You dissolve 0.64 g of potassium chloride (KCl) in 725 ml of water.
What is the molarity of the solution?
(From the periodic table: 1 mol K = 39.10 g; 1 mol Cl = 35.453 g)
Enter the value rounded to three decimal places with no units
Will give BRAINLEST

Answers

Answer 1

Answer:

0.012 M

Explanation:

Step 1: Given and required data

Mass of KCl (m): 0.64 gVolume of water (V): 725 mL (We will assume it is equal to the volume of the solution)Molar mass of KCl (M): 74.553 g/mol

Step 2: Calculate the moles (n) of solute (KCl)

We will use the following expression.

n = m/M = 0.64 g / (74.553 g/mol) = 8.6 × 10⁻³ mol

Step 3: Calculate the molar concentration (C) of the solution

The molarity is equal to the moles of solute divided by the liters of solution.

C = 8.6 × 10⁻³ mol/0.725 L = 0.012 M


Related Questions

Astronomers made two observations of the Moon that were several days apart. Their observations are shown in the diagram above. The light part of the Moon appeared to get larger over time. Why did this happen?

Answers

Answer:

Explanation:

As the earth revolves around the sun, and the moon revolves around the earth, the intensity of sunlight hitting the moon changes over time. This explains why we get the phases of the moon. The answer as to why, is because the moon was moving towards a state of being a "full moon."

As a roller coaster goes downhill.

A. kinetic energy is converted into potential energy

B. potential energy is converted into kinetic energy

C. electrical energy is converted into potential energy

D. potential energy is converted into electrical energy

Answers

Explanation:

C electrical energy is converted into potential energy

Answer:

I can confirm it is, Potential energy is converted into kinetic energy.

Explanation:

At 7:00 A.M., a patient receives a 1.00-mg dose of I-131 to treat thyroid cancer.

If the nuclide has a half-life of 8.0 days, what mass of the nuclide remains in the patient at 10:00 P.M. the next day? (Assume no excretion of the nuclide from the body.)

Answers

Approximately 0.874 mg of I-131 remains in the patient's body at 10:00 P.M. the next day.

First, we need to calculate how many half-lives have elapsed from 7:00 A.M. to 10:00 P.M. the next day, which is approximately 33 hours.

33 hours / 24 hours per day = 1.375 days

1.375 days / 8.0 days per half-life = 0.172

This means that approximately 0.172 half-lives have elapsed since the initial dose.

Next, we can calculate the fraction of I-131 that remains in the patient's body using the radioactive decay equation:

\(fraction\ remaining = (1/2)^{(number\ of\ half-lives\ elapsed)}\)

\(fraction\ remaining = (1/2)^{0.172}\\fraction\ remaining = 0.874\)

Finally, we can calculate the mass of I-131 that remains in the patient's body:

mass remaining = initial mass x fraction remaining

mass remaining = 1.00 mg x 0.874

mass remaining = 0.874 mg

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How many grams are there in 1.00x10 24 molecules of BCI3

Answers

Answer:

194.569 g

Explanation:

6.022×10^23 molecules = 117.17 g

1 molecules = 117.17/ 6.022×10^23

So, 1×10^24 molecules = (117.17×1×10^24)/(6.022×10^23)= 194.569 g

Please help me I don’t have idea,please

Please help me I dont have idea,please

Answers

4.4 a. The metal that the main part of the garden fork has been made from is iron. The correct option is B

b. The chemical name for rust is hydrated iron (iii) oxide

c. One way of preventing the fork from rusting is by painting the fork.

4.5 Based on the given equations;

a. the equation that produces a metal oxide is equation D.

b. the equation that is a neutralization reaction is equation B.

c. the equation that is a burning reaction is equation A.

The complete equation for the given equations are:

d. sodium + water → sodium hydroxide + hydrogen

e copper carbonate + sulfuric acid → copper sulfate + carbon dioxide + water

f. sulfur + oxygen → sulfur dioxide

What is rust?

Rust is an iron oxide, a typically reddish-brown oxide created when iron and oxygen react catalytically with moisture from the air or water.

Iron(III) oxide-hydroxide and hydrated iron(III) oxides make up rust, which is often linked to the corrosion of refined iron.

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The figure shows the metabolic pathway for aerobic respiration. What part of the process does box E represent?
A. Pyruvate oxidation and the formation of acetyl-CoA
B. Electron transport via NADH and FADH2
C. Citric acid cycle
D. Glycolysis​

The figure shows the metabolic pathway for aerobic respiration. What part of the process does box E represent?A.

Answers

Answer:

A

Explanation:

The figure shows the metabolic pathway for aerobic respiration. What part of the process does box E represent?A.

Answer:

b

Explanation:

A 50.0 mL sample of 0.00200 M AgNO3 is added to 50.0 mL of 0.0100 M NaIO3. What is the equilibrium concentration of Ag in solution

Answers

The equilibrium concentration of Ag⁺ in the solution is : 7.5 * 10⁻⁶ M

Given that :

Ksp for AgIO₃ = 3 * 10⁻⁸

Determine the equilibrium concentration of Ag in the solution

First step : Calculate the concentration of Ag⁺ and IO⁻₃ in the solution

[ Ag⁺ ] = ( mmol Ag⁺ / mL solution )

          = ( 50 * 0.00200 / 100 mL ) = 0.001 M

[ IO⁻₃ ] = ( mmol IO⁻₃ / mL solution )

           = ( 50 * 0.0100 / 100 mL )  = 0.005 M

Next determine the Ionic product ( Q )

Q = [ Ag⁺ ] [ IO⁻₃ ]

   = 0.001 * 0.005

   = 5 * 10⁻⁶  

Since the value of Q is > Ksp a precipitate ( IO⁻₃ )  will be formed after the completion of the precipitation reaction

Therefore the concentration of the excess  IO⁻₃  = 0.400 mmol / 100 mL

                                                                                 = 0.004 M

Second step : considering the initial and final concentrations

Initial concentrations ( mol/ L )                  Final concentrations ( mol/L )

[ Ag⁺ ] = 0 M                                                  [ Ag⁺ ]  = x

[ IO⁻₃ ] = 0.004 M                                          [ IO⁻₃ ] = 0.004 + x

Final step : Determine the equilibrium concentration of Ag in the solution

Ksp = 3 * 10⁻⁸ = [ Ag⁺ ]  [ IO⁻₃ ]

                      =  ( x ) ( 0.004 + x )

Therefore x = 7.5 * 10⁻⁶ ( Equilibrium concentration of Ag in the solution )

Hence we can conclude that The equilibrium concentration of Ag⁺ in the solution is : 7.5 * 10⁻⁶ M

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How many g of a 5.0% by weight NaCl solution are needed to give 3.2 g NaCl?

Answers

Answer:

1.12

Explanation:

The pictures show butter and water in solid states. The melting point of each substance is shown.

Students put solid butter and solid water on a table. The air temperature around the table is 20°C.

Answers

Students put solid butter and solid water on a table. The air temperature around the table is 20°C. After two hours, The butter will remain a solid, and the water will become a liquid. Therefore, option B is correct.

What do you mean by states of matter ?

A state of matter is one of the various forms that matter can take. In everyday life, four states of matter are visible: solid, liquid, gas, and plasma.

On a table, students placed solid butter and solid water. The temperature of the air around the table is 20°C. The butter will remain solid after two hours, while the water will become liquid.

Thus, option B is correct.

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Your question is incomplete, most probably your question was

The pictures show butter and water in solid states. The melting point of each substance is shown.

Students put solid butter and solid water on a table. The air temperature around the table is 20°C.

A. The butter and water will both become liquids.

B. The butter will remain a solid, and the water will become a liquid.

C. The butter and water will both remain solids.

D. The butter will become a liquid, and the water will remain a solid.

g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass. Must show your work on scratch paper to receive credit.

Answers

Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

why does glass containing an iced beverage feel cold

Answers

Answer:

Molecules in the skin are moving faster than molecules in the glass.

Explanation:

Put it in your own words.

Answer:

The energy from the ice transferred to the glass.

How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O?

Answers

Answer:

The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

C(s) + H2O(g) -> CO(g) + H2(g)

According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.

First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.

Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles

As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.

The molar mass of hydrogen (H2) is approximately 2 grams/mole.

So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams

Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.

Explanation:

Approximations followed for answer.

please help me out with this really need it there's more questions as well so if anyone could please contact me and help me out would greatly appreciate​

please help me out with this really need it there's more questions as well so if anyone could please

Answers

Answer:

1.) 2 Fe (s) + O2 (g) --> 2FeO (s)

2.) 4 Fe (s) + 3O2 (g) --> 2 Fe2O3

Which statement best describes an example of selective breeding?

A. People grow many radish plants from a package of radish seeds.

B. People use viruses to place certain genes in the cells of plant
tissues O

C. People use enzymes to cut DNA into pieces that are put back together.

D. People grow rose plants whose flowers have petals of a specific color..​

Answers

Answer:

D, the others are either genetic modification or no selection

Explanation:

It is an assignment question, so please check it properly to answer it and do use graph to explain it better!

It is an assignment question, so please check it properly to answer it and do use graph to explain it

Answers

The instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

To find the instantaneous rate of reaction at 17 minutes, we can use the concept of differential calculus and estimate the slope of the tangent line at t=17 on the graph of rate versus time.

To do this, we can use the formula for the slope of a line

slope = (change in y) / (change in x)

In this case, the "y" values are the rates of reaction and the "x" values are the times. We want to find the slope at t=17, so we can choose two points that are very close to t=17, such as t=15 and t=20. Then, we can use these values to estimate the slope at t=17

slope = (rate at 20 min - rate at 15 min) / (20 min - 15 min)

slope = (0.135 - 0.223) / (20 - 15)

slope = -0.178

This slope represents the instantaneous rate of reaction at t=17. However, since it has a negative value, it means that the rate of reaction is decreasing at t=17.

Therefore, the instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

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How many moles of NaHCO3 are in 2.4 x
1024 molecules of NaHCO:?

Answers

Answer:

4.0 moles NaHCO

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 2.4 × 10²⁴ molecules NaHCO

[Solve] moles NaHCO

Step 2: Identify Conversion

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                     \(\displaystyle 2.4 \cdot 10^{24} \ molecules \ NaHCO(\frac{1 \ mol \ NaHCO}{6.022 \cdot 10^{23} \ molecules \ NaHCO})\)[DA] Divide [Cancel out units]:                                                                       \(\displaystyle 3.98539 \ moles \ NaHCO\)

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.98539 moles NaHCO ≈ 4.0 moles NaHCO

98.1 mL of 5 M potassium hydroxide is mixed with 39.9 mL of 4.5 M Iron (III) acetate resulting in a precipitate of Iron (III) hydroxide. Calculate the theoretical yield in g of iron (III) hydroxide.

Answers

Given:98.1 mL of 5 M potassium hydroxide is mixed with 39.9 mL of 4.5 M Iron (III) acetate resulting in a precipitate of Iron (III) hydroxide.To calculate the theoretical yield in grams of Iron (III) hydroxide, the first step is to balance the chemical equation for the reaction that takes place between potassium hydroxide and iron (III) acetate. 3KOH + Fe(C2H3O2)3 → Fe(OH)3 + 3KC2H3O2The balanced chemical equation for the reaction that takes place between potassium hydroxide and iron (III) acetate can be represented as follows;3KOH + Fe(C2H3O2)3 → Fe(OH)3 + 3KC2H3O2The molar mass of Fe(OH)3 is calculated as follows;Molar mass of Fe(OH)3 = Atomic mass of Fe + (3 x Atomic mass of O) + (3 x Atomic mass of H) = (55.85 g/mol) + (3 x 16 g/mol) + (3 x 1 g/mol) = 106.85 g/molThus the molar mass of Fe(OH)3 is 106.85 g/mol.To determine the theoretical yield of Iron (III) hydroxide we must first determine the limiting reactant (the reactant that is fully consumed in the reaction) among potassium hydroxide and iron (III) acetate.Limiting ReactantIn order to find out the limiting reactant among potassium hydroxide and iron (III) acetate, we will first find out the number of moles of each using the formula;Moles = Concentration x Volume in Liters (L)Moles of KOH = Concentration of KOH × Volume of KOH = 5 M × (98.1 mL/1000 mL) = 0.4905 moles Moles of Fe(C2H3O2)3 = Concentration of Fe(C2H3O2)3 × Volume of Fe(C2H3O2)3 = 4.5 M × (39.9 mL/1000 mL) = 0.17955 molesBased on the balanced chemical equation, the mole ratio of KOH to Fe(C2H3O2)3 is 3:1. Hence, the limiting reactant is Fe(C2H3O2)3 since it is lesser in moles compared to KOH. This means that all of the 0.17955 moles of Fe(C2H3O2)3 will be consumed in the reaction while 0.4905 - (0.17955 x 3) = 0.05145 moles of KOH will be left over after the reaction is complete.The theoretical yield is then calculated using the limiting reactant. We can calculate the number of moles of Fe(OH)3 produced from 0.17955 moles of Fe(C2H3O2)3 using the balanced chemical equation. The mole ratio of Fe(C2H3O2)3 to Fe(OH)3 is 1:1. Hence;Moles of Fe(OH)3 = Moles of Fe(C2H3O2)3 = 0.17955 moles. The mass of Fe(OH)3 is then calculated using the formula;Mass = Number of moles × Molar massMass of Fe(OH)3 = Number of moles of Fe(OH)3 × Molar mass of Fe(OH)3 = 0.17955 moles × 106.85 g/mol = 19.179 gTherefore, the theoretical yield of Fe(OH)3 is 19.179 g.

The theoretical yield of iron (III) hydroxide is 19.19 grams.

What is the theoretical yield of iron (iii) hydroxide?

The balanced chemical equation for the reaction between potassium hydroxide and iron (III) acetate is:

3 KOH + Fe(C₂H₃O₂)₃ → Fe(OH)₃ + 3 KC₂H₃O₂

To calculate the theoretical yield of iron (iii) hydroxide, first, we determine the limiting reagent.

The number of moles of each reactant:

Number of moles (n) = Molarity (M) × Volume (V)

For potassium hydroxide (KOH):

n(KOH) = 5 M × 0.0981 L

number of moles = 0.4905 moles

For iron (III) acetate (Fe(C₂H₃O₂)₃):

number of moles = 4.5 M × 0.0399 L

number of moles = 0.17955 moles

Since the stoichiometric ratio is 1:1, the number of moles of Fe(OH)₃ = 0.17955 moles.

The molar mass of Fe(OH)₃ = 106.88 g/mol

Theoretical yield = Number of moles × Molar mass

Theoretical yield = 0.17955 moles × 106.88 g/mol

Theoretical yield= 19.19 grams

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Part A
In the year 2012, an estimated amount of 31.6 billion metric tons (1 metric ton = 1000 kg) of carbon dioxide (CO2) was emitted worldwide due to fossil fuel combustion
and cement production. Express this mass of CO2 in grams without exponential notation, using an appropriate metric prefix

Answers

The mass of CO₂ in grams without exponential notation and with the appropriate metric prefix is 31.6 Eg.  

First, let's calculate the amount of mass in grams of 31.6 billion metric tons.

Knowing that 1 metric ton is equal to 1000 kg, 31.6 billion metric tons is:

\(m = \frac{1000 kg}{1 \: metric \: ton}*\frac{1000 g}{1 kg}*31.6 \cdot 10^{12} \: metric \: ton = 3.16 \cdot 10^{19} g\)              

The metric prefix that is close to the above result is exa (E), which is equal to 10¹⁸.

Therefore, the mass of CO₂ in grams without exponential notation and with the appropriate metric prefix is 31.6 Eg (exa-gram).  

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I hope it helps you!

Why is there something blocking the answer?

Answers

Answer: the answer you are looking for does not exist

Explanation:

IM GIVEING 184 POINTSSSSSSSSSSSSSSSSSSSS

if you were asked to create a picnic lunch that includes 2 mixtures and 1 solution what would you serve and why?

Answers

Answer:

I would serve nothing

Explanation:

thank you bye\

Answer:

Explanation:

I would not serve it because what if Their is some dangerous chemical

A strip of aluminum foil is placed in concentrated sulfuric acid

Answers

Answer:  Aluminium reacts with hot, concentrated sulphuric acid to form aluminium sulphate with the evolution of sulphur dioxide gas. It is a redox reaction. Sulphuric acid acts an oxidising agent, and gets itself reduced to SO2. Only with the dilute acid, the metal liberates hydrogen gas.

Explanation:

Answer: Aluminium reacts with hot, concentrated sulphuric acid to form aluminium sulphate with the evolution of sulphur dioxide gas. It is a redox reaction. Sulphuric acid acts an oxidising agent, and gets itself reduced to SO2. Only with the dilute acid, the metal liberates hydrogen gas.

What mass of carbon dioxide is produced upon complete combustion

Answers

Answer:

1 mole CO2 = 44g i.e.by the complete combustion of 12g of carbon, 44g of CO2 is produced.

Explanation:

Answer:

1 mole CO2 = 44g i.e.by the complete combustion of 12g of carbon, 44g of CO2 is produced.

Explanation:

A sample of water at 21.5°C required an input of 1.69 x 104 of heat to reach its boiling point, 100.0 °C. What was the mass of the
water?

Answers

Fawn spends hours each week managing employee shifts and schedules, time she should be spending on other restaurant operations. What can she do? O a) Start leaving more time in her week for scheduling-related tasks b) Write everything down in a weekly planner O c) Consider online inventory management software O d) Consider online scheduling software

An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass in amu of X?

Answers

Answer:

25.4 amu

Explanation:

Step 1: Given data

Mass of the isotope ²⁵X (m²⁵X): 25 amuAbundance of the isotope ²⁵X (ab²⁵X): 80.5 % = 0.805Mass of the isotope ²⁷X (m²⁷X): 27 amuAbundance of the isotope ²⁷X (ab²⁷X): 19.5% = 0.195

Step 2: Calculate the average atomic mass of X

We will use the following expression.

m = m²⁵X × ab²⁵X + m²⁷X × ab²⁷X

m = 25 amu × 0.805 + 27 amu × 0.195

m = 25.4 amu

The spot on the fault where the pressure first releases is called the

Answers

Answer:

This movement releases energy and generates seismic waves that can be recorded by specialized instruments used by scientists. The point on a fault at which the first movement or break occurs during an earthquake is called the earthquake's hypocenter

Explanation:

Two solutions are separated by a semipermeable membrane. On one side of the semipermeable membrane is a 1.5 M NaCl solution. On the other side of the membrane there is a 0.5 M KBr solution. Which statement describes the direction water will flow?

Answers

If two solutions are separated by a semipermeable membrane with one side 1.5 M NaCl solution and other side 0.5 M KBr solution. Here water will flow from the KBr solution to the NaCl solution because of the water concentration difference.

When two solutions are separated with a semipermeable membrane, the water will flow from lower solute concentrated side to higher solute concentrated side.

Lower solute concentration means the water content will be high and that states higher water concentration.

Higher solute concentration means the water content will be low and that states low water concentration.

The water will flow from higher concentration to lower till the equilibrium where both sides the water and solute concentration is same.

In this case, the lower solute concentration is the 0.5 M KBr solution and the higher solute concentration is the 1.5 M NaCl solution.

Therefore, water will tend to flow from the KBr solution to the NaCl solution.

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what will I benefit or what will I gain if I know the absorbance and emission of any substance?

Answers

You will gain more knowledge and it will be for your own good

10 Points
The International Commission of Radiological Protection has set the limit for yearly radiation exposure at 1000 uSv. What is the risk
associated with this dose?
A. No risk at this limit or below.
OB. 1/2400 chance of cancer over a 40 year period.
OC. 1/1000 chance of cancer over a 40 year period.
OD. 1/100,000 chance of cancer over a 40 year period.

Answers

The maximum allowable annual dose of radiation has been set at 1000 uSv by the worldwide commission on radiological protection. At this threshold or lower, there is no risk.

What is S(sievert)?

The sievert, a measurement used to measure radiation, is used to calculate how much radiation is taken in by human tissues.1000 millisieverts are equal to one sievert (mSv) [ 1 Sv= 1000 mSv]. There are 1,000 microsieverts in a millisievert[ 1 mSv = 1000 uSv]

Here are some details concerning the risks increasing radiation levels cause to our health:

Yukio Edano, Japan's Chief Cabinet Secretary, had said that radiation levels near the damaged facility on the northeast coast may rise to 400 millisieverts (mSv) per hour.The lowest dose of exposure that causes any rise in cancer probability is readily visible is 100 mSv per year. Five out of every 100 people exposed to a cumulative 1,000 mSv (1 sievert) may likely get a deadly malignancy several years later.The central nervous system, as well as the red and white blood cells, are destroyed by high radiation doses or acute radiation exposure. This impairs the immune system, making it difficult for the sufferer to fight off diseases.One sievert (1,000 mSv), for instance, only results in radiation sickness, which includes nausea, vomiting, and bleeding, but not death. About half of individuals exposed to a single dose of 5 sieverts would perish within a month.

Therefore the correct choice is an option (A).

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Answer:

Answer D

Explanation:from founders Edtell :

A dose of 1000 uSv is believed to carry a 1/100,000 risk of getting cancer over 40 years due to your exposure to radiation. The average dose is around 2400 uSv.

determine the oxidation state for each of the elements below. the oxidation state of ... iodine ... in ... diiodine pentoxide i2o5 ... is ... . the oxidation state of xenon in xenon trioxide xeo3 is . the oxidation state of manganese in manganese(?) oxide mn2o3 is .

Answers

The oxidation state of iodine in diiodine pentoxide (I₂O₅) is +5,  the oxidation state of xenon in xenon trioxide (XeO₃) is +6, and the oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is +3.

The oxidation state (or oxidation number) of an element is the number of electrons it has gained or lost to form a chemical bond.

The oxidation state of iodine in diiodine pentoxide (I₂O₅) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of iodine.

The total oxidation state due to the two iodine atoms in the molecule is 2x.

The total oxidation state due to the five oxygen atoms in the molecule is (-2) x 5 = -10.

The sum of the oxidation states is 2x - 10 = 0.

Solving for x, we get:

2x - 10 = 0

2x = 10

x = +5

The oxidation state of xenon in xenon trioxide (XeO₃) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of xenon.

The total oxidation state due to the xenon atom in the molecule is x.

The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.

The sum of the oxidation states is x - 6 = 0.

Solving for x, we get:

x - 6 = 0

x = +6

The oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is calculated as follows:

The compound is neutral, so the sum of the oxidation states of all the elements must be zero.

Let x be the oxidation state of the manganese.

The total oxidation state due to the two manganese atoms in the molecule is 2x.

The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.

The sum of the oxidation states is 2x - 6 = 0.

Solving for x, we get:

2x - 6 = 0

2x = 6

x = +3

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This image shows a mixture of steam and carbon monoxide reacting to reversibly produce carbon dioxide and hydrogen gas. Write the balanced chemical equation which is taking place in the mixture.
Be sure to include the physical states of each species.

This image shows a mixture of steam and carbon monoxide reacting to reversibly produce carbon dioxide

Answers

The reversible production of carbon dioxide and hydrogen gas as a result of a reaction between steam and carbon monoxide. The chemical formula for a balanced reaction is CO (g) + H2O (g) CO2 (g) + H2(g).

Does reversible carbon monoxide reaction result in the production of hydrogen and carbon dioxide gases?

Carbon dioxide (CO2) and hydrogen gas are created when carbon monoxide (CO) and water mix (H2O). The process is reversible and every molecule in the balanced equation has a coefficient of 1.

What are the two processes that replenish the atmosphere with carbon in the form of CO2?

Significant amounts of carbon are released into the atmosphere as a result of the burning of fossil fuels, changing land use, and the production of concrete with limestone.

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