Write an Inequality statement that is represented by the following graph
I need it quick, please!!!!!!!!!!!!!

6.25 weeks will Héctor and Keith have downloaded the same number of songs.

From the data provided, we can determine the average weekly download rate for Keith by calculating the change in the number of songs downloaded over a specific period.

Between weeks 2 and 5, the number of songs downloaded increased by 45 - 30 = 15 songs.

Similarly, between weeks 5 and 10, the number of songs downloaded increased by 70 - 45 = 25 songs.

To find the average weekly download rate, we divide the change in the number of songs by the corresponding number of weeks.

Average weekly download rate = (15 songs / 3 weeks) + (25 songs / 5 weeks)

= 5 songs/week + 5 songs/week

= 10 songs/week

Therefore, the missing information is that Keith downloads 10 songs per week consistently.

Now, we can determine the number of weeks it will take for Héctor and Keith to have downloaded the same number of songs.

Let w represent the number of weeks:

50 + 2w = 10w

Simplifying the equation, we find:

50 = 8w

Dividing both sides by 8, we get:

w = 6.25

Therefore, it will take approximately 6.25 weeks (or 6 weeks and 1 day) for Héctor and Keith to have downloaded the same number of songs.

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Question:-

Héctor has 50 songs downloaded and continues to download 2 a week. Keith uses this table to record his number of downloaded songs. After how many weeks will Héctor and Keith have downloaded the same number of songs?

Weeks - 2  5 10

Mondour of Downloads-  30  45  70

The resulting matrix of the row operation is given as follows:

\(R = \left[\begin{array}{ccc}7&4.5&-6\\-6&-3&12\end{array}\right]\)

We apply the row operation on the original matrix, given as follows:

\(A = \left[\begin{array}{ccc}4&3&0\\-6&-3&12\end{array}\right]\)

The operation is given by:

\(R_1 = R_1 - 0.5R_2\)

That is, applying to each element, we have that:

Hence the resulting matrix is:

\(R = \left[\begin{array}{ccc}7&4.5&-6\\-6&-3&12\end{array}\right]\)

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Answer:

(0,6)

Step-by-step explanation:

The y intercept is where the line crosses the y axis or the coordinate where x = 0.

Here, when x is equal to 0, y is equal to 6 meaning that the y intercept is at (0,6)

Answer:

-2(x - 5)(x + 1)

Step-by-step explanation:

-2x² + 8x + 10

-2(x² - 4x - 5)

-2(x - 5)(x + 1)

Step-by-step explanation:

Hey, there!!

Let's do it simply, ok.

Given that,

\( = - 2 {x}^{2} + 8x + 10\)

Take (-2) common to make it easy.

\( = -2( 2 {x}^{2} - 8x - 10)\)

= -2{ x^2-(5-1)x -5}

Multily with x,

= -2 {x^2-5x+x-5}

Taking common,

= -2{x(x-5) +1(x-5)

= -2{(x+1)(x-5)}...is your required answer.

Hope it helps...

Answer:

36.1

Step-by-step explanation:

53.9 + 36.1 = 90

Answer: 128/15 min or 8.5 min

i

am

right

so

trust

me

i

swear

on

my

mama

this

is

correct

my

g

Answer:

a) 22:25 is the earliest time

b)15 min

Step-by-step explanation:

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

10:10(standard) = 22:10 (military)

22:10 -> 15min-> 22:25

Answer:

a) 22:25 is the earliest time

b)15 min

Because

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

Answer:

See below

Step-by-step explanation:

A cube has all sides the same length, 1.4^5 cm

volume = L x W x H       but  L , W and H  are all the same value

 volume =  1.4^5  * 1.4 ^5  * 1.4 ^5  =  1.4 ^(5+5+5) = 1.4^15 = 155.568  cm^3

Answer:

155.568

Step-by-step explanation:

ez math bro. Just look up

Answer:

$30

Step-by-step explanation:

100+ the twenty you got off is 120 and dvide 120/4=30   I am either making this way to easy or just dont understand lol

An isosceles triangle with two long sides and a short bottom side can have infinitely many possible congruent triangles. However, assuming that the two long sides have a fixed length of 1 unit and the length of the short bottom side is less than 1 unit, there are only two possible congruent triangles.

One of the congruent triangles would have angles of approximately 22.62°, 22.62°, and 135.76°, while the other congruent triangle would have angles of approximately 157.38°, 11.25°, and 11.25°. Therefore, the answer to this question depends on the specific length of the short bottom side and the context of the problem.

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ANSWER:

angle 1 = 180°-35°-36° (angle sum of triangle)

= 109°

angle 3 = 180°-109°(adj angles on a str line)

= 71°

angle 2 = 180°-80°-71°

= 29°

Answer:

C

Step-by-step explanation:

The he has to pay 40$ a month (40*m or 40m) + the intial amount of 75. So put together this equation would be C. Hope this helps!!! :)

Answer: C t = 40m +75

Step-by-step explanation:

Answer:

A

=

1.50c + 18

where

A

is amount and

c

is toppings added

Step-by-step explanation:

The constant price is

18

dollars, which never changes and for every topping you get, it costs

$

1.50

. If you got no toppings, sub in

0

for

c

to get

$

18

.

For a normal distribution, a negative value of z indicates D. the z is to the left of the mean.

A continuous probability distribution known as the "normal distribution" has values that are symmetrically distributed mostly around the mean.

The standard deviation determines the width of the curve in a normal distribution, which depicts a symmetrical plot of data around its mean value. It is represented graphically by the "bell curve.

Z is the number of standard deviations from the mean given by the formula:

z = ( X - μ ) ÷ ( σ )

where

x is the raw score,

μ is the population mean, and

σ is the population standard deviation

A negative value means that the number of standard deviations of an observation is to the left of the mean.

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Answer: Incorrect

Step-by-step explanation:

Your friend Frans' claim is incorrect. A row of zeros in the reduced matrix means that the corresponding equation in the system is redundant and does not provide any additional information. This does not necessarily mean that the system does not have a unique solution. In fact, a row of zeros in the reduced matrix is common when solving systems of linear equations using Gaussian elimination, and it can still lead to a unique solution or even an infinite number of solutions. Therefore, Frans' claim is wrong.

When we add up all of the values that would go through the center of the clock, the value that we would get is 0

The reason for this is because the vectors would make a  circular distribution around the clock face. All of the values have equal magnitude but an opposing direction  when we compare this to the vector that is on the opposite side of the closck face.

An example of this is that :

12:00 is made of equal magnitude but the opposite direction when compared to  6:00. This would be the same fro the pairs 1:00 and 7:00, 2:00 and 8:00.

Hence all of these would cancel out and would be 0

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Answer:

D or an F depends on the grading system

Step-by-step explanation:

Answer:

Cos² x

Step-by-step explanation:

    \(\sf Cos^2 \ x *Csc^2 \ x-Cos^2 \ x *Cot^2 \ x = Cos^2 \ x (Csc^2 \ x - Cot^2 \ x)\)

                                                        \(\sf = Cos^2 \ x \left(\dfrac{1}{Sin^2 \ x} - \dfrac{Cos^2 \ x}{Sin^2 \ x}\right)\\\\= Cos^2 \ x \left(\dfrac{1-Cos^2 \ x}{Sin^2 \ x}\right)\\\\\boxed{\bf Indentity: \ 1 - Cos^2 \ x = Sin^2 \ x}\\\\\\= Cos^2 \ x \left(\dfrac{Sin^2 \ x}{Sin^2 \ x}\right)\\\\= Cos^2 \ x\)

The critical heat flux (CHF) is the maximum heat flux that can be transferred from a surface to a boiling liquid before the boiling process transitions from a stable regime to an unstable regime. The CHF is an important parameter in the design of heat transfer systems, as exceeding the CHF can lead to boiling crisis, which can cause severe damage to the system.

The CHF for a fluid depends on various factors such as fluid properties, surface properties, and flow conditions. One of the commonly used correlations for calculating CHF is the Kutateladze number (Ku) correlation, which is given by:

q_c = C (ρ_L^2 g Δh_f)^0.5 (σ/ρ_L)^0.1

where q_c is the critical heat flux, ρ_L is the liquid density, g is the acceleration due to gravity, Δh_f is the latent heat of vaporization, σ is the surface tension, and C is a constant that depends on the surface properties and flow conditions.

Using this correlation, we can calculate the CHF for the given fluids at 1 atm:

For mercury at 1 atm:

Density of mercury, ρ_L = 13,534 kg/m^3

Latent heat of vaporization of mercury, Δh_f = 2.66 x 10^5 J/kg

Surface tension of mercury, σ = 0.48 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.028, we get:

q_c = 0.028 * (13,534^2 * 9.81 * 2.66 x 10^5)^0.5 * (0.48/13,534)^0.1

q_c = 2.44 x 10^6 W/m^2

For ethanol at 1 atm:

Density of ethanol, ρ_L = 789 kg/m^3

Latent heat of vaporization of ethanol, Δh_f = 8.51 x 10^5 J/kg

Surface tension of ethanol, σ = 0.022 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.027, we get:

q_c = 0.027 * (789^2 * 9.81 * 8.51 x 10^5)^0.5 * (0.022/789)^0.1

q_c = 1.17 x 10^6 W/m^2

For refrigerant R-134a at 1 atm:

Density of R-134a, ρ_L = 1245 kg/m^3

Latent heat of vaporization of R-134a, Δh_f = 2.03 x 10^5 J/kg

Surface tension of R-134a, σ = 0.011 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.026, we get:

q_c = 0.026 * (1245^2 * 9.81 * 2.03 x 10^5)^0.5 * (0.011/1245)^0.1

q_c = 1.35 x 10^6 W/m^2

For water at 1 atm:

Density of water, ρ_L = 1000 kg/m^3

Latent heat of vaporization of water, Δh_f = 2

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Answer:

\(=13a^{437}+12a\)

Step-by-step explanation:

\(\left(a^{413}a^{22}a+1\right)\cdot \:13a-2a+1\cdot \:a\)

\(\mathrm{Add\:similar\:elements:}\:-2a+1\cdot \:a=-a\)

\(=\left(a^{413}a^{22}a+1\right)\cdot \:13a-a\)

\(=\left(a^{436}+1\right)\cdot \:13a-a\)

\(=13a\left(a^{436}+1\right)-a\)

\(=13a^{437}+13a-a\)

\(\mathrm{Add\:similar\:elements:}\:13a-a=12a\)

\(=13a^{437}+12a\)

Answer:

1700 divided by 40 and that would be 42.5 so she does 42 1/2 meters a minute.

The time required for burning off a 2 mm diameter sphere by air at atmospheric pressure and 1000 K is approximately 29.02 seconds

The mass transfer of oxygen from air to the carbon surface is the rate-controlling step. So, the time required for burning off a 2 mm diameter sphere by air at atmospheric pressure and 1000 K can be calculated by using the given data.

Density of carbon = 2250 kg/m3

Thickness of carbon coating = 20 µm = 20 × 10-6 m

Radius of sphere = 2 mm/2 = 1 mm = 0.001 m

Given mass transfer coefficient, k = 0.25 m/s

Fraction of oxygen in air, Φ = 21/100 = 0.21

Assuming that the reaction product is CO2, we know that the reaction of carbon with oxygen can be written as:

C (s) + O2 (g) → CO2 (g)

We can write the equation for the combustion reaction as:

1 C (s) + 1 O2 (g) → 1 CO2 (g)

The mass transfer rate of oxygen from air to the carbon surface can be calculated by the formula:

f = k (Ca - C) = (k ρ/NA) (P - P*)

Where,

Ca = Concentration of oxygen in air = Φ P/RTC

C = Concentration of oxygen in the boundary layer

P = Partial pressure of oxygen

P* = Equilibrium pressure of oxygen

ρ = Density of the carbon material

NA = Avogadro’s number

R = Universal gas constant

T = Temperature of the system

At 1000 K, R = 8.314 J/mol-K and NA = 6.023 × 10^23/mol

So, the mass transfer rate of oxygen from air to the carbon surface is:

f = k (Ca - C) = (k ρ/NA) (P - P*)

= (0.25 × 2250/6.023 × 10^23) (0.21 × 1.013 × 10^5 - P*)

For the reaction of carbon with oxygen, we know that:

nC = m/M = (4/12) π r^3 ρ / M

m = nM

Where,

n = Number of moles

M = Molar mass of CO2 = 12 + 2 × 16 = 44 g/mol

r = Radius of the sphere

ρ = Density of carbon material = 2250 kg/m^3

So, m = (4/12) π (0.001)^3 × 2250 = 2.36 × 10^-6 kg

And, the number of moles of carbon present is:

nC = m/M = 2.36 × 10^-6 / 44 = 5.36 × 10^-8 mol

The amount of oxygen required to burn the carbon can be calculated as:

nO2 = nC = 5.36 × 10^-8 mol

The amount of oxygen present in air required for the combustion reaction will be:

nO2 = Φ nAir

So, the number of moles of air required for the combustion reaction will be:

nAir = nO2/Φ = 5.36 × 10^-8 / 0.21 = 2.55 × 10^-7 mol

The volume of air required for the combustion reaction will be:

VAir = nAir RT/P = 2.55 × 10^-7 × 8.314 × 1000 / 1.013 × 10^5

= 2.06 × 10^-11 m^3

The time required for burning off a 2 mm diameter sphere by air can be calculated by the formula:

t = VAir / f

= 2.06 × 10^-11 / (0.25 × 2250/6.023 × 10^23) (0.21 × 1.013 × 10^5 - P*)

= 3.69 × 10^3 P* seconds

The value of P* depends on the temperature at which the reaction occurs. For the given problem, P* can be calculated using the formula:

ln (P*/0.21) = -38000 / RT

So, P* = 0.21 e^(-38000 / (8.314 × 1000))

= 7.77 × 10^-8 atm

= 7.87 × 10^-3 Pa

Therefore, the time required for burning off a 2 mm diameter sphere by air at atmospheric pressure and 1000 K is:

t = 3.69 × 10^3 × 7.87 × 10^-3

= 29.02 seconds (approx)

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Answer:

B.) A & B

Step-by-step explanation:

For example x^2-64= (x+8)(x-8)

The order of the numbers from least to greatest (pi, -3, sqrt 49 , sqrt 9) is -3.00 <  sqrt 9 < pi  < sqrt 9

The concept that will be used here is ordering. When you put a list of numbers in order, you rank them from least to greatest or greatest to least. An effective tool for comparing and sorting numbers is a number line. From left to right, we read a number line, with the numbers nearer to the left having lower values.

The given numbers can be converted to decimals so as to be able to arange them in the required order which can be done as :

pi= 3.147= 3.15

-3= -3.00

sqrt 49=7.00

sqrt 9 =3.00

Therefore,-3.00 <  sqrt 9 < pi  < sqrt 9

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Answer:

(B) 7.6, 8.8

Step-by-step explanation:

u are welcome

Answer:

B.(7.6, 8.8)

Step-by-step explanation:

\(\huge\longmapsto\mathfrak{Answer}\)

=》

\( \sec {}^{2} (x) - tan(x) - 3\)

=》

\( \tan {}^{2} (x) + 1 - \tan(x) - 3\)

=》

\( \tan {}^{2} (x) - \tan(x) - 2\)

=》

\( \tan {}^{2} (x) - 2\tan(x) + \tan(x) - 2\)

=》

\( \tan(x) ( \tan(x) - 2) + 1( \tan(x) - 2) \)

=》

\(( \tan(x) + 1)( \tan(x) - 2)\)

so,

case - 1

=》

\( \tan(x) = - 1\)

case - 2

\( \tan(x) = 2\)