You've just put a new wood floor in your house. An object will dent the flooring if the stress--the force divided by the area--exerted by the object is great enough.
A) Find the stress produced by a 50 kg woman in high-heeled shoes (assume a circular heel pad 0.50 cm in diameter) with all of her weight on one heel.
Express your answer with the appropriate units.
B) Find the stress produced by a 5000 kg African elephant (assume a circular contact area of 40 cm in diameter for one foot) standing on all four feet.
Express your answer with the appropriate units.

Describe one of the Hubbard Brook experiment's examples of each of the scientific practices (Figure 2-2): The researchers used two distinct woodlands. One was pruned, while the other was unaltered. Then they took measurements of the water and nutrient discharge.

The Hubbard Brook Experimental Forest, a 7,800-acre field site in the White Mountains of New Hampshire, is the setting for the extensive, cooperative Hubbard Brook Ecosystem study. Long-term observation, testing, and modeling have been employed by scientists to establish a solid understanding of the northern hardwood forests of eastern North America for more than 60 years.

So finally we can say that - the description of one of the example of each of the scientific practices (Figure 2-2) in the Hubbard Brook experiment -  The scientists took two different forests. One cut down, and the other untouched. They then measured the outflow of water and nutrient.

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45/4  [ ln (v17 + 4) + 4v17 ] m or approx. 209.1 m, the distance traveled by the prey from the time it is dropped until the time it hits the ground = 209.1 m approx.

A parabolic trajectory in astrodynamics / celestial mechanics is an unbound Kepler orbit with an eccentricity of 1, which is exactly on the threshold between an elliptical and a hyperbolic orbit. An escape orbit, or a capture orbit in the alternative, is one that is traveling away from the source.

The parabolic trajectory of the falling prey is described by the equation y = 180 - (\(x^{2}\))/45. This equation can be used to calculate the time it takes for the prey to hit the ground.

Because the prey's height y is zero when it hits the ground, we can solve for x:

0 = 180 - (\(x^{2}\))/45

\(x^{2}\) = 8100

x = ±90

distance = 2 * 90 = 180 meters (to the nearest tenth of a meter).

As  a result, the prey travels a horizontal distance of 180 meters from the moment it is dropped to the ground.

Free fall has a trajectory, right?

Gravity's acceleration is constantly downward and constant, however the speed and direction of the acceleration vary. The ball exhibits zero velocity at its greatest point in its journey, and as it descends back toward the earth, its magnitude of velocity grows once more.

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Answer:

True

Explanation:

The kinetic energy of an object is the energy that it possesses due to its movement or motion.

True, the amount of kinetic energy an object has depends on its mass and its speed.

The kinetic energy of a moving object is directly proportional to the square of its velocity and directly proportional to its mass.

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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(a) F(x) = 0.503 x, where x is in meters and F is in newtons, is the formula given for the force. We can see that this equation's proportionality constant, C, must be expressed in newtons per meter. C is therefore measured in N/m in the SI.

(b) The work done by the force as the particle moves from x = 3.0 m to x = 1.5 m can be calculated using the formula for work, which is W = ∫ F(x) dx, where the integral is taken over the distance moved. Therefore, we have:

W = ∫ 0.503 x dx from x = 3.0 to x = 1.5

W = [0.503/2 x^2] from x = 3.0 to x = 1.5

W = [0.503/2 (1.5^2 - 3.0^2)]

W = -1.129 J

The work done by the force is -1.129 joules.

(c) At x = 3.0, the force is given to be in the opposite direction to the particle's velocity. Therefore, the force is opposing the motion of the particle. We can use the work–kinetic energy theorem to determine the change in kinetic energy of the particle between x = 3.0 and x = 1.5, and hence its speed at x = 1.5. The work–kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we have:

W_net = ΔK

In this case, the only force acting on the particle is the given force, and we have already calculated the work done by this force as -1.129 J. Therefore, we have:

W_net = -1.129 J

ΔK = 1.129 J (since the work done is negative, indicating a decrease in kinetic energy)

We can use the formula for kinetic energy, K = (1/2)mv^2, to find the particle's speed at x = 1.5. Therefore, we have:

ΔK = (1/2)m(v^2 - v_0^2)

1.129 = (1/2)(1.5)(v^2 - 12^2)

v^2 = 12^2 - (2/1.5)(1.129)

v^2 = 56.49

v = 7.52 m/s

The particle's speed at x = 1.5 is 7.52 m/s.

(d) kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, the net work done by the given force Is -1.129 J, the initial kinetic energy of the particle (since we are told its speed at x = 3.0).

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Answer:

B. Reaction Time

Explanation:

Reaction Time is the amount of time it takes to respond to anything.

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

534 j

Explanation:

100 lbs = 45.359 kg

work = F * d

         = 45.359 * 9.81  * 1.2 = ~ 534 j

The work done is the dot product of force and displacement. 100 lbs is 45.3 kg in weight. The work done on this weight to make a displacement of 1.2 m is 532.728  J.

Work done in physics is the dot product of  force and displacement. Force exerted on an object if results in displacement, it is said to be work  done on the object. Work done is a vector quantity, thus, both magnitude and direction.

Not any force results in work done. Work is done only if there occurs a displacement. It is given that the weight of object moved is 100 lbs.

1 lbs. = 0.453 kg

thus, 100 lbs. = 45.3 Kg.

Force F = mg

             = 45.3 Kg × 9.8 m/s²

             = 443.94 N

This is the force by its own weight.

Work done = Force × displacement.

                   =  443.94 N × 1.2 m

                   = 532.728  J

Therefore, the work done to move the weight is 532.72 J.

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Answer:

d

Explanation:

because is a reducing agent, O 2 is an oxidizing agent.

Answer: Glucose

Explanation:

Resistors limits the current/amps but keep the voltage the same.

You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.

Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.

So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,

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Answer:

Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.

Answer:

0.338125 m/s

Explanation:

Applying,

Law of conservation of momentum

m'v' = mv............ Equation 1

Where m' = mass of the first skater, v' = velocity of the first skater, m = mass of the second skater, v = velocity of the second skater.

make v the subject of the equation

v = m'v'/m........... Equation 2

From the question,

Given: m' = 54.1 kg, v' = 0.375 m/s, m = 60 kg

Substitute these values into equation

v = (54.1×0.375)/60

v = 20.2875/60

v = 0.338125 m/s

Answer: 529.9 Hz

Explanation:

Here we need to use the Doppler equation, so we have:

f' = f*(v + v0)/(v - vs)

Here, f is the frequency = 500Hz

v is the velocity of the wave, = 334m/s

v0 is the velocity of the observer = 20m/s

vs is the velocity of the source = 0m/s

Then we have:

f' = 500Hz*(334m/s + 20m/s)/(334m/s) = 529.9 Hz

The maximum height to which the ball attain before falling back down is 1147.96 m

The following data were obtained from the question:

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

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The airplane change in velocity be 120 m/sec

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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The types of chemical reactions are as follows:

Chemical reactions are changes in which new substances are formed.

The types of chemical reactions are as follows:

In conclusion, chemical reactions produce new substances.

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Astronomers can calculate the pair's size by observing how they tug on one another, and from that they can extrapolate other properties like temperature and radius. All solitary main sequence stars in the universe share these characteristics.

Any binary system has elliptical orbits for both stars around the center of mass (COM). The semi-major axis cuts the long axis of the elliptical in half. A specific kind of ellipse with a radius equal to its semi-major axis is a circle.

The relationship between the orbital period and orbital radius is described by Kepler's third law, sometimes referred to as the law of periods. This law states that the square of an object's orbital period is directly proportional to the cube of its orbital radius, or vice versa.

Therefore, In this instance, the V cube equals two, 3.14, 6.67, and 10 days. To part 30 in 27.45 split by 1.0 in 2-4 in two 3600, power -11 in two, two into 10 days. After solving, we see that v cubed is 42.49 into 10 raised to power 15 m/s, meaning that the value of V is 3.4 into 10 raised to power 5 m/s.

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The five examples of pseudoscience found on the Internet include the following:

Pseudosciences is defined as the science that is regarded as false science because it deals with something that has no connection to proper scientific methodology and cannot be proven realistically.

The different types of Pseudosciences include the following:

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Answer:

un café y a seguir pensando porque no se la respuesta xd

Answer:

Pitch is the correct answer!

Explanation:

~Hope this helps! :)

Answer:

B

Explanation:

I am pretty sure it is B as the speed is obviously constant but the velocity is not constant as it defines as the rate of speed AND DIRECTION meaning that it is not constant as it always changes direction. And angular velocity is constant.

Answer:

Explanation:

the 40-watt bulb is going to require less energy to power.

For a longitudinal wave, the compression region, is the one represented by the densely packed particles with high pressure and the region with loosely packed particles is called rarefaction. Hence, the first part is C he dense region and the second one with some space between the dots is labeled as R.

Longitudinal waves are a type of mechanical waves passing through a medium. Unlike electromagnetic waves, they cannot be passed through vacuum.

In a longitudinal wave, the oscillation of particles is along the direction of wave propagation. The wave is composed of high pressure regions and low pressure regions called compressions and rarefactions respectively.

The regions where, particles are densely packed and shows the thick dote are labelled as compressions and the regions where, some space between particles are labeled as rarefactions.

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1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

A. 4.82 cm

B. 24.66 cm

Explanation:

The depth of water = 19.6 cm

Distance of fish  = 6.40 cm

Index of refraction of water = 1.33

(A). Now use the below formula to compute the apparent depth.

\(d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\= \frac{1}{1.33} \times 6.40 \\= 4.82 cm.\)

(B). the depth of the fish in the mirror.

\(d_{real} = 19.6 cm + (19.6 cm – 6.40 cm) = 32.8 cm\)

Now find the depth of reflection of the fish in the bottom of the tank.

\(d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\d_{app} = \frac{1}{1.33} \times 32.8 = 24.66\\\)

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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