Would you want to minimize or maximize the heat transfer to and from the handrails? Explain your reasoning.

The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.

The word "force" has a clear definition. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.

Force ( F ) is 2100N

Acceleration ( a ) is 1.8m/s²

Mass(m)= ?

According to formula;

Force = mass × acceleration

F= m × a

2100 = m × 1.8

2100 / 1.8 = m

Therefore, m = 1166.6kg.

Thus, The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is  1166.67kg.

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The light intensity from  largest to smallest ranking will be  :B > D > A=C > E. where the area is measured on the plane perpendicular to the direction .

In physics, the intensity is the amount of energy that is transmitted per unit area, and the area is measured on a plane perpendicular to the direction that the energy equation will propagate. I = P/ 4(d2), with P denoting power. Let power of 1 bulb equal = P where I = intensity, d = distance at which the intensity must be determined.

case A = I =  P / (1) (1) 1 = P case with 2 = P In the situation B = I = 2P/(0.5)2 = 8P C = I = 4P / (2) (2) ^2 = P case Case (1)2 = 3P: D = I = 3P E = I = 2P /(1.5) (1.5) ^2 = 0.8 P

B > D > A=C > E will be the order of light intensity, from greatest to least.

rank the light intensity, from largest to smallest, at the point p in the figures?

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Answer: The answer is an electric generator

Explanation:

I just took the quiz and I thought it was an electric motor but the correct answer was an electric generator.

This concept of closed loop wire experiences a changing magnetic field and flowing of current is related to the Faraday's law of electromagnetic induction.

When ever there is a bar magnet inside the wire and the magnet moves relative to the wire there will be an EMF generated in the coil and current can be flown.

similarly by reversing the process if the magnet remains stationary and the coil is moved then again the emf and the current generated in the coil which is called as electromagnetic induction.

This is the basic principle of transformers,generators,motors .

Thus when a closed loop of wire experiences a changing magnetic field a voltage and therefore current is produced.

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The waves that are related to both electricity and magnetism are known as (EM) waves .electromagnetic Waves' this line is about a different topic than the rest of Shondra’s notes.

The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.

These waves, which are related to electricity and magnetism, would undoubtedly spread in space. The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves.

These waves are made up of time-varying electric and magnetic fields that travel over space. These waves, which are related to electricity and magnetism, would undoubtedly spread in space.

Hence option 1 is right because the 'Electromagnetic Waves' these line is about a different topic than the rest of Shondra’s notes.

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Answer:

256

Explanation:

Answer:

A. Neutrons have 0 Charge

Explanation

Neutrons have no charge for the same reason that plastics (and other insulators don't). They just don't.

"This isn't a great answer, but the thing with charge is that we don't really know what "charge" is. We know that certain "charged" objects will attract some objects, while repelling . We also know that other other "charged" objects will behave the same way, but when the two charged objects are brought together, they repell."

Answer:

Breathing.

Explanation:

1000N

From Newton's third law of motion, for every action there is an equal and opposite reaction. In other words, when two bodies are in collision, the forces acting between these bodies are equal in magnitude and opposite in direction.

In the case presented in the question, the bodies are the golf cart and the car. During collision, the golf car strikes the car with a 1000N of force (that is the action). Consequential of this, though in the opposite direction, the car will apply an equal force of 1000N (that is the reaction) on the golf car.

Therefore the car applied a force of 1000N on the golf cart.

Answer:

The car applied a force of 1000 N to the golf cart

Explanation:

Based on the laws of conservation of linear momentum, we have that linear momentum is always conserved during a collision.

By Newtons Second law, (impulse law),

\(Ft = [m_{1}(v-u)+ m_{2}(v-u)]\)

Let m 1 be the mass of the golf cart, and v 1 its initial velocity. They are = 200 kg and 5 m/s respectively.

Let m 2 be the mass of the car, and  V 2 it initial velocity. They are = 1500 kg and 0 m/s respectively.

The time involved is 1 second

Applying the values of the variables to the formula, we have.

\(F \times 1 = [200 \times (5-0) - 1500 \times (0-0)]\)

From this we have that the force the car applied to the golf cart is = 1000 N

If negligible velocity at inlet (C 1 ≈0), the velocity (C2) of steam (in m/s) at the nozzle exit is 447.21 m/s.

According to question:

The steady flow energy equation for steady flow devices

m (h1 + ((c1)2/2) + z1g) + Q = m (h2 + ((c2)2/2) + z2g) + Wcv

C1 = 0

Wcv = 0

z1 = z2

mh1 + Q = mh2 + m((C2)2/2)

m((C2)2/2) = m(h1-h2) + Q

0.1 × ((C2)2/2) × 10-3 = 0.1(2500-2350) -5

C2 = 447.21 m/s

Thus, the negligible velocity at inlet (C 1 ≈0), the velocity (C2) of steam (in m/s) at the nozzle exit is 447.21 m/s.

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The electric potential of a point charge is given by:

where q is the charge and r is the distance between the charge and the point of interest. In this case we have two charges, then to calculate the total potential on a point we need to add the individual potential of each charge.

For both charges the point of interest is at 0.1097 m, then we have:

Therefore, the electric potential midway of the charges is:

Answer:

\(\fbox {3.6kW}\)

Explanation:

Formula used :

\(\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}\)

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW

Answer:

Oh, umm…

Jump! (The higher, the better!)

Drop your pencil! (or pen or ruler, whichever you prefer!)

Throw a ball of paper! (and make sure you pick it back up later!)

Explanation:

if you satisfied to my answer , just put brainliest please , and ur welcomeee♥️♥️

Explanation:

Pressure = force / area

P = 400 N / 0.001 m²

P = 400,000 Pa

Answer:

The last one makes the most sense as they combine two like things that are easy to visualize

Explanation:

Answer:

C. The inner planets are like hard butterscotch candy and the outer planets are like cotton candy.

Explanation:

Right on ED2021, goodluck!

Answer:

The length of the image of the pole is 4/3 m

Explanation:

The given parameters are;

The length of the Pole = 4 m

The type of mirror = Convex mirror

The distance of the pole from the mirror = 2 m

The mirror formula for convex mirrors is presented here as follows;

\(\dfrac{1}{U} - \dfrac{1}{V} = - \dfrac{1}{F}\)

Where;

U = The object (pole) distance from the mirror = 2 m

V = The image of the objects (pole) distance from the mirror

The focal length of the mirror

Therefore, by substitution, we have;

\(\dfrac{1}{2} - \dfrac{1}{V} = - \dfrac{1}{1}\)

\(\dfrac{1}{2} + 1 = \dfrac{1}{V}\)

\(\dfrac{1}{V} = \dfrac{1}{2} + 1 = \dfrac{3}{2}\)

\(V = \dfrac{2}{3}\)

We have;

\(Magnification = \dfrac{Image \ height}{Object \ height } = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{Length \ of \ the \ of \ the \ Pole } =\dfrac{-V}{U}\)

Which by substitution gives;

\(Magnification = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{4} =\dfrac{-\dfrac{2}{3} }{2} = \dfrac{2}{6}\)

\({Length \ of \ the \ Image \ of \ the \ Pole}{} = 4 \times \dfrac{2}{6} = \dfrac{4}{3}\)

The length of the image of the pole = 4/3 m

Answer:

Explanation:7

99.16 Newtons is the new force of attraction between the particles.

The forces that hold atoms together to create molecules and solids are referred to as chemical bonds. The attraction between the electrons of one atom and the nuclei of another atom as a result of this electric force is what is known as a chemical bond.

\(F = (kq1q2)/r^2\)

\(9,916 = (kq1q2)/r^2\)

\(F = (k*(q1/5)*(q2/5))/(2r)^2\)

\(F = (1/100)((kq1*q2)/(r^2))\)

So, the new force of attraction is:

\(F = (1/100)*9,916 = 99.16\)Newtons (rounded to 4 decimal places)

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Answer:

D

Explanation:

These all can impact the magnetic properties

Approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

The force required on the input piston of the hydraulic jack can be calculated using the principle of Pascal's law, which states that the pressure exerted in a fluid is transmitted equally in all directions.

The ratio of the output force to the input force is equal to the ratio of the output piston area to the input piston area:

Force (output) ÷ Force (input) = Area (output) ÷ Area (input)

We can rearrange this equation to solve for the input force:

Force (input) = Force (output) × (Area (input) ÷ Area (output))

Given that the weight of the car is 1.80 × \(10^{4}\) N, the output force is 1.80 × \(10^{4}\) N. The input piston area is 0.0540 \(m^{2}\), and the output piston area is 0.710 \(m^{2}\).

Plugging these values into the equation, we have:

Force (input) = (1.80 × \(10^{4}\) N) × (0.0540 \(m^{2}\) ÷ 0.710 \(m^{2}\))

Simplifying the expression gives us:

Force (input) ≈ 1377.46 N

Therefore, approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

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The positive feedbacks without uncertainty are water vapor feedback. The feedbacks that affect the terrestrial radiation budget are lapse rate feedback, ice-albedo feedback, water vapor feedback, and cloud feedback.

Among the feedbacks listed, the ones that are definitely positive (without uncertainty) are: 1. Water vapor feedback: An increase in temperature leads to an increase in atmospheric water vapor content, which amplifies the greenhouse effect and further enhances warming. This feedback is positive. The feedbacks that affect the terrestrial radiation budget (the balance of incoming and outgoing radiation at the Earth's surface) are: 1. Lapse rate feedback: This feedback is related to the vertical temperature profile of the atmosphere. If the lapse rate (the rate at which temperature changes with altitude) decreases with warming, it can amplify the warming or cooling effects. It affects the radiation budget indirectly by influencing the atmospheric temperature structure. 2. Ice-albedo feedback: When temperatures rise, ice and snow cover decrease, exposing darker surfaces (such as land or ocean) that absorb more solar radiation. This leads to further warming, creating a positive feedback loop that affects the radiation budget. 3. Water vapor feedback: As mentioned earlier, an increase in temperature leads to increased atmospheric water vapor content. Water vapor is a potent greenhouse gas that affects the radiation budget by trapping outgoing longwave radiation and amplifying the greenhouse effect.b4. Cloud feedback: Changes in temperature and atmospheric moisture content can affect cloud formation and properties. Clouds can either trap heat (positive feedback) or reflect sunlight back to space (negative feedback), depending on their type, altitude, and coverage. The net effect of cloud feedback on the terrestrial radiation budget depends on the specific cloud changes in response to warming.

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The velocity of the dodgeball is 705.6 m/s. This answer may seem extreme, but it is correct based on the assumption that no external forces acted on the system during the collision

Two items collide when they briefly come into contact with one another.

Before the collision, the momentum of the system is:

p_initial = m_child * v_child + m_dodgeball * v_dodgeball

After the collision, the momentum of the system is:

p_final = (m_child + m_dodgeball) * v_final

Since the momentum of the system is conserved, we can equate the two expressions:

m_child * v_child + m_dodgeball * v_dodgeball = (m_child + m_dodgeball) * v_final

0 + 0.25 kg * v_dodgeball = (52 kg + 0.25 kg) * 4.2 m/s\

v_dodgeball = [(52 kg + 0.25 kg) * 4.2 m/s] / 0.25 kg

v_dodgeball = 705.6 m/s

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Answer:

The answer is

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

\(m = \frac{p}{v} \\ \)

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

\(m = \frac{280}{10} = 28 \\ \)

We have the final answer as

Hope this helps you

1. The power radiated away by Stuart is 191 W.

2. The radiative power absorbed by Stuart's body is 461 W.

3. The final temperature of Stuart's body will be approximately 54.4 °C.

1. The power radiated away by Stuart can be calculated using the Stefan-Boltzmann law:

Power radiated = emissivity * Stefan-Boltzmann constant * (surface area) * (temperature of body)⁴

Substituting the given values, we have:

Power radiated = 0.96 * (5.67 x 10⁻⁸ W/(m² K⁴)) * (0.4 m²) * (306 K)⁴

≈ 191 W

This calculation represents the power radiated away by Stuart's body due to its own temperature.

2. The radiative power absorbed by Stuart's body can be calculated by multiplying the incident solar radiation power per unit area by the exposed surface area and the emissivity:

Power absorbed = incident solar radiation * (exposed surface area) * emissivity

Given that only Stuart's top-half is exposed to the sun, the incident solar radiation is assumed to be 1200 W/m²:

Power absorbed = 1200 W/m² * (0.5 * 0.4 m²) * 0.96 ≈ 461 W

This calculation represents the power absorbed by Stuart's body due to the incident solar radiation.

3. The final temperature of Stuart's body is reached when the rate of heat absorption equals the rate of heat loss through radiation. In other words, when the power absorbed equals the power radiated away.

Setting the absorbed power (461 W) equal to the radiated power (191 W) and solving for the temperature, we can find the equilibrium temperature.

Power absorbed = Power radiated

1200 W/m² * (0.5 * 0.4 m²) * 0.96

= 0.96 * (5.67 x 10⁻⁸ W/(m² K⁴)) * (0.4 m²) * (final temperature)⁴

Simplifying the equation and solving for the final temperature, we find:

(final temperature)⁴ ≈ (1200 W/m² * 0.2 * 0.96) / (0.96 * 5.67 x 10⁻⁸ W/(m² K⁴))

(final temperature)⁴ ≈ 336031.68

Taking the fourth root of both sides, we get:

final temperature ≈ 54.4 °C

This calculation represents the equilibrium temperature that Stuart's body will reach while sunbathing.

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The highest-frequency square wave that can transmit under the assumption that you could transmit digital data over FM is limited by the maximum frequency deviation of the FM signal.

Frequency modulation (FM) is a technique of conveying digital data through radio signals. FM radio works by altering the frequency of the carrier wave to represent the information being transmitted. The bandwidth of an FM signal is determined by its maximum frequency deviation, which is the amount by which the instantaneous frequency of the modulated carrier signal differs from the center frequency. This deviation is determined by the modulation index (m) and the maximum modulating frequency (fm) as shown below:

Maximum frequency deviation = m x fm

Thus, the highest-frequency square wave that can be transmitted over FM is limited by the maximum frequency deviation (and hence the bandwidth) of the FM signal.

The highest-frequency square wave that can be transmitted under the assumption that you could transmit digital data over FM is limited by the maximum frequency deviation of the FM signal.

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Answer:

34kg

Explanation:

Answer:

5 Oxygen , 3 Carbon dioxide and 3 water

Answer: the answer is 5

The distance from the light bulb is 195km when  human eye can "see" with a signal of 100 photons per second of a 100W bulb.

Given the number of photons the human eye can see (n) = 100 per second

The power of light bulb (P) = 100W

The wavelength of light the bulb radiates (∧) = 550nm = 550 x 10^-9m

Let the diameter of pupil (d) = 5mm = 5 x 10^-3m

Let the distance the eye can see a 100-watt light bulb = r

Let the intensity of the light bulb = I

Let the power of eye = Pe

We know that I = P/4πr^2 where r is the distance from the light bulb

The power of eye = Intensity x Area of pupil = I x πd^2/4

Then,  I = 4Pe/πd^2 such that 4Pe/πd^2 = P/4πr^2

So, r^2 = P x d^2/16Pe then, r = d/4(√P/Pe)

We know that E = h∨ = hc/∧ where h is the planck's constant = and c is the speed of light = 3 x 10^8m/s.

E = the power of eye = Pe = hc/∧ x n

Then, r = d/4(√P∧/hcn)

r = 5/4(√100 x 550 x 10^-9/100 x 6.6 x 10^-34 x 3 x 10^8

r = 5/4√22.7 x 10^17

r = 15.6 x 10^4 x 1.25 = 19.5 x 10^4m = 195km

Hence the distance from the light bulb is 195km.

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Answer:

weow hahaha lol!

Explanation:

Answer:

LOLOLOLOLOL LOL

Explanation:

The intensity of the sound you hear at a distance of 280cm away from the tuning fork is 7.72 x 10⁻⁶ W/m².

The power carried by sound waves per unit area in a direction perpendicular to that area.

It is defined as the ratio of power and area.

I = P / 4πr²

Given is the radius 280 cm =  2.8 m and power 7.6 x 10⁻⁴ watt, then the sound intensity is

I =  7.6 x 10⁻⁴ / (4 x 3.14 x 2.8²)

I = 7.72 x 10⁻⁶ W/m²

Thus, the intensity of the sound you hear at a distance of 280cm away fr0om the tuning fork is 7.72 x 10⁻⁶ W/m².

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