To calculate the pH for a solution with pOH = 4.18:

pOH + pH = 14

pH = 14 - pOH

pH = 14 - 4.18

pH ≈ 9.82

b) To calculate the pH for a solution with pOH = 12.35:

pOH + pH = 14

pH = 14 - pOH

pH = 14 - 12.35

pH ≈ 1.65

a) To calculate the pOH for a solution with pH = 6.2:

pOH + pH = 14

pOH = 14 - pH

pOH = 14 - 6.2

pOH ≈ 7.8

b) To calculate the pOH for a solution with pH = 9.55:

pOH + pH = 14

pOH = 14 - pH

pOH = 14 - 9.55

pOH ≈ 4.45

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The balanced chemical equation for the reaction between nitrogen gas and hydrogen gas that produces ammonia is provided.N2+3H→2NH3.

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The figure shows particles of a substance in a closed container. The state of matter shown in the figure is a gas.

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The volume of water needed to dilute the solution to obtain a 0.25 M NaCl solution is 75 mL

M₁V₁ = M₂V₂

1 × 25 = 0.250 × V₂

25 = 0.25 × V₂

Divide both side by 0.25

V₂ = 25 / 0.25

V₂ = 100 mL

Volume of water = V₂ – V₁

Volume of water = 100 – 25

Volume of water = 75 mL

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The oxidation state of iodine in diiodine pentoxide (I₂O₅) is +5,  the oxidation state of xenon in xenon trioxide (XeO₃) is +6, and the oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is +3.

The oxidation state (or oxidation number) of an element is the number of electrons it has gained or lost to form a chemical bond.

The oxidation state of iodine in diiodine pentoxide (I₂O₅) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of iodine.

The total oxidation state due to the two iodine atoms in the molecule is 2x.

The total oxidation state due to the five oxygen atoms in the molecule is (-2) x 5 = -10.

The sum of the oxidation states is 2x - 10 = 0.

Solving for x, we get:

2x - 10 = 0

2x = 10

x = +5

The oxidation state of xenon in xenon trioxide (XeO₃) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of xenon.

The total oxidation state due to the xenon atom in the molecule is x.

The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.

The sum of the oxidation states is x - 6 = 0.

Solving for x, we get:

x - 6 = 0

x = +6

The oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of the manganese.

The total oxidation state due to the two manganese atoms in the molecule is 2x.

The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.

The sum of the oxidation states is 2x - 6 = 0.

Solving for x, we get:

2x - 6 = 0

2x = 6

x = +3

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Answer:

1- damp

meaning: slightly wet

2-stain

meaning: smear

3-scrub

meaning: rub

4-rust

meaning: stain form iron

5-bleach

meaning: expose under the sun

hope it helps, mark as brainliest!

The resistance of the light bulb is 266.7Ω

When an electric current flows through a bulb or any conductor, the conductor offers some obstruction to the current and this obstruction is known as electrical resistance and is denoted by R. Every material has an electrical resistance and this is the reason why conductors give out heat when current passes through it. The unit of electrical resistance is ohms.

According to Ohm’s law, there is a relation between the current flowing through a conductor and the potential difference across it. It is given by,

V ∝ I V = IR

Where,

V is the potential difference measured across the conductor (in volts)

I is the current through the conductor (in amperes)

R is the constant of proportionality called resistance (in ohms)

Therefore, R = V/I

To find the Resistance;

R = V/I

where V = 120V

I = 0.45A

R = 120/0.45

R = 266.7Ω

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1) We have that one mole of Platinum is 195,084 g/mol

2) The Avogadro number is 6,022x1023.

5 significant, because u have to start counting after the point

There are four significant figures in the given measurement  as there are  four non-zero numbers after the decimal.

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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Electronic structure refers to the way atoms are organized according to electron shell theory. It tells us what energy level the electrons are in and the number of electrons per energy level.

The groups of the periodic table are classified according to the valence electrons, that is, the electrons that they have in their last energy level. These electrons can make an atom more or less reactive. For example, an element in the last period, period 8. It has 8 valence electrons, that is, it complies with the octet rule and these atoms are very stable. Therefore, its reactivity is very low compared to other groups.

Groups 1 and 7 are quite reactive since group 1 has an electron in the last energy level. So it only has to lose one electron to form a bond and react. Group 7 has 7 electrons in its last energy level, that is, it needs 1 electron to form a bond. In general, group 7 elements are very reactive with group 1 elements.

So the main difference in group reactivity will be the valence electrons.

Answer:

less than 4.9 newtons Explanation:

Draw the substituted ring structure in which the chlorine is attached to the ring.

The benzene structure contains only 6 carbons and 6 hydrogens. The ring is replaced where the chlorine is attached to the ring. Therefore, the hydrogen-1 on the benzene ring is replaced by an ethyl group, and another hydrogen on the benzene ring is replaced by a chlorine group. Concerning the chlorine bond, there are 3 possible structures grouped called ortho, meta, and para.

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Answer:

1) Shortage of gas

2) shortage of electricity

Answer:

The somatosensory cortex is a region of the brain which is responsible for receiving and processing sensory information from across the body, such as touch, temperature, and pain.

Area 1 specifically is important in sensing the texture of an object. :)

Hope this helps!

Answer:

we are given that mass of lithium four spade that is equal to 77.7 grams

Answer:

D I think

Explanation:

cuz 0 j means there is nothing moving

Answer:

D. when an object is no longer in motion.

Explanation:

Answer:

0.396 J/g°C (to 3 sf)

Explanation:

50.0 = 10.6(24.9-13.0)(c)

c = 0.396 J/g°C (to 3 sf)

Answer:

is capable of combining with oxygen to form iron oxide

There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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Answer:

a metal which is found in 13 group and 3 period of periodic table

Answer:

According to the balanced chemical equation for the reaction:

N₂ + 3H₂ → 2NH₃

1 volume of nitrogen (N₂) reacts with 3 volumes of hydrogen (H₂) to form 2 volumes of ammonia (NH₃) at the same temperature and pressure.

Therefore, if 300 ml of nitrogen (N₂) reacts with 300 ml of hydrogen (H₂), the limiting reactant will be hydrogen, since it is present in the smallest amount. To find the volume of ammonia (NH₃) formed, we can use the volume ratio from the balanced chemical equation:

1 volume of N₂ + 3 volumes of H₂ → 2 volumes of NH₃

Since we have 300 ml of H₂, which is equivalent to 3 volumes of H₂, the maximum volume of ammonia (NH₃) that can be formed is:

2 volumes of NH₃ = 300 ml of H₂ × (2 volumes of NH₃ / 3 volumes of H₂) = 200 ml

Therefore, the correct option is (b) 200 ml.

The electronic configuration of ‘N’ atom is 2, 5 and to have Octet in the valence shell it requires three more electrons.When two nitrogen atoms approach each other, each atom contributes 3 electrons for bonding.There are six electrons shared between two nitrogen atoms in the form of three pairs.Therefore, there is a triple bond between two nitrogen atoms in $N _{ 2 }$ molecules.

Answer:

100ml x 0.774

divide by 4

x by 8

The acceleration of the car is -2.3m/s².

Acceleration is the rate at which the direction and speed of motion change over time. It is said to have been accelerated when something changes its direction and moves faster or slower. Motion on a circle accelerates even when the speed is constant because the direction is constantly changing.

Velocity is the rate at which displacement changes. The rate at which speed changes is known as acceleration. Because it consists of both magnitude and direction, velocity is a vector quantity. Since acceleration is merely the rate at which velocity changes, it too is a vector quantity.

v = u +at

0 = 35 + a×15

15a = -35

a = -35/15

a = -2.3m/s².

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Answer:

B. -2.3 m/s²

Explanation:

To answer this question, we have to use the following formula:
\(\boxed{a = \frac{v - u}{t}}\),

where:

• a ⇒ acceleration

• v ⇒ final velocity

• u ⇒ initial velocity

• t ⇒ time taken for the change in velocity to occur

From the question, we know that initially, the car was travelling at 35 km/h. Therefore, u = 35 km/h. The question also tells us that the car comes to a full stop, meaning its final velocity is 0 m/s. Therefore, v = 0 km/h. It takes the car 15 seconds to stop, so t = 15 s.

Using the information above and substituting it into the formula, we can calculate the acceleration of the car:

\(a = \frac{0 - 35}{15}\)

  = -2.3 m/s²

Therefore, the acceleration of the car is -2.3 m/s², and the correct answer is B.

Answer:

\(n_{CO(NH_2)_2}=73.3molCO(NH_2)_2\)

Explanation:

Hello.

In this case, given the two balanced chemical reactions:

\(CO(NH_2)_2 (l) \rightarrow HNCO(l) + NH_3(g)\\\\ 6HNCO(l) \rightarrow C_3N_3(NH_2)_3 (l) + 3CO_2(g)\)

We first compute the moles of HNCO from the obtained 1.00 kg of melamine (molar mass 126 g/mol) by considering the 65 % yield:

\(m_{C_3N_3(NH_2)_3}^{theoretical}=\frac{1.00kg}{0.65}=1.54kg\)

\(n_{HNCO}=1.54kgC_3N_3(NH_2)_3*\frac{1000g}{1kg}*\frac{1molC_3N_3(NH_2)_3}{126gC_3N_3(NH_2)_3} *\frac{6molHNCO}{1molC_3N_3(NH_2)_3} \\\\n_{HNCO}=73.3molHNCO\)

Next, we compute the moles of urea in the first chemical reaction:

\(n_{CO(NH_2)_2}=73.3molHNCO*\frac{1molCO(NH_2)_2}{1molHNCO} \\\\n_{CO(NH_2)_2}=73.3molCO(NH_2)_2\)

Best regards.

Answer:

no

Explanation:

different mixtures have different boiling and melting points

Answer:

Yes, they do.

Explanation:

To boil at a constant temperature, the vapour composition of the mixture has to account for liquid mixture composition.

And these mixtures are known as azeotropes or azeotropic mixture

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