Answers
Answer:
radius of the loop = 7.9 mm
number of turns N ≅ 399 turns
Explanation:
length of wire L= 2 m
field strength B = 3 mT = 0.003 T
current I = 12 A
recall that field strength B = μnI
where n is the turn per unit length
vacuum permeability μ = \(4\pi *10^{-7} T-m/A\) = 1.256 x 10^-6 T-m/A
imputing values, we have
0.003 = 1.256 x 10^−6 x n x 12
0.003 = 1.507 x 10^-5 x n
n = 199.07 turns per unit length
for a length of 2 m,
number of loop N = 2 x 199.07 = 398.14 ≅ 399 turns
since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.
this length is also equal to the circumference of each loop
the circumference of each loop = \(2\pi r\)
0.005 = 2 x 3.142 x r
r = 0.005/6.284 = \(7.9*10^{-4} m\) = 0.0079 m = 7.9 mm
Related Questions
a wire has a resistance 12 ohm. It is bent in the form of circle. The effective resistance between the points on any diameter will be:. a)12 ohm b)6 ohm c)3ohm d)24ohm
Answers
Answer:
a) 12 ohm
that's what I kno
Hi please answer the question labeled d
If Q1 is 5 times larger than Q2 the force that Q1 exerts on Q2 is?
(greater than, smaller than, or exactly the same as) the force that Q2 exerts on Q1.
Answers
part a) If Q increases by 5 times its original value, the electrostatic force (F) will increase5 times as well.
part b) If r is halved (reduced by 2), the force will become four times stronger (since 2² = 4).
part c) If Q1 is positive and Q2 is negative, the charges will attract each other.
part d) If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same.
What is electrostatic force?The electrostatic force is described as the force of attraction or repulsion between two charged particles.
With regards to Coulomb's Law, we have that the electrostatic force between two charges separated by a distance is :
Force = k * (Q1 * Q2) / r²
Where:
F_ = electrostatic force
k = electrostatic constant
Q1 and Q2 = magnitudes of the charges
r = distance
for case a:
If one of the charges, Q1 or Q2, increases by 5 times then the electrostatic force will also increase by 5 times.
case b)
If the distance between the charges, r, is halved, the electrostatic force will become four times stronger because (1/r²).
for case c.
if Q1 is positive and Q2 is negative, the charges will attract each other because of magnetic laws.
for case d.)
If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same as there is a resulting stronger gravitational or electromagnetic force.
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Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
Answers
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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Read the following situation and determine which of Newton's laws is being demonstrated and state why it is that law.
You balance a meter stick on one finger & the ruler on the other finger.
You find that one of them is easier to balance than the other.
Which of Newton's three laws is this situation demonstrating, and why is that law?
Answers
The situation is demonstrating Newton's second law of motion because the force acting on the finger is greater for the meter rule than the meter stick.
What are the Newton's laws of motion?Newton's laws of motion are laws which describe the relationship between the motion of bodies and objects and the forces that cause the motion.
There are three laws of motion propounded by Newton. The laws are:
An object will remain in its state of rest or motion along a straight line unless acted upon by an external forceThe rate of change of the velocity of a body is directly proportional to the applied net force and inversely proportional to the mass of the body.For every action, there is an equal but oppositely directed reactionConsidering the given problem:
You balance a meter stick on one finger & the ruler on the other finger. You find that one of them is easier to balance than the other.
The meter ruler has greater mass than the meter stick.
Based on their masses, the force of gravity acting on meter ruler is greater than that on the meter stick, therefore, it is more difficult to balance the meter rule on a finger than the meter stick. This is according to Newton's second law of motion of unbalanced forces.
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Using the given data table, calculate the acceleration of the skateboarder. You can use either form of the
equation:
Answers
The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)
The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)
The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)
force = mass * acceleration
mass1 = 62 kg
force1 = 480 N
acceleration1 = force / mass
= 480 / 62 = 7.74 \(m/s^{2}\)
mass2 = 62 kg
force2 = 240 N
acceleration 2 = 240 / 62 = 3.87 \(m/s^{2}\)
mass 3 = 62 kg
force 3 = 600 N
acceleration 3 = 600 / 62 = 9.68 \(m/s^{2}\)
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An 11 kg toddler is running at a speed of 8 m/s. How much energy does he have?
Please help
Answers
Answer:g
Explanation:jqjqksk
What is the relationship between resistivity of a wire and length of a wire is?
Answers
\(\boxed{\sf R=\rho\dfrac{\ell}{A}}\)
Or
\(\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}\)
Rho stands for resistivity of wireR stands for resistance of wire l stands for length of areaA stands for surface area of wireA PVC pipe has a length of 45.132 centimeters.a. What are the frequencies of the first three harmonics when the pipe is open at both ends? Include units in your answers.b. What are the frequencies of the first three harmonics when the pipe is closed at one end and open at the other? Include units in your answers.
Answers
ANSWERS
a. f₁ = 380 Hz; f₂ = 760 Hz; f₃ = 1140 Hz
b. f₁ = 190 Hz; f₃ = 570 Hz; f₅ = 950 Hz
EXPLANATION
a. For a pipe of length L open at both ends, the frequencies of the first three harmonics are:
\(\begin{cases}f_1=\frac{v}{2L} \\ \\ f_2=2f_1=\frac{v}{L} \\ \\ f_3=3f_1=\frac{3v}{2L}\end{cases}\)Assuming that the speed of the wave is the speed of sound: 343 m/s and knowing that the length of the pipe is L = 45.132 cm = 0.45132 m we can find the frequencies of the first three harmonics:
\(\begin{cases}f_1=\frac{343m/s}{2\cdot0.45132m}\approx380Hz \\ \\ f_2=2f_1=2\cdot380Hz\approx760Hz \\ \\ f_3=3f_1=3\cdot380Hz\approx1140Hz\end{cases}\)b. For a pipe of length L closed at one end and open at the other, the frequencies of the first three harmonics are:
\(\begin{cases}f_1=\frac{v}{4L} \\ \\ f_2=DNE \\ \\ f_3=3f_1=\frac{3v}{4L}\end{cases}\)In a closed pipe, there can only be odd harmonics (1, 3, 5...). Therefore, the second harmonic does not exist and the "third harmonic" would be the 5th,
\(\begin{cases}f_1=\frac{v}{4L} \\ \\ f_3=3f_1=\frac{3v}{4L} \\ \\ f_5=5f_1=\frac{5v}{4L}\end{cases}\)Again, the length of the pipe is 45.132 cm = 0.45132 m, so the first three harmonics are:
\(\begin{cases}f_1=\frac{343m/s}{4\cdot0.45132m}\approx190Hz \\ \\ f_3=3f_1=3\cdot190Hz=570Hz \\ \\ f_5=5f_1=5\cdot190Hz=950Hz\end{cases}\)If the frequency of a wave increases, the wavelength will
O decrease
O increase
O disappear
O remain unchanged
Answers
Answer:
the wavelength will decrease
Explanation:
If the frequency of a wave increases, the wavelength will decrease. This is because the speed of the wave is constant for a given medium, so if the frequency (the number of waves passing a fixed point per second) increases, then the distance between successive wave crests (i.e., the wavelength) must decrease to maintain a constant speed. This relationship is described by the wave equation:
v = f λ
where v is the speed of the wave, f is the frequency, and λ is the wavelength. If v is constant and f increases, then λ must decrease to keep the equation balanced.
A physics student mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them, and they appear concentric when viewed from either end). The lenses are identical, each with a positive (converging) focal length of 14.8 cm. They are separated by a distance of 39.4 cm. Lens 1 is to the left of Lens 2.
Required:
a. What is the final image's distance (in cm) from Lens 2?
b. Where is the final image located?
c. What is the overall magnification of the lens pair, considered as a single optical instrument?
Answers
Answer:
A) q₂ = 75.98 cm, B) q₂' = 115.38 cm, C)
Explanation:
A) This is an exercise in geometric optics, as the two lenses are separated by a greater distance than their focal lengths from each lens, they must be worked as independent lenses.
Lens 1. More to the left
let's use the constructor equation
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
where f is the focal length, p and q are the distance to the object and the image, respectively,
We must assume a distance to the object to perform the calculation, suppose that the object is 50 cm from lens 1 that is further to the left of the system.
\(\frac{1}{q_1} = \frac{1}{f} - \frac{1}{p}\)
\(\frac{1}{q_1} = \frac{1}{14.8} - \frac{1}{50}\)
1 / q₁ = 0.04756
q₁ = 21.0227 cm
this image is the object for the second lens that has f₂ = 14.8 cm
the distance must be measured from the second lens
p₂ = 39.4 -q₁
p₂ = 39.4 -21.0227
p₂ = 18.38 cm
let's use the constructor equation
1 / q₂ = 1 / f - 1 / p2
\(\frac{1}{q_2} = \frac{1}{14.8} - \frac{1}{18.38}\)
\(\frac{1}{q_2}\) = 0.01316
q₂ = 75.98 cm
measured from the second lens
B) the position of the final image with respect to the first lens is
q₂’= q₂ + 39.4
q₂'= 75.98 +39.4
q₂' = 115.38 cm
C) the magnification of a lens is
m = - q / p
in this case the image measured from lens 2 is q2 = 75.98 cm
the distance to the object from the first lens is p1 = 50cm
m = - 75.98 / 50
m = -1.5 X
the negative sign indicates that the image is inverted
A pebble of mass 0.05kg is thrown vertically upwards. Give the direction and
magnitude of the net force on the pebble.
(a) During its upward motion.
(b) At the highest point where it is momentarily at rest.
Answers
In each case, 0.5N of force in a downward direction
No matter which way an object is moving, gravity's acceleration always works downward. In all three scenarios, the stone is just subject to the gravitational pull. According to Newton's second rule of motion, its magnitude is as follows:
Force=ma
Where, m is a mass of the pebble and a is acceleration due to gravity
F = Net force.
M = 0.05 kg of pebble mass
a=g=10m/s^2 F=0.05 × 10=0.5N
In all three scenarios, there is a downward-moving net force of 0.5N acting on the stone.
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Technician A says that when replacing a rear hatch window with defroster grids, the
wiring connection may have a locking tab that will need to be released before
removal.
Technician B says that when replacing a rear hatch window with hydraulic lift struts,
the struts should be completely compressed before removal.
Who is right?
A only
B only
Both A and B
Neither A nor B
Answers
Technician A only is tight as hen replacing a rear hatch window with defroster grids, the wiring connection may have a locking tab that will need to be released before removal.
Who is a Technician?A technician is someone with expertise and training in a technical procedure. You might need to contact a network technician if your computer network is giving you problems.
A technician is familiar with all of the technical details (ins and outs) of a particular process. A computer technician is an expert in both operating and repairing computers. Similar to a mechanic, an automotive technician is well-versed in cars and how to repair them. Technology and technicians are not always synonymous. A painter or musician may also be referred to as a technician if they have received training in a variety of artistic or musical techniques.
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3.
How much force does the atmosphere exert on one side of a vertical wall 4.00-m high and
10.0-m long? The atmospheric pressure is standard atmospheric pressure.
4.05 x 105 N
E)
C)
4.05 x 106N
A)
2.53 x 103 N
D)
zero N
101 x 105N
Answers
Answer:
4.05×10⁶ N.
Explanation:
The following data were obtained from the question:
Breadth (B) = 4 m
Length (L) = 10 m
Standard pressure (P) = 101325 Nm¯²
Force (F) =..?
Next, we shall determine the area of the wall. This can be obtained as follow:
Area (A) = length (L) × breadth (B)
A = 10 × 4
A = 40 m²
Finally, we shall determine the force exerted on one side of the wall as follow:
Standard pressure (P) = 101325 Nm¯²
Area (A) = 40 m²
Force (F) =.?
Pressure (P) = Force (F) /Area (A)
101325 = F/40
Cross multiply
F = 101325 × 40
F = 4.05×10⁶ N.
Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.
A car changes its speed from 0 to 20 m/s in 4 seconds. What is the acceleration?
Answers
Answer:
5 m/s2
Explanation:
Acceleration = Change in velocity/ time
Or
a= v2 - v1/ t
a = 20- 0 /4
a = 20÷ 4
a= 5meters per seconds square
A veritical brass rod of circular section is loaded by placing a 10 kg wt on top of it .if it's length is 1 m. it's radius of cross section 1cm find the energy stored in rod .Y=3.5 ×10^10 Nm2
Answers
Answer:
Energy stored in the rod, W = 4.55 × 10⁻⁴ J
Explanation:
From the question, the following values are given:
Mass of the brass rod, m = 10kg
Length of rod, l = 1 m
Radius of brass rod, r =1 cm
Change in length of rod, e = ?
Energy stored, W = ?
Young's modulus of brass, Y = 3.5 × 10¹⁰ N/m²
Using the formula for energy stored in an elastic material;
W = 1/2 F × e
Force due to the load, F = mg = 10 × 10 = 100N
To determine the change in length, e, we use the formula for Young's modulus of elasticity;
Y = (F/A)/(e/l) = F × l / A × e
e = (F × l) / (Y × A)
where A = πr²
e = 100 × 1 / (3.5 × 10¹⁰ × π × (0.01)²
e = 9.09 × 10⁻⁶ m
Therefore, energy stored in the rod, W = 1/2 × 100 × 9.09 × 10⁻⁶
Energy stored in the rod, W = 4.55 × 10⁻⁴ J
A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H
Answers
(a) The direction of wave propagation is along the negative z-axis.
(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m
Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.
Hence, the direction of wave propagation for the given wave is along the negative z-axis.
To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:
E = c * H,
where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.
(a) Direction of wave propagation: Along the positive z-axis.
(b) Calculating λ, f, and Er:
Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.
The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.
Using the relation c = ω/k, we can solve for λ and f:
λ = 2π/k = 2π/2 = π m (meters)
f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)
To find the wave impedance (Er), we can use the equation Er = E/H:
Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) can be calculated using the relationship H = E/c:
H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
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a floating boat weighs 20,000 N what is the size of the upthrust
Answers
Answer:
20,000N
explanation:
a body can only float when the upthrust
balances with the weight of the body,
hence in accord with the question,as the body floats the upthrust is equal to it's weight.
We have that For a floating boat weighing 20,000N, the size of the upthrust is
20,000N
From the question we are told
a floating boat weighs 20,000 N what is the size of the upthrust
Generally the equation for the upthrust is mathematically given as
U=W
The upthrust is Directly equal the weight it suspends or acts on in water or any liquid
Since
The upthrust is Directly equal the weight it suspends or acts on in water or any liquid
Therefore
The Upthrust must be Directly equal the Weigh
Therefore
For a floating boat weighing 20,000N, the size of the upthrust is
20,000N
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Science has been wrong in the past. For example, we now know that the original models of the atom were not fully correct. In response to this, a friend tells you, "Science cannot be trusted. Don't believe anything a scientist says." What is your response to this statement? (For full credit, you need to write at least a full sentence explanation"
Answers
Although it is true that scientific models and hypotheses have been updated and improved over time, this is not sufficient justification to reject science as a whole or to doubt what scientists claim.
Given that we are aware of their limitations, why do scientists continue to employ atomic model simulations?Models aid in our comprehension of systems and their characteristics. An atomic model, for instance, depicts what an atom's structure may like based on what is known about how atoms function. It may not accurately represent the precise makeup of an atom. Models are frequently condensed.
Why do scientific theories alter over time, including the atomic model?Over time, this atomic model has evolved. The model was used by scientists to make predictions. Their trials occasionally yielded unexpected outcomes that did not match the pre-existing model. The model was modified by scientists so that it could account for the fresh data.
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What was the big bang?
Answers
The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now—and it is still stretching!
What's This Big Bang All About?
In 1927, an astronomer named Georges Lemaître had a big idea. He said that a very long time ago, the universe started as just a single point. He said the universe stretched and expanded to get as big as it is now, and that it could keep on stretching.
What an Idea!
The universe is a very big place, and it’s been around for a very long time. Thinking about how it all started is hard to imagine.
Some More Information
Just two years later, an astronomer named Edwin Hubble noticed that other galaxies were moving away from us. And that’s not all. The farthest galaxies were moving faster than the ones close to us.
This meant that the universe was still expanding, just like Lemaître thought. If things were moving apart, it meant that long ago, everything had been close together.
Everything we can see in our universe today—stars, planets, comets, asteroids—they weren't there at the beginning. Where did they come from?
A Tiny, Hot Beginning
When the universe began, it was just hot, tiny particles mixed with light and energy. It was nothing like what we see now. As everything expanded and took up more space, it cooled down.
The tiny particles grouped together. They formed atoms. Then those atoms grouped together. Over lots of time, atoms came together to form stars and galaxies.
The first stars created bigger atoms and groups of atoms. That led to more stars being born. At the same time, galaxies were crashing and grouping together. As new stars were being born and dying, then things like asteroids, comets, planets, and black holes formed!
A baseball is hit straight up in the air with an initial velocity of 38 m/s
How long does it stay in the air?
How high does it go?
Answers
The time of motion or time spent in air by the baseball is 7.76 seconds.
The maximum height attained by the baseball is 73.67 m.
The given parameters;
initial velocity of the baseball, u = 38 m/sThe time of motion of the baseball is calculated using the first kinematic equation as follows;
v = u - gt
where;
t is the time to reach maximum heightv is the final velocity of the ball at the maximum height = 00 = u -gt
gt = u
\(t = \frac{u}{g} \\\\\t = \frac{38}{9.8} \\\\t = 3.88 \ s\)
The time spent in the air = time of entire motion = 2(3.88 s) = 7.76 seconds
The maximum height attained by the ball is calculated using the second kinematic equation as shown below;
\(h = ut -\frac{1}{2} gt^2\\\\h = (38\times 3.88)\ - \ (0.5 \times 9.8 \times 3.88^2)\\\\h = 73.67 \ m\)
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When jeremiah stands in a swimming pool and looks at hid feet, his legs appear to be bent. Which is the term for this phenomenon?
A. Diffraction
B. Dispersion
C. Reflection
D. Refraction
Answers
Explanation: Refraction occurs when a medium bends the light rays of an object. Like water for instance as an example of a medium.
the change in resistance of a metallic conductor at temperature below 0°C is
A. Linear
B. Non linear
C. Curve
D. Curvilinear
Answers
Answer:
A: Linear
Explanation:
Formula for Resistance of a metallic conductor is given as;
R = R_o(1 + αΔT)
Where;
R_o is the original resistance
R is the final resistance after change in temperature
ΔT is change in temperature
α is coefficient of linear expansion
Now, from the formula given, we can see that the change in resistance is directly proportional to the change in temperature.
Thus, the higher the final temperature, the more the change in resistance and the lower the final temperature, the lesser the change in resistance.
Thus, for temperature less than zero, since the change is resistance is directly proportional to the temperature, it means it follows a linear relationship.
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
Find the magnitude 2 of the acceleration of block 2.
Answers
The magnitude of acceleration of block 2 is 4.67 m/s².
The diagram representing the blocks is shown below:It can be observed that the two blocks are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.Now let's derive the equation for acceleration, a2.
A key concept that must be understood to solve the problem is the difference in tension on either side of the string. Since the pulley is massless and frictionless, the tension must be the same on both sides. We can derive this concept using the following equations:Tension on block 1 side:T1 = m1(g)sin(1) - m1(g)cos(1) * f1Tension on block 2 side:T2 = m2(g)sin(2) + m2(g)cos(2) * f2Where g is acceleration due to gravity, which is equal to 9.8 m/s².Then:T1 = T2T1 + m1(g)cos(1) * f1 = m2(g)sin(2) + m2(g)cos(2) * f2Substitute the values into the above equation:2.25(9.8)cos(42.5) * 0.205 + 2.25(9.8)sin(42.5) = 5.55(9.8)sin(33.5) + 5.55(9.8)cos(33.5) * 0.105T2 = 25.836 N (correct to 3 significant figures)Now we can find the acceleration of block 2.
The acceleration of block 1 can be determined using the following equation:a1 = g(sin(1) - f1 cos(1))a1 = 9.8(sin(42.5) - 0.205cos(42.5))a1 = 5.748 m/s² (correct to 3 significant figures)Using the equation for acceleration of block 2:a2 = (T1 - T2) / m2a2 = (25.836 - 0) / 5.55a2 = 4.667 m/s² (correct to 3 significant figures).
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A brick is dropped from a high scaffold.
a. How far does the brick fall during this time?
Answers
Answer:
a: after 1 seconds it will have fallen 0.2452
after 2 seconds it will have fallen 0.981
after 3 seconds it will have fallen 2.2072
after 4 seconds it will have fallen 3.924
Explanation:
the formula for acceleration due to gravity is (ignoring friction I think)
g = G*M/R^2
earths gravitational constant is about 9.807
g = 9.807*M/R^2
The average weight of a brick is 5 pounds and I'm going to say it's 10 feet off the ground.
g = 9.807*5/10^2. g = 0.4905 so every second the brick will go 0.4905 fps faster. (fps means feet per second.)
after 1 seconds it will have fallen 0.2452
after 2 seconds it will have fallen 0.981
after 3 seconds it will have fallen 2.2072
after 4 seconds it will have fallen 3.924
Find the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth.
Answers
Answer:
Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.
Explanation:
A geosynchronous circular orbit is an orbit in which a satellite revolves around the Earth once every 24 hours so that it appears to be stationary in the sky relative to an observer on the ground. The radius of such an orbit is known as the geostationary radius and is approximately 42,164 km or 3.58 x 10^7 m above the surface of the Earth.
To find the orbital speed of a satellite in a geosynchronous circular orbit, we can use the formula:
v = (GM / r)^0.5
Where v is the orbital speed, G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), M is the mass of the Earth (5.97 x 10^24 kg), and r is the distance from the center of the Earth to the satellite (in this case, r = 3.58 x 10^7 m + radius of the Earth).
The radius of the Earth is approximately 6,371 km or 6.371 x 10^6 m. Therefore, the distance from the center of the Earth to the satellite is:
r = 3.58 x 10^7 m + 6.371 x 10^6 m
r = 4.217 x 10^7 m
Now we can plug in the values for G, M, and r into the formula and solve for v:
v = (GM / r)^0.5
v = [(6.674 x 10^-11 N m^2/kg^2) x (5.97 x 10^24 kg) / (4.217 x 10^7 m)]^0.5
v = 3.07 x 10^3 m/s
Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.
Explanation:
The orbital speed of a satellite in a circular orbit around the Earth can be found using the following formula:
v = sqrt(G*M/R)
where G is the gravitational constant, M is the mass of the Earth, and R is the distance from the center of the Earth to the satellite's orbit.
For a geosynchronous orbit, the satellite has a period of 24 hours, which means it completes one orbit in 24 hours. This corresponds to an orbital radius of:
R = 3.58 x 10^7 m + 6.38 x 10^6 m = 4.22 x 10^7 m
where 6.38 x 10^6 m is the radius of the Earth.
The mass of the Earth is approximately 5.97 x 10^24 kg, and the gravitational constant is approximately 6.6743 x 10^-11 N*(m/kg)^2. Substituting these values into the equation above, we get:
v = sqrt(GM/R) = sqrt(6.6743 x 10^-11 N(m/kg)^2 * 5.97 x 10^24 kg / 4.22 x 10^7 m) = 3074 m/s
Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3074 m/s.
A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?
the answer is 1.87
Answers
Answer:
1.9
Explanation:
A car with a mass of 1200kg is traveling west at 25 m/s collides head on with highway barrier. The car comes to rest in 0.35 seconds . What is the magnitude of the force and the impulse applied to the car
Answers
The magnitude of the force and the impulse applied to the car are 85714 N and 30000 N-s respectively.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The magnitude of the force applied to the car = change in momentum/time interval
= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second
= 85714 N.
The impulse applied to the car = change in momentum
= (1200 kg × 25 m/s - 1200 kg×0)
= 30000 N-s.
Learn more about force here:
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Air is a mixture of what?
1. Elements
2. Atoms
3. Compounds
4. Molecules
Answers
Answer:
gases......is the right ans. it means elements..
An electron in the first energy level of the electron cloud has an electron in the third energy level
Answers
Answer:
a lower energy than
Explanation:
sorry im a month late but is lower energy than
What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?
Question 16 options:
A)
12,000 J
B)
2,940 J
C)
6,000 J
D)
5,880 J
Answers
the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is 6,000 J. Option C is correct answer.
The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:
K.E = 1/2 mv²
Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object
Putting the given values in the above formula:
K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules
The correct answer is C.
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