You will need to do a comparison for two computers, documenting your findings for both computers on a PowerPoint Presentation-Name of the computer must be
visible, ex. Apple, HB, etc..
You are a fictitious small business owner-you make up the appropriate small business-First slide describes the business and the name-3-4 sentences. You have 1 in your budget to purchase a computer. You may purchase a laptop or desktop. You need the computer for your fictitious small business.
1. What is the operating system?
1. What is the CPU?
:D
2. How much RAM is installed?
3. How large is the hard drive?
4. Are the following applications on the system? What
1. Microsoft Word
Version
2. Microsoft Excel
3 Microsoft Access
4. Microsoft PowerPoint
Version
Versi…

The first law of thermodynamics states that the total energy of a closed system is constant; energy can neither be created nor destroyed, only transformed from one form to another.

This law can be expressed mathematically as:

dU = dQ - dW

Where dU is the change in internal energy, dQ is the heat added to the system, and dW is the work done by the system.

The second law of thermodynamics states that the entropy of a closed system always increases over time, approaching a maximum value at equilibrium. This law can be expressed mathematically as:

dS > 0

Where dS is the change in entropy.

Using these laws, we can write out the combined statements for the energy functions as follows:

For U = U(S, P):

dU = TdS - PdV

For H = H(S, P):

dH = TdS + VdP

For F = F(T, V):

dF = -SdT - PdV

For G = G(T, P):

dG = -SdT + VdP

Where T is the temperature, V is the volume, and S is the entropy.

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Answer:

what's the question?...........

Answer:

max temp = 711.32 k

mini temp = 331.29 k

Explanation:

Given data:

2kg block of Iron : temperature = 600k , C = 0.460 kJ/kgk

3 kg block of copper : temp = 800k ,  C = 0.385 KJ /kgk

10 kg block of granite : temp = 300k , C = 0.790 KJ/kgk

Cp = Cv at constant pressure and constant volume

Determine the minimum temperature that is obtained in any one of the block

considering the heat transfer equation

Q = mC ( T2 - T1 )

attached below is a detailed solution of the problem

The word "picnicking" has Greek origins, derived from the Greek words "pikers" meaning "sharp" or "bitter," and "nēma" meaning "woodland" or "grove." It evolved from the French term "pique-nique" and later became adopted in the English language.

The word "picnicking" originated from the French word "pique-nique," which was borrowed from the English language. However, the term "pique-nique" itself has Greek origins. It is believed to have derived from the Greek words "pikers" meaning "sharp" or "bitter," and "nēma" meaning "woodland" or "grove." This combination of words referred to an outdoor meal or social gathering held in a natural setting, such as a forest or park.

The concept of picnicking as a recreational activity became popular in Europe during the 18th century, and the term gradually spread to other languages, including English. So, although the word "picnicking" has French roots, its ultimate origin can be traced back to Greek elements.

In conclusion, among the given options, "picnicking" has Greek origins, specifically derived from the Greek words for "sharp" and "woodland".

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A). It is generally expected that the laboratory test results will have a higher strength value compared to the field test results. This is because laboratory tests are conducted under controlled conditions with proper equipment and procedures, while field tests are subject to variability and influences from the site conditions such as weather, soil type, and compaction.

B) It is generally expected that the laboratory test results will have a higher strength value compared to the field test results. This is because laboratory tests are conducted under controlled conditions with proper equipment and procedures, while field tests are subject to variability and influences from the site conditions such as weather, soil type, and compaction.

The rationale for the above response is that laboratory tests provide a more accurate representation of rock strength compared to field tests due to the controlled conditions and proper equipment and procedures used in the laboratory.

Thus, laboratory test results are recommended for the foundation design of a dam.

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a. the upper 3-dB frequency (f) of the discrete MOSFET common-source amplifier is approximately 808.65 MHz. b. the midband gain (AM) of the discrete MOSFET common-source amplifier is approximately -3.88.

(a) To find the overall midband gain (AM) of the discrete MOSFET common-source amplifier, we can use the following formula:

AM = -gm * (R || r) * (Rd || RL)

where gm is the transconductance of the MOSFET, R is the resistance connected to the drain, r is the output resistance of the MOSFET, Rd is the internal resistance of the voltage source, and RL is the load resistance.

Given:

gm = 4 mA/V

R = 2 MΩ

r = 100 kΩ

Rd = 500 kΩ

RL = 10 kΩ

We can calculate the parallel combination of resistances (R || r) as follows:

(R || r) = (R * r) / (R + r)

Substituting the given values:

(R || r) = (2 MΩ * 100 kΩ) / (2 MΩ + 100 kΩ) = 98.039 kΩ

Next, we calculate the parallel combination of resistances (Rd || RL) as follows:

(Rd || RL) = (Rd * RL) / (Rd + RL)

Substituting the given values:

(Rd || RL) = (500 kΩ * 10 kΩ) / (500 kΩ + 10 kΩ) = 9.901 kΩ

Now, we can calculate the overall midband gain:

AM = -gm * (R || r) * (Rd || RL)

  = -4 mA/V * 98.039 kΩ * 9.901 kΩ

  ≈ -3.88

Therefore, the overall midband gain (AM) of the discrete MOSFET common-source amplifier is approximately -3.88.

(b) The upper 3-dB frequency (f) can be calculated using the formula:

f = 1 / (2π * (R || r) * C)

where (R || r) is the parallel combination of resistances and C is the capacitance.

Given:

(R || r) = 98.039 kΩ

C = 2 pF

Substituting the given values:

f = 1 / (2π * 98.039 kΩ * 2 pF)

  ≈ 808.65 MHz

Therefore, the upper 3-dB frequency (f) of the discrete MOSFET common-source amplifier is approximately 808.65 MHz.

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Answer:

I = 2 A

Explanation:

Given:

N = 2.5·10¹⁹ electrons

| e | = 1.6·10⁻¹⁹ С  - electron charge modulus

t = 2 s

_______________

I - ?

Charge:

q = N·| e | = 2.5·10¹⁹·1.6·10⁻¹⁹ = 4 С

Current strength:

I = q / t = 4 / 2 = 2 A

The World Wide Web (WWW) is an information system that allows access to resources over the internet, uses URLs to identify websites and documents it stores and imposes standard restrictions on the websites it stores.

Everyone, not just researchers, now has access to the internet thanks to the world wide web. It connected the world in a way that greatly facilitated communication, sharing, and information access. Since then, technology has enabled people to share their ideas and works via blogs, social networking sites, video sharing, and other channels.

By the year 1989, Tim Berners-Lee had created the internet. He was looking for a fresh method for researchers to quickly exchange the results of their tests. Because of the web, this data could be shared across computers that were online.

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Everything you touch is pressed upon by the weighty air that surrounds you. This pressure is referred to as air pressure or atmospheric pressure.

It is the force that the air above a surface applies to it while gravity pulls the surface toward Earth. A barometer is frequently used to measure atmospheric pressure.

A mercury column in a glass tube acts as a barometer, rising or falling in response to variations in the atmosphere's density. By measuring how much the mercury rises, meteorologists can determine the air pressure.

The standard unit of measurement known as one atmosphere (atm) corresponds to the average atmospheric pressure at sea level and 15 degrees Celsius.

Therefore, Everything you touch is pressed upon by the weighty air that surrounds you. This pressure is referred to as air pressure or atmospheric pressure.

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The common characteristic of all material removal mechanisms in non-traditional machining processes is that they use a tool or electrode to remove material from the workpiece.

This can include processes such as laser cutting, electrochemical machining, electrical discharge machining, and waterjet cutting. These processes are often used when conventional machining methods are inadequate or inefficient, and they are able to achieve high levels of precision and accuracy.

The primary mechanism of material removal in Electron Beam Machining (EBM) is through thermal sputtering. This is a process in which incident electrons, accelerated by a high voltage, strike a surface and cause atoms or molecules to be ejected from the surface.

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Answer:

Compressibility.

Explanation:

The compressibility of a fluid can be defined as a measure of the change in volume (density) with respect to the amount of pressure applied to the fluid. Thus, as the pressure of a compressible fluid increases, both its viscosity and density increases.

Some examples of compressible fluids are vapors, gases, air etc.

Hence, compressibility is the property that describes the amount of volume that decreases when pressure is applied to a fluid.

Additionally, the compressibility of fluids plays a significant role in the field of science such as in aerodynamics, fluid mechanics, thermodynamics etc.

Answer:

compressiblity

Explanation:

Answer:

41.015

Explanation:

Solution

Given that:

Th first step to take is to find  the longitudinal stress in the cylinder

σl = PD/4t

P = the pressure

D = the diameter

t = the thickness

Thus,

σl = 1.25 * ^ 6 * 0.45 / 4 * 6 * 10 ^ ⁻3

=23.475Mpa

Now. we find the hoop stress in the cylinder∠

σh = PD/2t

σh = 1.25 * ^ 6 * 0.45/ 2 * 6 * 10 ^ ⁻3

σh  =46.875 Mpa

Then

we find the normal stress in the line of the 30° angle with the longitudinal axis stated below:

σab = σh + σl/2 + ( σh - σl/2) cos 2θ + t sin 2θ

So,

σab  =46.875 + 23.4375/2 + ( 46.875 - 23.4375/2) cos 2(30°) + 0

σab= 41.015

Therefore the normal stress to line A-B is 41.015

Answer:

my friend here justin

Explanation:

hes already taken

The cruise control in your car is a well-known illustration of a closed loop control system. The speed you specify serves as your COMMAND value. Your actual speed is regularly monitored by the vehicle, which is your FEEDBACK.

An open-loop system is a form of control system in which the output has no bearing on or effect on how the input signal is controlled. In order to be considered a "open-loop system," the output signal or condition must not be measured.

A living thing like a person is the ideal illustration of an open system. We actively engage with our surroundings.

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A large fast-moving truck collides with a small stationary car. During the collision the magnitude of force on the truck is greater than the magnitude of force on the car.

When a large, fast-moving truck collides with a small, stationary car, the forces experienced by the two vehicles are unequal. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. The force exerted by the truck on the car is equal in magnitude but opposite in direction to the force exerted by the car on the truck. However, due to the significant difference in mass and size between the truck and the car, the effects of the forces on each vehicle are not the same.

In this scenario, the truck has a much larger mass and momentum than the car. When the collision occurs, the truck transfers some of its momentum to the car, resulting in a change in velocity for both vehicles. The force experienced by the car is relatively smaller compared to the force experienced by the truck due to the car's lower mass. Therefore, the magnitude of force on the truck is greater than the magnitude of force on the car.

It is important to note that the force exerted during a collision depends on various factors, including the masses and velocities of the colliding objects. In cases where the size and mass of the vehicles involved in a collision differ significantly, as in the example given, the force experienced by the smaller object will generally be less than the force experienced by the larger object.

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Answer:

C, D, E

Explanation:

just did it on edge 2020

Answer:

c

d

e

Explanation:

edgunity 2020

performance here's how memory works on apple silicon

For the given network in Figure 15.58, we need to derive an expression for the steady-state input impedance and determine the frequency at which it has the maximum amplitude. The steady-state input impedance is determined by analyzing the circuit components and their frequency-dependent behaviors.

To derive the expression for the steady-state input impedance, we need to analyze the components in the network and their impedance characteristics. The input impedance is typically calculated by considering the series and parallel combinations of resistors, capacitors, and inductors in the circuit. By examining the circuit in Figure 15.58, we can determine the impedance of each component at a given frequency. The impedance of a resistor is simply its resistance, while the impedance of a capacitor and an inductor is frequency-dependent, given by 1/(jωC) and jωL, respectively (where j represents the imaginary unit and ω is the angular frequency). Using the appropriate impedance values for each component, we can determine the overall impedance of the circuit. This involves solving for the equivalent impedance of series and parallel combinations of components. To find the frequency at which the input impedance has maximum amplitude, we need to evaluate the magnitude of the impedance expression at different frequencies. The frequency at which the magnitude is highest corresponds to the frequency with maximum amplitude. In conclusion, by analyzing the circuit components and their impedance characteristics, we can derive the expression for the steady-state input impedance of the network in Figure 15.58. Additionally, by evaluating the magnitude of the impedance expression at different frequencies, we can determine the frequency at which the input impedance has the maximum amplitude.

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Both technicians A and B are partially correct, because it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability. Technician B is also partially correct in that ABS can improve braking performance on loose snow.

Both technicians are partially correct, but neither is entirely accurate.

Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability when the brakes are applied while turning a corner, especially on slippery or uneven road surfaces. The system can prevent the wheels from locking up and skidding, which can cause the vehicle to lose control. However, it's important to note that ABS does not necessarily guarantee superior directional stability in all situations, and the driver should still exercise caution and proper driving techniques when turning.

Technician B is also partially correct in that ABS can improve braking performance on loose snow, as the system can help prevent the wheels from locking up and losing traction. However, other factors such as tire type and condition, road gradient, and vehicle weight distribution can also impact braking performance on loose snow.

Therefore, both technicians are partially correct, but it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.

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Answer:

if you want it to go faster add chain

Explanation:

Answer:

I can help you with your calculation.

To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:

Align the angles so that the degrees, minutes, and seconds are in the same column.

Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.

Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.

Add or subtract the degrees last.

Using this method, your calculation can be done as follows:

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’

Therefore, the answer is 59º27’55.75’’. I hope this helps!

Explanation:

Answer:

a) 2.452

b) 1.256

Explanation:

Stress due to dead weight. = 14 Ksi

Stress due to fully loaded tractor-trailer = 45Ksi

ultimate tensile strength of beam = 76 Ksi

yield strength = 50 Ksi

endurance limit = 38 Ksi

Determine the safety factor for an infinite fatigue life

a) If mean stress on fatigue strength is ignored

β = ( 45 - 14 ) / 2

  = 15.5 Ksi

hence FOS ( factor of safety ) = endurance limit / β

                                                 = 38 / 15.5 = 2.452

b) When mean stress on fatigue strength is considered

β2 = 45 + 14 / 2

    = 29.5 Ksi

Ratio  = β / β2 = 15.5 / 29.5 = 0.5254

Next step: applying Goodman method

Sa =  [ ( 0.5254 * 38 *76 ) / ( 0.5254*76 + 38 ) ]

     = 19.47 Ksi

hence the FOS ( factor of safety ) = Sa / β

                                                      = 19.47 / 15.5 = 1.256

Given:

(a)

According to the question,

→ \(\beta = \frac{45-14}{2}\)

      \(= \frac{31}{2}\)

      \(= 15.5 \ Ksi\)

hence,

The safety factor will be:

= \(\frac{Endurance \ limit}{\beta}\)

= \(\frac{38}{15.5}\)

= \(2.452\)

(b)

→ \(\beta_2 = \frac{45+14}{2}\)

       \(= \frac{59}{2}\)

       \(= 29.5 \ Ksi\)

Ration will be:

= \(\frac{\beta}{\beta_2}\)

= \(\frac{15.5}{29.5}\)

= \(0.5254\)

By applying Goodman method,

→ \(Sa = \frac{0.5254\times 38\times 76}{0.5254\times 76+38}\)

       \(= 19.47 \ Ksi\)

hence,

The safety factor will be:

= \(\frac{Sa}{\beta}\)

= \(\frac{19.47}{15.5}\)

= \(1.256\)

Thus the above response is correct.

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A. R-chart An R-chart, also known as a range chart, is used to track the variability or dispersion of a manufacturing process.

It is commonly used in statistical process control (SPC) to monitor the consistency of a process over time.

In the case of copper tubing production, an R-chart would be suitable for tracking the variability of the tubing's diameter. The chart displays the range (the difference between the largest and smallest values) of a set of samples taken from the manufacturing process. By analyzing the range values, one can assess whether the process is producing tubing with consistent diameter or if there is excessive variability.

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Answer:

Amplifier gain is equal to 10.67.

Explanation:

Voltage gain of an amplifier can be expressed as this equation:

A_v = (V_output) / (V_input)

Where A_v is the gain, V_output is the output voltage, and V_input is the input voltage.

For this we will solve:

A_v = 128 mV / 12 mV

A_v = 10.67

So the amplifier's gain is 10.67.

Cheers.

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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Answer:

Printing press , lenses etc,

Explanation:

Almost all of the Renaissance innovations that influenced the world, printing press was one of them. The printing press is widely regarded as the Renaissance's most significant innovation. The press was invented by Johannes Gutenberg, and Germany's culture was altered forever.

Astrophysics, humanist psychology, the printed word, vernacular vocabulary of poetry, drawing, and sculpture practice are only a few of the Renaissance's main inventions.

To determine the convective and radiative heat fluxes to the wall at x = 0, we can use the following equations:

1. Convective heat flux:

q_conv = h * (T_s - T_∞)

2. Radiative heat flux:

q_rad = α * σ * (T_s^4 - T_∞^4)

where:

Given:

T_∞ = 20°C

T_sur = 40°C

h = 20 W/(m²·K)

α = 0.78

T_s = 24°C

Let's calculate the convective and radiative heat fluxes:

1. Convective heat flux:

q_conv = 20 * (24 - 20) = 80 W/m²

2. Radiative heat flux:

q_rad = 0.78 * 5.67 × 10^-8 * ((24 + 273.15)^4 - (20 + 273.15)^4) = 238.17 W/m²

Therefore, the convective heat flux to the wall at x = 0 is 80 W/m², and the radiative heat flux is 238.17 W/m².

In this scenario, the one-dimensional plane wall is exposed to both convective and radiative heat transfer. The convective heat transfer occurs due to the temperature difference between the surface of the wall (T_s) and the surrounding ambient temperature (T_∞), which is characterized by the convective heat transfer coefficient (h). The convective heat flux represents the amount of heat transferred per unit area through convection.

The radiative heat transfer, on the other hand, occurs due to the temperature difference and the emissivity/absorptivity of the wall's exposed surface (α). The radiative heat flux depends on the Stefan-Boltzmann constant (σ) and the fourth power of the temperatures involved (T_s and T_∞). The emissivity/absorptivity of the surface determines how efficiently it radiates and absorbs thermal radiation.

In this case, since the surroundings are considered "large," we assume that the temperature of the surroundings (T_sur) remains constant and unaffected by the wall's heat transfer. This assumption simplifies the analysis by focusing only on the heat exchange between the wall and the ambient environment.

By applying the equations for convective and radiative heat fluxes, we can calculate the respective contributions to the total heat transfer at the wall's exposed surface.

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Fermat's theorem can be used to find a number x between 0 and 28 that satisfies the congruence x^85 ≡ 6 (mod 29). By applying the theorem, we can simplify the calculation and determine the value of x without resorting to brute-force searching.

Fermat's theorem states that if p is a prime number and a is an integer not divisible by p, then a^(p-1) ≡ 1 (mod p). In this case, the prime number is 29. We can rewrite the congruence x^85 ≡ 6 (mod 29) as x^(283+1) ≡ 6 (mod 29), which implies that x^(283) * x ≡ 6 (mod 29).

Using Fermat's theorem, we know that x^(28*3) ≡ 1 (mod 29), since 29 is a prime number. Therefore, the congruence simplifies to 1 * x ≡ 6 (mod 29), which gives us x ≡ 6 (mod 29).

To find the value of x within the range of 0 to 28, we can observe that 6 + 29 = 35 is a multiple of 29. Thus, x = 35 satisfies the congruence. However, since we are looking for a value between 0 and 28, we subtract multiples of 29 from 35 until we find a value within the desired range. In this case, 35 - 29 = 6, so x = 6 is the solution that satisfies x^85 ≡ 6 (mod 29) within the given constraints.

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