(x+0)(x+5) what does this mean im confused whats the answer

In a one-tail hypothesis test where you reject h0 only in the upper tail

-1.2910  is the p-value.

P value = P (z > 1.70) = 1 - P(2<1.7) = 0.0446

P value = P (z > -2.44) = 0.0073

t< n-1 = -1.2910

A p-value is a statistical measure used to test a hypothesis against observed data. The p-value measures the probability of getting the observed result given that the null hypothesis is true. The lower the p-value, the higher the statistical significance of the observed difference.

For null hypothesis significance tests, the p-value is the probability of obtaining an extreme test result that is at least as extreme as the actually observed result, given that the null hypothesis is true.

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Answer:

The answer is ...adding a positive

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4). The optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

Maximize and minimize p = x + 2y

subject to:

x + y ≥ 4

x + y ≤ 10

x - y ≤ 4

x - y ≥ -4

First, let's graph the feasible region defined by the given constraints:

Plotting the lines:

x + y = 4 (solid line)

x + y = 10 (solid line)

x - y = 4 (solid line)

x - y = -4 (solid line)

The feasible region is the area that satisfies all the constraints and is bounded by the lines on the graph.

Upon examining the feasible region, we can observe that it is a bounded region.

To find the optimal solution, we need to evaluate the objective function p = x + 2y at the vertices (corner points) of the feasible region.

Now, let's find the vertices of the feasible region by solving the intersection points of the lines:

1. Intersection of x + y = 4 and x + y = 10:

Subtracting the equations, we get 0 = 6, which is not possible. No intersection point exists for these lines.

2. Intersection of x + y = 4 and x - y = 4:

Adding the equations, we get 2x = 8, x = 4. Substituting x = 4 into x + y = 4, we get 4 + y = 4, y = 0. The first vertex is (4, 0).

3. Intersection of x - y = 4 and x - y = -4:

Adding the equations, we get 2x = 0, x = 0. Substituting x = 0 into x - y = 4, we get -y = 4, y = -4. The second vertex is (0, -4).

Now, we evaluate the objective function at each vertex:

p(4, 0) = 4 + 2(0) = 4

p(0, -4) = 0 + 2(-4) = -8

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4).

Therefore, the optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

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Answer:

-60x+(-85y)

Step-by-step explanation:

Answer:

umm... i need a problem or anything bud

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

(y^3 * 2^5)^2

3x2=6

5x2=10

y6x2^10

Answer:

Step-by-step explanation:

Answer:

1. x = -4, y = -5

Chosen strategy was to substitute for y in the second equation since the first equation gives y in terms of x. This gives an equation in x which can be solved for x, then y can be found by substituting for x in the first equation

2.  x = -2, y = -3
Strategy used is to eliminate the x terms by simply adding the equations since the coefficients of x are the same but of opposite signs. Solve for y and use this value to solve for x by substituting in any one equation

3. x = -5, y = 6

Strategy used was to set the RHS of the equations equal to each other since both equations are  equations with y on the LHS. Solve for x then use this value to find y value

4. x = 0, y = 1

Strategy used was to get the y coefficients same but of opposite signs, add the two equations to eliminate the y term, solve for x and then solve for y by substituting x in one of the equations - in this case, the second equation

Step-by-step explanation:

Here is how I would answer this question. Remember there are multiple ways of solving a linear equation of two variables but looking at the equations and from experience, I have chosen the most efficient way (my opinion)

Q1.

y = x - 1     [1]
3x - 4y = 8  [2]

Since we are given y = x - 1 in Eq [1], an obvious strategy is to substitute for y in eqn [2]

=>  3x - 4y

=>  3x - 4(x-1)
=>  3x - 4x - 4(-1) =
=> 3x -4x + 4

=> -1x + 4

=> -x + 4

And we know that eqn [2] has 8 on the RHS

∴   -x + 4 = 8

Subtract 4 from both sides

-x + 4 - 4= 8 -4
-x = 4

Multiply by -1 both sides

x = -4

Substitute for x in equation [1] y = x - 1 to get
y = -4 - 1 = -5

Solution: x = -4, y = -5

Q2
3x + 2y = -12    [1}

-3x + 2y = 0     [2]

Here we can see the coefficients of x are the same but with opposite signs

Adding the two equations will eliminate the x terms and  allow us to solve for y which can be used then to solve for x

Adding [1] and [2] gives

3x + 2y + (-3x + 2y) = -12 + 0

4y = -12

y = -3

Substitute for y in equation [1]

=> 3x + 2(-3) = -12

=> 3x - 6 = -12

=> 3x = -12 + 6  (adding 6 on both sides

=> 3x = -6

x = -2

Solution x = -2, y = -3

Strategy used: Adding both equations to eliminate x terms since x coefficients are same but of different signs

Q3

y = 3x + 21  [1]

y = 2x + 16  ][2]

Since we have two expressions for y in terms of x, set the RHS of equations [1] and [2] to be equal and solve for x

=>  3x + 21 = 2x + 16

Subtract 2x from both sides

=> 3x - 2x  + 21 = 16

=> x + 21 = 16

Subtract 21 from both sides

x = 16 - 21  = -5

Substitute for x in equation [2]
y = 2x + 16

=> y =  2(-5) + 16

y = -10 + 16

y = 6

Solution: x = -5, y = 6

Q4

2x - 7y = -7   [1]

x + y = 1        [2]

We can make the coefficients of one of the variable in both equations the same and either add/subtract as necessary to eliminate one of the variable terms and solve for the other

Multiply [2] by 7 to get
7x + 7 y = 7   [3]

[1] and [3] have y coefficients same but of opposite signs so add [1] and [3] together

2x - 7y + (7x + 7y ) = - 7 + 7

2x + 7x - 7y + 7y = 0

9x = 0

x = 0

Sub for x in [2] x + y = 0 to get

0 + y = 1

or y = 1

Solution: x = 0, y = 1

Strategy used was to get the y coefficients same but of opposite signs, add the two equations to eliminate the y term, solve for x and then solve for y by substituting x in one of the equations - in this case, the second equation

The last digit of the product of all the numbers between 11 and 29 is 0.

A product is something that has undergone one or more multiplications.

Here, we're looking for the final digit of the product of all whole numbers greater than 11 and less than 29.

Next, we have the product as: 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28

Now take note of the 20 that is present.

Any number multiplied by 20 will result in a zero, so:

Product = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)

Using only that, we can infer that 0 represents the final digit in the product of all the numbers between 11 and 29.

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Excision of

benign lesions

on chest, 0.4 cm, with simple closure(CPT CODE)CPT code is a five-digit numeric code that is used to describe medical, surgical, and diagnostic procedures.

The CPT code for the Excision of benign lesions on chest, 0.4 cm, with simple closure is 11400. The CPT code 11400 is used to report the removal of benign lesions or skin tags. It is a

surgical

procedure performed to remove a benign lesion, which is a tumor that is not

cancerous

.

The

excision

of benign lesions is performed for a variety of reasons, including cosmetic purposes, symptom relief, or to prevent the

lesion

from becoming cancerous. Excision of benign lesions on chest, 0.4 cm, with simple closure is a minor surgical procedure that can be performed in an outpatient setting.

The simple closure refers to the wound closure technique, where the edges of the incision are brought together and closed with sutures or staples. A simple closure is used when the wound is small and does not require extensive tissue

rearrangement

or grafting. The excision of benign lesions on the chest, 0.4 cm, with simple closure is performed to remove a benign lesion or tumor from the chest area that measures 0.4 cm in size.

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The income you need to afford a $425,000 house is largely dependent on your debt-to-income ratio, credit score, and down payment. However, a general rule of thumb is to have an annual income that is at least three times the purchase price of the home, which in this case would be $1,275,000.

To more accurately determine the income needed to afford a $425,000 house, consider factors such as the interest rate on the mortgage, property taxes, homeowners insurance, and any homeowner association fees.

These additional expenses can significantly impact your monthly mortgage payment and thus your income requirements.
It's important to keep in mind that lenders have varying criteria when determining mortgage eligibility and income requirements, so it's best to speak with a mortgage professional to get a more accurate estimate based on your individual circumstances.

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\(\huge\color{pink}\boxed{\colorbox{black}{Answer♡}}\)

so ,

\(new \: selling \: price = 150 + \frac{26}{100} \times 150 \\ = > 150 + 39 \\ = > 189 \: rs\)

hσpє hєlpful~

Based on the information given the selling price of the pen set is $189.

Using this formula

Selling price=Selling price of pen+(Profit percentage× Selling price of pen)

Let plug in the formula

Selling Price=$150 +( 26% ×$150)

Selling Price=$150 +$39

Selling Price=$189

Inconclusion  the selling price of the pen set is $189.

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The solution of the given system of equations is x = -4, y = 5 and z = 2 is the answer.

The system of equations given below:x + 2y + 3z = 11;2x + 4y + 5z = 21;3x + 5y + 6z = 27.

Here, we will solve this system of equations using inverse of the matrix method as follows:

We can write the given system of equations in matrix form as AX = B where, A = [1 2 3; 2 4 5; 3 5 6], X = [x; y; z] and B = [11; 21; 27].

The inverse of matrix A is given by the formula: A-1 = (1/ det(A)) [d11 d12 d13; d21 d22 d23; d31 d32 d33]  where,

d11 = A22A33 – A23A32 = (4 × 6) – (5 × 5) = -1,

d12 = -(A21A33 – A23A31) = -[ (2 × 6) – (5 × 3)] = 3,

d13 = A21A32 – A22A31 = (2 × 5) – (4 × 3) = -2,

d21 = -(A12A33 – A13A32) = -[(2 × 6) – (5 × 3)] = 3,

d22 = A11A33 – A13A31 = (1 × 6) – (3 × 3) = 0,

d23 = -(A11A32 – A12A31) = -[(1 × 5) – (2 × 3)] = 1,

d31 = A12A23 – A13A22 = (2 × 5) – (3 × 4) = -2,

d32 = -(A11A23 – A13A21) = -[(1 × 5) – (3 × 3)] = 4,

d33 = A11A22 – A12A21 = (1 × 4) – (2 × 2) = 0.

We have A-1 = (-1/1) [0 3 -2; 3 0 1; -2 1 0] = [0 -3 2; -3 0 -1; 2 -1 0]

Now, X = A-1 B = [0 -3 2; -3 0 -1; 2 -1 0] [11; 21; 27] = [-4; 5; 2]

Therefore, the solution of the given system of equations is x = -4, y = 5 and z = 2.

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The probability that the students will be arranged in order from shortest to tallest is 1/(8!) or 1/40320.

Student is an individual who is enrolled in an educational institution such as a university, college, or a trade school. A student typically takes courses in order to further their knowledge and skills, to prepare for further education or training, or to receive credentials necessary to pursue a job or career. Students can include both full-time and part-time learners. Depending on the institution, a student may also be referred to as a pupil, student-athlete, or scholar. Students can also take part in a variety of student-led activities and organizations, both on-campus and off-campus.

This is because there are 8! (8 factorial) ways in which the students can be arranged in order from shortest to tallest.
Therefore, the probability of any one arrangement is 1/8!  
Thus, the probability of the students being arranged in order from shortest to tallest is 1/8! or 1/40320.

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Answer:

Step-by-step explanation:

The answer is not in the option

Step one:

given data:

we are told that the hourly earning= $8.50

then additional tip=$80

total earnings=$131.

Step two:

the linear function for the total earning is the same as the equation of a line

y=mx+c

where

y represents the total earning of $131

m represents the hourly earning= $8.50

x represents the number of hours h

c represents the tip of $80

The expression for the situation is modeled as

Answer:

The answer is 160. There are 160 boys in the school. Take 360 divide by 9, then multiply by four.  

Step-by-step explanation:

Answer:

\( \sf \: \frac{6}{7} \times 14 = 12\)

Step-by-step explanation:

Given problem,

\( \sf \rightarrow \: \frac{6}{7} \times 14\)

Let's solve the problem,

\( \sf \rightarrow \: \frac{6}{7} \times 14\)

\( \sf \rightarrow \frac{6}{\cancel{ \: 7 }} \times \cancel{14}\)

\( \sf \rightarrow \: 6 \times 2\)

\( \sf \rightarrow \: 12\)

Hence, the answer is 12.

Answer:

Option D

Step-by-step explanation:

Hackers send fraudulent emails and social media requests to people and once a person clicks on any such link, the hacker gets the access to the device and in most of the cases, apart form leaking of personal details there has been problem of unethical money transfers/frauds.

Hence, option D is an internet security issue

Answer:

-4x

Step-by-step explanation:

3-7=-4 just add a x

Answer:

51.5

Step-by-step explanation:

For the given cubic polynomial function (a) c = -6, d = 9, and k = -4, critical numbers are x = -2 and x = 1/3 (b) The critical number of the function f on the interval [1,3] is 0.

Given cubic polynomial function f(x) = x³ + x² + cx + d, to find the values of c, d, and k, such that 0 is a critical number, (0)=9, and the point (1,-1) is an inflection point of f(x). Inflection point - If the sign of the second derivative of a function changes at a point, then that point is known as the inflection point. Critical number - The critical numbers of a function are those values of x for which f'(x) = 0 or f'(x) does not exist. Now let's solve the question.(1) f(x) = x³ + x² + cx + df(0) = 0³ + 0² + c * 0 + d= 0 + 0 + 0 + d= d ...(i) f(x) = x³ + x² + cx + df'(x) = 3x² + 2x + c

For the critical number, f'(x) = 0 => 3x² + 2x + c = 0 ...(ii).Now (0) = 9 => d = 9 from equation (i).f(1) = 1³ + 1² + c * 1 + 9 = 1 + 1 + c + 9 = c + 11 and the point (1,-1) is an inflection point of f(x).  Therefore, f"(1) = 0 => 6 + c = 0 => c = -6 ...(iii) Substituting equation (iii) in equation (ii),3x² + 2x - 6 = 0 => x² + (2/3)x - 2 = 0 => (x + 2)(x - 1/3) = 0 => x = -2, 1/3 are the critical numbers.

(b) The given function is f(x) = x²√3 - x On differentiating w.r.t x, we get f'(x) = 2x√3 - 1We can observe that f'(x) is defined for all values of x. Hence, there are no critical numbers in the interval [1, 3]. Thus, the critical number of the function f on the interval [1,3] is 0. Answer: (a) c = -6, d = 9, and k = -4, critical numbers are x = -2 and x = 1/3.(b) The critical number of the function f on the interval [1,3] is 0.

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Answer:

x = -8, y = 2, or (-8,2)

Step-by-step explanation:

Hope it helps

Answer:

the required answers are :

a) x = 4

b) x = 3

c) a = 7

d) x = -15

Step-by-step explanation:

the whole process is given in the solution in attached picture. okay

Answer:

y = 5x + 14

Step-by-step explanation:

Let x = number of day and y = number of drawings.

She draws 5 drawings per day, so in x days, she draws 5x drawings.

She started with 14 drawings, so the total number of drawings in any day, x, is

5x + 14.

The equation is

y = 5x + 14

Answer: 5.450 x 10^-4 x 3.550 x 10^-7

19.3475 x 10^-11

1.935 x 10^10

Answer:

1.93475 x 10^-10

Step-by-step explanation:

5.450X10^-4 * 3.550X10-7

= 1.93475 x 10^-10

The median for the given continuous random variable is m = ±6.65

Let x be a continuous random variable over [a, b] with probability density function f.

Then the median of the x-values is that number m such that integral^ma f(x)dx = 1/2.

Find the median.

Given, f(x) = 1/242x and [0,22].

To find the median, we need to find the number m such that integral^ma f(x)dx = 1/2.

Now, let's calculate the integral,

∫f(x)dx = ∫1/242xdx

= ln|x|/242 + C

Applying the limits,\(∫^m_0 f(x)dx = ∫^0_m f(x)dx\)

∴ln|m|/242 + C

= 1/2 × ∫\(^22_0 f(x)dx\)

= 1/2 × ∫\(^22_0 1/242xdx\)

= 1/2 [ln(22) - ln(0)]/242

Now, we need to find m such that ln|m|/242

= [ln(22) - ln(0)]/484

ln|m| = ln(22) - ln(0.5)

ln|m| = ln(22/0.5)

m = ± √(22/0.5)

[Since the range is given from 0 to 22]

m = ± 6.65

Hence, the median is m = ±6.65

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The n 1/2 of the se 1/4 of the sw 1/4 and the ne 1/4 of the sw 1/4 of Section 19 contains 40 acres.

The method used for land surveying is called the government rectangular survey system.

This system is commonly known as the Public Land Survey System (PLSS) of the United States. It is based on a grid network. The grid is formed with meridians and baselines.

The meridians are the imaginary lines running north to south, and the baselines are the imaginary lines running east to west. The meridians and baselines are named as ranges and townships, respectively.

Each range is 6 miles wide and numbered consecutively, beginning with the one on the far west side of the state. The townships are numbered from 1 to 36, in sequence, beginning at the southeast corner of the state. The government rectangular survey system divides the land into smaller units as follows:

Each township is further divided into 36 sections, each section is one square mile, or 640 acres.

Each section is further divided into halves, or 320 acres, and each half is divided into quarters, or 160 acres, and each quarter is divided into quarters again, or 40 acres.

Finally, each 40-acre parcel is divided into quarters, or 10 acres.

Therefore, the n 1/2 of the se 1/4 of the sw 1/4 and the ne 1/4 of the sw 1/4 of section 19 contains 40 acres.

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Answer:

C

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Therefore, WT > 17 and WT > 18, so the smallest possible value of WT is 18. Therefore, WT ≈ 18.

The product of the lengths of their crossed arcs, divided by two, determines the size of each angle formed when two secants or chords cross paths inside of a circle. An inscribed angle's measurement is equal to half of its intercepted arc's measurement.

m ZYX = m(arc WY) + m(arc ZX) = 44° + 68° = 112° since arc WY = 44° and arc ZX = 68°. (vertical angles).

The opposing angles in the cyclic quadrilateral ZTYX are additional. m ZTX = 180° - m ZYX = 180° - 112° = 68°, as a result.

As a result, m ZTX = 68°.

(2) The Pythagorean theorem can be used to determine the length of the missing side TZ because WTX is a right triangle:

WT² + TX² = TZ²

(4.8)² + (8.0)² = TZ²

23.04 + 64 = TZ²

87.04 = TZ²

TZ ≈ 9.33

Therefore, TZ ≈ 9.33.

(3) The Triangle Inequality Theorem gives us the following:

WT + TY > WY

WT + 8 > 25

WT > 17

WT + TX > WX

WT + 8 > 25

WT > 17

Consequently, WT can only have a minimum value of 18.

WT can have a minimum value of 18 since WT > 17 and WT > 18.

Therefore, WT ≈ 18.

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Question:

In the given figure, m(arcWY)=44

o

,m(arcZX)=68

then

(1) Find the measure of ∠ZTX.

(2) If WT=4.8,TX=8.0,YT=6.4, find TZ.

(3) If WX=25,YT=8,YZ=26, find WT.