34. The temperature increased 2º per hour for six hours. How many degrees did the temperature raise after six hours? Number Expression: Sentence Answer:​

Answers

Answer 1

Answer: 12º

Step-by-step explanation:

       If the temperated is raised 2 degrees every hour, and we are accounting for 6 hours, we can multiply 2 by 6 to find how many degrees the temperature was raised.

2 degrees * 6 hours = 12º

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Answer 2
The temperature raised by a total of 12 degrees after six hours.

Related Questions

Suppose that a particular experiment will have outcome “A” with probability 13 and outcome “B” with probability of 23. If you were to perform this experiment 90 times, approximately how many times would you expect outcome “B” to occur

Answers

HsjshdbbNsbdbdbsnsnjss

find the exact value of the expression, if possible.arcsin[sin(9π/4)]

Answers

The exact value of the expression arcsin[sin(9π/4)] is π/4 or 45°.

Step-by-step explanation:

We know that the range of the arcsine function is from -π/2 to π/2.

Now, let's evaluate sin(9π/4). Since one full rotation is equal to 2π radians, we can subtract 2π radians from 9π/4 until we get an angle between 0 and 2π.

9π/4 - 2π = π/4

So, sin(9π/4) is equal to sin(π/4).

Now, we know that sin(π/4) = 1/√2.

Therefore, we can evaluate the given expression as:

arcsin[sin(9π/4)] = arcsin[sin(π/4)]

= arcsin[1/√2]

The arcsine of 1/√2 is equal to π/4 or 45°, since the sine is positive in the first and second quadrants.

Hence, the exact value of the expression arcsin[sin(9π/4)] is π/4 or 45°.

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You and 5 friends go to a concert. In how many different orders can you sit in the assigned seats?​

Answers

Answer: 720

Step-by-step explanation:

This is permutations.

To find all of the possible choices, you will have the number of seats with the mathematical exclamation mark after that number.

5 + you = 6 people

6! = 720

You and your 5 friends can sit in your seats 720 different ways.

Standard Appliances obtains refrigerators for $1,620 less 26% and 6%. Standard's overhead is 17% of the selling price of $1,690. A scratched demonstrator unit from their floor display was cleared out for $1,345. a. What is the regular rate of markup on cost? % Round to two decimal places b. What is the rate of markdown on the demonstrator unit? % Round to two decimal places c. What is the operating profit or loss on the demostrator unit? Round to the nearest cent d. What is the rate of markup on cost that was actually realized? % Round to two decimal places

Answers

a. The regular rate of markup on cost is approximately 26%.

b. The rate of markdown on the demonstrator unit is approximately 20%.

c. The operating profit on the demonstrator unit is approximately $3.73.

d. The rate of markup on cost that was actually realized is approximately 0.28%.

a. To calculate the regular rate of markup on cost, we need to find the difference between the selling price and the cost, and then calculate the percentage markup based on the cost.

Let's denote the cost as C.

Selling price = Cost + Markup

$1,690 = C + (26% of C)

To find the cost:

$1,690 = C + 0.26C

$1,690 = 1.26C

C = $1,690 / 1.26

C ≈ $1,341.27

Markup on cost = Selling price - Cost

Markup on cost = $1,690 - $1,341.27

Markup on cost ≈ $348.73

Rate of markup on cost = (Markup on cost / Cost) * 100

Rate of markup on cost = ($348.73 / $1,341.27) * 100

Rate of markup on cost ≈ 26%

The regular rate of markup on cost is approximately 26%.

b. The rate of markdown on the demonstrator unit can be calculated by finding the difference between the original selling price and the clearance price, and then calculating the percentage markdown based on the original selling price.

Original selling price = $1,690

Clearance price = $1,345

Markdown = Original selling price - Clearance price

Markdown = $1,690 - $1,345

Markdown = $345

Rate of markdown on the demonstrator unit = (Markdown / Original selling price) * 100

Rate of markdown on the demonstrator unit = ($345 / $1,690) * 100

Rate of markdown on the demonstrator unit ≈ 20%

The rate of markdown on the demonstrator unit is approximately 20%.

c. Operating profit or loss on the demonstrator unit can be calculated by finding the difference between the clearance price and the cost.

Cost = $1,341.27

Clearance price = $1,345

Operating profit or loss = Clearance price - Cost

Operating profit or loss = $1,345 - $1,341.27

Operating profit or loss ≈ $3.73

The operating profit on the demonstrator unit is approximately $3.73.

d. The rate of markup on cost that was actually realized can be calculated by finding the difference between the actual selling price (clearance price) and the cost, and then calculating the percentage markup based on the cost.

Actual selling price (clearance price) = $1,345

Cost = $1,341.27

Markup on cost that was actually realized = Actual selling price - Cost

Markup on cost that was actually realized = $1,345 - $1,341.27

Markup on cost that was actually realized ≈ $3.73

Rate of markup on cost that was actually realized = (Markup on cost that was actually realized / Cost) * 100

Rate of markup on cost that was actually realized = ($3.73 / $1,341.27) * 100

Rate of markup on cost that was actually realized ≈ 0.2781% ≈ 0.28%

The rate of markup on cost that was actually realized is approximately 0.28%.

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create an expression with these conditions:the expression has 3 terms.the expression has a coefficient of 5.the expression has a constant of 8.move a number or variable to each line to create the expression.response area with 4 blank spacesblank space 1 empty plus blank space 3 empty blank space 4 empty plus blank space 7 emptyanswer options with 4 options.

Answers

The expression in the format "5(blank space 1) + (blank space 3)(blank space 4) + 8(blank space 7)" represents a mathematical expression with three terms. To create the expression with the given conditions, we can use the following format:

5(blank space 1) + (blank space 3)(blank space 4) + 8(blank space 7)

Here are four options for each blank space:

Option 1:

Blank space 1: x

Blank space 3: 2

Blank space 4: y

Blank space 7: z

So the expression would be:

5x + 2y + 8z

Option 2:

Blank space 1: a

Blank space 3: 3

Blank space 4: b

Blank space 7: c

So the expression would be:

5a + 3b + 8c

Option 3:

Blank space 1: m

Blank space 3: 4

Blank space 4: n

Blank space 7: p

So the expression would be:

5m + 4n + 8p

Option 4:

Blank space 1: r

Blank space 3: 1

Blank space 4: s

Blank space 7: t

So the expression would be:

5r + s + 8t

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BRAINLIEST ANSWER GIVEN Solve inequality and write interval notation.\(5x+4\leq x-8\)

Answers

Answer:

\(x\leq -3\)

Step-by-step explanation:

I can't write interval notation on Brainly but I can solve the inequality.

\(5x+4\leq x-8\)

Subtract \(x\) from both sides

\(4x+4\leq -8\)

Subtract 4 from both sides

\(4x\leq -12\)

Divide both sides by 4

\(x\leq -3\)

A mural inspired by a photograph measures 108 inches by 180 inches. The scale of the photograph to the mural is 1.:12 in. What are the dimensions of the photograph

Answers

Answer:

108 inches and 2160 inches

Step-by-step explanation:

108 inches = 274.32 cm

180 inches = 457.2 cm

The area of the mural, A1 = 274.32 X 457.2 = 125419.1 cm²

Let the area of the photograph = A2

The scale A1 to A2,

1/12 = A1/A2

1/12 = 125419.1/A2

∴ A2 = 12 X 125419.1 = 1505029.2 cm²

For their lenghs

1/12 = L1/L2

1/12 = 457.2/L2

L2 = 12 X 457.2 = 5486.4 cm (or 2160 inches)

The width of  the photograph

1505029.2/5486.4 = 274.3 cm ( 108 inches)

Ellis weighs 7 stone and 5 pounds. Ed weighs 50 kilograms. 1 kg is Which of the two is heavier and by how much?​

Answers

The ellis weight is heavier and by 7.23 lbs.

We are given that;

Weight= 5pounds

Now,

To convert Ed’s weight from kilograms to pounds, we can multiply by the conversion factor of 2.20462262185. We get:

Ed’s weight in pounds = 50 kg * 2.20462262185 lbs/kg Ed’s weight in pounds = 110.2311310925 lbs

To convert Ellis’s weight from stones and pounds to pounds, we can multiply the number of stones by 14 and add the number of pounds. We get:

Ellis’s weight in pounds = 7 stones * 14 lbs/stone + 5 lbs Ellis’s weight in pounds = 98 + 5 Ellis’s weight in pounds = 103 lbs

To compare the weights, we can subtract them and see which one is larger. We get:

Ed’s weight - Ellis’s weight = 110.2311310925 lbs - 103 lbs Ed’s weight - Ellis’s weight = 7.2311310925 lbs

Therefore, by unitary method the answer will be 7.23 lbs.

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give an equation in the standard coordinates for images that describes an ellipse centered at the origin with a length 4 major cord parallel to the vector images and a length 2 minor axis. (the major cord is the longest line segment that can be inscribed in the ellipse.)

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An equation in the standard coordinates for images that describes an ellipse centered at the origin with a length 4 major cord parallel to the vector images and a length 2 minor axis is (x^2)/4 + (y^2) = 1.

An ellipse centered at the origin with a length 4 major chord parallel to the vector images and a length 2 minor axis can be described by the following equation in standard coordinates:

(x^2)/(a^2) + (y^2)/(b^2) = 1

"a" represents the semi-major axis, and "b" represents the semi-minor axis. Since the major chord has a length of 4, the semi-major axis (a) is half of that, or 2. Similarly, the minor axis has a length of 2, so the semi-minor axis (b) is half of that, or 1.

Substituting these values into the equation, we get:

(x^2)/(2^2) + (y^2)/(1^2) = 1

Simplifying the equation, we have:

(x^2)/4 + (y^2) = 1

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prove that the set of solutions of any system of linear equations can always be represented as the sum of an arbitrary solution and the subspace of solutions of the homogenous system corresponding to the given system

Answers

The Fundamental Theorem of Linear Algebra states that the set of solutions of any system of linear equations can be represented as the sum of an arbitrary solution and the nullspace (subspace) of the homogeneous system corresponding to the given system.

A system of linear equations consists of multiple linear equations with the same variables. The goal is to find a set of values for the variables that satisfy all the equations simultaneously.

The homogeneous system of linear equations is obtained by setting all the right-hand sides of the equations to zero. In other words, the homogeneous system has the same equations as the given system, but without the constant terms.

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Is 3 a an algebraic expression?

Answers

No, 3 is not an algebraic expression.

In mathematics, an algebraic expression is a combination of numbers, variables and arithmetic operations (such as addition, subtraction, multiplication and division) that can be evaluated to a specific value when the variables are assigned specific numerical values.

For example, 3x + 2 is an algebraic expression. Here, x is the variable and 3, 2 are constants. We can substitute any numerical value for x and evaluate the expression for that specific value.

On the other hand, 3 is a numerical value, not an expression. It doesn't contain any variables or operators that can be evaluated for different values. It is a constant value, it doesn't change with the change of x or any other variable.

In summary, an algebraic expression is a combination of numbers, variables and arithmetic operations, whereas 3 is just a numerical value, not an algebraic expression.

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(b) Factorise fully 9b-3b squared

Answers

Answer:

Step-by-step explanation:

b(9-3)

how do you increase 220 by 5%

Answers

Step-by-step explanation:

Increase the number by 5% of its value.

Percentage increase = 5% × 220

New value =

220 + Percentage increase =

220 + (5% × 220) =

220 + 5% × 220 =

(1 + 5%) × 220 =

(100% + 5%) × 220 =

105% × 220 =

105 ÷ 100 × 220 =

105 × 220 ÷ 100 =

23,100 ÷ 100 =

231

If the variable attractiveness increases as the variable weight remains constant, the correlation is said to be?

Answers

If the variable attractiveness increases while the variable weight remains constant, the correlation is said to be a positive correlation. A positive correlation means that as one variable increases, the other variable also tends to increase.

For example, let's consider a study examining the relationship between the attractiveness of a person and their weight. If the study finds that as attractiveness increases, weight also tends to increase while keeping other factors constant, then we can say there is a positive correlation between attractiveness and weight.

In this case, the variable attractiveness is increasing while the variable weight remains constant. This means that as attractiveness increases, weight also tends to increase, indicating a positive correlation.

It's important to note that correlation does not imply causation. Just because two variables are correlated does not necessarily mean that one variable causes the other to change. Correlation simply measures the strength and direction of the relationship between two variables.

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If the probability of an event occurring is 0.64. what is the probability of

the complement of that event?

O 16/25

O 9/25

0.46

O

1

Answers

Answer:

9/25

Step-by-step explanation:

1-0.64=0.36

0.36≡9/25

Plz help I rlly need it!

Plz help I rlly need it!

Answers

It’s greater than 25% because both have the numbers 3 and 5.

The foci and the vertices of the hyperbola are labeled.

Which equation represents the hyperbola shown in the graph?


Answer is B

The foci and the vertices of the hyperbola are labeled.Which equation represents the hyperbola shown

Answers

The answer is B and pls mark me brainiest

The equation of the hyperbola is:

(x - 3)² / 9 - (y - 2)² / 16 = 1.

To find the equation of the hyperbola with the given foci and vertices, we need to determine the center, semi-major axis (a), and semi-minor axis (b) of the hyperbola.

The center of the hyperbola is the midpoint between the two vertices:

Center = ((3 + 3) / 2, (5 + (-1)) / 2) = (3, 2).

The distance between the center and one of the vertices gives us the semi-major axis (a):

a = distance between center and vertex = 5 - 2 = 3.

The distance between the center and one of the foci gives us the distance c (the distance from the center to the focus):

c = distance between center and focus = 7 - 2 = 5.

Now, we can find the value of b (the semi-minor axis) using the relationship between a, b, and c in a hyperbola:

c² = a² + b²

5² = 3² + b²

25 = 9 + b²

b² = 25 - 9

b² = 16

b = 4.

Now that we have the center (h, k) = (3, 2), the semi-major axis (a) = 3, and the semi-minor axis (b) = 4, we can write the equation of the hyperbola in standard form:

For a hyperbola (center at (h, k)), the equation is:

(x - h)² / a² - (y - k)² / b² = 1.

Plugging in the values:

(x - 3)² / 3² - (y - 2)² / 4² = 1.

The equation of the hyperbola is:

(x - 3)² / 9 - (y - 2)² / 16 = 1.

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If Alfie designs the wheels to have a diameter of 67. 5mm and a width of 29. 3mm, what volume of plastic will be required to make the cylinder, to the nearest mm3?

Answers

To make wheels of a diameter of 67.5 mm and a width of 29.3 mm, Alfie requires 104891.38 cubic mm volume of plastic.

A cylinder is a 3-Dimensional shape with 3 faces that are one curved face and 2 flat ends. The volume of a cylinder is given by the expression:

V = π\(r^2h\)

r is the radius

h is the height

Given, diameter = 67.5 mm

radius = d ÷ 2 = 67.5 ÷ 2

= 33.75 mm

height = width = 29.3 mm

Volume = \(\frac{22}{7}*33.75*33.75*29.3\)

= 104891.38 cubic mm

Therefore, the volume of the cylindrical wheel that Alfie designed is 104891.38 cubic mm.

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Solve: log2(3x 8) = 5 which is an equivalent equation? 25 = 3x 8 52 = 3x 8 25 = [log2(3x 8)]2 52 = [log2(3x 8)]5

Answers

The value of the equivalent equation will be 32=3x+8

What will be the value of x?

It is given in the question that

\(\rm Log_2(3x+8)=5\)

Now from the antilog property property

\(\rm x=Log_by\)  can be written as below

\(b^x=y\)

So the value of  \(\rm Log_2(3x+8)=5\)  will be

\(2^5=3x+8\)

\(3x+8=32\)

Thus the value of the equivalent equation will be 32=3x+8

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Answer:

I did it on edgeinuity

Step-by-step explanation:

Solve: log2(3x 8) = 5 which is an equivalent equation? 25 = 3x 8 52 = 3x 8 25 = [log2(3x 8)]2 52 = [log2(3x


A rectangular field is 130 m by 420 m. A rectangular barn 19 m by 25 m is built in the field. How much area is left over?

Answers

The area left over after the barn is built is 54,125 m².

Given that, A rectangular field is 130 m by 420 m. A rectangular barn 19 m by 25 m is built in the field.

The total area of the rectangular field is 130 m x 420 m = 54,600 m².

The area of the rectangular barn is 19 m x 25 m = 475 m².

The area left over after the barn is built is

54,600 m² - 475 m² = 54,125 m²

Therefore, the area left over after the barn is built is 54,125 m².

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Brett's fish tank can hold up to 10.5 gallons of water before it overflows. Brett has poured 9 gallons of water into his fish tank so far.

Let x represent how many more gallons of water Brett can pour into his fish tank. Which inequality describes the problem?

Answers

Answer:

x=1.5

Step-by-step explanation:

Let p(x) = 2x − x3 and q(x) = x4 − 2x2 + 2x. Find a polynomial f(x) ∈ Q[x] such that it leaves remainder x2 +x when divided by p(x) and it leaves remainder x when divided by q(x).

Answers

Answer:

2x-3x=x4-2x2+2x

x=8x

x*x=8

which of the following is not a part of the business cycles that occur in economies over time?

Answers

The business cycle is a recurring pattern of economic expansion and contraction that occurs in economies over time. Each business cycle typically consists of four phases: expansion, peak, contraction, and trough.

The peak is the highest point of economic activity within a business cycle. It marks the end of the expansion phase and the beginning of the contraction phase. During this phase, economic indicators, such as GDP, employment, and consumer spending, reach their highest levels.

The peak is indeed a part of the business cycle. It represents the phase of maximum economic activity and is characterized by various indicators reaching their highest points. This phase is followed by the contraction phase, where economic activity slows down. Therefore, the peak is a crucial element in understanding and analyzing business cycles.

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Find the value of x in 3x + 4y = 8 and 4x - 4y = 6.

Answers

Answer:

x = 2

Step-by-step explanation:

by adding both equations ,

we get 7x = 14

that's why x = 2 .

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jim baked sugar cookies and peanut butter cookies he baked 8 sugar cookies and 3 times as many peanut butter cookies. what is the total number of cookies that jim baked?

Answers

Answer: 32 cookies

Step-by-step explanation:

8 times 3 is 24

24+8=32 cookies

the sum of two numbers is 41 . the sum of 3 times the larger and 8 times the smaller is 203 . find the numbers.

Answers

Answer:

The numbers are 16 and 25

the sum of two numbers is 41 . the sum of 3 times the larger and 8 times the smaller is 203 . find the

Consider the following five-point summary for a variable that was obtained using 200 observations.Minimum Q1 Median Q3 Maximum21 41 53 65 85a-1. Interpret 01.O Eighty percent of the observations are less than 41, 20% of the observations are greater than 41.O Seventy-five percent of the observations are less than 41, 25% of the observations are greater than 41.OTwenty percent of the observations are less than 41, 80% of the observations are greater than 41.O Twenty-five percent of the observations are less than 41, 75% of the observations are greater than 41.

Answers

For a-1 the correct option is d. Q₁ means 25%  observations are less than 41, and 75% are more than 41. For a-2, the correct option is b. Q₃ means 75% of observations are less than 65, and 25% falls above 65. The interquartile range is 24.

Here the five-point summary is given.

Min      Q₁        Median      Q₃         Max

  21       41            53            65         85

Minimum is the minimum value in the data, maximum is the maximum value. Median is the middle value or the 50th percentile. It is also known as second quartile. The first quartile or Q₁ is the 25th percentile. It means that the 25% of data falls below Q₁ and 75% falls above Q₁.

For the third quartile or Q₃ is the 75th percentile. 75% of values will be under this Q₃ and 25% of values falls above this value. Difference between first and third quartile is called interquartile range.

Interquartile range = 65-41 = 24

So for the Q₁ interpret, 25 % values fall under 41 and 75% values fall above 41. Option D is the correct answer. For Q₃ interpret 75% of values fall under 65 and 25% falls above 65. Option B is the correct answer.

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Complete question is provided as the image.

Consider the following five-point summary for a variable that was obtained using 200 observations.Minimum

Given the point (-2, 3) for the basic function y = f(x), find the corresponding point for the complex function y = f(x-4) +2 O (4,2) O (2,4) O (2, 3) None of the Above

Answers

None of the given options (4,2), (2,4), or (2,3) can be considered as the corresponding point for the complex function based on the information provided.

To find the corresponding point for the complex function y = f(x-4) + 2, where the basic function is y = f(x) and the given point is (-2, 3), we need to substitute x-4 into the function and evaluate it.

Let's substitute x-4 into the basic function y = f(x):

y = f(x-4)

  = f((-2)-4)

  = f(-6)

Since we only have the value of the basic function at (-2, 3), we cannot determine the corresponding point for the complex function y = f(x-4) + 2.

Therefore, none of the given options (4,2), (2,4), or (2,3) can be considered as the corresponding point for the complex function based on the information provided.

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x+2= square root -13x-26

Answers

Answer:

x = -15 and x = -2

Step-by-step explanation:

x+2 = \(\sqrt{-13x-26}\)

first step is to square both sides to eliminate the square root symbol

(x+2)² = -13x - 26

now use the 'foil' method on (x+2)² to get:

x² + 4x + 4 = -13x - 26

add 13x to each side to get:

x² + 17x + 4 = -26

add 26 to each side to get:

x² + 17x + 30 = 0

(x+15)(x+2) = 0

x+15 =0;  x = -15

x+2 =0;   x = -2

Write a recursive rule for an= Зn — 6.

Answers

Answer:

Explicit formula: a(n)=3n-6

Recursive formula: a(n)=-3+(n-1)3 <--

Step-by-step explanation:

a(n)=3n-6 where a(1)=3(1)-6=-3 and d=3

Plug values into recursive formula:

a(n)=a1+(n-1)d

a(n)=-3+(n-1)3

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