Zn(s) + Cu²*(aq) → Zn²+ (aq) + Cu(s)
What is the net potential (E) for the overall reaction?

(1) -0.42 V
(2)-1.10 V
(3) +1.10 V
(4) +0.42 V

The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2

Bond order = (8 - 5) / 2

Bond order = 1.5.

This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

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Answer:

why is what possible?

Explanation:

The value of K will vary depending on the specific conditions of the reaction.

The equilibrium constant, denoted as K, expresses the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants at equilibrium. For the given reaction:

2 CH₃Cl(g) + Cl₂(g) ⇌ 2 CH₂Cl₂(g) + H₂(g)

The equilibrium constant expression can be written as:

K = [CH₂Cl₂]²[H₂] / [CH₃Cl]²[Cl₂]

Note that the concentrations of gases are usually expressed in terms of their partial pressures. If the concentrations are given in molarities, you can replace them with the corresponding partial pressures using the ideal gas law.

It's important to note that without specific information on the concentrations (or partial pressures) of the substances at equilibrium, it's not possible to calculate the numerical value of the equilibrium constant K. The value of K will vary depending on the specific conditions of the reaction.

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Answer:

0.693 (you can round it up if you want to)

Explanation:

Density= mass ÷ volume

54.2 ÷ 78.1 = 0.693

I hope this helped☺

Answer:

edge sample answer -

Lesson Question: What is the effect of temperature on the solubility of a solid in a liquid?

Explanation:

Answer:

D.) 2,200 kJ

Explanation:

To find the energy needed to vaporize aluminum, you need to multiply the given mass (2 kg) by the latent heat of vaporization conversion (via table). You know your answer is correct if the units cancel out.

2 kg aluminum                1,100 kJ
-------------------------  x  ------------------------  = 2,200 kJ
                                   1 kg aluminum

**I apologize if there was another way using the equation **

The equilibrium constant expression for the decomposition of ammonium hydrogen sulfide can be written as follows:

Kc = [NH3][H2S]/[NH4HS]

where [NH3] represents the concentration of ammonia in moles per liter (mol/L), [H2S] represents the concentration of hydrogen sulfide in mol/L, and [NH4HS] represents the concentration of ammonium hydrogen sulfide in mol/L at equilibrium.

The equilibrium constant expression describes the ratio of the concentrations of the products to the concentration of the reactant at equilibrium. A larger value of Kc indicates that the products are favored at equilibrium, while a smaller value indicates that the reactant is favored.

In the case of the decomposition of NH4HS, if the value of Kc is greater than 1, it indicates that the forward reaction (decomposition of NH4HS to NH3 and H2S) is favored at equilibrium, and if Kc is less than 1, it indicates that the reverse reaction (formation of NH4HS from NH3 and H2S) is favored at equilibrium. If Kc is equal to 1, it indicates that the forward and reverse reactions are occurring at equal rates and the system is at equilibrium.

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(order in NO ) + (order in H2 ) = overall order = third

2 + (order in H2 ) = 3

(order in H2 ) = 3 - 2 = 1 = first order in H2 .

Rate = k[ NO ] 2 [ H2 ] 1 = k[NO]2[H2] .

What is Rate of reaction?

The rate at which reactants change into products is known as the rate of reaction or reaction rate. It goes without saying that the rate at which chemical reactions take place varies greatly. While certain chemical reactions occur almost instantly, others typically take time to achieve their final equilibrium.

Reaction rate is the rate at which a chemical reaction moves forward. It is frequently described in terms of either the concentration of a reactant that is consumed in a unit of time or the concentration of a product that is generated in a unit of time (amount per unit volume).

You may also define it in terms of how much of the reactants are used up or how much of the products are produced in a given amount of time. Consider, for illustration, a reaction where the balanced chemical equation is of the type A + 3B →   2Z.

The following alternate ways of expressing the rate are also possible:

Where t is the time, [A], [B], and [Z] are the substance concentrations, and a, b, and z are their amounts, the formula reads: d[Z]/dt, -d[A], -d[B], dz/dt, da/dt, and db/dt. Please take note that these six expressions are not interchangeable; rather, they are just connected.

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4th pic is solid, gas

and the other one is further apart; increase

5th pic for second question is D

and the first question is kinetic energy

yw bakugo

The measurements which are listed in the proper mathematical relationship include:

This is used in mathematical expressions and has a constant value which doesn't change in expression.

Options A,B and C have the appropriate constants as pressure is usually multiplied by volume.

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Answer:

2.58×10^6

Explanation:

1.20×2.152

=2.5824×10^6

Answer:

Explanation:

So, just find 55 on the solubility side and with your finger just move to the right untill you touch the line you should get in between 46-48. I would go more for 48.

Hope you have a wonderful day!

Answer:

I think that the metric system is one of the easiest systems once you understand it (no hate)

To produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta. To determine the amount of pasta required to produce 1000 kg of fishmeal, we need to consider the mass balance of the process. Let's break down the steps involved:

A. Extraction of fish oil:

The pasta obtained from the extraction stage contains 20% flour and 80% water. To calculate the amount of pasta, we need to determine the mass of flour and water in the pasta. Let's assume the total mass of the pasta is P kg.

Mass of flour = 20% of P = 0.2P kg

Mass of water = 80% of P = 0.8P kg

b. Drying of pasta:

During the drying stage, the pasta is dried in a rotary drum, resulting in fishmeal with 40% humidity. This means that the final fishmeal will contain 60% dry matter.

Let's assume the mass of the dried fishmeal is M kg.

Mass of dry matter = 60% of M = 0.6M kg

Since the dry matter in the fishmeal comes from the flour in the pasta, we can equate the mass of dry matter to the mass of flour:

0.6M kg = 0.2P kg

To produce 1000 kg of fishmeal, we want to find the corresponding value of P:

0.6M = 0.2P

P = (0.6M) / 0.2

P = 3M

Therefore, to produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta.

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Answer:

Formic acid H. COOH

Acetic acid CH3.COOH

Propionic acid CH3 . CH1 . COOH

Butyric acid CH3 . CH1 . CH1 . COOH

Explanation:

6HBr+2Al → 2AlBr3+3H2

now, as the reaction is showing

6 moles of  HBr  reactes with 2 moles of Aluminium gives us 2 moles of Aluminium bromide and 3 moles of hydrogen gas

as the question says  10g of HBr reacted with 5g of Al.

(i) mass of Aluminium bromide produced.

moles = given mass/molecular mass

moles =  5g/54g

moles 0.0925 mole

(ii) number of bromide ions formed

6 moles of bromide ions formed in this reaction

now 1 moles = 6.022×10^23

6 moles = 6 ×6.022×10^23

= 36.132×10^23ions

(iii) percentage yield if 0.55 g of aluminum bromide is actually yielded

percentage yield= moles×100

percentage yield= 0.55×100÷107

percentage yield=0.514%

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The vapor pressure of octane at 38 degrees Celsius is approximately 27.59 torr.

To calculate the vapor pressure of octane at 38 degrees Celsius, we need to use the Clausius-Clapeyron equation:
ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1)

P1 and T1 are the known vapor pressure and temperature, P2 is the vapor pressure at 38 degrees Celsius (which we want to find), T2 is the temperature in Kelvin (which is 38 + 273.15 = 311.15 K), ΔHvap is the heat of vaporization
ln(P2/13.95 torr) = -40 kJ/mol / (8.314 J/(mol*K)) * (1/311.15 K - 1/298.15 K)
Simplifying this equation:
ln(P2/13.95 torr) = -4813.85
Now we can solve for P2 by taking the exponential of both sides:
P2/13.95 torr = e^(-4813.85)
P2 = 2.382 torr
The vapor pressure of octane at 38 degrees Celsius is approximately 2.382 torr.
ln(P2/P1) = -(ΔHvap/R)(1/T2 - 1/T1)
P2 = ? at T2 = 38°C = 311.15 K
ΔHvap = 40 kJ/mol = 40,000 J/mol
Now, we can plug in the values and solve for P2:
ln(P2/13.95) = -(40,000 J/mol)/(8.314 J/mol·K)(1/311.15 K - 1/298.15 K)
ln(P2/13.95) = -1.988
Now, exponentiate both sides to solve for P2:
P2 = 13.95 * e^(-1.988) = 27.59 torr (rounded to two decimal places)

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A balanced chemical equation, which demonstrates that all mass is conserved throughout the reaction, demonstrates the law of conservation of mass. The quantity and types of atoms on either side of a chemical equation should be equal in a balanced chemical equation.

In accordance with the principle of mass conservation, There is neither creation nor destruction of mass during a chemical process. In other words, the total masses of the reactants and products must be equal.

The reactants of photosynthesis are sunlight, 6 carbon dioxide, and 6 water. The mass of the products, which are 1 glucose and 6 oxygen, is equal to the mass of these reactants added together. Contrarily, cellular respiration uses glucose and oxygen gas to create water, carbon dioxide, and ATP, a source of useable energy.

The products of photosynthesis are the reactants of cellular respiration, which is the reverse of photosynthesis. The law of conservation of mass is also observed during cellular respiration.

A balanced chemical equation, which demonstrates that all mass is conserved throughout the reaction, demonstrates the law of conservation of mass. The quantity and types of atoms on either side of a chemical equation should be equal in a balanced chemical equation.

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Considering the definition of pH and pOH, the pH and pOH of the solution is 12.8 and 1.2 respectively.

Molarity is the concentration of a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity= number of moles÷ volume

Molarity is expressed in units moles/L.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

You know:

Replacing in the definition of molar mass:

74 g/mole= 23.2 g÷ number of moles

Solving:

74 g/mole ×number of moles= 23.2 g

number of moles= 23.2 g÷ 74 g/mole

number of moles= 0.3135 moles

Now, you know:

Replacing in the definition of molarity:

molarity= 0.3135 moles÷ 2.5 L

Solving:

molarity= 0.1254 moles/L

Calcium hydroxide is a strong base, meaning that it dissociates completely in an aqueous solution. From the reaction:

Ca(OH)₂ → Ca⁺² + 2 OH⁻

The concentration of OH⁻ is then divided by 2 according to the given reaction. So [OH⁻]= [Ca(OH)₂]÷2 =0.1254 moles/L ÷2= 0.0627 moles/L

Now, pOH is calculated as:

pOH= - log (0.0627 moles/L)

pOH= 1.20

The pOH of the solution is 1.20.

The pH of the solution can be calculated as:

pH + 1.20= 14

pH= 14 - 1.20

pH= 12.8

The pH of the solution is 12.8

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in this question, we are given with the pressure at initial point i.e. 15 psi that undergoes compression from 470ml of volume to 260 ml.

We are asked to determine the final pressure after the compression.

For that we'd consider the Boyle's law that states that, for a gas in an iso-thermic system Pressure is inversely proportional to the Volume.

which means with the increase in Pressure, Volume of gas will reduce.

At constant Temperature, product of Pressure and Volume will be constant.

PV =  constant.

for same system at different pressure volume condition, we can say that-

\(P_{1}V_{1} = P_{2}V_{2}\)

\(P_{1} = 15psi\\ V_{1} = 470ml\\ V_{2} = 260ml\)

(15)(470) / (260) = \(P_{2}\)

Final Pressure = 27.11 psi

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The heat change (ΔH°rxn) for the slow reaction of zinc with water is -671.6 kJ. This value represents the heat absorbed or released during the reaction, indicating an exothermic process (-671.6 kJ of energy is released).

By applying Hess's law, we can calculate the heat change (ΔH°rxn) for the slow reaction of zinc with water, Zn(s) + 2H2O(l) -> Zn2+(aq) + 2OH-(aq) + H2(g). We need to manipulate the given reactions to obtain the desired reaction and then sum up the enthalpy changes. First, we reverse reaction 1 to obtain H2O(l) -> H+(aq) + OH-(aq) with a reversed enthalpy change of ΔH°rxn1 = 56.0 kJ. Next, we multiply reaction 2 by 2 to match the stoichiometry of Zn2+ in the desired reaction, resulting in 2Zn(s) -> 2Zn2+(aq) with a multiplied enthalpy change of ΔH°rxn2 = -307.8 kJ. Finally, we multiply reaction 3 by 2 to match the stoichiometry of H2 in the desired reaction, giving H2(g) -> 2H+(aq) with an enthalpy change of ΔH°rxn3 = 0.0 kJ.

Now we can sum up these manipulated reactions to obtain the desired reaction: 2Zn(s) + 2H2O(l) + H2(g) -> 2Zn2+(aq) + 2OH-(aq) + 2H+(aq) + H2O(l)

Adding up the enthalpy changes of the manipulated reactions:

ΔH°rxn = (2ΔH°rxn2) + ΔH°rxn1 + (2ΔH°rxn3)

= (2 * -307.8 kJ) + (-56.0 kJ) + (2 * 0.0 kJ)

= -615.6 kJ - 56.0 kJ + 0.0 kJ

= -671.6 kJ

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Being burned out means feeling empty and mentally exhausted, devoid of motivation.

What is burnout?

The ways to cope with personal stress:

Four methods that helped many supervisors cope with stress are

(1) engaging in physical exercise

(2) practicing relaxation techniques

(3) gaining a sense of control

(4) developing and maintaining good interpersonal relationships.

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The options which correctly describe entropy are- Entropy is a measure of the energy dispersal of a system, The greater the freedom of motion of particles in a system, the greater the entropy of the system and Any process that causes an increase in the entropy of a system will be spontaneous.

Entropy is a measure of the disorder or randomness of a system, and it is often associated with the amount of energy that is unavailable to do work. The symbol for entropy is S. It is not another term for kinetic energy or energy of movement.

The second law of thermodynamics says that the total entropy of a system either increases or will remain constant in any spontaneous process. It never decreases.

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Answer:

The answer is SiO2

Explanation:

Because nonmetals are those who gain electrons and form ve ions

Answer:

I'm guessing the alimentary canal

To find the Ksp (solubility product constant) for Ca(OH)2, we can use the given information about the pH of the solution. First, let's convert the pH to the concentration of OH- ions. Since the solution is basic (pH > 7), we can use the formula [OH-] = 10^(-pOH), where pOH = 14 - pH.

In this case,

pOH = 14 - 12.37 = 1.63, so [OH-] = 10^(-1.63) = 0.044 moles per liter (mol/L).

Next, we can assume that all the Ca(OH)2 in the solution has dissociated to form Ca2+ and 2 OH- ions, as Ca(OH)2 dissociates according to the equation: Ca(OH)2 -> Ca2+ + 2OH-. Since the molar ratio of Ca(OH)2 to OH- is 1:2, the concentration of Ca2+ ions will be half of the OH- concentration, i.e., 0.022 mol/L. Now, we can write the expression for:

Ksp: Ksp = [Ca2+][OH-]^2.

Substituting the concentrations, we have:

Ksp = (0.022)(0.044)^2 = 0.000053 moles per liter squared (mol^2/L^2).

So, the Ksp for Ca(OH)2 is 0.000053 mol^2/L^2. To find the Ksp for Ca(OH)2, we first convert the pH to the concentration of OH- ions using the formula [OH-] = 10^(-pOH), where pOH = 14 - pH. In this case, pOH is 14 - 12.37 = 1.63, so [OH-] is 10^(-1.63) = 0.044 mol/L. Assuming complete dissociation of Ca(OH)2, the concentration of Ca2+ ions is half of the OH- concentration, i.e., 0.022 mol/L. We can now write the expression for Ksp: Ksp = [Ca2+][OH-]^2. Substituting the concentrations, we have: Ksp = (0.022)(0.044)^2 = 0.000053 mol^2/L^2. Therefore, the Ksp for Ca(OH)2 is 0.000053 mol^2/L^2.

The solubility product constant (Ksp) for Ca(OH)2 is calculated to be 0.000053 mol^2/L^2 using the given information about the pH of the solution.

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Answer:

Explanation:

Answer:

NaCl(Sodium chloride)

Explanation:

The importance of sodium chloride are

It is used to prepare food

It is used for preserving food

The solution of sodium chloride may conduct electricity

Answer:

Option B. 176g/mol

Explanation:

We'll begin by writing the chemical formula for hexasodium difluoride. This is given below:

Hexasodium means 6 sodium atom

Difluoride means 2 fluorine atom.

Therefore, the formula for hexasodium difluoride is Na6F2.

The relative formula mass of a compound is obtained by simply adding the atomic masses of the elements present in the compound.

Thus, the relative formula mass of hexasodium difluoride, Na6F2 can be obtained as follow:

Molar mass of Na = 23g/mol

Molar mass of F = 19g/mol

Relative formula mass Na6F2 = (23x6) + (19x2)

= 138 + 38

= 176g/mol

Therefore, the relative formula mass of hexasodium difluoride, Na6F2 is 176g/mol

Answer:

B. 176 g/mol

Explanation:

chemistry ed tell

Answer:

6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.

Explanation:

We are given the chemical equation:

\(\displaystyle 2\text{NH$_3$}_\text{(g)} + 3\text{CuO}_\text{(s)} \longrightarrow \text{N$_2$}_\text{(g)} + 3\text{Cu}_\text{(s)}+3\text{H$_2$O}_\text{(g)}\)

And we want to determine the amount of products produced when 12.5 moles of NH₃ is reacted with excess CuO.

Compute using stoichiometry. From the equation, we can see the following stoichiometric ratios:

Dimensional Analysis:

\(\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{1\text{ mol N$_2$}}{2\text{ mol NH$_3$}} = 6.25\text{ mol N$_2$}\)

\(\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{3\text{ mol Cu}}{2\text{ mol NH$_3$}} = 18.8\text{ mol Cu}\)

\(\displaystyle 12.5\text{ mol NH$_3$} \cdot \frac{3\text{ mol H$_2$O}}{2\text{ mol NH$_3$}} = 18.8\text{ mol H$_2$O}\)

In conclusion, 6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.