write the number in two other forms (fraction, decimals, or percent 19/20 9/16 0.4 0.22

Answer:

Well, yes it is supposed to be 0

Answer:

$94.12

Step-by-step explanation:

($94.11 + $52.75) + (-$25.20 + -$22.04 + -$8.50) =

($146. 86) - (-$55.74) =

$94.12

$94.12 is the account balance at the end of the month.

The ratio of guppies to cichlids in Sean's aquarium is 7:12

Ratio is a mathematical term used to compare two or more quantities of the same type. It is expressed as the quotient of two numbers, and it indicates how many times one quantity is greater or smaller than another

To find the ratio of guppies to cichlids, we need to divide the number of guppies by the number of cichlids. So

Ratio of guppies to cichlids = Number of guppies / Number of cichlids

Plugging in the given numbers, we get

Ratio of guppies to cichlids = 7 / 12

This ratio cannot be simplified any further since 7 and 12 do not share any common factors other than 1

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Answer:

11) 1 3/8

12) 17/18

Step-by-step explanation:

Answer:

The answer is D

Step-by-step explanation:

Answer:

It would be D, hope this helps!

Answer:

i) around 41.7 kg

ii) 72 books

Step-by-step explanation:

i) if 108 books are 30 kg then how much is the mass for 150? You cross multiply so 150 multiply by 30 and 108 multiply by x (the unknown mass). you will get 4500=108x and then 4500/108 is the unknown mass.

ii) use the same way as above.

Answer:

1,325

Step-by-step explanation:

30 /2

= 155,000 - 245(15)

= 5,000 - 3,675

= 1,325

Answer:

1,325

Step-by-step explanation:

Answer: The measurement of angle B is 50 degrees

Step-by-step explanation: we know all triangles add up to 180 degrees so substitute 40 with a degrees and solve

Step-by-step explanation:

According to the Triangle Sum Theorem, all angles in triangle are sum of 180⁰. This means that m<a + m<b + m<c = 180⁰. You will first solve for a.

m<a + m<b + m<c = 180⁰

2a⁰ + a + 10⁰ + a⁰ = 180⁰ combine like terms.

2a⁰ + a + a⁰ + 10⁰ = 180⁰

4a⁰ + 10⁰ = 180⁰ subtract 10 from both sides.

4a⁰ + 10⁰ - 10⁰ = 180⁰ - 10⁰

4a⁰ = 170⁰ Divide 4 from both sides.

4a⁰ / 4 = 170⁰ / 4

a = 42.5⁰

Now that you found a, plug 42.5⁰ in place of in all angles and solve.

m<a :-

2a⁰

2(42.5)⁰

85⁰

m<b :-

a + 10⁰

42.5⁰ + 10⁰

52.5⁰

m<c :-

a⁰

42.5⁰

m<a = 85⁰

m<b = 52.5⁰

m<c = 42.5⁰

Remember that all angle must sum up to 180⁰ in a triangle. So we will now add all of our angle to find it if it equals 180⁰.

m<a + m<b + m<c = 180⁰

85⁰ + 52.5⁰ + 42.5⁰ = 180⁰

180⁰ = 180⁰

Thus, m<b = 52.5⁰.

Hope this helps, thank you :) !!

The value of US$4.50 in Eastern Caribbean currency is 12.15 dollars.

The exchange rate for one United States dollar (US $1.00) is two dollars and seventy cents in Eastern Caribbean currency (EC$2.70) .

Therefore, the value of US$4.50 in EC currency can be computed as follows:

Using the conversion rate,

1 US dollars = 2.70 Eastern Caribbean dollars

4.50 US dollars = ?

cross multiply

Therefore,

value of 4.5 US dollars to EC dollars = 2.7 × 4.50

value of 4.5 US dollars to EC dollars = 12.15 dollars

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Answer:

C is the answer

Step-by-step explanation:

the third one is the correct one

Answer:

B.

Step-by-step explanation:

She has created a connection of something physical to express a similar conection with her emotions.

The MLE of P(X > 2) is given by,\(\begin{aligned} \hat{P}(X > 2) &= (1-\hat{p}_{MLE})^2 \\ &= \left(1-\frac{1}{\over line{x}}\right)^2 \end{aligned}]\(\therefore \hat{P}(X > 2) = \left(1-\frac{1}{\over line{x}}\right)^2\)Thus, the required maximum likelihood estimate for the probability P(X > 2) is \(\hat{P}(X > 2) = \left(1-\frac{1}{\over line{x}}\right)^2\).

a. Formula for likelihood function:

The likelihood function is given by,![\mathcal{L}(p) = \prod_{i=1}^{n} P(X = x_i) = \prod_{i=1}^{n} p(1-p)^{x_i - 1}]

b. Log-likelihood function:The log-likelihood function is given by,\(\begin{aligned}&\ell(p) = \log_e \mathcal{L}(p)\\& = \log_e \prod_{i=1}^{n} p(1-p)^{x_i - 1}\\& = \sum_{i=1}^{n} \log_e(p(1-p)^{x_i - 1})\\& = \sum_{i=1}^{n} [\log_e p + (x_i-1) \log_e (1-p)]\\& = \log_e p\sum_{i=1}^{n} 1 + \log_e (1-p)\sum_{i=1}^{n} (x_i-1)\\& = n\log_e (1-p) + \log_e p\sum_{i=1}^{n} 1 + \log_e (1-p)\sum_{i=1}^{n} (x_i-1)\\& = n\log_e (1-p) + \log_e p n - \log_e (1-p)\sum_{i=1}^{n} 1\\& = n\log_e (1-p) + \log_e p n - \log_e (1-p)n\end{aligned}]\(\

therefore \ell(p) = n\log_e (1-p) + \log_e p n - \log_e (1-p)n\)Now, we obtain the first derivative of the log-likelihood function and equate it to zero to find the MLE of p. We then check if the second derivative is negative at this point to ensure that it is a maximum. Deriving and equating to zero, we get\(\begin{aligned}\frac{d}{dp} \ell(p) &= 0\\ \frac{n}{1-p} - \frac{n}{1-p} &= 0\end{aligned}]\(\therefore \frac{n}{1-p} - \frac{n}{1-p} = 0\)So, the MLE of p is given by,\(\hat{p}_{MLE} = \frac{1}{\overline{x}}\)

c. Find the maximum likelihood estimate for P(X > 2):We know that for a geometric distribution, the probability of the random variable being greater than some number k is given by,\(P(X > k) = (1-p)^k\)Hence, the MLE of P(X > 2) is given by,\(\begin{aligned} \hat{P}(X > 2) &= (1-\hat{p}_{MLE})^2 \\ &= \left(1-\frac{1}{\overline{x}}\right)^2 \end{aligned}]\(\t

herefore \hat{P}(X > 2) = \left(1-\frac{1}{\overline{x}}\right)^2\)Thus, the required maximum likelihood estimate for the probability P(X > 2) is \(\hat{P}(X > 2) = \left(1-\frac{1}{\overline{x}}\right)^2\).

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When three electrons are removed from this configuration, they are removed from the 4s² and 3d³ orbitals. As a result, the effective nuclear charge experienced by the remaining 3d electrons increases even more, and the electrons are pulled even closer to the nucleus, resulting in an even smaller ionic radius. Therefore, V³⁺ has an ionic radius of 73 pm.

The successive ionization energies (IE) provide information about the electronic configuration of an element. This configuration is less stable than the noble gas configuration, and the ion has a smaller ionic radius as a result.

The first two ionization energies (IE₁ and IE₂) correspond to the removal of one or two electrons from the outermost energy level (valence shell). The third ionization energy (IE₃) corresponds to the removal of an electron from the next energy level (the one below the valence shell).

Using the given ionization energies, we can determine the full electron configuration of the Period 2 element as follows:

IE₁: 801 kJ/mol (removal of one electron from valence shell)

1s² 2s² 2p⁶ → 1s² 2s² 2p⁵ + e⁻

IE₂: 2427 kJ/mol (removal of second electron from valence shell)

1s² 2s² 2p⁵ → 1s² 2s² 2p⁴ + e⁻

IE₃: 3659 kJ/mol (removal of electron from the next energy level)

1s² 2s² 2p⁴ → 1s² 2s² 2p³ + e⁻

IE₄: 25,022 kJ/mol (removal of electron from the next energy level)

1s² 2s² 2p³ → 1s² 2s² 2p² + e⁻

IES: 32,888 kJ/mol (removal of electron from the next energy level)

1s² 2s² 2p² → 1s² 2s² 2p¹ + e⁻

The full electron configuration of the Period 2 element is therefore: 1s² 2s² 2p¹.

The ionic radius of an ion depends on its electronic configuration and the number of electrons it has. In the case of V²⁺, the ion has lost two electrons, which means that its electronic configuration is now 1s² 2s² 2p⁶. This is a noble gas configuration, and the ion has a stable electronic structure, which causes the ionic radius to be relatively large.

In contrast, V³⁺ has lost three electrons, which means that its electronic configuration is now 1s² 2s² 2p⁵. This configuration is less stable than the noble gas configuration, and the ion has a smaller ionic radius as a result.

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To forecast using data that has seasonality, one commonly used method is seasonal decomposition of time series (STL). This method separates the time series data into three components: trend, seasonality, and residuals. By isolating the seasonal component, you can forecast future values by extrapolating the pattern observed in previous seasons.

Another approach is the use of seasonal autoregressive integrated moving average (SARIMA) models. SARIMA models are an extension of ARIMA models that incorporate seasonal patterns. These models capture both the trend and seasonality in the data and can be used to make forecasts.

To control volatility in various time series models, a common technique is to use a volatility model, such as the generalized autoregressive conditional heteroskedasticity (GARCH) model. This model estimates the volatility of the time series by incorporating past volatility and squared residuals. By modeling and forecasting the volatility, you can better understand and manage the potential fluctuations in the time series data.

A simple moving average method is a technique used to smooth out fluctuations and identify trends in time series data. It involves calculating the average of a fixed number of data points, often referred to as the window size or period. As new data becomes available, the oldest data point in the window is dropped, and the newest data point is included in the calculation. This process is repeated for each subsequent data point. The resulting moving average values can provide insights into the overall trend of the data, helping to identify patterns or changes over time.

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Answer:

Adriana is correct

Step-by-step explanation:

if you get rid of E, it is a 90 degree angle. so:

90-20=70

which is Adriana's answer

Answer:

I. The point (6, -2) is not a solution for the given equation

II. The slope of the line going through (-4, 1) and (-7, -5) is 2

III. The slope of the line x = -7 is ∞

IV The slope of the line y = -6 is 0

V. The coordinate of the x-intercept is (12.5, 0)

The coordinate of the y-intercept is (0, 25)

VI. The equation of the line is y = 17·x + 59

Step-by-step explanation:

I. The given equation is -4·x - 5·y = 32

The given point = (6, -2)

Therefore;

The x-coordinate value of the point = 6

The y-coordinate value of the point = -2

Plugging in the x and y-coordinate values into the given equation gives;

-4 × (6) - 5 × (-2) = -14 which does not correspond to the given equation, therefore, the point (6, -2) is not a solution for the given equation;

We can also show, by making y the subject of the formula of the given equation, weather the point is a solution of the given equation as follows;

-4·x - 5·y = 32

y = (-4/5)·x - 32/5

For x = -2, we have;

y = (-4/5) × (-2) - 32/5 = - 4.8

Therefore, the point (6, -2) where y = 6 when x = -2 is not a solution of -4·x - 5·y = 32

II. The slope of a straight line, given two points on the line is given as follows;

\(Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

Where the two points are (-4, 1), and (-7, -5), we have;

x₁ = -4, y₁ = 1, x₂ = -7, and y₂ = -5

\(Slope, \, m =\dfrac{-5-1}{-7-(-4)} =2\)

The slope, m, of the line going through (-4, 1) and (-7, -5) is m = 2

III. The slope of the line x = -7 = ∞ because, the difference in the x-value which is the denominator of the slope equation = 0 for all differences in the y-coordinate values

IV The slope of the line y = -6 is 0 because, the difference in the y-values which is the numerator of the slope equation = 0 for all differences in the x-coordinate values

V. The x and y-intercept of an equation is found by finding the values of the variable, x or y, in the equation, when the other variable, y or x is equal to zero respectively, which is given as follows;

The given equation is y = -2·x + 25

When y = 0, we have the x-intercept as 0 = -2·x + 25

∴ 2·x = 25

x = 25/2 = 12.5

Therefore, the coordinate of the x-intercept is (12.5, 0)

When x = 0, we have the x-intercept as y = -2·x + 25 = -2 × 0 + 25 = 25

The coordinate of the y-intercept is (0, 25)

VI. The general equation of a straight line is y = m·x + c

Where;

m = The slope of the line

c = The y-intercept

For the  line that goes through the points (-3, 8) and (-4, -9), we have;

\(The \ slope, \, m =\dfrac{-9-8}{-4- (-3)} = \dfrac{-9-8}{-4+3} = 17\)

The equation in point and slope form is y - 8 = 17 × (x - (-3))

∴ y  = 17·x + 51 + 8 = 17·x + 59

The equation of the line is y = 17·x + 59

The slope-intercept form of the equation of the line is y = x + 6.

A linear equation with a degree of one is referred to as an equation of the line. Two variables, x, and y, are present in the equation of the line. The third parameter is the line's slope, which indicates the line's elevation.

The equation of the line's general form is:

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

The formula for calculating the line's slope is

Slope = ( 6 - 4) / ( 2 - 0)

Slope = 1

The y-intercept will be calculated as:-

y = mx + c

y = x +c

6 = c

The equation of the line can be written as:-

y = x + 6

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Political instability refers to the vulnerability of a government to collapse either because of conflict or non-performance by government institutions.

The correct option is (d) ii, iii, iv.  

A measure of political instability would include all of the following except the number of political parties.The following can be used as a measure of political instability .

Frequency of unexpected government turnoversiii. Conflicts with neighbouring statesiv. Expected terrorism in the country Thus, options ii, iii, iv are correct. Hence, the correct option is (d).

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Answer:

i think that one of the answers is (3,2)

Step-by-step explanation:

Answer:

Step-by-step explanation:

4,6

After an hour, the percentage of alcohol in the vat is approximately 4.92%.

After an hour of pumping beer with 6% alcohol into the vat at a rate of 5 gallons per minute and simultaneously pumping the mixture out at the same rate, the percentage of alcohol in the vat can be calculated as follows:

Initially, the vat has 500 gallons of beer with 4% alcohol content. This means there are 20 gallons of alcohol in the vat (500 * 0.04).

Now, let's consider the beer being pumped in at a rate of 5 gallons per minute with a 6% alcohol content. Over the course of an hour (60 minutes), this amounts to 300 gallons of beer, containing 18 gallons of alcohol (300 * 0.06).

As the mixture is being pumped out at the same rate, only 500 gallons of beer remain in the vat after an hour. The total alcohol in the vat is the sum of the alcohol from the initial beer and the pumped-in beer, minus the amount of alcohol pumped out. The mixture pumped out contains the same proportion of alcohol as the mixture in the vat, so it amounts to (5 gallons/minute * 60 minutes) * X%, where X% is the percentage of alcohol in the mixture at the end of an hour.

To find X%, we can set up the following equation:

20 (initial alcohol) + 18 (alcohol pumped in) - 5 * 60 * X% = 500 * X%

Solving for X, we get:

38 - 300 * X% = 500 * X%

Rearranging and solving for X, we find that:

X% ≈ 4.92%

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Answer:

m ∠ E = 29°

Step-by-step explanation:

34 + 117 + m = 180

151 + m = 180

-151         -151

m ∠ E = 29°

I hope this helps!

Answer:

-1

-3

-5

Step-by-step explanation:

just substitue each value of x into the equation and u will get your answer

Answer:

-1, -3, -5

Step-by-step explanation:

To find why you simply plug in the value they give you for x in the formula.

The formula provided is y=-2x-2

The first x value is -1.

Plug it into the formula.

y=-2(-1)-3

Solve.

y=2-3

y=-1

The first y value is -1.

The second x value is 0.

Plug it into the formula.

y=-2(0) -3

Solve.

y=-3

The second y value is -3

The third x value is 1.

Plug it into the formula,

y=-2(1)-3

Solve.

y=-2-3

y=-5

The third y value is -3.

Answer:

15 cans

Step-by-step explanation:

There are two shapes that make up the dog house, they are the triangular and rectangular prism, with the combination of a semi-circle and rectangle as the door opening.

The area of a rectangle for the top ( T ) and bottom ( B ) side view:

top height = 3ft, and width= 8ft

bottom height = 4.5ft, width= 8 ft

Area ( T ) = 3 X 8 = 24 ft^2

Area ( B ) = 4.5 X 8 = 36ft^2

The front and back view is a triangle and rectangle:

area of triangle = 1/2 x base x height

with the base = 4ft,   and  sides= 3 ft

height = sqrt( side^2 - (1/2 height)^2 )^0.5

          = sqrt( 9 - 4 )  = 2.235

area of triangle( front and back )  = 1/2( 4 x 2.235 ) = 4.47 ft^2

area of rectangle ( back ) = 4 x 4.5 = 18ft

The entrance is a rectangle with area = 2.5 x 2 = 5ft^2

and semi-circle with area = (πr^2)/2 = (3.14 x 1^2)/2 = 1.57ft^2

area of entrance = 5 + 1.57 = 6.57ft^2

area of front view = 18 - 6.57 = 11.43ft^2

the total area of the doghouse is = 11.43 + 18 + 72 + 48 + 8.94  = 158.37ft^2

this is for just the outside. to get the total for inside and outside:

      158.37 x 2 = 316.74ft^2

total area per paint can = 20ft^2

total number of cans needed = 316.74 / 20  = 15 paint cans

Answer:

6 cans are needed to paint the dog house.

Step-by-step explanation:

Answer:

hope this helps you look it once.

The complate table is,

Statement                                                 Reasons

1) K is the midpoint of segments                      Given

  RM and JL.

2) RJ ≅ ML                                                  SSS Congruence Postulate

3) RK ≅ MK ,  JK ≅ LK                                 Definition of Midpoint

4) RK = MK , JK = KL                                    Definition of Congruence

                                                                   Segments

5) Δ EGF ≅ Δ EGH                                      CPCTC

A line segment is a part of line having two endpoints and it is bounded by two distinct end points and contain every point on the line that is between its endpoint.

Given that;

K is the midpoint of segments RM and JL.

Now,

Since, K is the midpoint of segments RM and JL.

Hence, We get;

   Statement                                                 Reasons

1) K is the midpoint of segments                      Given

  RM and JL.

2) RJ ≅ ML                                                  SSS Congruence Postulate

3) RK ≅ MK ,  JK ≅ LK                                 Definition of Midpoint

4) RK = MK , JK = KL                                    Definition of Congruence

                                                                   Segments

5) Δ EGF ≅ Δ EGH                                       CPCTC

Thus, The complete table is shown above.

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Using a system of equations, it is found that:

a) Suzette ran for 2 hours.

b) Suzette biked for 2 hours.

--------------------------

Velocity is distance divided by time, thus:

\(v = \frac{d}{t}\)

\(6 = \frac{d}{t}\)

\(d = 6t\)

\(v = \frac{d}{t}\)

\(12 = \frac{36 - d}{4 - t}\)

The substitution is:

\(d = 6t\)

Then, on the second equation:

\(12 = \frac{36 - 6t}{4 - t}\)

\(36 - 6t = 48 - 12t\)

\(6t = 12\)

\(t = \frac{12}{6}\)

\(t = 2\)

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The additional piece of information would allow you to prove that the triangles are congruent by the HL theorem is AB ≅ DE

The HL Postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

Given that two triangles Δ ABC and Δ DEF,

To prove them congruent by HL Postulate, we need one more side to be congruent, as the hypotenuse of both are already congruent.

Therefore, the sides should be either BC ≅ FE or AB ≅ DE

In options, AB ≅ DE is given.

Hence, The additional piece of information would allow you to prove that the triangles are congruent by the HL theorem is AB ≅ DE

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6√3

Step-by-step explanation:

6 is x. side across from right angle (12) is 2x. so 6x2 to get 12. missing side is x√3. so 6√3

Answer:

6√3

Step-by-step explanation:

using the pythagorean theorem you can plug in the numbers to get √(12^2 - 6^2) = √(144-36) = √108 = 6√3.

On solving the provided question, we can say that 1 degree = 3600 arc seconds and 1 degree = 60 arc minutes.

A 160 degree angle is measured in arc minutes, often known as arcmin, arcmin, arcmin, or arc minutes (represented by the sign '). One minute is equal to 121600 revolutions, or one degree, hence one degree equals 1360 revolutions (or one complete revolution). A degree, also known as a complete angle of arc, angle of arc, or angle of arc, is a unit of measurement for plane angles in which a full rotation equals 360 degrees. A degree is sometimes referred to as an arc degree if it has an arc of 60 minutes. Since there are 360 degrees in a circle, an arc's angles make up 1/360 of its circumference.

1 degree = 3600 arc seconds

1 degree = 60 arc minutes

A. 2 degree 18'36 = 2 + 18/60 + 36 / 2600 = 231 / 100 degree

B. 36 ′ 18 ′′ = 36/60 + 18/2600 = 121 / 200 degree

C. 7 degrees 59′ 59′′ = 7 + 59 / 60 + 59 / 3600 = 28799 / 3600 degree

D. 1' = 1/60 degree

F. 1" = 1/3600 degree

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