1. How much NaCl would you need to weigh out to prepare 100 mL of a 2.5% NaCl
solution?

Answers

Answer 1
Answer - 5.85g

Solution -

Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):

Given,

Molar mass of NaCl, M = 58.5g/mol

Volume of the solution, V= 100ml = 0.1L

Molarity, S= 1M

Mass of the solute,W=?

W=SMV

= 1×58.5×0.1

= 5.85g


Related Questions

(a) Thomson’s cathode–ray tube (Figure 2.6) and the mass spectrometer (Figure 2.15) both involve the use of electric or magnetic fields to deflect charged particles. What are the charged particles involved in each of these experiments?

Answers

The charged particles involved in  Thomson’s cathode–ray tube experiment is the negatively charged particles that we now call electrons.

The charged particles involved in the mass spectrometer is positively charged ions that is being deflected by magnetic fields.

What is the mass spectrometer?

The Mass spectrometer is an analytical tool that is used to measure the mass-to-charge ratio of ions.

One of the advantages of the mass spectrometer is that it is an excellent tool for identifying unknown components in a sample or confirming their presence.

The major disadvantages of mass spectrometer is that it is not very good at identifying hydrocarbons that produce similar ions and it's unable to tell optical and geometrical isomers apart.

In conclusion, some applications of mass spectrometer includes drug testing and discovery, food contamination detection.

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How can an igneous rock turn into a sedimentary rock?

Answers

Answer:

On the surface, weathering and erosion break down the igneous rock into pebbles, sand, and mud, creating sediment, which accumulates in basins on the Earth's surface. As successive layers of sediment settle on top of one another, the sediment near the bottom is compressed, hardens, and forms sedimentary rock.

After considering the results of the classification tests, the possibilities can be narrowed down further by determining the melting point of the
A derivative.
B Schiff addition product.
C iodoform.
D triiodo compound.

Answers

After considering the results of the classification tests, the possibilities can be narrowed down further by determining the melting point of the B Schiff addition product.

What two facts can you infer about your product based on its melting point range?

A compound's melting point is helpful in two ways: it provides information on the composition's identity and degree of purity. Impurities will affect a compound's melting point, resulting in broader and lower melting point ranges.

First, the solubility test must be performed in order to remove soluble contaminants from the target molecule. The desired chemical and the soluble impurities are dissolved in a minimum of near or boiling solvent once a suitable solvent has been selected. The solution is then given time to gradually cool.

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How much water would you need to add to 550 mL of a 2.5 M KCl solution to make a 1.0 M solution?

Answers

Answer with Explanation:

To determine the amount of water needed to dilute a 2.5 M KCl solution to a 1.0 M solution, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, we know that:

M1 = 2.5 M

V1 = 550 mL

M2 = 1.0 M

We want to find V2, the final volume of the solution, which will be greater than 550 mL due to the addition of water.

Using the dilution formula, we can solve for V2:

M1V1 = M2V2

2.5 M x 550 mL = 1.0 M x V2

V2 = (2.5 M x 550 mL) / 1.0 M

V2 = 1375 mL

Therefore, we would need to add 1375 mL - 550 mL = 825 mL of water to 550 mL of a 2.5 M KCl solution to make a 1.0 M solution.

What is the electromagnetic spectrum? How can electromagnetic radiation affect the human body?


You have decided to write an article for the local newspaper. Remember, an opinion article takes a stance and uses evidence to support the opinion that you possess. Your article will respond to ONE of the prompts below.

Ranking the most dangerous machines: cell phones, X-ray machines and microwaves.

Describe the importance of people protecting themselves against specific types of electromagnetic radiation.

Debunk a claim about the hazards of electromagnetic radiation on human health.

Is 5G dangerous?

As you write your article keep in mind the following questions.

What is electromagnetic spectrum?

What are the different sections of the electromagnetic spectrum?

How does electromagnetic radiation affect the human body?

Why are some sections of the spectrum more dangerous than others?

What claims have been made about the effects of cell phone radiation on human health?

What research has been done to support/debunk these claims?

Answers

Answer:

The electromagnetic spectrum is a range of energy that includes all forms of electromagnetic radiation, such as light, radio waves, microwaves, X-rays, and gamma rays. Depending on its frequency and intensity, electromagnetic radiation can affect the human body in different ways, from causing tissue damage and heating effects to potentially leading to cancer or other health problems.In terms of ranking the most dangerous machines, X-ray machines are generally considered the most dangerous, followed by microwaves and cell phones. X-ray machines emit high levels of ionizing radiation that can cause significant harm in large doses, while microwaves can cause tissue damage and heating effects with prolonged exposure to high levels of radiation. Although cell phones emit low levels of non-ionizing radiation, concerns have been raised about their potential health effects, although most scientific studies have found no clear evidence of harm.People need to protect themselves against specific types of electromagnetic radiation that may pose a risk of harm. This may involve taking appropriate precautions when using X-ray machines or other sources of ionizing radiation, or avoiding prolonged exposure to sources of non-ionizing radiation, such as microwave ovens or certain types of light bulbs. Individuals can also minimize their exposure to radiation by keeping a safe distance from sources of radiation and using protective equipment, such as lead aprons or radiation shields.There have been many claims about the hazards of electromagnetic radiation on human health, with some people suggesting that prolonged exposure to radiation from cell phones, Wi-Fi, or other sources can increase the risk of cancer, infertility, or other health problems. However, most scientific studies have found no clear evidence of such effects, and the World Health Organization and other public health organizations consider non-ionizing radiation to be safe for human use.As for the question of whether 5G is dangerous, current scientific evidence suggests that 5G technology is safe for human use. While concerns have been raised about the potential effects of 5G radiation, particularly in terms of its frequency and intensity, most scientific studies have found no clear evidence of harm. However, ongoing research is needed to monitor any potential health effects as the use of 5G technology continues to expand.

Article:

The electromagnetic spectrum is a range of energy that includes all forms of electromagnetic radiation. It is divided into categories based on their frequency and wavelength, from radio waves to gamma rays. Electromagnetic radiation is produced by many sources, including the sun, stars, and electronic devices such as cell phones and microwave ovens.

Electromagnetic radiation can affect the human body differently, depending on its frequency and intensity. Non-ionizing radiation, such as that produced by cell phones and other electronic devices, has low levels of energy and does not typically cause significant tissue damage. However, there are concerns about the potential long-term effects of exposure to this type of radiation, including an increased risk of cancer, infertility, or other health problems.

Some sections of the electromagnetic spectrum are more dangerous than others because of their potential to cause tissue damage and other health problems. Ionizing radiation, such as X-rays and gamma rays, can cause significant harm in large doses and should be used with caution.

         While there have been claims about the potential effects of cell phone radiation on human health, most scientific studies have found no clear evidence of such effects, and the World Health Organization and other public health organizations consider non-ionizing radiation to be safe for human use. Ongoing research is needed to monitor any potential long-term effects of cell phone radiation on human health, but current evidence suggests that the risks are low.

Adding 1.56 g of K2SO4 to 6.00 mL of water at 16.2ºC causes the temperature of the solution to drop by 7.70ºC.
How many grams of NaOH (ΔHsoln = –44.3 kJ/mol) would you need to add to raise the temperature back to 16.2ºC?

Answers

Answer:

You need to add 0.243g of NaOH to raise the temperature back to 16.2°C

Explanation:

Using the equation:

Q = C*m*ΔT

Where Q is heat

C is specific heat

m is mass

and ΔT is change in temperature

We can find the heat required to increase the temperature of the solution back to 16.2°C:

Assuming specific heat of the solution of water + K2SO4 = Specific heat of water:

C = 4.184J/g°C

m = 1.56g + 6.00g = 7.56g

ΔT = 16.2°C - 7.70°C = 8.50°C

Q = 4.184J/g°C * 7.56g * 8.50°C

Q = 268.86J = 0.269kJ of heat are required

As this heat is obtained from the dissolution of NaOH:

0.269kJ * (1mol NaOH / 44.3kJ) = 0.00607 moles of NaOH are required

In grams -Molar mass NaOH: 40g/mol-:

0.00607 moles NaOH * (40g / mol) =

You need to add 0.243g of NaOH to raise the temperature back to 16.2°C

At constant pressure for which of the reactions shown below should Delta H be greater than Delta E°?
1.2 SO2(g) + O2(g) - 2 SO3(g)
II. C5H12(9) + 8 O2(g) - 5 CO2(g) + 6 H20(1)
III. H2(g) + Br2(g) → 2 HBr(9),
IV. N204(9) - 2 NO2(g)

Answers

Answer: \(N_2O_4(g)\rightarrow 2NO_2(g)\) has higher value of \(\Delta H\) than \(\Delta E\)

Explanation:

The realtion between enthalpy change and internal energy change is:

\(\Delta H=\Delta E+\Delta n_gRT\)

where,

=  enthalpy of the reaction

= internal energy of the reaction

\(\Delta n_g\) = change in the gaseous moles of the reaction = Moles of product - Moles of reactant

R = gas constant

T = temperature

1. \(2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)\)

\(\Delta n_g\) = 2-3 = -1

2. \(C_5H_{12}(g)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)\)

\(\Delta n_g\) = 5-9 = -4

3. \(H_2(g)+Br_2(g)\rightarrow 2HBr(g)\)

\(\Delta n_g\) = 2-2 = 0

4. \(N_2O_4(g)\rightarrow 2NO_2(g)\)

\(\Delta n_g\) = 2-1 = 1

Thus reaction . \(N_2O_4(g)\rightarrow 2NO_2(g)\) has higher value of \(\Delta H\) than \(\Delta E\)

At constant pressure the given reaction that shows ΔH would be greater than ΔE is;

IV); N₂0₄(g) 2NO₂(g)

In chemistry, he meaning of ΔH and ΔE are;

- ΔH means the change in enthalpy, which is heat content.

- ΔE means the change in energy of a system.

Now, for a closed system the relationship between ΔH and ΔE is given by;

ΔH = ΔE + PΔV

where PΔV = ΔnRT

Thus; ΔH = ΔE + ΔnRT

where Δn = number of moles of product in the gaseous state - number of moles of reactants.

Thus, if Δn is negative, then ΔE would be greater than ΔH but if Δn is positive, then ΔH would be greater than ΔE

I) 2SO₂(g) + O₂(g) ⇒ 2SO₃(g)

number of moles of product = 2

number of moles of reactants = 2 + 1 = 3

Δn = 2 - 3

Δn = -1 and so ΔE would be greater than ΔH

II) C₅H₁₂(g) + 8O₂(g) ⇒ 5CO₂(g) + 6H₂0(l)

number of moles of product = 5 (6 is not used because water is in liquid and not gas)

number of moles of reactants = 8 + 1 = 9

Δn = 5 - 9

Δn = -4 and so ΔE would be greater than ΔH

III) H₂(g) + Br₂(g) → 2HBr(g)

number of moles of product = 2

number of moles of reactants = 1 + 1 = 2

Δn = 2 - 2

Δn = 0 and so ΔE would be equal to ΔH

IV) N₂0₄(g) → 2NO₂(g)

number of moles of product = 2

number of moles of reactants = 1

Δn = 2 - 1

Δn = +1 and so ΔH would be greater than ΔE

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An early arrangement of the then known elements was proposed by a British scientist John Newlands, which he called the Law of Octaves. Like other scientists at the time, Newlands arranged the elements in order of increasing atomic mass and noted that every eighth element had similar physical/chemical properties. In the modern Periodic Table, which of the following represents the last pair of elements for which Newlands' Law of Octaves would hold true?​

Answers

In the modern Periodic Table, the last pair of elements for which Newlands' Law of Octaves would hold true is Calcium (Ca) and Titanium (Ti).

Welcome to Gboard clipboard, any text that you copy will be saEnglish Language Test
14:50

1. I don’t think the boss is very ............. to agree.

a) probable
b) likely
c) suitable
d) talkativeved here.

Answers

The most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Option B)

Based on the given context, the word that best fits the sentence is "likely."

The sentence implies that the speaker doubts the boss's willingness to agree with something. In this case, "likely" expresses the probability or possibility of the boss agreeing. It suggests that the boss is not expected to be receptive or open to the idea.

"Probable" implies a higher degree of certainty or likelihood, which may not be suitable in this context since the sentence indicates skepticism about the boss's agreement.

"Suitable" means appropriate or fitting, but it does not convey the sense of agreement or willingness.

"Talkative" refers to someone who is inclined to talk a lot, which is unrelated to the boss's agreement.

Therefore, the most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Hence option B) is correct.

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1. Draw up schemes for the formation
of bonds between the atoms of the following
elements:
C and P; So; Mg u Si
2.
What kind of bond and type
of crystal
lattice
do you
follow me:
CaO, C, SiO2, Fe, K3N
Assume their physical
properties.
3. Specify which process
is depicted by the following diagram
(oxidation or reduction) and
make an electronic balance
corresponding to this scheme:
a) Cu0 -, Cu+2
b) S0
- S-2
B) Fe+3
Fe0
4. Make
up the redox reactions and
arrange the coefficients
by the electronic balance method:
A) H2O + CO2 - HCL +O2
b) Fe203 + H2 - Fe + H20
b) H2SO4 + S - SO2 + H2O

Answers

Schemes for the formation of bonds:

C and P; C + P → CPS; S + S → S₈Mg and Si: Mg + Si → Mg₂Si

How to setup schemes and bonds?

The schemes for the formation of bonds between the atoms of the following elements are:

Carbon and phosphorus:

C + P → CP

This is an example of a covalent bond, which is a type of bond that is formed by the sharing of electrons. In this case, the carbon atom shares one electron with the phosphorus atom, forming a single covalent bond.

Sulfur:

S + S → S₈

This is an example of a molecular bond, which is a type of bond that is formed by the sharing of electrons between multiple atoms of the same element. In this case, the sulfur atoms share two electrons each, forming a double bond.

Magnesium and silicon:

Mg + Si → Mg₂Si

This is an example of an ionic bond, which is a type of bond that is formed by the transfer of electrons from one atom to another. In this case, the magnesium atom gives up two electrons to the silicon atom, forming a magnesium ion with a charge of +2 and a silicon ion with a charge of -4. These ions are then attracted to each other by the opposite charges.

2. The types of bonds and crystal lattices for the following elements:

CaO: ionic bond, ionic lattice

C: covalent bond, diamond lattice

SiO₂: covalent bond, tetrahedral lattice

Fe: metallic bond, body-centered cubic lattice

K₃N: ionic bond, cubic lattice

3. The processes depicted by the following diagrams, along with the corresponding electronic balances:

Cu0 → Cu⁺²: oxidation

Cu0 → Cu⁺² + 2e⁻

S0⁻ → S⁻²: reduction

S0⁻- + 2e⁻ → S⁻²

Fe⁺³ → Fe⁺²: reduction

Fe⁺³ + 1e⁻ → Fe⁺²

4. The redox reactions and the coefficients arranged by the electronic balance method:

H₂O + CO₂ → HCL + O₂

2H⁺ + ¹/₂O₂ → HCL

2e⁻ + 2H⁺ → H₂

¹/₂O₂ + 2e⁻ → O₂⁻

Fe₂O₃ + H₂ → Fe + H₂O

Fe₂O₃ + 3H₂ → 2Fe + 3H₂O

3Fe⁺³ + 6e⁻ + 6H⁺ → 2Fe + 6H₂O

2O₂⁻ + 6H⁺ → 4H₂O

H₂SO₄ + S → SO₂ + H₂O

2H⁺ + SO₄²⁻ → SO₂ + H₂O

2e⁻ + 2H+ → H₂

S → S²⁻ + 2e⁻

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1. Write a balanced equation for each of the following reactions. Be sure to include the state of matter for each reactant and product.
b) Solid calcium cyanide and liquid water react to generate calcium hydroxide and hydrogen cyanide, both in solution.

Answers

The balanced equation for the reaction between solid calcium cyanide and liquid water to generate calcium hydroxide and hydrogen cyanide would be \(Ca(CN)_2 (s) + 2H_2O(l)-- > Ca(OH)_2 (aq) + 2HCN (aq)\)

Balancing chemical equations

The reaction between solid calcium cyanide and liquid water to generate calcium hydroxide and hydrogen cyanide would be written as follows:

The chemical formula of solid calcium cyanide = \(Ca (CN)_2 (s)\)

The chemical formula of liquid water = \(H_2O (l)\)

The chemical formula of calcium hydroxide in solution = \(Ca(OH)_2 (aq)\)

The chemical formula of hydrogen cyanide in solution = \(HCN (aq)\)

Bringing all the species together, the equation for the reaction would be:

\(Ca(CN)_2 (s) + H_2O(l)-- > Ca(OH)_2 (aq) + HCN (aq)\)

But the above equation is not balanced. The number of hydrogen and cyanide atoms is not balanced. Balanced chemical equations always have an equal number of every atom in the reactants and in the products.

Thus, the balanced equation of the reaction would be;

\(Ca(CN)_2 (s) + 2H_2O(l)-- > Ca(OH)_2 (aq) + 2HCN (aq)\)

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if you need 2.5 mole of sodium hydroxide what mass of aodium hydroxide does weight have

Answers

Explanation:

\(\large{ \star \fcolorbox{magenta}{purple}{ \fcolorbox{magenta}{blue}{ \fcolorbox{magenta}{pink}{ \fcolorbox{magenta}{red}{ \sf{ 2.5g }}}}}} \star\)

Now, inspect the properties of the unknown elements, compare them to the properties of your known elements, and see where the unknown elements best fit in the table above. Once you’re done, use your periodic table to identify each unknown element below.

Answers

Based on the comparison between the properties of the unknown elements and those of known elements, the elements are alkali metals.

The unknown elements are sodium and potassium.

What are the properties of alkali metals?

Alkali metals exhibit metal properties such as strong thermal and electrical conductivity, luster, ductility, and malleability. In the outermost shell of each atom of an alkali metal, there is just one electron. Compared to those in inner shells, this valence electron is significantly more loosely bonded.

Other properties of the alkali earth metals are:

Stored in a mineral oil solution.Low melting points.Low densitiesLow electronegativity.Low ionization energy.

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A 3.69 g
sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was combusted in excess oxygen. This produced 2.08 g
CO2
and 1.28 g
H2O
. A second sample of this compound with a mass of 4.65 g
produced 4.77 g
SO3
. A third sample of this compound with a mass of 8.62 g
produced 3.48 g
HNO3
. Determine the empirical formula of the compound. Enter the correct subscripts on the given chemical formula.

Answers

The empirical formula of the compound is C₂H₁₆S₂N₃O.

What is the empirical formula of the compound?

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

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3. Red light has a frequency of 401 THz. What is the wavelength?

Answers

A light wave in a medium has a wavelength of 5107 m and a frequency of 41014 Hz.

What wavelength is red light at 740 nm?

Its frequencies range from 4 to 8 hertz (Hz), or cycles per second, and its wavelengths range from 380 nanometers (nm), or 1.5 nm, to 740 nm, or 2.9 to 105 inches.

Which seven electromagnetic waves are there, from smallest to largest?

The parts of the electromagnetic spectrum are designated as follows, from highest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. The radio wave region of the electromagnetic spectrum includes microwaves (such as those found in microwave ovens).

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(d) Other
sugar molecules become
_____ and are carried away from the crystal.
the force of attraction is

Answers

Answer:

liquid

Explanation:

defiantly

What happens to the particles
of a liquid when it evaporates?
A. They spread farther apart.
B. They become tightly packed.
C. They stop moving.
D. They stay in the same place.

Answers

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor.

There are some particles in a liquid that have enough energy to escape the bonds to the other particles even below boiling point. This means they can move freely and turn into gas particles. The difference between boiling and evaporation is because boiling happens at a certain temperature and evaporation can happen at any temperature below boiling point.

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the answer is a, particles in gases are farther apart than in liquids

(HELP PLEASE) which pair would have an electrostatic force of attraction between them?

Na+ and Ar

Cs+ and Rb+

Cl− and O 2−


K+ and P 3−

Answers

Answer: K+ and P 3−

Explanation:

Electrostatic force of attraction is the attraction between different molecules that comes from them being electrically charged.

For molecules to have an electrostatic force of attraction, they need to have opposing charges because like charges repel each other but opposite charges attract.

In the question above, the only option that has opposing charges is option D so this is the correct option.

A gas has a volume of 54.0 mL at 475 torr and -13 degrees C . What will be the new volume be at STP?

Answers

Answer:35.437 mL

Explanation:

Combined gas law

P1V1/T1 = P2V2/T2

P1= 475 torr

V1= 54 mL

T1= 260.15 Kelvin

T2= 273.15 Kelvine

P2= 760 torr

V2=  

V2=P1V1T2/(T1P2) m

V2= 475 X 54 X 273.15 / (260.15 X 760) =35.437 mL

A person has a standing order for 6 doses of acetaminophen in a 24 hour period for fevers
acetaminophen requires what type of reporting?
ut of
Select one:
a. Routine
estion
b. Emergent
C. Certain Time
d. Urgent
4
A change in the type of seizure the person usually experiences that causes them to stop brea

Answers

Acetaminophen is used to treat patients with aches and fever. It is safe to give a dose of 4 grams in 24 hours period.

It is an effective medicine which does not require much time to provide relief to the patient.

Usually tylenol is the best medicine which consists of Acetaminophen in appropriate quantity to provide relief from pain and fever.

The reporting for the doses introduced to the patient must be routine since it is not an emergency case.

The correct answer is a. Routine

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What is the correct IUPAC name for Mn(CN)2?

Answers

The correct IUPAC name of Mn(CN)2 is Manganese II cyanide.

IUPAC is an acronym that stands for International Union of Pure and Applied Chemistry.

This body is in charge of devising the framework for the nomenclature of all chemical substances.

To name an ionic compound,  we must write the name of the metal followed by its oxidation state and lastly the name of the anion.

Hence the name of  Mn(CN)2 is Manganese II cyanide.

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I don't understand what the "amplitude" is?

I don't understand what the "amplitude" is?

Answers

In physics and mathematics, amplitude refers to the maximum displacement or distance that an oscillating or vibrating object or wave reaches from its equilibrium position.

For example, in the case of a simple harmonic motion (like a mass attached to a spring), the amplitude is the maximum displacement from the equilibrium position (i.e., the position where the spring is neither compressed nor stretched).

In the case of a wave, such as a sound wave or a light wave, the amplitude is the maximum distance that any part of the wave travels from its resting position (i.e., the position where there is no wave).

The amplitude is usually measured in units of distance, such as meters or feet, or in units of some other physical quantity that is related to distance, such as pressure or electric field strength.

If you have 0.36mol C that reacts with excess CuO, how many atoms do you have of Cu?

If you have 0.36mol C that reacts with excess CuO, how many atoms do you have of Cu?

Answers

Yeah I did it on egenugity , it’s c

Which two seasons are best for growing plants due to the amount of sun received at those times? (Select two.)
winter
summer
autumn
spring

Answers

Answer:

spring and summer

Explanation:

Answer:

summer and spring

Explanation:

what is the answer to this question

what is the answer to this question

Answers

4, they are: Fe,H,C,O

Electrolysis of molten lead bromide is carried out.
The bulb will not light until the lead bromide has melted. Why not?

Answers

Answer:

Read Below

Explanation:

Electrolysis is not possible with solid lead (II) bromide. This is because the ions are held in a three-dimensional lattice, unable to move freely to the electrodes. Melting enables the ions to become mobile and to travel to the respective electrodes.

The bulb won't glow when the electrodes are embedded in solid lead bromide.  The bulb will glow when the material surrounding the electrodes is molten lead bromide. When an ionic compound is in the molten (liquid) form the positive and negative ions are free to move around.

Hopes this Helps :D

Brainiest Please

When CH3NO2 burns in excess oxygen, it forms carbon dioxide, nitrogen dioxide and water. How many moles of oxygen are required to burn 17.10 mole(s) of CH3NO2

Answers

Explanation:

The given reaction is the combustion of CH3NO2.

The balanced chemical equation of the reaction is:

\(4CH_3NO_2+ 7O_2 ->4 CO_2+4NO_2+6H_2O\)

So, from the balanced chemical equation, it is clear that:

4 moles of CH3NO2 --- 7 moles of oxygen gas is required.

then,

for 17.10 moles of CH3NO2 the following number of moles of oxygen is required.

\(The number of moles of O_2 required=17.10 mol. x \frac{7 mol}{4 mol} \\=29.925 mol\)

Answer is :

29.9 mol of oxygen gas is required.

A nurse practitioner orders Medrol to be given 1.4 mg/kg of body weight. Medrol is an anti-inflammatory administered as an intramuscular injection. If a child weighs 71.6 lb and the available stock of Medrol is 20. mg/mL, how many milliliters does the nurse administer to the child? Express your answer to two significant figures and include the appropriate units.​

Answers

The nurse give 2.3 ml Medrol to the child

Further explanation

Mass is one of the principal quantities, which is related to the matter in the object  

The main mass unit consists of 7 units

kg, hg, dag, g, dg, cg, mg

Conversion :

1 Lb=0,453592 kg

For 71.6 lb :

\(\tt 71.6\times 0.453592=32.48~kg\)

Medrol to be given 1.4 mg/kg of body weight, so amount for the child :

\(\tt 32.48~kg\times 1.4~mg/kg=45.472~mg\)

The available stock of Medrol is 20. mg/mL, so the volume to the child :

\(\tt \dfrac{45.472}{20}=2.2736\approx2.3~ml\)

For the substituted cyclohexane compound shown, identify the atoms that will interact with the methyl group in a
1,3-diaxial fashion after rotation to the other chair conformation.
BE
BrE
HI
H
A CI
HF
HG
Н.С.
HOJ
D
HK
CIH
These atoms will interact with methyl in a 1,3-diaxial interaction.
DA
B
ID
ОН
EK
incorrect

For the substituted cyclohexane compound shown, identify the atoms that will interact with the methyl

Answers

Answer: choice: I & Choice E

Explanation:

Answer:

C and G

Explanation:

Write the equation for the equilibrium constant (K) of the reaction studied in this exercise.

2C04 2- (ag) + 2Ht (ag) = CI20, 2- (ag) + H20(1)

Answers

The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

For more such question on  equilibrium constant visit:

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