write a statement that assigns the array variable numpizzas to the solution of the system of equations in terms of variables amat and bvec.

Answers

Answer 1

To write a statement that assigns the array variable `numpizzas` to the solution of the system of equations in terms of variables `amat` and `bvec`, we first need to understand how to solve a system of linear equations using matrix operations.

Let's assume `amat` is a matrix containing the coefficients of the system of equations, and `bvec` is a column vector representing the constants on the right side of the equations. To solve this system, we can use the matrix inverse method:

1. Find the inverse of the matrix `amat`, denoted as `amat_inv`.
2. Multiply `amat_inv` by `bvec` to get the solution array `numpizzas`.

Here's the statement that assigns the array variable `numpizzas` to the solution:

import numpy as np

amat_inv = np.linalg.inv(amat)
numpizzas = np.dot(amat_inv, bvec)

The code above finds the inverse of the matrix `amat` and multiplies it by the vector `bvec` to obtain the solution array `numpizzas`. This assigns the variable `numpizzas` to the solution of the system of equations in terms of the given variables `amat` and `bvec`.

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Related Questions

What distinguishes the research, investigation, and analysis phase from later phases of the historical preservation process?


It involves careful attention to the history of the structure.

It is the only phase that does not involve construction.

It is primarily involved with fact finding.

It is the only phase that does not involve design.

Answers

Answer:

c

Explanation:

the highway department paves one section of an interstate with type a concrete and ajoining section with type b concrete and observes how long it takes until cracks appear in each.
a. Observational
b. Experimental

Answers

This scenario can be described as an experimental study. An experiment involves manipulating variables to observe the effects on an outcome.

In this case, the highway department manipulates the type of concrete used (Type A and Type B) and observes the time taken for cracks to appear in each section. The explanation for this conclusion is that by actively controlling the type of concrete used, the department can compare the performance and durability of both types, allowing them to make informed decisions about which concrete is more suitable for future use. In an observational study, no variables would be intentionally manipulated; rather, the researcher would simply observe and gather data without any intervention.

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A friend of yours bought several dozen pure silver rings on a recent trip abroad, but now suspects
that they might not be all that pure. He brings them to you to check. You weigh 10 of the rings and
find that each ring has a mass of 0.738g, you then place them in a graduated cylinder 2.5cm in
diameter and observe that the water level rises by 8.45mm. S.G of pure silver = 10.49
Using chemical engineering concepts, determine if the rings are pure silver.

Answers

Answer:

3

Explanation:

To determine if the rings are pure silver, we can calculate the density of the rings and compare it to the density of pure silver. The density of a material is the mass of the material per unit volume.

First, we need to find the volume of one of the rings. Since the rings are cylindrical, we can use the formula for the volume of a cylinder to find the volume of each ring:

V = π * r^2 * h

Where V is the volume of the ring, π is approximately equal to 3.14, r is the radius of the ring, and h is the height of the ring. In this case, the height of the ring is equal to the thickness of the ring, which is equal to the change in the water level (8.45 mm) divided by the number of rings (10). The radius of the ring is equal to half the diameter of the graduated cylinder (2.5 cm / 2 = 1.25 cm), since the rings are placed in the cylinder side by side.

Plugging these values into the formula, we find that the volume of each ring is:

V = 3.14 * (1.25 cm)^2 * (8.45 mm / 10) = 0.00367 cm^3

Next, we can use the mass and volume of each ring to calculate the density of the rings:

density = mass / volume

Since the mass of each ring is 0.738g and the volume of each ring is 0.00367 cm^3, the density of the rings is:

density = 0.738 g / 0.00367 cm^3 = 201.09 g/cm^3

Finally, we can compare the density of the rings to the density of pure silver, which is 10.49 g/cm^3. Since the density of the rings is much higher than the density of pure silver, it is likely that the rings are not pure silver.

It is important to note that this calculation is only an approximate estimation of the purity of the rings. There may be other factors that affect the density of the rings, such as impurities or variations in the thickness of the rings. Additionally, the value of the density of pure silver used in this calculation may not be entirely accurate, as the density of a material can vary depending on factors such as temperature and pressure. A more precise determination of the purity of the rings would require further testing and analysis.

Engineers design for everyone and consider all design challenges opportunities to problem-solve. The roller coaster in this photo is the largest wooden coaster in East China. It stands 32 meters tall, 1,060 meters long, and is capable of speeds of up to 91 kilometers per hour. Is the need to build a roller coaster should be considered an engineering design problem?

Answers

Answer:

No

Explanation:

The "need" to build a roller coaster would not be considered an engineering design problem. This would be more of a management/accounting problem because they are the ones that analyze numbers and decide what the amusement park would need in order to maintain/increase profitability by attracting more customers. Therefore, if they "need" a new roller coaster to do so then it becomes their problem. For it to be an engineering design problem the statement should be "the need to design a roller coaster with certain specifics" or something along those lines.

suppose the input signal is 7.3 v. if using the successive approximation method to encode the signal for a 6-bit register for an adc with a full-scale range of 10 v, the value in decimal number will be (precision is 3 digits after the decimal point):

Answers

One of the well-known traditional approaches for solving integral equations is the successive approximations method (SAM).

In the literature, it is sometimes referred to as the Picard iteration approach. In fact, this approach offers a strategy for resolving initial value issues or integral equations. With each incremental approximation toward the objective behavior of pressing the lever, Skinner would praise the rat for taking a step toward it, standing on its hind legs, and touching it. Using a binary search over all feasible quantization levels before settling on a digital output for each conversion, a successive-approximation ADC transforms a continuous analog signal into a discrete digital representation.

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A germanium diode carries a current of 1 mA at room temperature when a forward bias of 0.15v is applied. Estimate the reverse saturation current at room temperature.

Answers

The reverse saturation current, denoted as I0, can be estimated using the diode equation:

I = I0 * (exp(qV/kT) - 1)

where I is the current through the diode, q is the charge of an electron, V is the voltage across the diode, k is Boltzmann's constant, and T is the temperature in Kelvin.

At room temperature, T = 298 K. We are given that the diode carries a current of 1 mA when a forward bias of 0.15 V is applied. Let's assume that the diode is ideal, meaning that it has no series resistance, so the voltage across the diode equals the forward bias voltage.

Plugging in these values, we get:

1E-3 A = I0 * (exp((1.602E-19 C)(0.15 V) / (1.381E-23 J/K)(298 K)) - 1)

Simplifying, we get:

1E-3 A = I0 * (exp(0.01275) - 1)

1E-3 A / (exp(0.01275) - 1) = I0

I0 = 2.34E-12 A, or approximately 0.23 nA. Therefore, the estimated reverse saturation current at room temperature is 0.23 nA.

determine the steady state temperature distribution between two concentric spheres with radii 1 and 4

Answers

Answer:

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = \(\frac{C1}{r }\) + C2

u = \(\frac{\frac{-320}{3} }{r}\) + \(\frac{320}{3}\)

Explanation:

Solution:

Note: This question is incomplete and lacks necessary data to solve this question. But I have found a similar question and will try to solve it.

This question has this following part missing:

"If the temperature of the outer sphere is maintained at 80 degrees and the inner sphere at 0 degrees.

Now, this question is complete.

Let's find out the steady state temperature distribution.

As, we know the spherical symmetric heat equation:

\(\frac{du}{dt}\) = \(\frac{k}{r^{2} }\) \(\frac{D}{Dr}\) (\(r^{2}\) \(\frac{Du}{Dr}\))

Where, small (d) represents the partial differentiation and Capital D represents simple derivative.

And the ordinary differential equation (ODE) for steady state temperature distribution is:

\(\frac{k}{r^{2} }\) \(\frac{D}{Dr}\)(\(r^{2}\) \(\frac{Du}{Dr}\)) = 0

So it can be said that:

\(r^{2}\) \(\frac{Du}{Dr}\)

Consequently,

\(\frac{Du}{Dr}\) = \(\frac{C1}{r^{2} }\)

Taking derivative of the above equation we get:

u = -\(\frac{C1}{r }\) + C2

Solution of the ordinary differential equation

u = \(\frac{C1}{r }\) + C2 (Consuming the negative sign into C1 constant)

As, it is given in our question that our boundary conditions are: 1 and 4

So,

Putting the boundary conditions into the variable (r) to find the constants we get:

u1 = \(\frac{C1}{1} }\) + C2 = 0 (degrees)

u1 = C1 + C2 = 0 (degrees)  equation (1)

Similarly,

u4 = \(\frac{C1}{4}\) + C2 = 80 (degrees)

u4 = \(\frac{C1}{4}\) + C2 = 80 (degrees)  equation (2)

Solving for C1, we get:

Equation 1 - Equation 2

(C1 - C2 = 0) - (\(\frac{C1}{4}\) + C2 = 80)

\(\frac{-3}{4}\)C1 = 80

Solving for C1

C1 = -\(\frac{320}{3}\)

With the help of value of C1, we get value of C2

Put the value of C1 in equation (1) to get value of C2

C1 + C2 = 0

-\(\frac{320}{3}\) + C2 = 0

Solving for C2

C2 = \(\frac{320}{3}\)

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = \(\frac{C1}{r }\) + C2

Plugging in the values of C1 and C2

u = \(\frac{\frac{-320}{3} }{r}\) + \(\frac{320}{3}\)

A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?

Answers

The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.

What is a resistance?

This can be defined as the opposition to current flow in a circuit.

To calculate the total resistance, first we need to find the total resistance of the parallel resistor.

For parallel,

R' = (R₁R₂)/(R₁+R₂)............Equation 1

Where:

R' = Total resistance of the parallel resistor.

From the question,

Given:

R₁ = 6 ohmsR₂ = 6 ohms

Substitute these values into equation 1

R' = (6×6)(6+6)R' = 3 ohms.

Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.

Rt = R'+R₃.................. Equation 2

Where:

Rt = Total resistance of the circuit.

From the question,

R' = 3 ohmsR₃ = 6 ohms

Substitute these values into equation 2

Rt = 3+6Rt = 9 ohms.

Hence, the total resistance of the circuit is 9 ohms.

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if a barometer reads the pressure at the entrance of a building as 99.4 kpa and as 94.7 kpa at the top of the building, determine the height

Answers

Given the values of the barometer and atmospheric pressure on the ground and at the top of the building, its height is measured at 371.77 meters. The calculation steps are described below.

How to calculate the height of the building with a barometer

Step 1: The atmospheric pressure on the ground is measured with the barometer

Entrance of a building = 99.4 kpa

Step 2: The atmospheric pressure on the roof of the building is measured with the barometer

Top of the building = 94.7 kpa

Step 3: Calculate the height of the building by subtracting the both pressures and divide the result by the multiplication of air density and gravity.

Gravity on earth = 9.80 m/s²

Air density = 1.29 kg/m3

Entrance of a building - Top of the building = 99.4 – 94.7 = 4.7

Building height = 4.7 kpa / (9.80 m/s² * 1.29 kg/m3)

Converting kilopascals (kpa) to newton/m2:

4.7 kpa = 4700 n/m2 (newton = (kg*m)/ s²)

Solving units of measurement for density and gravity:

m/s² * kg/m3 = kg/ (s² * m²)

Solving for units of newtons and meters:

n/m2 = ( (kg*m)/ s² ) / m² = (kg*m)/ ( s² * m² ) = kg/ ( s² * m )

After:

kg/ ( s² * m ) / ( kg/ ( s² * m²) ) = m

Finally;

Building height = 4700 / (9.8 * 1.29) m

 

Building height = 4700 / 12.64 m

Building height = 371.77 m

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if a barometer reads the pressure at the entrance of a building as 99.4 kpa and as 94.7 kpa at the top

If a radiator in a steam heating system is cool while the others are hot because its valve is closed, it means the?

Answers

If a radiator in a steam heating system is cool while the others are hot because its valve is closed, it means that the closed valve is preventing the flow of steam into the radiator.

Steam heating systems work by circulating steam through pipes to heat radiators, which then release the heat into the surrounding space. The flow of steam is regulated by valves, which control the amount of steam that enters each radiator.

When a radiator's valve is closed, it effectively blocks the steam from entering the radiator, leading to a lack of heat output. As a result, the radiator remains cool while the others, whose valves are open, receive and emit the heat generated by the steam.

This situation commonly occurs when a room doesn't require as much heating or when an individual wants to control the temperature in specific areas of a building.

To rectify the issue and make the radiator heat up, the valve needs to be opened. By doing so, it allows the steam to flow into the radiator, enabling it to heat up and contribute to the overall heating system.

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There are two types of LEDs (Light Emitting Diodes) that can produce yellow light. One manufacturer offers an LED that emits only yellow light of wavelength 590 nm. Another manufacturer offers a unit that is actually two LEDs, one that emits red light with a wavelength of 630 nm, the other emits green light with a 540 nm wavelength. The yellow light from both LEDs looks identical when shined on a wall.
Suppose that each type of LED was used to shine light through a diffraction grating. In each case, there will be a pattern that appears on the screen. Describe the differences (if any) between those patterns as completely as you can.

Answers

Answer:

The light from the first LED will appear as yellow while the light from the second LED won't appear as Yellow light when passed through a diffraction grating

Explanation:

There are two types of LED's

First LED emits only yellow light  with wavelength of 590 nm

Second LED : emits red light with wavelength of 630 nm and emits green light with a 540 nm wavelength

The second LED produces a yellow light because of the mixture of red and green lights

therefore when the light from the SECOND LED is passed through a  diffraction grating, the light is split into its components ( i,e green and red lights ) this is because the lights are not on the same wavelength

Joey has a car that uses the hand crank to open the windows. Joey is wondering where the energy comes from to open the windows.The sunHuman-powered energy from JoeyThe hand crankThe moving car

Answers

Explanation:

Joey has a car that uses the hand crank to open the windows. Joey is wondering where the energy comes from to open the windows.The sunHuman-powered energy from JoeyThe hand crankThe moving car

What is the current I 2 I2 through resistor R 2 ? R2? Find an expression for I 2 I2 in terms of V a , Va, V b , Vb, R 1 , R1, R 2 , R2, and R 3 . R3. Take the positive direction to be downward.

Answers

To solve for the current \(I_2\) through resistor \(R_2\), we need to use Kirchhoff's current law (KCL) at the node where \(R_1\), \(R_2\), and \(R_y\) meet.

By KCL, the current flowing into this node must be equal to the current flowing out of the node. We can express this as:

\(I_1\) = \(I_2\) + \(l_y\)

Where I1 is the current flowing from the positive terminal of the \(V_a\) battery, \(l_y\) is the current flowing through resistor \(R_y\), and \(I_2\) is the current flowing through resistor \(R_2\).

We can also apply Kirchhoff's voltage law (KVL) to the outer loop of the circuit, which includes the Va and Vb batteries and  \(R_1\) and \(R_2\) resistors. This gives us:

\(V_a\) - \(I_1\)\(R_1\) - \(I_2\) \(R_2\) - \(V_b\) = 0

We can solve these two equations for \(I_2\), which gives us:

\(I_2\) = (\(V_a\) - \(V_b\) + \(l_y\)*\(R_y\))/\(R_2\)

This expression for \(I_2\) in terms of Va, Vb, \(R_1\), \(R_2\), and \(R_y\) shows that the current through \(R_2\) depends on the voltages of the two batteries, the values of the resistors, and the current through \(R_y\).

Complete question:

The circuit is constructed using two batteries and three resistors. What is the current \(I_2\) through resistor \(R_2\)? Find an expression for \(I_2\) in terms of \(V_a\), \(V_b\), \(R_1\), \(R_2\), and \(R_y\). Take the positive direction to be downward.

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What is the current I 2 I2 through resistor R 2 ? R2? Find an expression for I 2 I2 in terms of V a ,

Diameters of bolts produced by a particular machine are normally distributed with mean 8.6 mm and standard deviation 0.25 mm. Specifications call for diameters from 7.3 mm to 7.8 mm.
What percentage of bolts will meet these specifications?

Answers

The proportion (or percentage) of bolts that will meet the given specifications is approximately 0.1% (or 0.001 as a proportion).

To determine the percentage of bolts that will meet the given specifications, we need to calculate the proportion of bolts with diameters between 7.3 mm and 7.8 mm within the normal distribution.

First, we can standardize the specifications using the formula for standardizing a normally distributed variable:

Z = (X - μ) / σ

Where:

Z is the standardized value,

X is the observed value,

μ is the mean, and

σ is the standard deviation.

For the lower specification of 7.3 mm:

Z_lower = (7.3 - 8.6) / 0.25

For the upper specification of 7.8 mm:

Z_upper = (7.8 - 8.6) / 0.25

Calculating these values:

Z_lower = -4.8

Z_upper = -3.2

Next, we can use a standard normal distribution table or statistical software to find the proportion of values between these Z-scores.

We can find the corresponding probabilities by looking up the Z-scores in a standard normal distribution table.

P(Z > -4.8) is approximately 1.0 (because the value is extremely low).

P(Z > -3.2) is approximately 0.999 (again, the value is very low).

Now, we can subtract the probability from 1 to find the proportion of bolts that meet the specifications:

Proportion = 1 - P(Z > -4.8) - P(Z > -3.2)

= 1 - 1.0 - 0.999

= 0.001

Therefore, the proportion (or percentage) of bolts that will meet the given specifications is approximately 0.1% (or 0.001 as a proportion).

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1. Plot these two state points on a pressure (ordinate) - volume (abscissa) plane: at state $1, P_1=60 {Bar}, {V}_1=100 {li}$; at state $2, {p}_2=10 {bar}, {V}_2=700 {li}$. Now join them with a single straight line. (a) What will be the pressure and volume of a third state point located on this line and mid-way between the first two state points? (b) From a right triangle using the straight line as the hypotenuse. What will be the pressure and volume of the state point located at the junction of the two legs of the triangle?

Answers

(a) The pressure and volume of the third state point located midway between the first two state points will be approximately 35 Bar and 400 li, respectively.

(b) The pressure and volume of the state point located at the junction of the two legs of the right triangle will be approximately 40 Bar and 250 li, respectively.

(a) To find the pressure and volume of the third state point, we can use the concept of linear interpolation. Since the two given state points are joined by a straight line, we can determine the pressure and volume at the midpoint by taking the average of the corresponding values of the two points. Thus, the pressure at the third state point is (60 + 10)/2 = 35 Bar, and the volume is (100 + 700)/2 = 400 li.

(b) In a right triangle, the hypotenuse represents the straight line joining the two state points. By using the Pythagorean theorem, we can calculate the length of the hypotenuse, which corresponds to the pressure and volume at the junction of the two legs. The difference in pressure between the two state points is 60 - 10 = 50 Bar, and the difference in volume is 700 - 100 = 600 li. Treating these differences as the legs of a right triangle, we can calculate the hypotenuse length using the theorem. The pressure at the junction point is given by sqrt((40^2) + (50^2)) = 40 Bar, and the volume is sqrt((250^2) + (600^2)) = 250 li.

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Which option explains the benefit of a newly designed fluid power system in the following scenario? A new fluid power rail system is being designed to travel across a large expanse of China. The new system will have a state-of-the-art hydraulic power system. The new fluid power system will have microstructures in the inner tubing to decrease friction and allow for more efficient dispersion of the fluid. The new fluid power system will have microstructures in the inner tubing to decrease friction and allow for more efficient dispersion of the fluid. The new fluid power system will have microstructures in the inner tubing to increase friction and allow for more efficient dispersion of the fluid. The new fluid power system will have microstructures in the inner tubing to increase friction and allow for more efficient dispersion of the fluid. The new fluid power system will have smooth surfaces to decrease friction and allow for more efficient dispersion of the fluid. The new fluid power system will have smooth surfaces to decrease friction and allow for more efficient dispersion of the fluid. The new fluid power system will have smooth surfaces to increase friction and allow for more efficient dispersion of the fluid.

Answers

Answer:

B

Explanation:

Answer:

The new fluid power system will have microstructures in the inner tubing to increase friction and allow for more efficient dispersion of the fluid.

Explanation:

what is the purpose of the control rods in a nuclear power plant?

Answers

The purpose of the control rods in a nuclear power plant are to regulate the rate of the nuclear reaction that is taking place in the reactor core of the nuclear power plant, and to stop the nuclear reaction in the event of an emergency.

In nuclear power plants, control rods are an essential component that help to control the rate of the nuclear reaction and prevent a nuclear meltdown.

Control rods are made of materials like boron or cadmium that are capable of absorbing neutrons.

When the control rods are inserted into the reactor core, they absorb neutrons and slow down the nuclear reaction.

When they are removed, the nuclear reaction speeds up again.

This makes them a crucial tool for regulating the output of a nuclear power plant.

Control rods also play an important role in safety, as they can be used to quickly stop the nuclear reaction in the event of an emergency.

If something goes wrong with the reactor, the control rods can be fully inserted into the core to stop the nuclear reaction from continuing.

This can help to prevent a meltdown and protect the safety of people living near the nuclear power plant.

In conclusion, control rods are a vital component in a nuclear power plant, as they help to regulate the rate of the nuclear reaction and can quickly stop the reaction in the event of an emergency.

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which is an increased risk of performing vertical ventilation?

Answers

There's a chance that the building or its roof will collapse, as well as that you'll become disoriented from the dense smoke or accidentally step off the roof.

What presents the biggest danger to firemen practising vertical ventilation?

Which benefit from correctly executed ventilation is most likely to occur? the structure's inside has improved. What poses the biggest risk to firefighters practising vertical ventilation? failure of a roof

What kind of ventilation would be vertical, then?

By allowing smoke and poisonous gases to follow their natural course upward, vertical ventilation removes these substances from the air. Fire departments accomplish this by using a ladder, saws, and other tools to climb the roof, create an aperture on the roof's exterior, and then knock out the ceiling with a different tool.

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An eyewash station should be located within what maximum distance from every location where a person may come into contact with substances that can cause damage to the eyes?

Answers

An eyewash station should be located within a maximum distance of 25 feet from every location where a person may come into contact with substances that can cause damage to their eyes.

For a bronze alloy, the stress at which plastic deformation begins is 284 MPa and the modulus of elasticity is 106 GPa. (a) What is the maximum load that can be applied to a specimen having a cross-sectional area of 310 mm2 without plastic deformation? (b) If the original specimen length is 120 mm, what is the maximum length to which it may be stretched without causing plastic deformation?

Answers

Answer:

a) the maximum load is 88,040 N

b)

the maximum length to which the specimen may be stretched is 0.12032148 mm

Explanation:

Given the data in the question;

the stress at which plastic deformation begins σ = 284 MPa = 2.84 × 10⁸ Pa

modulus of elasticity E = 106 GPa = 1.06 × 10¹¹ Pa

a)

Area A = 310 mm² = 310 × 10⁻⁶ m ( without plastic deformation )

now, lets consider the equation relating to stress and cross sectional area.

σ = F / A₀

hence, maximum load F = σA₀  

so we substitute

F = (2.84 × 10⁸) × (310 × 10⁻⁶)

F = 88,040 N

Therefore, the maximum load is 88,040 N

b)

Initial length specimen l₀ = 120 mm  = 120 × 10⁻³ m

using engineering strain, ε = (l₁ - l₀)/l₀

Also from Hooke's law, σ = Eε

so from the equation above;

l₁ = l₀( ε + 1 )

l₁ = l₀( σ/E + 1 )

so we substitute

l₁ = (120 × 10⁻³)( (2.84 × 10⁸)/(1.06 × 10¹¹)) + 1 )

l₁ = (120 × 10⁻³) ( 1.002679 )

l₁ = 0.12032148 mm

Therefore, the maximum length to which the specimen may be stretched is 0.12032148 mm

Technician a says an automotive master cylinder is a device that uses brake system pressure to produce friction for stopping wheel rotation. technician b says an automotive master cylinder holds the wheel cylinder piston and brake pads. who is right?

Answers

Answer:

Neither A nor B

(a) (6 points) Find the integer a in {0, 1,..., 26} such that a = -15 (mod 27). Explain. (b) (6 points) Which positive integers less than 12 are relatively prime to 12?

Answers

a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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An incremental encoder is rotating at 15 rpm. On the wheel there are 40 holes. How many degrees of rotation would 1 pulse be?

Answers

Answer:

1 pulse rotate = 9 degree

Explanation:

given data

incremental encoder rotating = 15 rpm

wheel holes = 40

solution

we get here first 1 revolution time

as 15 revolution take = 60 second

so 1 revolution take = \(\frac{60}{15}\)

1 revolution take = 4 seconds

and

40 pulse are there for 1 revolution

40 pulse for 360 degree

so 1 pulse rotate is = \(\frac{360}{40}\)

1 pulse rotate = 9 degree

Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years

Answers

Top 10 Emerging Technologies in Chemistry
Nanopesticides. The world population keeps growing. ...
Enantio selective organocatalysis. ...
Solid-state batteries. ...
Flow Chemistry. ...
Porous material for Water Harvesting. ...
Directed evolution of selective enzymes. ...
From plastics to monomers. ...

A series resistive circuit has two resistors. R1 is 570 ohms and R2 is 560 ohms.
The total circuit current is 17.9 milliamps.
Find the voltage drop across R1 in volts.

Answers

Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.

A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is applied to the top side of the plate. A normal tensile force of 20kN is applied to the right side of the plate. The elastic modulus, E, is 115 GPa for titanium.If the left and bottom edges of the plate are fixed, calculate the normal strain and elongation of both the TOP and RIGHT side of the plate.

Answers

Answer:

\(X_t=2.17391304*10^{-4}\)

\(X_r=2.89855072*10^{-4}\)

\(e_t=0.0026\)

\(e_r=0.0035\)

Explanation:

From the question we are told that:

Dimension \(12*12\)

Thickness \(l_t=5mm=5*10^-3\)

Normal tensile force on top side \(F_t= 15kN\)

Normal tensile force on right side  \(F_r= 20kN\)

Elastic modulus, \(E=115Gpap=>115*10^9\)

Generally the equation for Normal Strain X is mathematically given by

 \(X=\frac{Force}{Area*E}\)

Therefore

For Top

 \(X_t=\frac{Force_t}{Area*E}\)

Where

 \(Area=L*B*T\)

 \(Area=12*10^{-2}*5*10^{-3}\)

 \(Area=6*10^{-4}\)  

 \(X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}\)

 \(X_t=2.17391304*10^{-4}\)

For Right side\(X_r=\frac{Force_r}{Area*E}\)

Where

Area=L*B*T

 \(Area=12*10^{-2}*5*10^{-3}\)

 \(Area=6*10^{-4}\)  

 \(X_r=2.89855072*10^{-4}\)

 \(X_r=2.89855072*10^{-4}\)

Generally the equation for elongation is mathematically given by

 \(e=strain *12\)

For top

 \(e_t=2.17391304*10^{-4}*12\)

 \(e_t=0.0026\)

For Right

 \(e_r=2.89855072*10^{-4} *12\)

 \(e_r=0.0035\)

Which option identifies the step skipped in the following scenario?

Eric is a newly hired engineer who has just ruined a prototype of a very expensive jet plane made from steel. He was short on time, so he rushed the molds of the body of the jet, causing them to crack. The cost incurred put the project far over budget.


He deviated from the design plans of the project.

He did not use the proper materials for the project.

He did not pay attention to the cost analysis of the project.

He did not allow the metal to cool properly when making molds.

Answers

Answer:

he didn't use the proper material

Answer:

A. He did not allow the metal to cool properly when making molds.

Explanation:

Two aerial photographs were taken 30 seconds apart over one east-bound lane of l-80 near Grand Island, NE. The following results were recorded.
Position from start of road section Vehicle 2000 2300 1700 1200 600 2940 3200 2400 2100 1730 1000 2 3 4
Plot the trajectories of the vehicles on graph paper and compute the average flow (vph), density (veh/mi) and space mean speed (mph) over the 3000 ft length of the lane.

Answers

Answer:

the average flow (vph) = 222.69 veh/hr.  

The average velocity = 111348 ft/hr.

density = 2 × 10⁻³ veh/ft.

Explanation:

The first thing to do in this particular question is to determine the average velocity.

The average velocity = [ ( 2940 - 2000/30) + ( 3200 - 2300/30) + ( 2400 - 1700/30) + ( 2100 - 1200) + ( 1730 - 600/30) + ( 1000 - 0/30).

The average velocity = [31.33 + 30 + 23.33 + 30 + 37.66 + 33.66]/ 6 = 30.99 ft/sec.

Thus, 30.99 ft/sec × 60 × 60 = 111348 ft/hr.

The next thing to do is to determine the density. therefore, the density = 6/ 3000 = 2 × 10⁻³ veh/ft.  

The average flow (vph) =  111348 ft/hr × 2 × 10⁻³ veh/ft.  = 222.69 veh/ hr.

Also, the space mean speed (mph) over the 3000 ft length of the lane = 6/ [ 1/31.33 + 1/30 + 1/23.33 + 1/30 + 1/37.66 + 1/33.66] = 6/ 0.1977 = 30.34 ft/sec.

class Main {
public static void main(String[] args) {
int x9 = 3;
System.out.print(ii(x9*2) + " " + (x9 - 4) + ii(x9));
}
public static int ii(int x){
x = x * -3;
System.out.print(x);
x++;
return x;
}
}

Why does this post:

-18-9-17 -1-8

Im so confused as to how that gets posted... I dont think i understand how operators in methods work

Answers

In the given code, the output " -18-9-17 -1-8" is printed because of the combination of print statements inside the main() and ii() methods. The output will be : public static void main(String[] args) {int x9 = 3;// x9 is initialized to 3System.out.print(ii(x9*2) + " " + (x9 - 4) + ii(x9));}

The above statement first calls the ii() method with an argument of x9*2 = 6, which means the x parameter inside the ii() method is 6. Now, the ii() method does the following:public static int ii(int x){x = x * -3;System.out.print(x);x++;return x;}x is multiplied by -3, so x becomes -18.

The print statement inside the ii() method prints the value of x, which is -18. The value of x is incremented by 1 and the new value of x (-17) is returned to the calling function. Now, the main() method continues with the evaluation of the expression:System.out.print(ii(x9*2) + " " + (x9 - 4) + ii(x9));The second argument in the print statement is (x9 - 4), which is equal to -1 (since x9 is 3). Now, the ii() method is called again, this time with an argument of x9 = 3.

The ii() method performs the following steps:public static int ii(int x){x = x * -3;System.out.print(x);x++;return x;}x is multiplied by -3, so x becomes -9. The print statement inside the ii() method prints the value of x, which is -9. The value of x is incremented by 1 and the new value of x (-8) is returned to the calling function.

Finally, the print statement inside the main() method prints the values returned by the two ii() method calls, which are -17 and -8, respectively. This results in the output " -18-9-17 -1-8".Thus, the output "-18-9-17 -1-8" is generated because of the combination of print statements inside the main() and ii() methods.

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an architectural element that projects from a wall to support a horizontal part of a building such as beams or eaves of a roof is called:

Answers

An architectural element that projects from a wall to support a horizontal part of a building such as beams or eaves of a roof is called: Bracket.

A soffit is a horizontal, elevated aspect of any construction element that can be seen on the interior or exterior of a building. The underside of eaves (used to join a retaining wall to projecting edge(s) of the roof) is its classic form, occasionally integrating or implying the projection of beams. The bracket that gives support underneath a structure like a roof, ceiling, window, beam, or shelf is known in architecture as a corbel. In addition, a block or other system that protrudes from a building's wall is referred to as a corbel.

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