10) Find the perimeter of the polygon:*
9x - 6
2x - 5
-7x+3
2x - 5
-7x +3
9x - 6

Answer:

  False

Step-by-step explanation:

You want to know if it is true that the graph of a rational function cannot cross a horizontal asymptote.

Once a function is on its final approach to an asymptote, it will approach, but not cross, that asymptote.

The function may have a variety of behaviors prior to that point, so may cross the horizontal asymptote one or more times before its final behavior is established.

An example with the asymptote y = 0 is attached.

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The answer is d) 0.5123.

Given the mean and standard deviation, we can model the amount of time in minutes required by college students to complete a test as a normal distribution with the following parameters: Mean (μ) = 34.6Standard deviation (σ) = 7.2.

We need to find the probability that a randomly chosen student will require between 30 and 40 minutes to complete the test.

In mathematical notation, we can write this as: P(30 < X < 40). We can solve this problem by standardizing the normal distribution and using the standard normal distribution table.

The standardized random variable Z is given by the formula: Z = (X - μ) / σ where X is the amount of time required by the student, μ is the mean and σ is the standard deviation.

Substituting the given values, we have: Z = (X - 34.6) / 7.2. To find P(30 < X < 40), we need to find P(Z1 < Z < Z2) where Z1 and Z2 are the standardized values of 30 and 40 respectively.

We can compute these standardized values as follows:Z1 = (30 - 34.6) / 7.2 = -0.639Z2 = (40 - 34.6) / 7.2 = 0.75.

Now we can use the standard normal distribution table to find the probability that a randomly chosen student will require between 30 and 40 minutes to complete the test.

We have: P(30 < X < 40) = P(Z1 < Z < Z2) = P(0.75) - P(-0.639) = 0.7734 - 0.2611 = 0.5123.

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Answer:First we need to simplify the left side of the equation:

12,5(3x-1)+132,4 = 12,5*3x - 12,5 + 132,4 = 37,5x + 120,9

Now we need to simplify the right side of the equation:

2,8-4x = 2,8 - 4x

Now we have to set the two sides equal:

37,5x + 120,9 = 2,8 - 4x

Now we have to move all the x terms to one side of the equation:

37,5x - 4x + 120,9 = 2,8

Next step is to combine like terms:

33,5x + 120,9 = 2,8

Subtracting 120.9 from both sides of the equation:

33,5x = -118.1

Dividing both sides by 33,5

x = -3,54

So the solution of the equation is x = -3,54

Step-by-step explanation:

\(2) \: 2(9 + 3) = 2(12) = 24\)

Answer: 24

Ok done. Thank to me :>

hope this was fast enough!!

Firslty, we need to find the function, whcih we can do by substituting one into the other:

Now, for the domain we have more complicated approach.

We first have to find the domain for both f(x) and g(x).

The domain of f(x) is all real number, because it is a quadratic polynomial.

The domain of g(x) is all the real numbers except the x values that makes the square root interior negative, so all real numbers so that:

Now, the domain of the composite function f(g(x)) is the set of all the values of x in the domain of g(x) such that the corresponding g(x) is in the domain of f(x).

Since the domain of f(x) is all real numbers and g(x) is a real number function, all the values of g(x) will be in the domain of f(x), so we just need to check the values of x that are in the domain of g(x).

The domain of g(x), as we saw, is:

And any value of x will give a g(x) that will be in the domain of f(x) so, the domain of f(g(x)) is:

So, the correct alternative is:

Rashid spent a total of 1 hour and 30 minutes on homework for these three subjects.

If Rashid spent 30 minutes on each piece of homework for three subjects, we can calculate the total time he spent by multiplying the time spent per subject (30 minutes) by the number of subjects (3).

30 minutes * 3 = 90 minutes.

To convert this into hours and minutes, we divide 90 minutes by 60 since there are 60 minutes in an hour.

90 minutes ÷ 60 = 1 hour and 30 minutes.

Therefore, Rashid spent a total of 1 hour and 30 minutes on homework for these three subjects.

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When the above is simplified using Boolean Algebra, we have F = x' + y' + w'xy.

We can simplify  the Boolean function F = xy'z' + xy'z+ w'xy +   w'x'y' + w'xy using the following Boolean Algebra rules.

Absorption - x + xy = x

Commutativity -  xy = yx

Associativity - x(yz) = (xy)z

Distributivity - x(y + z) = xy + xz

Using the above , we   have

F = xy'z' + xy'z+ w'xy + w'x'y' +   w'xy

= xy'(z + z') + w'xy(x + x')

= xy' +  w'xy

= (x' + y)(x' + y')  + w'xy

= x' + y' + w'xy

This means that the simplified expression is F = x' + y' + w'xy.

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30 units

Since from point 0 to V, there are 25 units of distance

and from 0 to T, there are 5 units of distance

From T to V, 25 + 5 = 30 units

NB: Since we are only considering the length the - is not taken into account

Answer:The answer will be 35ft

Step-by-step explanation:

One way that you can answer this is by using sin law. You will put the length of a side on top and the corresponding angle that faces towards that side at the bottom of a fraction. So for this one it will be 30/sin(70) = x/sin(90) The 90 comes from the bottom of the building with the ground. And the side the angle faces is the ladder. After that you put 30sin(90)/sin(70) to find x. And you get 34.655 which rounds to 35 ft.

The shape of the distribution of water bills can be described as skewed right.

Here's a step-by-step explanation:
1. Analyze the histogram: 100-125 (1), 125-150 (2), 150-175 (5), 175-200 (10), 200-225 (13), 225-250 (8).
2. Observe that the frequency increases as the monthly water bill increases, reaching a peak at the 200-225 range.
3. Notice that after the peak, the frequency decreases as the monthly water bill increases further (from 225-250).
4. Based on this pattern, we can conclude that the distribution is not uniform (equal frequency across all ranges) or roughly symmetric (equal frequency on both sides of a central point).
5. Since the frequency increases as we move to the right and then decreases, the shape of the distribution is skewed right.

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Therefore, the vector form of the equation y = x² - 8x + 15 is y = (x - 4)² + 14. The vertex of the parabola is at the point (4, 14).

To convert the quadratic equation y = x² - 8x + 15 from standard form to vertex form, we need to complete the square by adding and subtracting a constant term. Here's the step-by-step explanation:

Factor the coefficient of x²: The coefficient of x² is 1, so we don't need to factor it.

Group the x terms: Rewrite the quadratic equation as y = (x² - 8x) + 15.

Complete the square: To complete the square, we need to add and subtract a constant term that will make the expression inside the parentheses a perfect square trinomial. The constant we need to add is half of the coefficient of x, squared: (8/2)² = 16.

y = (x² - 8x + 16 - 16) + 15 // add and subtract 16

y = (x - 4)² - 1 + 15 // factor and simplify

Simplify: Now we can simplify the expression by combining the constants -1 and 15 to get 14.

y = (x - 4)² + 14

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Answer:

7.21 cm.

Step-by-step explanation:

4² + 6² = x²

16 + 36 = x²

52 = x²

\(\sqrt{52} = x\)

7.21 cm.

Check

The third side of a triangle is greater than the difference and less than the sum of the lengths of the two given sides.         6 - 4 = 2  and 6 + 4 = 10

So the third side is between 2 and 10.                                                                                            

The lock can be solved by examining the asset allocation of each mutual fund and identifying its type according to the given key.

The correct series of numbers can then be obtained by concatenating the numbers corresponding to the mutual funds in the order in which they appear.

To solve the lock, we need to examine the asset allocation of each mutual fund and identify its type according to the given key. The key may include categories such as large-cap stocks, small-cap stocks, international stocks, bonds, and cash. Based on the asset allocation of each mutual fund, we can determine its type and assign a number from the key to it.

For example, if a mutual fund has an asset allocation of 60% large-cap stocks, 20% small-cap stocks, 10% international stocks, 5% bonds, and 5% cash, we can identify it as a large-cap stock fund and assign it the number 1 from the key. Similarly, if a mutual fund has an asset allocation of 30% small-cap stocks, 50% international stocks, 10% bonds, and 10% cash, we can identify it as an international stock fund and assign it the number 3 from the key.

Once we have identified the type of each mutual fund and assigned a number from the key to it, we can concatenate the numbers corresponding to the mutual funds in the order in which they appear to obtain the correct series of numbers for the lock.

For example, if the mutual funds in the order in which they appear are a large-cap stock fund, a bond fund, an international stock fund, and a cash fund, and their corresponding numbers from the key are 1, 4, 3, and 5 respectively, then the correct series of numbers for the lock would be 1435.

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0.3317  is the p-value .

What is the P value?

H0 : Mu  =  10.2

H1 : Mu > 10.2

Test statistic

t=0.45          (since n is small)

P value = 0.3317

Hence P is greater than 0.10

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Answer:

hope this help you

have a great day

Answer:

i) The order of matrix is 2 ×3

ii)The order of matrix is 3×3

Answer:

-5/4x + 5/2

Step-by-step explanation:

Slope: (-3-2)/5-1) = -5/4

Point: (1,2)

y-2 = -5/4 (x -1)

y - 2 = -5/4x +5/4

y = -5/4x + 5/4 + 2

y = -5/4x + 13/4

The function for the population of Madison t years from now is:\(p(t) = 25000 (1.12)^{t}\)

To write a function that gives the population P(t) in Madison t years from now, considering the town has an initial population of 25,000 and an annual increase factor of 1.12, you can use the formula:

\(p(t) = P_{0}  (1 + r)^{t}\)

Where:
- P(t) is the population at time t
- P_0 is the initial population (25,000)
- r is the annual increase factor (1.12 - 1 = 0.12)
- t is the number of years

So, the function for the population of Madison t years from now is:
\(p(t) = 25000 (1.12)^{t}\)

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A scientific calculator is typically used for pre-calculus.

This type of calculator is designed to handle more advanced mathematical functions, such as trigonometry, logarithms, and exponents, which are commonly used in pre-calculus.

It is important to have a scientific calculator for pre-calculus because it allows you to easily solve more complex equations and perform calculations quickly and accurately.

Additionally, many scientific calculators have graphing capabilities, which can be useful for visualizing equations and understanding how they behave. Overall, a scientific calculator is an essential tool for pre-calculus and can help you succeed in the course.

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Answer:

I would say a graph

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The blue line is the one that that slants from lower right to upper left. It has a negative slope as in - 1/2. The line is solid so that means the values of the line are included in the expression.

The area covered is purple, so y is less than the y values of the line. C is the only value that shows the paragraph above.

But we have to check the other inequality just to make sure you are right.        y >  2/3 x - 4. The line is not included, so C is your answer.

\(7n^{8} + 3n^{6}+3\)
if that helps

the total consumption of oil in the United States from January 1, 1980, to January 1, 1990 is approximately 596,533.7 billion barrels.

To find the total consumption of oil in the United States from January 1, 1980 to January 1, 1990, we need to integrate the given function\(C(t) = 27.08e^t\)with respect to time t, over the interval [0, 10], where t is measured in years.

The integral of the function is:
∫\((27.08e^t) dt\)

To solve this integral, we use the fact that the integral of\(e^t\) is \(e^t\)itself. Thus, we get:
27.08∫\(e^t dt = 27.08e^t\)
Now, we need to evaluate the definite integral over the interval [0, 10]:
\(27.08e^t\)| from 0 to 10 =\(27.08(e^{10} - e^0)\)

As e^0 = 1, the expression simplifies to:
\(27.08(e^{10} - 1)\)
Now, we can calculate the value of the expression:
\(27.08(e^{10} - 1) =27.08(22026.47 - 1) = 27.08 * 22025.47 =596533.7\)
Thus, the total consumption of oil in the United States from January 1, 1980, to January 1, 1990 is approximately 596,533.7 billion barrels.

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The variable that should be plotted on the horizontal x-axis is the "number of years of education".

This is because the number of years of education is the independent variable, which typically goes on the x-axis, while the annual salary is the dependent variable, which goes on the vertical y-axis.

The relationship between the two quantitative variables can then be analyzed using a scatter plot or by calculating the correlation coefficient.

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Area of the circle = π * (35 yd)^2

Let A be the area of the sector subtended by a central angle measuring 80º. Then

A / (π * (35 yd)^2) = 80º / 360º  ==>  A = 2450π/9 yd^2 ≈ 854.78 yd^2

Subtract from A the area of the triangle, whose base has length 45 yd and with height 25 yd:

A - 1/2 * (45 yd) * (25 yd)  ≈ 292.28 yd^2

This is the area of the missing circular segment.

Then the area of the playground is equal to the area of the circle minus this area,

π * (35 yd)^2 - 292.28 yd^2 ≈ 3554 yd^2

Answer:

3.6h - 3.1d + 13

Step-by-step explanation:

Combine like terms. Like terms have same variables.

Like terms : (i) 6h and (-2.4h) (ii) -8.1d and 5d

6h + (-8.1d) - 13  + 5d - 2.4h = 6h - 2.4h + (-8.1d) + 5d - 13

             = (6 - 2.4)h + (-8.1 + 5)d - 13

             = 3.6h - 3.1d + 13

The simplified expression for its perimeter and area are 8x.

The perimeter of a square is the sum of the lengths of all the sides of a square. Thus, by summing the lengths of a square's four sides, we can get its perimeter.

An equal number of sides make up a square. As a result, the side of a square is added four times to determine the square's perimeter.

The formula for finding the Perimeter of square = 4*a

= 4 * 2x

= 8x

Perimeter of square = 8x

Hence, the simplified expression for its perimeter is 8x

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Step-by-step explanation:

does that mean you understand all the other questions but not 5. ?

that is strange, as this seems to be the easiest one of all the 6 questions.

to be sure, let's have a look at all 6.

1.

the distance MJ = 18 - 2 = 16

MX / XJ = 3/1

the ratio talkes about 3+1 = 4 basic units.

as the whole distance is 16, one such basic ratio unit is 16/4 = 4.

that means from M to X we have 3 of these basic ratio units, and from X to J the remaining 1 of the basic ratio units.

so, MX = 3×4 = 12

since M = 2, X = 2 + 12 = 14

2.

similar to 1.

just now

MY / YJ = 2/3

so, the ratio uses 2+3 = 5 basic units.

that means 1 basic unit is 16/5 = 3.2

2 basic units = 2 × 3.2 = 6.4

3 basic units = 3 × 3.2 = 9.6

so, MY = 6.4

since M = 2, Y = 2 + 6.4 = 8.4

3.

the distance A F = 5 - -7 = 5 + 7 = 12

AW / WF = 1/3

so, the ratio uses 1+3 = 4 basic units.

1 basic unit is 12/4 = 3

3 basic units is 3 × 3 = 9

so, AW = 3

since A = -7, W = -7 + 3 = -4

4.

the distance BF = 5 - -5 = 5 + 5 = 10

BX / XF = 3/2

so, the ratio uses 3+2 = 5 basic units.

1 basic unit = 10/5 = 2

2 basic units = 2 × 2 = 4

3 basic units = 3 × 2 = 6

so, BX = 6

since B = -5, X = -5 + 6 = 1

5.

the distance CE = 2 - -4 = 2 + 4 = 6

CY / YE = 1/1

so, the ratio uses 1+1 = 2 basic units.

1 basic unit = 6/2 = 3

so, CY = 3

since C = -4. Y = -4 + 3 = -1

6.

attention : this goes in the other direction than the other questions. all the others were looking from a point on the left to a point on the right.

but this one looks from a point on the right to a point on the left.

but the same principles apply.

the distance FD = |1 - 5| = |-4| = 4

a distance is always positive, so for this direction we need to apply the absolute value (formality we did that also for the other direction in the other questions, but there it was not necessary to use it explicitly) .

FZ / ZD = 5/3

so, the ratio uses 5+3 = 8 basic units.

1 basic unit = 4/8 = 0.5

3 basic units = 3 × 0.5 = 1.5

5 basic units = 5 × 0.5 = 2.5

so, FZ = 2.5

since F = 5, Z = 5 - 2.5 = 2.5

this is where the other direction really hits : since we have to go to the smaller side, we have to subtract the distance from the original coordinate (instead of the usual addition).