write an expression for the operation described below subtract v from 2

The answer is on the pic

Step-by-step explanation:

Btw brainliest me plss

Answer: zxy=39 wxy=78

Step-by-step explanation:

Since xz bisects wxy, the 2 angles that make up wxy are equal.

The algebraic expression for the area is:

A = (2H - 8)*H/2

Here we want to write the expression:

"the area of a triangle that has a base 8 inches less than 2 times wider than the height."

Remember that for a triangle of base B and height H, the area is:

A = B*H/2

So if the base is 8 inches less than 2 times the height, we can write:

B = 2*H - 8

Replacing that in the area equation we get:

A = (2H - 8)*H/2

That is the equation for the area.

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The values that used to create the box and whisker plot

[using these values]

Minimum value: Lower whisker: 12

Q1: 23.5

Q2 (median): 36

Q3: 46

Maximum value: Upper whisker: 56

Here, we have,

Step 1: Order the data set from smallest to largest:

12, 19, 28, 32, 34, 38, 45, 47, 50, 56

Step 2: Calculate the lower quartile (Q1), median (Q2), and upper quartile (Q3):

Q1 (25th percentile): The value that separates the lowest 25% of the data from the rest. Since we have 10 data points, the first quartile will be the average of the 2.5th and 3.5th data points. In our case, it's the average of the 2nd and 3rd data points:

Q1 = (19 + 28) / 2 = 23.5

Q2 (50th percentile or median): The value that separates the lowest 50% of the data from the rest. Since we have an even number of data points, the median will be the average of the 5th and 6th data points:

Q2 = (34 + 38) / 2 = 36

Q3 (75th percentile): The value that separates the lowest 75% of the data from the rest. Since we have 10 data points, the third quartile will be the average of the 7.5th and 8.5th data points. In our case, it's the average of the 7th and 8th data points:

Q3 = (45 + 47) / 2 = 46

Step 3: Calculate the interquartile range (IQR):

IQR = Q3 - Q1 = 46 - 23.5 = 22.5

Step 4: Determine the whiskers:

Lower whisker: The smallest value that is not smaller than Q1 - 1.5 * IQR

Upper whisker: The largest value that is not larger than Q3 + 1.5 * IQR

Lower whisker limit: 23.5 - 1.5 * 22.5 = -10

Upper whisker limit: 46 + 1.5 * 22.5 = 79.5

Our data points are all within these limits, so the lower whisker is at the smallest value, 12, and the upper whisker is at the largest value, 56.

Now, you can plot the box and whisker plot using these values:

Minimum value : Lower whisker: 12

Q1: 23.5

Q2 (median): 36

Q3: 46

Maximum value: Upper whisker: 56

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create a box and whisker plot for the following set of data

12, 19, 28, 32, 34, 38, 45, 47, 50, 56

Answer: Evaluate

Step-by-step explanation:

Answer: 177.65

Step-by-step explanation:

its the only accurate  answer.........

Answer: Can you translate for me? I don't know spanish.

Step-by-step explanation:

:)

Answer:

Charlotte started with 65.

Step-by-step explanation:

In order to find what number Charlotte started with, we need to go backward. So first, multiply by 2, then multiply by 5/6. 39 multiplied by 2 is 78, which is 6/5 of the number Charlotte started with. So what we need to do is multiply 78 by 5/6. That equals 390/6, which is 65. The problem has been solved. Charlotte started with 65.

Consequently, the measurement between points AA and BB is roughly 14092.3 feet, rounded to the closest hundredth of a foot.

A pair of rays (half-lines) with such a shared termination are combined to form an angle. The latter is referred to as the angle's vertex, and the beams are sometimes referred to as the angle's legs and other times as its limbs.

Let's call the distance from point AA to the lighthouse/beacon light as "d" and the distance from point BB to the lighthouse/beacon light as "x".

We can use the tangent function to relate the angles of elevation to these distances:

tan(14°) = h/d, where h is the height of the lighthouse/beacon light above sea level

tan(5°) = h/x

We can eliminate h from these equations by solving for it in terms of d and x. Rearranging the first equation, we get:

h = d tan(14°)

This is what we get when we enter it into the second equation:

tan(5°) = (d tan(14°))/x

Solving for x, we get:

x = d tan(14°)/tan(5°)

Substituting the given value of d (1246 feet), we get:

x = 1246 tan(14°)/tan(5°) ≈ 14092.3 feet

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Answer:

53%

Step-by-step explanation:

Total voters = 5,800

5,800= 100%

3,074=X

X=3,074*100/5,800= 53%

Answer:

30

Step-by-step explanation:

5 x 6 = 30

2 x 6 = 12

30+12 = 42

The correct option for the given sum is option B. The point (2,-9) paired with (2, 3), will make a side equal to this length.

Let the other point of the pentagon will be M(n, o).

The given point be A (a, b)

Also given one of the sides of a pentagon has length 12.

Now, we need to find the distance between the two points,

Distance between two points: |AM| = √\((a-n)^2+(b-o)^2\)

Now,

\(12 = \sqrt{(2-n)^2+(3-o)^2}\)

\((12)^2\) = \((2-n)^2+(3-o)^2\)

\((2-n)^2+(3-o)^2\) = 144 ----------------------------- eq (1)

Now, check every point for the values to match with equation (1)

Option A: \((2-14)^2+(3-15)^2\) = 288. So the option is false.

Option B:

\((2-2)^2+(3-(-9))^2\) =114

0+114 =114

Therefore option B is correct. The other point is (2,-9).

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Step-by-step explanation:

so, if I understand this correctly, the original function (shown in the graph) is

f(x) = sqrt(x)

the following transformations were done going from f(x) to h(x) :

x -> x + 4 as variable term moved the whole curve 4 units to the left. because now a specific functional value is calculated for a smaller x (by 4 units) than for the original f(x). e. g. let's call g(x) = sqrt(x + 4). then g(-4) = f(0). as mentioned, everything moved over to the left by 4 units.

sqrt(x) -> 3×sqrt(x) increased the range of the function (the generated y values) by the factor 3. was the functional result for a x value = 1, then it is now 3 for the same x value.

sqrt(x) -> sqrt(x) - 1 moved the whole curve down by 1 unit.

in summary, the whole original curve was moved 4 units to the left, then stretched upwards by the factor 3, and then that result was moved down by 1 unit.

so, e.g.

h(-4) = 3×f(0) - 1 = -1 point (-4, -1) corresponds to old (0, 0)

h(-3) = 3×f(1) - 1 = 2 point (-3, 2) corresponds to old (1, 1)

h(0) = 3×f(4) - 1 = 5 point (0, 5) corresponds to old (4, 2)

Answer:

b - 100 cm²

c - 45.5 cm²

Step-by-step explanation:

Hello There!

For b - The following figure shown is a trapezoid with the dimensions

height = 10cm

longer base = 12cm

shorter base = 8cm

We can calculate the area of a trapezoid using this formula

\(A=\frac{a+b}{2} h\)

where a and b are bases and h = height

knowing the dimensions all we have to do is plug in the values

\(A=\frac{8+12}{2} 10\\8+12=20\\\frac{20}{2} =10\\10*10=100\)

so we can conclude that the area of figure b is 100 cm²

for a

The figure shown is an irregular shape so to calculate the area we're going to want to divide the irregular shape into two regular shapes

a rectangle with the dimensions:

width = 7 cm

length = 8cm (total height of irregular figure) - 3cm (height of the triangle)

8cm-3cm=5cm so the length of the rectangle is 5cm

a triangle with the dimensions:

base (length) = 7cm

height = 3cm

Now lets find the area of each shape

for the rectangle:

the area of a rectangle can simply be found by multiplying the length and width

7 * 5 = 35 so the area of the rectangle is 35 cm²

for the triangle:

the area of a triangle can be found using this formula

\(A=\frac{1}{2} bh\) where b = base and h = height

knowing the dimensions all we have to do is plug in the values

\(A=\frac{1}{2} 3*7\\3*7=21\\\frac{21}{2} =10.5\)

so we can conclude that the area of the triangle is 10.5 cm²

finally we add the two areas of the regular shapes

10.5 + 35 = 45.5 cm²

In conclusion the area of the figure is 45.5 cm²

To determine the function that models the data, we need to analyze the relationship between the cost per photo and the number of photos a customer buys. From the given information, we can observe that the cost per photo varies inversely with the number of photos. This implies that as the number of photos increases, the cost per photo decreases, and vice versa.

To model this relationship, we can use the inverse variation equation, which can be expressed as:

y = k/x

Here, y represents the cost per photo, x represents the number of photos, and k is the constant of variation.

Let's examine the data given in the table to find the value of k:

Number of Photos (x) Cost per Photo (y)

10 10

25 4

50 2

100 1

We can see that as the number of photos increases, the cost per photo decreases. We can use any pair of values from the table to solve for k. Let's choose the pair (50, 2):

2 = k/50

Solving for k:

k = 2 * 50 = 100

Now that we have the value of k, we can write the function that models the data:

y = 100/x

Therefore, the function that models the data is y = 100/x, where y represents the cost per photo and x represents the number of photos a customer buys.

S = (HR(Wi - Wn)) / 1000.

First, multiply both sides by 1000.

1000S = HR(Wi - Wn)

Divide bot sides by H(Wi - Wn)

(1000S) / H(Wi - Wn) = R

Answer:

Top left is A

Top right is B

Bottom left is D

Bottom right is A

Step-by-step explanation:

Answer:

The height of the rugby ball is 45 feet at t = 1.27s and t = 2.17s

Step-by-step explanation:

The height of the ball, in feet, after t seconds, is given by the following equation:

\(h(t) = -16t^{2} + 55t + 1\)

When the height of the rugby ball is 45 feet

This is t for which: h(t) = 45

So

\(h(t) = -16t^{2} + 55t + 1\)

\(45 = -16t^{2} + 55t + 1\)

\(-16t^{2} + 55t - 44 = 0\)

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

\(ax^{2} + bx + c, a\neq0\).

This polynomial has roots \(x_{1}, x_{2}\) such that \(ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})\), given by the following formulas:

\(x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}\)

\(x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}\)

\(\bigtriangleup = b^{2} - 4ac\)

In this question:

\(-16t^{2} + 55t - 44 = 0\)

So \(a = -16, b = 55, c = -44\)

\(\bigtriangleup = 55^{2} - 4*(-16)*(-44) = 209\)

\(t_{1} = \frac{-55 + \sqrt{209}}{2*(-16)} = 1.27\)

\(t_{2} = \frac{-55 - \sqrt{209}}{2*(-16)} = 2.17\)

The height of the rugby ball is 45 feet at t = 1.27s and t = 2.17s

Answer

its b

Step-by-step explanation:

43k 67u 88j

Answer:

tens place

Step-by-step explanation:

24 can't be into the thousands place or the hundreds place. hope this helps

Answer

 hundredths place

Step-by-step explanation:

When performing long division, the first digit of the quotient appears over the least significant digit of the first portion of the dividend that is greater than or equal to the divisor.

Here, when performing long division we compare ...

 64 vs 1 . . . no quotient digit

 64 vs 15 . . . no quotient digit

 64 vs 159 . . . the first quotient digit appears with the same place value as the 9 in 1.59. That is, the first quotient digit will be 0.02, 2 in the hundredths place.

Answer:

B) 5

Step-by-step explanation:

The points are (2,2) and (6,5). Subtract both Y's and X's and then square the answers and add. you should get 25, which has a square root of 5.

Answer

We will obtain maximum revenue when 250 apartments are rented.

Explanation

The total revenue is given in function form as

R(x) = 200x - 0.4x²

x = number of apartments rented

We are then asked to find the number of apartments rented (x) that produces the maximum revenue.

For this, we know that at maximum point for any function, the first derivative is 0 and the second derivative is negative.

So, to find the x when the function is maximum, we just find the first derivative and equate it to 0.

R(x) = 200x - 0.4x²

First derivative

(dR/dx) = 200 - 0.8x

200 - 0.8x = 0

0.8x = 200

Divide both sides by 0.8

(0.8x/0.8) = (200/0.8)

x = 250 apartments rented

Second derivative

(d²R/dx²) = -0.8

Negative, proving that this is truly the maximum point for this function.

Hope this Helps!!!

The amount of solution A and B required are 60 and 90 ounces respectively.

Creating simultaneous equations for the problem:

Mass of solution A = a

Mass of solution B = b

a + b = 150 _____(1)

0.65a + 0.90b = 150×0.80

0.65a + 0.90b = 120 __(2)

From (1)

a = 150-b ____(3)

substitute (3) into (2)

0.65(150-b) + 0.90b = 120

97.5 - 0.65b + 0.90b = 120

0.25b = 120-97.5

0.25b = 22.5

b = 22.5/0.25

b = 90

a = 150 - b

a = 150 - 90

a = 60

Therefore , 60 ounces of solution A and 90 ounces of solution B is required.

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Answer:

-222

Step-by-step explanation:

The number of points won by Tina is; 125 points.

Let the number of points won by Warren be = a

Let the number of points won by Lisa be = b

Let the number of points won by Tina be = c

According to the question:

Therefore, total number of points won by Warren, a = 24 + 16 + 10 = 50.

Since Lisa won the same number of points as Warren; b = 50.

Ultimately, the total number of points won by Warren, Lisa and Tina is; 225.

c = 125 = number of points scored by Tina

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Answer:

question of number 10 is 3

The minimum length of pipe required to deliver water to points A and B is approximately 20.375 miles.

We are given that a water pumping station is to be built on a river at point P in order to deliver water to points A and B. The design requires that LAPD = /BPC so that the total length of piping that will be needed is a minimum. We need to find this minimum length of pipe.

The given figure is shown below: \(AB = 10 \ miles\)\(BC = 6 \ miles\)\(CP = 12 \ miles\). We are given that \(LAPD = LCPB\).

Now, we need to find the minimum length of pipe required for delivering the water to points A and B.The total length of the pipe, \(L_{total} = LA + AB + BP\)Since \(LAPD = LCPB\), we can say that\(AP^2 + PD^2 = BP^2 + PC^2\).

From the triangle ACP, we can say that\(AC^2 = AP^2 + PC^2\). So, we can substitute AP^2 + PC^2 with AC^2 to get\(AP^2 + PD^2 = BP^2 + AC^2\)Now, we can substitute AP = AC - PC and BP = BC + PC in the above equation to get\((AC - PC)^2 + PD^2 = (BC + PC)^2 + AC^2\).

After solving this equation, we get\(AC = \frac {37}{8}\) and \(PC = \frac {27}{8}\)Now, we can calculate the length of pipe required as follows: \(L_{total} = LA + AB + BP = 10 + 6 + \frac {27}{8} = \boxed{20.375 \ miles}\). Therefore, the minimum length of pipe required to deliver water to points A and B is approximately 20.375 miles.

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