Answer:
tn =a+(n-1)d is the nth formula
you are on the game show, and the host of the show is asking everyone on the show to pick a number from one to 100 and the person who picks the number that's close to two-thirds of the average is the winning number and you win the show. assuming that there are 500,000 people on this game show, you are the only person who knows this information, what do you pick? what's the number that you pick
The chance that you will win the show even if you pick 34.
As given in the question, there are 500,000 people in the game show, and the host is asking everyone to pick a number from one to 100. The person who picks the number that's close to two-thirds of the average is the winning number, and he or she will win the show. So, what number should you pick?The average of all the numbers that everyone picks is (1 + 2 + 3 + ....... + 100)/N, where N is the number of people participating in the show. Therefore, the average is (1 + 2 + 3 + .....+ 100)/500,000, which is 50.5.Now, you have to pick a number that's close to two-thirds of 50.5. So, two-thirds of 50.5 is 33.67. As you need to pick a number close to this, you should go for 33 or 34. Since it's impossible for anyone to choose 33.67, you need to pick a number close to either 33 or 34.
Therefore, the number that you should pick is 33 or 34.If you pick 33, then two-thirds of the average will be (2/3) × 50.5 = 33.67, which is very close to 33. Therefore, it's highly likely that you will win the show. However, if you pick 34, then two-thirds of the average will be (2/3) × 50.5 = 33.67, which is close to 34. Therefore, there is still a chance that you will win the show even if you pick 34.
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HELP ME PLEASE!!,I WILL GIVE BRAINLIEST!!I PROMISE:)!!
Answer: C
The denominator is just the number on the bottom. In this case its \(2\sqrt{2}\)
Please help me I am bad at math!
Group the terms together and solve.
-6 -8c = 3c + 16
A. 242
B. -4.4
C. -2
D. 10/11
Sorry if this is easy
Answer:
I got C.
Step-by-step explanation:
Calculator.
Answer:
C. -2
Step-by-step explanation:
Subtract 3c from -8c, and add -6 to 16 to simplify the equation.
If is the probability that the reciprocal of a randomly selected positive odd integer less than 2010 gives a terminating decimal, with and being relatively prime positive integers, what is
The probability value of (m, n) is (1, 2^1005).
Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.
If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.
We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.
Thus, the probability is:
P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004
We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.
Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:
|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|
where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.
By the inclusion-exclusion principle:
|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)
where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.
This simplifies to:
(1/2) ⋅ (2^1004 + (-1)^1005)
Thus, the probability is: P = (1/2^1004) ⋅ (1/2) ⋅ (2^1004 + (-1)^1005) = 1/2 + 1/2^1005. Hence, (m, n) = (1, 2^1005).
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Complete question:
If m/n is the probability that the reciprocal of a randomly selected positive odd integer less than 2010 gives a terminating decimal, with m and n being relatively prime positive integers. what is probability value of m and n?
The probability value of (m, n) is (1, 2^1005).This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.
Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.
If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.
We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.
Thus, the probability is:
P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004
We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.
Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:
|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|
where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.
By the inclusion-exclusion principle:
|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)
where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.
This simplifies to:
\((1/2) * (2^{1004} + (-1)^1005)\)
Thus, the probability is: P = \((1/2)^{1004}* (1/2) *(2^{1004} + (-1)^{1005}) = 1/2 + 1/2^{1005}.\)
Hence, (m, n) = (\(1, 2^{1005\)).
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an insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel in 91 of them. (a) (8 pts) find the 95% confidence interval for , the true proportion of all auto accidents that involve teenage drivers. (note: for full credit, show all your work. no credit
The 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
To find the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers, we can use the formula for the confidence interval for a proportion.
The formula for the confidence interval is:
CI = p1 ± Z * √((p1 * (1 - p1)) / n)
Where:
CI is the confidence interval,
p1 is the sample proportion (proportion of accidents involving teenage drivers),
Z is the Z-score corresponding to the desired confidence level (95% confidence level corresponds to Z ≈ 1.96),
n is the sample size (number of accidents checked).
Given:
Number of accidents checked (sample size), n = 582
Number of accidents involving teenage drivers, x = 91
First, we calculate the sample proportion:
p1 = x / n = 91 / 582 ≈ 0.1566
Now we can calculate the confidence interval:
CI = 0.1566 ± 1.96 * √((0.1566 * (1 - 0.1566)) / 582)
Calculating the standard error of the proportion:
SE = √((p1 * (1 - p1)) / n) = √((0.1566 * (1 - 0.1566)) / 582) ≈ 0.0184
Substituting the values into the formula:
CI = 0.1566 ± 1.96 * 0.0184
Calculating the values:
CI = 0.1566 ± 0.0361
Finally, we can simplify the confidence interval:
CI = (0.1205, 0.1927)
Therefore, the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
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I need help ;-; pls
Answer:
B) 17
Step-by-step explanation:
3 (12 - 8) + 5
(3 x 12) - (3 x 8) + 5
(36 - 24) + 5
12 + 5
17
If UV=x and TW=-x+99 what is the value of x?
If UV = x and TW = x+99 ,using triangle proportional theorem, then the value of x is 99
What is triangle proportional theorem?Triangle proportion theorem states that if a line is drawn parallel to any one side of a triangle so that it intersects the other two sides in two distinct points, then the other two sides of the triangle are divided in the same ratio.
since TU = TS and S W = VW. This show that triangle SUV is an isosceles triangle
then TW / UV = 1/2
therefore x/-x+99 = 1/2
2x = -x+99
Collect like terms
2x- x = 99
x= 99
therefore the value of x is 99
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y-intercept of the line with slope of 2 and
through the point ( 14,3)
Answer: -25
Step-by-step explanation:
I used point-slope form [y-3=2(x-14)] and the Y intercept is -25
Select all expressions that are equivalent to 5^n/2^n. There may be more than one correct answer. A. (5/2)^n B. (2/5)^-n C. - (5/2)^n D. (2.5)^n E. (1/2/5)^n F. 2^-n/5^-n
The expression equivalent to the 5ⁿ/2ⁿ will be (5/2)ⁿ , (2/5)⁻ⁿ , (2.5)ⁿ , 2⁻ⁿ/5⁻ⁿ.Options A, B, D, and F are correct.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the expression is, 5ⁿ/2ⁿ
The expression can be written in different ways as,
5/2)ⁿ
(2/5)⁻ⁿ
(2.5)ⁿ
2⁻ⁿ/5⁻ⁿ
Thus, the expression equivalent to the 5ⁿ/2ⁿ will be (5/2)ⁿ , (2/5)⁻ⁿ , (2.5)ⁿ, 2⁻ⁿ/5⁻ⁿ. Options A, B, D, and F are correct.
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Prove each of the following statements using strong induction. a. Prove that any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps. b. Prove that any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps. c. Prove that any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.
a) By strong induction, any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.
b) By strong induction, any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.
c) By strong induction, any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.
a. Prove that any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.
Base case: For postage worth 8 cents, we can use two 4-cent stamps, which can be made using a combination of one 3-cent stamp and one 5-cent stamp.
Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 8, can be made from 3-cent or 5-cent stamps.
Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 8, we can use the induction hypothesis to make k cents using 3-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with a 5-cent stamp to get the same value. If the last stamp we added was a 5-cent stamp, we can replace it with two 3-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3-cent or 5-cent stamps.
b. Prove that any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.
Base case: For postage worth 24 cents, we can use three 8-cent stamps, which can be made using a combination of one 7-cent stamp and one 5-cent stamp.
Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 24, can be made from 7-cent or 5-cent stamps.
Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 24, we can use the induction hypothesis to make k cents using 7-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 5-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with three 5-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 7-cent or 5-cent stamps.
c. Prove that any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.
Base case: For postage worth 12 cents, we can use one 3-cent stamp and three 3-cent stamps, which can be made using a combination of two 7-cent stamps.
Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 12, can be made from 3-cent or 7-cent stamps.
Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 12, we can use the induction hypothesis to make k cents using 3-cent or 7-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with one 3-cent stamp and two 7-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3
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Can someone please help I’m stressing and can’t answer this
65°
Step-by-step explanation:
just have to rest 115° from 180°
The radius of the circle shown below is 3 inches.
What is the area of this circle, in square inches?
Answer:
the area = 28.27 or you can write the answer out as 28.2744 or also 28.27433
Step-by-step explanation:
start with what we know. the formula for solving this is A=pi R squared
so, area= pi (3.1416)
then, multiply that by the radius given, which is 3.
So, 9.4248 × 3 = 28.2744 square inches
or 28.27 sq.in.
HOPE THIS HELPS... HAVE A GREAT DAY!!
What is the symbol of proportional?
The symbol for proportionality is "∝". It is read as "is proportional to" or "varies in proportion to".
Proportionality is a mathematical concept that describes the relationship between two quantities. When two quantities are proportional, it means that they have a constant ratio. For example, the distance traveled by a car is proportional to the time it takes to travel that distance. This means that if the time taken to travel doubles, then the distance traveled also doubles.
In mathematics, we use the symbol "∝" to represent proportionality. This symbol is read as "is proportional to" or "varies in proportion to". So, if we say that A ∝ B, it means that A is proportional to B. This implies that if B increases or decreases, then A also increases or decreases, but the ratio of A to B remains constant.
The concept of proportionality is used in various mathematical fields, such as algebra, geometry, and physics. It is a powerful tool for solving problems that involve relationships between quantities, and it is widely used in real-world applications, such as in engineering, economics, and statistics.
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Im struggling a lot with these problems can anyone help and show the WORK please?
Answer:
Step-by-step explanation:
I'll give a couple answers so you get the gist of things.
All you have to do is substitute 1/2 for x and 3/4 for y.
Ex - 30. x × y = 1/2 × 3/4 = 3/8
Find the equation of the line that is perpendicular to 3y + x = -2 and passes through
the point (-2,-5).
Answer:
y=3x+1 or 3x-y=-1
Step-by-step explanation:
Hello,
We are given the line 3y+x=-2, and we want to write an equation of the line that is perpendicular to 3y+x=-2, and contains the point (-2, -5)
First, we'll need to find the slope of 3y+x=-2, as perpendicular lines have slopes that multiply to -1
In order to find the slope of 3y+x=-2, let's convert the equation of the line from standard form to slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
y is isolated by itself in slope-intercept form, so let's subtract x from both sides of the equation
3y=-x-2
Now divide both sides by 3
y=\(-\frac{1}{3}x - \frac{2}{3}\)
The slope of the line is -1/3
Now to find the slope of the line perpendicular to it, use this formula:
-1/3m=-1
Multiply both sides by -3
m=3
So the slope of the line perpendicular to it is 3
We can write the equation of this new line in slope-intercept form; substitute 3 as m in y=mx+b:
y=3x+b
Now we need to find b
As the equation passes through the point (-2, -5), we can use its values to help solve for b
Substitute -2 as x and -5 as y:
-5=3(-2)+b
Multiply
-5=-6+b
Add 6 to both sides
1=b
Substitute 1 as b:
y=3x+1
The equation can be left as this, or we can write it in standard form, if you wish
In standard form, x and y are on the same side; so we'll subtract 3x from both sides in order to have both variables on the same side
-3x+y=1
However, a (the coefficient in front of x) cannot be negative; so we'll multiply both sides by -1 to change the sign of the variable.
3x-y=-1
Hope this helps!
Find BC if BE 24, CD 32, and AB 33.
Determine k so that Col (A) is a subspace of R^k when A = [7 - 2 0 - 2 0 - 5 0 - 5 7 -5 7 - 2]. k = 6 k = 4 k = 5 k = 2 k = 3 Determine k so that Null (A) is a subspace of R^k when A = [2 - 6 - 1 3 - 4 12 3 - 9].
The null space of A is a subspace of\(R^2\\\).
The dimension of the null space of A is given by k = n - r, where n is the number of columns of A and r is the rank of A. To calculate the rank of A,
we need to perform row reduction operations on A.
After row reduction operations, the matrix A becomes:
A = [2 -6 -1 0 4 8 0 0 12].
From the above matrix, it can be seen that the rank of A is r = 3, as there are three non-zero rows. Therefore, the dimension of the null space of A is k = n - r = 5 - 3 = 2.
Therefore, the null space of A is a subspace of \(R^2\).
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PLEASE HELP!! 3 IN 1
1.solve and simplify 2/7 Divided by 4/5
2. Convert the fraction to a decimal 38/333
3. Convert the fraction to a decimal 12/111
Answer:
1. D
2.B
3.0.1081 (the one with a line over it)
I need help asap
Explain
Answer:
the awnser is:30° yup it is
Answer:
30°
Step-by-step explanation:
We Know
(4x - 2) + (20x - 10) = 180°
4x - 2 + 20x - 10 = 180
24x - 12 = 180
24x = 192
x = 8
Find m∠EBD
∠ABC is a vertical angle to ∠EBD, meaning they will equal it.
4(8) - 2
32 - 2
30°
So, m∠EBD is 30°
I need help this is due tomorrow !
Answer:
b i think
Step-by-step explanation:
as part of an ongoing service project, the students at arlington high school recently spent an afternoon planting trees. they planted an average of 5 trees per participant. soon they plan to do some more planting, averaging 4 trees per participant. if everything goes as planned, what will be the percent of decrease in the average number of trees planted?
The average number of trees planted by students at Arlington High School decreased by 20% when comparing the first planting session (5 trees per participant) to the upcoming session (4 trees per participant).
To calculate the percent of decrease, we can use the following formula:
Percent decrease = ((Initial value - Final value) / Initial value) * 100
For the first planting session, the initial value is 5 trees per participant, and for the upcoming session, the final value is 4 trees per participant. Plugging these values into the formula:
Percent decrease = ((5 - 4) / 5) * 100 = (1 / 5) * 100 = 20%
Therefore, the percent of decrease in the average number of trees planted is 20%. This means that the average number of trees planted per participant decreased by 20% from the first planting session to the upcoming session
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A college professor is curious if the location of seat in class affects grades in the class. They are teaching in a lecture hall with 240 students. The lecture hall has 10 rows, so they split the rows into 5 sections - Rows 1-2, Rows 3-4, Rows 5-6, Rows 7-8, and Rows 9-10. At the end of the course, they determine the top 25% of grades in the class, and if the location of the seat makes no difference, they would expect that these top 25% of students would be equally dispersed throughout the classroom. Their observations are recorded below. Run a Goodness of Fit test to determine whether or not location has an impact on the grade. Let α=0.05.
Hypotheses:
H0: Location in the classroom __________ impact final grade.
H1: Location in the classroom _________ impact final grade.
Select the best fit choices that fit in the two blank spaces above.
Location in the classroom has no impact final grade and the P-Value = 0.58609.
Null Hypothesis:
The null hypothesis is a typical statistical theory which suggests that no statistical relationship and significance exists in a set of given single observed variable, between two sets of observed data and measured phenomena.
Here null hypothesis is the ratio that is equal for all rows (No impact)
Alternate Hypothesis: At least one is different
Event Observed Expected Expected (0-E)^r (0-E)^r/E
frequency probability frequency
1 - 2 14 0.2 12 4 0.3333
3 - 4 8 0.2 12 16 1.3333
5 - 6 13 0.2 12 1 0.0833
7 - 8 10 0.2 12 4 0.3333
9 - 10 15 0.2 12 9 0.75
Total 60 60 2.83333
The corresponding P-Value = 0.586093
Reject Null Hypothesis if P < ∝ (0.05)
Here P > ∝ (we do not reject Null hypothesis)
All proportions are same
Hence the answer is, Location in the classroom has no impact final grade and the P-Value = 0.58609.
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-2 1/6 + (-2/3) im really confunsed and i cant find out the answer
Answer:
-2 5/6
Step-by-step explanation:
First, you have to change the fraction 2/3 to have a common denominator with 1/6. 2/3 x 2/2 = 4/6.
Second, now your equation is -2 1/6 + ( -4/6 ).
Third, you have to add -2 1/6 and -4/6 which gets you -2 5/6
Hope this helps!
1/2 times what gives you 4
Answer:
8
Step-by-step explanation:
8 x .50 = 4
Answer:
8
Step-by-step explanation:
Henry goes to the town fair.Use the prices on the photograph to complete the table.Enter the correct answer in the box.
ANSWER
$28
EXPLANATION
We have that the entry fee is $10 and for each ride, $6 must be paid.
We want to complete the table by finding the cost of 3 rides.
First, let us represent the cost of going to the fair and taking the ride.
Let the number of rides a person takes by x.
We have that the cost of taking x rides will be the entry fee plus the cost of each ride taken:
Cost = 10 + 6x
So, for taking 3 rides, it will cost:
Cost = 10 + 6(3)
Cost = 10 + 18
Cost = $28
That is the cost of taking 3 rides.
Can you solve 17+4x<9
Answer:
x<-2
Step-by-step explanation:
17+4x<9
4x<-8
x<-2
The solution is:
↬ x < -2Work/explanation:
Recall that the process for solving an inequality is the same as the process for solving an equation (a linear equation in one variable).
Make sure that all constants are on the right:
\(\bf{4x < 9-17}\)
\(\bf{4x < -8}\)
Divide each side by 4:
\(\bf{x < -2}\)
Hence, x < -2does anyone know how to use substitution for
x+y=21
2x-15=y
Answer:
Step-by-step explanation:
Replace x
x=-y+21
2(-y+21)-15=y
Then solve the rest
Each time Cheryl runs, she runs 3miles. She rides her bike only on Saturday’s and always for 10miles. She exercises the same amount each week. She rides and runs for a total of 22 miles in a week.
Write an equation that can be used to find out how many times, X, Cheryl goes running each week.
Answer: 6
Step-by-step explanation: 22 / 6 = 3.6666666666666666666666666667
Based on the information given, the equation will be 3x + 10y = 22.
How to solve and equation:Let the number of times she walks be x.
Let the number of times she rides be y.
Since she runs 3miles, therefore, from the information given, the equation will be 3x + 10y = 22.
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If the equation y = x^2 - 82 -- 8.0 + 15 is converted to the form y= (x - h)^2 + k, find the values of h and k.
Answer:
= 0 and k = -59.
Step-by-step explanation:
The equation y = x^2 - 82 -- 8.0 + 15 can be written as y = (x - 0)^2 - 82 + 15 + 8.0.
The value of h is the number that is subtracted from x in the square term. In this case, h = 0.
The value of k is the constant term that is added to the square term. In this case, k = -82 + 15 + 8.0 = -59.
Therefore, the values of h and k are h = 0 and k = -59.
the values of h and k in the equation y = x^2 - 82x - 8.0 + 15 converted to the form y = (x - h)^2 + k are h = 41 and k = -162.
To convert the equation y = x^2 - 82x - 8.0 + 15 to the form y = (x - h)^2 + k, we need to complete the square.
First, let's rearrange the terms:
y = x^2 - 82x + 7
To complete the square, we need to add and subtract a constant term that will allow us to factor the quadratic expression as a perfect square trinomial.
We can rewrite the quadratic expression as:
y = (x^2 - 82x + 169) - 169 + 7
Now, let's factor the perfect square trinomial within the parentheses:
y = (x - 41)^2 - 162
Comparing this form to the form y = (x - h)^2 + k, we can identify the values of h and k:
h = 41
k = -162
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I need this asap very easy!!! Please serious answers please!! I will mark brainliest if right
Answer:
1. no
2. 36+196=232 c=441 Obtuse.
3. x is greater than 3, less than 21.
Step-by-step explanation:
1. no
2. 36+196=232 c=441 Obtuse.
3. x is greater than 3, less than 21. is the correct answer to the question