2. An object with a net charge of 24 µC is placed in a uniform electric field of 610 N/C , directed vertically. What is the mass of the
object if it “floats” in the electric field?

Raju's statement is not correct fully as it states that uniform motion is seen only in objects traveling in a straight line while ,Tejas is correct in pointing out that uniform motion can also be observed in objects traveling in circular motion. 

Uniform motion refers to the movement of an object at a constant speed in a particular direction. In this type of motion, the object covers equal distances in equal intervals of time. Suppose for example (straight line movement), a car moving on a straight road at a constant speed of 60 km/h. If the car maintains this speed without any change in direction, it exhibits uniform motion. Other example is regarding the object moving in circular path where  a race car driving around a circular track with a radius of 100 meters. If the car maintains a constant speed of 40 meters per second and completes each lap in the same amount of time, it exhibits uniform motion. Therefore, Tejas' justification is valid, as he states that uniform motion can indeed be observed in objects traveling in circular paths, in addition to objects moving in straight lines.

Learn more about linear motion here

https://brainly.com/question/118814

#SPJ1

The maximum height be 3.01 m.

According to the law of conservation of energy: The total energy of the system is conserved in a closed system, also known as an isolated system.

Given parameters:

Mass of the box: m = 2.0 kg

Spring constant: k = 2000 N/m.

Compression of spring: x = 20 cm = 0.2m

Angle of inclination: θ = 37°

Coefficient of friction: μ = 0.1

If the box raises up to distance d then according to law of conservation of energy:

1/2kx² = mgdsin37° + μ mg d sin37°

1/2kx² = mgdsin37°(1 + μ)

d = 1/2kx²/(1+μ)mgsin37° = 1/2 × 2000 × 0.2²/{(1+0.1) × 2 × 10 × sin37°}

= 3.01 m.

Hence,  The maximum height be 3.01 m.

Learn more about energy here:

https://brainly.com/question/1932868

#SPJ1

Answer:

57.98 °Fahrenheit =

14.4333 °Celsius

Explanation:

(rounded to 6 digits)

Answer: Both static and kinetic coefficients of friction depend on the pair of surfaces in contact. Their values are determined experimentally. For a given pair of surfaces, the coefficient of static friction is larger than the kinetic friction. The coefficient of friction depends on the materials used.

Explanation:

the coefficient of static friction is larger than the kinetic friction.

Answer:

The coefficient of kinetic friction and the coefficient of static friction are both affected by the area of contact between two surfaces in contact. The following is a detailed explanation of how the values of these coefficients are affected by the area of contact.

The coefficient of kinetic friction is defined as the ratio of the force required to maintain a constant velocity between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion between two surfaces in contact. The coefficient of kinetic friction is affected by several factors, including the nature of the surfaces in contact, their roughness, and their temperature. However, the area of contact between two surfaces also plays a crucial role in determining the coefficient of kinetic friction.

The larger the area of contact between two surfaces, the greater the frictional force acting between them. This is because a larger area of contact means that there are more points of interaction between the two surfaces, which leads to a greater number of intermolecular forces acting between them. As a result, it becomes more difficult to maintain a constant velocity between two surfaces with a larger area of contact, and hence, the coefficient of kinetic friction increases.

On the other hand, the coefficient of static friction is defined as the ratio of the maximum force required to initiate motion between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion when an object is at rest on a surface. Like the coefficient of kinetic friction, it is also affected by several factors including surface roughness and temperature. However, unlike the coefficient of kinetic friction, it is not affected significantly by changes in area of contact.

This is because when an object is at rest on a surface, it does not matter how much area it covers on that surface. The maximum force required to initiate motion remains constant regardless of whether an object has a small or large area in contact with another surface. Therefore, changes in area of contact do not significantly affect the coefficient of static friction.

Answer:

  250 mL

Explanation:

We must assume the volume ratio is the same as the mass ratio. If x represents the volume of solution, we want ...

  0.15 mL/x = 600/10^6

  x = (0.15·10^6)/600 mL = 250 mL

250 mL of the solution will contain 0.15 g of sucrose.

_____

Additional comment

Often the distinction between mL and grams is blurred when describing dilute solutions. That is, mass per volume ratios are given in percent or ppm or ppb as though the units in the ratio cancel.

Answer:

The value is \(R = 0.321 \ \Omega\)

Explanation:

From the question we are told that

   The diameter is  \(d = 8.252 \ mm = 0.008252 \ m\)

    The length of the wire is  \(l = 1.0 \ km = 1000 \ m\)

   Generally the cross sectional area of the copper wire is mathematically represented as

           \(A = \pi * \frac{d^2}{4}\)

=>        \(A = 3.142 * \frac{ 0.008252^2}{4}\)

=>         \(A = 5.349 *10^{ - 5} \ m^2\)

Generally the resistance is mathematically represented as

      \(R = \frac{\rho * l }{A }\)

Here \(\rho\) is the resistivity of copper with the value  \(\rho = 1.72*10^{-8} \ \Omega \cdot m\)

=>    \(R = \frac{1.72 *10^{-8} * 1000 }{5.349 *10^{ - 5} }\)

=>    \(R = 0.321 \ \Omega\)

Answer:

ΔE = GmM/3R

Explanation:

The absolute potential energy of an object in a planet's field is given as:

E = -GmM/2r

where,

E = Potential Energy

G = Universal Gravitational Constant

m = mass of spaceship

M = Mass of Planet

r = distance from surface of planet

Therefore, for initial state:

E = E₁ and r = R

E₁ = - GmM/2R

and for final state:

E = E₂ and r = 3R

E₂ = - GmM/6R

So, the required energy will be:

ΔE = E₂ - E₁ = - GmM/6R + GmM/2R

ΔE = GmM(- 1/6R + 1/2R)

ΔE = GmM/3R

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

Learn more about molecules on:

https://brainly.com/question/32298217

#SPJ1

In the horizontal direction, the forces acting on the person are

• friction with magnitude f, opposing motion, and

• the horizontal component of the pulling force (itself with mag. p ) with mag. p cos(30º), in the direction of motion.

There is no friction in the vertical direction, so we omit any discussion of the vertical forces.

By Newton's second law, we then have

p cos(30º) - f = m a cos(30º)

where m is the person's mass, and a is their acceleration so that a cos(30º) is the magnitude of the horizontal component of acceleration. The person is pulled by a force of p = 401 N, so solve for f :

(401 N) cos(30º) - f = (53 kg) (0.59 m/s²) cos(30º)

f ≈ 320 N

Answer:

Volcanic mountains can be formed by a convergent boundary.

Answer:

Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.

hope helpz~

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

Answer:depends on the masses of the objects and the distance between them

Explanation:

According to Newton's law of universal gravitation,the force of attraction between two objects depends on the masses of the objects and the distance between them

Answer:

In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

SI unit: watt (W)

Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω

In SI base units: kg⋅m2⋅s−3

Answer:

As a student, what are your insights about this lesson? Write an essay on your

toughts about the types of drugs/subtance of abuse, discussing its description and

effects

Answer:

The velocity of the ball can be found by dividing the total distance (130 meters) by the total time (20 seconds). This gives a velocity of 6.5 m/s

As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of R such that

R - 50 N - (3 kg) g = 0   =>   R = 79.4 N

As soon as you remove your hand, the block has acceleration a such that, by Newton's second law,

R - (3 kg) g = (3 kg) a   =>   a = (79.4 N - (3 kg) g) / (3 kg) ≈ 16.7 m/s^2

pointing upward.

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

For more questions on gravitational force

https://brainly.com/question/27943482

#SPJ8

We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.

A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.

Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.

Learn more about geology on https://brainly.com/question/830768

#SPJ1

The complete question is that:

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)

A. The rock display with smaller holes shows copper drilling, which is deep underground.

B. The rock display with larger holes shows petroleum drilling, which is deep underground.

C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.

D. The rock display with larger holes shows copper drilling, which is closer to the surface.

Answer:

a. πi(r₁² + r₂²)

b. πi(r₂²- r₁²)

Explanation:

(a) Find the net dipole moment of this system.

The magnetic dipole moment, μ = iA where i = current and A = For area

For the circular loop with radius r₁, and current i₁ in a clockwise direction, i₁ = + i positive

μ₁ = i₁A₁

= +i(πr₁²)

= πir₁²

For the circular loop with radius r₂, and current i₂ in a clockwise direction, i₂ = +i

μ₂ = i₂A₂

= +i(πr₂²)

= πir₂²

The net dipole moment, μ = μ₁ + μ₂

μ = μ₁ + μ₂

=  πir₁² + πir₂²

= πi(r₁² + r₂²)

(b) Repeat for the reversed current in the inner loop

With the reversed current in the inner loop, the current is negative. So i₂ =-i

μ₁ = i₂A₁ = -i(πr₁²) = -πir₁²

So,

μ = μ₁ + μ₂

=  -πir₁² + πir₂²

= πi(-r₁² + r₂²)

= πi(r₂²- r₁²)

The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

Learn more about the unit of measurement from here

brainly.com/question/12629581

#SPJ1

Answer:

a) y = 127.6 m, b) 11.9s,  c)  v = 103.6  m / s, θ’= 326.7º

Explanation:

This is a missile throwing exercise

let's start by breaking down the initial velocity

         sin 30 = \(\frac{v_{oy} }{v_o}\)

         cos 30 = v₀ₓ / v₀

         v_{oy} = v₀ go sin 30

         v₀ₓ = v₀ cos 30

         v_{oy} = 100 sin 30 = 50 m / s

         v₀ₓ = 100 cos 30 = 86.6 m / s

a) the maximum height is requested.

At this point the vertical velocity is zero (v_y = 0)

         v_y² = \(v_{oy}^2\) - 2 g y

         0 = v_{oy}^2 - 2g y

         y = \(\frac{v_{oy}^2 }{2g}\)

         y = 50² / (2  9.8)

         y = 127.6 m

b) Flight time

this is the time it takes to reach the ground, the reference system for this movement is taken on the ground this is a height of y = 0 m and the body is at an initial height of i = 100m

         y = y₀ + v₀ t - ½ g t²

       0 = 100 + 50 t - ½ 9.8 t²

we solve the quadratic equation

        4.9 t² - 50 t - 100 = 0

         t = \(\frac{50 \pm \sqrt{50^2 + 4 \ 4.9 \ 100} }{2 \ 4.9}\)

         t = \(\frac{50 \ \pm \ 66.8}{9.8}\)

         t₁ = 11.9 s

         t₂ = -8.4 s

flight time is 11.9s

c) The time 1 s before hitting the ground is

        t1 = 11.9 -1

        t1 = 10.9 s

let's find the vertical speed

       v_y =\(v_{oy}\) - g t

       v_y = 50 - 9.8 10.9

       v_y = -56.8 m / s

the negative sign indicates that the direction of the velocity is downward.

On the x-axis there is no acceleration therefore the speed is constant.

Let's use the Pythagorean theorem

        v = \(\sqrt{v_x^2+v_y^2}\)

        v = \(\sqrt { 86.6^2 + 56.8^2}\)

        v = 103.6  m / s

let's use trigonometry

        tan θ = \(\frac{v_y}{v_x}\)

        θ = tan⁻¹  \frac{v_y}{v_x}

        θ = tan⁻¹  (-56.8 / 86.60)

        θ = -33.3º

the negative sign indicates that it is measured clockwise from the x-axis

for a counterclockwise measurement

          θ’= 360 - θ

          θ' = 360 - 33.3

          θ’= 326.7º

Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

Answer:

To solve this problem, we need to use the law of conservation of momentum, which states that the total momentum before a collision is equal to the total momentum after the collision.

The momentum of an object is given by its mass multiplied by its velocity, so we can calculate the initial momentum of each ball before the collision:

- The northbound ball has a momentum of 535g * 12.4 m/s = 6644 g*m/s north

- The southbound ball has a momentum of 725g * (-6.4 m/s) = -4640 g*m/s north (note that the negative sign indicates southward direction)

Adding these momenta together, we get a total momentum of 6644 g*m/s - 4640 g*m/s = 2004 g*m/s north.

After the collision, the two clay balls stick together and move as a single unit. Let's call the mass of the combined unit "M" and its velocity "v". By conservation of momentum, we know that the total momentum of the combined unit after the collision must be the same as the total momentum before:

M * v = 2004 g*m/s north

To solve for v, we need to figure out the mass of the combined unit. This is simply the sum of the masses of the two original balls:

M = 535g + 725g = 1260g

Substituting this into the equation above, we get:

1260g * v = 2004 g*m/s north

Solving for v, we get:

v = 1.59 m/s north

Therefore, the combined unit moves 1.59 m/s north after the collision.

However, the answer choices given in the problem are in meters per second, not meters per second north/south. To convert the answer, we need to add a direction. Recall that the northbound ball had a positive velocity and the southbound ball had a negative velocity. Since the combined unit is moving northward, we know its velocity must be positive.

Therefore, the final answer is 1.59 m/s north, which corresponds to answer choice C.

Answer:

Explanation:

The mass of the rock can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{500}{75} = \frac{20}{3} \\ = 6.66666...\)

We have the final answer as

Hope this helps you

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

\(p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2}\) (1)

Where:

\(p_{S,1}\), \(p_{S,2}\) - Initial and final momemtums of the small object, measured in kilogram-meters per second.

\(p_{B,1}\), \(p_{B,2}\) - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that \(p_{S,1} = 7\,\frac{kg\cdot m}{s}\), \(p_{B,1} = 0\,\frac{kg\cdot m}{s}\) and \(p_{S, 2} = 4\,\frac{kg\cdot m}{s}\), then the final momentum of the big object is:

\(7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}\)

\(p_{B,2} = 3\,\frac{kg\cdot m}{s}\)

The magnitude of the large object's momentum change is:

\(p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}\)

\(p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}\)

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Answer:

what is most widely accepted today is the giant-impact theory. It proposes that the Moon formed during a collision between the Earth and another small planet, about the size of Mars. The debris from this impact collected in an orbit around Earth to form the Moon.

Explanation:

i hope this is right

Answer:

D

Explanation:

The size of the frictional force on the box is 2N

The size of the normal force on the box is 98.1 N

The ratio of the frictional force to the normal force is 0.02

The size of the frictional force on the box is calculated as follows:

Total force acting on the box = Net force + Normal force

Hence;

Normal force = Total force - Net force

Net force on the box = mass * acceleration

From the formula, v² = u² + 2as

where a = acceleration

v = final velocity

u = initial velocity

s = distance

a = v² - u² / 2s

v = 0 m/s

u = 2 m/s

s = 10 m

a = 0 - 2² / 2 * 10

a = - 0.2 m/s²

Net force = 10 * -0.2 m/s²

Net force = 2 N

The frictional force = Stopping Force = Net force

Hence, frictional force = 2 N.

Normal force = mass * g

Normal force = 10 * 9.81

Normal force = 98.1 N

Learn more about frictional force at: https://brainly.com/question/4618599

#SPJ1