1pt During a phase change, as energy is added, the temperature of a substance
O A. increases
O B. is constant
O C. decreases
O D. first increases and then decreases to its original value

reduction

deflation

these are examples of the opposite of enlarged to make something smaller is really the key thing here

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:

The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.

A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is

             E = h νν

Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.

If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.

In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.

In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:

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The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

The following data were obtained from the question:

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

B = 15μT

Explanation:

In order to calculate the magnitude of the magnetic field generated by the coaxial cable you use the Ampere's law, which is given by:

\(B=\frac{\mu_oI}{2\pi r}\)       (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

I: current

r: distance from the wire to the point in which B is calculated

In this case you have two currents with opposite directions, which also generates magnetic opposite magnetic fields. Then, you have (but only for r > radius of the cylindrical conductor) the following equation:

\(B_T=B_1-B_2=\frac{\mu_o I_1}{2\pi r}-\frac{\mu_o I_2}{2\pi r}\\\\B_T=\frac{\mu_o}{2\pi r}(I_1-I_2)\)  (2)

I1: current of the central wire = 2.00A

I2: current of the cylindrical conductor = 3.50A

r: distance = 2.00 cm = 0.02 m

You replace the values of all parameters in the equation (2), and you use the absolute value because you need the magnitude of B, not its direction.

\(|B|=|\frac{4\pi*10^{-7}T/A}{2\pi (0.02m)}(2.00A-3.50A)|=1.5*10^{-5}T\\\\|B|=15*10^{-6}T=15\mu T\)

The agnitude of the magnetic field outside the coaxial cable, at a distance of 2.00cm to the center of the cable is 15μT

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Answer:

Explanation:

According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.

This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.

For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.

hat he sais

Answer:w

Explanation:

The horizontal range of the ball is 6.13 m

The initial velocity of the ball, u = 8 m/s

Angle made by the ball with the horizontal, θ = 35°

Acceleration due to gravity, g = 9.81 m/s²

The horizontal range is calculated as shown below

Substitute u = 8 m/s, θ = 35°, and g = 9.81 m/s² into the range formula above

Therefore, the horizontal range of the ball is 6.13 m

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter \((I_{r})_{d}=1\ kg\ m^{2}\)

The radius of metallic ring and uniform disc both are equal.

So, \(R_{r}=R_{d}\)

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

\((I_{r})_{c}=2\times (I_{r})_{d}\)

Put the value into the formula

\((I_{r})_{c}=2\times1\)

\((I_{r})_{c}=2\ kg\ m^2\)

Put the value of moment of inertia

\(MR_{r}^2=2\)

\(R_{r}^2=\dfrac{2}{M}\)

Put the value of M

\(R_{r}^2=\dfrac{2}{1}\)

So, \(R_{r}^2=R_{d}^2=2\ m\)

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

\(I_{d}=\dfrac{1}{2}MR_{d}^2\)

Put the value into the formula

\(I_{d}=\dfrac{1}{2}\times1\times2\)

\(I_{d}=1\ kg\ m^2\)

Hence, The moment of inertia of disc about own axis is 1 kg-m².

The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The net force on the particle = mass of the particle × acceleration

                                                =3.80*(−3.40i + 1.70j)

                                                = -12.92i + 6.49j

Thus, the magnitude of the net force on the particle would be 14.46 Newtons.

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It would take approximately 1.33 x 10^8 seconds (or about 42 years) for a light signal from Earth to reach Proxima Centauri. For a spacecraft traveling at 0.0001c, it would also take about 42 years to reach Proxima Centauri.

To calculate the time it takes for a light signal to travel from Earth to Proxima Centauri, we can use the formula:

Time = Distance / Speed

Given:Distance to Proxima Centauri = 4.0 x 10^13 km (convert to meters by multiplying by 10^3, as 1 km = 10^3 m)

Speed of light (c) = 3 x 10^8 m/s

Converting the distance to meters:

Distance = 4.0 x 10^13 km * 10^3 = 4.0 x 10^16 m

Using the formula, we can calculate the time it takes for the light signal to travel:

Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^8 m/s)

Time ≈ 1.33 x 10^8 seconds

To calculate the number of years it would take for a spacecraft traveling at a speed of 0.0001c to reach Proxima Centauri, we need to divide the distance by the speed of the spacecraft.

Speed of spacecraft (v) = 0.0001c = 0.0001 * 3 x 10^8 m/s = 3 x 10^4 m/s

Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^4 m/s)Time ≈ 1.33 x 10^12 seconds

To convert seconds to years, divide the time by the number of seconds in a year:

Number of years ≈ (1.33 x 10^12 seconds) / (3.1536 x 10^7 seconds/year)

Number of years ≈ 42 years

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The impact speed of the mouse is 23.3 m/s as per the data given in the question.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

To solve for the impact speed, we can use the following equation:

\(v^2 = u^2 + 2as\)

Where:

v = impact speed,

u = initial speed (which is the horizontal speed of the owl),

a = acceleration due to gravity (9.8 m/\(s^2\)), and

s = vertical distance fallen (15.0 m).

Substituting the known values, we get:

\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)

\(v^2\) = 256 + 294

\(v^2\) = 550

v = sqrt(550 )

v = 23.3 m/s

Thus, the impact speed of the mouse is 23.3 m/s.

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Answer:

17.15 N

Explanation:

Remember   F = m a

                       = 7 kg * 2.45 m/s^2 = 17.15 N

Answer:

As the penny falls 320 meters, its vertical velocity increases at the rate of 9.8 m/s

Explanation:

Distance:

It is the measure of length that is the actual path traveled by a particle.

Distance depends upon the path traveled by the particle from the initial to the final point.

The distance measured for a particle is always positive.

Displacement:

It is the measure of the shortest distance between initial and final points.

Displacement is not dependent on the path but depends only on the shortest distance between initial and final points.

The displacement of a particle can either be positive, negative, or zero.

Conociendo la longitud y frecuencia de un péndulo, queremos encontrar la longitud de otro pendulo de tal forma que tenga otra frecuencia.

Veremos que la longitud del nuevo péndulo debe ser 6.25m

Sabemos que un péndulo de 4m de longitud tiene una frecuencia de 5Hz.

La frecuencia de un péndulo está dada por:

\(f = \frac{1}{2*\pi} *\frac{g}{l}\)

Donde g es la aceleración gravitatoria y l es la longitud del péndulo, remplazando los datos que tenemos en esa ecuación obtenemos:

\(5 Hz = \frac{1}{2*3.14} *\sqrt{\frac{g}{4m} } \\\\(5Hz*2*3.14)^2*4m = g = 3,943.8 m/s^2\)

Ahora debemos encontra la longitud de tal forma que la frecuencia sea 4Hz, entonces debemos resolver:

\(4Hz = \frac{1}{2*3.14} *\sqrt{ \frac{3943.8m/s^2}{l} }\\\\4hz*2*3.14 = \sqrt{ \frac{3943.8m/s^2}{l} }\\\\l =\frac{3943.8m/s^2}{ (4hz*2*3.14)^2} = 6.25m\)

La longitud del nuevo péndulo deve ser 6.25m

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Answer:

microwave

Explanation:

The insights to be used in creating a primary message is that; Electric vehicle demand is skyrocketing. Option C

We can see that the demand for electric vehicles has increased in the recent times. Why has the demand for electric vehicles increased? We know that in the recent times there has been a push for the use of cleaner energy.

This has made a strong impressions upon governments around the would and has led to an increase in the rate at which any kind of research that tries to fund the use of devices that use alternative energy to fossil fuels is concerned.

As a result of this, there has been an increase in the demand and the use of the electric vehicles especially in the developed countries where more people can be able to afford the vehicles.

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Answer:408849499400504053-2

Explanation:kfnkdtozskf

Given that,

Rank in order from largest to smallest the magnitude of the electric field at block dot.

Electric field :

Electric field is proportional to the charge divided by square of distance.

In mathematically,

\(E\propto\dfrac{q}{r^2}\)

Where, q = charge

r = distance

If the charge is greater then electric field will be greater.

If the distance is greater then electric field will be smaller.

We need to find the electric field at black dot

According to figure,

(I). The electric field at black dot due to positive charge point q to left. the distance is r.

The electric field will be

\(E=\dfrac{kq}{r^2}\)

The electric field will be largest.

(II). The electric field at black dot due to positive charge point 2q to left. The distance is 2r.

Then, the electric field will be

\(E=\dfrac{k2q}{(2r)^2}\)

\(E=\dfrac{kq}{2r^2}\)

The electric field will be smallest.

(III).  The electric field at black dot due to positive charge point 2q to left. The distance is r.

Then, the electric field will be

\(E=\dfrac{k2q}{(r)^2}\)

The electric field will be very largest.

(IV). The electric field at black dot due to positive charge point q to left. The distance is 2r.

Then, the electric field will be

\(E=\dfrac{kq}{(2r)^2}\)

\(E=\dfrac{kq}{4r^2}\)

The electric field will be very smallest.

So, The electric field from largest to smallest will be

\(E_{3}>E_{1}>E_{2}>E_{4}\)

Hence, The ranking will be 3, 1, 2, 4.

(D) is correct option.

Answer:x=20

Explanation:

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Throughout the entire journey, the runner averaged a speed of 4 m/s for the total distance of 600 m .

Distance divided by speed equals 300/3,

                                  =  100 seconds, for the first run.

The second run took  = 300/6,

                                 =  50 m/s.

The average speed is equal to the total amount of time and distance traveled.

The average speed is   = 600 / 150,

                                    =  4 meters per second.

The total distance traveled by the object over a given time period is the average speed. A scalar number is the average speed. It does not have a direction and is only represented by the magnitude. The average speed of something is determined by dividing the total distance traveled by the amount of time it took to travel that distance. Speed is the speed at which something is moving at any given time. The average rate of speed over the course of a trip is known as the average speed.

The distance/time ratio, which is a scalar, is the average speed. Speed doesn't know where it is going. Velocity, on the other hand, is a vector quantity; It knows where to go. The rate at which the position changes is called velocity.

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Answer:

A) Pitch

Explanation:

Wavelength determines the pitch  ( or frequency which is 1/wavelength)

Answer:

Component

Explanation:

All circuits have some basic parts, called components. One component is the power source, also called a voltage source. The power source is what pushes the electricity through the circuit.

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

Bicycle riders could accelerate/ increase their speed in various ways

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