You need to get to class, 300 meters away, and you arrive in 1 minute. What speed were you walking? (calculate in meters per second).​

Answers

Answer 1
5 meters per second. 300 / 60(seconds)

Related Questions

L= 1 H and R = 3.9 KQ. V (w) Vi (w) b) Sketch the magnitude of the frequency response function H(w). c) Determine what type of ideal filter is approximated by this circuit. a) Find H (w) = + vi(t) L R + vo(t)

Answers

The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.

L = 1 H (inductance)

R = 3.9 KΩ (resistance)

The circuit can be represented by the following equation:

H(w) = (jwL + R) / (jwL + R + 1)

To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.

Taking the magnitude of the transfer function, we have:

|H(w)| = |(jwL + R) / (jwL + R + 1)|

Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.

From the transfer function:

H(w) = (jwL + R) / (jwL + R + 1)

As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:

H(w) ≈ jwL / jwL = 1

This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.

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Watch the motion of the protists at 100x and 400x. What structures allow each protist to move?.

Answers

Structures allow each protist to move is Amoeba: pseudopodia,Euglena: flagellum,Paramecium:

The membrane encloses the cytoplasm and organelles of an amoeba cell. Ameoba have a single pseudopod that they employ for locomotion and navigation. To maintain osmotic balance, each amoeba possesses one or more nuclei and a simple contractile vacuole. Vacuoles are where the amoeba stores and digests the food it has swallowed. A protist is something like amoebas. They are not fungi, animals, or plants, despite the fact that each of their cells contains a nucleus. The majority of amoebas are so tiny that a microscope is required to observe them. Most scientists advise using a 100x overall magnification to view amoebas. As a result, you would see an image that was 100 times larger than the amoeba itself.

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A student examined a patch of mud and recorded several statements about footprints in the mud. Which statement is most likely an inference? A. There are ve footprints in the mud B. The depth of the deepest footprint is 3 centimeters C. The footprints were made by a dog D. The footprints are oriented in an east-west direction

Answers

Answer:

C

C. The footprints were made by a dog.

The student may have noticed specific characteristics or features in the footprints that lead them to believe that they were made by a dog.

Hence, the correct option is C.

An inference is a conclusion or deduction based on evidence or observations. It involves making an educated guess or interpretation about something that may not be explicitly stated.

Out of the provided options, the most likely inference is The footprints were made by a dog.

This statement is an inference because it involves making a conclusion based on the observed footprints in the mud. The student may have noticed specific characteristics or features in the footprints that lead them to believe that they were made by a dog.

However, this inference might not be a definite conclusion, as there could be other animals or factors that create similar-looking footprints in the mud.

Therefore, The student may have noticed specific characteristics or features in the footprints that lead them to believe that they were made by a dog.

Hence, the correct option is C.

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In a population of ground beetles, a genetic locus that codes for setae on the elytra has two variants: G is dominant and codes for setae on the elytra, and g is recessive and codes for glabrous elytra (no setae). If the frequency of beetles with glabrous elytra is 0.36, what is the frequency of the G allele, assuming the population is in Hardy-Weinberg equilibrium? Show all your calculations. (5 pts) a. 0.6 b. 0.4 C. 0.64 d. 0.16 e. none of the above

Answers

The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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How does your collected data help you to see if you meet your criteria for success

Answers

Collected data plays a crucial role in evaluating whether the criteria for success have been met. By analyzing the collected data, one can assess the progress made towards achieving the desired goals and determine if the criteria have been fulfilled.

Data provides an objective measure of performance or outcomes, allowing for an evidence-based assessment of success. It helps to quantify and track key metrics or indicators related to the criteria for success. By comparing the actual data with the predetermined benchmarks or targets, one can determine if the criteria have been met or if further improvements are required.

Data analysis also enables the identification of trends, patterns, and correlations, providing insights into the factors influencing success. It helps in identifying areas of strength and areas that need improvement. Additionally, data can be used for comparative analysis, benchmarking against previous periods or similar projects, to gain a broader perspective on success.

In summary, collected data provides an objective basis for evaluating progress and success by comparing actual performance against predetermined criteria, identifying areas of improvement, and gaining insights for future decision-making.

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In a nuclear reactor, electricity is produced from

Answers

Answer:

Nuclear reactors are the heart of a nuclear power plant. They contain and control nuclear chain reactions that produce heat through a physical process called fission. That heat is used to make steam that spins a turbine to create electricity

~+lil more info!+~

What material is used to power a nuclear reactor?

uranium !

All commercial power reactors are based on nuclear fission. They generally use uranium and its product plutonium as nuclear fuel, though a thorium fuel cycle is also possible.

Water can be thought to be made up of millions of tiny little particles. These tiny particles are constantly moving. At higher temperatures, particles have more energy and they move faster. Given below is water at different temperatures. In which one will the particles of water be moving the fastest?

(1 Point)

a. Water at 25°

b. Water at 60°

c. Ice

d. steam

Answers

The particles of water will be moving the fastest in steam. Steam is the gaseous form of water, which occurs at temperatures above 100 degrees Celsius (212 degrees Fahrenheit). In this state, the water molecules have the highest amount of energy, and they move rapidly and freely in all directions.

When water is heated and reaches its boiling point, the energy supplied to the molecules causes them to overcome the attractive forces between them, leading to the transition from a liquid to a gas. As steam, the water molecules have gained enough energy to break free from the liquid phase and exist as individual molecules in the gaseous state.

On the other hand, at lower temperatures, such as 25 degrees Celsius (77 degrees Fahrenheit), water is in its liquid state. While the particles still possess kinetic energy and are in constant motion, their movement is comparatively slower than in steam. The intermolecular forces in the liquid state are stronger than in the gaseous state, allowing the molecules to stay closer together and move more sluggishly.

Ice, which is water in its solid state, has the slowest particle movement among the given options. At temperatures below 0 degrees Celsius (32 degrees Fahrenheit), the water molecules form a rigid lattice structure, and their movement is restricted to vibrations in fixed positions. The particles in ice have the least amount of energy and exhibit the least mobility.

Therefore, considering the given options, steam is the state of water where the particles are moving the fastest due to the high temperatures and increased molecular energy.

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which planets are in the habitable zone? ​

which planets are in the habitable zone?

Answers

planets

Explanation:

kelper-174dkelper-443 bFlies 876 c16 Cygnus Bb

A cart with mass 2m has a velocity v before it strikes another cart of mass 3m at rest. The two carts couple and move off together with a velocity of?

Answers

Answer:

2/5 v

Explanation:

Use conservation of momentum

originally    mv = 2m v

  after the crash   mv is still the same (2mv)

        but the mass is now   5m x      where x is the new velocity

                   2mv = 5 mx

                  x = 2/5 v

                   

The momentum of two objects in a collision is conserved. Hence, the total initial momentum is equal to the final momentum of the coupled mass. Here the final velocity will then be 2/5 v.

What is momentum ?

Momentum of a moving object is the product of mass and velocity. It is a vector quantity with direction and magnitude. The total momentum of two colliding bodies is equal to the total final momentum after collision.

Let m1 and m2 be the masses and v1 and v2 be the final velocities. Vt be the velocity of the coupled mass.

Then, m1 v1 + m2 v2 = (m1 + m2) Vt

Given, mass of cart 1 = 2m

cart 2 = 3m

velocity of cart 1 = v

cart = 0 since it was at rest.

Then, 2m v + 0 = (2m + 3m) Vt

Vt = 2/5 v

Therefore, the final velocity of the couple of carts will be 2/5 v.

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Suppose a particle moves along a straight line with velocity meters per second after seconds.

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Many meters will a particle have traveled after t seconds if it is moving in a straight line at a velocity of v(t)=t2e2t meters per second?

What are velocity and speed?

In contrast to velocity, which describes the speed and direction of such an object's movement, speed is the rate of movement along a path. Alternatively, velocities is a vector while speed is just a scalar quantity.

Why is there a velocity formula?

Velocity (v), which can be expressed by the expression v = s/t, is still a tensor quantity that determines dislocation (or the shift in position, s), over change in time (t).

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A delivery truck travels 21 blocks north, 15 blocks east, and 27 blocks south.

Part A

What is its final displacement from the origin (magnitude)? Assume the blocks are equal length. Express your answer as an integer.

Part B

What is its final displacement from the origin (direction)? Express your answer using three significant figures.

Answers

Part A
Here, we have to find out the final displacement from the origin. In order to find the displacement, we have to find out the net distance travelled by the delivery truck.

First we will find the total distance covered in the north and south direction:21 blocks north, 27 blocks southSo, the net distance travelled in north-south direction = (21-27) blocks = -6 blocksNow, we will find the total distance covered in the east and west direction: 15 blocks east.

So, the net distance travelled in east-west direction = 15 blocks Net distance travelled = √(6² + 15²) ≈ 16 blocks. So, the final displacement from the origin (magnitude) is 16 blocks.

Part B

To find the final displacement from the origin (direction), we have to find the direction of the displacement. Here, the delivery truck travels 21 blocks north, 15 blocks east, and 27 blocks south.

So, the displacement vector has two components, i.e. one in north-south direction and another in east-west direction. Net displacement in east-west direction = 15 blocksAnd, net displacement in north-south direction = -6 blocks

Therefore, the angle of the displacement vector with the east direction can be found as shown below:θ = tan-1((-6)/15)≈ -22.6°The angle is negative because the vector is in the opposite direction to the east direction. Therefore, the final displacement from the origin (direction) is 23° west of the north direction (approximate to three significant figures).

Magnitude : The simple definition of magnitude is "distance or quantity." In the sense of motion, it depicts the absolute or relative direction or size of an object's movement. It is used to convey something's size or scope. In material science, extent by and large alludes to distance or amount.

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a toy car is wound up and released on the floor. it accelerates at a rate of 0.4 m/s/s . the mass of the care is 3kg. what is the force that the cars wheels exert on the floor.

Answers

Answer:

1.2N

Explanation:

f=m×a

m=3kg

a=.4m/s/s

3×.4=1.2

kg×m/s/s = N

on a deep sea fishing trip, captain c-bo knows that each of his passengers will catch red snapper at a rate of 2 fish per hour.

Answers

Captain C-Bo takes his passengers on a deep-sea fishing trip where he expects them to catch red snappers at a rate of two fish per hour. Deep-sea fishing is done in areas of the ocean that are over 30 meters deep, where there are several types of fish, including red snapper.

The red snapper is a common catch in deep-sea fishing trips as it's a popular and delicious fish. It's found in deep waters from 30 feet to 200 feet in depth, typically near the bottom, and can weigh up to 40 pounds. Red snapper is a popular catch in deep-sea fishing, and because of its popularity, the fishing industry has developed specific rules and regulations to protect it and ensure it's sustainably fished.

In deep-sea fishing, the passengers use a fishing rod and bait to catch fish. The captain knows that each passenger will catch red snapper at a rate of two fish per hour. Thus, if there are 10 passengers on the boat, they would catch 20 fish per hour. If the trip lasts for four hours, each passenger will have caught eight fish. If the trip lasts for eight hours, each passenger will have caught 16 fish.

Thus, it's essential to understand the duration of the fishing trip to determine the catch. In conclusion, on a deep-sea fishing trip, passengers can expect to catch red snapper. If there are 10 passengers, they will catch 20 fish per hour, with each passenger catching two fish. The duration of the trip will determine the overall catch.

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What is the work done in lifting 60 kg of blocks to a height of 20m

Answers

Answer:

The answer is 1200

Explanation:

A charged acrylic rod is brought close to a pith ball. The pith ball attracted to the rod, makes contact, and is then repelled by the red. This an example of
A) grounding
B) static discharge
C) induction
D) conduction
E) none of the above

Answers

Answer:

It is induction

A charged acrylic rod is brought close to a pith ball. The pith ball attracted to the rod, makes contact,

Convert 100°c into Faherenite and kelvin in steps.​

Answers

Answer:

100°c = 373.15 K

100°C=212°F

Explanation:

Given the 100°C

To convert Celsius to Kelvin, we need the following equation.

°C + 273.15 = K

100°C + 273.15 = K

373.15 = K

Therefore, 100°c = 373.15 K

Celsius To Fahrenhite:

F = 9/5C + 32

   =9/5(100)+32

  = (180) + 32

  = 212°

Therefore,

100°C=212°F

Asap
1. In the news yesterday, an airplane’s engine blew apart while in the air. Using what we have learned about forces
and Newton’s Laws of motion, explain, why parts of the engine fell to the ground but the airplane was able to land
safely on the ground

2. Using the acceleration due to gravity, 9.8 m/s2, and what you know about motion. Determine the speed at which an
object that falls from the sky for 1.25 minutes will have when it hits the ground. Neglect air resistance

3. A bird flies north with a speed of 8.5 m/s, for 10 minutes. Determine the distance of the bird’s flight

4. A dog can run with an average speed of 5.5 m/s. Determine how much time the dog will take to travel 1.5 miles

Answers

His third law states that in nature, for every action (force), there is an equal and opposite reaction. When object A applies a force to object B, object B applies an equal and opposite force to object A. In other words, forces are the result of interactions.

What is newton second law of motion ?

Newton's first law of motion predicts the behavior of objects whose forces are all balanced. The first law, also known as the law of inertia, states that if the forces acting on an object are balanced, the object's acceleration is 0 m/s. Objects in equilibrium (the state in which all forces are equal) will not accelerate. Newton stated that an object will only accelerate if it is subjected to a net or unbalanced force. An object will accelerate in the presence of an unbalanced force, changing its speed, direction, or both speed and direction.

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The true power used or consumed in a purely capacitive circuit is zero watts. (T/F)

Answers

The given statement "The true power used or consumed in a purely capacitive circuit is zero watts" is True.

In a purely capacitive circuit, the power used or consumed is zero watts. This is because a capacitor stores energy in an electric field rather than converting it into another form of energy, such as heat or light.

When a capacitor is connected to an AC power source, it charges and discharges in a cycle, but the current flowing through the capacitor is 90 degrees out of phase with the voltage across it.

This means that the power delivered to the capacitor at any given moment is proportional to the product of the voltage and the current,

but the product of the voltage and current is zero at every moment because they are out of phase. Therefore, the average power consumed by the capacitor over one cycle is zero.

Although the power consumed by a purely capacitive circuit is zero, the circuit still plays an important role in electronics.

Capacitors can be used to filter out unwanted noise in electronic signals, store charge in electronic devices, and help regulate the voltage in power supplies.

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a force that is at rest or moves in at a constant speed and in a constant direction is called a what force

Answers

The question is fishing for "balanced force".

But the description in the question is terrible.

What is work done in physics?

Answers

Answer:

work done is the product of force and distance moved in the direction of a force

Answer:

work is said to be done when an energy or force is used.

Explanation:

when you carry a cement and you take a step, work is done.

A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. Friction is not negligible.

Answers

A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.

How does tension force work?

The force transmitted through a rope, string, or wire while opposing forces pull it is referred to as the tension force.

Energy is drawn equally from both ends by the tension force, which is exerted along the entire length of the wire.

A box is being dragged across the floor at a constant speed by a horizontally pulling rope. Friction has a big impact.

As a result, the weight W, normal force N, and tension force T in the string will all be acting on the box.

Your question is incomplete but most probably your full question was

A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. identify all the forces acting on the box.

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A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. Friction

a van exerts a force on trailers of different masses m. compared with the force exerted on each trailer, rank the magnitude of force each trailer exerts on the van. (or are all pairs of forces equal in magnitude?)

Answers

The trailer pulls on the vehicle with an average force of A=B=C.

Newton's second law of acceleration is expressed as follows: F = ma

In this case, the mass is m, and the acceleration is a.

Assume that g=9.8 m/s2 represents the acceleration caused by gravity.

The acceleration of the object will be zero if it is travelling at a constant speed.

Because of the constant velocity, the van's net force on the trailer is therefore zero.

As a result, the van applies the same amount of force to each trailer. Thus, FA FB = FC.

As a result, each trailer pulls on the van with the same amount of force in the opposite direction. FA' = FB' = Fc', therefore.

As a result, A=B=C represents the rank of the force the trailer exerts on the van.

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The D & J Fruit Farm pays pickers $0.50 per pound to pick blueberries. The
berries are packed in pint baskets and sold to grocery stores for $1.15 per
pint. How many pint baskets are needed for 300 pounds of berries?

Answers

Answer:

.36

Explanation:

:)

Answer:

.36

Explanation:

A particular Carnot heat engine has two reservoirs held at different temperatures of 230 K and 2310 K. Which of the following engines have the same efficiency as this enginea) 230 K and 2310 Kb) 690 K and 4620 Kc) 690 K and 6930 Kd) 240 K and 2320 Ke) 2310 K and 230 K

Answers

Therefore, the engines with the same efficiency as the Carnot heat engine with reservoirs at 230 K and 2310 K are engines a) 230 K and 2310 K and e) 2310 K and 230 K.

To determine which of the given engines has the same efficiency as the Carnot heat engine with reservoirs at temperatures of 230 K and 2310 K, we first need to calculate the efficiency of this engine using the Carnot efficiency formula:
Efficiency = 1 - (T_cold / T_hot)
For the given engine:
Efficiency = 1 - (230 K / 2310 K)

Now let's calculate the efficiencies of the other engines:
a) 230 K and 2310 K
Efficiency = 1 - (230 / 2310)

b) 690 K and 4620 K
Efficiency = 1 - (690 / 4620)

c) 690 K and 6930 K
Efficiency = 1 - (690 / 6930)

d) 240 K and 2320 K
Efficiency = 1 - (240 / 2320)

e) 2310 K and 230 K
Efficiency = 1 - (230 / 2310)
Now, compare the efficiencies of these engines to the original engine. The engines with the same efficiency as the original engine will have the same values in the above calculations. From the calculations, we can see that engines a) and e) have the same efficiency as the original engine.

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A digital audio compact disc (CD) carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies 0.6 mm of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of 1.30 m/s. Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of 2.30 cm, and (b) at the end of the record-ing, where the spiral has a radius of 5.80 cm. (c) A full-length recording lasts for 74 min, 33 s. Find the average angular acceleration of the disc. (d) Assuming the acceleration is con-stant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.

Answers

(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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write any two conditoons at which a body of certain mass become weightless

Answers

A body of a certain mass could become weightless in the following two conditions:

1. In microgravity

2. In neutral buoyancy

Cheers,

qxxi

As a red of recent weather activity, there’s less water available for human consumption. Which blome is affected by the most by this change?

Answers

Answer:

The freshwater biome will be most likely to be affected by the weather conditions as the freshwater reservoirs accumulates water from sources like rain, flood and melting of snow. The reservoirs form are groundwater, river, lakes, ponds and others. In the absence of rain the water will not be accumulated in the biome and will effect the life forms living there.

Explanation:

How thermal energy is transferred throughout the water

Answers

Answer:

Explanation: Thermal energy is transferred through water by conduction, convection, and radiation. Conduction occurs when heat is transferred through direct contact between water molecules with different thermal energy. Convection occurs when warmer water rises to the top and cooler water sinks to the bottom, creating a circular motion that distributes heat. Radiation is the transfer of energy through electromagnetic waves, but it is not significant in water due to poor conduction. The specific mechanism that dominates heat transfer depends on various factors such as temperature gradient, depth, and presence of other materials.

Help me please! i will give brainliest i need it done i know its easy but i have a lot of work to do

Help me please! i will give brainliest i need it done i know its easy but i have a lot of work to do

Answers

Answer:

Down below :)

Explanation:

1. Solid - A

2. Liquid - C

3. Gas - E

4. Melting - G

5. Evaporation - F

6. Condensation - D

7. Freezing - B

Hope it is right!

Answer:

See below

Explanation:

We know the 3 (basic) states, solid, liquid, and gas.

We know that the higher the temperature (amount of heat energy) in an object, the more "spread out" particles will be, and as such the object will go from solid to liquid to gas.

So,

A is a Solid (1)

B is Freezing (7)

C is a Liquid (2)

D is Condensation (6)

E is a Gas (3)

F is Evaporating (5)

G is Melting (4)

what are someone of the sources of errors in the ohm's law experiment​

Answers

Common sources of error include instrumental, environmental, procedural, and human. All of these errors can be either random or systematic depending on how they affect the results.
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