Write empirical formula

Answer:

Chromosphere

Explanation:

You see the middle layer of the sun’s atmosphere, the Chromosphere, at the start and end of a total eclipse.

Answer:

Explanation:

% yield = (actual yield / theoretical yield) X 100

For this question,

% yield = (150g/ 162 g) X 100 = 92.6%

Answer:

92.6%

Explanation:

This archipelago and its enormous marine reserve are referred to be a "living museum and showcase of evolution" for their singularity.

Thus, The 127 islands, islets, and rocks that make up the Galapagos archipelago, 19 of which are major and 4 of which are inhabited, are located roughly 1,000 kilometres from the Ecuadorian mainland. In 1959, national parks were established on 7,665,100 ha, or 97% of the entire emergent surface.

On the remaining three percent of the islands, only human habitation is permitted in designated rural and urban zones (the fifth island only includes an airport, a tourist dock, a fuel containment system, and military installations).

The Galapagos Marine Reserve, one of the largest marine reserves in the world, was established in 1986 and expanded to its current area in 1998. It surrounds the islands. Inland waters of the archipelago are also a part of the marine reserve.

Thus, This archipelago and its enormous marine reserve are referred to be a "living museum and showcase of evolution" for their singularity.

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Answer:

A

Explanation:

Atomics number = number of protons

F=ma

(a) when the mass of an object is fixed , measure the relationship between external force F and acceleration a.

(b) when the external force F. fixed , measure the relationship between mass of the moving object m and it's acceleration a .

Thank you.......Hope it will helps you

Can I get brainlist..........

Answer: 0.04M.

Explanation: Using M1V1=M2V2, we can find the new molarity (M2).

We are given M1 and V1 with 0.119M and 25mL, we are also given V2 since it says we added 55mL to the original 25mL.

25mL+55mL = 80mL.

Let's convert mL to L by dividing by 1000.

V1 = 25ml/1000 = 0.025L

V2 = 80mL/1000 = 0.08L.

Now plug in and solve algebraically.

0.119 * 0.025 = M2 * 0.08.       Divide both sides by 0.08.

\(\frac{0.119*0.025}{0.08}\) = 0.037.

M2 = 0.037M

However, since we are given 25mL which only has 2 sig figs, the new molarity os 0.04M.

By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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The volume of carbon dioxide produced is approximately (d) 11.9 liters.

To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:

C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)

First, we calculate the number of moles of C\(S_2\) using its molar mass:

Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol

Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol

From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.

Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Converting the temperature from Celsius to Kelvin:

T(K) = 28.85°C + 273.15 = 302 K

Using the ideal gas law:

V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L

The correct answer is 11.9 liters.

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First, we need to write the balanced chemical equation for the reaction:

2 NO2(g) + H2O(l) → HNO3(aq) + NO(g)

From the equation, we can see that 2 moles of NO2 react with 1 mole of H2O to produce 1 mole of HNO3 and 1 mole of NO. Therefore, we need to determine which reactant is limiting and calculate the amount of HNO3 that can be produced based on that.

To do this, we can use the mole ratio of NO2 to H2O:

5.0 mol NO2 × (1 mol H2O / 2 mol NO2) = 2.5 mol H2O

Since we have 11.0 mol of H2O, it is not limiting and we will use up all of the NO2.

Therefore, we can calculate the amount of HNO3 that can be produced from 5.0 mol of NO2:

5.0 mol NO2 × (1 mol HNO3 / 2 mol NO2) = 2.5 mol HNO3

Therefore, the largest amount of HNO3 that could be produced is 2.5 mol, rounded to the nearest 0.1 mol.

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Answer:

lungs

Explanation:

Answer:

C

Explanation:

I believe it would be weather because climate is the average temperature of a area. This leads me to believe it is c.

I am sorry if this is incorrect, but that is what I would've went with if I was taking the test. :)

a) The total pressure of the system is  1.79 atm

b) The mole fraction and partial pressure of hydrogen is  0.89 and 1.59 atm respectively

c) The mole fraction and the partial pressure  of argon is 0.11 and 0.19 atm.

We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;

PV = nRT

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

Number of moles of hydrogen = 14.2 g/2g = 7.1 moles

Number of moles of Argon = 36.7 g/40 g/mol

= 0.92 moles

Total number of moles =  7.1 moles + 0.92 moles = 8.02 moles

Then;

P = nRT/V

P = 8.02 * 0.082 * 273/100

P = 1.79 atm

Mole fraction of hydrogen = 7.1/8.02 = 0.89

Partial pressure of hydrogen =  0.89 * 1.79 atm

= 1.59 atm

Mole fraction of argon = 0.92 / 8.02

= 0.11

Partial pressure of argon = 0.11  *  1.79 atm

= 0.19 atm

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Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

Empirical evidence for a proposition is evidence, i.e. what supports or counters this proposition, that is constituted by or accessible to sense experience or experimental procedure. Empirical evidence is of central importance to the sciences and plays a role in various other fields, like epistemology and law.

Explanation:

thanks me later

The one which is the heterogeneous mixture is the correct option is oil and water.

The heterogeneous mixture are the mixture that can be  defined as the combination of the two more substance  that  are not completely soluble and are easily  be separated from each other by the physical means. The homogeneous mixture are the type of the mixture in which the two more substance combine and are completely soluble.

The mixture of oil and water are the  heterogeneous mixture, because these two liquids  are immiscible  as they can be separated  on the basis of the density. Therefore , oil and water are heterogenous mixture.

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:

one to two inches (three to five centimeters) per year.

Explanation:

Answer:

1 to 2 inches (3 to 5 centimeters) per year

Explanation:

It depends on what plates your talking about, but in general, they move apart anywhere from 1 to 2 inches (3 to 5 centimeters) per year.

Specifically, though, The Arctic Ridge has the slowest rate (less than 2.5 cm/yr), and the East Pacific Rise near Easter Island, in the South Pacific about 3,400 km west of Chile, has the fastest rate (more than 15 cm/yr).

Answer:

Q5. 16.3g

Q6. 18.9g

Q7. 43.3g

Explanation:

Knowledge required to answer the questions:

1. The mass in 1 mole of a chemical substance in grams is equal to the formula mass of the substance

2. The equation: m = n × Mr, where m = mass (in g), n = number of moles (in mol) and Mr = formula mass (i.e. the sum of the atomic mass of all the atoms in the chemical substance)

3. The ratio of moles of each chemical substance in a reaction is according to the balanced equation

Question 5:

HBr + KHCO₃ → H₂O + KBr + CO₂

According to principle 2, find the number of moles of HBr using the given mass and the calculable Mr;

The Mr will be the sum of the atomic mass of each atom in the chemical compound, these atomic masses can be found on the periodic table:

HBr Mr = 1 + 79.9

HBr Mr = 80.9

If m = n × Mr, then n = m/Mr;

n = 30/(80.9)

n = 0.370828183

According to principle 3, and the balanced reaction equation, we can see the ratio of HBr to the CO₂ is 1:1;

In other words, 1 mol of HBr will react with 1 mol of KHCO₃ to produce 1 mol of H₂O, 1 mol of KBr and 1 mol of CO₂;

So, if you start with 30g or 0.37... moles of HBr, this will react with 0.37... moles of KHCO₃ to produce 0.37... moles of H₂O, 0.37... moles of KBr and 0.37... moles of CO₂;

Now, we simply have to use the equation from principle 2 to get the mass;

CO₂ Mr = 12 + 2(16)

Notice how you need to add (2 × 16) since CO₂ has two oxygen atoms

CO₂ Mr = 44

m = 0.37... × 44+

m = 16.3164401 ⇒ 16.3g

If the number of moles of reagents does not match up with the ratio illustrated in the balanced equation, then one will be the limiting reagent and the other or others would be in excess;

Using this principle and the method used previously, you could solve the questions 6 and 7;

I won't explain in full these questions, but will give the answers:

Question 6:

2 NaOH + H₂SO₄ → 2 H₂O + Na₂SO₄

NaOH m = 150

NaOH Mr = 23 + 16 + 1 = 40

m = n * Mr

n = 40/150 = 0.2666..

NaOH : Na₂SO₄

2 : 1

Na₂SO₄ n  = 0.26.../2 = 0.1333...

Na₂SO₄ Mr = 2(23) + 32.1 + 4(16) = 142.1

m = 0.1333... * 142.1 = 18.946... ⇒ 18.9g

Question 7:
Pb(SO₄)₂ + 4 LiNO₃ → Pb(NO₃)₄ + 2 Li₂SO₄

Li₂SO₄ m = 350

Li₂SO₄ Mr = 2(6.9) + 32.1 + 4(16) = 109.9

Li₂SO₄ n = 109.9/350 = 0.314

Li₂SO₄ : LiNO₃

2 : 4 simplifies to:

1 : 2

LiNO₃ n = 0.314 × 2 = 0.628

LiNO₃ Mr = 6.9 + 14 + 3(16) = 68.9

LiNO₃ m = 0.628 × 68.9 = 43.2692 ⇒ 43.3g

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:

я не знаю ответа :(

Explanation:

Answer:

Noble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

Explanation:

I pretty much covered it in my answer!

Pls Brainliest! It would mean a lot! ;)

Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

PLS GIVE BRAINLIEST

Answer:

Isotopes are one of two or more forms of the same chemical element.

Explanation:

Different isotopes of an element have the same number of protons in the nucleus, giving them the same atomic number,but a different number of neutrons giving each element isotope of a different atomic weight.

Answer:

284.48 g/mol

Explanation:

You can find the molar mass of any molecule by looking at a periodic table and adding up all of the masses of each element. When you do this with stearic acid, you get somewhere around 284.5 g/mol. Hope this helped!

Answer:

(R)-but-3-en-2-ylbenzene

Explanation:

In this reaction, we have a very strong base (sodium ethoxide). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an E2 mechanism, therefore, the hydrogen that is removed must have an angle of 180º with respect to the leaving group (the "OH"). This is known as the anti-periplanar configuration.

The hydrogen that has this configuration is the one that placed with the dashed bond (red hydrogen). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.

See figure 1

I hope it helps!

Answer:

(a) Cr3+ and Br- will form CrBr3 (chromium(III) bromide)

(b) Fe3+ and O2- will form Fe2O3 (iron(III) oxide)

(c) Hg22+ and CO32- will form Hg2CO3 (mercury(I) carbonate)

(d) Ca2+ and ClO3- will form Ca(ClO3)2 (calcium chlorate)

(e) NH4+ and PO43- will form (NH4)3PO4 (ammonium phosphate)

Explanation:

chatGPT

The chemical formulas for the compounds formed by the given pairs of ions are: (a) CrBr3, (b) Fe2O3, (c) Hg2(CO3)2, (d) Ca(ClO3)2, and (e) (NH4)3PO4.

(a) Cr3+ and Br- : In order to form a neutral compound, the charges of the ions must balance. The charge of Cr3+ is 3+ and the charge of Br- is 1-. To balance the charges, we need three Br- ions for every Cr3+ ion. Therefore, the chemical formula is CrBr3.

(b) Fe3+ and O2- : The charge of Fe3+ is 3+ and the charge of O2- is 2-. To balance the charges, we need two O2- ions for every Fe3+ ion. Therefore, the chemical formula is Fe2O3.

(c) Hg22+ and CO2- : The charge of Hg22+ is 2+ and the charge of CO2- is 2-. The charges are already balanced, so no extra ions are needed. Therefore, the chemical formula is Hg2(CO3)2.

(d) Ca2+ and ClO3- : The charge of Ca2+ is 2+ and the charge of ClO3- is 1-. To balance the charges, we need two ClO3- ions for every Ca2+ ion. Therefore, the chemical formula is Ca(ClO3)2.

(e) NH4+ and PO3- : The charge of NH4+ is 1+ and the charge of PO3- is 3-. To balance the charges, we need three NH4+ ions for every PO3- ion. Therefore, the chemical formula is (NH4)3PO4.

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The expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P\(r^4\))/(8ηl) ∆t.

To derive an expression for the volume of liquid flowing per unit time through a cylindrical tube, we can apply the principles of fluid mechanics, considering the pressure gradient, viscosity coefficient, and tube radius.

The volume flow rate (Q) is defined as the volume of fluid passing through a cross-sectional area per unit time. In this case, we will consider the flow through a cylindrical tube of radius r and length l.

The Hagen-Poiseuille equation describes the flow rate in terms of the pressure gradient (∆P), viscosity coefficient (η), and tube dimensions:

Q = (π∆P \(r^4\))/(8ηl)

where k = π/8 is a constant.

To derive the expression for the volume of liquid flowing per unit time (∆V/∆t), we need to multiply the flow rate (Q) by the time interval (∆t):

∆V/∆t = Q ∆t

= (π∆P \(r^4\))/(8ηl) ∆t

Now, if we assume a constant pressure difference (∆P) and substitute k = π/8, the expression becomes:

∆V/∆t = (k∆P \(r^4\))/(ηl) ∆t

Simplifying further:

∆V/∆t = (π∆P\(r^4\))/(8ηl) ∆t

So, the expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P \(r^4\))/(8ηl) ∆t.

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Rough ER is connected to the nuclear membrane and is responsible for the synthesis and processing of proteins.

The rough endoplasmic reticulum (ER) is a network of membrane-bound sacs and tubules that is studded with ribosomes on its surface. These ribosomes are responsible for protein synthesis. The rough ER is connected to the nuclear membrane because it receives instructions for protein synthesis from the DNA in the nucleus. This connection allows for the efficient transfer of genetic information from the nucleus to the rough ER.

Once the ribosomes on the rough ER synthesize proteins, the rough ER is also involved in the processing and modification of these proteins. It helps in folding the newly synthesized proteins into their functional three-dimensional shapes and also adds various modifications such as glycosylation (the addition of sugar molecules) or signal sequences that target the proteins to specific locations within or outside the cell.

After processing, the proteins may be transported to other parts of the cell or exported to the cell membrane or extracellular space. The connection between the rough ER and the nuclear membrane ensures a coordinated flow of genetic information and protein synthesis, allowing the cell to efficiently carry out its functions.

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Explanation:

The balanced equation is

2  H2        +    02 ======> 2 H2 O

so it takes twice as many H2 moles as O2 to complete the reaction

  the chemist does not have enough  H2 (needs 8 moles)   , so H2 is the limiting reactant .