Will the plastic insulation on the electrical wire decrease the heat transfer from the wire?

Answers

Answer 1

Plastic insulation does not necessarily decrease the heat transfer from the wire. Although it is insulated to keep it safe, shock free and protect the wire from high temperature.

Plastic is a poor conductor of heat. The reason is it does not have free electrons in its conduction band which makes it a perfect conductor.

Since Plastic is good insulator, they do not allow the flow of heat through them. When an electric wire is insulated with plastic it does not let the heat reach the electric wire.

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Answer 2

The plastic insulation on the electrical wire will not decrease the heat transfer from the wire.

Plastic insulation cannot always reduce heat transmission from the wire. Despite the fact that it is protected to make it safe, shock-free, and to shield the wire from extreme temperatures.

Plastic is a bad heat conductor. The reason for this is that it has no flow of electrons inside its conduction band, making it an excellent conductor.

Because plastic is a poor insulator, it does not enable heat to pass through it. Whenever an electric wire is protected with plastic, it prevents heat from reaching the wire.

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Related Questions

moral lesson learnt from the sermon on the mount​

Answers

Blessed are the merciful: for they shall obtain mercy is the moral lesson learned from the sermon on the mount​

What is the Sermon on the Mount's main message?

Christians learn the following crucial lessons from this sermon: The things we own here on Earth don't matter. Good people will discover meaningful spiritual "treasures" in Heaven. God will take care of people, so they shouldn't be concerned.

In the Sermon on the Mount, what did Jesus say?

1. And, seeing the crowds, he climbed a mountain: His disciples came to him after he was set.

2. And he spoke to them, saying

3. Because the kingdom of heaven is theirs, those who are poor in spirit are blessed.

4. Happy are the bereaved because they will find comfort.

Who wrote the sermon on the Mount?

Scholars put forth a number of arguments for the claim that Matthew is the author of the Sermon on the Mount, but only using New Testament sources.

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Two point charges of 30 μc each are 4 cm apart. What is the electric field at the midpoint between the two charges? group of answer choices A. 5. 0 x 106 n/c B. 2. 30 x 107 n/c C. 4. 50 x 107 n/c 0 n/c

Answers

The electric field is 135 N/C at the center of the two charges, which equals \(4.50 * 10^7 N/C\), Hence the correct option is (C).

To find the electric field at the midpoint between two point charges, we can use the formula:

\(E = k * (q1 + q2) / r^2\)

here,

E is electric field,

k is Coulomb constant \((9 * 10^9 Nm^2/C^2)\),

q1 and q2 are charges, and

r is distance between the charges.

In this problem, we have two charges of 30 μC each, which means q1 = q2 = 30 \(\mu C = 30 * 10^-^6 C\). The distance between the charges is 4 cm, or 0.04 m, so r = 0.02 m.

To find the electric field at the midpoint between the two charges, we need to find the electric field due to one of the charges at the midpoint, and then double that value to account for the contribution of the other charge.

The midpoint between the two charges is 2 cm, or 0.02 m, from each charge. Therefore, we can use the formula to find the electric field due to one of the charges at the midpoint:

\(E1 = k * q1 / r^2 = (9 * 10^9 Nm^2/C^2) * (30 * 10^-^6 C) / (0.02 m)^2 = 67.5 N/C\)

To find the total electric field at the midpoint, we need to double this value:

\(E = 2 * E1 = 2 * 67.5 N/C = 135 N/C\)

Therefore, the electric field at the midpoint between the two charges is 135 N/C.

Answer: C. \(4.50 * 10^7 N/C\)

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the suraface of glass place is coated witha transparent thin film a beam of monocharmitc light of wavelength meter traclinv in air is incident normally on surafce s1

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The surface of a glass plate is coated with a transparent thin film. When a beam of monochromatic light of wavelength λ meters is incident normally on surface S1, it will reflect off the surface and then pass through the thin film before reflecting off surface S2 and exiting the film. We can determine the thickness of the thin film that will result in constructive or destructive interference for a given wavelength of light.

The reflection off of surface S1 will cause a phase shift of 180 degrees, while the reflection off of surface S2 will not cause a phase shift. Therefore, the two reflected beams will interfere constructively or destructively depending on the thickness of the thin film and the wavelength of the light. If the thickness of the thin film is an integer multiple of λ/4, then the two reflected beams will interfere constructively and the reflected light will be bright. If the thickness of the thin film is an odd multiple of λ/4, then the two reflected beams will interfere destructively and the reflected light will be dim.

The formula for the interference condition is given by:
2nt = (m + 1/2)λ
Where n is the refractive index of the thin film, t is the thickness of the thin film, m is an integer, and λ is the wavelength of the light.

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How harmful are the emissions from cosmetics, hygiene, and cleaning products? Claim
Evidence 1
Evidence 2
Evidence 3
Reasoning ​

Answers

The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.

Evidence 1: Effect of Air Quality

Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.

Environmental impact is evidence number two

Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.

Evidence 3: Worker health effects

Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.

Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.

Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.

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If you just take the points I will find you and you will not like what I do


Advanced Space Weather Activity
This lesson highlighted different types of space weather. If you were responsible for reporting space weather like Earth's weather is reported, how would you do it? What would you include?

Create any type of weather report to warn people about space weather activity. You can present it like a weather app, radio announcement, television news report, or newspaper weather section. You only need to pick one type of report to submit to your instructor.

Activity Checklist:

Include at least three different types of space weather events.
Include details and warnings for viewers or listeners about space weather outcomes.
Include images to help identify space weather or its effects on Earth.
Pick a weather app, radio announcement, television news report, or newspaper weather section as the format for your report.

Answers

Answer:

Explanation:

here this is a whole slideshow i made

Answer:

Explanation:

Fun homework assignment!

I will provide the info that should allow you to write the space weather report.

Three different types of space weather events:

- Solar flare: strong radiation from the Sun. People should stay inside their spacecrafts.

- Meteorite shower: space rocks zipping by at extreme high speed. Again people should stay inside.

- Man-made space debris: big and small space junk left by human space activities. Slower than meteorite but still need to keep an eye on them.

Effect on Earth:

- Solar flare will affect radio communication and satellite transmission.

- Meteorite shower usually burns up in atmosphere but some may hit ground.

- Space debris also burn up in air but some may land like the recent Chinese rocket.

Newton's first law of motion is the law of inertia

Answers

Answer:

this statement is true because I looked it up

yes this is a true statement

An Atwood machine is constructed using two wheels (with the masses concentrated at the rims). The left wheel has a mass of 1.9 kg and radius 20.81 cm. The right wheel has a mass of 2.4 kg and radius 28.8 cm. The hanging mass on the left is 2 kg and on the right 1.39 kg.
What is the acceleration of the hanging
mass on the left? Use down as the positive direction. The acceleration of gravity is
9.8 m/s².
Answer in units of m/s²

An Atwood machine is constructed using two wheels (with the masses concentrated at the rims). The left

Answers

The acceleration of the left-hanging mass is  6.811 m/s²

What is acceleration?

Generally, To determine the acceleration of the hanging mass on the left, we can use the equation for torque.

Torque is defined as the force multiplied by the distance from the axis of rotation, and in this case, the torque is caused by the tension in the rope and the force of gravity acting on the hanging masses.

The equation for torque is:

τ = (F_L - F_R) * r_L

where

τ is the torque, F_L is the force on the left hanging mass, F_R is the force on the right hanging mass, and r_L is the distance from the axis of rotation to the left-hanging mass.

The force on the left hanging mass is:

F_L = m_L * a

where m_L is the mass of the left hanging mass and a is the acceleration.

The force on the right hanging mass is:

F_R = m_R * g

where

m_R is the mass of the right hanging mass and

g is the acceleration due to gravity.

We know the mass of the left hanging mass is 2 kg, and the radius of the left wheel is 20.81 cm, so we can substitute these values into the torque equation:

τ = (m_L * a - m_R * g) * r_L

τ = (2 * a - 1.39 * 9.8) * 0.2081

We know the torque is zero, so we can set the left side of the equation to zero and solve for a:

0 = (2 * a - 1.39 * 9.8) * 0.2081

a = 6.811 m/s²

The acceleration of the left-hanging mass is  6.811 m/s²

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under the principles of the concentric ring model, what is the name of the activities found in the most outer circle / ring?

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a concentric ring model in which social groupings are spatially organised in a hierarchy of rings. The upper class resides further away from the center, while the lower class is located closer to it.

The concentric ring model operates on the presumption that cultural content results from the incorporation of original ideas into the creation and/or presentation of music, text, and picture, and that these concepts originate in the fundamental artistic creativity spheres. Burgess' concentric ring model concept envisions growth occurring in a series of concentric rings surrounding the concentric ring model . According to Hoyt's sector model, economic expansion follows transportation corridors.

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an experiment to determine the molecular size of a substance​

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Size exclusion chromatography is the method by which scientists determine the molecular size (not the weight), of a particular substance.

Size-exclusion chromatography (SEC), also known as molecular sieve chromatography, is a chromatographic method in which molecules in solution are separated by their size, and in some cases molecular weight. It is usually applied to large molecules or macromolecular complexes such as proteins and industrial polymers.

Typically, when an aqueous solution is used to transport the sample through the column, the technique is known as gel-filtration chromatography, versus the name gel permeation chromatography, which is used when an organic solvent is used as a mobile phase. The chromatography column is packed with fine, porous beads which are commonly composed of dextran, agarose, or polyacrylamide polymers. The pore sizes of these beads are used to estimate the dimensions of macromolecules.

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True or false. A small amount of mass can produce a large amount of energy

Answers

The satement is true.

This comes from the fact that, according to Einstein:

\(E=mc^2\)

and since c² is a very large number then, if we find a way to convert all the mass in energy a small amount will produce a large amount of energy.

Select the correct rocks.
Identify the igneous rocks.

Select the correct rocks.Identify the igneous rocks.

Answers

Answer:

Red Volcano Rock and the Lava Rock Covered in Sulphur

Explanation:

Igneous Rocks are formed by volcanoes, lava, and magna. Sandstone is sedimentary and Slate is metamorphic. The other two are literally formed by volcanoes.

Answer:

Red Volcano Rock and the Lava Rock Covered in Sulphur

Explanation:

Write short notes on proper management of sewage and garbage​

Answers

Explanation:

Waste management (or waste disposal) includes the processes and actions required to manage waste from its inception to its final disposal.[1] This includes the collection, transport, treatment and disposal of waste, together with monitoring and regulation of the waste management process and waste-related laws, technologies, economic mechanisms. Proper management of waste is important for building sustainable and liveable cities, but it remains a challenge for many developing countries and cities. A report found that effective waste management is relatively expensive, usually comprising 20%–50% of municipal budgets. Operating this essential municipal service requires integrated systems that are efficient, sustainable, and socially supported.[6] A large portion of waste management practices deal with municipal solid waste (MSW) which is the bulk of the waste that is created by household, industrial, and commercial activity.[7] Measures of waste management include measures for integrated techno-economic mechanisms[8] of a circular economy, effective disposal facilities, export and import control[9][10] and optimal sustainable design of products that are produced.

Ways of proper management of sewage and garbage​.

What is water management?

Waste management (or waste disposal) includes the processes and actions required to manage waste from its inception to its final disposal.

This includes the collection, transport, treatment and disposal of waste, together with monitoring and regulation of the waste management process and waste-related laws, technologies, economic mechanisms.

Proper management of waste is important for building sustainable and liveable cities, but it remains a challenge for many developing countries and cities. A report found that effective waste management is relatively expensive, usually comprising 20%–50% of municipal budgets.

Operating this essential municipal service requires integrated systems that are efficient, sustainable, and socially supported. A large portion of waste management practices deal with municipal solid waste (MSW) which is the bulk of the waste that is created by household, industrial, and commercial activity.

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The data table below shows the distribution of the energies of a pendulum 0.60 s into its motion. What is the missing value?
A. 0.054 J
B. 0.654 J
C. 0.864 J
D. 0.972 J

Answers

The missing value in the distribution of energies of the pendulum 0.60 s into its motion is 0.654 J (Option B).

Determine the missing value?

Based on the information given, we can assume that the table lists the energy values at different time intervals during the motion of the pendulum. The missing value can be determined by analyzing the options provided and identifying the closest match to the distribution pattern.

Since the question states that the missing value occurs 0.60 s into the motion, we need to look for an option that corresponds to this time interval. Among the given options, 0.654 J (Option B) closely matches the pattern and fits the expected energy value.

It's important to note that without additional context or specific calculations, the answer is determined by analyzing the given options and identifying the closest match to the distribution pattern for the given time interval.

Therefore, the energy missing from the pendulum's distribution 0.60 s into its motion is 0.654 J (Option B), as it closely matches the pattern and expected value at that time interval.

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The data table below shows the distribution of the energies of a pendulum 0.60 s into its motion. What

The angle θ always has a value in the range of...?

Answers

The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used.

The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used. This is because a full circle contains 360 degrees or 2π radians, and any angle can be expressed as a multiple of this full circle.

When measuring angles in degrees, the range of theta is typically given as 0 ≤ θ ≤ 360 degrees. This means that theta can take on any value between 0 degrees and 360 degrees, inclusive.

When measuring angles in radians, the range of theta is typically given as 0 ≤ θ ≤ 2π radians. This means that theta can take on any value between 0 radians and 2π radians, inclusive.

It's worth noting that angles can also have negative values or values greater than 360 degrees or 2π radians, but these are typically considered to be outside the standard range of theta.

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write an equation to help stacy find the gravitational force on an object if she knows the mass. in the equation let w represent gravitational force m represent mass and g represent the ratio you found in part s test your equation using a set of values from the table to be sure it works

Answers

The gravitational force on the object with a mass of 5 kg on the surface of the Earth is 49.05 N.

The equation that can help Stacy find the gravitational force on an object if she knows its mass is:

F = w = m x g

where:

F is the gravitational force (in Newtons, N)

m is the mass of the object (in kilograms, kg)

g is the acceleration due to gravity (in meters per second squared, \(m/s^2)\)

The value of g varies depending on the location of the object, but on the surface of the Earth, it is approximately 9.81 \(m/s^2.\)

To test the equation using a set of values from the table, let's say we have an object with a mass of 5 kg. Using the value of g on the surface of the Earth, we can calculate the gravitational force on the object as:

F = 5 kg x 9.81\(m/s^2\)

F = 49.05 N.

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Calculate the momentum for the 5 kg bowling ball moving at 6 m/s.

Answers

Answer:

Given

mass (m) =5kg

velocity (v) =6m/s

momentum (p) =?

Form

p=mv

5kgx6m/s

p=30kg.m/s

momentum =30kg.m/s

A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.

Answers

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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Cover each end of a cardboard tube with metal foil. Then use a pencil to punch a hole in each end, one about 3 millimeters in diameter and the other twice as big. Place your eye to the small hole and look through the tube at the colors of things against the black background of the tube. You'll see colors that look very different from how they appear against ordinary backgrounds.


Write down observation

Answers

This straightforward experiment illustrates the idea of colour perception and how the background against which an object is seen can affect it, can make a viewing device by covering the ends of a cardboard tube with metal foil, punching a small hole on one end, and a larger hole on the other.

The black background of the tube suppresses much of the ambient light and produces a gloomy atmosphere for viewing when you gaze through the tiny hole and see objects through it. In contrast to viewing items against common backdrops under typical lighting circumstances, this enables your eyes to adjust and perceive colours differently.

The little hole serves as a pinhole camera, which sharpens the image by limiting the quantity of light entering the tube. Contrarily, the bigger hole let in more light and broadens the field of vision. Because of this, objects visible through the little hole may appear to have more vivid and saturated colours than those visible through the bigger hole, which may appear washed out or lackluster.

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2. If the wind speed increased, what would happen to the plane’s ground speed?

Answers

Answer:

If the wind speed increased, the plane's ground speed would be affected.

Explanation:

The ground speed of a plane is the speed at which it is traveling relative to the ground. Wind speed affects the plane's airspeed, which is the speed at which it is traveling relative to the air. If the wind speed increases, it can either help or hinder the plane's ground speed, depending on whether the wind is a headwind or a tailwind. A headwind can slow down the plane's ground speed, while a tailwind can increase it.

When we burn gasoline to run a car, for example, the amount of produced by the does not vanish, nor does any new appear that was not present before the combustion. Some of the goes toward driving the car forward (about 20%), and the rest is dissipated into the surroundings as (just feel the engine). However, the total given off by the combustion equals the of the amount of driving the car forward and the amount dissipated as

Answers

When we burn gasoline to run a car, the amount of energy produced by the combustion does not vanish, nor does any new energy appear that was not present before.

Some of the energy goes toward driving the car forward (about 20%), and the rest is dissipated into the surroundings as waste heat (exhaust and engine heat). However, the total energy given off by the combustion equals the sum of the amount of energy used for driving the car forward and the amount of energy dissipated as waste heat.

In the process of burning gasoline, chemical energy is converted into mechanical energy (used for propulsion) and thermal energy (waste heat). The mechanical energy is harnessed by the car's engine to move the vehicle forward, while the waste heat is a byproduct of the combustion process and is released into the environment.

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The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration. True or false?.

Answers

Answer:

The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration

Explanation:

a skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.

Answers

Gravity is the only force at work. However, when a person levitates toward the ground, it creates drag.

As the skydiver falls faster, the drag increases until it reaches the magnitude of gravity. When drag becomes as great as gravity, a force balance is reached and the skydiver stops accelerating. To simplify the topic.

We can say that the two most common factors that directly affect the amount of drag are object velocity and object cross-sectional area. Gravity and air resistance act on a skydiver jumping out of an airplane. The speed at which an object falls and the shape of the object on the surface on which the force of air resistance acts.

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PLEASE HELP WILL MARK AND 5 stars

What is the average repetition or time for High Knees

Answers

30 minutes to an hour

Tessa uses a toy slingshot to launch a tennis ball across the park for her dog to fetch. For her first launch, she
uses 100 N of force. Her second launch uses 200 N of force, and her third launch uses 300 N. Which launch had
the greatest acceleration of the tennis ball?

Answers

Answer:

See the explanation below.

Explanation:

To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass [kg]

a = acceleration [m/s²]

The mass of the tennis ball will always be the same therefore it will never change.

Now clearing a:

\(a=\frac{F}{m}\)

If the mass of the ball remains the same:

\(a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}\)

We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.

Convert 250mm to kilometers using conversion factor

Answers

Answer:

0.00025 kilometers

Explanation:

divide the length value by 1e+6

Answer:

250 mm = 0.00025 km.

Explanation:

250 mm equal 0.00025 km

Conversion details

To convert mm to km use the following formula:

1 mm equals 0.000001 km

So, to convert 250 mm to km, multiply 0.000001 by 250 i.e.,

250 mm = 0.000001 * 250 km = 0.00025 km

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A child has an ear canal that is 1. 3 cm long. at what sound frequencies in the audible range will the child have increased hearing sensitivity?

Answers

A child has an ear canal that is 1. 3 cm long. Sound frequencies in the audible range for the child to have increased hearing sensitivity is 6600 Hz to 19,800 Hz

The shape of the human ear is similar to a pipe that has a closed end and other end is open. Hence,

λ = 4L where L is the length of child's ear

Wavelength, λ = 4 × Length of the ear of the child

                     λ = 4 × 0.013m

                     λ = 0.052m

Frequency is the no. of oscillations per unit time.

The frequency of the sound, ν = c/λ

where c is the speed of sound i.e. 343 m/s

           λ is the wavelength of sound

The child's audible range is equal to

ν = 343/0.052

ν = 6600Hz

We can also say that, ν is 13200 Hz or 19,800 Hz.

In general, the audible range of frequency for human ear is 20Hz to 20,000Hz.

Hence, sound frequencies in the audible range will the child have increased hearing sensitivity is 6600Hz to 19800 Hz.

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While on the moon, Buzz Aldrin carried on his back a support system that would
weigh over 1,775 N on Earth. What did the backpack weigh on the moon? (gravity
on the moon is 1.62 m/s^2)

Answers

Answer:

W' = 287.55 N

Explanation:

We know that weight force is defined as follows:

W = m × g

So:

On Earth (W = 1775 N):

1775 = m × 9.8

m = 1775 / 9.8

m = 181.12 kg

On the Moon (g' = 1.62 m/s²):

W' = m × g'

W' = 181.12 × 1.62

W' = 293.42 N

Which law of motion is this and why?

A stationary bumper car is sent into motion after being hit with another bumper car.

Answers

Answer:

Third Law Of Motion.

Explanation:

The law of interaction, the third one, explains that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body.

An incredibly dense star so massive that light cannot escape from its surface is called a _______________

Answers

An incredibly dense star so massive that light cannot escape from its surface is called a Black Hole.

Black Hole, is an incredibly dense star so massive that light cannot escape from its surface.

Black hole is the region in space where the gravity is maximum indicating no particle can escape from it.

It is formed from the start debris that died in the explosion.

It creates deep stinks of gravity that even light cannot escape from it.

It was discovered by John Michell. It is believed that the universe may have originated from the black hole only.

They roam among the stars of the Milkyway galaxy

Black holes live for infinite number of years which is like the age of the universe.

Earth would never fall into the black hole but if it does then even earth cannot escape from falling.

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why is it colder at the poles and warmer at the equator? group of answer choices the greenhouse effect at the poles solar radiation is spread over a larger area at the poles, radiation is spread over a smaller area at the equator, radiation is spread over a larger area

Answers

The main reason it is colder at the poles and warmer at the equator is due to the difference in solar radiation distribution. Solar radiation from the Sun plays a significant role in determining temperature patterns on Earth.

At the equator, solar radiation is more direct and concentrated. The same amount of radiation is spread over a smaller area, leading to a higher intensity of heat per unit area. This results in higher temperatures at the equator.

In contrast, solar radiation at the poles arrives at an oblique angle and is spread over a larger area. The same amount of radiation is distributed over a larger surface area, leading to a lower intensity of heat per unit area. This results in colder temperatures at the poles.

The greenhouse effect, which traps heat in the atmosphere, does play a role in global temperature patterns, but it is not the primary reason for the temperature differences between the poles and the equator. It is the variation in solar radiation distribution that primarily drives the temperature contrast.

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