Writing Equations of lines

Write the equation of each line with the given information

through: (-3, 4) and (-5, -1)

Answer:

Hello There!!

Step-by-step explanation:

The answer is that=>Yes It is a rational number.

hope this helps,have a great day!!

~Pinky~

Answer:

Yes.

Step-by-step explanation:

A rational number is any number that can be written as a fraction. These include whole numbers, fractions, decimals that end, and decimals that repeat. Positive and negative do not affect rationality.

Answer:

k-k-k-kabbajje!

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\huge\textsf{What is addition \& subtraction?}\)

\(\huge\textbf{What is addition?}\)

\(\bullet\large\textbf{ Well, \underline{addition} simply means when you're ADDING}\\\large\textbf{2 or more numbers from each other to get the result of}\\\large\textbf{a number.}\)

\(\huge\textbf{Random notes}\)

\(\star\large\textbf{ Usually, you start working with addition when you're in}\\\large\textbf{pre-kindergarten (pre-k also known as head-start)}\\\\\star\large\textbf{ When, you're adding you are going upward.}\\\\\star\large\textbf{ Addition sometimes come after you learn how to count}\\\large\textbf{the basic numbers and so forth because adding never}\\\large\textbf{ends if you really think about.}\)

\(\huge\textbf{Example:}\)

\(\heartsuit\large\textbf{ 2 \boxed{\bf +} 5 = 7}\\\\\\\heartsuit\large\textbf{ You got the result of 7 because you started at 2 \& went}\\\larg\textbf{up 5 spaces to your right on your number and you landed}\\\large\textbf{on 7.}\)

\(\huge\textbf{What is subtraction?}\)

\(\bullet\large\textbf{ Well, subtraction simply means you're taking away. Often}\\\large\textbf{people call it take aways.}\)

\(\huge\textbf{Random notes:}\)

\(\star\large\textbf{ Usually, you start working with subtraction when you're}\\\large\textbf{in pre-kindergarten (pre-k also known as headstart)}\\\\\star\large\textbf{When you're subtracting you are doing downward.}\\\\\star\large\textbf{You focus more on subtraction when you're counting}\\\large\textbf{backwards.}\)

\(\huge\textbf{Example:}\)

\(\heartsuit\large\textbf{ 7 \boxed{\bf -} 5 = 2 }\\\\\\\heartsuit\large\textbf{ 7 \boxed{\bf -} 2 = 5}\\\\\\\heartsuit\large\textbf{ For equation \#1. you begin at 7 and go BACK 5 spaces}\\\large\textbf{and you should have landed on 2.}\\\\\\\heartsuit\large\textbf{ For equation \#2. you begin at 7 \& go BACK 2 spaces}\\\large\textbf{and you should have landed on 5.}\)

\(\huge\textsf{KEEP IN MIND:}\)

\(\circ\large\textsf{ Addition OPPOSITE is subtraction \& subtraction OPPOSITE is}\\\large\textsf{addition.}\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitirite1040:)}\)

The total value of the loan with quarterly compounded interest is approximately $45,288.38, while the total value of the loan with monthly compounded interest is approximately $45,634.84. The difference in total interest accrued is approximately $346.46.

Part A: To determine the total value of the loan with quarterly compounded interest, we can use the formula for compound interest:

A = P(1 + r/n)^(nt),

where:

A is the total value of the loan,

P is the principal amount (initial loan amount),

r is the interest rate (in decimal form),

n is the number of times interest is compounded per year,

and t is the number of years.

Given:

P = $20,000,

r = 9% or 0.09,

n = 4 (quarterly compounding),

t = 10 years.

Substituting the values into the formula, we have:

A = 20000(1 + 0.09/4)^(4*10).

Calculating this value, we find:

A ≈ $45,288.38.

Therefore, the total value of the loan with quarterly compounded interest is approximately $45,288.38.

Part B: To determine the total value of the loan with monthly compounded interest, we follow the same formula but with a different value for n:

n = 12 (monthly compounding).

Substituting the values into the formula, we have:

A = 20000(1 + 0.09/12)^(12*10).

Calculating this value, we find:

A ≈ $45,634.84.

Therefore, the total value of the loan with monthly compounded interest is approximately $45,634.84.

Part C: The difference between the total interest accrued on each loan can be calculated by subtracting the principal amount from the total value of each loan.

For the loan with quarterly compounding:

Total interest = Total value - Principal

Total interest = $45,288.38 - $20,000

Total interest ≈ $25,288.38.

For the loan with monthly compounding:

Total interest = Total value - Principal

Total interest = $45,634.84 - $20,000

Total interest ≈ $25,634.84.

The difference between the total interest accrued on each loan is approximately $346.46.

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The regression equation is: y = -0.0068824x + 36.8881

So, the correct option is:

D) None of these.

To compute the regression equation based on the given data, we can use the formulas for slope (b1) and y-intercept (bo):

b1 = (NΣXY - ΣXΣY) / \((N\sum X^2 - (\sum X)^2)\)

bo = (ΣY - b1ΣX) / N

Where:

N = Number of data points (in this case, 11)

ΣX = Sum of all X values (prices)

ΣY = Sum of all Y values (average number of pounds sold per day)

ΣXY = Sum of the product of X and Y values

\(\sum X^2\) = Sum of the squares of X values

Using the provided data:

Ex = 210

Xy = 450

Zcy = 10387

Zz = 7275

Xy = 42471

Let's calculate the required values:

N = 11

ΣX = Ex + Zcy + Zz = 210 + 10387 + 7275 = 17872

ΣY = Xy = 450

ΣXY = Xy = 450

\(\sum X^2 = (Ex)^2 + (Zcy)^2 + (Zz)^2 = (210)^2 + (10387)^2 + (7275)^2 = 239208144\)

Now, substitute these values into the formulas to find b1 and bo:

\(b1 = (11 \times450 - 17872 \times 450) / (11 \times239208144 - (17872)^2)\)

= -14112250 / 2050445128

≈ -0.0068824

bo = (450 - (-0.0068824 \(\times\) 17872)) / 11

= (450 + 122.7790368) / 11

≈ 36.8881

Therefore, the regression equation is:

y = -0.0068824x + 36.8881

So, the correct option is:

D) None of these.

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The complete question may be like:

Over a period of one year, retailer sells widgets at 11 different prices. He Calculates the average number of oiunds sold per day at each different price. From theese data, the following are calculated. Ex = 210, Xy = 450, Zcy = 10387, Zz? 7275 Xy? 42471 Compute the regression equation , SELEC A) y 0.20261x + 0.549951 B) y = 0.549951x + 30.410021 C) y = 0.20261. + 30.410021 D) none of these =b1x + bo.

The trigonometric equations has the following solutions: x = 0 + j · π or x = 0.352π + j · π or x = - 0.352π + j · π, where j is a non-negative whole number.

In this problem we find the case of a trigonometric equation, whose solutions on the interval [0, 2π] must be found. This can be done by both algebra properties and trigonometric formulae. First, write the entire expression:

tan² x · sec² x + 2 · sec² x - tan² x = 2

Second, use trigonometric formulas to reduce the number of trigonometric functions:

tan² x · (tan² x + 1) + 2 · (tan² x + 1) - tan² x = 2

Third, expand the equation:

tan⁴ x + tan² x + 2 · tan² x + 2 - tan² x = 2

tan⁴ x + 2 · tan² x = 0

Fourth, factor the expression:

tan² x · (tan² x - 2) = 0

tan² x = 0 or tan² x = 2

tan x = 0 or tan x = ± √2

Fifth, determine the solutions to trigonometric equation:

x = 0 + j · π or x = 0.352π + j · π or x = - 0.352π + j · π, where j is a non-negative whole number.

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Answer:

11/18

Step-by-step explanation:

let n represent the number to be found

simplify the ratio on the right by multiplying both parts by 3

we now have

n/11 =11/18  ( cross-multiply )

18n = 11 ( divide both sides by 18 )

n = 11/18

Answer:

a = 0.9

Step-by-step explanation:

For the quadratic equation \(\boxed{ax^2 + bx + c = 0}\) to have exactly one real root, the value of its discriminant, \(\boxed{b^2 - 4ac}\), must be zero.

For the given equation:

\(y = ax^2 - 6x + 10\),

• a = a

• b = -6

• c = 10.

Substituting these values into the formula for discriminant, we get:

\((-6)^2 - 4(a)(10) = 0\)

⇒ \(36 - 40a = 0\)

⇒ \(36 = 40a\)

⇒ \(a = \frac{36}{40}\)

⇒ \(a = \bf 0.9\)

Therefore the value of a is 0.9 when the given quadratic has exactly one root.

Answer:

See answer below.

Step-by-step explanation:

The ordered pairs on the graph: (-6, -1), (-1, 3), (2, 0), (4, -2), and (5, 3).

The domain is the values of x-term in the ordered pair not repeating a number.

The range is the values of y-term in the ordered pair not repeating a number.

Domain is  {-6, -1, 2, 4, 5}

Range is {-1, 3, 0, -2}      Note: Only use 3 one time in the set because it was repeated.

The amount cheaper is the car washes Malcolm orders than the car washes Martha's order is $13.

The correct answer choice is option B.

Malcolm's gift card = $50.

Cost Malcolm's car wash per visit = $7

Martha's gift card = $180

Cost Martha's car wash per visit = Difference between gift card balance of first and second visit

= $180 - $160

= $20

How cheap is the car washes Malcolm orders than the car washes Martha's order = $20 - $7

= $13

Therefore, Malcolm's car wash is cheaper than Martha's car wash by $13

The complete question is attached in the diagram.

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Answer:

Step-by-step explanation:

V = 1/3 * pi * r^2 * h

r = ?

pi = 3.14

h = 17 cm

3*V = pi * r^2 h = r^2    Divide by pi

3*V/pi = r^2 h  = r^2     Divide by h

3*V/(pi*h)         =r^2      Take the square root of the left to get just  r

sqrt(3*V/(pi*h))  = r         Now solve the equation.

sqrt(3*538.25 /(3.14*17)) = r

sqrt(1614 / 53.38) =

r = sqrt(30.24)

r = 5.493

the answer is C

18 -2=16

16/2=8

-7+1=6-

6/2=3-

D. I and IV are the quadrants the cosine function is positive

To determine in which quadrants the cosine function is positive, we need to consider the signs of cosine in different quadrants of the Cartesian coordinate system.

The unit circle is a useful tool to understand the behavior of trigonometric functions. In the unit circle, the x-coordinate represents the cosine value, while the y-coordinate represents the sine value. The cosine function is positive in the quadrants where the x-coordinate is positive.

Quadrant I is the top-right quadrant, where both the x and y coordinates are positive. In this quadrant, cosine is positive because the x-coordinate is positive.

Quadrant II is the top-left quadrant, where the x-coordinate is negative, but the y-coordinate is positive. In this quadrant, cosine is negative because the x-coordinate is negative.

Quadrant III is the bottom-left quadrant, where both the x and y coordinates are negative. In this quadrant, cosine is negative because the x-coordinate is negative.

Quadrant IV is the bottom-right quadrant, where the x-coordinate is positive, but the y-coordinate is negative. In this quadrant, cosine is positive because the x-coordinate is positive.

Based on this analysis, we can conclude that cosine is positive in Quadrant I and Quadrant IV. Therefore, the correct answer is D. I and IV.

It's important to note that this applies to the standard unit circle and the principal values of cosine. When considering periodicity and multiple revolutions around the unit circle, the positive regions of cosine will repeat every 360 degrees or 2π radians.

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The image of quadratic function f(x) = x² is equal to g(x) = 6 · x².

In this question we see the representation of quadratic equation f(x) = x², from which we need to generate the image of this function, this can be done by a rigid transformation known as vertical dilation:

g(x) = k · f(x), k > 1

Where:

If we know that f(x) = x² and k = 6, then the image of function is:

g(x) = 6 · x²

Whose representation on Cartesian plane is shown in the image attached below.

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Step-by-step explanation:

Since we have three sides and trying to find an angle, use Law of Cosines

\(c = \sqrt{ {a}^{2} + {b}^{2} - 2ab \times \cos(d) } \)

where c is

Solving for the angle d.

\( \cos {}^{ -1 } (( \frac{ {c}^{2} - {b}^{2} - {a}^{2} }{ - 2ab} ) = d\)

where d is in degrees

The angle d is the opposite of the side c.

It does not matter what a and b is(they can be either 4 or 5)

let

c=7

a=4

b=5

\( \cos {}^{ - 1} ( \frac{ - 1}{5} ) = d\)

This angle must be within 0 and 180

We get

\(d = 101.54\)

Answer:

Mark as brainliest please!

Step-by-step explanation:

3/8 and in decimal form it is 0.375

Answer:

2/3 or 67%

Step-by-step explanation:

To find the exact probability for you to reach into the orange balls you'll have to do a data table on which you'll include how many orange balls are by the total amount of balls that are within the urn.

For example:
The urn contains:

* 10 red balls
* 20 yellow balls
* 60 orange balls

Total amount of balls that you have on the urn is 90, you'll get this result by doing a simple addition of the table of content.

Afterwards, we have to find the probability, so you will have to take the amount of orange balls (which is 60) and divide it by 90 (Which is the total amount of balls you have on the urn).

60/90

A quick tip for you to do this on a simplified manner is by dividing the numerator and the denominator by their greatest common divisor (Which in this case is 30) (30x2 = 60) (30x3 = 90)

60/90 = (60 divided 30) / (90 divided 30) = 2/3

To resolve this problem, we get that the probability of selecting an orange ball is 2/3 or approximately 0.67 which we'll simplify to 67%

I hope this helped you

The solution for x in the equation x + 3x + 5 + 2 = ? is x = (? - 7) / 4.

We must first reduce the equation's left side in order to find the value of x in the formula x + 3x + 5 + 2 =?

x + 3x + 5 + 2 = 4x + 7

The formula for the equation is now 4x + 7 =? We must isolate x on one side of the equation in order to find its value. By taking 7 away from both sides, we can accomplish this:

4x + 7 - 7 = ? - 7

After examining the right side and simplifying the left, we arrive at:

4x = ? - 7

Now, we must split both sides by 4 in order to isolate x:

4x / 4 = (? - 7) / 4

After examining the right side and simplifying the left, we arrive at:

x = (? - 7) / 4

As a result, x = (? - 7) / 4 is the answer to the equation x + 3x + 5 + 2 =?

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The workers percentile score is given as follows:

69.15%.

The z-score of a measure X of a normally distributed variable that has mean represented by \(\mu\) and standard deviation represented by \(\sigma\) is obtained by the equation presented as follows:

\(Z = \frac{X - \mu}{\sigma}\)

The z-score for this problem is given as follows:

z = 0.5.

Hence the percentile score is of 69.15%, as z = 0.5 has a p-value of 0.6915.

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Now

Distance:-

Answer:

We can use the formula for compound interest to solve this problem. The formula is:

A = P * (1 + r/n)^(n*t)

where:

A = the amount of money after t years

P = the principal amount (the initial investment)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

In this case, P = $5000, r = 0.03, n = 12 (since the interest is compounded monthly), and t = 10. Plugging these values into the formula, we get:

A = 5000 * (1 + 0.03/12)^(12*10)

A = 5000 * (1.0025)^120

A ≈ $6,621.36

So the investment will be worth approximately $6,621.36 after 10 years.

Answer:

21000

Step-by-step explanation:

2745 -> 3000

6.9 -> 7

3000 x 7 =

21000

Answer:

1. 77520

2. \(P_1\) = 0.0017

3. \(P_2\) = 0.0019

4. \(P_3\) = 0.9981

5. \(P_4\) = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

\(nCx = \frac{n!}{x!(n-x)!}\)

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

\(20C7 = \frac{20!}{7!(20-7)!}=77520\)

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

\(P_1=\frac{20C7}{45C7} =0.0017\)

The probability that all 7 selected workers will be from the same shift is calculated as:

\(P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019\)

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

\(P_3 = 1- P_2=1 - 0.0019 = 0.9981\)

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

\(P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036\)

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

The relationship between y and t can be modeled by an exponential function of the form:

y = a x e^(-rt)

An exponential function is a mathematical function which we write as a

f(x) = aˣ, where a is constant and x is variable term. The most commonly used exponential function is eˣ , where e is constant having value 2.7182

The relationship between y and t can be modeled by an exponential function of the form:

y = a x e^(-rt)

where a is the initial area of the forest (1500 km²), r is the rate of decrease (6.25%), and t is the number of years since 2000.

To find the value of r, we can convert 6.25% to a decimal:

r = 0.0625

Now we can plug in the values for a and r into our exponential function:

y = 1500 x e^(-0.0625t)

This exponential function shows the relationship between the area of the forest and the number of years since 2000.

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The functions for this problem are defined as follows:

The functions for this problem are given as follows:

The addition and subtraction functions for this problem are given as follows:

At x = -2, the numeric value of the subtraction function is given as follows:

(t - s)(-2) = -2³ - 5(-2)²

(t - s)(-2) = -28.

The product function for this problem is given as follows:

(ts)(x) = \(5x^5\)

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To verify if the relation is a function, it must be verified if from each value of x only one arrow departs.

A relation represents a function when each input value is mapped to a single output value.

In mapping notation, with the arrows, it must be verified if there is no input from which more than one arrow departs.

The problem is incomplete, hence the general procedure to verify if the relation is a function was presented.

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