You witnessed a slide breaking while someone is using a microscope.The silde was not dropped.You are tasked with finding out why the slide broke.Explain

Answer:

See attached picture.

Explanation:

Hello,

In this case, we should define each type of structural formula as shown below:

- Chain isomers: molecules with the same molecular formula, but different arrangements.

- Positional isomers are constitutional isomers that have the same carbon skeleton and the same functional groups but differ from each other in the location of the functional groups.

- Functional isomers are structural isomers that have the same molecular formula (that is, the same number of atoms of the same elements), but the atoms are connected in different ways so that the groupings are dissimilar.

Regards.

To dilute a solution of sodium chloride (NaCl), we can use the following methods: Add more water to the solution and Remove a small amount of the solution and mix it with water.

By adding water, you increase the overall volume of the solution, which effectively reduces the concentration of NaCl. This is the most common and straightforward method of dilution.

By taking out a portion of the concentrated solution and mixing it with water, you decrease the concentration of NaCl in that portion, resulting in overall dilution when you combine it back with the rest of the solution.

By heating the solution, you cause the water to evaporate, leaving behind a more concentrated solution of NaCl. This process does not dilute the solution but rather concentrates it further.

Adding more NaCl to the solution would actually increase the concentration, not dilute it. Therefore, it is not a valid method for dilution.

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Answer:

D.

Explanation:

From the forgoing, we can conclude that the the correct statements are;

The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;

E°cell = 0.0592/n log K

E°cell = cell potential

n = number of electrons

K = equilibrium constant

E°cell = -0.403 - 0.535 = -0.938 V

n = 2 electrons

Thus;

-0.938 =  0.0592/2 logK

-0.938 * 2/ 0.0592 = log K

K = 2 * 10^-31

Also;

ΔG = - nFE°cell

ΔG = - (2 * 96500 *  -0.938)

ΔG = 181kJ/mol

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Answer:

47900 cm

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

0.479 km

Step 2: Identify Conversions

1 km = 1000 m

1 m = 100 cm

Step 3: Convert

\(0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} )\) = 47900. cm

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

47900. cm ≈ 47900 cm

Answer:

77.8 grams of Ca

Explanation:

In an ecosystem, the  impact of soil Science to the development of Ghana's agriculture is that it provides suitable conditions for root germination and growth.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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​

Answer:

133.340538.

Explanation:

The answer is 133.340538. We assume you are converting between grams AlCl3 and mole. You can view more details on each measurement unit: molecular weight of AlCl3 or mol This compound is also known as Aluminium Chloride. The SI base unit for amount of substance is the mole.

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒  \(Mass \ of \ Butane = Density\times Volume\)

On putting the estimated values, we get

⇒                              \(=0.579\times 7.96\)

⇒                              \(=4.60 \ g\)

Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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The mass of the acid produced is 0.252 g from the information in the question.

The term neutralization refers to the reaction between an acid and a base that yileds salt and water only.

The equation of this reaction is; 2HCl + CaCO3 ----->CaCl2 + CO2 + H2O

Number of moles of CaCO3 =   0.350 g/100 g = 0.0035 moles

Since 2 moles of acid reacts with 1 mole of CaCO3

x moles acid reacts with 0.0035 moles of CaCO3

x = 0.007 moles

Mass of acid = 0.007 moles * 36 g/mol = 0.252 g

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Taking into account the definition of density, the density of the piece of metal is 19.213 g/cm³.

Density is the amount of matter in a given space and is defined as the amount of mass of a substance per unit volume.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷volume

Density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

density= 19.5061 g÷1.01 cm³

Solving:

density= 19.213 g/cm³

Finally, the density is 19.213 g/cm³.

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Answer:

A. it should have a cell wall to give it structure

The rate of the vacuum's airflow in L/s, is 70.792 L/s

We'll begin by converting 210 ft³/min to L/min. This can be obtained as follow:

1 ft³/min = 28.3168 L/min

Therefore,

150 ft³/min = 150 × 28.3168

150 ft³/min = 4247.52 L/min

Thus, 150 ft³/min is equivalent to 4247.52 L/min

We can convert 4247.52 L/min to L/s as illustrated below:

60 L/min = 1 L/s

Therefore,

4247.52 L/min = 4247.52 / 60

4247.52 L/min = 70.792 L/s

Thus,

150 ft³/min = 70.792 L/s

The rate of the vacuum's airflow in L/s is 70.792 L/s

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77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

A mole is defined as 6.02214076 ×\(10^{23}\) of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

\(Moles = \frac{mass}{molar \;mass}\)

\(Moles = \frac{5.00g}{180.156 g/mol}\)

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

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Answer:

Magnesium (Mg)

Explanation:

The elements have very similar properties: they are all shiny, silvery-white, somewhat reactive metals at standard temperature and pressure.

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Answer:

The answer is C. Magnesium(Mg)

Pls thank you

3:2

Before we can determine the mole ratio of compounds in a chemical reaction, the reaction must be balanced first.

Given the balanced chemical reactions;

Since the given reaction is balanced, we will determine the number of atom of the calcium hydroxide and aluminium hydroxide in the reaction.

There are 3 moles of calcium hydroxide at the reactant and 2 moles of aluminium hydroxide in the reaction, hence the mole ratio of calcium hydroxide to aluminum hydroxide is 3:2

Answer:

The molar density of any ideal gas at STP is:

1 mol / 22.4 L = 0.04464 mol / L

The molar mass of F2 is: 2(19) = 38 g/mol

0.04464 mol / L * (38 g / mol) = 1.70 g/L

Explanation:

Answer: acid

Explanation:

Answer:

A) Acid

Explanation:

I got the same question and answered correctly

The energy diagram of the given reaction shows that, the activation energy of the reactants is less than that of the products. The transition state is having the highest activation energy.

An endothermic reaction is the reaction in which the reactants will absorb heat energy from the surroundings. The reactants will gain sufficient energy to overcome the barrier potential of the reaction and thereby they have less activation energy.

The given reaction of the decomposition  of hydrogen iodide is an endothermic reaction. Hence, HI has the least activation energy and the products hydrogen gas and iodine gas have the higher activation potential as shown in the diagram.

The activation energy of the transition state is indicated with the central arrow,

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The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:

Isotope N–14 = 99%

Isotope N–15 = 1%

Explanation:

Let isotope A be N-14

Let isotope B be N-15

From the question given above, the following data were obtained:

For isotope A (N-14):

Mass of A = 14

Abundance of A = A%

For isotope B (N-15):

Mass of B = 15

Abundance of B = (100 – A%)%

Atomic mass of nitrogen = 14.01 amu

Thus, we can obtain the relative abundances of the naturally occurring isotopes of nitrogen as illustrated below:

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

14.01 = [(14 × A%)/100] + [(15 × (100 – A%)/100]

14.01 = 0.14A% + 0.15(100 – A%)

14.01 = 0.14A% + 15 – 0.15A%

Collect like terms

14.01 – 15 = 0.14A% – 0.15A%

– 0.99 = – 0.01A%

Divide both side by – 0.01

A% = – 0.99 / –0.01

A% = 99%

Abundance of B = (100 – A%)%

Abundance of B = (100 – 99)%

Abundance of B = 1%

Thus, the relative abundances of the naturally occurring isotopes of nitrogen are:

Isotope N–14 = 99%

Isotope N–15 = 1%

Answer:

2

Explanation:

the level below which the ground is saturated with water.

2

Water Table Examples:

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In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia.  Option 3.

Ammonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.

Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.

Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.

Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.

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Answer:

62.02 g/mol

62.03 g/mol

Explanation:

62.03 g/mol

The molar mass of H2CO3 is 62.02 g/mol

The molar mass of the compound is the sum of molar mass of indivitual atom multiple by number of that atom.

Calculation of molar mass of H2CO3 ,

Molar mass of H2CO3 =  Molar mass of H*2 +  Molar mass of C + Molar mass of O*3

Molar mass of H2CO3 = 1.0079*2 + 12.010 + 15.999*3

Molar mass of H2CO3 = 2.0158 + 12.010 + 47.997

Molar mass of H2CO3 = 62.02 g/mol

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Answer:

Explanation:

From the information given:

The Chemical equation is:

\(SO_2Cl_{2(g)} \iff SO_{2(g)} + Cl_{2(g)}\\\)

since 43.6% of the initial concentration remains at equilibrium

Then; the amount of \(SO_2Cl_2\) that is being reacted is:

= 0.543 × (100 -43.6)%

= 0.306 M

The ICE table can be computed as follows:

           \(SO_2Cl_2\)               ⇔           \(SO_{2(g)\)           +             \(Cl_{2(g)\)

I            0.543                                    0                           0

C          0.306                                 +0.306                     0.306

E           0.237                                  0.306                      0.306

\(K_c = \dfrac{[SO_2] [Cl_{2}]}{[SO_2Cl_2]}\)

\(K_c = \dfrac{0.306 \times 0.306}{0.237}\)

\(K_c = 0.995\)

Thus; the concentration at equilibrium for the species are:

\(SO_2Cl_2\)  = 0.237 M

\(SO_{(2g)\) = 0.306 M

\(Cl_{2(g)\) = 0.306 M

Answer:

4 CO + 8 H2 -> 4 CH3OH

Hope that it works

Explanation:

First, you need to balance the equation:

N2    +  3 H2   ====>    2  NH3

                  so three moles of H2   result in  2 moles of NH3

                               ratio of   3:2

How many moles of NH3 is 36.5 gm  ??

   Using periodic table NH3 mole weight = 14.007  + 3*1.008 =17.031 g/mole

     36.5 g / 17.031 g/mole = 2.14 moles  of NH3

Using the ratios above   3/2 = x / 2.14   shows x = 3.21 moles of H2 needed