y = - 2x + 2
2x + y = 2
What is the solution to this ??
Pls helpppp

Answer:

A: 16

Step-by-step explanation:

its in between

The expression is given as 3u⁶

First, we need to know that index forms are defined as forms that are used for representing numbers or variables in more convenient forms.

We also need to know that the rules of index forms are;

From the information given, we have that;

(3u²)⁵/ 3u⁴

expand the bracket

3u¹⁰/3u⁴

Now, subtract the exponents, we have;

3u¹⁰⁻⁴

3u⁶

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(a) The initial speed of the projectile - 28.2m/s

(b)The total time interval the projectile was in flight - 4.07s.

a) When a projectile is launched with speed \(v_{i}\) at an angle above the horizontal, the initial velocity components are \(v_{xi}\) = \(v_{i}\) cos\(θ\) and                  \(v_{yi}\)= \(v_{i}\) sin\(θ\) . Neglecting air resistance, the vertical velocity when the projectile returns to the level from which it was launched (in this case, the ground) will be \(v_{y} = - v_{yi}\) .

From this information, the total time of flight is found  \(v_{yf} = v_{yi} + a_{y}\) to be

         \(t_{total} = \frac{v_{yf} - v_{yi} }{a_{y}}\)   = \(\frac{-v_{yi} - v_{yi} }{-g}}\)  = \(\frac{2v_{yi} }{g}\)

         \(t_{total} = \frac{2v_{i}sinθ }{g}\)

Since the velocity of a projectile with no air resistance is constant, the horizontal distance it will travel in this time is given by

R = \(v_{xi} t_{total} = (v_{i} cosθ_{i}) \frac{2v_{i}sinθ }{g}\)  =  \(\frac{v^{2}_{i}}{g}( 2sinθ_{i} cosθ_{i} )\) = \(\frac{v^{2} _{i} (sin2θ_{i} ) }{g}\)

Thus, if the projectile is to have a range of R=81.1m when launched at an angle of \(θ_{i}\)=45.0°, the required initial speed is

\(v_{i} = \sqrt{\frac{81.1 * 9.80}{sin90} }\) = 28.2 m/s

Therefore, the initial speed of the projectile - 28.2m/s

b) With \(v_{i}\)=28.2m/s and \(θ_{i}\) = 45.0°, the total time of flight (as found

above) will be

        \(t_{total} = \frac{2v_{i}sinθ }{g}\)  = \(\frac{2(28.2 m/s) sin45}{9.80m/s^{2}}\) = 4.07s

∴The total time interval the projectile was in flight - was 4.07s.

c) Note that at \(θ_{i}\) =45.0° that sin(2\(θ_{i}\)) will decrease as \(θ_{i}\) is increased above this optimum launch angle. Thus, if the range is to be kept constant while the launch angle is increased above 45.0°, we see from \(v_{i}\) = \(\sqrt{\frac{Rg}{sin2θ_{i}} }\)that the required initial velocity will increase.

Observe that for \(θ_{i}\) <90°, the function sin\(θ_{i}\) increases as \(θ_{i}\) it increased. Thus, increasing the launch angle above 45.0° while keeping the range constant means that both \(v_{i}\) sins will increase. Considering the expression  \(t_{total}\) given above, we see that the total time of flight will increase.

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The correct question is :

The record distance in the sport of throwing cowpats is 81.1m. This record toss was set by Steve Urner of the United States in 1981. Assuming the initial launch angle was 45° and neglecting air resistance, determine (a) the initial speed of the projectile and (b) the total time interval the projectile was in flight. (c) How would the answers change if the range were the same but the launch angle was greater than 45°? Explain.

Answer:4

Step-by-step explanation:

Just count lol n I did it rn

Answer:

4

Step-by-step explanation:

trust me

Answer:

3628800 ways if the women are always required to stand together.

To solve this problem, we can consider the number of ways to arrange the women and men separately, and then multiply the results together.

First, let's consider the arrangement of the women. Since no two men can be seated next to each other, the women must be seated in between the men. We can think of the 5 men as creating 6 "gaps" where the women can be seated (one gap before the first man, one between each pair of men, and one after the last man).

Out of these 6 gaps, we need to choose 7 gaps for the 7 women to sit in. This can be done in "6 choose 7" ways, which is equal to the binomial coefficient C(6, 7) = 6!/[(7!(6-7)!)] = 6.

Next, let's consider the arrangement of the 5 men. Once the women are seated in the chosen gaps, the men can be placed in the remaining gaps. Since there are 5 men, this can be done in "5 factorial" (5!) ways.

Therefore, the total number of ways to seat the 5 men and 7 women is 6 * 5! = 6 * 120 = 720.

There are 720 ways to seat the 5 men and 7 women in a row such that no two men are next to each other.

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\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3200\\ r=rate\to 7.75\%\to \frac{7.75}{100}\dotfill &0.0775\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &13 \end{cases} \\\\\\ A=3200\left(1+\frac{0.0775}{1}\right)^{1\cdot 13}\implies A=3200(1.0775)^{13}\implies A\approx 8444.51\)

Zeros of the given polynomial are -2, 2, -3/2, 3/2

Zeros of a polynomial can be defined as the points where the polynomial becomes zero as a whole.

Given a polynomial 1/4(4\(x^{4}\) - 25\(x^{2}\) + 36)

1/4(4\(x^{4}\) - 25\(x^{2}\) + 36) = 0

(4\(x^{4}\) - 25\(x^{2}\) + 36) = 0

4\(x^{4}\) - 16\(x^{2}\) - 9\(x^{2}\) + 36= 0

4\(x^{4}\)(\(x^{2}\) - 4) - 9(\(x^{2}\) - 4) = 0

(4\(x^{4}\)-9)(\(x^{2}\) - 4) = 0

(x+2)(x-2)(2x+3)(2x-3) = 0

x = -2, 2, -3/2, 3/2

Hence, Zeros of the given polynomial are -2, 2, -3/2, 3/2

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Answer:

Expression: 6x + 30

Step-by-step explanation:

2[x + (x + 5) + (x + 2(5))]

2[2x + 5 + x + 10]

2(3x + 15)

6x + 30

The second question's terminology is too ambiguous for me to answer, apologies.

Answer:

Step-by-step explanation:

The dimension of the basis is {[1 0 0 2], [-1 1 0 0]}.

To find a basis for the subspace S = span {[1 -1 0 2], [3 -5 4 8], [0 1 -2 -1]}, we can use the same method as in the example. First, we put the vectors in a matrix and row-reduce it:

[1 -1 0 2]
[3 -5 4 8]
[0 1 -2 -1]

R2 - 3R1 -> R2
R3 -> R3 + 2R1

[1 -1 0 2]
[0 -2 4 2]
[0 1 -2 -1]

-1/2R2 -> R2

[1 -1 0 2]
[0 1 -2 -1]
[0 1 -2 -1]

R3 - R2 -> R3

[1 -1 0 2]
[0 1 -2 -1]
[0 0 0 0]

We can see that the last row is all zeros, so we have only two pivots and one free variable. This means that the dimension of the subspace S is 2. To find a basis, we can write the pivots as linear combinations of the original vectors:

[1 -1 0 2] = [1 0 0 2] + [-1 1 0 0]
[0 1 -2 -1] = [0 1 -2 -1]

Therefore, a basis for S is {[1 0 0 2], [-1 1 0 0]}.

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The probability of selecting a human character randomly in the game is \(\frac{1}{3}\)

The probability that a human character will be chosen when the player selects a character randomly can be calculated by dividing the number of human characters by the total number of available characters.

There are 8 animal characters and 4 human characters, making a total of 12 characters to choose from. Therefore, the probability of selecting a human character randomly is:

P(Human) = Number of human characters / Total number of characters

P(Human) = 4 / 12

Simplifying this fraction, we find:

P(Human) = 1 / 3

Therefore, the probability of selecting a human character randomly is 1/3 or approximately 0.333.

In the given scenario, there are a total of 8 animal characters and 4 human characters, making a total of 12 characters to choose from. When a player selects a character randomly, each character has an equal chance of being chosen. Since there are 4 human characters, the probability of selecting one of them is determined by dividing the number of human characters (4) by the total number of characters (12).

When we simplify the fraction 4/12, we find that it is equal to 1/3.

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Ans:-

\( \: \)

Solution:-

\(↣ \: \textsf{-5 ( -2 )³ + 8 ( -2 )²}\)

\( \: \)

\( ↣ \: \textsf{-5 ( -8 ) + 8 ( -4 )}\)

\( \: \)

\( ↣ \: \textsf{40 + ( -32 ) }\)

\( \: \)

\( \textsf{[ + , - = - ]}\)

\( \: \)

\(↣ \: \textsf{40 - 32 }\)

\( \: \)

\( \underline{ \underline{↣ \textsf \orange{ \: \: 8 \: \: \: }}}\)

\( \: \)

━━━━━━━━━━━━━━━━━━━━━━━━━━━

hope it helps!:)

Answer: Please post your question!

Step-by-step explanation:

Answer:

i will gladly help, i just need the question lol

Step-by-step explanation:

The distribution that matches the arrival of cars at an average rate of 360 cars per hour is the Poisson distribution.

The Poisson distribution is a probability distribution that models the number of events occurring within a fixed interval of time or space when these events happen independently and at a constant average rate. It is commonly used to describe the occurrence of rare events or events that happen randomly over time. In this case, the tollbooth operator has observed cars arriving randomly, and the average rate of arrival is given as 360 cars per hour.

The Poisson distribution is characterized by a single parameter, λ (lambda), which represents the average rate of events occurring in the given interval. In this scenario, λ is equal to 360. The probability mass function of the Poisson distribution allows us to calculate the probability of observing a specific number of events within a given time interva

Therefore, the Poisson distribution is the most appropriate choice for modeling the arrival of cars at the tollbooth, as it accounts for the random and independent nature of the arrivals, while the average rate of 360 cars per hour aligns with the distribution's parameter.

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The combined perimeter of

2b (14y - 12)

2c (18y + 4)

2d (14y - 16), is

Add the like terms

The combined perimeter is (46y - 24)

The combined area of

1b (10y^2 - 27y +5)

1c (20y^2 + 11y - 3)

1d (12y^2 -24y), is

Add the like terms

The combined area is (42y^2 - 40y + 2)

The probability of a randomly chosen bolt having a width between 941 and 959 mm is 0.6294, and the appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8729 is 963.80 mm.

To calculate the probability of a bolt having a width between 941 and 959 mm, we need to standardize the values using the formula z = (x - μ) / σ, where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation. Thus, for the lower value of 941 mm, we get z = (941 - 951) / 10 = -1, and for the upper value of 959 mm, we get z = (959 - 951) / 10 = 0.8. Using a standard normal distribution table or a calculator, we can find the probabilities corresponding to these z-scores, which are 0.1587 and 0.7881, respectively. Therefore, the probability of a randomly chosen bolt having a width between 941 and 959 mm is the difference between these two probabilities, which is 0.6294, rounded to four decimal places.

To find the value of C such that a randomly chosen bolt has a width less than C with probability 0.8729, we need to use the inverse normal distribution function, also known as the z-score or percentile function. This function gives us the z-score corresponding to a given probability. Using a calculator or a table, we can find the z-score corresponding to a probability of 0.8729, which is 1.18, rounded to two decimal places.

To get the corresponding width, we use the formula x = μ + zσ, where μ and σ are the mean and standard deviation of the normal distribution, and z is the z-score we just found. Thus, C = 951 + 1.18 × 10 = 963.8 mm, rounded to two decimal places. Therefore, the appropriate value for C is 963.80 mm.

Therefore, the probability of a randomly chosen bolt having a width between 941 and 959 mm is 0.6294, and the appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8729 is 963.80 mm.

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the area of the shaded region : (9x3)+(12x3) = 27+36=63

The area of the shaded region is equal to the subtraction of the total area to the area of the two small squares and one big square. Then the area of the shaded region is 63 square units.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

All of the quadrilaterals in the shape below are squares.

Then the area of the shaded region will be

The area of the shaded region is equal to the subtraction of the total area to the area of the two small squares and one big square.

Area = 15 × 15 - 3 × 3 - 3 × 3 - 12 × 12

Area = 225 - 9 - 9 - 144

Area = 225 - 162

Area = 63

The area of the shaded region is 63 square units.

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The amount that Ayaan will have in his tax-free savings account after 6 months of depositing $746 at 2.15% interest is $754.02.

The future value refers to the present value plus the interest.

The future value for this savings account can be computed using the simple interest system since there is no compounding of interest.

The initial deposit (present value) = $746

Interest rate = 2.15%

Savings period = 6 months

Future value = $754.02 ($746 + ($746 x 2.15% x 6/12)

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Answer:

1. 302.1 ÷ 5 can be rewritten as 181.26 ÷ 3

2. 12.15 ÷ 0.02 can be rewritten as 2430 ÷ 4

3. 1.375 ÷ 0.11 can be rewritten as 75 ÷ 6

Step-by-step explanation:

Hope this helps!

Answer:

27?

Step-by-step explanation:

because 1 page per 1 hour leads up to 27 hours for 27 pages. Or if your not counting the 10 pages she has already written, she spent 17 hours.

The number of people with scores greater than X = 14 cannot be determined based on the given frequency distribution.

The given distribution provides information about the number of people in specific score ranges, but it does not specify the exact scores of individuals within those ranges. Therefore, we cannot determine the number of people with scores greater than X = 14.

Given the distribution provided, we can determine the number of people who had scores greater than X = 14 by summing the frequencies of the score ranges that are greater than 14. From the given information, the score ranges greater than 14 are 15-19 and 20-25.

The frequency for the 15-19 range is given as 5, and the frequency for the 20-25 range is given as 2. Therefore, the total number of people with scores greater than 14 is 5 + 2 = 7.

Without knowing the exact scores of individuals within the given ranges, it is not possible to determine the number of people with scores greater than X = 14.

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Answer:

1020

Step-by-step explanation:

Answer: CD

Step-by-step explanation:

The solution set is,

\(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

option A is the correct answer.

From the question, we have

2cos⁡(θ)=2cos⁡(2θ)

cos⁡(2θ)-cos⁡(θ)=0

2cos^2⁡(θ)-cos⁡(θ)-1=0

cos⁡(θ)=(1±√(1+8))/(2×2)

cos⁡(θ)=1, cos⁡(θ)=-1/2

      \(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

The solution is,

\(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

Multiplication:

Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.

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Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. The median weight of the players on the football team is 160 pounds.

The box plot shows that the median weight of the players is the middle value of the distribution. In this case, the median weight is halfway between the 26th and 27th players, which is 160 pounds.

The box plot also shows that the minimum weight of the players is 150 pounds and the maximum weight is 212 pounds. The interquartile range, which is the range of the middle 50% of the data, is 20 pounds.

In conclusion, the median weight of the players on the football team is 160 pounds. This means that half of the players on the team weigh more than 160 pounds and half of the players weigh less than 160 pounds.

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Answer:

10th term = .076208...

Step-by-step explanation:

The sequence is a geometric sequence

Use the formula

\(a_{n} = ar^{n - 1}\) where "a" is the first term, r is the common ratio and n is which term in the sequence.

So, in your problem a = 4500, r = 1500/4500 = 1/3 and n = 10

\(a_{10} = 4500(1/3^{10 - 1} )\)

     = 4500(1/59049) = .076208...

The total amount of money Jessica paid to rent the apartment for 6 years is $54,120.61.

   In the first year, Jessica paid $8,756.85 for rent.

   For the subsequent years, the rent increased by 1.95% annually.

To calculate the rent for each year, we can use the following formula:

New rent = Previous year's rent + (1.95% of Previous year's rent)

Let's calculate the rent for each year:

Year 2:

New rent = $8,756.85 + (0.0195 * $8,756.85)

New rent = $8,756.85 + $170.71

New rent = $8,927.56

Year 3:

New rent = $8,927.56 + (0.0195 * $8,927.56)

New rent = $8,927.56 + $174.05

New rent = $9,101.61

Year 4:

New rent = $9,101.61 + (0.0195 * $9,101.61)

New rent = $9,101.61 + $177.63

New rent = $9,279.24

Year 5:

New rent = $9,279.24 + (0.0195 * $9,279.24)

New rent = $9,279.24 + $180.94

New rent = $9,460.18

Year 6:

New rent = $9,460.18 + (0.0195 * $9,460.18)

New rent = $9,460.18 + $184.26

New rent = $9,644.44

To find the total amount paid, we add up the rent for all 6 years:

Total amount = Rent for year 1 + Rent for year 2 + Rent for year 3 + Rent for year 4 + Rent for year 5 + Rent for year 6

Total amount = $8,756.85 + $8,927.56 + $9,101.61 + $9,279.24 + $9,460.18 + $9,644.44

Total amount = $54,120.61

Therefore, Jessica paid a total of $54,120.61 to rent the apartment for 6 years.

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Answer:

134/1111

Step-by-step explanation:

Answer:

Reduce the expression, if possible, by cancelling the common factors.

Exact form:  \(\frac{134}{1111}\)

Decimal form: 0.1206...   (repeating)

Given differential equation is dt dM = 0.11 MIntegrating both sides, we getdM/M = 0.11 dt∫dM/M = ∫0.11 dtln|M| = 0.11t + C1 Taking antilog, we get|M| = e0.11t+C1|M| = ke0.11t.

Where k = ±eC1 Thus, the general solution of the given differential equation isM = ±ke0.11tNow, let's check the solution by substituting into the differential equation.

M = ±ke0.11tdM/dt = 0.11ke0.11tdt/dt = 1L.H.S = dt/dt dM/dt = 0.11ke0.11tR.H.S = 0.11M = 0.11(±ke0.11t)= ±ke0.11t∴ L.H.S = R.H.STherefore, the solution M = ±ke0.11t satisfies the given differential equation. MIntegrating both sides, we getdM/M = 0.11 dt∫dM/M = ∫0.11 dtln|M| = 0.11t + C1 Taking antilog, we get|M| = e0.11t+C1|M| = ke0.11t.

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Answer:

5 = w/2.2

To isolate w, we need to apply inverse operations.

The inverse operation of division is multiplication (because w is being divided by 2.2), so we multiply by 2.2 on both sides;

x2.2 x2.2

11 = w