Answer:
v= 7.3 m/s
Explanation:
Assuming that the cyclists are going uphill at constant speed, and neglecting friction between the tires and the road, the force exerted by the bikers must be equal and opposite to the force downhill.This force downhill, has two components, one due to gravity, and the other due to the air resistance.This last one is a given of the problem, 14.5 N.The force due to gravity along the slope of the road, can be showed that is as follows:\(F_{g} = m*g*sin\theta= 139 kg*9.8m/s2*sin 4.9 = 116.4 N\)
So, the total force downhill is just the sum of the two:\(F_{net} =F_{g} + F_{air} = -130.9 N\)
(Taking as positive the direction uphill)Now, we know that the maximum power to be developed by the bikers, is P=955 W = 955 J/sAs the power is energy per unit time, and the change in energy is equal to the work done, we can write the following expression:\(W = F* \Delta x = \Delta E = P*\Delta t\)
As v = Δx/Δt, rearranging in the expression above, we get:P = F*vThe force must be equal in magnitude and opposite to the one acting downhill, that we have just got, so as P is a given, we need just to solve for v, as follows:\(v_{max} = \frac{P}{F_{up} } =\frac{955 W}{130.9N} = 7.3 m/s\)
So the fastest the bikers can climb the slope is 7.3 m/s.matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are
Answer:
very small...
Explanation:
i guess... but i may be missing something. the question feels too straightforward
1. Calculate the increase in length of an iron wire that is 30m long at 20°c when it is warmed to 45°c (take airon 1.1x10³J/k)
2. If 2200 Joule of heat is added to a 190 g object its temperature increases by 12°c.W hat is
a. specific heat capacity
b. heat capacity of the object
The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.
ΔL = L × α × ΔT
Where:
ΔL is the change in length
L is the original length of the wire
α is the coefficient of linear expansion for iron
ΔT is the change in temperature
The coefficient of linear expansion for iron is typically 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\).
Given:
L = 30 m (original length of the wire)
α = 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\) (coefficient of linear expansion)
ΔT = 45°C - 20°C = 25°C (change in temperature)
ΔL = 30 m × (1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\)) × 25°C
= 30 m × 1.1 x\(10^(^-^5^)\) × 25
= 8.25 x \(10^(^-^3^)\) m
2) Q = mcΔT
Where:
Q is the heat energy transferred
m is the mass of the object
c is the specific heat capacity
ΔT is the change in temperature
Given:
Q = 2200 J (heat energy transferred)
m = 190 g (mass of the object)
ΔT = 12°C (change in temperature)
a. Specific heat capacity (c):
one need to rearrange the formula to solve for c:
c = Q / (m × ΔT)
Substituting the given values:
c = 2200 J / (190 g × 12°C)
First, need to convert the mass to kilograms:
m = 190 g = 190 g / 1000 = 0.19 kg
Now can calculate the specific heat capacity:
c = 2200 J / (0.19 kg × 12°C)
= 9.62 J/(kg°C)
b. Heat capacity (C):
The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.
C = mc
Substituting the given values:
C = 0.19 kg × 9.62 J/(kg°C)
= 1.83 J/°C
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Can someone please help me with this one
Answer:
im pretty sure the answer is A. up but im not 100% sure
Identify two types of motion where an object's speed remains the same while it continues to change direction
Answer:
motion in which acceleration is orthogonal to travel directionmotion in which speed is constantExplanation:
1) Any motion in which the acceleration is orthogonal to the direction of travel will have this characteristic:
circular motion in a plane
motion of a charged particle in a magnetic field perpendicular to the direction of travel
__
2) Motion in which the speed is constant, regardless:
motion of a photon through a varying gravitational field
9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer
Answer:
Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.
Explanation:
Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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Please help me with this question.
With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
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A wire carrying a 25.0 A current bends through a right angle. Consider two 2.00 mm segments of wire, each 3.00 cm from the bend (Figure 1).
a) Find the magnitude of the magnetic field these two segments produce at point P , which is midway between them.
b) Find the direction of the magnetic field at point P
The magnitude of the magnetic field and the direction of the magnetic field at point P is mathematically given as
B=1.9*10^{-5}T
To determine the magnetic field direction, use the right-hand -rule on the page magnetic field is going.
What is the magnitude of the magnetic field these two segments produce at point P, which is midway between them.?Generally, the equation for Biot savant law is mathematically given as
\(B=(\frac{u}{4\pi}*{\frac{Ilsin\theta}{r^2})\)
Their net field is
Bn=2B
\(Bn=2* B=(\frac{u}{4\pi}*{\frac{Ilsin\theta}{r^2})\)
Hence
\(B=(\frac{4*\p *10^{-7}}{4\pi}*{\frac{(30)(2*10^{-3}sin45)}{\sqrt{(3*10^{-2})^2+((3*10^{-2})^2)}/2})\)
B=1.9*10^{-5}T
In conclusion, To determine the magnetic field direction, use the right-hand -rule on the page magnetic field is going.
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Answer:
The magnitude of the magnetic field at the point P is \(1.57*10^{-5}T\) and the field is pointing into the page.
Explanation:
The general form of a similar question to this is:
\(\vec{B} = \frac{\mu _{0} }{4\pi } * \oint \frac{Id\vec{l} \times \hat{r}}{r^{2} }\)
where \(\vec{B}\) is the vector of the Magnetic Field, \(\mu _{0}\) is the Free Space Permeability Constant (equal to \(4\pi * 10^{-7} \frac{N}{A^2}\)), \(I\) is the current, and \(r\) is the distance from the segment to the point P. (I will get to the \(d\vec{l} \times \hat{r}\) term in a bit)
This equation is fairly complicated. Luckily, it can be simplified by looking at the magnitude and direction separately.
The first thing to simplify is the cross product. Due to the fact that a cross product can be simplified from \(\vec{x} \times \vec{y}\) to \(xy\sin(\theta)\), where \(\theta\) is the angle between the 2 vectors, and \(\hat{r}\) is the unit vector of \(r\) (i.e. \(\hat{r} = \vec{r}/r\)) we can simplify \(d\vec{l} \times \hat{r}\) to just \(dl \sin(\theta)\).
Next, we will look at the integral. In this scenario, everything will function as a constant, so we can essentially ignore it.
Finally, \(\frac{\mu_{0}}{4\pi}\) simplifies down to \(10^{-7}\).
This gives us our new equation for the Magnetic Field produced by a single segment at a point:
\(B = \frac{Il\sin\theta}{r^{2}}*10^{-7}\)
Now we need to find values for \(r\) and \(\theta\). Luckily, we are dealing with a 45-45-90 triangle with sides of \(1.5 cm\). This means the distance \(r\) is \((1.5\sqrt2)cm\)! Similarly, because it is a 45-45-90 triangle, our \(\theta\) is \(45\textdegree\)!
Now we can start plugging things in:
\(B = \frac{(25A)(2*10^{-3}m)\sin(45\textdegree)}{(1.5\sqrt2*10^{-2}m)^2}*10^{-7}\frac{N}{A^2}\)
\(B = 7.86^{-6} \frac{N}{A}\) or \(T\)
This is the magnitude due to only one single segment. In order to find the total field, we need to know the direction of the field due to each segment.
Finding the direction is really easy. Just use the right hand rule. Point your thumb in the direction of the current and curl the rest of your fingers around an imaginary pole. The direction your fingers point is the direction of the field. In this case, the field lines due to the segments point into the page in the 4th quadrant (the origin is the bend). This means that at point P, both segments induce the same field in the same direction. Therefore, we can take our value from before and double it, giving us our final answer:
\(B = 1.57*10^{-5} T\); into the page.
Explain the light detection technique of photovoltaic detection
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
______________________________
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.
N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.
In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²
according to kinematics,
s = ut + 1/2 at²
s = 1/2 ×9.8×3.4²
s = 56.6 m
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Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as much as Jack's power output. four times Jack's power output. twice Jack's power output. one-half as much as Jack's power output. the same as Jack's power output.
Answer:
Second Choice.
Explanation:
Jack's Power = W/t
Jill's Power = 2W/(0.5)*t
2/0.5 = 4
Jill's Power = 4*W/t
Jill's Power is 4 times greater than Jack's
Second Choice
What is the difference between a wave and energy?
Answer:
The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy
Explanation:
The main difference between a wave and energy is: wave is oscillation of energy whereas energy is ability of doing work.
What is wave?A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.
What is energy?The capacity to do work is energy. Energy can only be changed from one form to another; it cannot be created or destroyed. Energy is measured in Joules, the same unit used to measure work. There are several sorts of energy since it is present in many different things.
There are two types of energy: kinetic and potential. Kinetic energy is the energy that is in motion, whereas potential energy is the energy that is stored in an object and is determined by the amount of work that is required.
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The scale on the horizontal line axis is 5s per division on the vertical axis 9 m per division
I need help with part 2
Questions deserve answers in their common format.
Two forces of 25 and 45 N act on an object. Their directions differ by
70°. The resulting acceleration has magnitude of 10.0 m/s2. What is the
mass of the body?
The mass of the body is 4.336 kg.
Resultant forceThe resultant of the given two forces is calculated as follows;
\(R^2 = 25^2 + 45^2 - (2\times 25 \times 45) cos(70)\\\\R^2 = 1880.45\\\\R = \sqrt{1880.45} \\\\R = 43.36 \ N\)
Mass of the bodyThe mass of the body is calculated by applying Newton's second law of motion as follows;
F = ma
m = F/a
m = 43.36/10
m = 4.336 kg
Thus, the mass of the body is 4.336 kg.
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If a 900 kg cow stampedes at 10 m/s, what is the cows kinetic energy?
90j
9000j
45,000j
4500j
Answer:
45,000 J
General Formulas and Concepts:
Energy
Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)
m is mass (in kg)v is velocity (in m/s)Explanation:
Step 1: Define
Identify variables
[Given] m = 900 kg
[Given] v = 10 m/s
Step 2: Solve for KE
Substitute in variables [Kinetic Energy Formula]: \(\displaystyle KE = \frac{1}{2}(900 \ kg)(10 \ m/s)^2\)Evaluate exponents: \(\displaystyle KE = \frac{1}{2}(900 \ kg)(100 \ m^2/s^2)\)Multiply: \(\displaystyle KE = (450 \ kg)(100 \ m^2/s^2)\)Multiply: \(\displaystyle KE = 45000 \ J\)how can empiricism assist you as a teacher to achieve your goals in a classroom
Empiricism is the notion that all ideas are derived from experience, that all ideas may be relevant or are about experiences, or that all prepositions and beliefs that are seen to be reasonable are known or justified largely by experience. The main function of experience is explained by empiricism. Empiricism maintains that experience serves as the foundation for all knowledge.
Empiricism plays a major role in the psychological history of America and Britain. Psychology is unjustified in light of human-made scientific knowledge. Empiricism was a key component of ancient, medieval, and contemporary philosophy. The popular sense of the day seemed to be empiricist (Britannica). Empiricism was seen to be a crucial force resisting the pretense of speculative rationalist philosophy. Even if they accepted the majority of the significant information that was nonempirical, most medieval philosophers adopted the empiricist approach, at least in terms of concepts.
Empiricism, therefore, takes on many forms. Their relaxation is the major factor that separates them. According to the widely accepted explanation, people's perceptions of their physical environment are influenced by their experiences. According to the phenomenalist interpretation, assistance merely benefits a person's sensory experience.
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The four particles as connected by rods of negligible mass as fig below. if the origin is the canter of rectangle and the system rotates in the XY plane about the Z axis with an rad angular speed of 12. calculate S a) The moment of inertia of the system about Z axis and b) The rotational kinetic energy of the system 3.00 kg 2.00 kg y(m) 2.00 kg 6.00 m 4.00 kg ---x(m)
The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.
The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.
Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.
\(Iz = ICM + MR^{2}\)
(1)We can obtain the moment of inertia of the rectangle about its center as: \(ICM = (1/12) ML^{2}\)
(2) where M is the mass of the rectangle, and L is the length of the rectangle.
Substituting values, we get: ICM = \((1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )\)
ICM = \(5 kg m^{2}\)
Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:
\(IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}\)
The moment of inertia of the system about Z-axis is: \(Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}\)
The kinetic energy of a rotating body is given as:\(K.E. = (1/2) I\omega^{2}\) where I is the moment of inertia of the system, and ω is the angular velocity of the system.
The rotational kinetic energy of the system is:\(K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
2)\(I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
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onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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The softest sound a human ear can hear is at 0 dB (Io = 10-12 W/m2). Sounds above 130 dB cause pain. A particular student's eardrum has an area of A = 51 mm2. What is the most power, in watts, the ear can receive before the listener feels pain?
Im so confused on how to even start with this problem, my main question is how sound and power are related.
Answer:
Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.
To solve this problem, you can use the formula for sound intensity:
I = P/A
where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).
You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:
P = AI
where A is the area of the eardrum in square meters.
Substituting the given values, you get:
P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))
Simplifying this expression, you get:
P = 1.8 x 10^-3 W
Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.
An electron that has a velocity with x component 2.0 × 106 m/s and y component 3.0 x 106 m/s moves through a uniform magnetic field with x component 0.024 T and y component -0.12 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.
Which terms describe this graph? (Choose all that apply)
negative correlation
linear
inversely proportional relationship
no correlation
non-linear
directly proportional relationship
The term that describes the given graph is a negative correlation, linear, inversely proportional relationship
Regression evaluation is a similar method for inspecting the connection between a final results variable and one or extra threat elements or confounding variables (confounding is mentioned later). The end result variable is likewise referred to as the reaction or based variable, while the threat elements and confounders are referred to as predictors, explanatory variables, or unbiased variables. The based variable in regression evaluation is indicated with the aid of using "Y," whilst the unbiased variables are denoted with the aid of using "X."
The path of the hyperlink is indicated with the aid of using the signal of the correlation coefficient. The correlation coefficient's price displays the electricity of the hyperlink.
It is vital to spotlight that whilst there can be a non-linear dating among non-stop variables, calculating a correlation coefficient does now no longer display this. As an end result, it's miles usually vital to investigate the statistics well earlier than setting up a correlation coefficient. Graphical representations are very powerful for investigating relationships among variables.
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what is the terminal velocity of blood
Answer:
25.1
Explanation:
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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If an electron vibrates up and down 1000 times each second, it generates an electromagnetic wave having aa. wavelength of 1000 mb. frequency of 1000 Hzc. speed of 1000 m/sd. period of 1000 s
The correct answer is frequency of 1000 Hz. The frequency of an electromagnetic wave is determined by the number of times the electron oscillates in a given amount of time.
What is electromagnetic wave?An electromagnetic wave is a type of energy wave that is composed of electric and magnetic fields and propagates through space. Electromagnetic waves are created when an electric field couples with a magnetic field. This happens when a charged particle accelerates, causing a disturbance in the electric and magnetic fields. Electromagnetic waves can be described in terms of their frequency, which is the number of times the wave oscillates per second, and their wavelength, which is the distance between two successive peaks of the wave. The frequency and wavelength of an electromagnetic wave determine its type. Different types of electromagnetic waves include radio waves, microwaves, infrared waves, ultraviolet waves, x-rays, and gamma rays.
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An explosion occurs 3400m away. Given that sound travels at 340 m/s, how long will it take for the sound to reach you?
Answer:
To solve this problem, we can use the formula:
time = distance / speed
where distance is the distance between you and the source of the sound, and speed is the speed of sound.
In this case, the distance is 3400m and the speed of sound is 340 m/s. So, we have:
time = 3400m / 340 m/s = 10 seconds
Therefore, it will take 10 seconds for the sound of the explosion to reach you.
Each of two small spheres is charged positively, the combined charge being 5.0×10 ³C. If each sphere is repelled from the other by a force of 1.0N when the spheres are 2.0m apart, calculate the charge on each sphere.
After considering the given data we conclude that the charge on each sphere is 2.5 × 10³ C, under the condition that Coulomb's law was used.
Coulomb's law states
F = (k ×q₁× q₂ )/r²,
Here
F = electrostatic force between two point charges,
k = coulomb constant,
q₁ and q₂ = charges on the spheres and r is the distance between them
We are given that both spheres have equal charges and force between them is 1.0 N and they are 2.0 m apart
q= √(1.0 N × 4.0m²)/k
q = 2.0 × 10⁻⁴ C
Since charge on each sphere is same, so the charge on each sphere will be
q₁ = q₂ = 2.5 × 10³ C
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A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. [04 Marks]
The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer:
Vf = 2.12 [m/s]
Explanation:
To solve this problem we must first find acceleration using Newton's second law, using mass and force.
ΣF = m*a
where:
F = force = 1.5 [N]
m = mass = 0.2 [kg]
a = acceleration [m/s²]
Now clearing a, we have:
\(a = F/m\\a = 1.5/0.2\\a = 7.5 [m/s^{2}]\)
Now we must use the following expression of kinematics, to find the final speed, we must take into account that the initial speed is equal to zero, since the car starts from zero.
\(v_{f}^{2} =v_{o} ^{2} +2*a*x\\v_{f} ^{2} = 0 + (2*7.5*0.3)\\v_{f} = \sqrt{4.5}\\v_{f} = 2.12 [m/s]\)
A ray of light in air is approaching the boundary with water at an angle of 52 degrees. Determine the angle of refraction of the light ray. (Refractive index of water = 1.33)
A light ray from the air enters the water surface making an angle of 52 degree.
This is the angle of incidence.
Also, refractive index of water is 1.33
From Snell's law,
Sin i = (n2/n1)Sin r
Here, Sin i is angle of incidence.
Sin r is angle of refraction
n2 is refractive index of water
n1 is refractive index of air
Refractive index of air is 1
Substituting the values,
Sin 52 degree =(1.33/1) Sin r
0.788/1.33 = Sin r
0.592 = Sin r
r= sin inverse (0.592)
r=36.29 degree
Thus, the angle of refraction is 36.29 degree.
How large is the acceleration of a 35-kg mass that has a net force of 270 N applied to it horizontally? Write units as well.
We will find the acceleration using the formula of force. The formula states that the net force applied on an object is directly proportional to the product of mass of the body and the acceleration of the body...
\( \mathcal{F = MA}\)
Where,
F is forceM is massA is accelerationIn our case,
F = 270 NM = 35 kgA = Unknown\(\large\underline{\underline{\maltese{\orange{\pmb{\sf{\: Solution :-}}}}}}\)
\( \green \leadsto \purple{ \tt 270 = 35 \times a}\)\( \green \leadsto \purple{ \tt 270 = 35 a}\)\( \green \leadsto \purple{ \tt 35a = 270}\)\( \green \leadsto \purple{ \tt 35a \div 35 = 270 \div 35}\)\( \green \leadsto \purple{ \tt a = 7.7 \: {m/s}^{2} }\)➪ Therefore, The acceleration of the body is 7.7 m/s²...~
According to the given statement The acceleration of the body is 7.7 m/s².
What is acceleration?Acceleration refers to the rate at which speed and direction of velocity vary over time. A point or object moving straight ahead is pushed when it accelerates or decelerates. Even though the speed is constant, movement on a circle accelerates so because direction is constantly shifting.
Briefing:F is force = 270N
M is mass = 35 kg
A is acceleration = unknown
F = m* a
270 = 35 * a
270 = 35a
35a = 270
a = 270/35
a = 7.7 m/s².
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