1. Which of these is not a natural fibre?
a. leather
b. jute
C.Wool
d. cotton​

The correct measuring tool is a Graduated cylinder. The correct option is B

Tangential speed refers to the linear speed or velocity of an object along its circular path, specifically in the direction tangent to the circle. It represents how fast an object is moving along the circumference of the circle at a given point.

The other options are not suitable for measuring the time it takes for the toy to complete one revolution around the circle for the following reasons:

A) Force probe: A force probe is used to measure forces, not time. It would not provide accurate timing information for the toy's revolution.

C) Meterstick: A meterstick is used to measure lengths and distances. It cannot directly measure time, which is required to determine the time for one revolution.

D) Spring scale: A spring scale is used to measure forces. It would not provide accurate timing information for the toy's revolution.

On the other hand, a graduated cylinder is a cylindrical container with markings indicating volume. While it is primarily used for measuring the volume of liquids, it can also be used as a timing tool in this scenario. By filling the graduated cylinder with a known volume of liquid and placing it under the toy's path, the time it takes for the toy to complete one revolution can be measured by observing the displacement of the liquid level in the graduated cylinder over time.

Therefore, the correct answer is option B.

The question is incomplete , I think the question is,

One end of a string is attached to the ceiling - with the other end attached to toy. The toy can be set into motion such that travels in horizontal circular path , constant tangential speed as shown above: Which of the following measuring tools could be used to determine the time it takes for the toy to complete one revolution around the circle? String

A) Force probe

B) Graduated cylinder

C)Meterstick

D) Spring scale Toy

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Answer: 30.51L

Explanation:

Let's assume the gas is an ideal gas, the equation for ideal gas equation is

PV = nRT

⇒ PV/T = nR

n and R are both constants

Thus for another circumstance of the same gas, it's again P'V'/T' = nR

Thus we can say PV/T = P'V'/T'

Now in the question,  P1V1/T1 = P2V2/T2

⇒ (2.3 × 17)/299 = (1.5 × v2)/350

⇒ v2 = 30.51 L

Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

ΔP = P₂-P₁  ----> ΔP = 2.30*10⁷ - 1.00*10⁵ = 2.29*10⁷

A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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F = Kq₁q₂/(r)²

K is a constant

R is the distance between them

F = 9.0 E9 × 1.0 E-6 × 1.0 E-6/(0.30)²

= 9.0E-3/0.30² = 9.0E-3/0.09 = 0.1 N

The electrostatic force of repulsion between two charges can be determined using Coulomb's law of electrostatic force. The force of repulsion between the point charges of magnitude 1 ×10 ⁻⁶ C separated by 0.30 m is 0.1 N.

According Coulomb's law of electrostatic forces, the force between two charges q1 and q2 separated by a distance of r meters is given by the expression:

F =  K q1 q2/r²

Where, K is Coulomb's Constant equal to  9.0 ×10⁹ Nm²/C²

Given q1 = q2 = 1 ×10 ⁻⁶ C

r = 0.30 m

k = 9.0 ×10⁹ Nm²/C².

Then the electrostatic force of repulsion between the two point charges is calculated as follows:

F = 9.0 ×10⁹ Nm²/C² × 1 ×10 ⁻⁶ C × 1 ×10 ⁻⁶ C/ (0.30 m )²

  = 0.1 N.

Therefore, the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters apart is 0.1 N.

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Answer:

All other SI units are derived by multiplying, dividing or powering the base units in various combinations, For example: mechanical work is force applied multiplied by distance moved and has the unit newton metre written as Nm.

Explanation:

please mark me as the brainliest

Answer:

Explanation:

The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.

 \(\mathbf{I_w}\) = constant.

The overall value of such moment of inertia is now altered when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.

Recall that:

The Kinetic energy is given by:

\(\mathbf{K = \dfrac{1}{2} Iw^2} \\ \\\mathbf{K = \dfrac{1}{2} lw*w}\)

where;

\(\mathbf{I_w}\) is constant and w reduces;

As a result, just after the collision, the system's total kinetic energy decreases.

The total kinetic energy of the system decreases after the collision.

The angular momentum of any rotating body is defined as the product of the moment of inertia of the body and the angular velocity of the body.

Now from the question, we can see that the angular momentum of the body remains constant before and after the impact of the collision when the clay sphere adheres to the disk.

So angular momentum will be

\(Iw\) = constant.

The overall value of such a moment of inertia is now changed when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.

The Kinetic energy is given by:

\(KE=\dfrac{1}{2} Iw^2\)

\(KE= \dfrac{1}{2} Iw\times w\)

Since the angular momentum \(Iw\) is constant and w is reducing then ultimately the energy of the system is decreasing.

Thus the total kinetic energy of the system decreases after the collision.

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The speed with which the egg pass the point from which it was thrown is √(-216) m/s.

The speed with which the egg pass the point from which it was thrown is calculated by using the following kinematic equation.

Since the only acceleration acting on the egg is gravity (g = 9.8 m/s²), we have:

v² = u² + 2gh

where:

Solving for v, the final velocity

v² = 6.00² + 2(-9.8) (13.0)

v²  = 36 + (-252)

v²  = -216

v = √(-216)

The square root of a negative number is not a real number, so this answer is not physically meaningful. This means that the egg will not pass the point from which it was thrown. The egg will instead reach its highest point and then fall back down to the ground.

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Answer:

The work done is 13680.8 J.

Explanation:

The work done can be calculated as follows:

\( W = F*d \)              

Where:            

F: is the force                                                        

d: is the displacement = 40 m                                    

The force acting on the boulder is given by:

\( F = mgsin(\theta) \)

Where:

m: is the mass = 100 kg

g: is the acceleration due to gravity = 10 m/s²

θ: is the angle = 20°      

Then, the work is:

\( W = mgsin(\theta)d = 100 kg*10 m/s^{2}*sin(20)*40 m = 13680.8 J \)

Therefore, the work done is 13680.8 J.  

I hope it helps you!  

Answer:

Explanation:

Quarter 1 - 10,000 units

Quarter 2 - 12,000 units

Quarter 3 - 16,000 units

Quarter 4 - 14,000 units

Quarter 5 - 10,000 units

Quarter 6 - 8,000 units

Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.

Answer:

jack has done more work pulling more weight and Jill has more power.

Explanation:

Answer:

  C)  5.9 amperes

Explanation:

When the resistance changes by a factor of 413/810, the inverse proportionality means the current changes by a factor of 810/413.

  (810/413)(3 A) ≈ 5.884 A ≈ 5.9 A

The current is about 5.9 amperes.

Answer:

0.5A

Explanation:

The current can be calculated using the following equation:

Where P is the power and V is the voltage. Replacing P = 60W and V = 120V, we get:

Therefore, the current is 0.5A

Answer:

Δv/Δt

Explanation:

I beat your game SAW.

Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.

Explanation:

Answer:

Hey there!

W=mg, where m is the mass and g is the acceleration of gravity.

The acceleration of g on the moon is about 1.622 m/s^2, so plugging that in as a value gives us W, the force is equal to approximately 197 Newtons.

Let me know if this helps :)

Answer:

Ca = 0.2892

Explanation:

given data

fresh water temperature =  20°C

depth = 2-m

ambient pressure = 131 kPa

Ca = 0.25

V = 30 m/s

water cold = 5°C

solution

we know at 20°C here Pv = 2.337 kPa

so

Ca (critical) = \(\frac{2(Pa-Pv)}{\rho v^2}\)

0.25 = \(\frac{2(131000-2337)}{998 \times v^2}\)

so

Vcrit = 32.11 m/s

and

when temperature decrese by 5

Pv = 863 pa

ϼ = 1000 kg/m³

so for this we know hee

v = 30 m/s

and

Ca = \(\frac{2(131000-863)}{1000 \times 30^2}\)

Ca = 0.2892

here Ca > 0.25 so that this body will not cavitate for given condition

Answer: its actually 0

Explanation: i read the khan academy hints and the answer is 0

yes the answer is 0 and if its not and have this graph its -2.0

Answer:

The angular acceleration of CD player is \(13.93\ rad/s^2\).

Explanation:

Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.

It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :

\(a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2\)

So, the angular acceleration of CD player is \(13.93\ rad/s^2\).

Answer:his weight plus the centripetal force must equal 1170 N

Explanation:

83.0 [g + (v^2 / r)] = 1170

v^2 / 18.0 = (1170 / 83.0) - 9.81

Answer:

Approximately \((-1.6 \times 10^{5}\; \rm J)\) (assuming that the car was on level ground.)

Explanation:

When an object of mass \(m\) is moving at a speed of \(v\), the kinetic energy of that object would be \((1/2) \, m \cdot v^{2}\).

Initial kinetic energy of the car:

\(\begin{aligned}&\frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2}\times 1120\; \rm kg \times (17\; \rm m \cdot s^{-1})^{2} \\ &\approx 1.6\times 10^{5}\; \rm J \end{aligned}\).

After the car comes to a stop, the kinetic energy of this car would be \(0\; \rm J\) because the car would not be moving.

Change to the kinetic energy of the car: \(\text{Final KE} - \text{Initial KE} = -1.6 \times 10^{5}\; \rm J\).

If the car is traveling on level ground, friction would be the only force that contributed to this energy change. Hence:

\(\text{Work of friction} = \text{Energy change} = -1.6\times 10^{5}\; \rm J\).

The value of the work that friction did is negative. The reason is that at any instant before the car comes to a stop, friction would be exactly opposite to the direction of the movement of the car.

The work of a force on an object is the dot product of that force and the displacement of that object. The dot product of two vectors of opposite directions is negative. Hence, in this question, the work that friction did on the car would be negative because the friction vector would be opposite to the movement of the car.

The time taken for the hare to catch up with the tortoise is 10 seconds.

The time taken for the hare to catch up with the tortoise is calculated by applying the principle of relative velocity as shown below.

Distance travelled by hare + Distance travelled by tortoise = Total distance

V₁t + V₂t = d

where;

Since they are moving in the same direction, the relative velocity becomes

V₁t - V₂t = d

(V₁ - V₂)t = d

(4 - 1)t = 30

3t = 30

t = 30/3

t = 10 seconds

Thus, the time taken for the hare to catch up with the tortoise is 10 seconds.

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The complete question is below:

A tortoise and a hare run to the East. The hare knows that it is faster, so it gives the tortoise a 30-meter head start. The tortoise is moving east at 1 m/s and the hare is moving east at 4 m/s. At what time does the hare catch up with the tortoise?

The atom that has been shown is an atom of carbon(C).

We know that in an atom is the smallest particle of a substance that can be able to take part in a chemical reaction. In this case, we have a an atom that have been shown. As expected, the protons that are in the atom have been shown as the circle that is in the innermost part of the image.

The electrons are found around the shells of the atom. The electrons that are in the shells of the atom must be equal to the number of protons that are in the atom of the element.

Given that the number of electrons must be equal to the number of protons and the number of protons gives us the identity of the element that have been shown in the image, we can conclude that this is an atom of carbon.

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South

Explanation:

The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by

\(\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}\)

and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.

Answer:

Explanation:

The electron with a smaller mass will accelerate faster than the proton as the force is the same.

Charge on electron = Charge on proton = 1.6*10^-19C

Distance between the two electrons = 1.5*10^-10m

The Electric force between two electrons is given by :

k*Q1*Q2/d^2, where k is the Coulombic constant = 9*10^9

= (9*10^9)*1.6*10^-19*1.6*10^-19/(1.5*10^-10)^2

= 1.024*10^-8N

Electron acceleration = Force/mass

= 1.024*10^-8/9.1x10^-31

= 1.125*10^22 m/s^2

Answer:

Explanation:

electron will accelerate faster cuz' its lighter

charge on electron n proton = 1.6*10^-19C

coulombic force bet electron n proton

= k*q^2/d^2 where k is the Coulombic constant = 9*10^9

= (9*10^9)*(1.6*10^-19)^2/(1.5*10^-10)^2

= 1.02*10^(-8)N

force = mass*acceleration

e- mass: 9.1*10^(-31)

acceleration = 1.02*10^(-8)/(9.1*10^(-31))

= 1.12*10^(22) m/s^2

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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