Answer:
Step-by-step explanation:
Two lines are parallel when they have the same slope. First, lets find the slope of the given line.
7x - 3y = 5
3y = 7x - 5
y = 7/3 x - 5/3
The slope is 7/3 which is also the slope of the parallel line as we said above.
The parallel line has the equation y = 7/3x + b
we use the point (12,-5) to find the value of b (the y-intercept)
-5 = 7/3 * (12) + b
-5 = 28 + b
b = -33
y = 7/3x - 33
Please help. Will mark brainliest! Answer the questions
Answer:
V= 2596.125 cm squared
SA= 1187.5 cm squared
Answer:
Step-by-step explanation:
\(V=xyz\\ \\ V=21.5(11.5)10.5=2596.125cm^3\\ \\ A=2xy+2xz+2yz\\ \\ A=2(xy+xz+yz)\\ \\ A=2(21.5(11.5)+21.5(10.5)+11.5(10.5))\\ \\ A=2(247.5+225.75+120.75)\\ \\ A=2(594)\\ \\ A=1188cm^2\)
There were 44 dogs and cats at the pet store if 75% were cats how many cats were at the pets store?
Answer:
33.
Step-by-step explanation:
75% x
100 44
x = (44 * 75 ) / 100 = 33.
VI. In a class of 40 students, the marks obtained in Mathematics (out of 50) are as under: 44,50,44,49,42,47,45,42,44,48,49,48,47 49,47,41,45,48,41,48,41,42,47,49,49,48, 50.47.49.48.46.44.45.45.46.44.42.47.48.45 ow answer the following questions: a) b) c) d) e) Find the number of students getting more than 45 marks. Find the number of students getting less than 45 marks. Find the maximum number of students getting the same marks. Find the average marks obtained by the students in the class. Find the number of students getting more than average marks.
a) To find the number of students getting more than 45 marks, we count the students whose marks are greater than 45 in the given list.
In the given list, the students with marks greater than 45 are: 50, 49, 47, 48, 49, 48, 47, 49, 48, 50, 47, 49, 48, 46, 47, 48, 47.
Counting these numbers, we find that there are 17 students who obtained more than 45 marks.
b) To find the number of students getting less than 45 marks, we count the students whose marks are less than 45 in the given list.
In the given list, the students with marks less than 45 are: 44, 44, 42, 41, 41, 42, 41, 44, 44, 42, 45, 45, 45, 44, 45.
Counting these numbers, we find that there are 15 students who obtained less than 45 marks.
c) To find the maximum number of students getting the same marks, we look for the mark that appears most frequently in the given list.
In the given list, the marks obtained by the students are: 44, 50, 44, 49, 42, 47, 45, 42, 44, 48, 49, 48, 47, 49, 47, 41, 45, 48, 41, 48, 41, 42, 47, 49, 49, 48, 50, 47, 49, 48, 46, 44, 45, 45, 46, 44, 42, 47, 48, 45.
Counting the frequency of each mark, we find that the marks 47 and 48 appear most frequently, with a count of 6 each. Therefore, the maximum number of students getting the same marks is 6.
d) To find the average marks obtained by the students in the class, we sum up all the marks and divide by the total number of students.
Total marks = 44 + 50 + 44 + 49 + 42 + 47 + 45 + 42 + 44 + 48 + 49 + 48 + 47 + 49 + 47 + 41 + 45 + 48 + 41 + 48 + 41 + 42 + 47 + 49 + 49 + 48 + 50 + 47 + 49 + 48 + 46 + 44 + 45 + 45 + 46 + 44 + 42 + 47 + 48 + 45
= 1912
Total number of students = 40
Average marks = Total marks / Total number of students
= 1912 / 40
= 47.8
Therefore, the average marks obtained by the students in the class is 47.8.
e) To find the number of students getting more than the average marks, we count the students whose marks are greater than 47.8.
In the given list, the students with marks greater than 47.8 are: 50, 50, 49, 48, 49, 48, 49, 48, 50, 49, 49, 48, 48, 50, 49, 49, 48, 48, 47, 49, 49, 48, 50, 47,
49, 49, 48, 50, 47, 49, 49, 48, 48, 49, 48, 47, 48, 49, 49, 48, 50, 49.
Counting these numbers, we find that there are 40 students who obtained more than the average marks.
Find all values of n for which the equation has two complex (non-real solutions)
6r² = 8r+ (n + 4)
Answer:
When n < - 6 2/3 the given equation has two complex solutions------------------------------
Given is a quadratic equation:
6r² = 8r+ (n + 4) ⇒ 6r² - 8r - (n + 4) = 0A quadratic equation has no real solutions if its discriminant is negative.
The discriminant of ax² + bx + c is:
D = b² - 4acApply to given equation:
D = (-8)² - 4*6*( - (n + 4)) = 64 + 24(n + 4) = 64 + 24n + 96 = 24n + 160Find the value of n when D < 0:
24n + 160 < 024n < - 160n < - 160/24 n < - 20/3 n < - 6 2/3A straight railway track passes through the coordinates (8, 3) and (12, 1). What is the
slope of the line for the path the track?
(2 points-1 point showing work, 1 point correct slope)
Answer:
\(-\dfrac{1}{2}\)
Step-by-step explanation:
Slope Formula
\(\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}\)
Where (x₁, y₁) and (x₂, y₂) are points on the line.
Given points:
(x₁, y₁) = (8, 3)(x₂, y₂) = (12, 1)Substitute the given points into the formula and solve for m:
\(\implies \textsf{slope}\:(m)=\dfrac{1-3}{12-8}=\dfrac{-2}{4}=-\dfrac{1}{2}\)
Therefore, the slope of the line for the path of the track is -¹/₂.
5 1
1)
4 3
What is the anwser
P is the point (2, 5) and Q is the point (6, 0).
A line l is drawn through P perpendicular to PQ to meet the y-axis at the point R. Find the coordinates of the point R.
The coordinates of the point R: (0, 3.4)
What is the slope?
In mathematics, the slope or gradient of a line is a number that describes both the direction and the steepness of the line
Slope PQ 5–0/ 2–6 = 5 /-4
equation of PQ y =-5/4 x +c ;
this passing through 2,5
5 =-5/4*2 +c ; C = 5 -5/2 =5/2
y =-5x/4+5/2 =-5x+10/4 ; 4y =-5x +10 ;
equation of PQ =5x +4y-10 =0 ;
slope of PR : m1 *m2 =-1 ;m2 = -1/ [-5/4 ] = 4/5
equation of PR y = mx +c this passes through [2,5]
5 = 4/5*2 +C so C = 5- 8/5 =17/5
y =4 x /5 +17/5 so coordinates of R = [0, 3.4]
Hence, the coordinates of the point R: (0, 3.4)
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Someone please please help me with this!!!
Answer:
\(4x {}^{2} - 36 \\ = (2x + 6)(2x - 6) \\ hence \: option \: b \: is \: correct\)
Person 1, person 2, and person 3 paid a total of $120 for lunch. They split the money respectively using the ratio 1:2:3. How much more did person 3 pay than person 2?
Person 3's payment exceeded person 2's payment by $20.
To find out how much more person 3 paid than person 2, we need to calculate the amounts each person paid based on the given ratio and then compare their payments.
The ratio given is 1:2:3, which means that person 1 gets 1 part, person 2 gets 2 parts, and person 3 gets 3 parts of the total amount.
Step 1: Calculate the total number of parts in the ratio.
1 + 2 + 3 = 6
Step 2: Determine the value of one part.
$120 (total amount) divided by 6 (total number of parts) = $20
Step 3: Calculate the payments for each person based on the ratio.
Person 1: 1 part * $20 = $20
Person 2: 2 parts * $20 = $40
Person 3: 3 parts * $20 = $60
Therefore, person 3 paid $60, while person 2 paid $40. To find out how much more person 3 paid than person 2, we subtract the amount person 2 paid from the amount person 3 paid:
$60 - $40 = $20
Hence, person 3 paid $20 more than person 2.
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what is the slope?
First, determine the slope.
(200,14)
(225,16)
Answer:
\(\displaystyle m=\frac{2}{25}\)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Slope Formula: \(\displaystyle m=\frac{y_2-y_1}{x_2-x_1}\)Step-by-step explanation:
Step 1: Define
Point (200, 14)
Point (225, 16)
Step 2: Find slope m
Simply plug in the 2 coordinates into the slope formula to find slope m
Substitute in points [SF]: \(\displaystyle m=\frac{16-14}{225-200}\)[Fraction] Subtract: \(\displaystyle m=\frac{2}{25}\)
Los organizadores de la Feria de Alimentos colocan un contenedor de agua que mide 2,76 metros de largo, por 23,5 decímetros de ancho y por 196 centímetros de alto. ¿Cuál es el volumen del contenedor? Expresa la respuesta en metros cúbicos con aproximación a centésimos.
The volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.
To find the volume of the container, we need to multiply its length, width, and height. Let's convert the given measurements to meters to ensure consistent units.
The length of the container is 2.76 meters.
The width of the container is 23.5 decimeters, which is equal to 2.35 meters (since 1 decimeter = 0.1 meters).
The height of the container is 196 centimeters, which is equal to 1.96 meters (since 1 meter = 100 centimeters).
Now we can calculate the volume of the container:
Volume = Length × Width × Height
Volume = 2.76 meters × 2.35 meters × 1.96 meters
Volume ≈ 12.9516 cubic meters (rounded to four decimal places)
Therefore, the volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.
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Imagine a clock with the hour hand at 12 and the minute hand at 2. Does the angle formed by the two hands have a measure greater than, less than, or equal to 1/4 turn?
The angle formed by the two hands have a measure less than 1/4 turn
How to relate the measure of the angle to 1/4 turn?From the question, we have the following parameters that can be used in our computation:
A clock with the hour hand at 12 and the minute hand at 2
The turn represented by the above is represened as
Turn = (2 * 30)/360
When simplified, we have
Turn = 1/6
Next, we have
Angle at the turn = 1/4
1/6 is less than 1/4
This means that the angle formed by the two hands have a measure less than 1/4 turn
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find the exact value of cos(7\pi /12)
7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.
Recall that
\(\cos^2x=\dfrac{1+\cos(2x)}2\)
which tells us
\(\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1+\cos\left(\frac{7\pi}6\right)}2}\)
Now,
\(\cos\left(\dfrac{7\pi}6\right)=-\cos\left(\dfrac\pi6\right)=-\dfrac{\sqrt3}2\)
and so
\(\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1-\frac{\sqrt3}2}2}=\boxed{-\dfrac{\sqrt{2-\sqrt3}}2}\)
On average, teens spend 4 hours a week using the Internet and 4 hours doing chores. They spend 10 hours listening to the radio. What percent of the total time teens spend using the Internet and doing chores is the time they spend listening to the radio?
The percent of the total time teens spend using the Internet and doing chores is the time they spend listening to the radio is 55.56%.
How the percentage is calculatedTime spent using the internet = 4 hours
Time spent doing chores = 4 hours
The time spent listening to the radio = 10 hours
The total time spent during the week is 4 + 4 + 10 = 18 hours
The percentage of this total time that is spent listening to the radio is:
(10 hours / 18 hours) x 100% =55.56%
This is basic arithmetic operations and is used in calculation of numbers.
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Twenty four blood samples were selected by taking every seventh blood sample from racks holding 199 blood samples from the morning draw at a medical center ANSWER BOTH A AND B
a. FPCF for this sample is FPCF = √(199/24) = 2.89.
b. The population cannot be considered effectively infinite, so the answer is no.
What is FPCF?When the sample size is significant compared to the size of the community, the Finite Population Correction Factor, also known as the FPC factor, is applied. The population in most cases is so vast that typical sample sizes are insufficient to raise concerns about the need for the FPC.
The recommendation is to use the FPC when the sample size to population size ratio is higher than 5%. The FPCF must be used, for instance, if the population number is 300 and the sample size is 30, which results in a ratio of 10%.
a. To calculate the FPCF (finite population correction factor) for this sample, we can use the formula:
FPCF = √(N/n)
where N is the population size, and n is the sample size.
In this case, N = 199 (the number of blood samples in the racks), and n = 24 (the number of samples selected every seventh blood sample).
FPCF = √(199/24) = 2.89 (rounded to two decimal places)
b. To determine whether the population should be considered effectively infinite, we need to compare the sample size to the population size. A general rule of thumb is that the population can be considered effectively infinite if the sample size is less than 5-10% of the population size.
In this case, the sample size is 24, which is approximately 12% of the population size of 199. Therefore, the population cannot be considered effectively infinite, and the FPCF should be applied to adjust for the finite population size.
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The changes in housing prices over short time periods are in part determined by supply and demand. A real estate company in Minnesota projected an increase in its average selling prices of homes in the first quarter of 2014 over the mean 2013 selling price of $201,800. The reason for the projection was an increase in demand due to business expansion and the subsequent increase in labor. To investigate the accuracy of the projection, a sample of homes in the first quarter of 2014 was selected and the following selling prices (in $) recorded:
235,000 271,900 183,300 203,000 182,900 225,500 189,000 214,200 237,900 233,500 217,000 230,400 202,950, 216,500 209,900, 245,500
Required:
a. At 5% level of significance, is there sufficient evidence to support the real estate company's projection?
b. Which statistical distribution should be applied in this situation and why? Explain carefully.
c. Discuss the consequences of Type I and Type II errors in terms of the problem.
d. Does the management at the real estate company want a small or large value of the significance level? Explain carefully.
e. Based on a 95% confidence level, estimate the actual average selling price homes in the first quarter of 2014.
Answer:
The data given is
235,000 271,900 183,300 203,000 182,900 225,500 189,000 214,200 237,900 233,500 217,000 230,400 202,950, 216,500 209,900, 245,500
The sample size is n = 16
The population is \(\mu = \$201,800\)
The sample mean is mathematically represented as
\(\= x =\frac{\sum x_i}{n}\)
=> \(\= x =\frac{235,000 + 271,900 + \cdots + 245,500 }{16}\)
=> \(\= x = 218653.125\)
Generally the sample standard deviation is mathematically represented as
\(s = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }\)
=> \(s = \sqrt{\frac{ (235,000 - 218653.125)^2+ (271,900 - 218653.125)^2 + \cdots + (245,500 - 218653.125)^2}{16} }\)
=> \(s = 23946.896 \)
The null hypothesis is \(H_o : \mu = \$201,800\)
The alternatively hypothesis is \(H_o : \mu > \$201,800 \)
Generally the test statistics is mathematically represented as
\(t = \frac{\= x - \mu }{ \frac{s}{\sqrt{n} } }\)
=> \(t = \frac{218653.125 - 201800 }{ \frac{23946.896 }{\sqrt{16} } }\)
=> \(t = 2.82\)
Generally the degree of freedom is mathematically represented as
\(df = n - 1\)
=> \(df = 16 - 1\)
=> \(df = 15\)
Generally the probability of \(t = 2.82\) at a degree of freedom of \(df = 15\) from the t - distribution table is
\(p-value = P( t >2.82 ) =0.00646356\)
The
From the values obtained we see that \(p-value < \alpha\)
The decision rule is
Reject the null hypothesis
The conclusion is
There is sufficient evidence to conclude that the real estate company's projection is true
Given that the population variance is unknown then the best statistical distribution to be applied is the t -distribution
Type I Error
The type 1 error occur when the null hypothesis is wrongfully rejected
The consequence in this case is the company will assume that the average selling price has increase and this will lead the company to start expanding the business while in the real sense the average selling price is still $201,800
Type II Error
The type 11 error occur when the null hypothesis is wrongfully accepted(i.e wrongfully failed to reject the null hypothesis)
The consequence in this case is that the company will assume that the average selling price is still $201,800 and will not make plans to increase the business while in the real sense the average selling price has increased
Given that resource is scare the management of the company will want a smaller significance level in order not to commit type I error which will lead to wrongly expanding the business and wastes of resources
generally the critical value of \(\frac{\alpha }{2}\) from the normal distribution table is
\(Z_{\frac{\alpha }{2} } = 1.96\)
Generally the margin of error is mathematically represented as
\(E =Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }\)
=>\(E =1.96* \frac{23946.896}{\sqrt{16} }\)
=>\(E = 11733.96\)
Generally the 95% confidence interval is mathematically represented as
\(218653.125 - 11733.96 < \mu < 218653.125 + 11733.96\)
=> \(206919.165 < \mu < 230387.085\)
Generally there is 95% confidence that the actual average selling price is within this interval
Step-by-step explanation:
A spherically shaped hot air balloon has a
diameter of about 27 meters when fully inflated.
What is the volume of the hot air balloon when it
is fully inflated?
Answer: 7725.5775
Step-by-step explanation:
d=27
r=d/2=27/2=13.5
the volume of the spherical balloon= 3.14*r^3
= 3.14*(13.5)^3
= 7725.5775
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хY у-1-30-333315,Find a quadratic function to model the values in the table.y-2x2 + 3x + 2y--3-3-3y-3x + 3x - 3y--2x - 3x+ 3
The answer is b
it satisfies all the given x,y values
when x=0
its give y=-3
when x=-1
it gives y=-3
so it satisfies the condition'
so the answer is B
question 13Consider the following data: 12, 15, 13, 10, 15, 10. Answer the following questicwrite final answers only. [T/I - 4]#1) What is the mean of the data?#2) What is the median of the data?#3) What is the mode of the data?#4) What is the range of the data?
Solution:
Given:
The data;
\(12,15,13,10,15,10\)Question 1:
To get the mean:
The mean of a set of numbers, sometimes simply called the average, is the sum of the data divided by the total number of data.
\(\begin{gathered} \text{Mean}=\frac{\text{ sum of data}}{n\text{ umber of data}} \\ \text{Mean}=\frac{12+15+13+10+15+10}{6} \\ \text{Mean}=\frac{75}{6} \\ \text{Mean}=12.5 \end{gathered}\)Therefore, the mean is 12.5
Question 2:
To get the median:
The median of a set of numbers is the middle number in the set (after the numbers have been arranged from least to greatest)
If there is an even number of data, the median is the average of the middle two numbers.
\(\begin{gathered} R\text{ earranging the data given in rank order,} \\ 10,10,12,13,15,15 \end{gathered}\)
The data indicates an even number of data. There are 6 numbers in the set.
Hence, the median is the mean of the middle two numbers.
\(\begin{gathered} \text{The middle two numbers are;} \\ 12\text{ and 13} \\ \text{Hence, the median is the mean of 12 and 13} \\ \text{Median}=\frac{12+13}{2} \\ \text{Median}=\frac{25}{2} \\ \text{Median}=12.5 \end{gathered}\)Therefore, the median is 12.5
Question 3:
To find the mode:
The mode of a set of numbers is the number that occurs the most. Hence, the mode of a set of numbers is the number with the highest frequency.
If a set of data has two modes, the data is said to be bimodal.
\(\begin{gathered} 10,10,12,13,15,15 \\ \\ \text{From the above, 10 appears twice} \\ 15\text{ also appears twice} \\ \\ \text{Hence, the mode is 10 and 15. The data has two modes, it is a bimodal data.} \end{gathered}\)
Therefore, the modes are 10 and 15.
Question 4:
The range is the difference between the highest and lowest values in a set of numbers.
\(\begin{gathered} 10,10,12,13,15,15 \\ \text{Lowest number=10} \\ \text{Highest number=15} \\ \\ \text{Hence, range=highest number-lowest number} \\ \text{Range}=15-10 \\ \text{Range}=5 \end{gathered}\)Therefore, the range is 5.
Find the value of n for which the division of x^2n-1 by x+3 leave remainder of -80.
The value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80 is n = 1.
To find the value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80, we can use polynomial long division. Let's perform the division step by step:
Write the dividend and divisor in polynomial long division format:
_________________________
x + 3 │ x^(2n-1) + 0x^(2n-2) + 0x^(2n-3) + ...
Divide the leading term of the dividend (x^(2n-1)) by the leading term of the divisor (x). The result is x^(2n-1)/x = x^(2n-2).
Multiply the divisor (x + 3) by the quotient obtained in the previous step (x^(2n-2)). The result is x^(2n-2) * (x + 3) = x^(2n-1) + 3x^(2n-2).
Subtract the result obtained in step 3 from the original dividend:
x^(2n-1) + 0x^(2n-2) + 0x^(2n-3) + ... - (x^(2n-1) + 3x^(2n-2)) = -3x^(2n-2) + 0x^(2n-3) + ...
Bring down the next term of the dividend (which is 0x^(2n-3)) and repeat steps 2-4 until the remainder is constant.
Since we are given that the remainder is -80, we can set the remainder equal to -80 and solve for 'n'.
-3x^(2n-2) + 0x^(2n-3) + ... = -80
Since the remainder is constant (-80), it means that all the terms with x have been canceled out in the division process. Therefore, we can deduce that the highest power of x in the divisor (x + 3) is 0.
This implies that x^(2n-2) = 0, and for any value of 'n', the exponent 2n-2 should be equal to zero. Solving this equation:
2n-2 = 0
2n = 2
n = 1
Therefore, the value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80 is n = 1.
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Write the equation of the line that passes through the points (-3,-1) and (5, -1).
Put your answer in fully simplified point-slope form, unless it is a vertical or
horizontal line
The equation of line passes through the points (-3, -1) and (5, -1) will be;
⇒ y = - 1
What is Equation of line?The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
Two points on the line are (-3, -1) and (5, -1).
Now,
Since, The equation of line passes through the points (-3, -1) and (5, -1)
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (- 1 - (-1)) / (5 - (-3))
m = 0/8
m = 0
Thus, The equation of line with slope 0 is,
⇒ y - (-1)= 0 (x - (-3))
⇒ y + 1 = 0
⇒ y = - 1
Therefore, The equation of line passes through the points (-3, -1) and (5, -1) in slope intercept form is,
⇒ y = - 1
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A box contains 3 defective batteries and 7 good ones. You reach in and pull out three
batteries. What is the expected number of defective batteries?
Answer:
The expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.
Step-by-step explanation:
Given that a box contains 3 defective batteries and 7 good ones, and I reach in and pull out three batteries, to determine what is the expected number of defective batteries, the following calculation must be performed:
3 + 7 = 100
3 = X
10 = 100
3 = X
3 x 100/10 = X
300/10 = X
30 = X
3 x 3/10 = X
0.9 = X
Therefore, the expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.
1. The slant height of a cone is 5cm and the radius of its base is 3cm. Find correct to the nearest
whole number the volume of the cone (A) 48cm3 (B) 47cm3 (C) 38cm3 (D)13cm3
The volume of the cone is 13 cm³. option D
How to determine the volumeTo determine the volume of the cone, we have that;
The formula for calculating the volume of a cone is expressed as;
Volume = (1/3)πr ²√(L ² - r ²).
Such that;
r is the radiusL is the slant heightSubstitute the values, we have;
Volume = 1/3 × 3.14 ² × √(25 - 9)
Find the squares, we get;
Volume, V = 1/3 × 9. 86 × √16
Find the square root
Volume, V = 1/3 × 9.86 × 4
Volume, V = 13 cm³
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How much more would the value of y be on the graph than its value in the table when x = 12?
Answer:
Y = 20x so the answer is 20
Step-by-step explanation:
What is the area of
the segment? Express
the answer in terms
of pi.
The area of the segment is 9( π-2) units²
What is area of segment?The area of a figure is the number of unit squares that cover the surface of a closed figure.
A segment is the area occupied by a chord and an arc. A segment can be a major segment or minor segment.
Area of segment = area of sector - area of triangle
area of sector = 90/360 × πr²
= 1/4 × π × 36
= 9π
area of triangle = 1/2bh
= 1/2 × 6²
= 18
area of segment = 9π -18
= 9( π -2) units²
therefore the area of the segment is 9(π-2) units²
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Which property is illustrated by the equation 3 (m n) = (3 m) n?
associative property
commutative property
distributive property
identity property
Answer:
a...
associative property
Step-by-step explanation:
trust me
Answer:
it is A.
Step-by-step explanation:
hope this helps!
Help solve these 2 step by step.
The area of the shaded region in each of the shapes are:
10) 16.324 ft²
11) 114.546 cm²
What is the area of the shaded region?10) The formula for the area of a circle is:
A = πr²
where:
r is radius
Thus;
A_c = π * 4²
A_c = 50.265 ft²
Area of a hexagon inscribed in a circle is:
A_h = ((3√3)/2) * r²
A_h = ((3√3)/2) * 4²
A_h = 33.941 ft²
Area of shaded region = 50.265 ft² - 33.941 ft²
= 16.324 ft²
11) Area of a hexagon with side length has the formula:
A_h = 2(1 + √2)a²
where a is the length of one side. Thus:
A_h = 2(1 + √2) * 9²
A_h = 391.103 cm²
The interior angle of a regular octagon is 135°.
Using sine rule, we can find the length of the square:
9/sin 22.5 = x/sin 135
x = 16.63 cm
Area of square = 16.63 * 16.63
= 276.557 cm²
Area of shaded region = 391.103 - 276.557
Area of shaded region = 114.546 cm²
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The coordinates of the point � G are ( 0 , 8 ) (0,8) and the coordinates of point � H are ( 8 , 8 ) . (8,8). What is the distance, in units, between the point � G and point � ? H?
The distance between the points G and H is D = 8 units
Given data ,
Let the distance between 2 points be represented as D
Now , let the first point be G ( 0 , 8 )
Let the second point be H ( 8 , 8 )
Now , let the distance between G and H be D , where
D = √( ( x₂ – x₁ )² + ( y₂ – y₁ )²)
D = √ ( 0 - 8 )² + ( 8 - 8 )²
D = √64 units
D = 8 units
Hence , the distance is 8 units
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The mean height of the students in a class is 152 cm. The mean height of boys is 158 cmwith a standard deviation of 5 cm. And the mean height of girls is 148 cm with a standarddeviation of 4 cm. Find the percentage of boys in the class and also the S.D of heights of allthe students in the class?
The percentage of boys in the class and also the standard deviation of heights of all the students in the class are 78% and 9 cm respectively
How to find the percentage of boys in the class?Percentage of the boys in the class deals with a ratio of the boys to the number of students in the class
The given parameters that will help us to get the percentage are
Mean height of the class = 152 cm
Mean height of the boys = 158 cm
The standard deviation of the boys = 5 cm
Mean height of the girls = 148 cm
Standard deviation of the girls = 4 cm
(1) The percentage of boys in the class is
Total mean height = 158 +148 = 306
Percentage = 158/306 * 100 = 51.6%
Then the percentages 51.6/100 * 152 = 78%
(2) The total standard deviation of all the students
Boys + girls = 5+4 = 9 cm
Therefore, the percentage of boys in the class and also the standard deviation of heights of all the students in the class are 78 students and 9 cm respectively
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I need help anyone know what this is?
Answer:
∠\(ACD=60\)° or B
Step-by-step explanation:
\(110+120+70= 300\)
\(360-300=60\)
Answer:
B 60
Step-by-step explanation:
Do not let all the extra triangles on the outside trip you out. The shape is a trapezoid which total should equal 360. Add all the angles up and subtract from 360 to get 60
Hope this Helps :)