Within the last month, the raw material price and consumable price combined has increased by 5.5%. If the throughput was 5 parts/hour, estimate the future throughput that has to take place in order to maintain a constant production cost. Consider the yield of this production is 90%. It is known that materials contained in each product weigh 2.5kg, materials (including consumables) cost is $100/kg, All equipment cost is $750,000 to be written off in 5 years with an average machine utilization of 45% over 24 hr/day, tooling cost is $200, the overhead rate (including labor) is $250/hr, energy cost is $25/hr, space and administration cost is $120/hr, and information (R&D, royalties, licenses) is $35/hr.

For a wear indicator type ball joint, when the grease fitting boss is flush with the base: B. The ball joint should be replaced.

A wear indicator can be defined as a type of technology that is designed to alert and warn a car owner or driver that the car's brake pad is needs a replacement.

Generally, a wear indicator is designed and fitted with a small boss. Thus, this small boss would continuously recede into its housing as wear occurs. However, when it recedes into the cover plate or flush with the base, it simply means that the ball joint should be replaced.

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Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, \($\epsilon$\) = 3%

                        = 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = \($0.03 \times 30 \times 10^9$\)

\($\frac{P}{A} =0.03 \times 30 \times 10^9$\)

\($P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$\)

 = 342119.44 N

For the four sensors,

Maximum weight = 4 x P

                            =  4 x 342119.44

                            = 1368477.76 N

Therefore, weight in kg is \($m=\frac{W}{g}=\frac{1368477.76}{9.81}$\)

                     m = 139498.24 kg

b). Change in resistance

\(k=\frac{\Delta R/R}{\Delta L/L}\)

\($\Delta R = k. \epsilon R$\)    , since \($\epsilon= \Delta L/ L$\)

\($\Delta R = 6.9 \times 0.03 \times 340$\)

\($\Delta R = 70.38 $\) Ω

For 4 resistance of the sensors,

\($\Delta R = 70.38 \times 4 = 281.52$\) Ω

c). \($k=\frac{\Delta R/R}{\epsilon}$\)

If linear strain,

\($\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$\)  , where k = 1

\($\Delta R = \frac{\Delta L}{L} \times R$\)

\($\Delta R = 0.03 \times 340$\)

\($\Delta R = 10.2 $\) Ω

The most important element for the building of a skyscraper is a strong and robust structural framework. It provides the necessary support to withstand vertical and horizontal loads and ensures the stability and longevity of the building.

Skyscrapers are monumental structures that reach great heights, and their construction demands careful consideration of various factors. However, the core element that ensures the stability, strength, and longevity of a skyscraper is its structural framework. This framework typically consists of steel or reinforced concrete elements that work together to distribute the weight and forces throughout the building.

The structural framework provides the necessary support to withstand the vertical and horizontal loads imposed on the skyscraper. It must be engineered to resist the forces of gravity, wind, earthquakes, and other external factors. Additionally, the framework should allow for flexibility and movement to accommodate environmental conditions and minimize structural stresses.

The design and construction of the structural framework require meticulous planning, advanced engineering techniques, and adherence to strict safety standards. Skilled architects, structural engineers, and construction professionals collaborate to create a framework that can withstand the immense pressures and challenges of a tall building.

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Answer:described by direction and is either Axial or Diametric

Explanation:

Answer:

Magnetization is the density of magnetic dipole moments that are induced in a magnetic material when it is placed near a magnet.

The incident that taught us the importance of working with our neighbors to inform them and protect them from the risks in our facilities is Bhopal.

Bhopal was an industrial town in central India that became synonymous with the world's worst industrial disaster. A toxic gas leak in a pesticide factory owned by Union Carbide, a US chemical company, killed thousands of people instantly in December 1984. The gases affected hundreds of thousands of people, some of whom were exposed to it for years. It was a horrific tragedy that no one could ever forget. This incident taught us that the health and well-being of communities surrounding chemical facilities are crucial and should be prioritized.

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Answer:

Hope this will help you

Have a good day

Answer:

false

Explanation:

Answer:

revenue

Explanation:

even when people visit your web site you are still abe to make some money

Control charts for variables are based on data that come from continuous measurement processes.

These processes generate numerical measurements of a characteristic of interest, called a variable. The variable can be any measurable attribute such as weight, length, height, volume, temperature, pressure, and so on. The data obtained from measuring the variable is plotted on a control chart to monitor the stability and performance of the process over time.
Variables control charts consist of two types: X-bar and R charts. The X-bar chart displays the average value of the variable, and the R chart displays the range or variation of the variable. Both charts are used together to detect any shifts or changes in the process mean or variability.
The data used to construct the control charts should be representative of the process being monitored and should be collected in a systematic and consistent manner. The data should be accurate, precise, and unbiased. Typically, a minimum of 20 to 25 consecutive samples of the variable is collected before constructing the control charts.
In summary, control charts for variables are based on data that come from continuous measurement processes of a measurable attribute. The data is used to construct X-bar and R charts to monitor the stability and performance of the process over time. The quality of the data is essential to ensure the reliability and usefulness of the control charts.

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Answer:

Kh/Kv =  2.8

Explanation:

The horizontal conductivity = K1H1+K2H2+K3H3/(H1+H2+H3)

= K1H+K2H+K3H/3H

= K1+K2+K3/3

= 10-3 cm/sec + 10-3 cm/sec + 10-2 cm/sec/3

= 4 * 10^-3 cm/s

Vertical conductivity

= H+H+H/(H/K1 +H/K2+H/K3)

= 3/(1/K1+1/K2+1/K3)

= 1/700 cm/s

Kh/Kv = 4 * 10^-3 cm/s/ 1/700 cm/s

Kh/Kv =  2.8

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

Centrifugal force is the force exerted on an object moving in a circular path and directed outward from the center. In order to determine the centrifugal force in pound-force of a centrifuge carrying 50mL of blood, we will need to use the formula for centripetal force:

Centrifugal force = (mass x acceleration)/radius

Here's how to solve the problem:

First, we need to determine the mass of the blood being carried by the centrifuge. We know the volume of blood (50 mL) and the density of blood (0.994 g/mL), so we can use the formula:

mass = volume x density

mass = 50 mL x 0.994 g/mL

mass = 49.7 g

Next, we need to convert the given units to SI units (meters and seconds):

Centripetal acceleration = 64 ft/s^2
1 ft = 0.3048 m
Centripetal acceleration = 64 ft/s^2 x 0.3048 m/ft = 19.5072 m/s^2

Rotational speed = 345 rpm
1 rpm = 1/60 s
Rotational speed = 345 rpm x 1/60 s = 5.75 s^-1

Now we can use the formula to calculate centrifugal force:

Centrifugal force = (mass x acceleration)/radius

The radius of the centrifuge is half the diameter (3.5 inches or 0.0889 meters):

Centrifugal force = (49.7 g x 19.5072 m/s^2)/0.0889 m

Centrifugal force = 10,879.52 N

Finally, we need to convert Newtons to pound-force:

1 N = 0.22481 lb-f
Centrifugal force = 10,879.52 N x 0.22481 lb-f/N

Centrifugal force = 2,442.69 lb-f

Therefore, the centrifugal force in pound-force is 2,442.69 lb-f.

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Answer:

\(250\ \text{lbm/min}\)

\(625\ \text{ft/min}\)

Explanation:

\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)

\(V_1\) = Velocity of water at section 1 = 100 ft/min

\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)

\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)

\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)

Mass flow rate is given by

\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)

The mass flow rate through the pipe is \(250\ \text{lbm/min}\)

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)

The speed at section 2 is \(625\ \text{ft/min}\).

(a) The mass flow rate will be "250 lbm/min".

(b) At section 2, the speed will be "625 ft/min".

According to the question,

Section 1 area, A₁ = 10 ft²

Section 2 area, A₂ = 2 ft²

Water's velocity, V₁ = 100 ft/min

Volume at section 1, v₁ = 4 ft³/lbm

(a) We know the formula,

Mass flow rate, m = ρA₁V₁

                              = \(\frac{A_1 V_1}{v_1}\)

By substituting the values,

                              = \(\frac{10\times 100}{4}\)

                              = \(\frac{1000}{4}\)

                              = 250 lbm/min

(2) The speed will be:

→ m = ρA₂V₂

or,

  V₂ = \(\frac{m}{\rho A_2}\)

By substituting the values,

       = \(\frac{250}{0.2\times 2}\)

       = \(\frac{200}{0.4}\)

       = 625 ft/min

Thus the responses above are correct.  

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It means that the gas with the lowest molecular weight will have the highest effusion rate.

The given gases' effusion rates are listed in order from highest to lowest. The effusion rate of a hydrogen molecule is the highest, whereas that of a hydrocarbon is the lowest.

A gas will effuse faster when it is lighter and more slowly when it is heavier. Helium (He) will have the highest rate of effusion since it has the lowest molecular weight (atomic weight, in this example).

The following equation can be used to compare the rate of effusion for two gases: The effusion rates in this case are inversely related to the square root of the gas molecules' masses. A container contains an amalgam of neon and argon gas.

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To find the resulting rotation matrix after a sequence of rotations, we need to multiply the matrices representing each rotation in the order they were performed.

The first rotation is about the world x-axis, so we need to use a matrix that represents a rotation about the x-axis. The second rotation is about the current z-axis, which has changed after the first rotation, so we need to use the rotation matrix for the current z-axis. Finally, the third rotation is about the world y-axis, so we use the rotation matrix for the y-axis. The resulting matrix is the product of these three matrices, in the order they were performed. By multiplying these matrices, we can find the final rotation matrix that represents the combined effect of all three rotations.

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Answer:

Placement.

Explanation:

SAE is an acronym for Supervised Agricultural Experience programs and it is typically a planned, practical-based program designed to help students develop competent skills and experience in their various career choice. Basically, it enhances the academic knowledge and agricultural skills acquired by the students in the classroom.

Generally, there are four (4) main types of Supervised Agricultural Experience Programs;

1. Entrepreneurship SAE.

2. Exploratory SAE.

3. Research and Experimentation SAE.

4. Placement SAE.

A non-entrepreneurship, work-based, agricultural type of Supervised Agricultural Experience program (SAE), in which a student learns and gains skills in a paid or unpaid position describe a placement.

Some examples of organizations or businesses that provide placement SAE to students includes; lawn services, veterinary clinics, soil conservation firms, livestock farms, floral shops, grain farms etc.

Answer:

Placement

Explanation:

Answer:

Using the Manning's Equation, the discharge rate can be calculated as follows:

Q = (1.49/n) x A x R^(2/3) x S^(1/2)

Where:

Q = discharge rate (m^3/sec)

n = Manning's roughness coefficient (0.011)

A = cross sectional area of the ditch (2m x 0.5m = 1 m^2)

R = hydraulic radius (half the width of the ditch, or 1 m)

S = slope of the ditch (0.0009)

Q = (1.49/0.011) x 1m^2 x 1m^(2/3) x 0.0009^(1/2)

Q = 13,636.36 m^3/sec

Many examples of value created through deep learning are Visual reality, entertainment, healthcare, etc

What are the examples of value created through the use of deep learning?

Virtual assistants today are as powerful as a human at your disposal. At the command of your voice, they can take notes, perform actions, and even make suggestions.

Deep learning has aided the process of creating, publishing, and distributing entertainment media. Human body language analysis using cameras has made it easier to create virtual characters. Deep video analysis has sped up the editing, audio-video synchronization, and transcription processes. Deep Learning is revolutionizing filmmaking.

AI in healthcare can improve preventive care and quality of life, produce more accurate diagnoses and treatment plans and lead to overall better patient outcomes. AI can also predict and track the spread of infectious diseases by analyzing data from government, healthcare, and other sources.

Hence to conclude above examples are value-added ones for deep learning

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Answer:

Following are the solution to the given question:

Explanation:

Line voltage:

\(V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v\)

Power supplied to the load:

\(P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi\)

\(10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A\)

Check wye-connection, for the phase current:

\(I_{ph}=I_L= 32.68\ A\)

Therefore,

Phasor currents: \(32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A\)  

Magnitude of the per-phase load impedance:

\(Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega\)

Phase angle:

\(\phi = \cos^{-1} \ (0.85) =31.79^{\circ}\)

Please find the phasor diagram in the attached file.

The ER diagram for the Temporary Employment Corporation (TEC) based on the business rules given is given below: Attributes for Entities:

(One-to-Many)One candidate can have many job histories. (One-to-Many)One job history can belong to only one candidate. (One-to-One)One placement can belong to only one candidate. (One-to-One)One job opening can be placed by many placements. (One-to-Many)One candidate can have many placements.

In the given diagram below, all the relationships and primary keys are labeled correctly and the ER diagram is resolved for all M:N relationships and 1:N relationships. If you want to add more attributes to each entity, you can do it accordingly:

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Answer:

The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is  an idication that your vehicle may be developing a cooling system problem.

Explanation:

Answer:

1.2 Newtons upwards

Explanation:

because the friction is opposite of the magnitude.

Only technician B is correct when she claims that some lab scopes may simultaneously display two waveforms.

By giving you both time and voltage data on a display screen, a lab scope solves the problems of a fast changing signal. An image of voltage levels, voltage changes, and the frequency (speed) of these changes can be seen on a lab scope. Since some lab scopes can display two waveforms simultaneously, technician B is correct when she says that this is a feature of some lab scopes. Technician A is mistaken when she claims that a lab scope shows a sensor's resistance as it varies over time. In order to detect electronic glitches that happen faster than can be recorded with merely a digital meter, a lab scope (also known as an oscilloscope) is a device, it shows measurements of time as well as the voltage values of an electric circuit.

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The ultimate goal of the PI Planning event is to align all the teams within the Agile Release Train (ART) to a shared vision and mission for the upcoming Program Increment (PI).

This is achieved through a series of activities and discussions that help teams to identify dependencies, risks, and objectives for the upcoming PI. By the end of the PI Planning event, all teams should have a clear understanding of their role and responsibilities for the upcoming PI and should be able to work together effectively to achieve the shared goals. By aligning all the teams within the ART to a shared vision and mission for the upcoming PI, the PI planning event helps to ensure that the entire organization is working towards the same goals and that the work being done by each team is contributing to the overall success of the organization.

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Project Mazer: Vision and   project Mazer stands for Math Analyzer for mazers.

 The objective is to develop a command-line tool for analyzing mathematical expressions using the specified characters in the alphabet.

The implementation of the project Mazer must satisfy the following requirements:

The tool should be command-line based.

Alphabet consists of: 0−9,+,−(,), space,tab.

Acceptable forms:

integers - int (can be signed - single, parenthesized - multiple)

White space is ignored,

except between a+/− and int.

Accepts an input and indicates whether it's "Valid" or "Invalid".

Repeat until the user enters 0. + - must be followed by an int or something that evaluates to int.

A + or - cannot follow a+ or −. Any other forms of mazer are invalid.

The implementation must be in a language of your choice. You must not use an evaluator but read input character by character. Sample outputs, commented code, and test suites must be submitted.

The submission deadline is Thursday, October 6, 2022, by class time.

As you proceed with implementing the project Mazer, consider the objectives, requirements, and constraints of the project. You can also leverage feedback from class discussions to help you make better decisions about the design, implementation, and testing of the project.

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Answer:

i dont know

Explanation:

i dont know how i answer this

steam tables or thermodynamic software and verify the accuracy of the specific enthalpy and internal energy values for water vapor, as well as the properties of air, to ensure precise calculations.

In the given problem, two separate scenarios are described. Let's address each scenario individually.

Scenario 1: Water vapor cooling at constant volume

Starting with water vapor at 2.0 MPa and 300 °C, it is cooled at constant volume until the temperature drops to 150 °C. At the end of the process, we need to find the dryness fraction and the specific internal energy of the saturated liquid-vapor mixture.

To determine the dryness fraction, we need to calculate the quality (x) of the mixture, which represents the mass fraction of vapor present. The dryness fraction can be calculated using the equation:

x = (h - hf) / (hg - hf),

where h is the specific enthalpy of the mixture, hf is the specific enthalpy of the saturated liquid at the final temperature, and hg is the specific enthalpy of the saturated vapor at the final temperature.

The specific internal energy (u) of the saturated liquid-vapor mixture can be determined using the equation:

u = (x * u g) + ((1 - x) * u f),

where ug is the specific internal energy of the saturated vapor at the final temperature, and uf is the specific internal energy of the saturated liquid at the final temperature.

Scenario 2: Compressed air in a cylindrical tank

Given a compressed air pressure of 400 kPa, a tank diameter of 0.3 m, a height of 1.5 m, and the specific gas constant (R) for air as 0.287 kJ/kg·K, we need to find the mass and specific weight of the compressed air.

To determine the mass of the compressed air, we can use the ideal gas law:

PV = mRT,

where P is the pressure, V is the volume of the tank, m is the mass, R is the specific gas constant, and T is the temperature.

The specific weight (γ) can be calculated by dividing the weight (W) of the air by the volume (V) of the tank:

γ = W / V.

By substituting the known values into the equations and performing the necessary calculations, the mass and specific weight of the compressed air can be determined.

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The discovery that describes how the Bronze Age was introduced is that metalsmiths working with impure copper realized that the addition of small amounts of tin or other metals to copper produced a harder and more durable substance known as bronze.

This discovery revolutionized metalworking and led to the widespread use of bronze in tools, weapons, and other artifacts during the Bronze Age, which lasted from around 3300 BCE to 1200 BCE.

The discovery of bronze allowed for the creation of stronger and more complex tools, leading to advancements in agriculture, transportation, and warfare, among other areas.

Thus, this describes the way in which the Bronze Age was introduced.

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When in regular operation, ash and other debris should be removed daily from the combustion chamber of a wood-burning heater.

A wood stove radiates heat as it warms up via the stove's top and walls. The nearby region is warmed by the radiant heat, which can also warm other areas of the house thanks to the natural airflow in the building.

Fans using electric or convection power can help move this heat around to warm a bigger space. Some wood stoves use a convection chamber that wraps around the firebox to combine radiant and convection heat into a single appliance. Cool air is drawn into this convection chamber where it is heated and then circulated once again around the space.

Ash and other debris should be taken out of a wood-burning heater's combustion chamber every day when it is in regular use.

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The compound microscope developed by Zacharias and Hans Janssen was a significant advancement in the field of microscopy.

It consisted of a combination of lenses that allowed for enhanced magnification and visualization of tiny objects.The microscope featured two sets of lenses, namely the objective lens and the eyepiece lens. The objective lens, located close to the specimen, collected and magnified the light passing through it. This magnified image was then further enlarged by the eyepiece lens, which allowed the viewer to see the specimen in greater detail.One notable feature of the Janssen brothers' microscope was the ability to achieve higher magnification than the simple microscopes of that time. By combining multiple lenses, they were able to obtain higher resolution and clearer images.

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