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As shown in the figure below, Clara rushes 30 m toward her truck. She notices she forgot her donut and returns
back to the house. Her total travel time is 120 s.
30 m
30 m
What is Clara's average velocity over the 120 s period?

The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

The electric field is calculated as follows;

E = kq/r²

where;

midpoint of 3.08 m, x = 1.54 mm

r(1.54 mm, 2.00 mm)

|r| = √(1.54² + 2²)

|r| = 2.52 mm

E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²

E = 5.287 X 10¹³ N/C

Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

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Answer:

plane on edge

Explanation:

Answer:

Energy = 12000 [kw*h]

Explanation:

In order to solve this problem, we must multiply the power used by the amount of time in use.

\(Energy = Power*time\\Energy = 1500*8\\Energy = 12000 [kW*h]\)

A) There are 3.70 x 10¹⁶ Cs nuclei present initially and B) There are 2.27 x 10¹⁵ Cs nuclei present 2.6 min later.

A) To solve this problem, we can use the following equation,

\(N = N'2^{\frac{-t}{T_{1/2}}}\)), number of Cs nuclei present is N, initial number of Cs nuclei present is N', elapsed time is t, half-life of Cs-124 is T½. First, we need to convert the initial mass of Cs-124 to the number of nuclei present,

7.5 μg Cs-124(1g/10⁶μg)(6.022x10²³nuclei/1g)

= 4.52 x 10¹⁵ Cs-124 nuclei.

Using the equation above, we can find the number of Cs-124 nuclei present after 0 s,

\(N = 4.52 * 10^{15} * 2^{\frac{-0}{30.8}}}\)

= 4.52 x 10¹⁵ Cs-124 nuclei

Therefore, initially, there are 4.52 x 10¹⁵ Cs-124 nuclei present.

B) After 2.6 min (156 s), we can again use the same radioactivity equation to find the number of Cs-124 nuclei present,

\(N = 4.52 * 10^{15} * 2^{\frac{-156}{30.8}}}\)

N = 1.60 x 10¹⁴ Cs-124 nuclei

Therefore, 2.6 min later, there are 1.60 x 10¹⁴ Cs-124 nuclei present.

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The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

Recall the definition of the cross product with respect to the unit vectors:

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)

Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have

a × b = (8i + j - 2k) × (5i - 3j + k)

a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)

… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)

… … … … + 8 (i × k) + (j × k) - 2 (k × k)

a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)

a × b = - 5k - 10j - 24k - 6i - 8j + i

a × b = -5i - 18j - 29k

Answer:

Explanation:

If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​

Answer:

56.55 m/s

Explanation:

Frequency=1/T

1/6 = 0.1666666

V=(2*pi*1.5)/0.166666

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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P(W) = E(J) / t(s)

50/25=2

A) Baby's vertical velocity when Johnny releases her is 12.5 m/s upward. B) Assuming Baby's center of gravity was 1.5 m above the floor when Johnny released her, she will reach a peak height of approximately 1.87 m above her initial height.

A) To find Baby's vertical velocity when Johnny releases her, we can use the equation:

F = ma

where F is the force applied to Baby, m is her mass, and a is her acceleration. Since Johnny exerts a vertical force of 500 N for 1.0 s, we can calculate the acceleration:

a = F/m = 500 N / 40 kg = 12.5 m/s²

We also know that Baby starts from rest, so we can use the equation:

v = u + at

where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration, and t is the time interval during which the force is applied. In this case, t is 1.0 s, so we have:

v = 0 + (12.5 m/s²)(1.0 s) = 12.5 m/s upward

Therefore, Baby's vertical velocity when Johnny releases her is 12.5 m/s upward.

B) To find the peak height Baby will reach, we can use the equation:

h = ut + 0.5a*t²

where h is the vertical displacement (or peak height), u is the initial velocity (which is 12.5 m/s upward), t is the time interval during which Baby is in the air, and a is the acceleration due to gravity (-9.8 m/s^2).

To find the time Baby is in the air, we can use the fact that the upward and downward portions of her motion take equal time:

t = 2u/a = 2(12.5 m/s)/(9.8 m/s²) = 2.55 s

Using this value of t, we can find the peak height:

h = (12.5 m/s)(2.55 s) + 0.5*(-9.8 m/s²)*(2.55 s)² + 1.5 m

h = 19.68 m + 33.26 m + 1.5 m = 54.44 m

However, this answer doesn't make sense in the context of the problem, since Baby would have been thrown far above the ceiling. It's likely that the question meant to give a different height for Baby's center of gravity. Assuming that Baby's center of gravity was actually 1.5 m above the floor when Johnny released her, we can calculate the peak height as follows:

h = (12.5 m/s)(2.55 s) + 0.5*(-9.8 m/s^2)*(2.55 s)² + 1.5 m + 1.5 m

h = 19.68 m + 33.26 m + 3 m = 55.94 m

Therefore, Baby will reach a peak height of approximately 1.87 m above her initial height.

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Answer:

a homogeneous mixture

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer: read this hope this helped

Explanation: A hypothesis is a possible explanation for a set of observations or an answer to a scientific question. ... The next step in the scientific method is to test the hypothesis by designing an experiment. This includes creating a list of materials and a procedure— a step-by-step explanation of how to conduct the experiment.

Answer:

See below

Explanation:

Fg = G m1 m2 / r^2        Fg = force of gravity   and

               G, the gravitational constant =   6.6743x10^-11   m^3/(kg s^2)

m2 = 2 m1   is given, then sub in the values:

2.63 x 10^-12 = 6.6743 x 10^-11 ( m1)(2 m1) / ( .032)^2

results in 2 m1^2 = .00004035059

then m1 = .004491 kg      and m2 is twice this much

mass 1 = 4.49 x 10^-3 kg     as you stated

Answer:

I think hes cool

Explanation:

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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The formula for determining the gravitational potential energy of the balloon is expressed as

Energy = mgh

where

m is the mass of the ballon

g is the accelaration due to gravity and the value is 9.8m/s^2

h is the height of the balloon above the ground

From the information given,

m = 371

h = 615

Thus,

= 371 x 89.8 x615 = 22316017 NKJoulesJoules8298.651

Answer:

The Big Bang Theory is the leading explanation about how the universe began. At its simplest, it says the universe as we know it started with a small singularity, then inflated over the next 13.8 billion years to the cosmos that we know today.

Explanation: Hope this help! :)

Answer:

0.47 J

Explanation:

5/4 m/s^{2} would be its new acceleration .

What is centrifugal acceleration ?

The simplest case of circular motion is uniform circular motion, where an object moves in a circular trajectory with constant velocity. Note that the linear velocity of an object in circular motion is constantly changing because, unlike velocity, it is constantly changing direction. From kinematics we know that acceleration is a change in velocity, either in magnitude or direction, or both. Therefore, an object in uniform circular motion will always be accelerated even if the magnitude of its velocity is constant. You can feel this acceleration every time you get in the car while cornering. Keeping the handle steady while turning and moving at a constant speed creates a smooth circular motion. What you will notice is a feeling of skidding (or skidding depending on speed) out of the center of the turn.

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(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.

(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;

Fg = Gm₁m₂ / R²

where;

The acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.

Force on the rock;

F = mg

where;

F = 6.6 kg x 9.8 m/s²

F = 64.68 N

The force on the pebble;

F = mg

F = 5.6 x 10⁻⁴  x 9.8

F = 5.488 x 10⁻³ N

Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

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Answer:

A

Explanation:

hope this helps

Answer:

The electric field is given by 4.5 N/C.

Explanation:

Charge density = 80 nC/m3

inner radius, r' = 1 mm

outer radius, r'' = 3 mm

distance,  r = 4 mm

The linear charge density is given by

\(\lambda =\rho \times\pi\times (r''^2 - r'^2)\\\\\lambda = 80\times 10^{-9}\times 3.14\times 10^{-6}\times(9-1)\\\\\lambda = 2\times 10^{-12}\\\)

The electric field is given by

\(E = \frac{\lambda }{4\pi\varepsilon_or}\\E=\frac{9\times 10^9\times 2 \times 10^{-12}}{0.004}\\\\E=4.5 N/C\)

Answer:

what do the lines look like

Answer:

Force of gravity, F = 70 N      

Explanation:

It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.

The force of gravity is equal to the weight of an object. It is given by :

\(F=mg\)

g = acceleration due to gravity, for Earth, g = 10 m/s²

So,

\(F=7\times 10\\\\F=70\ N\)

So, 70 N of force of acting on an object.

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

No, it's a cap

Explanation:

Hats have circular or rounded edges all around but with Caps, it has a pointed round front edge

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question

f = 20 N

m = 10 kg

We have

\(a = \frac{20}{10} \\ \)

We have the final answer as

Hope this helps you

Answer:.

Explanation:.

Answer:

Organisms 2 and 3

Explanation: