Answers
The initial velocity at which the ball was tossed up, u=30.0 m/s
The acceleration due to gravity, g=-9.8 m/s².
The negative sign of the acceleration due to gravity is because that it is in the opposite direction of the direction of motion of the ball.
When the ball reaches the top it stops and then starts to travel towards the down. Thus, when the ball reaches the top its velocity i.e., its final velocity is v=0 m/s
From the equation of the motion,
\(v=u+gt\)Where t is the time duration in which the ball reaches the top.
On rearranging the above equation,
\(t=\frac{v-u}{g}\)On substituting the known values in the above equation,
\(t=\frac{0-30.0}{-9.8}=3.06\text{ s}\)Therefore it will take 3.06 seconds for the ball to reach the top.
Related Questions
An athlete training for an event does 6.53 104 J of work during a workout and gives off 5.97 105 J of heat. Consider the athlete to be like a heat engine. (a) Determine the magnitude of the change in internal energy of the athlete. J (b) What is the efficiency of the athlete
Answers
Answer:
(a) The magnitude of the change in internal energy is 6.623 x 10⁵ J
(b) the efficiency of the athlete is 10.94 %
Explanation:
Given;
work done by the athlete (system), W = 6.53 x 10⁴ J
the heat given off by the athlete (system), Q = 5.97 x 10⁵ J
The simple diagram below will be used to illustrate the direction of the energy flow assuming a heat engine.
Q← ⊕ →W
The work, W, points away from the system since the system does the work
The heat, Q, points away from the system since heat is given off
Apply first law of thermodynamic;
ΔU = Q + W
where;
q is the heat flowing into or out of the system
(+q if the heat is flowing into the system
(-q if the heat is leaving the system
w is the work done by or on the system
(+w if the work is done on the system by the surrounding
(-w if the work is done by the system to the surrounding
Thus, from the above explanation, the change in internal energy of the system is calculated as;
ΔU = -Q - W
ΔU = - 5.97 x 10⁵ J - 6.53 x 10⁴ J
ΔU = -6.623 x 10⁵ J
The magnitude of the change in internal energy = 6.623 x 10⁵ J
(b) the efficiency of the athlete;
\(Efficiency = \frac{W}{Q} \times 100\%\\\\Efficiency = \frac{6.53 \times 10^4}{5.97 \times 10^5} \times 100\%\\\\Efficiency = 10.94 \ \%\)
pls help need it last question on my test
Answers
The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.
Friction is a force that opposes motion between two surfaces in contact.
In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.
As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.
Friction is a resistance force that opposes motion.
It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.
When the car is moving, there is friction between the two surfaces.
The direction of the friction force is opposite to the direction of motion of the car.
This means that the friction force slows the car down.
In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.
The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
For more questions on force
https://brainly.com/question/30762901
#SPJ8
What ideas do you have about what determines how currents like this move?
Answers
Which of the vectors in the graph below is the negative of the vector v?
Answers
Answer:
D
Explanation:
Answer:
A. D
Explanation:
Part B
A roller coaster ride starts with the roller coaster car being pulled to the top of the first hill with pulley system. The car is
released from the top with an initial velocity close to zero, then accelerates downward. From that first hill, the roller coaster just
coasts; there is no driving force, other than gravity, to keep It going. Assuming no friction, what can you say about the height of
the other hills in the roller coaster ride?
Answers
The highest point of a roller coaster is almost always the first hill. In the majority of roller coasters, the hills get smaller as the train travels down the track.
To find the answer, we have to know more about the mechanical energy of a system.
How to find the answer?Since it influences the mechanical energy of the system, the first hill must be the highest.One of the fundamental tenets of physics is that, in the absence of friction, mechanical energy must be conserved. Mechanical energy is the product of kinetic energy and potential energy.When the vehicles ascend the first hill on the roller coaster, mechanical energy is provided to the system because the speed is zero at this point.Mechanical energy = U = mgh
Where m represents the car mass, g represents gravity, and h represents height
If the system is to continue moving, the other hills on the mountain must be lower than the first hill. When the vehicles are released, this energy is converted into kinetic and potential energy when it lowers and ascends, but the sum of these two cannot be larger than the starting energy.Finally, by applying the principle of energy conservation, we may determine that, the initial hill must be the highest.
Learn more about the mechanical energy here:
https://brainly.com/question/1674514
#SPJ1
Unbalanced forces have no change in motion and ______ equal zero
just need the answer that fills the blank space plsss
Answers
Answer
due to balanced forces, an object in motion cannot change its direction or speed, and also the net forces act a zero in balanced forces.
Explanation:
Unbalanced forces have a change in motion and they have a resultant force in a direction. Whereas, a balanced force does not change in direction and the resultant force is zero.
What is force?Force is an external agent acting on a body to make it changed in its state of motion or rest or to deform it. There are various kinds of forces such as magnetic force, nuclear force, gravitational force, frictional force etc.
If there are two or more forces acting on a body from the same direction, then the net force will be the sum of all the forces. If the two forces are equal in magnitude and if act from the opposite directions they will cancel each other and will not make a displacement. Such forces are called balanced forces.
The imbalance in force on a body is made by the change in direction or in magnitude of the forces. Then there will be a net force and will make the body a change in its motion.
To find more on forces, refer here:
https://brainly.com/question/26115859
#SPJ2
You are sitting on a Ferris wheel moving at a constant speed of 8 m/s. When you are at the bottom of the rotation, what is the normal force of the seat on you if you have a mass of 50 kg and the radius of the Ferris wheel is 10 m
Answers
Answer:
40NExplanation:
Formula for calculating normal force is expressed as:
\(F = ma\\since \ a = \frac{v^2}{r} \\F = \frac{mv^2}{r}\)
m is the mass of the body = 50kg
v is the velocity of the Ferris wheel = 8m/s
r is the radius of the Ferris wheel
Substitute into the formula:
\(F = \frac{50 \times 8}{10}\\ F = \frac{400}{10}\\ F = 40N\\\)
Hence the normal force of the seat is 40N
Psi(x) = (alpha/pi) ^ (1/4) * e ^ (- (alpha * x ^ 2)/2)
Find wave function
1- p*2 =
2- x =
3- X*2 =
Answers
The wave function can be obtained by taking the square root of the probability density function. In this case, the probability density function is given by:
Psi(x) = (alpha/pi)^(1/4) * e^(-(alpha * x^2)/2)
So the wave function is:
phi(x) = sqrt(Psi(x)) = sqrt((alpha/pi)^(1/4) * e^(-(alpha * x^2)/2))
We can simplify this expression by using the fact that the square root of a product is equal to the product of the square roots:
phi(x) = sqrt(alpha/pi)^(1/4) * sqrt(e^(-(alpha * x^2)/2))
phi(x) = (alpha/pi)^(1/8) * e^(-(alpha * x^2)/4)
Therefore, the wave function is:
phi(x) = (alpha/pi)^(1/8) * e^(-(alpha * x^2)/4)
Now, to answer the other questions:
To find p^2, we need to square the wave function:
phi(x)^2 = ((alpha/pi)^(1/8) * e^(-(alpha * x^2)/4))^2
phi(x)^2 = (alpha/pi)^(1/4) * e^(-(alpha * x^2)/2)
So p^2 is (alpha/pi)^(1/4) * e^(-(alpha * x^2)/2).
The variable x is already given in the function Psi(x). It represents the position of a particle in one dimension.
To find X^2, we need to use the operator for the position squared:
X^2 = x^2
So X^2 is simply x squared, which in this case would be:
X^2 = x^2
Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?
Answers
Answer:
The difference between the positions of the two events as measured in = 3.53 *10^8 m/s
Explanation:
As we know -
\(\Delta x = -\gamma \mu\Delta t\)
Here,
\(\Delta x\) is the difference between the positions of the two events as measured in S^
\(\gamma\) \(= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }\)
And
\(\mu\) = 0.547 c
Substituting the given values in above equation, we get -
\(\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8\)meter per second
When it comes to fitness, at the end of the day the most important thing is
Answers
Answer:
Getting a good rest
Explanation:
How much force must be applied to push a 1.35 kg book across the desk at constant speed if the coefficient of sliding friction is 0.30?
Answers
The magnitude of the force that must be applied to push the book across the desk is 3.97 N.
The given parameters;
mass, m = 1.35 kgcoefficient of friction, μ = 0.3The acceleration of the book across the desk is calculated as follows;
a = μg
where;
g is acceleration due to gravitya = 0.3 x 9.8
a = 2.94 m/s²
The magnitude of the force that must be applied is calculated as follows;
F = ma
F = 1.35 x 2.94
F = 3.97 N
Thus, the magnitude of the force that must be applied to push the book across the desk is 3.97 N.
Learn more about applied force here:https://brainly.com/question/2733221
Assume the three blocks (m1 = 1.0 kg, m2 = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below move on a frictionless surface and a force F = 34 N acts as shown on the 4.0-kg block. Answer parts a-c.
Answers
(a) The acceleration of the system is 8.5 m/s².
(b) The tension in the cord connecting the 4.0 kg and 1.0 kg blocks is 42.5 N.
(c) The force exerted by the 1.0 kg block on the 2.0 kg block is 59.5 N.
To solve this problem, we can use Newton's second law of motion (F = ma) and consider the forces acting on each block individually.
(a) Determine the acceleration given this system:
To find the acceleration (a) of the system, we can use the net force acting on the 4.0 kg block (m3). The only force acting on m3 is the applied force (F = 34 N).
F = m3 * a
34 N = 4.0 kg * a
Solving for a, we find:
a = 34 N / 4.0 kg
a = 8.5 m/s²
Therefore, the acceleration of the system is 8.5 m/s².
(b) Determine the tension in the cord connecting the 4.0-kg and the 1.0-kg blocks:
To find the tension in the cord (T), we can consider the forces acting on the 1.0 kg block (m1).
T - F = m1 * a
T - 34 N = 1.0 kg * 8.5 m/s²
T - 34 N = 8.5 N
T = 42.5 N
Therefore, the tension in the cord connecting the 4.0 kg and 1.0 kg blocks is 42.5 N.
(c) Determine the force exerted by the 1.0-kg block on the 2.0-kg block:
To find the force exerted by the 1.0 kg block (m1) on the 2.0 kg block (m2), we can consider the forces acting on the 2.0 kg block.
F - T = m2 * a
F - 42.5 N = 2.0 kg * 8.5 m/s²
F - 42.5 N = 17 N
F = 59.5 N
Therefore, the force exerted by the 1.0 kg block on the 2.0 kg block is 59.5 N.
for more questions on acceleration
https://brainly.com/question/460763
#SPJ8
An object weighing 75 N is dropped from the top of a building and falls a distance of 28 m to the ground. How much work does gravity do on the object from the time it is dropped to the time it hits the ground?
Answers
Given , the weight is 75N I.e force
And displacement is 28 m
We know that ,
Work done = Force x displacement
So , now W = 75 x 28 = 2100 Joules
Hope this helps you dear :)
Have a good day <3
Step-by-step equation:
A phone with a mass of 0.2 kg is dropped from a height of 30 m what is it’s speed when it hits the ground?the acceleration of gravity is 9.8ms
Answers
Answer:
24.2 m/s
Explanation:
Mass is irrelevant in this situation....
Displacement: ( to find time)
x = xo + vo t - 1/2 at^2
30= 0 + 0 - 1/2 (9.8)t^2
t = 2.47 seconds
Velocity:
vf = a t = 9.8 (2.473) = 24.2 m/s
A car accelerates from rest to 28 m/s in 3.5 seconds. What’s the acceleration
Answers
Acceleration = change in speed, over time
(0-28)/3.5
8m/s
In an air - standard Carnot cycle, heat is transferred to the working fluid at 1150 K, and heat is rejected at 300 K. The heat transfer to the working fluid at 1150 K is 120 kj/kg. The maximum pressure in the cycle P, is 16.5 MPa. Assuming constant specific heat of air, determine the cycle efficiency and pressure at different points of cycle.
Answers
Answer:
Explanation:
From the given information:
The efficiency can be calculated by using the formula:
\(E= 1 - (\dfrac{T_2}{T_1}) \\ \\ \\ E = 1- (\dfrac{300}{1150}) \\ \\ \\ =0.739\)
Using the isothermal condition, the process from state 1 → 2 is as follows:
Heat transferred Q₁ = 120 kJ/kg
Workdone W₁ = 120 kJ/kg
However, \(W_1 = (R_{air} \times T_1 ) In( \dfrac{P_1}{P_2}) ---(1)\)
If the equation is rewritten, we can have the following:
\(In (\dfrac{P_1}{P_2}) = \dfrac{120}{(0.287 \times 1150)} \\ \\ In (\dfrac{P_1}{P_2}) = 0.364\)
By solving the above equation;
\(P_2 = 11.471 MPa\)
However, at state 2 → 3, there is an adiabatic process.
Thus,
\(P_2^{1-\gamma} T_2^{\gamma} = P_3^{1-\gamma} T_3^{\gamma}\)
Specific heat rate is denoted by \(\gamma\)
Thus,
\(P_3 = P_2\Big ( \dfrac{T_2}{T_3}\Big)^\dfrac{\gamma}{1-\gamma}}\)
Thus;
recall that:
\(\dfrac{\gamma}{1-\gamma}} = \dfrac{1.4}{1-1.4} \\ \\ = \dfrac{1.4}{-0.4} \\ \\ = -3.5\)
Thus,
\(P_3 = \dfrac{11.471 }{(\dfrac{1150}{300})^{-3.5}} \\ \\ = 0.104 \ MPa\)
Finally from state 4 - state 1, we have an isentropic or adiabatic process;
As such:
\(P_2^{1-\gamma} T_2^{\gamma} = P_4^{1-\gamma} T_4^{\gamma}\)
Thus,
\(P_4 = P_1(\dfrac{T_1 }{T_4})^{\dfrac{\gamma}{1-\gamma}}\)
\(P_4 = \dfrac{16.5 \ MPa }{(\dfrac{1150}{300})^{-3.5}} \\ \\ = 0.15 \ MPa\)
A ballast bag is dropped from a balloon that is 300 m above the ground and rising at 13 m/s. For the bag, find (a) the maximum height reached, (b) its position and velocity 5.0 s after it is released, and (c) the time at which it hits the ground.
Answers
308.6 m the maximum height reached.
Define velocity
The main determinant of an object's location and rate of motion is its velocity. It can be explained as the distance an object travels in one measure of time. The displacement of the item in a given amount of time is referred to as velocity.
The distance a person travels in a predetermined amount of time is referred to as speed.
Vi is the starting speed.
Vf is final speed
A=acceleration and Y=displacement
When the bag is freed, its Vi equals that of a balloon traveling at 13 m/s upward.
At the moment of release, choose up as positive y=0.
Vf=0 when it is maximum. Using the equation 2Vf=2Vi+2ay,
0=(13m/s)2+2(9.81m/s2)y, and y=8.6m
300 + 8.6 = 308.6 m is the highest point.
To learn more about velocity use:
https://brainly.com/question/80295?source=archive
#SPJ1
light of wavelength 485 nm passes through a single slit of width 8.32 *10^-6m. what is the single between the first (m=1) and second (m=2) interference minima?
Answers
Answer:
3.35
Explanation:
Got it on Acellus
The light of wavelength 485 nm passes through a single slit. The single between the first (m=1) and second (m=2) interference minima is 3.36°.
What is diffraction?Diffraction is the phenomenon of bending of waves through obstacles.
Given is the wavelength λ= 485 nm, silt width d = 8.32 *10⁻⁶ m, then the angle θ will be
d sinθ =mλ
for m=1, sin θ₁ = λ/d
for m=2, sin θ₂ = 2λ/d
Substitute the values into both expressions to find the angles,
sin θ₁ = 485 x 10⁻⁹ / 8.32 *10⁻⁶
θ₁ = 3.34°
and sin θ₂ = (2 x 485 x 10⁻⁹ )/ 8.32 *10⁻⁶
θ₂ = 6.7°
The angle between m =1 and m=2 will be
θ₂ -θ₁ = 6.7° - 3.34° =3.36°
Thus, angle between the first (m=1) and second (m=2) interference minima is 3.36°.
Learn more about diffraction.
https://brainly.com/question/12290582
#SPJ2
Multiply 2.594 kg and 23.4 cm/s according to the rules of significant figures. What is the answer in kg*cm/s and kg*m/s?
Answers
The multiplication of the given decimals in kg*cm/s and kg*m/s to 3 significant figures are 60.7kg.cm/s and 0.607kg.m/s respectively.
What is the answer in kg*cm/s and kg*m/s?Given that;
a = 2.594 kgb = 23.4 cm/sMultiplication = ?a × b = ?
2.594kg × 23.4cm/s
= 60.6996kg.cm/s
= 60.7kg.cm/s ( 3 significant figures )
a = 2.594 kgb = 23.4 cm/s = ( 23.4/100)m/s = 0.234m/sMultiplication = ?
a × b = ?
2.594kg × 0.234m/s
= 0.606996kg.m/s
= 0.607kg.m/s ( 3 significant figures )
The multiplication of the given decimals in kg*cm/s and kg*m/s to 3 significant figures are 60.7kg.cm/s and 0.607kg.m/s respectively.
Learn about multiplication here: https://brainly.com/question/14059007
#SPJ1
Р.ЗА.3
7. Which behavior does the picture show?:
A. The wave speed is decreasing
B. The amplitude increases
Answers
Answer:
b. the amplitude increases
Explanation:
because that's not wave
A hot air balloon traveled 3 hours at a speed of of 450 km/hr. What distance did it travel?
Answers
Answer:
it traveled 1350 kilometers or 839 miles
Explanation:
You just have to do 450 times three because its 3 HOURS and 450 kilometers per HOUR.
If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'
Answers
Answer: Distance traveled in time t is s
Explanation: Self Explanatory
Find the terminal velocity of a sphere that has a mass of 600g and a radius of 30cm. Take the density of air 1.2 kg/m^3 . Report the speed in mph.
Answers
The terminal velocity of the sphere is approximately 22.68 mph.
The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:
Fd = (1/2) * rho * Cd * A * v²
where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.
The gravitational force pulling the sphere down is given by:
Fg = m * g
where m is the mass of the sphere and g is the acceleration due to gravity.
At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:
Fd = Fg
Substituting the expressions for Fd and Fg and solving for v, we get:
v = √((2 * m * g) / (rho * Cd * A))
where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.
Plugging in the given values, we get:
v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s
To convert this to mph, we multiply by 2.23694:
v ≈ 22.68 mph
To know more about terminal velocity, here
brainly.com/question/2654450
#SPJ1
It is useful to use a _________ to demonstrate how an electric circuit works
Answers
It is useful to use a model in order to demonstrate how an electric circuit works.
What is a model?In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.
For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.
The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.
In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.
Learn more about scientific models here:
https://brainly.com/question/13134745
#SPJ1
Đoạn dây dẫn thẳng có dòng điện I chạy qua, đặt trong từ trường
đều và vuông góc với các đường sức từ. Lực từ tác dụng lên đoạn dây
có phương
Answers
A straight piece of wire with a current I flowing through it is placed in a magnetic field
A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the string
A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the stringthere is a way
What is the symbol for a variable resistor?A. Horizontal wireB. 2 parallel wiresC. Line with a zig zag pattern with a diagonal line drawn across itD. Circle with an X through it
Answers
The symbol for a variable resistor is a line with a zig zag pattern with a diagonal line drawn across it; therefore the answer is C
A pitot tube (the figure) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes B (four are shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the U-tube is connected to hole A at the front end of the device, which points in the direction the plane is headed. At A the air becomes stagnant so that VA = 0, At B, however, the speed of the air presumably equals the airspeed B of the plane. Use Bernoulli's equation to derive a formula giving the air speed in terms of the difference h in the liquid levels in that tube, the density rho of the liquid in the U-tube, and the density of air Pair. Suppose that the tube contains alcohol and the level difference h is 34.0 cm. What is the plane's speed relative to the air? The density of the air is 1.14 kg/m3 and that of alcohol is 810 kg/m3. Air Hole A Liquid Number Units
Answers
The plane's speed relative to the air is 63.3m/s.
What is relative speed?
When two or more bodies (objects) travel at the same or different speeds in the same or different directions, the concept of relative speed is applied. As a result, relative speed can be defined as a concept that calculates the speed of one moving body in relation to another moving body traveling at the same speed.
For example, if two people are running in opposite directions, the relative speed of one of them to the other stationary body can be calculated because the bodies are moving in opposite directions at the same time. Thus, relative speed can be defined as the speed of a moving body in relation to another stationary body.
The difference between the bodies is calculated while calculating the relative speed of bodies moving in the same direction.) Bernoulli's equation gives p A =p b+ 1 ρ air v²
2
However, △=p A −p B =ρgh
in order to balance the pressure in the two arms of the U-tube.
Thus ρgh= 1 ρ air v²
2
, or v = √2ρgh
√ ρ air
(b) The plane's speed relative to the air is
v= ρ air 2ρgh =√2(810kg/m 3 )(9.8m/s 2 )(0.260m) =63.3m/s
√ 1.03kg/m³
Hence, the plane's speed relative to the air is 63.3m/s.
To know more about relative speed from given link
brainly.com/question/17228388
#SPJ4
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
Know more about potential energy here:
https://brainly.com/question/21175118
#SPJ8
An object with a kinetic energy of 250j has a mass of 32 kg what is the velocity of the object?
Answers
Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Velocity of the objectIn this case, you know:
Ec= 250 Jm= 32 kgv= ?Replacing in the definition of kinetic energy:
250 J = 1/2× 32 kg×v²
Solving:
250 J÷ (1/2× 32 kg) = v²
15.625 J÷kg = v²
√15.625 J÷kg = v
3.95 m/s² = v
Finally, the velocity of the object is 3.95 m/s².
Learn more about kinetic energy:
brainly.com/question/17809741
#SPJ1
What might Earth be like if it had never been hit by the theoretical protoplanet Orpheus?
Answers
Answer:
If Earth hadn't been hit by Orpheus, it would be covered by ocean, with perhaps a few mountaintops emerging through the water. There would be no humans, but there could be other forms of life. Earth would rotate rapidly, as the moon would not be present to produce the tidal friction that slows Earth's rotation today