Answer:
...............,........................
Question 2 (1 point)
What happens to the number of waves when you change the light from green to red?
Increase
decrease
remain the same
there are zero waves
When you change the light from green to red, the number of waves remains the same.
Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.
The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.
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Unit 1 Horizontal Kinematics Homework #3 Acceleration 1. A bowling ball starts from rest and moves 300 m down the gutter in 22.4 seconds. a) What is its speed at the end of the track? b) What is its acceleration?
Answer:
Explanation:
since the object start its motion from rest and ends its motion at 300 m so
ΔS=S2-S1=300m-0m=300 m
given time is 22.4 sec therefore
v=ΔS/t
v=300/22.4=14.7 m/s
so the speed of the ball at the end of the track is 14.7 m/s
now to find the acceleration we know that
a=v/t
a=14.7/2.4
a=0.65m/sec²
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Think about how geothermal energy is captured and used. Explain how geothermal energy shows the flow of thermal energy from hot to cold or cold to hot.
Answer:
People can capture geothermal energy through: Geothermal power plants, which use heat from deep inside the Earth to generate steam to make electricity. Geothermal heat pumps, which tap into heat close to the Earth's surface to heat water or provide heat for buildings
When the weather is cold, the water or refrigerant heats up as it travels through the part of the loop that's buried underground. Once it gets back above ground, the warmed water or refrigerant transfers heat into the building. The water or refrigerant cools down after its heat is transferred.
what is the force when ur pulling heavy furniture that wont budge
Answer:
Gravity? is it multiple choice?
did thomson conclude from his experiment ?
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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What causes an object to slowdown or speed up
Answer:
A force can speed up or slow down an object. A force can change the direction in which an object is moving. A bigger force on an object will produce a bigger change in the motion. A heavier object requires a larger force than a lighter object in order to undergo the same change in motion.
How can you measure the strength of a force?
for 14 points
The strength of a force can be measured by using a force sensor or a spring scale. These instruments measure force in units of newtons (N) or pounds (lbs). The amount of deflection or extension of the spring is directly proportional to the force applied. The force can also be measured indirectly by measuring its effect on an object, such as the acceleration of an object under the influence of the force, using Newton's second law of motion.
when a fixed amount of ideal gas goes through thermal expansion what happens to internal energy
Answer:
A) its internal (thermal) energy does not change.
Explanation:
When a fixed amount of ideal gas goes through an isothermal expansion
A circuit is made up of a moving magnet, a wire coil, a battery, and
conducting wires. Which item is not required for the circuit to produce an
electric current?
A. The moving magnet
B. The battery
C. The conducting wires
O D. The wire coil
Answer:
the battery
Explanation:
I tried D and got it incorrect it said it was the battery
The battery is not required for the circuit to produce an electric current.
What is circuit?An electronic circuit is composed of individual electronic components, such as resistors, transistors, capacitors, inductors and diodes, connected by conductive wires or traces through which electric current can flow.
What is moving magnet?The magnet moves when a current flows through the coil or else movement of the magnet generates a current.
What is conducting wires?Conducting wire is a metal conductor that carries electricity over a distance.
Hence, the battery is the correct option for given question.
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Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct?
We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.
Who is a geologist?A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.
Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.
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The complete question is that:
Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)
A. The rock display with smaller holes shows copper drilling, which is deep underground.
B. The rock display with larger holes shows petroleum drilling, which is deep underground.
C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.
D. The rock display with larger holes shows copper drilling, which is closer to the surface.
For the purpose of calculating the electric field strength by means of Gauss’s law, determine whether approximate cylindrical symmetry holds in each of the following situations.
Part (a) We have a 3.6-m long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (b) We have a 8.9-cm long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from rod near its center.
TRUE FALSE
Part (c) A 1.9-m long wooden rod is glued end-to-end to a 1.9-m long plastic rod, both of radius 1 cm. The combined rod is then painted with an electrically charged paint so that it is covered with a uniform charge density, giving it total charge of 1.5 nC. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (d) For the same charged rod as in part (c) we want to calculate the electric field strength at a point 8.9 m from each end of the rod.
TRUE FALSE
Answer:
1. True
2. False
3. True
4. False
Explanation:
a) In this case, length of the copper rod is 3.6 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.
b) In this case, length of the copper rod is 8.9 cm which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.
c) In this case, length of the copper rod is 3.8 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.
d) In this case, length of the copper rod is 3.6 m which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.
Which best explains why an MRI is useful for diagnosing cancer but ineffective in treating it?
The frequency of the radio waves used is so high that the waves cannot be used to target specific cells.
The wavelength of the radio waves used is so short that the waves cannot be used to target specific cells.
The amount of energy carried by radio waves is enough to provide images but not enough to kill cells.
The amount of energy carried by radio waves is so high that it provides images but can also damage cells.
Answer:The amount of energy carried by radio waves is enough to provide images but not enough to kill cells.
Explanation:
The reason of MRI should be useful is that the energy amount that should be carried out via the radio waves.
What is Magnetic resonance imaging (MRI) ?It refers to the medical imaging technique that should be applied in the radiology to create the pictures with respect to the anatomy and the process of physiological with related to the body.
Also, it is applied for strong the magnetic field, gradient related to the magnetic field, also the radios waves for produce image in the body organs.
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A visible light has a wavelength of 727.3 nm. Determine its frequency, energy per photon, and color.
Answer:
\(f=4.12\times 10^{14}\ Hz\) and \(E=2.73\times 10^{-19}\ J\)
Explanation:
The wavelength of a visible light is 727.3 nm.
\(727.3\ nm=727.3 \times 10^{-9}\ m\)
The formula is as follows :
\(c=f\lambda\)
f is the frequency of the visible light
\(f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{727.3 \times 10^{-9}}\\\\f=4.12\times 10^{14}\ Hz\)
Energy of a photon is given by :
E = hf, h is Planck's constant
\(E=6.63\times 10^{-34}\times 4.12\times 10^{14}\\\\E=2.73\times 10^{-19}\ J\)
Red color has a frequency of \(4.12\times 10^{14}\ Hz\) and energy per photon is \(2.73\times 10^{-19}\ J\).
An electron enters a magnetic field of with a velocity perpendicular to the direction of the field. At what frequency does the electron traverse a circular path
Answer:
A) 2.1 × 1010 Hz
Explanation:
I think this is the answer you're looking for but it may change depending on mass and charge of electron. Hope this helps :)
11.15 in the circuit of fig. 11.46, find the value of zl that will absorb the maximum power and the value of the maximum power.
The value of x =3.
What is value?Value is regard that something is held to deserve the important worth or usefullness of something .
In ∆ ABC
<A= <B=<C
Triangle is equilibrium triangle.
All the triangle side will be equal
6x-3=3x+6=5x
=6x-3 =3x+6
=3x=g
X=3
Thus, X = 3
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A hot air balloon contained a large volume of air with a density of 0.0013 g/mL. After opening up the burner for an extended period of time, the air began to substantially heat up. Consequently, the spaces between the air particles became greater and the volume of the air in the balloon increased by 5%. If the mass of the air stayed pretty-much the same, what would be the density of the heated air in the balloon?
Answer: The density of the heated air in the balloon would be 0.00124 g/mL.
Explanation: The density of a substance is defined as its mass per unit volume. If the mass of the air in the balloon remained unchanged, but its volume increased by 5%, then the density of the air must have decreased by 5%. This means that the density of the heated air in the balloon would be 0.0013 g/mL * (1 - 0.05) = 0.00124 g/mL.
(a ) A 14 turns circular coil is placed on a paper which lies in 1.2 T magnetic field pointing inwards to the paper. The coil's diameter changes from 22.5 cm to 7.2 cm in 1.8 s.
(i) Determine the direction of the induced current. .
(ii) Calculate the magnitude of the emf induced in the circuit.
(iii) Calculate the induced current if the circular coil resistance is 7.5 Ω
(b) A circular coil of N turns with current 9.4 mA has an inductance 15 mH. Calculate
(i) magnetic flux linkage through the coil. (ii) radius of the coil if N = 420 turns.
(i) The direction of the current will be in opposite direction to the magnetic field.
(ii) The magnitude of the emf induced in the circuit is 0.359 V.
(iii) The induced current if the circular coil is 0.048 A.
b(i) The magnetic flux linkage through the coil is 1.41 x 10⁻⁴ Tm².
b(ii) The radius of the coil is r√3 m.
Direction of the currentThe direction of the current will be in opposite direction to the magnetic field.
Emf induced in the circuitInitial area of the coil = (πd²)/4
Initial area of the coil = (π x 0.225²)/4 = 0.0398 m²
Final area of the coil = (π x 0.072²)/4 = 0.001296 m²
\(emf = \frac{NB(A_1 - A_2)}{t} \\\\emf = \frac{14 \times 1.2(0.0398 - 0.001296)}{1.8} \\\\emf = 0.359 \ V\)
Induced currentI = emf/R
I = 0.359/7.5
I = 0.048 A
Magnetic flux linkage through the coilФ = LI
Ф = 0.015 x 0.0094
Ф = 1.41 x 10⁻⁴ Tm²
Radius of the coil\(L = \frac{\mu_o N^2\pi r^2}{l} \\\\r^2 = \frac{Ll}{\mu_o N^2\pi } \\\\r = \sqrt{\frac{Ll}{\mu_o N^2\pi } } \\\\r = \sqrt{\frac{0.015(l)}{4\pi\times 10^{-7} \times (420)^2 \pi } } \\\\r = 3 \sqrt{l} \ m\)
where;
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What is the mass of a block of lead that is 30cm by 80cm by 60cm?
Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.
The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.
So, the mass of the block of lead is approximately 1.63 metric tons.
A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal velocity of 7.2 m/s.] How far does it move horizontally in this time
Answer:
Explanation:
Assuming negligible air resistance, the horizontal velocity of the shingle will remain constant and the vertical motion will be influenced by gravity.
We can use the kinematic equations of motion to determine the horizontal distance traveled by the shingle. The relevant equation is:
d = v * t
where d is the distance, v is the initial horizontal velocity, and t is the time of flight.
To find the time of flight, we can use the equation for the vertical displacement of an object under constant acceleration:
y = v0t + (1/2)at^2
where y is the vertical displacement, v0 is the initial vertical velocity (which is zero), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight. Solving for t, we get:
t = sqrt((2y)/a)
where sqrt means square root.
Substituting the given values, we have:
y = 9.4 m
a = -9.8 m/s^2
t = sqrt((2*9.4 m) / -9.8 m/s^2) = 1.45 s (using the positive root since time cannot be negative)
Now, we can use the horizontal velocity to find the distance traveled in this time:
d = v * t = 7.2 m/s * 1.45 s = 10.44 m
Therefore, the shingle moves a horizontal distance of 10.44 meters in this time.
Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?
Before they were decommissioned, the NASA space shuttles required two solid rocket boosters (SRBs) to launch the shuttle from Earth’s surface. Both SRBs produced 1.7 x10^7 N at liftoff. The combined mass of a shuttle and rocket boosters was about 1.5 x 10^ 6 kga) Calculate the net acceleration of a space shuttle and rockets at the time of liftoff. (b) Calculate the speed of the shuttle and rockets after 10.0 s.
Given:
The force on the booster is
\(F=\text{ 1.7}\times10^7\text{ N}\)The mass is
\(m=\text{ 1.5}\times10^6\text{ kg}\)Required:
(a) The net acceleration
(b) Speed of the shuttle and rockets after time t = 10 s
Explanation:
(a) The net acceleration can be calculated as
\(\begin{gathered} a=\frac{F}{m} \\ =\frac{1.7\times10^7}{1.5\times10^6} \\ =11.33\text{ m/s}^2 \end{gathered}\)(b)
The initial speed of the rocket and shuttle will be zero.
The speed of the rocket and shuttle after time t = 10 s will be
\(\begin{gathered} v=0\text{ m/s + 11.33}\times10 \\ =\text{ 113.3 m/s} \end{gathered}\)Final Answer:
(a) The net acceleration is 11.33 m/s^2.
(b) The speed of the rocket and shuttle is 113.3 m/s
A massage technique that consists of applying pressure to specific points of the face and body to release muscle tension, stimulate and restore balance (chi) is known as
Answer:Acupressure
.
.
..
But why post this question in Physics
In a certain lab experiment, a spring gun was placed on a table and fired a steel ball horizontally outward. A student determines that the ball starts 1.0 m above the floor and travels 2.7 m before striking the floor
In a certain lab experiment, a spring gun was placed on a table and fired a steel ball horizontally outward. A student determines that the ball starts 1.0 m above the floor and travels 2.7 m before striking the floor.
(a) Determine the time that the ball is in the air. (2 pts)
(b) Determine the initial velocity of the ball. (2 pts)
a) The time that the ball is in the air is 0.23 second.
b) The initial horizontal velocity of the ball is 11.74 m/s.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction.
Vertical height of the point = 1.0 meter.
The horizontal distance travelled by the ball = 2.7 m.
a) The time that the ball is in the air is = √(H/2g)
= √(1.0/2×9.8)
= 0.23 second
b) The initial horizontal velocity of the ball is = 2.7 m/0.23 s
= 11.74 m/s
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Replace the incandescent bulb with the Voltage meter and return loop # to 3. What happens when you move the bar magnet back-n-forth through the loop? Does this appear to be creating a Direct Current or an Alternating Current? How do you know?
If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.
What is magnet?A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.
Here,
The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.
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An object is placed 40 mm away from a diverging lens with a focal length of 10 cm. Find the object distance and determine whether the image is upright or inverted and real or virtual.
The distance between the object and a diverging lens is -20 cm and the image is virtual and inverted.
How to calculate object's distance?The object distance for this scenario is 40 mm, as given in the problem statement.
To determine the image properties, we need to use lens equation which is 1/f = 1/u + 1/v where f is the focal length, u is the object distance and v is the image distance.
Using the given information, the lens equation can be written as:
1/10 = 1/40 + 1/v
Solving for v, we get:
v = -20 cm
As the image distance is negative, it means that the image is virtual and inverted.
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Particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC are in a line. Particles q1 and q2 are separated by 0.876m and particles q2 and q3 are separated by 0.432m. What is the net force on particle q3?
The net force on q3 due to q1 and q2 is \(-13.76 * 10^{-3} N\).
Electrostatic force is the fundamental force between charged particles. The electrostatic force is responsible for many phenomena in our daily life, from the attractive force between a magnet and a metal object to the lightning that occurs during a thunderstorm. We can calculate the net force between charged particles using Coulomb's law. In this question, we have three particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC, which are separated by distances r1 = 0.876m and r2 = 0.432m. The electrostatic force on q3 due to q1 and q2 can be calculated by using the formula: \(F13 = k q_1 q_3 / r_1^2 + k q_2 q_3 / r_2^2\), where k is the Coulomb's constant \(k = 9 * 10^9 N m^2 / C^2\). Plugging in the given values of q1, q2, q3, r1, r2, and k in the above formula, we can calculate the electrostatic force on q3 due to q1 and q2.F13 = (9 x 10^9) (-75.8 x 10^-6) (-84.2 x 10^-6) / (0.876)^2 + (9 x 10^9) (90.6 x 10^-6) (-84.2 x 10^-6) / (0.432)^2F13 = \(-13.76 * 10^{-3} N\). The negative sign indicates that the force is attractive and is directed towards q1 and q2. Therefore, the net force on q3 is given by the vector sum of the forces on q3 due to q1 and q2. Since the forces are collinear, we can add them algebraically. Fnet = F13 Fnet = \(-13.76 * 10^{-3} N\)The net force on q3 due to q1 and q2 is -13.76 x 10^-3 N. The negative sign indicates that the force is attractive and is directed towards q1 and q2.For more questions on net force
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List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.
Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust
What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:
What are the issues that should be addressed?
What are the relevant facts and data related to this problem or issue?
What assumptions am I making about the problem or issue?
What are the possible solutions or outcomes, and what are the pros and cons of each?
What are my values and priorities related to this problem or issue?
What additional information do I need to make an informed decision or come to a reasonable conclusion?
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You jump off a platform 134 m above the Neuse River. After you have free-fallen for the first 40 m, the bungee cord attached to your ankles starts to stretch. You continue to descend another 80 m before coming to rest. Assume that your mass is 100 kg. What is your acceleration when you are momentarily at rest at the lowest point in the jump
Answer:
The acceleration at lowest point is 19.62 m/s^2
Explanation:
Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.
Lets Assume
Constant of string is K
By using the conservation of energy we will have the following equation
1/2 x 80^2 x K = m x 9.81 x 120
3200 K = 1177.2 m
K = 1177.2 m / 3200
K = 0.368 m
At the lowest point we will have
a = ( K x X - m x g ) / m
a = ( 0.368 m x 80 - m x 9.81 ) / m
a = 19.62 m / s^2
So, the acceleration at lowest point is 19.62 m/s^2
The acceleration at lowest point is \(\bold { 19.62\ m / s^2}\), when someone momentarily at rest.
Fom the conservation of energy equation,
\(\bold {\dfrac 12 \times 80^2 \times K = m \times 9.81 \times 120}\\\\\bold {3200 K = 1177.2\times m}\\\\\bold {K = \dfrac {1177.2\times m}{ 3200}}\\\\\bold {K = 0.368 m}\)
At the lowest point
\(\bold {a =\dfrac { K\times X - m \times g ) }{ m}}\\\\\bold {a =\dfrac { 0.368 m \times 80 - m \times 9.81 } m}\\\\\bold {a = 19.62\ m / s^2}\)
Therefore, the acceleration at lowest point is \(\bold { 19.62\ m / s^2}\).
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