The speed of the water leaving the hole 2 inches from the top of the cup when it first forms is approximately 7.67 ft/s. The speed of the water leaving the hole 4 inches from the top of the cup when it first forms is approximately 10.86 ft/s.
To determine the speed of the water leaving each hole, we can use Torricelli's law, which states that the speed of a fluid leaving an opening is equal to the square root of twice the acceleration due to gravity (9.8 m/s²) times the difference in height between the water surface and the opening.
For the hole 2 inches from the top, the height difference is 2 inches or 0.167 ft. Plugging the values into the equation, we have:
Speed = √(2 * 9.8 * 0.167) = 7.67 ft/s.
For the hole 4 inches from the top, the height difference is 4 inches or 0.333 ft. Plugging the values into the equation, we have:
Speed = √(2 * 9.8 * 0.333) = 10.86 ft/s.
The speed of the water leaving the hole 2 inches from the top of the cup when it first forms is approximately 7.67 ft/s, while the speed of the water leaving the hole 4 inches from the top is approximately 10.86 ft/s. These calculations assume no air resistance and neglect the effects of the cup's shape or the water's viscosity.
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describe the importance of measurements in brief.
Answer:
importance of measurement is it gives proper required amount of anything if it will not exist then alot of work be disrupted .In many work measurement is very necessary like in scientific works
For a bronze alloy, the stress at which plastic deformation begins is 280 MPa and the modulus of elasticity is 115 GPa. (a) What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm without plastic deformation? (b) If the original specimen length is 115 mm, what is the maximum length to which it may be stretched without causing plastic deformation?
(a) The maximum load that may be applied to the specimen without plastic deformation is 91,000 N.
To calculate the maximum load, we can use the formula:
maximum load = stress × cross-sectional area
where stress is given as 280 MPa and the cross-sectional area is given as 325 mm^2. However, we need to convert the units to the SI unit of Pascal (Pa) to get the answer in Newtons (N).
1 MPa = 1 × 10^6 Pa
325 mm^2 = 325 × 10^-6 m^2
Substituting these values, we get:
maximum load = 280 × 10^6 Pa × 325 × 10^-6 m^2
maximum load = 91,000 N
Therefore, the maximum load that may be applied to the specimen without plastic deformation is 91,000 N.
(b) The maximum length to which the specimen may be stretched without causing plastic deformation is 115.28 mm.
To calculate the maximum length to which the specimen may be stretched without causing plastic deformation, we can use the formula:
maximum elongation = maximum stress / modulus of elasticity
where the maximum stress is given as 280 MPa and the modulus of elasticity is given as 115 GPa. However, we need to convert the units to the SI unit of Pa to get the answer in meters (m).
1 GPa = 1 × 10^9 Pa
Substituting these values, we get:
maximum elongation = (280 × 10^6 Pa) / (115 × 10^9 Pa)
maximum elongation = 0.00243
The maximum elongation is given as a ratio of the original length, so we can calculate the maximum length as:
maximum length = (1 + maximum elongation) × original length
maximum length = (1 + 0.00243) × 115 mm
maximum length = 115.28 mm
Therefore, the maximum length to which the specimen may be stretched without causing plastic deformation is 115.28 mm.
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What is the atomic number the atom shown?
A. 3
B. 13
C. 14
D. 27
Answer:
13
Explanation:
Brainlest pls
Answer:
B-13
Explanation:
The protons listed in the atom are 13, and the protons are the same number as the atomic number.
A plane flies 300km in 3 hrs. What is
the rate of the plane?
the plane is on a average of 100km a hour
Answer:
on average, the plane is traveling at 100km per hour, so i think the rate is 100:1
Explanation:
the a 36 shaft is made from two segments ac has a diameter of 0.5 in and cb has a diameter of 1 in. if the shaft is fixed at its ends a and b and subjected to uniform distributed torque of 60 ln in/in along segment cb determine the absolute maximum shear stress in the shaft
The absolute maximum shear stress in the shaft is determined by the torque applied and the geometry of the segments.
To calculate the shear stress, we can use the formula: τ = (T * r) / (J * c), where τ is the shear stress, T is the torque, r is the radius, J is the polar moment of inertia, and c is the distance from the center to the outermost fiber.
In segment CB with a diameter of 1 inch, the radius (r) is 0.5 inches, and the distance to the outermost fiber (c) is 0.5 inches as well. To determine the polar moment of inertia (J) for segment CB, we can use the formula: J = π/2 * (r^4).
Substituting the given values into the formula, we have J = π/2 * (0.5^4) = 0.0491 in^4.
Now we can calculate the shear stress: τ = (60 ln in/in * 0.5 in) / (0.0491 in^4 * 0.5 in) = 244.2 psi.
Therefore, the absolute maximum shear stress in the shaft is approximately 244.2 psi.
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A wheel is spinning at 50 rpm with its axis vertical. After 15 s, it’s spinning at 65 rpm with its axis horizontal. Find (a) the magnitude of its average angular acceleration and (b) the angle the average angular acceleration vector makes with the horizontal.
The magnitude of the average angular acceleration is 0.104 \(rad/s^2\) and the angle the average angular acceleration vector makes with the horizontal is approximately 1.14 degrees.
We can use the formula for average angular acceleration to solve this problem:
α_avg = (ω_f - ω_i) / t
where α_avg is the average angular acceleration, ω_i is the initial angular velocity, ω_f is the final angular velocity, and t is the time interval.
(a) First, we need to convert the initial and final angular velocities from rpm to rad/s:
ω\(_i\) = 50 rpm x (2π rad/rev) x (1 min/60 s) = 5.24 rad/s
ω\(_f\) = 65 rpm x (2π rad/rev) x (1 min/60 s) = 6.80 rad/s
Substituting these values into the formula, we get:
α\(_a_v_g\) = (ω\(_f\)- ω\(_i\)) / t = (6.80 rad/s - 5.24 rad/s) / 15 s = 0.104 \(rad/s^2\)
Therefore, the magnitude of the average angular acceleration is 0.104 \(rad/s^2\).
(b) The angle the average angular acceleration vector makes with the horizontal can be found using trigonometry. Let's denote this angle by θ. We can use the following relationship:
tan(θ) =α\(_a_v_g\) / ω\(_i\)
Substituting the values we found earlier, we get:
tan(θ) = 0.104\(rad/s^2\) / 5.24 rad/s
tan(θ) = 0.0199
Taking the inverse tangent of both sides, we get:
θ = \(tan^(^-^1^)\)(0.0199) = 1.14 degrees
Therefore, the angle the average angular acceleration vector makes with the horizontal is approximately 1.14 degrees.
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How would you obtain a mean value for the specific heat
capacity of a material?
some solids exist in his regular structure known as a lattice true or false
Answer:
B.) The cake rises as gas bubbles form in the baking cake.
Explanation:
I got A on the quiz
True, some solids exist in his regular structure known as a lattice.
Regular structure of solids
A crystalline solid can be formed from the regular repeating three-dimensional structure of a solid called crystal lattice.
Irregular structure of solidsSolids can alos aggregate with no particular order, in which case they form an amorphous solid.
Thus, some solids exist in his regular structure known as a lattice.
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Suppose the green car was traveling at 0 miles the white car was traveling at 70 miles at the red car was trailing at 22 miles which car is covering the most distance every second?
Answer:
The white car will cover the most distance every second.
Explanation:
The formula for the uniform speed of an object is given as follows:
\(s = vt\)
where,
s = distance covered by the object
v = speed of the object
t = time required
Now, if we assume time to be constant at 1 s. Then the distance covered by each car will be directly proportional to the speed of the car. Hence, the car with the greatest speed will travel the greatest distance in 1 second.
We, have:
Speed of white car > Speed of red car > Speed of green car
Therefore, the white car will cover the most distance every second.
A wave with a frequency of 325 Hz. is travelling at a speed of 125 m/s. What is the wavelength of this wave?
Answer:
0.385 meters
Explanation:
Just remember this very simple equation:
velocity=(wavelength)*(frequency)
I always remember it as "Velma is Waving Frantically"
So, 125=(wavelength)*(325)
Therefore, wavelength=0.385 meters!
Hope this helped!
Supposet that f(x,y)= The temperature of a sheet of metal (in°C)at the position (z,y) (in cm) Suppose that VJ (2,3)=(5,12) Suppose that an ant is crawling on the pan. At t=5s, the position of the ant is (2,3) cm, and the velocity of the ant is (3, 4) cm/s. For each of the following questions, show how you get your answer.
(a) At t= 5s, at what (instantaneous) rate is the ant warming up (assume the ant always has the same temperature as the metal it is standing on). Your a answer chould be in
(b) At t = 58, at what (instantaneous) rate is the ant warming up per cm it travels? Your answer should be in C
(c) If the position of the ant is (2,3) cm, in which direction should the ant move to maximize the instantaneous rate it warms up? Give your answer as a unit vector.
(d) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c), at what instantaneous rate is it warming up per cm it travles? Give your answer in cm C
(e) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c) with a speed of 4 at what instantaneous rate is it warming up with respect to time? Give your answer in
Explanation:
the answers are calculated in above pictures
a cylinder has volume 50 cm and radius 4 cm find its volume. pls do it with the full process
Explanation:
Please, check the question properly
A solid conducting sphere of radius 5. 00 cm carries a net charge. To find the value of the charge, you measure the potential difference VAB=VA−VB between point A, which is 8. 00 cm from the center of the sphere, and point B, which is a distance r from the center of the sphere. You repeat these measurements for several values of r > 8cm. When you plot your data as VAB versus 1/r, the values lie close to a straight line with slope -18. 0 V⋅m.
What does your data give for the net charge on the sphere?
Data obtained from the measurements of potential difference as well as the corresponding distances (r) from the center of solid conducting sphere, can be used to determine the net charge on the sphere.
When the data is plotted as VAB versus 1/r, it forms a straight line with a slope of -18.0 V⋅m. The slope of this line is related to the charge on the sphere.
To find the net charge, we can use the relationship between electric potential difference (V), charge (Q), and distance (r):
V = k * (Q/r)
Where:
- V is the electric potential difference between points A and B
- k is the electrostatic constant (9.0 x 10⁹ N⋅m²/C²)
- Q is the net charge on the sphere
- r is the distance from the center of the sphere to point B
Since the slope of the straight line in the plot is -18.0 V⋅m, we can equate this to the expression for V:
-18.0 V⋅m = k * (Q/r)
Simplifying the equation, we have:
(Q/r) = -18.0 V⋅m / k
Now, to find the net charge on the sphere, we need to solve for Q. We can rearrange the equation as follows:
Q = (-18.0 V⋅m / k) * r
Since the radius of the sphere is given as 5.00 cm (or 0.05 m), we can substitute this value into the equation:
Q = (-18.0 V⋅m / k) * 0.05 m
Calculating the value using the given value of k, we find:
Q ≈ -18.0 V⋅m * 0.05 m / (9.0 x 10⁹ N⋅m²/C²)
This calculation gives us the net charge on the solid conducting sphere. However, it is important to note that the negative sign in the equation indicates that the net charge is negative.
So, the data obtained from the measurements of the potential difference and the corresponding distances allows us to determine the net charge on the sphere.
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Which of the following element has seven total valence electrons? Your answer: argon helium oxygen bromine
Answer:
bromine
Explanation:
Any element in the halogen group will have seven valence electrons. These elements include fluorine, chlorine, bromine, iodine, and astatine
An astronaut drops a feather from 1.2 m above
the surface of the moon. If the acceleration of
gravity on the moon is 1.62 m/s2 downward,
how long does it take the feather to hit the
moon's surface?
It take "1.49 sec" to hit the moon's surface. A further explanation is provided below.
According to the question,
Height,
d = 1.2 m/sAcceleration of gravity,
a = 1.62 m/s²Initial velocity,
u = 0With the help of the equation,
→ \(t^2 = \frac{2d}{a}\)
By substituting the values, we get
→ \(= \frac{2\times 1.2}{1.62}\)
→ \(= \frac{2.4}{1.62}\)
→ \(= 1.49 \ sec\)
Thus the above answer is right.
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Drag each label to the correct location on the table.
Sort the processes based on the type of energy transfer they involve.
The correct processes based on the type of energy transfer they involve can be linked as ;
condensation - thermal energy removedfreezing -thermal energy removeddeposition - thermal energy removedsublimation - thermal energy addedevaporation - thermal energy addedmelting - thermal energy addedWhat is energy transfer ?Conduction, radiation, and convection are the three different ways that thermal energy is transferred. Only fluids experience the cyclical process of convection.
The total amount of energy in the universe has never changed and will never change because it cannot be created or destroyed.
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what is one physical force that can change an object from one phase to the next
One physical force that can change an object from one phase to the next is temperature. The phase of matter is determined by the arrangement and movement of its particles. As temperature changes, the average kinetic energy of the particles also changes, causing them to move faster or slower.
This change in movement can lead to a change in the arrangement of particles, which ultimately changes the phase of the matter.
For example, if a solid is heated, the particles gain energy and vibrate faster, causing the bonds between particles to weaken. Eventually, the bonds break, and the particles are able to move freely, resulting in a liquid phase. Similarly, if a liquid is cooled, the particles lose energy and move slower, causing the bonds between particles to strengthen. Eventually, the particles will become fixed in a rigid pattern, resulting in a solid phase.
Therefore, temperature can act as a physical force to change the phase of matter, and it is a fundamental concept in the study of thermodynamics and phase transitions.
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What problem can you imagine coming from using digitized
DNA storage?
Answer: There are many problems associated with digitized DNA storage.
Explanation:
The cost of encoding the DNA data is high and lot of working efficiency is required for the same. The encoding process requires a considerable amount of time and encoding is slow. It takes about 400 bytes per second. This is done in a silicon memory chip. The process is millions of times slower.
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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An object starts at position -2m with an initial velocity of -4 m/s and a constant acceleration of +3 m/s^2.
a. In which direction is the object traveling initially?
b. What will be the object's velocity after 1s, 2s, 3s?
c. What will the objects position be after 3s?
Answer:
here is the answer
Explanation:
a) since displacement is given as a negative value, object must travelling i the negative direction (with respect to a cartesian plane).
b) after 1 second
v = u + at
v = -4 + 3× 1
v = -4 + 3
v = -1 m/s
after 2 seconds
v = -4 + 3×2
v = -4 + 6
v = 2 m/s
after 3 seconds
v = -4 + 3×3
v = -4 + 9
v = 5 m/s
c) we need to find the position after three seconds
initial velocity= u= -4m/s
final velocity = v= 5 m/s ( as previously calculated)
acceleration=3m/s²
s = ut + 1/2 × at²
s = -4×3 + 1/2 × 3×(3)²
s = -12 + 1/2 × 27
s = -12 + 27/2
s = 1.5 meters ( in the positive direction; as time has increased and acceleration in positive)
position = -2 + 1.5 = -0.5 meters
(s indicates distance travelled)
A 580 kg elevator accelerates upward at 1.2 m/s2 for the first 13 m of its motion. How much work is done during this part of its motion by the cable that lifts the elevator? Neglect any friction.
The work done during this part of its motion by the cable that lifts the elevator is 64844 Joule.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Upward acceleration of the elevator is = 1.2 m/s².
Mass of the elevator is = 580 kg
Displacement of the elevator = 13 m
Hence, the work is done during this part of its motion by the cable that lifts the elevator = 580 × (9.8 + 1.2) ×13 Joule
= 64844 Joule.
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A study of classical waves tells us that a standing wave can be expressed as a sum of two travelling waves. Quantum-Mechanical travelling waves, discussed in Chapter 4, is of the form φ(x,t) = Ae^i(kw=wt) Show that the infinite well’s standing wave function can be expressed as a sum of two traveling waves.
In quantum mechanics, the wavefunction of a particle in an infinite well can be described as a standing wave, which is a superposition of two traveling waves propagating in opposite directions.
The standing wave function in an infinite well is given by:
ψ(x, t) = A sin(kx) e^(-iωt)
Using the Euler's formula, we can rewrite the sine function as a sum of exponential functions:
sin(kx) = (1/2i) * (e^(ikx) - e^(-ikx))
Substituting this back into the standing wave function, we have:
ψ(x, t) = A (1/2i) * (e^(ikx) - e^(-ikx)) * e^(-iωt)
Simplifying the expression, we obtain:
ψ(x, t) = (A/2i) * (e^(ikx - iωt) - e^(-ikx - iωt))
Now, we can define two traveling waves:
ψ_1(x, t) = (A/2i) * e^(ikx - iωt)
ψ_2(x, t) = (A/2i) * e^(-ikx - iωt)
The superposition of these two traveling waves gives us the standing wave function:
ψ(x, t) = ψ_1(x, t) + ψ_2(x, t)
Therefore, we have shown that the infinite well's standing wave function can be expressed as a sum of two traveling waves propagating in opposite directions.
By expressing the sine function in terms of exponential functions and defining two traveling waves, we can show that the infinite well's standing wave function can be written as the sum of these two traveling waves. This demonstrates the connection between standing waves and the superposition of traveling waves in the context of quantum mechanics.
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which mineral is hard enough to scratch calcite but is not hard enough to scratch amphibole
Answer:
Muscovite mica. Flourite. Olivine.
The mineral that should be hard sufficient to scratch calcite at the same time it should be hard enough to scratch amphibole is fluorite.
What is fluorite?Fluorite refers to the mineral form of calcium fluoride, CaF₂. It should belong to the halide minerals. It should be crystallized in isometric cubic habit.
So based on this we can say that The mineral that should be hard sufficient to scratch calcite at the same time it should be hard enough to scratch amphibole is fluorite.
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Place the follow in increasing order of impedance, which order is correct?
A. PZT, matching layer, gel, skin
B. matching layer, gel, PZT, skin
C. PZT, gel, skin, matching layer
D. skin, gel, matching layer, PZT
The correct order of increasing impedance is:
C. PZT, gel, skin, matching layer
Impedance is a measure of the opposition to the flow of sound waves in a medium. It depends on the density and speed of sound in the material. In the given options, the order of increasing impedance can be determined by considering the properties of the materials involved.
PZT (lead zirconate titanate) has a higher impedance than gel, skin, and the matching layer. PZT is a piezoelectric material commonly used in ultrasound transducers and has a higher density and speed of sound, leading to higher impedance.
Gel has a lower impedance compared to PZT but higher impedance than skin and the matching layer. Gel is used as a coupling medium between the transducer and the skin to enhance acoustic coupling and minimize impedance mismatch.
Skin has a lower impedance than both gel and the matching layer. It is the outermost layer and acts as an interface between the transducer and the biological tissue.
The matching layer has the lowest impedance among the given options. It is designed to match the impedance of the PZT to the impedance of the tissue being imaged, facilitating efficient sound transmission.
Therefore, the correct order is C.
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Convert 149 °F into a °C, (b) Kelvin
Answer:
a.149 °F into °C
149 - 32 = 117
117 x 5 = 585
585 / 9 = 65
149 °F = 65 °C
b.149 °F into Kelvin
(149°F − 32) × 5/9 + 273.15 = 338.15K
what would happen to the generator, if the output voltage dropped below battery voltage and the rcr failed in the closed position ?
If the output voltage of the generator dropped below battery voltage and the RCR (reverse current relay) failed in the closed position, the battery would begin to discharge back through the generator.
This can cause the generator to overheat and may damage the internal components.
The battery could also become damaged due to excessive charging. In addition, the electrical system of the vehicle may experience fluctuations in voltage,
which could affect the operation of other components such as lights, radio, and other electronic devices.
It is important to have a functioning RCR in the system to prevent this type of situation from occurring, as it acts as a safety mechanism to prevent reverse current flow from the battery to the generator.
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An object wants to maintain its state of motion because it has mass. True or false
Answer:
True
Explanation:
When no net force is applied to a moving object, it still comes to rest because of its inertia.
It is a true statement that an object wants to maintain its state of motion because it has mass, as per the first law of the motion due to the effect of inertia an object tries to maintain its state of motion whether it would be a state of motion or the state of the rest.
What is Newton's first law?According to Newton's first law, until pushed to alter its condition by the intervention of an external force.
Every object will continue to be at rest or in uniform motion along a single direction.
It is true that an item wants to keep moving because it has mass. According to the first law of motion, this is because of the influence of inertia, which causes an entity to try to keep moving whether it is in movement or at standstill.
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a 26.0 kgkg child plays on a swing having support ropes that are 2.00 mm long. a friend pulls her back until the ropes are at angle ϕϕphi = 39.0 ∘∘ from the vertical and releases her from rest. A: What is the potential energy for the child just as she is released, compared with the potential energy at the bottom of the swing?
B: How fast will she be moving at the bottom of the swing?
C: How much work does the tension in the ropes do as the child swings from the initial position to the bottom?
A. The potential energy for the child just as she is released (PE_initial) is equal to the potential energy at the bottom of the swing (PE_bottom), which is zero.
B. She will be moving at the bottom of the swing at v = sqrt(2 * g * L).
C. The work done by the tension in the ropes is equal to the gravitational potential energy of the child at the initial position, which is m * g * L.
A: The potential energy for the child just as she is released can be compared to the potential energy at the bottom of the swing.
At the initial position, the potential energy is given by the formula:
PE_initial = m * g * h_initial
Since the child is released from rest, her initial height (h_initial) is equal to the length of the support ropes (L). Therefore, we have:
PE_initial = m * g *
At the bottom of the swing, the potential energy is given by:
PE_bottom = m * g * h_bottom
The height at the bottom of the swing (h_bottom) is zero because the child is at the lowest point of the swing. Hence, we have:
PE_bottom = m * g * 0 = 0
Therefore, the potential energy for the child just as she is released (PE_initial) is equal to the potential energy at the bottom of the swing (PE_bottom), which is zero.
B: To determine the speed of the child at the bottom of the swing, we can use the principle of conservation of mechanical energy. At the highest point, all of the potential energy is converted into kinetic energy.
Initial potential energy (PE_initial) = Final kinetic energy (KE_bottom)
m * g * L = (1/2) * m * v^2
Simplifying the equation, we find:
v = sqrt(2 * g * L)
C: The work done by the tension in the ropes as the child swings from the initial position to the bottom is equal to the change in mechanical energy. It is given by:
Work = PE_initial - PE_bottom = m * g * L - 0 = m * g * L
Therefore, the work done by the tension in the ropes is equal to the gravitational potential energy of the child at the initial position, which is m * g * L.
Note: The given value of the angle ϕ is not required to solve parts A, B, and C of the problem.
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If the specific heat of iron = 0.46J C, how much heat is needed to warm 50 g of iron from 20C to 100C
Answer:
1840 J
Explanation:
From the question given above, the following data were obtained:
Specific heat capacity (C) = 0.46 J/gºC
Mass (M) = 50 g
Initial temperature (T₁) = 20 °C
Final temperature (T₂) = 100 °C
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 20 °C
Final temperature (T₂) = 100 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 100 – 20
ΔT = 80 °C
Finally, we shall determine the heat required. This can be obtained as follow:
Specific heat capacity (C) = 0.46 J/gºC
Mass (M) = 50 g
Change in temperature (ΔT) = 80 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.46 × 80
Q = 1840 J
Thus, 1840 J of heat energy is required.
Diffraction occurs when waves _______ around the edge of a barrier?
Answer:
travels
Explanation:
hope this helps and have a blessed day