2. An archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force is...
a. Air resistance against the bow
b. Arrow's push against the bowstring
c. Grip of the archer's hand on the bow

The Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

option D.

The Falcon 9 rocket, is developed by SpaceX, and it holds  a significant importance in today's space exploration world due to several key features and achievements, and some of the importance include the following;

From the given options, we can conclude that the Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

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To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

A is the oscillation's amplitude, or the maximum displacement of the object from equilibrium, in either the positive or negative x-direction. Simple harmonic motion is cyclical.

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The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Given:

The mass of the base runner is: m = 63 kg

The initial speed of the base runner is: u = 4.3 m/s

The coefficient of friction is: μ = 0.70

To find:

a) The amount of mechanical energy lost due to friction

b) How far the base runner slides?

Explanation:

We use the work-energy theorem to determine the loss in the mechanical energy of the base runner. Thus, we get:

Here, v is the final velocity of the base runner which is zero. Thus, v = 0 m/s.

Substituting the values in the above equation, we get:

The negative sign indicates energy lost in due to friction. Thus, the mechanical energy lost due to friction is 582.44 Joules.

The negative sign also indicates frictional force is acting in the opposite direction of the displacement of the base runner.

As the frictional force is opposite to the displacement of the base runner, the angle between the displacement direction and the frictional force is 180°. Thus, the work done by the frictional force is calculated as:

Here, s is the displacement of the base runner.

Rearranging the above equation, we get:

The frictional force F can be expressed as:

Thus, the equation of displacement "s" can be written as"

Substituting the values in the above equation, we get:

Final answer:

a) The loss in mechanical energy due to friction is 582.44 Joules.

b) The base runner covers a distance of 1.35 m by sliding.

Answer:

all are harmful to the body

Answer:

it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle

Answer:

acceleration an velocity are two different types of hate for each individual to choose from my favorite ones and not just one for me like you said you would have to pay for the person you want and you will need to pay for your business.

Explanation:

no exceptions

Answer:

Right

Explanation:

Coil move right yes

Rock: Weight in air (N): 1.2, Apparent weight (N): 1.0, Buoyant Force (N): 0.2, Mass of beaker and water (kg): 0.069, Mass of beaker (kg): 0.048, Mass of displaced water (kg): 0.021 and Weight of displaced water (N): 0.21.

Buoyant force is the upward force exerted on an object when it is submerged in a fluid. This force is caused by the pressure differences between the top and bottom of the object, due to the fact that the pressure at the bottom of the object is greater than the pressure at the top. This pressure difference is caused by the fluid’s weight, which is pushing down on the object from above.

Styrofoam:

Weight in air (N): 0.85

Apparent weight (N): 0.13

Buoyant Force (N): 0.72

Mass of beaker and water (kg): 0.123

Mass of beaker (kg): 0.048

Mass of displaced water (kg): 0.075

Weight of displaced water (N): 0.75

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

Higher denisty

Explanation:

High pressure=high denisty

The charges are of the same type. As a result, any force exerted between them will be repulsive.

What exactly is force?

Force is an influence that causes an object to accelerate, decelerate, or change its direction of motion. It is a vector quantity, meaning it has both magnitude (strength) and direction. Examples of forces include gravity, friction, electromagnetic fields, and the applied force of pushing or pulling on an object.

The charges of the same nature repel each other because of the electrostatic force of repulsion. This is because like charges have the same sign and the electrostatic force of repulsion between them is stronger than the attraction between opposite charges. This repulsive force increases as the distance between the charges decreases. This is why two objects with the same charge will be pushed away from each other.

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Answer: 317.52

Explanation:

I'm just him, so I just know

Answer:

the greater the height of an object the *greater* its gravitational potential energy

greater

Answer:the answer is “A book sitting on a high shelf” :)

Explanation:

Explanation:

kE =1/2mv²

1/2(0.6×(3m/s)²

1/2(0.6×9m/s)

2.7J I think this is the answer

The average kinetic energy of the toy car is 2.7 J.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

Given data;

Mass of car is,m= 600 g = 0.6 kg

d is the distance travelled = 6 m

T is the time travelled = 2 sec

The velocity of the car is found as;

v  = d /t

V = 6m / 2 sec

V = 3 m/sec

KE =1/2mv²

KE = 1/2 × 0.6 kg ×( 3 m/sec )²

KE = 2.7 J

Hence, the average kinetic energy of the toy car is 2.7 J.

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Here

According to first equation of kinematics.

\(\\ \sf\longmapsto v=u+at\)

\(\\ \sf\longmapsto v=0+at\)

\(\\ \sf\longmapsto v=at\)

\(\\ \sf\longmapsto v\propto t\)

Answer:

Organizing and making sense of behavioral observations is central to psychology’s goal of explanation.

You push on a box with net force of 5 N and it accelerates. If you exert  same net force on an object that has half the mass, then :The object will accelerate twice as much.

Newton's second law of motion states that : acceleration of object is directly proportional to net force acting on it and inversely proportional to  mass. Therefore, if net force acting on object is constant, and mass is reduced by factor of 2, then its acceleration will be twice as much.

In this case, if you exert net force of 5 N on object with mass M, and it accelerates with acceleration A, then :

F = M*A; F is the net force applied.

If you exert same net force of 5 N on an object that has half the mass of the previous object, i.e., its mass is M/2, then its acceleration would be:

A' = F/(M/2) = 2F/M = 2A;  A' is the new acceleration of the object.

Object will accelerate twice as much if you exert the same net force on an object that has half the mass.

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The internal energy after heating in terms of U is 100U.

The given parameters;

Assuming a constant pressure, the internal energy of the ideal gas is equal to the change in the enthalpy of the ideal gas.

\(\Delta H = U \times \Delta T\\\\\Delta H = U (200 - 100)\\\\\Delta H = 100 U\)

Thus, we can conclude that the internal energy after heating in terms of U is 100U.

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Answer:

60 m

Explanation:

also if u ever get stuck just look up displacment caculator it can help . Please give me brainlist

Answer:

i don'tkniw

Explanation: ido not know

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

the 5 is because u have to select the currents and volts which gives us 2 and 1 plus 3 is 6 but if we rest 1 is 5, thats the answer

Answer:

\( |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} \)

The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8)  the distance between ant and spider is 5.83 m.

The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( \(x_{1}\) , \(y_{1}\) , \(z_{1}\) ) and B( \(x_{2}\) , \(y_{2}\) ,\(z_{2}\)),

AB² = (\(x_{2}\) - \(x_{1}\))² + (\(y_{2}\) - \(y_{1}\))² + ( \(z_{2}\)  - \(z_{1}\) )²

In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points  A( \(x_{1}\) , \(y_{1}\) )  and B( \(x_{2}\) , \(y_{2}\) ).

Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is

AB² = (\(x_{2}\) - \(x_{1}\))² + (\(y_{2}\) - \(y_{1}\))² + ( \(z_{2}\)  - \(z_{1}\) )²

AB² = 4² + 3² + 3²

AB² = 34

AB  = 5.83 m

Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.

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Given

The mirror is concave.

The object is placed between the focal point and a concave mirror. From the sign convention, the object distance is taken as negative.

As the focal point is on the left side of the concave mirror, the focal length is also taken as negative from the sign convention.

Thus, the focal length must be negative so that the mirror formula can work.

Answer:

The intensity is  \( I  = 0.0175I_o \)

Explanation:

From the question we are told that

   The wavelength is  \(\lambda = 633 \ nm = 633*10^{-9} \ m\)

   The width of the slit is \(d = 0.24 \ mm = 0.00024 \ m\)

   The distance from the screen is  \(D = 6.0 \ m\)

   The distance of the position considered from the center is \(y = 3.0 \ mm = 0.003 \ m\)

  Generally the intensity from at a point on the screen 3.0 mm from the center of the pattern is

       \(I = I_o * \frac{sin^2 [\frac{\pi d * y}{ \lambda D } ]}{[\frac{\pi d * y }{\lambda D} ]^2}\)

 Here  \(I_o\) is the intensity of the central bright fringe

=>    \( I  = I_o *  \frac{sin^2 [\frac{3.142  * 0.00024 * 0.003}{ 633*10^{-9} * 6 } ]}{[\frac{3.142*0.00024  * 0.003 }{633*10^{-9} * 6} ]^2}\)

=>    \( I  = 0.0175I_o \)        

Answer:

a)  w = 2.52 10⁷ rad / s, b)  K / K₀ = 1.19 10⁴

Explanation:

a) We can solve this exercise using the conservation of angular momentum.

Initial instant. Before collapse

         L₀ = I₀ w₀

Final moment. After the collapse

         L_f = I w

angular momentum is conserved

        L₀ = L_f

         I₀ w₀ = I w                 (1)

The moment of inertia of a sphere is

        I = 2/5 m r²

we take from the table the mass and diameter of the star

        m = 1,991 10³⁰ kg

        r₀ = 6.96 10⁸ m

        r = 6.37 10⁶ m

to find the angular velocity let's use

       w = L / T

where the length of a circle is

      L = 2π r

      T = 24 days (24 h / 1 day) (3600 s / 1h) = 2.0710⁶ s

we substitute

      w = 2π r / T

      wo = 2π 6.96 10⁸ / 2.07 10⁶

      wo = 2.1126 10³ rad / s

we substitute in equation 1

      w = \(\frac{I_o}{I}\)

      w = 2/5 mr₀² / 2/5 m r² w₀

      w = (\(\frac{r_o}{r}\)) ² wo

      w = (6.96 10⁸ / 6.37 10⁶) ² 2.1126 10³

      w = 2.52 10⁷ rad / s

b) the kinetic energy ratio

      K = ½ m w²

       K₀ = ½ m w₀²

       K = ½ m w²

       K / K₀ = (w / wo) ²

       K / K₀ = 2.52 10⁷ / 2.1126 10³

       K / K₀ = 1.19 10⁴