A wind turbine transfers energy from __________ energy stores. What one word completes the sentence?
A wind turbine transfers kinetic energy to mechanical energy from energy stores, which is then used to generate electricity.
What is wind energy?Wind energy is a type of renewable source of energy that can be used for converting it into electrical energy by the use of turbines that transform mechanical energy into electricity, which is then used for different purposes (both industrial and particular home usage).
Therefore, with this data, we can see that wind energy can be used to generate electricity by means of turbines that convert mechanical energy into electricity.
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In the experiment that student needs to know the mass of four different objects: a shoe, piece of paper,book, and a tissue.which of the following units of measurement should the student use
The unit of measurement the student should use is the gram. The correct option is c.
What are the measurements units?
The International System of Units (SI) uses the gram (formerly gram; SI unit symbol g) as the unit of mass that corresponds to one-thousandth of a kilogram.
A student must know the masses of four different objects for an experiment: a shoe, a piece of paper, a book, and a tissue. The learner should utilize grams as their measurement units.
Therefore, the correct option is c. gram is used to measure the mass of objects and things.
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The question is incomplete. The missing options are given below:
milligram
ounce
gram
kilogram
Season and date for this person
Answer:
summer June 21 is the answer
A helpful association method like remembering the Allies during World War II as BAR
(Britain, America, and Russia) is called
O an acronym
O the DAP flashcard method
O a visual image
O a mind map
Answer:
an acronym because it is shorted to remember like mvemjsun it's the planet
2. Two equipotential lines are separated by a distance of 2.17 cm. If the potential values of the lines are 5.9 volts and 8.6 volts, what would the strength of the electric field between the lines be
What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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A projectile is launched horizontally on a table that it 40 cm high. The projectile lands 10 m away. What is the horizontal
velocity of the projectile as it leaves the launcher?
The horizontal velocity of the projectile as it leaves the launcher is 35 m/s.
What is the time of motion of the projectile?
The time of motion of the projectile is calculated by applying the following kinematic equation as shown below.
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity = 0t is the time of motiong is acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h/g)
t = √(2 x 0.4 / 9.8)
t = 0.286 s
The horizontal velocity of the projectile as it leaves the launcher is calculated as follows;
v = x/t
where;
x is the horizontal distancet is the time of motionv = 10 m / 0.286 s
v = 35 m/s
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Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such lines near their homes could pose health dangers.
a) For a line that has current 150 A and a height of 8.0 m above the ground, what magnetic field does the line produce at ground level? Express your answer in teslas.
b) What magnetic field does the line produce at ground level as a percent of the earth's magnetic field, which is 0.50 G .
c) Is this value of magnetic field cause for worry?
Yes. Since this field does not differ a lot from the earth's magnetic field, it would be expected to have almost the same effect as the earth's field.
No. Since this field does not differ a lot from the earth's magnetic field, it would be expected to have almost the same effect as the earth's field.
Yes. Since this field is much greater than the earth's magnetic field, it would be expected to have more effect than the earth's field.
No. Since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
(a) The magnetic field the line produced at ground level is 3.75 x 10⁻⁶ T.
(b) The lines magnetic field as a percent of the earth's magnetic field is 7.5%.
(c) No, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
Magnetic field the line produced at ground levelB = (μ x I) / (2πr)
B = (4π x 10⁻⁷ x 150) / (2π x 8)
B = 3.75 x 10⁻⁶ T
Percent of the earth's magnetic fieldx = 3.75 x 10⁻⁶ /0.5G
x = (3.75 x 10⁻⁶ ) / (0.5 x 10⁻⁴)
x = 0.075
x = 0.075 x 100% = 7.5%
Thus, we can conclude that, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
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Is there a frame of reference one can go into that seems to eliminate gravity as Newton described it?
Answer:
Yes such a frame exists: a free-fall (free-float frame) frame. This frame of reference is subject only to gravity and no forces such as electromagnetic forces or nuclear forces.
8. A unique property of water because of its chemical structure is that it's _____ dense when it's a solid than when it's a liquid.
A. less
B. equally
C. inversely
D. more
A unique property of water because of its chemical structure is that it's A. less dense when it's a solid than when it's a liquid.
What is water?Water is an incredibly unique substance, and its physical properties are largely due to its chemical structure. Water is a polar molecule, meaning it has a positively charged end and a negatively charged end, which creates an attraction between molecules of water that is known as hydrogen bonding.
This hydrogen bonding is responsible for a number of the unique properties of water, one of which is its density. Water is less dense when it is a solid than when it is a liquid. This is counterintuitive to most substances, which are more dense when they are solid than when they are liquid. The explanation for this is that when water freezes, the hydrogen bonds between the molecules force them to move further apart, resulting in a decrease in density.
This is why ice floats on top of liquid water, and it is why bodies of water don’t freeze from the bottom up.
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A 42.6kg lamp is hanging from wires as shown in figure.The ring has negligible mass. Find tensionsT1, T2,T3 if the object is in equilibrium.
Answer:
T1 = 417.48N
T2 = 361.54N
T3 = 208.74N
Explanation:
Using the sin rule to fine the tension in the strings;
Given
amass = 42.6kg
Weight = 42.6 * 9.8 = 417.48N
The third angle will be 180-(60+30)= 90 degrees
Using the sine rule
W/Sin 90 = T3/sin 30 = T2/sin 60
Get T3;
W/Sin 90 = T3/sin 30
417.48/1 = T3/sin30
T3 = 417.48sin30
T3 = 417.48(0.5)
T3 = 208.74N
Also;
W/sin90 = T2/sin 60
417.48/1 = T2/sin60
T2 = 417.48sin60
T2 = 417.48(0.8660)
T2 = 361.54N
The Tension T1 = Weight of the object = 417.48N
Which phrases accurately describe an elliptical galaxy? Check all that apply.
may be egg-shaped
may be spiral-shaped
has no recognizable shape
has no new stars being formed
has almost no gas or dust between stars
Answer:
May be egg shaped
Has no new stars being formed.
Has almost no gas or dust between stars.
Explanation:
Elliptical galaxy is the collection of many stars which are bounded together gravitationally, which is smooth and ellipsoidal and shape and the appearance is featureless.
Elliptical galaxy is ovoid or spherical masses of stars.
It is found in galaxy clusters and compact galaxies.
It has no gas or dust between stars which result in low rates of star formation.
It is formed When two spirals collide, they lose their familiar shape, morphing into the less-structured elliptical galaxies.
Elliptical galaxy is made of old stars and have no gas and dust.
An example is elliptical galaxy m60 which shines brightly and is egg shaped.
(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 x 108 m. Find the time it took for his voice to reach earth via radio waves. (b) Someday a person will walk on Mars, which is 5.6 x 1010 m from earth at the point of closest approach. Determine the minimum time that will be required for that person's voice to reach earth.
Answer:
a). 1.28333 seconds
b). 186.66 seconds
Explanation:
a). Given :
Distance between the earth and the moon, d = \($3.85 \times 10^8$\) m
Speed of the radio waves, c = \($3 \times 10^8$\) m/s
Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :
\($t=\frac{d}{c}$\)
\($=\frac{3.85 \times 10^8}{3 \times 10^8}$\)
= 1.28333 seconds
b). Distance between Mars and the earth, d = \($5.6 \times 10^{10}$\) m
Speed of the radio waves, c = \($3 \times 10^8$\) m/s
So, the time required for his voice to reach earth is :
\($t=\frac{d}{c}$\)
\($=\frac{5.6 \times 10^{10}}{3 \times 10^8}$\)
= 186.66 seconds
Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km
1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m
Answer:
Approximately \(9.0\; \rm N \cdot C^{-1}\) at \(1\; \rm m\) from this charge, pointing away from the point charge.Approximately \(2.2\; \rm N \cdot C^{-1}\) at \(\rm 2\; \rm m\) from this charge, pointing away from the point charge.Approximately \(1.0\; \rm N \cdot C^{-1}\) at \(3\; \rm m\) from this charge, pointing away from the point charge.Assumption: there is no object between this point charge and the observer.
Explanation:
The electric field of a point charge is inversely proportional to the square of the distance from that point charge.
Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:
\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).
Convert the magnitude of the point charge in this question to standard units:
\(q = 1\; \rm nC = 10^{-9}\; \rm C\).
Apply that equation to find the magnitude of the electric field due to this point charge:
\(r = 1\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 2\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 3\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).
The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.
Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.
write down the value of
920 kg in g
Answer:
920000
Explanation:
Each kg contains 1,000 grams
In which situation does the reactive force between two colliding objects cause a physical change? (1 point)
two bumper cars at an amusement park colliding, causing both cars to change direction
a baseball player swinging a bat and hitting a baseball, causing the bat to shatter
a swing hitting another swing, causing the second swing to move away
the exhaust from a rocket thrusting the rocket away from the ground
Answer: i believe it is a swing hitting another swing, causing the second swing to move away
Explanation: because force is making one swing move and once it hit's the other swing if forces it to move
i belive that is the answer if wrong sry
Which of the following statements is always true?
a. An object attest has no forces acting on it
b. Unbalanced forces lead to a change in speed or
direction
c. Gravity always leads to an unbalanced force
d. The net force on a moving object can never be zero
Answer: B
Explanation:
An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. An unbalanced force is an unopposed force that causes a change in motion.
Answer:B
Explanation:
A helicopter flies 160 m horizontally and then moves downward to land 50 m below. What is the helicopter's resultant displacement?
Answer:
Displacement = 167.63 m
Explanation:
Distance refers to the total ground covered by an object while in motion while displacement refers to how far an object is from it's original position.
Now, we are told that the helicopter flies 160m horizontally and then flies 50m downwards.
This means that it's displacement will be the distance from its final position to the initial position.
This can be represented with a triangle attached.
From the triangle, the displacement d will be gotten from pythagoras theorem.
Thus;
d² = 160² + 50²
d² = 25600 + 2500
d² = 28100
d = √28100
d ≈ 167.63 m
The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.
The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and 475 nm is\(6.31 x 10^14 Hz\)
The equation that links the speed of light to wavelength and frequency is
c = λν
Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.
Calculating the frequency of light with a wavelength of
655 nm:λ = 655 nm = \(6.55 x 10^-7m\)
Using the above equation, we get
c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)
Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)
Using the above equation, we get
c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).
Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get
c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)
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A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.
Express ALL parts with appropriate units
A. Δx = 384,400 km (distance between Earth and Moon)
How to solveB. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s
C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)
D, E, F. Cannot answer without specified primed frame.
G. Δx for laser beam = 384,400 km
H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s
I. s² for laser beam ≈ 0 km² (light-like separated events)
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2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)
This is the period in a simple harmonic motion which is 2 seconds in this question.
What is Period ?The period of an oscillatory object can be defined as the total time taken by a vibrating body to make one complete revolution about a reference point.
We are given the below question
2×3.14√(1.0m/(9.8〖ms〗^(2) )= T
This question can as well be expressed as
2π√(L/g) which is equal to period T.
In a nut shell, Period T = 2×3.14√(1.0m/9.8)
T = 6.28√0.102
T = 6.28 × 0.32
T = 2.006 s
Therefore, the period T of the oscillation is 2 seconds approximately.
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Olivia is rolling down a hill on a skateboard and is accelerating at 2.4 m/s2. After 3 seconds, she runs into Reid at the bottom of the hill. If her initial velocity was 1.5 m/s, what was her velocity when she hit Reid?
did you ever get the answer?
Answer:
8.7
Explanation:
A=2.4m/s2 1.5m/s + (2.4m/s2)(3s)
Vi=1.5m/s 1.5m/s + 7.2
Vf=? Vf= 8.7m/s
T=3s
3) A ball is thrown from a cliff with a speed of 28.00m/s at an angle 48.0 degrees above
the horizontal direction. The cliff is 25.00m high.
a) what is the highest height attained by the ball?
ad profesor
b) At what time it hits the ground?
c) What are the magnitude and direction of velocity when it hits the ground?
If a ball is thrown from a cliff with a speed of 28.00m/s at an angle 48.0 degrees above the horizontal direction. the highest height attained by the ball is 45.06 meters.
What is the highest height?a) We can use the following equation to find the time it takes for the ball to reach this point:
vf = vi + at
where vf is the final velocity (which is zero at the highest point), vi is the initial velocity (which is the vertical component of the initial velocity), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time it takes to reach the highest point.
First, let's find the vertical component of the initial velocity:
vi = 28.00 m/s * sin(48.0°) = 19.84 m/s
Now, we can use the equation above to find the time it takes for the ball to reach the highest point:
0 = 19.84 m/s + (-9.8 m/s^2)t
t = 2.02 s
The time it takes for the ball to reach the highest point is 2.02 seconds. To find the highest height attained by the ball, we can use the following equation:
y = yi + vit + (1/2)at^2
where y is the height at any time t, yi is the initial height (25.00 m in this case), vi is the initial vertical velocity (19.84 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time.
At the highest point, the vertical displacement (y - yi) is equal to the highest height attained by the ball. We can use the time we just found to calculate this displacement:
y - yi = vi*t + (1/2)at^2
y - 25.00 m = 19.84 m/s * 2.02 s + (1/2)(-9.8 m/s^2)(2.02 s)^2
y - 25.00 m = 20.06 m
y = 45.06 m
Therefore, the highest height attained by the ball is 45.06 meters.
b) To find the time it takes for the ball to hit the ground, we can use the same equation we used to find the time to reach the highest point, but this time we'll solve for the time when y = 0 (i.e., when the ball hits the ground):
0 = 19.84 m/s + (-9.8 m/s^2)t
t = 2.03 s
Therefore, the time it takes for the ball to hit the ground is 2.03 seconds.
c) At the instant the ball hits the ground, its vertical velocity is -vi = -19.84 m/s (i.e., the negative of its initial vertical velocity), and its horizontal velocity is v = 28.00 m/s * cos(48.0°) = 18.08 m/s (i.e., the horizontal component of its initial velocity). The magnitude of its velocity can be found using the Pythagorean theorem:
v = sqrt[(18.08 m/s)^2 + (-19.84 m/s)^2] = 26.03 m/s
The direction of its velocity can be found using the inverse tangent function:
theta = tan^-1((-19.84 m/s) / (18.08 m/s)) = -49.57°
The negative sign indicates that the velocity vector makes an angle of 49.57° below the horizontal direction.
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if a referee tosses a basketball in the air and hits the floor, at what point will the ball have no mechanical kinetic energy (hint: this occurs at more than one point)
the ball have no mechanical kinetic energy:
Just before the ball is set in motion in the air. Just after it hits the floor.What is mechanical kinetic energy?This refers to the energy that an object possessed due to its motion or due to its position. It is calculated by getting the product of the mass of the object and its velocity and dividing it by two. It is measured in joules, J.
if a referee tosses a basketball in the air, the ball will not have mechanical kinetic energy:
Just before the ball is set in motion in the air. ( Potential energy that is energy due to an object's position).Just after it hits the floor. ( Potential energy that is energy due to an object's position).Learn more about kinetic energy on
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(I am doing a lab called, Density of solids and I need help with this question) (I am in HS and I picked Physics because I thought it was short for Physical Science )
4. Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings?
Answer: Location the data and observations collected in your lab guide
Explanation:
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?
Answer:
2ohms
Explanation:
the net resistance is given by
1/R=1/R1 +1/R2,we are supposed to find R
thus by making R the subject ....
R=R1•R2/R1+R2
R=3•6/3+6
R=18/9 =2Ohms
A solid cube just gets completely immersed in water when
a 0.5 kg mass is placed on it. If the mass is removed, the cube
is 5 cm above the water level. What is the length of each side of the cube?
(Density of water =1 kg/L
A. 8 cm
B. 10 cm
C. 20 cm
D. 6 cm
If possible can you also explain the answer.
Thank you!
Answer:
B. 10 cm
x^3 = 1 L
1 L = 1000 cm^3 (since 1 L = 1000 cm^3)
x^3 = 1000 cm^3
A 100 N force pulls a box but it doesn’t move. How much work is done?
A. 0 J
B. 100 J
C. 50 J
D. Not enough info
Answer:
A
Explanation:
Work = force * distance
= 100 n * 0 = 0 work done
In what way is the technique used by Öst in this video similar to both systematic desensitization and flooding (as described in Chapter 5)?
Answer:
Because the out in a video
Answer: it is gradual, fairly intense
Explanation: