Write an equal ratio for the fraction 5/7

Answer:

2762.5

Step-by-step explanation:

The equation of the line with a slope of 1 passing through the point (0, 2) is y = x + 2.

To verify this, we can substitute the coordinates of the given point (0, 2) into the equation y = x + 2:

2 = 0 + 2

This equation holds true, confirming that the line y = x + 2 passes through the point (0, 2) and has a slope of 1.

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Answer:

25

Step-by-step explanation:

a=15

2(15)-5=25

30-5=25

Answer:

25

Step-by-step explanation:

The problem substituting a for 15 would be 2(15)-5

2*15 is 30, then -5 is 25.

To approximate the integral ∫2.4 to 2 f(x) dx using Simpson's rule, we divide the interval [2, 2.4] into subintervals and approximate the integral within each subinterval using quadratic polynomials.

Given the data points (x, f(x)) = (2, 0.6931), (2.2, 0.7885), and (2.4, 0.8755), we can use Simpson's rule to approximate the integral.

Step 1: Determine the step size, h.

Since we have three data points, we can divide the interval [2, 2.4] into two subintervals, giving us a step size of h = (2.4 - 2) / 2 = 0.2.

Step 2: Calculate the approximations within each subinterval.

Using Simpson's rule, the integral within each subinterval is given by:

∫f(x)dx ≈ (h/3) * [f(x₀) + 4f(x₁) + f(x₂)]

where x₀, x₁, and x₂ are the data points within each subinterval.

For the first subinterval [2, 2.2]:

∫f(x)dx ≈ (0.2/3) * [f(2) + 4f(2.1) + f(2.2)]

≈ (0.2/3) * [0.6931 + 4(0.7885) + 0.8755]

For the second subinterval [2.2, 2.4]:

∫f(x)dx ≈ (0.2/3) * [f(2.2) + 4f(2.3) + f(2.4)]

≈ (0.2/3) * [0.7885 + 4(0.4545) + 0.8755]

Step 3: Sum up the approximations.

To obtain the approximation of the total integral, we sum up the approximations within each subinterval.

Approximation ≈ (∫f(x)dx in subinterval 1) + (∫f(x)dx in subinterval 2)

Calculating the values, we get the final approximation of the integral ∫2.4 to 2 f(x) dx using Simpson's rule.

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Based on the information given, we can assume that the population of all measurements of the same liquid has a Normal distribution with a mean of 5 and a standard deviation of 0.2.

The 6 measurements obtained can be used to estimate the true conductivity of the liquid.

The given measurements can be used to estimate the true conductivity of the standard liquid by calculating the sample mean and standard deviation. The sample mean is calculated as the average of the given measurements, which in this case is 5.02.

The sample standard deviation is calculated as 0.223. Since the standard deviation of the population is known to be 0.2, we can use a t-test or a z-test to determine if the sample mean is significantly different from the true mean of 5.

Based on the sample mean and standard deviation, we can also calculate a confidence interval for the true conductivity of the liquid. The confidence interval gives us an idea of the range of values that the true conductivity is likely to fall within, based on the given measurements.

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Answer:

48160

Step-by-step explanation:

Answer:

It's: A

Step-by-step explanation:

Answer: 45 / 40 ft

Step-by-step explanation:

Given that She decides to change the width, the shorter side of the courtyard, from 45 ft to 40 ft. Which expression finds the change in the scale factor?

Actual width of shorter side = 45 ft

New width of shorter side = 40 ft

Scale factor is the ratio of the actual length to the new or intended length

Scale factor = Actual width / New width

Hence, scale factor :

45 ft / 40 ft

Answer:

For the first picture, I think it is C and the second one should be A.

Step-by-step explanation:

You use vertical lines and if it hits it multiple times it is not a function. Like if it hits two dots or something it is not a function. I hope that make sense, let me know if it doesn't.

Solution:

From the given table;

Where, the November values is used as 100 percent;

To find the missing percentages of Elm leaves

For the month of May

To find the missing percentages of Hazel leaves

What is the independent and dependent variable?

An independent variable is a variable that does not depend on any other variable.

For example,

x is an independent variable because for every value of x, there is a different value of y

A dependent variable is a variable whose value depends upon an independent variable.

For example;

From the expression above, the value of y depends on the value of x

For a series S, let S=1−19+12−125+14−149+18−181+116−1121+⋯+an+⋯

Both statements I and III are true.

I. S converges because the terms of S alternate and limn→∞ an = 0: In the given series S, the terms alternate between positive and negative values. Additionally, as n approaches infinity, the terms an approach zero. This condition satisfies the alternating series test, which states that if a series alternates in sign and the absolute values of the terms approach zero as n approaches infinity, then the series converges. Therefore, statement I is true.

III. S converges although it is not true that |an+1| < |an| for all n: The convergence of a series depends on the behavior of the terms as a whole rather than the strict inequality |an+1| < |an| for all n. While the given series does not satisfy the condition |an+1| < |an| for all n, it can still converge if the alternating sign pattern and the limit of the terms approaching zero hold. Therefore, statement III is also true.

Statement II is false because it assumes that for a series to diverge, it is necessary for |an+1| to be strictly greater than |an| for all n. However, this is not a universal condition for divergence. There are cases where a series may diverge even if |an+1| < |an| for all n.

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Answer:

Option A. (-400)

Step-by-step explanation:

Graph attached shows the sales of the concert tickets.

We choose the two points through which the given line is passing,

Let the two points are (0, 4000) and (10, 0)

Slope of a line = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

                        = \(\frac{4000-0}{0-10}\)

                        = -400

Therefore, slope of the line graphed has the slope = -400

Option (A) will be the answer.

Answer:

a. -400

Step-by-step explanation:

got it correct!

Step-by-step explanation:

biểu thức ở đâu?

bạn thực sự cần đặt một biểu thức để tôi có thể giải quyết

The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4

\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5

\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls. The calculation results in approximately 0.369, or 36.9%.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

[P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

[P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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since the diameter is 66 cm, then its radius is half that or 33 cm.

\(\textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=33\\ \underset{complete~turn}{\theta =2\pi ~\hfill } \end{cases}\implies s=(33)(2\pi )\implies s=66\pi \implies s\approx 207.34~cm\)

Answer:

x = 0

y = 2

Step-by-step explanation:

We can find the value of y using the steps on the image

Then we will use that to find x

2x + 3y = 6 replace y with 2

2x + 3*2 = 6

2x + 6 = 6 subtract 6 from both sides

2x = 0 and x = 0

Answer:

miles is the answers for the question

Step-by-step explanation:

please mark me as brainlest

Answer:

\(y = \frac{1}{4} x - 3\)

Answer:

y = 1/4x -3

Step-by-step explanation:

Answer:

uhm 0 degrees

Step-by-step explanation:

The value of the inverse trigonometric expression sin⁻¹(sin 17°) will be 17°.

Simply put, inverse trigonometric operations are the opposites of the fundamental trigonometric parameters sine, cosine, secant, cosecant, tangent, and cotangent.

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The inverse trigonometric expression is given below.

⇒ sin⁻¹(sin 17°)

We know that the value of sin⁻¹(sin θ) is θ.

Then the value of the inverse trigonometric expression will be

⇒ sin⁻¹(sin 17°)

⇒ 17°

Thus, the value of the inverse trigonometric expression sin⁻¹(sin 17°) will be 17°.

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The value of the triple integral is (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)] where E is bounded by the parabolic cylinder z=16−y2z=16−y2 and the planes z=0,x=4, and x=−4.

To evaluate the triple integral ∭E \(x^8 e^y\) dV, where E is bounded by the parabolic cylinder z=16−y² and the planes z = 0,x = 4, and x = −4, we can use the cylindrical coordinate system. Here are the steps to solve the integral:

Write down the limits of integration for each variable:

For ρ, the radial distance from the z-axis, the limits are 0 to 4.

For φ, the angle in the xy-plane, the limits are 0 to 2π.

For z, the height, the limits are 0 to 16 - y² for the parabolic cylinder, and 0 to the plane z = 0.

Write the integral using cylindrical coordinates:

∭E \(x^8 e^y\) dV = ∫\(0^4\) ∫0²π ∫\(0^{(16-y^2)\) (\(\rho^9\) \(cos^8\) φ) (\(e^y\)) ρ dρ dφ dz

Evaluate the integral:

∫0²π ∫\(0^4\)(16-y²) (\(\rho^9\) \(cos^8\) φ) (\(e^y\)) ρ dρ dφ dz

= ∫\(0^4\) ∫0²π (\(cos^8\) φ) dφ ∫\(0^{(16-y^2)}\)(\(\rho^{10\) \(e^y\)) dρ dz

= ∫\(0^4\) ∫0²π (\(cos^8\) φ) [\((16-y^2)^{11}\) / 11 \(e^y\)] dy dφ

= ∫\(0^4\) ∫0²π (\(cos^8\) φ) [(\(16^{11}\) / 11) \(e^y\) - (11/11) y² (\(16^{10}\)) \(e^y\) + (55/11) \(y^4\) (\(16^9\)) \(e^y\) - ...] dφ

= ∫\(0^4\) (\(16^{11}\) / 11) \(e^y\) [(\(cos^8\) φ) (2π)] dy

= (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)]

Therefore, the value of the triple integral is (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)].

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Answer:

6x-2(x+1) > 0

6x -2x -2 > 0

4x - 2 > 0

4x > 2

x > 1/2

Answer:

Let's call the cost of a blouse "b" (in dollars). Then, according to the problem, the cost of a dress is 3/4 of the cost of a blouse, or (3/4)b.

We know that Vicky paid $350 for 3 dresses and 4 blouses, so we can set up the equation:

3(3/4)b + 4b = 350

Simplifying this equation, we get:

9/4 b + 4b = 350

Combining like terms, we get:

17/4 b = 350

To solve for b, we can multiply both sides by 4/17:

b = 350 × 4/17 = $82.35 (rounded to two decimal places)

Therefore, the cost of a dress is:

(3/4)b = (3/4)($82.35) = $61.76 (rounded to two decimal places)

So each dress cost $61.76.

3) Perpendicular lines form right angles

4) \(\angle AXP \cong \angle AXQ\)

6) SAS

7) CPCTC

The expression ((t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9) can be written in terms of product notation as Π⁷k=1 \((t^k - 9)\).

As per the question, we can write the expression as:

(t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9)

Using product notation, we can write this as:

Π⁷k =1 \((t^k - 9)\)

where Π represents the product of terms, k is the index of the product, and the subscript 7 indicates that the product runs from k = 1 to k = 7.

Therefore, the expression ((t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9) can be written in terms of product notation as Π⁷k=1 \((t^k - 9)\).

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We have that BC = BA and m

We will have that the angle DAB and BAC are supplementary, therefore:

DAB + BAC = 180°

And replecing the value of DAB, we will get:

120 + BAC = 180 => BAC = 60.

By theorem the angles that oppose equal sides are equal, therefore: ACB = 60.

From this, we will also get that ABC = 60.

And B = 90.

Triangle ABD will be a scalene triangle.

Triangle DBC will be a rectangle triangle.

Answer:

There are two possibilities of determine which solution is the smallest one:

(i) The smallest solution is the value of \(x\) has the smallest distance with respect to origin: \((x_{2},y_{2}) = (0.18,0)\)

(ii) The smallest solution is the most negative value: \((x_{1},y_{1}) = (-1.577,0)\)

Step-by-step explanation:

Let \(f(x) = g(x)\), \(f(x) = \ln (x+5)-1\) and \(g(x) = x^{3}-2\cdot x + 1\), then we have the following implicit equation:

\(\ln (x+5)-x^{3}+2\cdot x -2 = 0\) (1)

This equation cannot be solved by analytical means. There are two different strategies to solve this expression: (i) Numerical methods, (ii) Graphical methods. We decide to use the second method:

Let suppose that we use this function \(h(x) = \ln (x+5) -x^{3}+2\cdot x - 2\). By the help of a graphing tool, we find the smallest solution such that \(h(x) = 0\). There are three possible solutions: \((x_{1},y_{1}) = (-1.577,0)\), \((x_{2},y_{2}) = (0.18,0)\), \((x_{3}, y_{3}) = (1.376, 0)\)

There are two possibilities of determine which solution is the smallest one:

(i) The smallest solution is the value of \(x\) has the smallest distance with respect to origin: \((x_{2},y_{2}) = (0.18,0)\)

(ii) The smallest solution is the most negative value: \((x_{1},y_{1}) = (-1.577,0)\)

The smallest smallest solution of f(x) = g(x) will be \(\rm \left(-1.577,0.223\right)\)

A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.

Given functions;

f(x) = ln(x + 5) – 1

g(x) = x³ – 2x + 1

After graphing both the function, we get the three solutions of the given equation,

\(\rm \left(-1.577,0.223\right)\)

\(\left(0.18,0.645\right)\)

\(\left(1.376,0.853\right)\)

Hence,the smallest smallest solution of f(x) = g(x) will be \(\rm \left(-1.577,0.223\right)\)

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Therefore , the solution of the given problem of standard deviation comes out to be the CEO is informed that the mean scores for Cities A and B are identical.

Variance is a measure of difference used in statistics. The typical variance here between dataset and the mean is calculated using the multiplier of that figure. By comparing each figure to the mean, it incorporates those data points into its calculations, unlike other measurable measures of variability. Variations may result from internal or external factors and may include unintentional errors, inflated expectations, and changing economic or commercial circumstances.

Here,

It is clear that both offices share a comparable average score from the sentence "The CEO is informed that both City A or City B have the same mean score."

If City A is more reliable than City B, then City A will have a lower standard deviation.

A collection of data's variability or dispersion is measured by the standard deviation. The closer the data points are to the mean, the lower the standard deviation, and the less variable the data are.

So, the appropriate answer is:

The CEO is informed that the mean scores for Cities A and B are identical. However, due to the fact that City A's standard deviation is lower than City B's, City A is more reliable than City B.

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YOUR ANSWER IS ANGLE BAC