You believe the population is normally distributed and you know the standard deviation is o = 5.2. You obtain a sample mean of M = 78.5 for a sample of size n = 64. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistica What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 11 with mean M 84.6 and a standard deviation of SD = 9.9. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 109 with mean M = 63.7 and a standard deviation of SD = 15.8. What is the test statistic for this sample? (Report ariswer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 232 with mean M = 77 and a standard deviation of SD = 6.7. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value You wish to test the following claim (H) at a significance level of a = 0.05. Họ: A = 78.2 Hu> 78.2 You believe the population is normally distributed and you know the standard deviation is o = 5.2. You obtain a sample mean of M = 78.5 for a sample of size n = 64. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = You wish to test the following claim (H) at a significance level of a = 0.002 Họ: A = 76.5 H: > 76.5 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 11 with mean M = 84.6 and a standard deviation of SD = 9.9. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = You wish to test the following claim (H) at a significance level of a = 0.002. Họ: A = 66.4 H: 766.4 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 109 with mean M = 63.7 and a standard deviation of SD = 15.8. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = You wish to test the following claim (H) at a significance level of a = 0.02. Hu = 78.1 Hu < 78.1 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 232 with mean M = 77 and a standard deviation of SD = 6.7. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value

Answers

Answer 1

1. Test Statistic :The test statistic for this sample is given as:t = (78.5 - 78.2) / (5.2 / sqrt(64))t = 1.15Thus, the test statistic for this sample is 1.15.2. P-Value :The P-value for this sample is obtained as:P(t > 1.15) = 0.1253

Thus, the P-value for this sample is 0.1253.3. Test Statistic :The test statistic for this sample is given as:t = (84.6 - 78.2) / (9.9 / sqrt(11))t = 2.14Thus, the test statistic for this sample is 2.14.4. P-Value :The P-value for this sample is obtained as:P(t > 2.14) = 0.0305Thus, the P-value for this sample is 0.0305.5. Test Statistic :The test statistic for this sample is given as:t = (63.7 - 78.2) / (15.8 / sqrt(109))t = -5.83

Thus, the test statistic for this sample is -5.83.6. P-Value :The P-value for this sample is obtained as:P(t < -5.83) = 0.0000Thus, the P-value for this sample is 0.0000.7. Thus, the test statistic for this sample is -4.14.8. P-Value :The P-value for this sample is obtained as: P(t < -4.14) = 0.0000

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Related Questions

a class has 30 students. what is the probability that at least two people in this class share the same birthday?

Answers

To calculate the probability that at least two people in a class of 30 share the same birthday, we can use the complement rule, which states that the probability of an event happening is equal to one minus the probability of the event not happening.

If we assume that birthdays are uniformly distributed throughout the year (i.e., each day is equally likely to be someone's birthday), then the probability that no two people in the class share the same birthday is:

365/365 * 364/365 * 363/365 * ... * 336/365

This is because the first person can have any birthday (probability of 365/365), the second person must have a different birthday (probability of 364/365), the third person must have a different birthday than the first two (probability of 363/365), and so on, up to the 30th person, who must have a different birthday than the first 29 (probability of 336/365).

Calculating this probability gives us:

(365/365) * (364/365) * (363/365) * ... * (336/365) ≈ 0.2937

So the probability that no two people in the class share the same birthday is approximately 0.2937.

Using the complement rule, the probability that at least two people in the class share the same birthday is:

1 - 0.2937 = 0.7063

Therefore, the probability that at least two people in a class of 30 share the same birthday is approximately 0.7063, or 70.63%.

there is a direct relationship between changing one attribute of a rectangular prism by a scale factor and its new surface area?

Answers

Yes, there is a direct relationship between changing one attribute of a rectangular prism by a scale factor and its new surface area. When one attribute of a rectangular prism is changed by a scale factor, all other attributes also change proportionally.

This means that the surface area of the prism will also change by the same scale factor. For example, if the length of a rectangular prism is increased by a scale factor of 2, then its surface area will increase by a scale factor of 4 (2 squared), there is a direct relationship between changing one attribute of a rectangular prism by a scale factor and its new surface area.

When you change one attribute (length, width, or height) of a rectangular prism by a scale factor, the surface area will also change according to that scale factor. Here's a step-by-step explanation:

1. Identify the attribute you want to change (length, width, or height).
2. Multiply the chosen attribute by the scale factor.
3. Calculate the new surface area using the modified attribute and the other two unchanged attributes.

Note that when you change one attribute, the relationship between the scale factor and the new surface area is linear. If you were to change all three attributes by the same scale factor, the relationship between the scale factor and the new surface area would be quadratic (since the surface area would be multiplied by the square of the scale factor).

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what is $4.89 x $6.3

Answers

$30.807
This is the answer
You get it

Answer:

30.807

Step-by-step explanation:

$4.89 x $6.3= 30.807

Find the volume of the cylinder. Round to the nearest hundredth.
5 mm.
25.5 mm.
V=
mm3

Answers

Answer:

2002.77mm³

Step-by-step explanation:

Formula : pi × r²× height

pi × 5² × 25.5 = pi × 25 × 25.5 = 2002.765317mm³

Find the equation of circle touching the Y=axis at point (0,3) and whose Centre is at (–3,3).

Answers

The equation of the circle is \((x + 3)^2 + (y - 3)^2 = 9.\)

What is equation?

In mathematics, equations are used to solve problems and find unknown values.

To find the equation of a circle, we need to know the coordinates of its center and its radius. In this problem, we are given the center of the circle, which is (-3, 3), and we know that the circle touches the Y-axis at point (0, 3).

Since the circle touches the Y-axis at point (0, 3), its radius is the distance from the center (-3, 3) to this point, which is 3 units.

So, the equation of the circle is of the form:

\((x - h)^2 + (y - k)^2 = r^2\)

where (h, k) are the coordinates of the center and r is the radius.

Substituting the given values, we have:

\((x - (-3))^2 + (y - 3)^2 = 3^2\)

Simplifying this equation, we get:

\((x + 3)^2 + (y - 3)^2 = 9\)

So the equation of the circle is \((x + 3)^2 + (y - 3)^2 = 9.\)

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Ava has a large-screen TV. The TV has a screen with a 51-inch diagonal and a width of 45 in. The base of the TV is 4 in. from the bottom of the screen. 45 in. h in. 51 in 4 in. what is the total height,h,in inches, of the TV?

Answers

Answer: Height: 24.9 inch, Width: 44.3 inch

Step-by-step explanation:

The total height of the TV is given by H = 28 inches

What is a Triangle?

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

if a² + b² = c² , it is a right triangle

if a² + b² < c² , it is an obtuse triangle

if a² + b² > c² , it is an acute triangle

Given data ,

Let the triangle be represented as ΔABC

Now , We can use the Pythagorean theorem to find the height of the TV. Let h be the height of the screen in inches. Then, we have:

h² + 45² = 51²

Simplifying and solving for h:

h² = 51² - 45²

h² = 2601 - 2025

h² = 576

Taking square roots on both sides , we get

h = √(576)

h = 24 inches

Therefore, the height of the screen is 24 inches.

To find the total height of the TV, we need to add the 4 inches from the base to the height of the screen:

Total height of the TV , H = 24 + 4

Total height of the TV , H = 28 inches

Hence , the total height of the TV is 28 inches.

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The complete question is attached below :

Ava has a large-screen TV. The TV has a screen with a 51-inch diagonal and a width of 45 in. The base of the TV is 4 in. from the bottom of the screen. what is the total height,h,in inches, of the TV?

Ava has a large-screen TV. The TV has a screen with a 51-inch diagonal and a width of 45 in. The base

How do you find these

What is the measure of segment DC?
What is the measure of segment C'B'?
What is the measure of segment AD?
What is the measure of segment A'B'?
What is the measure of angle C?
What is the measure of angle A'?
What is the measure of angle D'?
What is the measure of angle B'?
What is the measure of angle A?

How do you find these What is the measure of segment DC?What is the measure of segment C'B'?What is the

Answers

Measure of segment DC is 24

Measure of segment C'B' is 16

Measure of segment AD is 10

Measure of segment A'B' is 7

Measure of angle C is 49 degrees

Measure of angle A' is 111 degrees

Measure of angle D' is 65 degrees

Measure of angle B' is 135 degrees

Measure of angle A is 111 degrees

How to determine the measures

To determine the measures, we need to know the properties of parallelograms, we have;

Opposite angles are equal.Opposite sides are equal and parallel.Diagonals bisect each other.Sum of any two adjacent angles is 180°

We have that the two parallelograms are equal

Now, trace the angles from one to other

Angle A = 360 - (49 + 135 + 65)

add the values, we have;

Angle A = 360 -249

Angle A =111 degrees

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this histogram shows the yearly number of unprovoked attacks by alligators on people in florida over 33 years. what is the midpoint of the yearly number of unprovoked alligator attacks?

Answers

The midpoint of the yearly number of unprovoked alligator attacks can be calculated by finding the class interval that contains the median value. In this histogram, the class intervals are not provided, so we cannot determine the exact midpoint.

However, we can estimate the midpoint by visually locating the point where the histogram is balanced or roughly in the middle. Based on the histogram, it appears that the midpoint is around 6-8 attacks per year.
The midpoint of the yearly number of unprovoked alligator attacks in Florida over 33 years can be found by first identifying the highest and lowest number of attacks in the histogram. Once you have those values, add them together and divide by 2 to find the midpoint.

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find x an y. will give 30 points for correct answer

find x an y. will give 30 points for correct answer

Answers

Answer: X=54

              Y=126

Step-by-step explanation:

PLEASE HELP I AM BEING TIMED!!!

Statment: Find the measure of the angle indicated by 19x+5

Options: 130
50
80
100

PLEASE HELP I AM BEING TIMED!!!Statment: Find the measure of the angle indicated by 19x+5Options: 130

Answers

Answer:

100

Step-by-step explanation:

These two angles are corresponding which means they add up to 180.

so... 19x+5+(16x)=180

If you simplify...

35x+5=180

Then solve for x...

35x=175

x=5

Then take that 5 and fill it into 19x+5...

19(5)+5

95+5=100

Find the area of the parallelogram. 4 cm 1.1 cm ​

Answers

Answer:4.4cm

Step-by-step explanation:

area = length x width

area = 4cm x 1.1cm

area =  4.4cm

Write an equation of a line that is perpendicular to y = 2/3 x + 8 and has a y-intercept of
2.
Answer in slope-intercept form

Answers

Answer:

y = -3/2x + 2

Step-by-step explanation:

Since you know it has a point at (0, 2) - the y intercept, put those values into the equation and solve. To be perpendicular it seems the reciprocal of the slope with the opposite sign, so 2/3 is the original slope, and -3/2 becomes the new slope.

y = 2/3x + 8 becomes

2 = -3/2(0) + b  We substitute in the x and y values, but we have to figure out what the last number will be.

2 = 0 + b

b = 2

So put the whole equation together

y = -3/2x + 2

The main difference between hypergeometric and binomial distributions is that, with the hypergeometric distribution, the _____.

Select one:

a. trials are independent of each other

b. probability of success must be less than .5

c. probability of success changes from trial to trial

d. random variable is continuous

Answers

Answer:

c. probability of success changes from trial to trial.

Step-by-step explanation:

What is the mean absolute deviation of the data set?
{12, 10, 10, 8, 6, 7, 7, 12}
01
02
06
09

What is the mean absolute deviation of the data set?{12, 10, 10, 8, 6, 7, 7, 12}01020609

Answers

Answer:

  (b)  2

Step-by-step explanation:

You want the mean absolute deviation of the data ...

  {12, 10, 10, 8, 6, 7, 7, 12}

MAD

The mean absolute deviation (MAD) is the mean of the absolute values of the differences between the data values and their mean. The calculation of this is shown in the attachment.

The mean absolute deviation is 2.

<95141404393>

What is the mean absolute deviation of the data set?{12, 10, 10, 8, 6, 7, 7, 12}01020609

.Does education really make a difference in how much money you will earn? Reseachers randomly selected 100 people from each of three income categories—"marginally rich," "comfortably rich," and "super rich"—and recorded their education levels. The data is summarized in the table that follows.10
a Describe the independent multinomial populations whose proportions are compared in the χ 2 analysis.
b Do the data indicate that the proportions in the various education levels differ for the three income categories? Test at the α = .01 level.
c Construct a 95% confidence interval for the difference in proportions with at least an undergraduate degree for individuals who are marginally and super rich. Interpret the interval.

Answers

a. The independent multinomial populations whose proportions are compared in the chi-square analysis are the proportions of individuals with different levels of education (high school, some college, bachelor's degree, and advanced degree) in the three income categories (marginally rich, comfortably rich, and super rich).

To construct a 95% confidence interval for the difference in proportions with at least an undergraduate degree for individuals who are marginally and super rich, we can use the following formula:

(p1 - p2) ± zsqrt(p1(1-p1)/n1 + p2*(1-p2)/n2)

where p1 and p2 are the sample proportions with at least an undergraduate degree for marginally rich and super rich individuals, n1 and n2 are the sample sizes, and z is the critical value from the standard normal distribution for a 95% confidence level (z = 1.96).

From the table, we can see that there are 42 individuals in the marginally rich group and 72 individuals in the super rich group with at least an undergraduate degree. The sample proportions are:

p1 = 42/100 = 0.42

p2 = 72/100 = 0.72

Substituting these values into the formula, we get:

(p1 - p2) ± zsqrt(p1(1-p1)/n1 + p2*(1-p2)/n2)

= (0.42 - 0

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Goods are purchased for $1500. If one fifth of the goods sold at a profit of 5% and the remaining four-fifth of the goods at a profit of 10%, find the net profit percentage.

Answers

Answer:

9 percent

Step-by-step explanation:

1/5 of 1500 = 300

4/5 of 1500 = 1200

1200x110/100=1320

315+1320=1635

1635-1500 = 135

134/1500x100 = 9%

find a 95% confidence intervals for the impact multiplier, the one-period interim multiplier, and the total multiplier?

Answers

Therefore, we can say with 95% confidence that the true impact multiplier lies between 0.281 and 3.403, the true one-period interim multiplier lies between 1.485 and 6.119, and the true total multiplier lies between 4.487 and 10.124.

What is confidence interval?

A confidence interval is a range of values that is likely to contain an unknown population parameter with a certain level of confidence, based on a sample from that population.

Here,

a) The estimated relationship between sales and advertising expenditure is as follows:

The intercept is 25.34 million dollars.

An increase of 1 million dollars in advertising expenditure in the current period (ADV+) is associated with an increase in sales revenue of 1.842 million dollars.

A one-period lag in advertising expenditure (ADVt-1) is associated with an increase in sales revenue of 3.802 million dollars.

A two-period lag in advertising expenditure (ADVt-2) is associated with an increase in sales revenue of 2.265 million dollars.

The total effect of a sustained $1 million increase in advertising expenditure is the sum of the impact multiplier (1.842), the one-period interim multiplier (3.802), and the two-period interim multiplier (2.265). Therefore, the total effect is 7.909 million dollars.

b) Using a two-tailed test and a 5% significance level, the critical t-value is 2.021.

ADVt-1: t-statistic = 3.802 / 1.482 = 2.565 > 2.021, so the coefficient is significantly different from zero.

ADVt-2: t-statistic = 2.265 / 1.161 = 1.948 < 2.021, so the coefficient is not significantly different from zero.

Using a one-tailed test and a 5% significance level, the critical t-value is 1.645.

ADVt-1: t-statistic = 3.802 / 1.482 = 2.565 > 1.645, so the coefficient is significantly different from zero.

ADVt-2: t-statistic = 2.265 / 1.161 = 1.948 < 1.645, so the coefficient is not significantly different from zero.

Using a two-tailed test and a 10% significance level, the critical t-value is 1.684.

ADVt-1: t-statistic = 3.802 / 1.482 = 2.565 > 1.684, so the coefficient is significantly different from zero.

ADVt-2: t-statistic = 2.265 / 1.161 = 1.948 < 1.684, so the coefficient is not significantly different from zero.

Using a one-tailed test and a 10% significance level, the critical t-value is 1.282.

ADVt-1: t-statistic = 3.802 / 1.482 = 2.565 > 1.282, so the coefficient is significantly different from zero.

ADVt-2: t-statistic = 2.265 / 1.161 = 1.948 < 1.282, so the coefficient is not significantly different from zero.

c) The estimated covariance matrix of the coefficients is:

ADV ADVt-1 ADVt-2

ADV 2.5598 -0.7099 -0.1317

ADVt-1 -0.7099 1.3946 -1.0406

ADVt-2 -0.1317 -1.0406 2.1606

The standard errors are the square roots of the diagonal elements of this matrix:

SE(β1) = √(2.5598) = 1.599

SE(β2) = √(1.3946) = 1.181

SE(β3) = √(2.1606) = 1.471

The 95% confidence intervals for each coefficient can be calculated as follows:

Impact multiplier (β1):

CI = β1 ± t(0.025, n-3) x SE(β1)

where t(0.025, n-3) is the critical value of the t-distribution with (n-3) degrees of freedom, corresponding to the 0.025th percentile. For this problem, n = 105, so t(0.025, n-3) = 1.984.

CI = 1.842 ± 1.984 x 1.599

CI = (0.281, 3.403)

One-period interim multiplier (β2):

CI = β2 ± t(0.025, n-3) x SE(β2)

CI = 3.802 ± 1.984 x 1.181

CI = (1.485, 6.119)

Total multiplier (β1 + β2 + β3):

CI = (β1 + β2 + β3) ± t(0.025, n-3) x SE(β1 + β2 + β3)

CI = (1.842 + 3.802 + 2.265) ± 1.984 x sqrt(2.5598 + 1.3946 + 2.1606)

CI = (4.487, 10.124)

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Complete question:

The file ex9_2 contains 105 weekly observations on sales revenue (SALES) and advertising expenditure (ADV) in millions of dollars for a large midwest department sotre in 2008 and 2009. The following relationship was estimated: SALESt = 25.34 + 1.842ADV+ + 3.802ADVt-1 + 2.265ADVt-2 a) Describe the relationship between sales and advertising expenditure. Include an explanation of the lagged relationship. When does advertising have its greatest impact? What is the total effect of a sustained $1 million increase in advertising expenditure? b) The estimated covariance matrix of the coefficients is ADV ADV -1 ADV -2 ADV ADV - 1 ADV -2 2.5598 -0.7099 -0.1317 -0.7661 -0.7099 1.3946 -1.0406 0.0984 -0.1317 -1.0406 2.1606 -1.0367 -0.7661 0.0984 -1.0367 1.4214 Using a two-tailed test and a 5% significance level, which lag coefficients are significantly different from zero? Using a one-tailed test and a 5% significance level, which lag coefficients are significantly different from zero? Using a two-tailed test and a 10% significance level, which lag coefficients are significantly different from zero? Using a one-tailed test and a 10% significance level, which lag coefficients are significantly different from zero? c) Find a 95% confidence intervals for the impact multiplier, the one-period interim multiplier, and the total multiplier?

Find the perimeter RST. Round answer to the nearest tenth
Show all the work

Find the perimeter RST. Round answer to the nearest tenthShow all the work

Answers

Answer:

35.1 units

Step-by-step explanation:

Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:

RS²=3²+6²

RS=\(\sqrt{45}\)≈6.7 units

Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:

RT²=9²+12²

RT=\(\sqrt{225}\) = 15 units

Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:

TS²=12²+6²

TS=\(\sqrt{180}\)≈13.4 units

Perimeter=RS+RT+TS

=6.7+15+13.4

=35.1 units

Write an equation of the line that passes through (1, 2) and is perpendicular to the line y = -5x + 4

Answers

Answer:

y = -1/5 + 7

Step-by-step explanation:

Substitute the point (1,2) for the x and the y in the equation, set the 4 to b since we are solving for b.

2 = -5(1) + b  now solve for b

2 = -5 + b

+5   +5

7 = b

we know that the slope must be the reciprocal for it to be perpendicular

y = -1/5 + 7 add b (7) to the equation and change the reciprocal

Please can somebody help me, I literally have no idea what to do

Please can somebody help me, I literally have no idea what to do

Answers

Answer:

this is pythagoras theorem, a^2 + b^2 = c^2

Step-by-step explanation:

imma solve one and you figure the rest by ur self,
8^2 + 6^2 = 10^2
this is what i would assume the question's is talking about

In three days Tina sold 15 boxes. On the second day, she sold 1 more than on the first. On the third day, she sold 5 more than on the first. How many boxes did she sell on the third day?

Answers

Answer:

Step-by-step explanation:

15 divded by 3 is 5 one 5 is 2 second 6 third 7

Question:

In three days Tina sold 15 boxes. On the second day, she sold 1 more than on the first. On the third day, she sold 5 more than on the first. How many boxes did she sell on the third day?

Answer:

8. Tina sold eight boxes on the third day.

Step-by-step explanation:

Three days, 15 boxes.

On the first day, Tina sold 3 boxes.

On the second, she sold one more than on the first. (4)

On the third day, she sold five more than on the first. (8)

 3 + 4 = 7

7 + 8 = 15

So your answer would be:

Tina sold eight boxes on the third day.

Please help!! very behind! 50 PTS

PICK BETWEEN:
ASSOCIATEIVE PROPERTY OF ADDITON
ASSOCIATIVE PROPERTY OF MULTIPLATION
COMMUNITAVE PROPERTY OF ADDITION
COMMUNITIVE PROPERTY OF MULTIPLICATION
DISTRIBUTIVE PROPERTY

Please help!! very behind! 50 PTSPICK BETWEEN:ASSOCIATEIVE PROPERTY OF ADDITONASSOCIATIVE PROPERTY OF

Answers

Answer:

Line 1 to Line 2 = Distributive property

Line 2 to Line 3 = ASSOCIATIVE PROPERTY OF MULTIPLATION

Line 3 to line 4 = COMMUNITIVE PROPERTY OF MULTIPLICATION

Pls can you give me brainliest

pls :(

i will give brainlist to who ever gets it right

i will give brainlist to who ever gets it right

Answers

Answer:

2(j+2)

Step-by-step explanation:

Since 2 is the GCF, you should take out 2 to make the answer 2(j + 2).

Answer:

that will be 2(j+2) by taking hCf outside

plz mark as brainliest

HELP
ME
PLEASE THIS IS URGENT

HELPME PLEASE THIS IS URGENT

Answers

Answer:

meters/second

Step-by-step explanation:

That's a velocity unit :).

Answer:

Meters/Second

Given the LP model below. Do the following: a. Formulate the new LP model. b. Set up the initial table then identify the optimum column, pivotal row, entering variable out, going variable, Zj row entries, and Cjn - Zj row entries Maximize eamings =$0.80X 1
​ +$0.40X 2
​ +$1.20X 3
​ −$0.10x 4
​ subject to X 1
​ +2X 2
​ +X 3
​ +5X 4
​ ≤150 X 2
​ −4X 3
​ +8X 4
​ =70 6X 1
​ +7X 2
​ +2X 3
​ −X 4
​ ≥120 X 1
​ ,X 2
​ ,X 3
​ ,X 4
​ ≥0

Answers

(a) The new LP model is formulated by converting the given LP model into standard form by introducing slack, surplus, and artificial variables as necessary.

(b) To set up the initial table and identify the optimum column, pivotal row, entering variable out, going variable, Zj row entries, and Cjn - Zj row entries, the LP model needs to be solved using the simplex method step by step.

(a) To formulate the new LP model, we need to convert the given LP model into standard form by introducing slack, surplus, and artificial variables. The slack variables are added to the inequality constraints, surplus variables are added to the equality constraints, and artificial variables are added to represent any negative right-hand side values. The objective function remains the same. The new LP model is then ready to be solved using the simplex algorithm.

(b) Setting up the initial table involves converting the new LP model into a tableau form. The initial tableau consists of the coefficient matrix, the right-hand side values, the objective function coefficients, and the artificial variables. The simplex algorithm is applied iteratively to identify the optimum column (the most negative coefficient in the objective row), the pivotal row (determined by the minimum ratio test), the entering variable (corresponding to the minimum ratio in the pivotal column), and the outgoing variable (the variable exiting the basis).

During each iteration, the Zj row entries are calculated by multiplying the corresponding column of the coefficient matrix with the basic variable's coefficients. The Cjn - Zj row entries are obtained by subtracting the Zj row entries from the objective function coefficients. The process continues until an optimal solution is reached, where all the coefficients in the objective row are non-negative.

By following these steps and performing the simplex algorithm iterations, the optimum column, pivotal row, entering variable out, going variable, Zj row entries, and Cjn - Zj row entries can be identified to determine the optimal solution of the LP model.

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Groups A, B, and C have means of 4, 6, and 8, respectively. There are 15 cases in total, with equal sample sizes in each group. SSwithin is 120. 16-7. For 16-4a, what is omega-squared? 0 .12 0.25 d .33 O2

Answers

Groups A, B, and C have means of 4, 6, and 8, respectively. There are 15 cases in total, with equal sample sizes in each group. Within is 120. 16-7. 16-4a, the value of omega-squared is 0.25.

What is omega-squared?

       In statistics, omega-squared is a measure of effect size that can be used for one-way ANOVA to determine how much variance is due to the treatment or independent variable. It is calculated by dividing the between-group variance by the total variance, which includes both the within-group and between-group variance.

       Omega-squared is used to determine the percentage of variance accounted for by a particular factor or treatment. It is represented as ω2 and ranges from 0 to 1, with higher values indicating a stronger relationship between the independent variable and the dependent variable.

       The formula for omega-squared is as follows:

                         ω2=SSBetween / SSTotalSSWithin

                              = SSTotal - SS Between

         Where SSTotal is the sum of squares for the total variance.SSBetween is the sum of squares between the groups, and within is the sum of squares within the groups.

     The given information is:

                       Mean of group A = 4Mean of group

                                                 B = 6Mean of group

                                                 C = 8Total cases

                                                    = 15SSWithin

                                                    = 120

             We can calculate the sum of squares between the groups as follows:

                        SSTotal = SSBetween + SSWithinSSTotal

                                      = (nA + nB + nC - 1) × (σA² + σB² + σC²)SSBetween

                                      = SSTotal - SS Within SS Between

                                      = (3 - 1) × (42 + 62 + 82) - 120SSBetween

                                      = 80 Next,

           we can calculate the total variance as:

                      SSTotal = SSWithin + SSBetweenSSTotal

                                    = 120 + 80SSTotal

                                     = 200

            Now, we can calculate omega-squared as follows:

                     ω2 = SSBetween / SSTotalω2

                           = 80/200ω2

                           =0.4

       Hence, the value of omega-squared is 0.25.

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Can 18,18,36 be a right triangle

Answers

a^2 + b^2 = c^2

18^2 + 18^2 = 36^2;

324 + 324 = 1296

not equal, no

In the triangle below, what is the length of the side opposite the 30° angle?
30"
3
60"
O A. 213
O B. 313
O c.
3
2
O D. 13

In the triangle below, what is the length of the side opposite the 30 angle?30"360"O A. 213O B. 313O

Answers

Answer:

square root of 3 as shown above

In the triangle below, what is the length of the side opposite the 30 angle?30"360"O A. 213O B. 313O

Identify the lateral area and the surface area of a right rectangular prism with a 12cm by 10cm base and height 16cm.

Answers

Answer:

944 cm²

Step-by-step explanation:

get the area of each side: 12*10+10*16+12*16= 472

2 sets of each side: 944

Let the long-run profit function for a representative firm is given by π i

=p 2
−2p−399, where p is the price of computer. The inverse market demand for computer is given by p=39−0.009q, where q is unit of computers. Suppose technology for producing computers is identical for all firms and all firms face identical input prices. (a) Find the firm's output supply function. (b) Find the market-equilibrium price and the equilibrium number of firms. (c) Find the number of computers sold by each firm in the long run.

Answers

(a) The firm's output supply function is given by q = (p + 199) / 2.

(b) The market-equilibrium price is $32.56, and the equilibrium number of firms is 10.

(c) Each firm sells 70 computers in the long run.

To find the firm's output supply function, we need to maximize the firm's profit function, which is given by π = p^2 - 2p - 399. In the long run, firms will produce where marginal cost equals marginal revenue. Marginal revenue can be obtained by differentiating the inverse market demand function with respect to q, and marginal cost is equal to the derivative of the profit function with respect to q. Equating the two, we get:

(39 - 0.009q) = (2q - 2) / q

Simplifying the equation, we find:

q = (p + 199) / 2

This represents the firm's output supply function.

To find the market-equilibrium price and the equilibrium number of firms, we need to find the intersection point of the market demand and supply. Substituting the output supply function into the inverse market demand function, we have:

p = 39 - 0.009((p + 199) / 2)

Simplifying and solving for p, we get:

p ≈ $32.56

Substituting this price back into the output supply function, we find:

q = (32.56 + 199) / 2 ≈ 115.78

Given that each firm produces 70 computers in the long run, we can calculate the equilibrium number of firms:

Number of firms = q / 70 ≈ 10

Since each firm sells 70 computers in the long run, and there are 10 firms, the total number of computers sold by each firm is:

70 * 10 = 700

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