you drop a 14-gram ball from a height of 1.5 m and it only bounces back to a height of 0.85 m. what was the total impulse (magnitude only; in kg m/s) on the ball when it hit the floor?
Answers
The total impulse that acts on the ball when it is thrown from a height of 1.5 m and bounces to 0.85 m is 0.0189 kg m/s.
Impulse refers to the force acting on the body over time. It can also be described as the change of momentum of a body.
i.e. I = Δp = mΔv
where I is the impulse on the body
p is the momentum of the body
m is the mass of the body
v is the velocity of the body
To calculate impulse acting on the body, one needs to calculate the velocity of the ball just before and after hitting the floor
According to the third equation of motion,
\(2as=v^2-u^2\)
where s is the displacement of the mass
u is the initial velocity
v is the final velocity
a is the acceleration
Velocity before hitting (v) = \(v_1\)
Height or distance traveled (s) = 1.5 m
u = 0 m/s
a = g = 10 \(m/s^2\)
\(2*10*1.5 = 0 - v_1^2\\30 = v_1^2\\v_1 = \sqrt{30} = 5.47 m/s\)
Velocity after hitting (u) = \(v_2\)
v = 0m/s
height (s) = 8.5 m
a = g = 10 \(m/s^2\)
\(2*10*8.5=v_2^2-0\\17 = v_2^2\\v_2 = \sqrt{17} = 4.12 m/s\)
Thus impulse = mass *change in velocity
= 0.014 * (5.47 - 4.12)
=0.0189 kg m/s
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The total impulse (magnitude only) on the ball when it hit the floor is approximately 0.133 kg m/s
Answer -To find the total impulse on the 14-gram ball when it hit the floor, we'll first need to calculate its change in velocity.
Initial velocity (v1) can be found using the equation: v1 = √(2gh1), where g is the acceleration due to gravity (9.81 m/s^2) and h1 is the initial height (1.5 m).
v1 = √(2 * 9.81 * 1.5) ≈ 5.42 m/s (downward)
Final velocity (v2) can be found similarly: v2 = √(2gh2), where h2 is the final height (0.85 m).
v2 = √(2 * 9.81 * 0.85) ≈ 4.09 m/s (upward)
Now, we can calculate the change in velocity (∆v) by summing the magnitudes of v1 and v2:
∆v = 5.42 + 4.09 = 9.51 m/s
To find the total impulse, we'll use the equation: Impulse = m∆v, where m is the mass of the ball (converted to kg).
m = 14 g * (1 kg / 1000 g) = 0.014 kg
Impulse = 0.014 kg * 9.51 m/s ≈ 0.133 kg m/s
The total impulse (magnitude only) on the ball when it hit the floor is approximately 0.133 kg m/s.
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Related Questions
An Athelice complete :Round of a circular track of diameter 200m in base Distance travelled by athletes And displacement
Answers
Answer:
Distance = 1256 m
Displacement = 0
Explanation:
Distance :
Distance may be defined as the actual length between two points along its path.
It is a scalar quantity and its value can be positive or zero.
Displacement :
Displacement is defined as the shortest length between two point , i.e. between the initial point and the final point.
It is a vector quantity and it has values which can be either positive or negative or zero.
From the question, the diameter of the circular track is, r = 200 m
∴ Distance travelled by an athlete is = circumference of the circular track
= 2πr
= 2 x 3.14 x 200
= 1256 m
Displacement = 0 (since the original point coincides with the final point).
A golf ball with a mass of 45 g is rolling down a hill. At the bottom of the hill, its speed is 6 m/s. What is its GPE?
Answers
Answer:
GPE = 0 (when the golf is downhill)
GPE = 0.81 [J](when the golf is at the highest point of the hill)
Explanation:
In order to solve this problem, we must use the principle of energy conservation, which tells us that energy is transformed from kinetic energy to potential energy or vice versa.
We must define a reference energy point, where at this point the potential energy is zero. Let's take this point at the bottom of the hill.
At this point where the potential energy is zero, all the potential energy will have been transformed into kinetic energy, at this point the velocity will be maximum.
\(E_k=E_p\\where:\\E_{p}=m*g*h\\E_{k}=\frac{1}{2} *m*v^{2}\)
where:
m = mass = 45 [g] = 0.045 [kg]
g = gravity acceleration = 9.81 {m/s²]
h = elevation [m]
v = velocity = 6 [m/s]
\(E_{k}=\frac{1}{2}*0.045*(6)^{2} \\E_{k}=E_{p}=0.81 [J]\)
GPE = 0 (when the golf is downhill)
GPE = 0.81 [J](when the golf is at the highest point of the hill)
What are the 3 main approaches to the identification of unknown bacteria?
Answers
The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification
What is Phenotypic, Molecular and Biochemical identification?1. Phenotypic identification
Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.
2. Biochemical identification
Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.
3. Molecular identification
Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.
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1. A car has a total mass of 1200 kg and is traveling at 100 km per hour when the driver experience is a brake failure and collides with the barrels. Calculate the change in momentum it will experience whilst coming to a standstill.2. According to GSU's HyperPhysics Project this crash would have been fatal for an average 80 kg person. The safety zone in terms of momentum, ranges from 0 to 1,000 kg per metre per second. Determine the minimum velocity the car can slow down to during a collision with the barrels without the crash being fatal.
Answers
Question 1.
Given:
Mass = 1200 kg
Velocity = 100 km per hour.
Let's find the change in momentum it will expperience.
To find the change in momentum, apply the formula:
\(\Delta p=mv_f-mv_i\)Where:
Δp is the change in momentum
m is the mass of the car = 1200 kg
vf is the final velocity
vi is the initial velocity.
Here, the final velocity is = 0 m/s
The initial velocity is = 100 km/h
Let's convert the initial velocity to m/s.
Where:
1 m/s = 3.6 km/h
100 km/h = 100/3.6 = 27.78 m/s
Input the values into the formula and solve for Δp.
We have:
\(\begin{gathered} \Delta p=(1200\times0)-(1200\times27.78) \\ \\ \Delta p=0-3333.33 \\ \\ \Delta p=-33333.33kg.m\text{ /s} \end{gathered}\)Therefore, the change in momentum is 33333.33 kg.m/s
Question 2.
Since the safety zone for momentum is 0 to 1000 kg.m/s, to find the minimum velocity of the car, substitute 1000 kg.m/s for Δp and solve for the final velocity vf
We have:
\(\begin{gathered} \Delta p=m_{}v_f-mv_i \\ \\ 1000=(1200v_f)-(1200\times27.78) \\ \\ 1000=1200v_f-33333.33_{} \\ \\ v_f=\frac{1000-33333.33}{1200} \\ \\ v_f=-26.94\text{ m/s} \end{gathered}\)Therefore, the minimum velocity the car can slow down to a velocity is 26.94 m/s.
ANSWER:
(a). 33333.33 kg/m.s
(b). 26.94 m/s
Two forces act on an object. One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south. The net force on the object isA. 8 N south.B. 12 N south.C. 20 N north.D. 8 N north.
Answers
Answer:
8 N North.
Explanation:
Given that,
One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south.
We need to find the magnitude of net force acting on the object.
Let North is positive and South is negative.
Net force,
F = 10 N +(-2 N)
= 8 N
So, the magnitude of net force on the object is 8 N and it is in North direction (as it is positive). Hence, the correct option is (d) "8N north".
Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?
A. visible light
B. infrared light
C. X-rays
D. ultraviolet light
Answers
Answer:
we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.
Hence, option A is correct.
Explanation:
Generally, after the storm, we can witness the presence of a rainbow with our naked eyes. Rainbow, visible to our eyes, consists of all the seven constituent colors of white light. Those seven colors range from violet to red, all having different wavelengths. When water particles present in our atmosphere get exposed to light, all the constituent colors of a white light tend to deviate at a variety of angles. It happens due to their refraction through water particles; thus, a spectrum is obtained.
As we cannot see X-rays, UV rays, and infrared waves through our naked eye, visible light is the kind of electromagnetic wave that makes anyone able to see the objects.
Please note that all the constitute colors of a beautiful rainbow associate with the visible region of the electromagnetic spectrum.
Therefore, we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.
Hence, option A is correct.
Answer: A.) Visible light
Explanation: Edge 2020 good luck friend ^__^
a. Ayas mass is 45kg. What is her weight in newtons on Earth?
b. What is Ayas mass on the moon?
c. What is Ayas weight in newtons on the moon?
Answers
a. The Aya's weight on Earth is 441 Newtons.
b. The Aya's mass on the moon would still be 45 kg.
c. Aya's weight on the moon is 72 Newtons.
a. Ayas weight on Earth can be calculated using the formula:
Weight = mass * gravitational acceleration
The gravitational acceleration on Earth is 9.8 m/\(s^2\).
Plugging in the given mass:
Weight = 45 kg * 9.8 m/\(s^2\) = 441 N
Therefore, Ayas' weight on Earth is 441 Newtons.
b. Aya's mass remains the same on the moon as it does on Earth. Therefore, Aya's mass on the moon would still be 45 kg.
c. To calculate Aya's weight on the moon, we need to consider the gravitational acceleration on the moon. The gravitational acceleration on the moon is approximately 1.6 m/\(s^{2}\). Using the same formula:
Weight = mass * gravitational acceleration
Weight = 45 kg * 1.6 m/\(s^{2}\) = 72 N
Therefore, Aya's weight on the moon is 72 Newtons.
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What if? what would be the change in electric potential energy (in j) of the system if the charge q were moved a distance d
Answers
The change in electric potential energy depends on the initial and final positions of the charge, as well as the electric field that exists between those positions.
The change in electric potential energy (ΔU) of a system when a charge q is moved a distance d in an electric field depends on the strength of the field and the magnitude and direction of the charge.
The formula for calculating the change in electric potential energy is:
\(\triangle U = q * E * d cos\theta\)
where q is the magnitude of the charge, E is the strength of the electric field, d is the distance the charge is moved, and θ is the angle between the direction of the field and the direction of the movement of the charge.
If the charge q is positive and is moved in the direction of the electric field, then θ = 0 and cos(θ) = 1, and the formula simplifies to:
\(\triangle U = q * E * d\)
If the charge q is negative and is moved in the direction of the electric field, then θ = 180 degrees and cos(θ) = -1, and the formula becomes:
\(\triangle U = -q * E * d\)
If the charge is moved perpendicular to the electric field, then θ = 90 degrees and cos(θ) = 0, and the change in electric potential energy is zero.
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4. The batteries on electric vehicles are recharged using electricity from either a wall socket or dedicated charging
unit.
A) O True
B) O False
Answers
Answer:
Hey!
Your answer is A) TRUE!
Explanation:
The electricity in this instance is called "grid-electricity" because it has come from a generation plant elsewhere instead of recharging the batteries via Kinetic/Potential energy...
A teacher asks her students to jump off of the ground. Once the students complete the task, she says, "All of you just made Earth accelerate." Using Newton's three laws, explain how the teacher is correct even though no one saw the Earth move.
Answers
Answer:
Explained below
Explanation:
A) Newton's first law of motion states that an object will remain at rest or continue in its current state of motion except it is acted upon by another force.
Now using this law, when you jump off the ground, the earth will move a tiny bit and accelerate due to the force applied by the jumping.
B) Newton's 2nd law states that the acceleration of a system is directly proportional to the net external force acting on that system, is in the same direction with it and also inversely proportional to the mass.
In this case, when one jumps, an external force is exerted on the earth and we are told it is directly proportional to the acceleration of the system which in this case it's the earth, then it means that there is some motion by the earth even though you didn't see it move.
C) Newton's third law of motion states that to every action, there is an equal and opposite reaction.
In this case the motion of the jumper will lead to an equal and opposite reaction of the earth.
How do different elements of the
human body work together?
Answers
Answer:
There are several ways to consider the composition of the human body, including the elements, type of molecule, or type of cells. Most of the human body is made up of water and H2O, with bone cells being comprised of 31% water and the lungs 83%.1 Therefore, it isn't surprising that most of the human body's mass is oxygen. Carbon, the basic unit for organic molecules, comes in second. 96.2% of the mass of the human body is made up of just four elements: oxygen, carbon, hydrogen, and nitrogen.
Explanation:
Elements are essential units that are the basic constituents of all living and non-living beings. They are the core of the universe. Every tiny or huge particle comprises elements. Our body is built up of five major elements: Carbon, Hydrogen, Oxygen, Nitrogen and calcium.
can an object under constant acceleration come to rest and stay at rest?
Answers
Explanation:
No. If the object stays at rest, its acceleration is 0. So the acceleration must have changed.
Exam
You push on a shovel then the
shovel pushes on dirt. The force
you apply to the shovel is the
input force. The shovel then
pushing on the dirt is known as
what?
A. Output work
B. Input work
C. Input force
D. Output force
Answers
explanation:
Explanation: for example, you exert force on the handle of a shovel when you use it to lift soil. You exert the improve force that moves the machine on a certain distance, called the input distance. The force the machine exerts on the object (DIRT) is called the output force.
Jim traveled the first 3 hours of his journey at speed of 60 mph and the remaining 5 hours at 24 mph. How long is the whole journey in miles?
Answers
Answer:
300 miles
Explanation:
3*60 + 5*24 = 300
If calcium reacts with a nonmetal, what will the charge of the calcium cation be?
Answers
If calcium reacts with a nonmetal, the charge of the calcium cation be +2.
What is cation?A cation has a net positive charge because it has more protons than electrons. One or more electrons must be lost in order for a cation to develop; normally, these electrons are drawn away by atoms having a larger affinity for them. The chemical symbol is followed by the number of lost electrons and the ion's charge.
When calcium reacts with a nonmetal, calcium (Ca) loses two electrons to become Ca²⁺. Hence, the charge of the calcium cation be +2 when calcium reacts with a nonmetal.
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3. Assume that each atom of copper contributes one free electron. The density of Cu is 9g/cc and atomic weight is 63g. if the current flowing through the copper wire of 1mm dia is 1.1A, drift velocity of electrons will be-
Answers
Answer:
\(v_d=0.1\ mm/s\)
Explanation:
The current flowing through a conductor is given as:
\(I=neAv_d\\where\ A =area\ of\ conductor=\pi d^2/4=\pi(1*10^-3)^2/4=7.85*10^{-7}\\\\I=current\ flowing\ through\ the \ conductor=1.1A\\\\e=charge\ of \ electron=1.602*10^{-19}\\\\N_A=Avogadro \ constant=6.023*10^{23}\ mol^{-1}\\\\Density=9*10^3kg/m^3=9*10^6g/m^3\\\\n=\frac{6.023*10^{23}\ mol^{-1}*9*10^6\ g/m^3}{63\ g/mol} =8.604*10^{28}\ m^{3}\\\\v_d=\frac{I}{neA}=\frac{1.1}{8.604*10^{28}*1.602*10^{-19}*7.85*10^{-7}}=0.0001\ m/s\\\\v_d=0.1\ mm/s\)
do you know this???
ill give you 20 points
Answers
Answer:
it looks like B on the first one and D on the second hope this helps!!
Explanation:
what do you predict in activity 2-2 when the coil is pulled awway frm the north pole of the magnet
Answers
In Activity 2-2, there will be a generated electric current in the coil due to the induced EMF when the coil is pulled away from the north pole of the magnet.
1. The magnetic field through the coil will change as the coil moves further away from the magnet's north pole. This change in magnetic field induces an electromotive force (EMF) in the coil according to Faraday's Law.
2. As the coil moves away from the north pole of the magnet, the direction of the induced EMF will be such that it opposes the change in a magnetic field. This is in accordance with Lenz's Law.
3. As a result, an electric current will be generated in the coil due to the induced EMF. The direction of the current will be determined by the right-hand rule, with the thumb pointing in the direction of the induced EMF and the fingers curling in the direction of the current.
4. The magnitude of the induced EMF and the resulting current will decrease as the coil moves further away from the magnet's north pole. This is because the rate of change in the magnetic field will decrease with distance.
In summary, when the coil is pulled away from the north pole of the magnet in Activity 2-2, an induced EMF and electric current will be generated in the coil. The magnitude of the induced EMF and current will decrease as the coil moves further away from the magnet's north pole.
Therefore, in Activity 2-2, there will be a generated electric current in the coil due to the induced EMF when the coil is pulled away from the north pole of the magnet.
Here is the complete question:
Activity 2-2: Coil Moving Near a Magnet
1. Mount the magnet close to the coil so the magnet can't move.
2. When the coil is connected to the meter in exactly the same way as in Activity 2-1 make observations to test Prediction 2-2. Start or end with one pole of the magnet near the center of the coil.
What do you predict in activity 2-2 when the coil is pulled away from the north pole of the magnet?
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Kamala made a table to describe parts of the electromagnetic spectrum. A 3-column table with 4 rows. The first column labeled wave has entries visible, microwaves, infrared, gamma rays. The second column labeled frequency has entries medium, low, low, very low. The third column labeled wavelength has entries medium, long, long, very short. What mistake did kamala make? gamma rays should have a very high frequency, not a very low frequency. Visible light should have a low frequency and a long wavelength. Infrared light should have a short wavelength, not a long wavelength. Microwaves should have a high frequency and a short wavelength.
Answers
The mistake that Kamala made from the table is that Gamma rays should have a very high frequency, not a very low frequency.
The electromagnetic spectrum is what?The grouping of electromagnetic radiations in the electromagnetic spectrum is done according to diminishing or increasing frequency or wavelength.
The following are some examples of electromagnetic radiations depending on increasing wavelength:
Gamma raysX raysultrasound wavesobservable lightIR radiationMicrowaveswaves on radioHow do gamma rays work?These are the radiation waves produced by the radioactive disintegration of atomic nuclei.
These rays have high frequencies. The frequency happens 1019 times every second.
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Answer: gamma rays should have a very high frequency, not a very low frequency.
Explanation:
In the diagram, q1 = -6.39*10^_9 C and q2 = +3.22*10^-9 C. What is the electric potential at point P? Include a + or - sign.
Answers
To determine the + or - sign of the electric potential, we need to know the signs and positions of the charges relative to point P.
To calculate the electric potential at point P, we need to use the equation for electric potential due to a point charge. The formula is:
V = k * q / r
Where:
V is the electric potential
k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2)
q is the charge
r is the distance between the point charge and the point at which we are calculating the electric potential.
Since we have two charges, q1 and q2, at point P, we need to calculate the electric potential due to each charge and then add them together.
Let's assume that point P is located at a distance r1 from charge q1 and a distance r2 from charge q2.
Electric potential due to q1:
V1 = k * q1 / r1
Electric potential due to q2:
V2 = k * q2 / r2
To find the total electric potential at point P, we add the potentials due to each charge:
V_total = V1 + V2
To determine the + or - sign of the electric potential, we need to know the signs and positions of the charges relative to point P. Please provide additional information about the positions of point P and the charges q1 and q2 in the diagram.
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how many molecules are in 3 moles of CO2
Answers
Answer:
1.806 x 10^24 molecules
Explanation:
1 mole of CO2 has 6.02 x 10^23 molecules
3 mole of CO2 has 3x6.02x10^23 molecuels = 1.806 x 10^24 molecules
The 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
One mole of \(CO_{2}\) contains \(6.022*10^{23}\) molecules.
In 3 moles of \(CO_{2}\) ,
\(=3*6.022*10^{23}=1.8066*10^{24}\) molecules.
Hence, the 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
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explain why thermal energy is always transferred whenever work is done
Answers
Answer:
Heat
Explanation:
All materials have go some sort of heat.
Answer:Since the friction force is non-conservative as potential energy. All the work done by the friction forces results in a transfer of energy into thermal energy of the box floor system.
Explanation:
Does the velocity of the center of mass change in a collision.
Answers
Answer:
The velocity of the system's center of mass does not change, as long as the system is closed. The system moves as if all the mass is concentrated at a single point.
What is the most underrated part of the overhand float serve a. Stance b. Toss c. Swing d. Follow-through
Answers
There are different kinds of sport. The the most underrated part of the overhand float serve is Follow-through.
How do a person follow through on a volleyball serve?One can Follow-through by bring their the ball in front of the serving arm's shoulder (Their hand) and they should also keep their hips square to the net.
Here slowly toss the volleyball for about two to four feet high, in front of one's serving shoulder and as the person contact the ball, one has to follow through until your serving arm is is said to be fully extended out.
This point is known to be underrated because it is not as important as the other aspect such as stance, toss and Swing.
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What is the acceleration of a 10 kg block that experiences a 50 N applied force as it slides across a
horizontal surface where the coefficient of kinetic friction between it and the surface is 0.10?
Answers
4.02 m/sec² is the acceleration of a 10 kg block that experiences a 50 N applied force as it slides across a horizontal surface.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
force = 50 N - frictional force = ma
50 - 9.8 = ma
a = 40.2/10
a = 4.02 m/sec²
4.02 m/sec² is the acceleration of a 10 kg block that experiences a 50 N applied force as it slides across a horizontal surface.
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A person pushes a large block on a horizontal ice surface in a straight line to the right with constant speed, as shown above. The mass of the block is 10kg and frictional forces between the block and the ice are negligible. However, the block has a wide cross-sectional area such that air resistance acting on the block cannot be neglected. The opposite is true for the person: air resistance on the person is negligible, but the person’s shoes do not slip on the ice. The table shows the force exerted by the person on the block for several values of constant speed. Force of person’s push (N) Constant speed of block (m/s) ±0.05 20 1.25 40 2.51 60 3.73 80 5.00 (a) A student claims that the data show that the magnitude of the force of air resistance is proportional to the speed of the object, within experimental uncertainty. Use physics principles to explain whether the claim is correct. 0 / 10000 Word Limit Question 2 (b) As the person pushes the block, the person moves with the same constant speed as the block. Consider the scenario in which the person’s speed is 5.00 m/s. i. On the dot below, which represents the person, draw and label the forces (not components) exerted on the person. Each force must be represented by a distinct arrow starting on, and pointing away from, the dot. The figure presents a large dot. 0 / 10000 Word Limit Question 3 ii. The person now stops and releases the block. Determine the magnitude and direction of the block’s acceleration at the instant the block is released.
Answers
Newton's second law and graphical analysis allow to find the results for the questions about the air resistance force are:
A) The air resistance is proportional to the velocity because the graph of force vs velocity is linear.
B) In the adjoint we see the free body diagram on the man, where all the forces are in equilibrium.
C) The block acceleration is: a = - 0.03 m/s²
Part A
Newton's second law establishes a relationship between the net force and the product of the mass and the acceleration of the body
∑ F = m a
Where the bold letters indicate vectors, F is the forces, m the mass and the acceleration of the body.
Indicates that the only significant force is air resistance.
∑ F = \(f_{air\ resistence}\)
They give a table of force versus speed.
F (N) v (m / s)
0.05 20
1.25 40
2.51 60
3.73 80
In the attachment we make a graph of the force versus velocity and we see that it is a linear relationship, therefore the air resistance must be proportional to the value of the body, an expression can be:
f_{air\ resistence} = - b v
The results of the equation of the linear regression is:
f = 0.0615 v -1.19
For this case the term b found from the linear regression is
b = 0.0615 N s / m
Part 2
in the second attachment see a free body diagram of the force on the person
The normal force and weight are in balance.
The force applied by the person on the box (F) and there is a force applied by the box on the person (F '), are in equilibrium since the speed is constant, therefore the acceleration is zero.
Part 3
Indicate that the person stops, ask the acceleration of the block of mass 10 kg for the speed of 5 m / s.
Let's write Newton's second law for the x-axis.
f_{air\ resistence} = m a
- b v = m a
a = \(- \frac{b v}{m}\)
Let's calculate
a = \(- \frac{0.0615 \ 5}{10}\)
a = -0.03 m / a²
The negative sign indicates that the block is stopping.
In conclusion, using Newton's second law and graphical analysis we can find the results for the questions about the air resistance force are:
A) The air resistance is proportional to the velocity because the graph of force vs velocity is linear.
B) In the adjoint we see the free body diagram on the man, where all the forces are in equilibrium.
C) The block acceleration is: a = - 0.03 m / s²
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Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy of the skateboarder as they ride up and down the ramp.
Elisa: I think the skateboarder has the more total energy at the top bottom of the ramp than the bottom of the ramp.
Raymond: I think the skateboarder has the same total energy at all points on the ramp.
Which student do you agree with? Why?
Answers
Answer:
The correct option is;
Raymond: I think the skateboarder has the same total energy at all points on the ramp
Explanation:
The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder
Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.
However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.
A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy
Answers
Answer:
42.69J
Explanation:
The question is not complete, here the complete one
A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy
and it velocity vx= -3.4m/s
Step one:
given
mass m= 2.3kg
spring constant k= 120 N/m
x= 0.7m
vx=-3.4m/s
Step two:
The expression for the total energy is
\(Energy= 1/2mv^2 + 1/2Kx^2\)
substituting we have
\(Energy= 1/2*2.3*3.4^2+1/2*120*0.7^2\)
\(Energy= 13.29+29.4\\\\Energy=42.69J\)
Which best contrasts Newton's and Einstein's ideas?
Newton believed that mass tells objects how to move. Einstein believed that the curvature of space-time tells force how to
move objects.
Newton believed that force tells mass how to move. Einstein believed that the curvature of space-time tells velocity how to
change.
Newton believed that distance tells gravity how much force to exert. Einstein believed that distance tells space-time how to
curve.
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Answers
Answer:
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Explanation:
Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.
Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.
This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.
Answer:
first one is for the assignment second is for the quiz
Explanation:
Assignment - C.
Quiz - D.
Conservation of momentum - Internal Motion Problem A man with a mass of 70 kg
is standing on the front end of a flat railroad car, which has a mass of 1,000 kg
and a length of 10 m
. The railroad car is initially at rest relative to the track. The man then walks from one end of the car t
to the other at a speed of 1.0 m/s
relative to the track. Assume there is no friction in the wheels of the railroad car. (a) What happens to the cart while the man is walking? (b) How fast does the cart move? (c) What happens when the man stops at the rear of the car?
Answers
On conservation of momentum:
(a) The cart goes in the opposite direction as the man does.
(b) With a speed of 0.07 m/s, the cart proceeds in the opposite direction as the guy.
(c) the cart starts moving in the forward direction with the same velocity of 0.07 m/s.
How to determine conservation of momentum?(a) As per the conservation of momentum, the total momentum of the system is conserved. Initially, the system was at rest, but when the man starts walking towards the other end, he gains some momentum in the forward direction, which the cart has to compensate for. So, the cart moves in the opposite direction to that of the man's motion.
(b) Assume that the man moves a distance of 10 m, i.e., the length of the cart.
Therefore, the total distance covered by the man is 20 m (10 m forward and 10 m backward).
The momentum gained by the man while walking forward is (70 kg) x (1.0 m/s) = 70 kg m/s.
As the total momentum of the system is conserved, the cart gains an equal and opposite momentum of -70 kg m/s.
The mass of the cart is 1,000 kg, so its velocity can be calculated using the conservation of momentum formula:
Total initial momentum = Total final momentum
0 = (70 kg) x (1.0 m/s) + (1,000 kg) x V
V = -0.07 m/s
So, the cart moves in the opposite direction to that of the man's motion with a speed of 0.07 m/s.
(c) When the guy comes to a complete halt at the back of the automobile, he loses the momentum he got while going forward, and the cart obtains equal and opposite motion. As a result, the cart begins going ahead at the same velocity of 0.07 m/s.
Find out more on Conservation of momentum here: https://brainly.com/question/7538238
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