How much work is done on a small car if a 3150 N force is exerted to move it 75.5 m to the side of the road
Answer:
Explanation:
Work = Force times displacement. Therefore,
W = 3150(75.5) so
W = 238000 N*m
Please help someone. A generator consumes 147 joules of energy in fuel and produces 75 joules of energy
in electricity. Engineers are challenged to produce a generator that is 20% more
efficient. Which of the following combinations of input and output energy represents a generator that has met this design challenge?
a. 150 joules of fuel to produce 90 joules of electricity
b. 135 joules of fuel to produce 68 joules of electricity
c. 60 joules of fuel to produce 100 joules of electricity
d. 115 joules of fuel to produce 82 joules of electricity
Answer:
A
Explanation:
Current effiency
= 75/147
= 0.5102
New Efficiency
= 120/100 × 0.5102
= 0.6122
Only option A satisfies this efficiency.
a beach ball is left in the bed of a pickup truck. Describe what happens to the ball when the truck accelerates forward
need help this is timed
suppose that a meter stick is balanced at its center. a 0.14 kg mass is then positioned at the 2-cm mark. at what cm mark must a 0.29 kg mass be placed to balance the 0.14 kg mass?
The 0.29 kg mass must be placed at the 0.972 cm mark to balance the 0.14 kg mass.
Suppose that a meter stick is balanced at its center.
A 0.14 kg mass is then positioned at the 2-cm mark.
To balance the 0.14 kg mass, the following steps need to be taken.
Find the torque produced by the 0.14 kg mass on the meter stick.
Torque = force x perpendicular distance from the pivot
Torque = 0.14 kg x 9.81 m/s^2 x 0.02 m
Torque = 0.02772 Nm
The torque produced by the 0.29 kg mass must balance the torque produced by the 0.14 kg mass.
Torque produced by 0.29 kg
mass = 0.02772 Nm
Torque produced by 0.29 kg
mass = force x perpendicular distance from the pivot
Let the distance of the 0.29 kg mass from the pivot be x cm.
Then,0.02772 Nm = 0.29 kg x 9.81 m/s^2 x (x/100) m0.02772 = 2.8479x/10000x = 0.972 cm
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To make a perfect pie dough, you must mix the ingredients until they are
O
O
assiduous
cohesive
coalition
abstract
The best pie crust is a perfect balance between fat, flour, and liquid. is
To make a perfect pie dough .
Why is it called pie?"Pie" was the word for a magpie before it was a word for a pastry, from the Latin word for the bird, Pica (whence the name of the disorder that makes you eat weird things). Pica morphed into "pie" in Old French, following the proud French tradition of actually pronouncing as few consonants as possible.
What is in pie?pie, dish made by lining a shallow container with pastry and filling the container with a sweet or savoury mixture. A top crust may be added; the pie is baked until the crust is crisp and the filling is cooked through.
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The ideal proportion of oil, flour, and liquid goes into making the greatest pie crust. is to create the ideal pie dough.
How come it's called pie?Before it became a term for a baked food, "pie" was the Slang phrase for bird, Pix (whence the name of the disorder that makes you eat weird things). Following their noble French custom of genuinely speaking as few letters as possible, pica evolved into "pie" during Old French.
How is pie made?Pie is a dish that is created by lining the shallow dish with dough and filling it with either a sweet or spicy combination. Its pie is heated until the filling is heated all the way through and the top crust is crunchy.
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Calculate the force of attraction between a body of mass 5kg at a distance of 10cm
\( 3.35 \times 10 ^{ - 11} \)
Explanation:
proof:\(m1= 5 kg \\ \\ m2 = 10 kg\)
\(distance \: \: between \: \: objects = 10 cm \\ \\ force \: \: of \: \: attraction = ? \\ \\ F= g m1 \times \frac{m2}{ {d}^{2} } \\ \\ =6.7 \times {10}^{ - 11} \times 5 \times \frac{10}{ {10}^{2} } \\ \\ = 67 \times {10}^{ - 11} \times 5 \times \frac{10}{100 \times 10} \\ \\ = 67 \times \frac{ {10}^{ - 11} }{20} \\ \\ =6.7 \times \frac{ {10}^{ - 11} }{2} \\ \\ = 3.35 \times 1 {0}^{ - 11} \)
hope it helps9. A force is applied horizontally to a 20 kg box on a flat table, if the acceleration of the box is 2 m/s and the
coefficient of friction between the box and the table is 0.5, what was the magnitude (number) of the
applied force?
By Newton's second law,
n + (-w) = 0
p + (-f ) = (20 kg) (2 m/s²)
where n is the magnitude of the normal force, w is the weight of the box, p is the magnitude of the applied force (p for push or pull), and f is the magnitude of the friction force.
Calculate the weight of the box:
w = (20 kg) (9.80 m/s²) = 196 N
Then
n = w = 196 N
and
f = µ n = 0.5 (196 N) = 98 N
Now solve for p :
p - 98 N = 40 N
p = 138 N
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.500 m. What is net force on 93?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m-
-5.00 x 10-6 C
92
-5.00 x 10-6 C
93
0.500 m-
The answer to the question is 1.125 Newton
Formula for electrostatic force is F = ( K q1 q2 )/ r²
where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.
Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.
Electrostatic force between q1 and q3
r will be 0.500 + 0.500 = 1 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²
F₁₃ = 2.25 × 10⁻¹ N
Electrostatic force between q2 and q3
r will be 0.500 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²
F = (225 × 10⁻³) / (25 × 10⁻²)
F₂₃ = 9 × 10⁻¹ N
Total force on q3 will be F₁₃ + F₂₃
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 11.25 × 10⁻¹ ) N
Total force on q3 = 1.125 N
Thus after solving we got the net force on q3 as 1.125 Newton
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A lamp uses a standard 9 V battery, How much resistance is in the circuit is in the current of 1.05 A?
Answer:
R= v/I
R= 9/1.05=8.5714 ohms
A motorcycle travels at a constant 20 m/s for 10 s. How far has it traveled?
d =200 m
Explanation:Hi there !
Velocity formula
v = d/t => d = v×t
d = distance
t = time
d = 20m/s×10s = 200 m
Good luck !
A bicycle has a mass of 39.5kg on Earth . What would its weight be on moon (g=1.6m/s^2)
Answer:
63.2N
Explanation:
\(Solution,\\\\Mass(m)=39.5kg\\\\\\Gravity(g)=1.6m/s^{2} \\Now,\\\\Weight -on- moon=m*g=39.5*1.6m/s^{2} =63.2N\)
According to the Theory of Plate Tectonics, which of the following statements is correct?
a. Earth’s outer layer is cool and rigid.
b Earth’s outer layer is divided into large pieces called plates
c. Earth’s plates never move
d. The two first answer choices are both correct
Answer:
It's D. The geothermal energy from Earth's core loses most of its heat before reaching the outer layer. The plates on the outer layer have been proven to be moving due to evidence such as earthquakes, volcanic eruptions, and tsunamis.
Explanation:
The emf, formerly known as electromotive force, is actually... a potential difference. a field. a force. an energy.
Answer:
The correct option is (a) "potential difference".
Explanation:
EMF is an Electromotive force. It is the energy per unit electric charge that is imparted by an energy source, such as an electric generator or a battery. One of the terminals of device is positive and other is negative. It is also defined as terminal potential difference when no current flows.
It is actually a potential difference across the terminals.
Answer:
potential difference
Explanation:
Which of the following never changes no matter where in the universe
Answer:mass
Explanation:
Mass of the body is defined as he amount of matter a body have.It is denoted by m and its unit is kg.Mass is the only option never change no matter in the universe.
What is difference between mass and weight?
Mass of the body is defined as the amount of matter a body have.It is denoted by m and its unit is kg.Mass is the quantity on which a lot of physical quantity depends.
Weight is defined as the amount of force an object excerts on the surface.It is given as the product of mass and the gravitational pull.;
Mass is an indepedent quantity it never depend on the other.While weight is a dependent quantity depends upon the gravitational pull.
The value of gravitational pull is different in the different part of the universe.For example on the earth the value of gravitational acceleration is 9.81 m/sec².While on the moon it is g/6.
Weight is change according to the place or surrounding while the mass of the body is constant everywhere.
Hence the mass is the only option never change no matter in the universe.
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What is living being
Answer:
the things that eat, breathe, grow, move, reproduce and have senses is called living beings.
An image is a copy of an object formed by ____
light.
The answer is: Reflected
Explanation:
An image is a copy of an object that is formed by reflected (or refracted) light. Regular reflection occurs when light reflects off a very smooth surface and forms a clear image. Diffuse reflection occurs when light reflects off a rough surface and forms a blurry image or no image at all.
A plane electromagnetic wave is traveling vertically downward with its magnetic field pointing eastward.
Its electric field must be pointing?
toward the east.
toward the south.
toward the north.
vertically upward.
vertically downward.
An electromagnetic wave is a transverse wave consisting of oscillating electric and magnetic fields that propagate through space at the speed of light.
The direction of propagation of the wave is perpendicular to the electric and magnetic fields.
In this scenario, a plane electromagnetic wave is traveling vertically downward, meaning the direction of propagation is vertical, and the magnetic field is pointing eastward.
According to the right-hand rule, if the magnetic field is pointing eastward, then the electric field must be perpendicular to it and to the direction of propagation.
Therefore, the electric field must be pointing toward the north.
This is because the electric and magnetic fields in an electromagnetic wave are orthogonal to each other, meaning they are at right angles to each other.
So, if one field is pointing in a particular direction, the other field must be pointing in a direction perpendicular to it.
Understanding the direction of the electric and magnetic fields in an electromagnetic wave is crucial to understanding how the wave behaves and interacts with matter. This is fundamental to many areas of physics, including optics, electromagnetic radiation, and communication systems.
So, the correct answer is: toward the north.
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The electric field of an electromagnetic wave is perpendicular to the magnetic field and both are perpendicular to the direction of wave propagation. Therefore, since the magnetic field is pointing eastward, the electric field must be pointing vertically downward.
The right-hand rule is a way to determine the direction of the electric field based on the direction of the magnetic field. If we hold our right hand with the thumb pointing in the direction of the propagation (vertically downward in this case) and the fingers curled in the direction of the magnetic field (eastward in this case), then the direction that the extended fingers point to will be the direction of the electric field.
In this scenario, the magnetic field is pointing eastward and the propagation is vertically downward. If we use the right-hand rule, we can see that the electric field could be pointing either toward the north or toward the south, as those are the directions that are perpendicular to both the magnetic field and the direction of propagation. Therefore, without further information, we cannot determine the exact direction of the electric field.
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imagine you had performed a third trial in which you had pushed the cart from behind rather than pull it by the thread. if the cart started from the rest,
In the third trial, if you pushed the cart from behind rather than pulling it by the thread, and the cart started from rest, you would follow these steps:
1. Place the cart on a flat surface, ensuring it is at rest.
2. Apply a force to the cart by pushing it from behind.
3. Observe and record the cart's acceleration and motion as it moves forward due to the applied force.
4. Compare the results with the previous trials where the cart was pulled by a thread to analyze the differences in motion and acceleration.
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A 10- kilogram box is at static equilibrium and the downward pull of gravity acting on the box is 98 Newton's what is the minimum force that would be required to just pick up the box ?
Answer:
Explanation:
Now
Look at it this way. This box is in equilibrium... Meaning forces around balanced out.
Now...
The Earth's pull on it is 98N
What Minimum external forces is needed to pick this up....
Now... The Minimum Force is 98N
Why?
Since This Box is under the influence of gravity...
Gravity is acting as a resistance
If you apply a force less than 98N... Let's say 50N on this box... It won't budge because your applied force is less than the resisting force on it(98N).
So We need a force ≥98. So the least force is 98N. Nothing below this will move the Box
Answer 98N.
Answer:
See image
Explanation:
Plato
7) You think you have found a diamond. Its mass is 5.28 g and its volume is 2 cm3. Calculate the density
and say if it is a diamond or not.
Answer:
\(\boxed {\tt d=2.64 \ g/cm^3}\)
\(\boxed {\tt Not \ a \ diamond}\)
Explanation:
Density can be found by dividing the mass by the volume.
\(d=\frac{m}{v}\)
The mass is 5.28 grams and the volume is 2 cubic centimeters.
\(m=5.28 \ g\\v= 2 \ cm^3\)
Substitute the values into the formula.
\(d=\frac{5.28 \ g }{2 \ cm^3}\)
Divide.
\(d=2.64 \ g/c^3\)
The density of the unknown substance is 2.64 grams per cubic centimeter.
The density of a diamond is about 3.5 grams per cubic centimeter. Since 2.64 is not equal to 3.5, the unknown substance is not a diamond.
A certain electromagnetic wave has an intensity of 8 x 10^7. Determine the amplitude of this wave's magnetic field.
The correct answer is 14 T
B= Amplitude of wave's Magnetic field.
∪°=permeability of free space.
I= Intensity
\(I =B^2/2u\)
\(B=\sqrt{2uI}\)
Here
\(I= 8*10^7 w/m²\)
\(B=\sqrt{2/10/8×107}\)
\(B=\sqrt{2u/8*10^7}\)
\(B=\sqrt{2*4T* 10*7 *8*10^-^7}\)
B = 14-18 T ~ 14 T.
B= 14T
What is magnetic field?
A magnetic field is a vector field that describes the magnetic influence on charges, currents, and magnetic materials in motion. A moving charge inside a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field. A changing magnetic field also has an effect on a variety of nonmagnetic materials by influencing the motion of their outer atomic electrons. Magnetic fields are formed around magnetised materials and are generated by electric currents similar to those found in computers. computers.
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4. As a 500 N woman sits on the floor, the floor exerts a force on her of
ext
a) 1000 N.
b) 500 N.
c) 250 N.
d) 50 N.
e) 5 N.
Answer: 1000
Explanation:
Its double her weight
Two vehicles are traveling when they enter an intersection and crash and stick together. Both have a mass of 1,650 kg and both are traveling at 15 m/s. If one is headed North and the other is headed East, after the collision they end up traveling NE together at what speed (in m/s)? Please input your answer as a positive number with two decimal places.
Answer:
10.61 m/s
Explanation:
To find the final speed, we will use the conservation of momentum in each direction, so we can write the following equations:
\(\begin{gathered} p_{ix}=p_{fx} \\ m_1v_{1x}+m_2v_{2x}=(m_1+m_2)v_{fx} \\ \text{and} \\ p_{iy}=p_{fy} \\ m_1v_{1y}+m_2v_{2y}=(m_1+m_2)v_{fy} \end{gathered}\)Where m1 and m2 are the mass of the vehicles, v1 and v2 are their respective velocities in each direction, and Vfx and Vfy are the final velocities in each direction.
If one of the vehicles is headed north, its horizontal velocity Vx = 0 m/s. In the same way if the other is headed east, its vertical velocity Vy = 0m/s
Therefore, we can replace the values and solve the first equation as:
\(\begin{gathered} 1650(0)+1650(15)=(1650+1650)v_{fx} \\ 24750=3300v_{fx} \\ \frac{24750}{3300}=v_{fx} \\ 7.5m/s=v_{fx} \end{gathered}\)In the same way, we can solve the second equation as:
\(\begin{gathered} 1650(15)+1650(0)=(1650+1650)v_{fy} \\ 24750=3300v_{fy} \\ \frac{24750}{3300}=v_{fy} \\ 7.5m/s=v_{fy} \end{gathered}\)Now, we know that the vertical and horizontal speed was 7.5 m/s. So, we can calculate the final speed using the Pythagorean theorem as:
\(\begin{gathered} v=\sqrt[]{(v_{fx})^2+(v_{fy})^2} \\ v=\sqrt[]{(7.5)^2+(7.5)^2} \\ v=\sqrt[]{56.25+56.25} \\ v=\sqrt[]{112.5}=10.61\text{ m/s} \end{gathered}\)So, the speed after the collision was 10.61 m/s
An airplane flies 700 miles with a tail wind in 2.0 hrs. If it takes 2.5 hrs to cover the same distance against the headwind, then what is the speed of the plane in still air? A).290mph B).315mph C).240mph D).330mph E).250mph
Answer:
B).315mph
Explanation:
Let the speed of the plane = p
Let the speed of the wind = w
Set up the system equation as;
Relative V: Time: Distance:
in wind direction: p + w 2 700
against wind: p - w 2.5 700
2(p + w) = 700
2.5(p - w) = 700
2p + 2w = 700
2.5p - 2.5w = 700
2.5 x: 5p + 5w = 1750
2 x: 5p - 5w = 1400
10p = 3150
p = 315 mph
Therefore, he speed of the plane in still air is 315 mph
A 10 kilogram sled is pulled across a frictionless surface with a force of 50 newtons for a distance of 10 meters. The pull is applied to the sled for a time of 2.0 seconds.
Answer:
The power will be "250 watt". A further explanation is given below.
Explanation:
The given values are:
Force,
F = 50 N
Displacement,
d = 20 m
Time,
t = 2.0 seconds
Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1
Now,
The work will be:
= \(Force\times displacement\times \Theta\)
On substituting the given values, we get
= \(50\times 10\times Cos0^{\circ}\)
= \(50\times 10\times 1\)
= \(500 \ Newton\)
Now,
The Power will be:
= \(\frac{Work \ done}{time}\)
= \(\frac{500}{2.0}\)
= \(250 \ watt\)
average method and it reports the tollowing unit data tor the rorming department. Units completed in the torming department are transferred to the painting department. Production cost information for the forming department follows. . Calculate the equivalent units of production for both direct materials and conversion for the Forming department. o. Calculate the costs per equivalent unit of production for both direct materials and conversion for the Forming department c. Using the weighted average method, assign costs to the forming department's output-specifically, its units transferred to painting and its endina work in brocess inventorv. Calculate the costs per equivalent unit of production for both direct materials and conversion for the For Jsing the weighted average method, assign costs to the forming department's output-specifically, its 4 d its ending work in process inventory. Complete this question by entering your answers in the tabs below. Calculate the equivalent units of production for both direct materials and conversion for the forming department. a. Calculate the equivalent units of production for both direct materials and conversion for the Forming departm b. Calculate the costs per equivalent unit of production for both direct materials and conversion for the Forming c. Using the weighted average method, assign costs to the forming department's output-specifically, its units tra and its ending work in process inventory. Complete this question by entering your answers in the tabs below. Calculate the costs per equivalent unit of production for both direct materials and conversion for the forming department Required information Using the weighted average method, assign costs to the forming department's output-specifically, its units trar painting and its ending work in process inventory.
Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.
Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500
Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000
a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units
Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units
b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production
Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit
Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit
c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production
Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700
Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300
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Why is the loss of mass of the object only an apparent loss?
Answer:
archimides princile
Explanation:
Archimede's principle states that when a body is immersed partly or wholly in a liquid, there is an apparent loss in the weight of the body which is equal to the weight of the liquid displaced by the body.
Answer:
archimides
Explanation:
Might it be possible to explain the interaction of the rod and pieces of paper as a gravitational interaction? please explain why you think that your answer is true.
It is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
What is Gravitational interaction?This is defined as the interaction between a particle or body resulting from their mass. This type of interaction is usually weak and occurs in all distances possible.
It is not gravitational interaction, because the rod attracts paper only against the gravitational force of the earth and there is no attraction between both bodies under a different condition.
This is therefore the reason why it is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
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identify each of the following orbitals, and determine the n and l quantum numbers. explain your answers.
In quantum mechanics, an orbital is a mathematical function that describes the probability of finding an electron in a particular region of space around an atom's nucleus.
Quantum refers to the smallest indivisible unit of energy, matter, or any other physical quantity. It is a term used in quantum mechanics, the branch of physics that describes the behavior of matter and energy at the scale of atoms and subatomic particles.
Orbitals are characterized by three quantum numbers: the principal quantum number (n), the azimuthal quantum number (l), and the magnetic quantum number (m).
The principal quantum number determines the size and energy level of the orbital, while the azimuthal quantum number determines the shape of the orbital. The magnetic quantum number determines the orientation of the orbital in space.
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Correct question:
Identify each of the following orbitals, and determine the n and l quantum numbers. Explain your answers.