Write inequalities to describe the region between the yz-plane and the vertical plane x = 9.

Hicksian demand functions are:x1** = 2P₁x₂ ; x₂** = P₂²

Utility function: u(x1+x2) = .5ln(x1) + .25ln(x₂) .The Marshallian demand functions are: x1* = - and x₂* = P₂.

The indirect utility function is found by substituting Marshallian demand functions into the utility function and solving for v(P₁, P₂, Y).u(x1*,x2*) = v(P₁,P₂,Y) ⇒ u(-, P₂) = v(P₁,P₂,Y) ⇒ .5ln(-) + .25ln(P₂) = v(P₁,P₂,Y) ⇒ v(P₁,P₂,Y) = - ∞ (as ln(-) is not defined)

Thus the indirect utility function is undefined.

Minimum expenditure function can be derived from the Marshallian demand function and prices of goods:

Exp = P₁x1* + P₂x2* = P₁(-) + P₂P₂ = -P₁ + P₂²

Minimum expenditure function is thus:

Exp = P₁(-) + P₂²

Hicksian demand functions can be derived from the utility function and prices of goods:

H1(x1, P1, P2, U) = x1*H2(x2, P1, P2, U) = x2*

Hicksian demand functions are:

x1** = 2P₁x₂

x₂** = P₂²

If there are no restrictions on the amount of money the consumer can spend, the Hicksian demand functions for x1 and x2 coincide with Marshallian demand functions.

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Answer: A its B

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

if y = 0

0 = -2x + 4 _ eq 1

0 - 4 = -2x

-4 = -2x

divide through by 2

x = -4 ÷ -2

x = 2

if x = 0

y = -2(0) + 4_ eq 2

y = 0 + 4

y = 4

:.(x,y) = (2,4)

a random variable can have any value that is possible within the range of -infinity and infinity.So a. can have any value between -infinity and infinity.

A random variable from an experiment with outcomes that are normally distributed can take on any value between -infinity and infinity. This means that it can take on any real number, including fractions and decimals. It is not limited to only a few discrete values, nor does it have to be positive.

A random variable from an experiment with outcomes that are normally distributed can take on any real value between -infinity and infinity. This means that the variable is not limited to a few discrete values, nor does it have to be positive. Instead, it can have any value, no matter how small or large, and including fractions and decimals. Such a random variable can have any value that is possible within the range of -infinity and infinity.

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Answer:

Step-by-step explanation:

-10.9p + 3.9

-10.9p turns positive.

The (p) is isolated.

10.9 - 3.9= 9.18 = -9.18

Answer

-9.18

Using the concepts of domain and range of functions, we have that:

10. The range is y ≥ 2.

11. The domain is all real numbers, the range is y ≤ 3, and it is a function.

12. The domain is (-4,3], and the range is (-5,5).

Hence, for these problems:

10. The range is y ≥ 2.

11. The domain is all real numbers, the range is y ≤ 3, and it is a function.

12. The domain is (-4,3], and the range is (-5,5).

In item 11, we have that it is a function because it has no vertically aligned points, that is, each value of x is associated with only one value of y.

In item 12, the open intervals are due to the open circles at the extremes of the domain and the range on the graph.

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Answer:

\(\frac{5}{36}\)

Step-by-step explanation:

Answer:

-1/9 * (-5/4) = 5/36

Step-by-step explanation:

Answer: x=12

Step-by-step explanation: 10(x−3)=90

(10)(x)+(10)(−3)=90 (Distribute)

10x+−30=90

10x−30=90

Step 2: Add 30 to both sides.

10x−30+30=90+30

10x=120

Step 3: Divide both sides by 10.

x=12

The resultant value of x for the given quadratic equation 9x² − 16 = 0 is x = ±4/3.

Any equation in algebra that can be written in standard form where x stands for an unknown value, where a, b, and c stand for known values, and where a 0 is true is known as a quadratic equation.  

An algebraic equation of the second degree in x is a quadratic equation.

The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

So, we have the quadratic equation:

9x² − 16 = 0

Now, solve as follows:

a = 9

b = 0

c = -16

Now,

c = -0 ± √0² - 4-9(-16)/2*9

x = ±4/3

Therefore, the resultant value of x for the given quadratic equation 9x² − 16 = 0 is x = ±4/3.

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9514 1404 393

Answer:

  J Compound interest; $298.65

Step-by-step explanation:

Interest compounding pays interest on the interest. For the same annual rate, any amount of compounding will earn more interest.

For short time periods, the effect of compounding is not great. In general, it will be a fraction of the equivalent simple interest rate. Here, the effective multiplier for annual compounding is ...

  1.051^4 = 1.22024337

and the effective multiplier for simple interest is ...

  1 +0.051·4 = 1.204

Then the difference in interest rate multiplier for the 4-year period is ...

  1.22024337 -1.204 = 0.01614337

That fraction of the $18500 principal is $298.65.

Compound interest earns $298.65 more than simple interest in this scenario.

Answer:see the photo I send to you

Step-by-step explanation:

Ok

Answer:

heres a sentence using it

Eating five chocolate bars is not congruent with your plan for losing weight.

Triangles are considered congruent when they have the same angles.

it means

having the same size and shape

Answer:

Congruent

Step-by-step explanation:

Multiple objects the work well together.

Hope this helps (:

The area between z=1.1 and z=2.1 is approximately 0.982 - 0.864 = 0.118, rounded to three decimal places.

To find the area below z=1.04 for an Upper N(0,1) density, you will need to use the standard normal distribution table or a calculator with a z-table function. Here are the steps:

1. Locate the value of z=1.04 in the table or use the calculator's function.
2. Find the corresponding area value (which represents the probability or percentage of values below z=1.04).

The area below z=1.04 is approximately 0.851, rounded to three decimal places.

(b) To find the area above z=-1.4 for an Upper N(0,1) density, follow these steps:

1. Locate the value of z=-1.4 in the table or use the calculator's function.
2. Find the corresponding area value.
3. Since we need the area above z=-1.4, subtract the area value found in step 2 from 1.

The area above z=-1.4 is approximately 1 - 0.0808 = 0.919, rounded to three decimal places.

(c) To find the area between z=1.1 and z=2.1 for an Upper N(0,1) density, follow these steps:

1. Locate the values of z=1.1 and z=2.1 in the table or use the calculator's function.
2. Find the corresponding area values for both z=1.1 and z=2.1.
3. Subtract the area value of z=1.1 from the area value of z=2.1 to find the area between them.

The area between z=1.1 and z=2.1 is approximately 0.982 - 0.864 = 0.118, rounded to three decimal places.

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The probability of first day and black shirt is 0.25.

Probability is calculated by the formula -

Probability = outcome of specific result ÷ maximum possible outcomes

The specific result here is black shirt, which is 1. Maximum possible outcomes in this case is 4. The question mentions the first day. Since no tshirt has been worn yet, Molly gets the chance to select among yellow, black, blue and green t shirt.

Keep the values in formula to find probability -

Probability = 1/4

Performing division on Right Hand Side of the equation

Probability = 0.25

Therefore, the resultant probability is 0.25.

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Refer to the image for the graph of the lines.

The common form of the equation of a line is y = mx + c, where m is the slope of the line and c is a constant.

We need to draw any line with a slope m = 2, and

another line with a slope m = -2.

Disclaimer: Let us assume that the constant c = 0.

Then the equation to the line with a slope of "positive" 2 is given by

y = 2x

Then the equation to the line with a slope of "negative" 2 is given by

y = -2x

Refer to the attached image for the graph of the lines with the slope of "positive" 2 and "negative" 2.

f: green line indicates a line with a slope of "positive" 2.

g: blue line indicates a line with a slope of "negative" 2.

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The distance from -4 to 1 is 5 units.

The correct number line and expression to find the distance from -4 to 1 are:

Number line: -4 -3 -2 -1 0 1

Expression: |-4 - 1|

To find the distance, we subtract the smaller number (-4) from the larger number (1) and take the absolute value:

|-4 - 1| = |-5| = 5

Therefore, the distance from -4 to 1 is 5 units.

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Answer:

Approximately 5 boxes

Step-by-step explanation:

6x4=24 ft

24x2=48 ft

48x12=576 in

576/6=96

96/20=4.8 boxes

If I'm wrong I'm sorry

Answer:

ur answer is 1.42

Step-by-step explanation:

Answer:

3.14

Step-by-step explanation:

This is the equation of the line tangent to the curve x⁶ + 2xy + y³ = 4 at the point (1, 1).

To find the equation of the tangent line to the curve defined by x⁶ + 2xy + y³ = 4 at the point (1, 1), we first need to find the derivative dy/dx using implicit differentiation.

Differentiate both sides of the equation with respect to x:
6x⁵ + 2y(dx/dy) + 2x(dy/dx) + 3y²(dy/dx) = 0

Now, solve for dy/dx:
dy/dx × (2x + 3y²) = -6x⁵ - 2y(dx/dy)
dy/dx = (-6x⁵ - 2y(dx/dy)) / (2x + 3y²)

Since we want to find the tangent line at the point (1, 1), plug in x = 1 and y = 1:
dy/dx = (-6(1)⁵ - 2(1)(dx/dy)) / (2(1) + 3(1)²)
dy/dx = (-6 - 2(dx/dy)) / 5

Now, we can solve for dx/dy and find the slope of the tangent line:
dy/dx = (-6 - 2(dx/dy)) / 5
5(dy/dx) = -6 - 2(dx/dy)
(dy/dx) - 2/5(dx/dy) = -6/5

At the point (1, 1), the tangent line has a slope of dy/dx. Therefore, using the point-slope form of a linear equation, the equation of the tangent line is:
y - 1 = (dy/dx)(x - 1)

Substitute dy/dx with the expression we found earlier:
y - 1 = (-6/5 - 2/5(dx/dy))(x - 1)

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Scenario: A small business owner needs to analyze their sales data to make informed decisions about pricing and profitability.

Supporting Detail 1: The concept of linear equations can be applied to determine the break-even point and set optimal pricing strategies for the business.

Worked Example 1: Let's say the small business sells a product for $10 each, and the fixed costs (expenses that don't vary with the number of units sold) amount to $500. The variable costs (expenses that depend on the number of units sold) are $2 per unit. We can use the formula for a linear cost equation (C = mx + b) to find the break-even point where revenue equals total costs:

10x = 2x + 500

Simplifying the equation, we get:

8x = 500

x = 500/8

x = 62.5

The break-even point is 62.5 units. Knowing this information, the business owner can make decisions about pricing, cost control, and production targets.

Supporting Detail 2: The concept of systems of equations can be applied to optimize the allocation of resources in the business.

Worked Example 2: Let's consider a scenario where the business owner sells two different products. Product A generates a profit of $5 per unit, while Product B generates a profit of $8 per unit. The business owner has a limited budget of $500 and wants to determine the optimal allocation of resources between the two products. We can set up a system of equations to represent the profit constraints:

x + y = 500 (total budget)

5x + 8y = P (total profit, represented as P)

By solving this system of equations, the business owner can find the optimal values of x and y that maximize the total profit while staying within the budget constraints.

Conclusion: Applying concepts from this algebra course to real-life scenarios, such as analyzing sales data for a small business, helps in understanding the material by providing practical applications. It demonstrates the relevance of algebra in making informed decisions, optimizing resources, and maximizing profitability.

These examples highlight how algebraic concepts enable problem-solving and provide valuable tools for individuals in various fields, including business and entrepreneurship.

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Answer:

30 minutes

Step-by-step explanation:

It took 20 minutes to progress from 5 to 9 feet meaning it goes 1 foot every 5 minutes. 15 - 9 is 6 and 6 * 5 = 30 meaning in 30 minutes it will reach 15 feet.

Answer:LN

Step-by-step explanation:

Answer:

Angle PTR and angle PTS are supplementary angles. Lines PQ and RS intersect at an angle less than a right angle. Angle PTR and angle PTS are complementary angles.

Step-by-step explanation:

Answer:

¿Qué quieres comer?

Step-by-step explanation:

The Laplace Transform of f(t) isL{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...

                            = (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...= (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]

Given function is,f(t) ={ t, 0 < t < π π < t < 2π}

where f(t + 2 π) = f(t)

Let's take Laplace Transform of f(t)

                     L{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...f(t + 2π) = f(t)

∴ L{f(t + 2 π)} = L{f(t)}⇒ e^{2πs}L{f(t)} = L{f(t)}

     ⇒ [e^{2πs} − 1]L{f(t)} = 0L{f(t)} = 0

when e^{2πs} ≠ 1 ⇒ s ≠ 0

∴ The Laplace Transform of f(t) is

                       L{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...

                               = (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...

                              = (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]

The Laplace Transform of f(t) isL{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...

                            = (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...= (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]

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Answer:

They frosted the same amount

Step-by-step explanation:

did it on IXL and got it right ("Wonderful!")

Mean amount in Sydney = $205.7 Mean amount in Darwin = $95.29

To calculate the mean amount in Sydney:240 + 145 + 410 + 120 + 170 + 103 + 137 + 75 + 307 + 350 = 2057Total amount spent in Sydney = $2057The number of entries = 10Mean amount = total amount / number of entriesMean amount in Sydney = $2057 / 10Mean amount in Sydney = $205.7To calculate the mean amount in Darwin:140 + 25 + 210 + 25 + 70 + 111 + 86 = 667Total amount spent in Darwin = $667The number of entries = 7Mean amount = total amount / number of entriesMean amount in Darwin = $667 / 7 Mean amount in Darwin = $95.29

To calculate the answer, the first step is to find out the mean amount spent on weekends in Sydney and Darwin respectively.The mean amount in Sydney is calculated by adding the amount spent by people in Sydney and dividing it by the number of entries. To find the mean amount in Darwin, the same method is used.The mean amount spent on weekends in Sydney is $205.7, while the mean amount spent in Darwin is $95.29.The conclusion drawn from these calculations is that people in Sydney tend to spend more money on weekends as compared to those in Darwin. The mean amount in Sydney is more than double the mean amount in Darwin. This data can be useful for businesses looking to expand into either of these cities. If a business is looking to expand into a city where people spend more on weekends, Sydney could be a better choice. On the other hand, if the business is looking to expand into a city where people spend less on weekends, Darwin could be a better choice.

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The area  of Vivian’s garage door is 62.5 square feet

The Vivian garage is made up of a trapezoid and a rectangle. The area of the door is expressed as;

Area = Area of rectangle + area of trapezoid

Area = (5 * 8) + 0.5(7 + 8)*3
Area= 40 +22.5
Area = 62.5 square feet

Hence the area  of Vivian’s garage door is 62.5 square feet

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The total value of Mr. Liling's shares at the end of 2016 was $1388.50.

The value of a share, also known as the stock price, represents the price per unit of ownership in a company. It is determined by supply and demand for the stock in the stock market and can fluctuate based on a variety of factors such as the company's financial performance, industry trends, and overall market conditions.

At the beginning of 2016, Mr. Liling bought 10 shares of stock in QIZ Software for $198.58 per share, so the total cost was 10 * $198.58 = $1985.80.

In 2016, the stock price of QIZ Software changed by -$59.73, so the value of Mr. Liling's shares at the end of 2016 was $1985.80 - 10 * $59.73 = $1985.80 - $597.30 = $1388.50.

So, the total value of Mr. Liling's shares at the end of 2016 was $1388.50.

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Supply and demand problems are typically solved by finding the intersection point of the supply and demand curves to determine the equilibrium price and quantity.

To solve supply and demand problems, we typically use the intersection point of the supply and demand curves to determine the equilibrium price and quantity.

Once the equilibrium price and quantity are determined, we can use them to make predictions about the behavior of the market and the effects of changes in supply and demand. We can also calculate consumer surplus, producer surplus, and total surplus.

Various mathematical and graphical methods can be used to analyze supply and demand, including linear equations, graphs, and calculus techniques.

To solve supply and demand problems, we typically start by identifying the supply and demand curves for the market in question.

Then, we can find the intersection point of these curves, which represents the equilibrium price and quantity. If the market price is above the equilibrium price, there will be a surplus of supply and prices will tend to fall. If the market price is below the equilibrium price, there will be a shortage of supply and prices will tend to rise.

We can also analyze the effects of shifts in the supply and demand curves due to changes in various factors such as taxes, subsidies, technology, or consumer preferences. This can help us understand the market dynamics and make predictions about the future behavior of the market.

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The given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.

In the question, we are asked to show that x.cosec²x = cot x - d/dx x.cot x.

To prove, we go by the right-hand side of the equation:

cot x - d/dx x.cot x.

We solve the differential d/dx using the product rule, according to which, d/dx uv = u. d/dx(v) + v. d/dx(u), where u and v are functions of x.

cot x - {x. d/dx(cot x) + cot x. d/dx(x)}

= cot x - {x. (-cosec²x) + cot x} {Since, d/dx(cot x) = -cosec²x, and d/dx(x) = 1}

= cot x + x. cosec²x - cot x

= x. cosec²x

= The left-hand side of the equation.

Thus, the given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.

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