The kinetic energy of elf just before she catches the mouse is greater than that of yoda.
option A is the correct answer.
What is kinetic energy?
The kinetic energy of an object is the energy possessed by the object due to its motion.
Mathematically, the formula for kinetic energy is given as;
K.E = ¹/₂ mv²
where;
m is the mass of the objectv is the velocity of the objectFrom the formula given above, at a constant mass, the kinetic energy of an object will increase with an increase in speed of the object.
The kinetic energy of the elf will increase more than that of the yoda when the elf runs at a greater speed since the mass of both elf and yoda are equal.
Thus, kinetic energy increases with increase in the speed of an object and decreases with a decrease in the speed of the object.
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The complete question is below:
yoda and elf are cats. They both weigh the same. They start out chasing a mouse at the same speed, but Elf runs faster when she gets closer to the mouse and ended up catching the mouse. what is true about the kinetic energy of elf just before she catches the mouse?
A. the kinetic energy of elf is greater than that of yoda
B. The kinetic energy of elf is smaller than that of yoda
C. The kinetic energy of both are equal
D. The elf has no kinetic energy
A.005kg bullet going 200m/s, hits a .995kg block of wood, what is the final speed of the bullet and wood as they fly off together?
Answer:
Given :
m 1 =0.5 kg
u 1 =0 m/s
m 2=0.005 kg
u 2=200 m/s
Let the velocity acquired by the block after the collision be V.
Using conservation of linear momentum before and after the collision : P i =P f
∴ m1u 1 +m 2u 2=(m 1+m 2 )V
OR
0.5×0+0.005×200=(0.5+0.005)V
⟹V≈1.9 m/s
Answer:
V= 1.9 m/s
Explanation:
I did the test
Hope this helps :)
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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What is the net force on this object A: 0 newtons b: 200 newtons c:400 newtons D:600 newtons
Answer:
100kg
Explanation:
Total force =400N+600N=1000N
As we have,
F=m×g
1000N=m×10m/s²
1000N÷10m/s²=m
m=100kg
a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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Kent Belate is driving down I-294 at 26.7 m/s. He accelerates at a uniform rate of 5.78 m/s/s over a distance of 52.1 m. How much time is required to cover this distance?
The time taken for Kent Belate to travel the distance is 3.21 seconds.
What is the time taken for Kent Belate to travel the distance?
The time taken for Kent Belate to travel the distance is calculated by applying the following kinematic equation as shown below.
s = (u + v)/2 x t
where;
u is the initial velocity of Kent Belate v is the final velocity of Kent Belate t is the time of motion of Kent Belate s is the distance travelled by Kent Belate2s = (u + v)t
t = (2s) / (u + v)
t = (2 x 52.1) / (26.7 + 5.78)
t = 3.21 second
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if we sketch a pressure vs. volume graph of a gas at a given temperature, what changes on the graph are seen as the volume decreases?
Answer:
The pressure will show inverse relation - it will start to increase along with the decrease in volume.
Explanation:
The volume of a gas is inversely proportional to the pressure exerted upon it; hence for a given temperature, if you observe a decrease in the volume on the graph, you can be certain that the pressure must have increased.
To elucidate it even more just think of how the molecules of gas will behave in a closed container at a given temperature. The more you compress or put pressure upon the gas the more the volume of it will decrease.
Which of the following is true at the point where you reach the top of your jump on a trampoline?
The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.
The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.
What is Potential EnergyPotential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.
This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.
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An object begins moving 14 m/s to the right. The object moves with a constant acceleration for a time t.The object has an average velocity during this time of 22 m/s. What is the final velocity of this objectafter accelerating?
Given that the initial velocity is
\(V_o=14\text{ m/s}\)The average velocity is
\(V_{av}=\text{ 22 m/s}\)We have to find the
Why is the weight of earth is 1 by 6 of the weight of moon?; How do you calculate your weight on the moon and earth?; What is the mass of a 6 kg object when it is brought to the moon that has a gravity that is 1/8 of that on earth?; What is the weight of a 30 kg object on earth?
Answer:
Below
Explanation:
weight = mass * g <==g is less on the moon, so your weight is less on the moon
to calculate weight, you have to use the g of the planet you are on
The MASS does not change....it will be 6kg on the moon or earth
Weight of 30 kg on earth = 30 * g = 30 * 9.81 = 294 N
The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by various atmospheric processes, including lightning. If research came out on Planet x in a distant solar system that had a electric field with strength 222 N/C and 0.6 the radius of the earth, what would be the excess charge on planet x
Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q = \(\frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}\)
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q = \(\frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}\)
q = 3.6 10⁵ C
5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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A sinewave has a period (duration of one cycle) of 460 μs. What is the corresponding frequency of this sinewave in kHz, expressed to three significant figures (see Study Note 7.1 in the Using numbers (maths) booklet)?
If the frequency of the sinewave is now reduced by a factor of 4.25, what will be the new period value? Express your answer in ms to three significant figures.
Note: in the second part of this question, to avoid rounding errors in your calculations, use the full frequency value from the first part, not the rounded value to three significant figures.
Answer:
See below
Explanation:
Frequency = 1 / period
= 1 / 460 X 10^-6
2173.91 Hz = ~ 2.17 Khz
2.17391 kHz / 4.25 = .511 kHz <====new frequency
period = 1/frequency
= 1955 microseconds =1.96 ms
Answer:
2.17 kHz1.96 msExplanation:
You want to know the frequency in kHz of a sine wave with a period of 460 μs, and its period if the frequency is reduced by a factor of 4.25.
UnitsWhen you are interested in the frequency in kHz, it is convenient to use milliseconds (ms) to express the period. Milliseconds and kilohertz are inverse units.
The period of the given sine wave can be expressed in milliseconds as ...
460 μs = 460×(0.001 ms) = 0.460 ms
FrequencyThe frequency of the wave is 1/(0.460 ms) ≈ 2.17 kHz.
PeriodBecause period and frequency are reciprocals of each other, reducing the frequency by a factor of 4.25 increases the period by the same factor.
The new period is 4.25×0.460 ms = 1.96 ms.
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A charge of +6.10 mC is located at x = 0, y = 0 and a charge of −8.80 mC is located at x = 0, y = 3.00 m. What is the electric potential due to these charges at a point P with coordinates x = 4.00 m, y = 0?
The electric potential due to these charges at a point P is 2.1 x 10⁷ Nm/C.
Distance between point P and charge at y = 3 m
Apply Pythagoras theorem to determine the distance between these two points.
y² = 3² + 4²
y² = 25
y = √25
y = 5 m
Electric potential at point P due to -8.8 mC\(V_y = \frac{kQ}{r} \\\\V_y = \frac{9\times 10^9 \times (-8.8 \times 10^{-3})}{5} \\\\V_y = -1.584 \times 10^{7} \ Nm/C\)
Electric potential at point P due to +6.10 mC\(V_x = \frac{kQ}{r} \\\\V_x = \frac{9\times 10^9 \times 6.1 \times 10^{-3}}{4} \\\\V_x = 1.373 \times 10^{7} \ Nm/C\)
Resultant electric potential\(V = \sqrt{V_y^2 + V_x^2} \\\\V = \sqrt{(-1.584 \times 10^7 )^2\ + \ (1.373 \times 10^7)^2} \\\\V = 2.1 \times 10^7 \ Nm/C\)
Thus, the electric potential due to these charges at a point P is 2.1 x 10⁷ Nm/C.
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Define in your own words what Economics is about?
Answer:
Economics definition, the science that deals with the production, distribution, and consumption of goods and services, or the material welfare of humankind.
A student determines a value for a force using the formula F = k I l.
k is a constant with units of N A-1 m-1
I is current measured in mA
l is length measured in mm
The student uses the numbers directly from each measurement in their calculation.
What will be the units of the force from that calculation?
1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.
What is force?
Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.
Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.
The given formulae are;
F = k I l
k is a constant with unit= N A-1 m-1
I is currently measured in mA = 10⁻³A
l is the length measured in mm= 10⁻³ m
F = k I l
F= N A-1 m-1× 10⁻³A×10⁻³ m
F= 10⁻⁶ N ( 1N = 10⁻⁵ dyne)
F= 0.1 dyne
Hence the unit of force will be dyne and the value of force will be 0.1 dynes.
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A stretch limo of the future is 8.0 meters long, but appears to only be 6.0 meters long to astationary observer when driven at speed close to the speed of light. How fast must the limobe driving?
Given data:
* The length observed by the observer at rest is,
\(l_o=6\text{ m}\)* The actual length is,
\(l=8\text{ m}\)Solution:
By the law of relativistic length contraction,
\(\begin{gathered} l_o=l_{}\sqrt[]{1-\frac{v^2}{c^2}} \\ 6=8\sqrt[]{1-\frac{v^2}{c^2}} \\ \sqrt[]{1-\frac{v^2}{c^2}}=\frac{6}{8} \\ \sqrt[]{1-\frac{v^2}{c^2}}=0.75 \\ 1-\frac{v^2}{c^2}=0.5625 \\ \frac{v^2}{c^2}=1-0.5625 \\ \frac{v^2}{c^2}=0.4375 \end{gathered}\)Thus, the value of the velocity is,
\(\begin{gathered} \frac{v}{c}=0.661 \\ v=0.66c \end{gathered}\)where c is the speed of light,
\(\begin{gathered} v=0.66\times3\times10^8 \\ v=1.98\times10^8ms^{-1} \end{gathered}\)\(\text{Thus, the sp}eed\text{ of the limo is 1.98}\times10^8ms^{-1}\). A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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a copper water tank of mass 20 kg contains 150 kg of water at 15°C calculate the energy needed to heat the water and the tank to 55°C
copper shc - 385j/kg
water shc - 4200j/kg
Answer: 25230800 Joules
Explanation: We can treat the copper tank and the water inside as two different objects since they have different specific heats. We will utilize Q=Mcdelta(t) in this problem where M is mass, c is specific heat, and delta t is the change in temperature.
Since we are treating the copper and water separately we can make a Mcdelta(t) for each one of them. This gives us Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t)). The delta t will be the same because both the copper and water are at 15 celsius. Now we just do some calculations.
Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t))
Q=(20)(385)(55-15)+(150)(4200)(55-15)
Q=30800+25200000
Q=25230800 J
This number may seem absurdly high but there is 150 kg of water being heated up which is 150 liters(A LOT!).
Hope this helps!
What is the speed of a wave that has a frequency of of 3.7 * 10 ^ 3 Hz and a wavelength of 1.2*10^ -2 m?
Answer:
44.4m/s
Explanation:
v = (3.7*10 ^3) ( 1.2 * 10 ^ -2)
= 44.4 m/s
Answer:
44.4 m/s
Explanation:
By using the wave speed formula, v = fλ ( speed= frequency × wavelength)
v = 3.7×10³ × 1.2×10^-2
= 44.4 m/s
Hope that's the answer you're looking for:)
Ritalin and the pain medication Demerol have a high risk of dependence but may be used for medicinal purposes under a doctor's supervision. These substances are _____ of the CSA list.
Ritalin and Demerol are both controlled substances that have a high risk of abuse and dependence.
What is the list?Schedule II drugs are believed to have a high abuse potential that could lead to severe psychological or physical dependence. They do, however, occasionally have other known medical applications and can be prescribed by a licensed healthcare provider.
Ritalin is an example of a stimulant, whereas Demerol is an example of an opioid. Thus the drugs that have been mentioned here are drugs that are strictly controlled.
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Suppose that a series RL circuit is connected to a voltage source whose input voltage (Vin) is shown in the figure above. As shown in the figure above, the input voltage Vin = Vmax only within time interval 0 ≤ t ≤ T. The input voltage Vin = 0 outside this time interval. Assume that initially (at t = 0), no current is flowing in this circuit (I = 0)! A Determine the output voltage Vout as a function of time t! B Assume that the time interval T is very short so that T → 0, and also assume the the maximum voltage Vmax is quite high, so that VmaxT ≈ Φimp. Show that the output voltage Vout can be approximated by the following equation : Vout(t) ≈ Φimp τ e −t/τ where τ = L R
A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:
Vout(t) = Vmax * (1 - e^(-t/τ))
Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:
Vout(t) ≈ Vmax * e^(-t/τ)
In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.
Rearranging the equation, we get:
Vout(t) ≈ Φimp * e^(-t/τ)
This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.
The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.
Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.
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The social model was created by
Secondary succession can happen after primary succession or independently of primary succession. Please select the best answer from the choices provided T F
Answer: ok
Explanation: “In primary succession, newly exposed or newly formed rock is colonized by living things for the first time. In secondary succession, an area that was previously occupied by living things is disturbed, then re-colonized following the disturbance.”-Khanacademy
I think basically, it is saying that you need primary succession in order to colonize and then you have secondary succession which re-colonizeses the area. It could be like a natural disaster, but secondary succession will rebuild back the ecosystem and may even bring good alterations in some scenarios.
I just took the test.
I put True.
I got it right.
each
A boy of mass 10kg
climbs up to Steps
of height
0.2m in 20 seconds calculate the
Power of the body.
So the right answer is 0.98 watt.
look at the attached picture
Hope it will help you
Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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A tennis ball is shot vertically upward inside a tower with an initial speed of
20.0 m/s. Neglect air resistance. Approximately how long does it take the tennis ball to reach its maximum height?
0.50 s
2.04 s
4.08 s
6.08 s
9.80 s
Determine the velocity of the ball 3.0 s after it is thrown
9.40 m/s, downward
9.40 m/s, upward
29.4 m/s, downward
38.8 m/s, upward
38.8 m/s, downward
The ball's height at time t is
y = (20.0 m/s) t - 1/2 g t²
where g is the acceleration due to gravity, with magnitude 9.80 m/s².
Also, recall that
v² - u² = 2 a ∆y
where u is the initial velocity, v is the final velocity, a is the acceleration, and ∆y is the change in height. Let Y be the maximum height. At this height, v = 0, so
- (20.0 m/s)² = 2 (-g) Y
==> Y ≈ 20.408 m
Plug this into the first equation and solve for t :
Y = (20.0 m/s) t - 1/2 (9.80 m/s²) t²
==> t ≈ 2.04 s
The ball's velocity at time t is
v = 20.0 m/s - g t
After t = 3.0 s, its velocity will be
v = 20.0 m/s - (9.80 m/s²) (3.0 s)
v = -9.40 m/s
or 9.40 m/s in the downward direction.
2. Circle the best answer:
1000 Newtons
1000 Newtons
A. The forces shown above are PUSHING / PULLING forces.
B. The forces shown above are WORKING TOGETHER/OPPOSITE FORCES.
C. The forces are EQUAL/NOT EQUAL.
D. The forces DO / DO NOT balance each other.
E. The resultant force is 1000 N TO THE RIGHT / 1000 N TO THE LEFT/ZERO.
F. There IS/IS NO motion.
According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.
How to explain each element in the image?According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.
On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.
Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.
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In terms of electric pressure, describe a charged capacitor.
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
A net force of 275 N accelerates a 18.0 kg mass. What is the resulting acceleration? (5 points)
Answer:
The answer is 15.28 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
where
m is the mass
f is the force
We have
\(a = \frac{275}{18} \\ = 15.277777...\)
We have the final answer as
15.28 m/s²Hope this helps you